Sucrose: density = 1.59 g/cm³. Your experiment showed a density of 1.68 g/cm³. What is the percent error *

Answer:

79.04 L

Explanation:

We are given;

Initial Volume; V1 = 6.24L

Initial Pressure; P1 = 760 mm Hg

Final pressure; P2 = 60.0mm Hg

To solve for final volume, we will use Boyles law;

P1•V1 = P2•V2

Let's make V2 which is the final volume the subject;

V2 = (P1•V1)/P2

V2 = (760 × 6.24)/60

V2 = 79.04 L

Answer: Yes

Explanation:

Answer:

YESS

Explanation:

This equipment could be used to find out how much energy a fuel gives out when it burns. By measuring the temperature change in the container, the energy released by the combustion reaction can be calculated. The thermometer measures the temperature change and the container is used to hold the mixed chemicals (fuel and oxidizer). The lid is used to prevent the loss of heat and to create a closed system for the reaction to take place.


ALLEN

Answer:

Sugar is sucrose or \(C_{12} H_{22}O{11}\)

Not sure what yo're looking for... Is it molecular? Solid? Nonsystematically named (sucrose)? C12H22O11?

Explanation:

mole = mass/molar mass

mole of Nacl = mass/mm

molar mass of Nacl = Na + Cl = 23+35=58

mole of NaCl = 29/58

mole of NaCl = 0.5mol

H2SO4 + NaCl ====> HCl + Na2SO4

1. 1. 1. 1

since mole of NaCl is 0.2mol then mole of HCl is also 0.2mol since they are all in the same ratio

mole of HCl = Mole of NaCl = 0.5mol

mass of HCl = ?

molar mass of HCl = H + Cl = 1+ 35=36

mole of HCl = mass /molar mass

0.5= mass/36

mass = 0.5×36 = 18 grams

Answer:

1/6 kg

Explanation:

90 bean seeds is 15kg

1 bean seeds is 15/90 = 1/6 kg

Answer: 0.166 kg

90 bean seeds --> 15kg

1 bean seed --> 15/90 which is 0.166 kg

Brainliest pwease if it is correct!

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HCl, HI, \(H_{2}SO_{4}\), LiCl, and KI are all classified as acids. Acids are substances that can donate protons (H+) in a chemical reaction.

These compounds are characterized by their ability to increase the concentration of hydrogen ions in an aqueous solution.

HCl (hydrochloric acid), HI (hydroiodic acid), and \(H_{2}SO_{4}\) (sulfuric acid) are strong acids, meaning they completely dissociate in water, releasing a large number of H+ ions.

LiCl (lithium chloride) and KI (potassium iodide) are examples of salts that can dissociate in water, producing H+ ions, albeit to a lesser extent.

These compounds exhibit acidic properties and can react with bases or neutralize alkaline substances.

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Answer:

78tjg7jijihhh

Explanation:

Answer: In a pure metal, there are atoms that are surrounded by free moving valence electrons in which they move from one part of metal to another part . There for we can conclude that pure metals are held together by things called metallic bonds and due to attraction between the mobile valence electrons and the positively charged metal ions.

Explanation:

The ability to be drawn into thin sheet is called malleability. The ability to be drawn into thin wires is called ductility. Therefore, the metallic bonds is between metals and metals.

Metallic bonding is a type of chemical bonding that rises from the electrostatic attractive force between conduction electrons and positively charged metal ions.

Covalent bonds are not strong bond. They can not have malleability and ductility. Ionic bonds are very strong bond. These are too not malleable or ductile. Lewis structure is used to show valence electron of every element in a molecule so, it has nothing to do with malleability and ductility. Due to metallic bonding, there is high melting and boiling point.

Therefore, the metallic bonds is between metals and metals.

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The triple helix of collagen is arranged in such a way that every third position has to be glycine due to its unique structure and amino acid composition. The collagen molecule consists of three polypeptide chains, each forming an alpha helix, which then intertwine to create a triple helix structure.

Step 1: Understand the role of glycine in collagen
Glycine is the smallest amino acid, and its presence at every third position allows the three alpha helices to pack closely together, maintaining the stability of the triple helix structure.

Step 2: Recognize the amino acid sequence pattern in collagen
The amino acid sequence in collagen typically follows a pattern of Gly-X-Y, where Gly is glycine, and X and Y can be any other amino acids (often proline and hydroxyproline, respectively).

Step 3: Visualize the arrangement of the triple helix
The three polypeptide chains coil around each other in a right-handed helical structure, with the glycine residues from each chain aligning at the center of the triple helix. This arrangement facilitates tight packing and stability of the collagen molecule.

In conclusion, the triple helix of collagen is arranged so that every third position is glycine because its small size enables the close packing of the three helices, providing stability to the overall structure.

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Answer:

bla bla bla bla hahahhaa jokers

Answer:

On contact with ice, calcium chloride forms brine rapidly, which lowers the freezing point of water and melts snow and ice quickly. Calcium chloride forms brine faster than other ice melters because its hygroscopic properties actually cause it to attract moisture from its surroundings

Explanation:

HOPE IT WILL HELP YOU

A. n = 105 lines/mm = 105000 lines/m

d*sin θ  = m*λ

(1/105000) * sin θ = 1*498*10^-9 ⇒     θ =  3.0 degree

Also  (1/105000) * sin θ = 1*569*10^-9 ⇒     θ =  3.43 degree

Δθ = 3.43° – 3.0°

Δθ = 0.43°

b) Chromatic Resolving power, R = λ / Δλ

λ  / Δλ  =  m (width) n

589 /0.59 = 2 (width) (105000)

Width = 4.75 mm

Diffraction gratings can split beams of different wavelengths into a spectrum of related lines through the principle of diffraction. In certain directions, only waves of certain wavelengths have obtained the rest are destroyed by their respective interference. other.

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Answer:

here u go! ................

Answer:

Hope this is ok :))

Explanation:

Answer:

mol is a measurement of large amounts so big

Answer:

See explanation below

Explanation:

In order to do this, you are missing two important data, which are the initial temperatures of the water and the rod.

For practical purposes, I will assume this data, and then you'll just replace the procedure with your data to get an accurate result.

So, for this exercise, I will assume that the rod of Chromiun was heat to 100 °C and then cooled with water at 20 °C, so the final temperature is 54.5 °C.

To get the specific heat, we need to use the following expression:

q = m.C.ΔT  (1)

Where:

q: Heat of the substance/compound

m: mass

C: specific heat

ΔT: Difference of temperature of the mixture.

With this expression, we need to calculate first the heat of the water, because:

q₁  + q₂ = 0

Therefore, with the value of the transfered heat, we can determine later the specific heat. So, As we have the specific heat of water which is 4.18 J/g °C, and the temperature and mass, we can determine the heat of the mixture:

ΔT = 54.5 - 20 = 34.5 °C

q₁ = 35 * 4.18 * 34.5

q₁ = 5047.35 J

Now, we can determine the specific heat of the rod:

q₁ = -q₂

-5047.35 = 323.98 * (54.5 - 100) * C

-5047.35 = -14741.09C

Hope this helps

Answer:

Boron Carbonate; B₂(CO₃)₃

Explanation:

For names, carbonide does not exist; that rules out the first option. Carbide refers to just a carbon atom, not carbon and oxygen as in the polyatomic ion carbonate. That rids us of the third option. We are left with boron carbonate with the formula BCO or boron carbonate with the formula B₂(CO₃)₃.

Recall the carbonate polyatomic ion's formula: CO₃²⁻

Thus BCO cannot be the formula.

Option 4 is your answer, Boron Carbonate; B₂(CO₃)₃.

To further check your answer, observe the oxidation states of boron and the polyatomic ion carbonate. Boron can exist in oxidation states of either 2+ or 3+, and carbonate is only 2-; in this formula, boron will exhibit a 3+ state to balance out with carbonate.

2x3+ = 6+; 3x2- = 6-

6+ + 6- = 0; balanced

The electrons are first placed in the higher energy level orbitals before pairing up. The chromium ion (Cr2+) has a d4 configuration with six water (H2O) ligands.

Since there are four unpaired electrons in the t2g orbitals, the complex has a magnetic moment of 4.9 BM (Bohr magnetons) which indicates that it is paramagnetic. Therefore, the main answer is 4 unpaired electrons.
1. Determine the oxidation state of Cr in the complex.
2. Determine the electron configuration of Cr in that oxidation state.
3. Count the number of unpaired electrons.

Step 1: Oxidation state of Cr
[Cr(H2O)6]2+ has a charge of +2, so the oxidation state of Cr is +2.
Step 2: Electron configuration of Cr
Cr has an atomic number of 24, so its electron configuration is [Ar]3d5 4s1. In the +2 oxidation state, it loses two electrons, leaving [Ar]3d4.
Step 3: Count unpaired electrons

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Answer: 3.0 kJ × 1 mol/40.65 kJ× 18.02 g/mol × 1 mL/1 g= 1.3 mL

Answer:

Carbon

Name: Carbon

Symbol: C

Number of protons: 6

Number of neutrons: 6 or 7 (Carbon has two stable isotopes with 6 or 7 neutrons)

Number of electrons: 6

Sodium

Name: Sodium

Symbol: Na

Number of protons: 11

Number of neutrons: 12 or 13 (Sodium has one stable isotope with 12 neutrons, and another with 13 neutrons)

Number of electrons: 11

Helium

Name: Helium

Symbol: He

Number of protons: 2

Number of neutrons: 2

Number of electrons: 2

Chlorine

Name: Chlorine

Symbol: Cl

Number of protons: 17

Number of neutrons: 18 or 20 (Chlorine has two stable isotopes with 18 or 20 neutrons)

Number of electrons: 17

Gold

Name: Gold

Symbol: Au

Number of protons: 79

Number of neutrons: 118 (Gold has only one stable isotope with 118 neutrons)

Number of electrons: 79

A reaction produces 14.2 grams of a product. The theoretical yield of that product is 17.1 grams. The true statements are (E) The actual yield of the product is 14.2 grams and (C) The percent yield of the product is 83.0%.

The actual yield refers to the amount of product obtained in the reaction, which is given as 14.2 grams. It represents the experimental result of the reaction.

The percent yield is a measure of how efficiently the reaction produces the desired product. It is calculated by dividing the actual yield by the theoretical yield (17.1 grams) and multiplying by 100. In this case, the percent yield is approximately 83.0%.

The other statements (A, B, D, F) are not true. The percent yield cannot be equal to the actual yield, and it cannot exceed 100%.

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Complete question :

A reaction produces 14.2 grams of a product. The theoretical yield of that product is 17.1 grams. Which of the statements are true? Select 2 that apply.

A. The percent yield of the product is 14.2%.

B. The percent yield of the product is 17.1%.

C. The percent yield of the product is 83.0%.

D. The percent yield of the product is 120.0%.

E. The actual yield of the product is 14.2 grams.

F. The actual yield of the product is 17.1 grams.

Answer:

Flerovium

Explanation:

Answer:

Fl or flerovium. Atomic number is the number above the element on a periodic table.

The 50% concentration of the very last solution is a result of mixing the ninety five% concentration with water, that's 0% concentration.

Multiply the concentration of every liquid instance by the 0 of ml you may use, add these and divide by means of the overall ml to get 50%

X = the range of ml of the 95% alcohol combination

Y = the variety of ml of water

X + Y = 855

{.95·X + (0)(Y } / 855 = .50

once more, the zero above represents the water that's 0% attention

.95X / 855 = .50

.95X = 427.50

X = 450

plug 450 into the equation X + Y =855

450 + Y =855

Y = 405

Hence, 450 ml of the ninety-five% solutions and 405 ml of water.

The concentration of a substance is the quantity of solute found in a given amount of solution. Concentrations are normally expressed in terms of molarity, defined because of the variety of moles of solute in 1 L of answer.

The Concentration of an answer is a measure of the quantity of solute that has been dissolved in a given amount of solvent or answer. A concentrated answer is one that has a rather huge quantity of dissolved solute.

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No, it does not pass the "fat pencil" test. Therefore, a normal distribution is not a reasonable model. Option B is the correct answer.

The "fat pencil" test is a quick visual check to determine if a dataset can be reasonably approximated by a normal distribution. In this case, the pH readings of wastewater show a significant deviation from a normal distribution. The presence of several low pH values (1.0) and a few high pH values (10.0, 10.5, 11.4) indicate a non-normal distribution with skewness and potential outliers. Therefore, it is not reasonable to model these data using a normal distribution.

Option B is the correct answer.

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Metals can be removed from ores by reduction – the deletion of oxygen or forming a metal element from a compound.

Metal is extracted from mashed ore by one of two major methods: smelting or electrolysis. Smelting uses heat to discrete the valuable metal from the rest of the ore. Smelting usually needed a reduction agent, or another chemical, to separate metal from its ore.

Isolation of metal from concentrated Ore – Here the ore is changed to its oxide form and then reduced. The steps involved are either scorching or roasting and then heating with a reducing agent.

So we can conclude that trade extraction of metals from minerals is usually practiced by dump leaching, heap leaching, tank leaching, or pushed leaching.

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Answer:

It is the site where oxygen combines with small molecules of glucose and releases large amounts of energy

Explanation:

Answer

The new substances often have different combinations of atoms different from the reactants.

Explanation

The reactants and the new substances in a chemical reaction contain the same atoms, but they are rearranged during the reaction. As a result, the atoms end up in different combinations in the new substances. This makes the products new substances that are chemically different from the reactants.

The bond order for a second-period diatomic particle containing five electrons in antibonding molecular orbitals and eight electrons in bonding molecular orbitals is 1.5

Bond order is defined as the number of electrons in bonding molecular orbitals minus the number of electrons in antibonding molecular orbitals divided by two. As a result, we may determine the bond order of this diatomic particle by the formula: Bond order = (number of bonding electrons - number of antibonding electrons) / 2

Bond order = (8 - 5) / 2

Bond order = 1.5.

This diatomic molecule, according to the bond order, is a stable molecule since the bond order is greater than 1, indicating that it is a double bond. The molecule has an overall bond strength that is greater than a single bond, but not as strong as a triple bond. So therefore he bond order for a second-period diatomic particle containing five electrons in antibonding molecular orbitals and eight electrons in bonding molecular orbitals is 1.5

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