Substances A₂, B₂, and C₂ can all act as oxidizing agents. In solution, A₂ is green, B₂ is yellow, and C₂ is red. In the reactions in which they participate, they are reduced to A,B, and C ions, all of which are colorless. When a solution of B2 is mixed with one containing C to red. ions, the color changes from yellow a. Which species is oxidized? Which is reduced? When a solution of B2 is mixed with one containing A ions, the color remains yellow. Which species is a better oxidizing agent, B₂ or A₂ ?
Which species is a better oxidizing agent B₂ or C₂?
Arrange A₂, B₂, and C₂ in order of increasing strength of oxidizing agent. weakest strongest

Answer:

6 neutrons

Explanation:

6 neutrons

Boron having an atomic number of 5 means that it will have 5 protons. 11 atomic mass units in total. Neutrons also have a atomic mass unit of 1. So there are 6 neutrons

Answer:

Reduce, reuse, and recycle your waste and trash. Protecting the environment helps protect the wetlands, especially since trash can make its way into the water. The best and easiest way to protect the environment is by limiting your household waste.

Answer:

3.5ML

Explanation:

At the constant pressure, the final volume of the carbon dioxide gas was equal to 4.62 ml at a temperature of 0ºC.

Charles's law can be explained as when the pressure of the gas is kept constant, the volume of gas is directly proportional to the temperature of a gas.

The volume of the gas and the temperature of the gas have a direct relationship according to this law.

Therefore, V∝ T

or    V₁/T₁ = V₂/T₂                                               ....................(1)

Given, the initial temperature of the CO₂ gas, T₁ = 22 ºC

T₁ = 22 + 273 = 295 K

The final temperature of the CO₂ gas, T₂ = 0ºC

T₂ = 0 + 273 = 273 K

The initial volume of the gas, V₁ = 5 ml

Substitute the value of V₁, T₁, and T₂ in equation (1 ) to get final volume of CO₂ gas:

5/295 = V₂/273

V₂ = 4.6 ml

Therefore, the final volume of the gas is equal to 4.6 ml at 0 ºC, when there is no change in the pressure.

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Answer:

a) To determine the limiting reactant, we need to compare the amount of product that can be produced by each reactant. To do this, we need to convert the mass of each reactant to moles.

For C3H7OH:

moles = mass / molar mass = 8 g / 60.1 g/mol = 0.133 mol

For O2:

moles = mass / molar mass = 4 g / 32 g/mol = 0.125 mol

According to the balanced equation, 2 moles of C3H7OH react with 9 moles of O2 to produce 6 moles of CO2. Therefore, for 0.133 mol of C3H7OH, we need:

moles of O2 = (9/2) x 0.133 mol = 0.597 mol

Since we only have 0.125 mol of O2, it is the limiting reactant. Therefore, O2 is the limiting reactant.

b) C3H7OH is the excess reactant.

c) Using the balanced equation, we can see that 2 moles of C3H7OH react with 9 moles of O2 to produce 6 moles of CO2. Therefore, for 0.125 mol of O2, we can produce:

moles of CO2 = (6/9) x 0.125 mol = 0.083 mol

d) The molar mass of CO2 is 44.01 g/mol. Therefore, the mass of CO2 produced is:

mass of CO2 = moles of CO2 x molar mass of CO2

mass of CO2 = 0.083 mol x 44.01 g/mol = 3.65 g

e) To calculate how much excess reactant is used, we need to first determine how much of the excess reactant is present:

moles of C3H7OH = mass / molar mass = 8 g / 60.1 g/mol = 0.133 mol

moles of C3H7OH needed = (2/9) x moles of O2 = (2/9) x 0.125 mol = 0.028 mol

mol of excess C3H7OH = moles of C3H7OH present - moles of C3H7OH needed

mol of excess C3H7OH = 0.133 mol - 0.028 mol = 0.105 mol

moles of O2 needed = (9/2) x mol of excess C3H7OH = (9/2) x 0.105 mol = 0.473 mol

moles of O2 used = moles of limiting reactant = 0.125 mol

moles of excess C3H7OH used = (1/2) x moles of O2 used = (1/2) x 0.125 mol = 0.0625 mol

f) To calculate how much excess reactant remains, we need to subtract the moles of excess reactant used from the initial moles of excess reactant:

mol of excess C3H7OH remaining = 0.105 mol - 0.0625 mol = 0.0425 mol

The mass of excess reactant remaining can be calculated as follows:

mass of excess C3H7OH remaining = mol of excess C3H7OH remaining x molar mass of C3H7OH

mass of excess C3H7OH remaining = 0.0425 mol x 60.1 g/mol = 2.55

Water 3.0 deals mainly with sewage treatment. The primary aim of this project is to reduce the harmful impacts of chemical pollutants from industrial and agricultural activities on natural water resources.

Currently, used wastewater treatment technologies can break down some of the chemicals in wastewater but not all of them. Chemicals that are not broken down are referred to as persistent organic pollutants. These chemicals persist in the environment for long periods, and they can cause severe damage to aquatic life and human health.
Currently, the primary challenge facing water treatment technologies is the removal of persistent organic pollutants such as pesticides, pharmaceuticals, and endocrine-disrupting chemicals from wastewater.

These pollutants are generally water-soluble and resist microbial degradation, making them hard to remove from wastewater using current water treatment technologies. For example, conventional activated sludge treatment used in wastewater treatment plants does not remove some persistent organic pollutants from wastewater.
Failure to remove these pollutants from wastewater can have significant environmental and health impacts.

For example, pharmaceutical chemicals can cause antibiotic resistance, while endocrine-disrupting chemicals can cause birth defects, cancer, and other health problems.

Therefore, there is a need to improve wastewater treatment technologies to remove persistent organic pollutants from wastewater.
In conclusion, wastewater treatment technologies can break down some chemicals but not all. Chemicals that are not broken down are persistent organic pollutants and pose a significant risk to the environment and human health. Therefore, it is important to develop wastewater treatment technologies that can remove these pollutants from wastewater.

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Answer:

Because it is the same element but has different atomic mass

Answer: When the enthalpy of this overall chemical equation is calculated, the enthalpy of the second intermediate equation is halved and has its sign changed.

Explanation:

Hess’s law of constant heat summation states that the amount of heat absorbed or evolved in a given chemical equation remains the same whether the process occurs in one step or several steps.

According to this law, the chemical equation is treated as ordinary algebraic expressions and can be added or subtracted to yield the required equation. This means that the enthalpy change of the overall reaction is equal to the sum of the enthalpy changes of the intermediate reactions.

The overall chemical reaction follows:

\(CaO(s)+CO_2\rightarrow CaCO_3(s)\)     \(\Delta H^o_{rxn}=?\)

The intermediate balanced chemical reaction are:

(1) \(Ca(s)+CO_2(g)+\frac{1}{2}O_2(g)\rightarrow CaCO_3(s)\)    \(\Delta H_1=-812.8kJ\)  

(2) \(2Ca(s)+O_2(g)\rightarrow 2CaO(s)\)     \(\Delta H_2=-1269kJ\)

The expression for enthalpy of the reaction follows:

\(\Delta H^o_{rxn}=[1\times (\Delta H_1)]+[\frac{1}{2}\times (-\Delta H_2)]\)

Hence, when the enthalpy of this overall chemical equation is calculated, the enthalpy of the second intermediate equation is halved and has its sign changed.

Answer:

A. is halved and has its sign changed.

Explanation:

just took the test on edge

The difference between the number of valence electrons an isolated atom of that element would have and the number of electrons it actually has in the molecule is defined as the formal charge on that atom in the molecule.

The formal charge is computed as follows:

Formal Charge = (Number of lone pair electrons + Number of bonding electrons / 2) Valence Electrons

The oxygen atom has six valence electrons in the structure you provided, four of which are bonding electrons and two of which are lone pair electrons. The formal charge on the oxygen atom is calculated as follows:

Formal Charge = 6 minus (2 + 4 / 2) = 6 minus (2 + 2) = 6 minus 4 = 2 minus 4 = -2

As a result, the oxygen atom in the structure has a formal charge of -2

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The Nitrogen-13 has a half-life of 10 minutes0.250 g  of a 200 mg sample would remain after 30 minutes .

Calculation :

Determine the remaining mass of the substance,

mf if the initial mass is mi = 2.00 g. After 30 minutes, 30 minutes/10 minutes = 3 half-lives have passed, so the residual mass is reduced by a factor of i/2³. Calculate the residual mass of a substance using the formula, mf=mi×1/2³. We proceed with the solution.

mf=mi×1/2³

mf=2.00g/8

=0.250g

Half-life (symbol t½) is the time it takes for a (substance) quantity to reduce its original value by half. The term is often used in nuclear physics to describe how quickly unstable atoms radioactively decay or how long stable atoms survive.

The term is also used more generally to characterize any type of exponential (or rarely non-exponential) decay. For example, medicine is concerned with the biological half-life of drugs and other chemicals in the human body. The opposite of half-life (when growing exponentially) is doubling time.

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Extensive properties, such as mass and volume, depend on the amount of matter that is being measured. ... Both extensive and intensive properties are physical properties, which means they can be measured without changing the substance's chemical identity

Answer: There are 576.46 number of grams present in 16.95 mol hydrogen peroxide \((H_{2}O_{2})\).

Explanation:

Number of moles is defined as the mass of substance divided by its molar mass.

The molar mass of \(H_{2}O_{2}\) is 34.01 g/mol. Hence, mass of hydrogen peroxide present in 16.95 moles is calculated as follows.

\(Moles = \frac{mass}{molarmass}\\16.95 mol = \frac{mass}{34.01 g/mol}\\mass = 576.46 g\)

Thus, we can conclude that there are 576.46 number of grams present in 16.95 mol hydrogen peroxide \((H_{2}O_{2})\).

Answer:

charge of copper.. ........mark me brainlest

The repeating monomer unit of polyglycine is simply the amino acid glycine. The chemical structure of glycine is:

H

|

H2N — C — COOH

|

H

The polymerization of glycine involves the condensation of the amino group (-NH2) of one glycine molecule with the carboxyl group (-COOH) of another glycine molecule, releasing a molecule of water (H2O) in the process. The resulting bond is called a peptide bond, and it connects the carbon atom of one glycine molecule to the nitrogen atom of the other glycine molecule.

The repeating monomer unit of polyglycine can be represented as:

H          H          H

|          |          |

H2N — C — CO — NH — C — CO — NH — C — COOH

|                               |

H                               H

Note that the NH group on the left side of the monomer unit represents the amino group of one glycine molecule, and the CO group on the right side represents the carboxyl group of the other glycine molecule. This pattern repeats indefinitely to form the polyglycine polymer.

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Answer:

Brainliest pls

Explanation:

shows the three main types of evolution: divergent, convergent, and parallel evolution.

Divergent: tending to be different or develop in different directions.

Convergent: coming closer together, especially in characteristics or ideas.

Parallel evolution:  implies that two or more lineages have changed in similar ways

Answer:

An element contains just one type of atom. A compound contains two or more different atoms joined together. A mixture contains two or more different substances that are only physically joined together, not chemically. A mixture can contain both elements and compounds.

The equation that has been the representation of the decomposition reaction has been \(\rm Li_2CO_3\;\rightarrow\;Li_2O\;+\;CO_2\).

The chemical reaction has been defined as the reaction in which the chemical structure, composition and properties of the substances changes.

The chemical reaction has been given as the synthesis, decomposition and displacement reaction.

The chemical reaction in which there has been formation of a new product has been the synthesis reaction. The reaction in which the reactant has been breakdown into the constituent substances has been the decomposition reaction.

The reaction in which the less reactive element has been displaced by the more reactive element has been the displacement reaction.

The following reactions have been categorized as:

The reactant has been broken down into products. It has been a decomposition reaction.

There has been replacement of H by Zn. Thus, it has been a displacement reaction.

The reactants combine to form a new product. Thus, it has been a synthesis reaction.

The reaction has been the breakdown of glucose in the presence of oxygen. It has been a degradation reaction.

Thus, the equation that has been the representation of the decomposition reaction has been \(\rm Li_2CO_3\;\rightarrow\;Li_2O\;+\;CO_2\).

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Which equation is a decomposition reaction?

A. Li2CO3 Right arrow. Li2O + CO2

We have that the bond angles that are closest to the actual values for the h-n-c and o-c-o bond angles are

Generally, In H-N-C bond nitrogen has Sp3 hybridization, it will have the angle 109.5 degrees.

In O-C-O bond C atom has sp^2 Hybridization so it will have the angle by 120 degrees.

Therefore,bond angles that are closest to the actual values for the h-n-c and o-c-o bond angles are

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Answer:

the answer is 4.9×10-10M

Answer: Level 1's answer is D/ Making observations. The second one is it must restate the question/ B. No. 3:variable (often denoted by x ) whose variation does not depend on that of another. No.4 IS Controlled Vari

Explanation:

As each ice cube contains one mole of water, you would need at least 44.4 ice cubes to cool the liquid water from 20°C to 0°C

To solve this problem, we need to use the equation:
Q = m × c × ΔT
where Q is the amount of heat transferred, m is the mass of the substance, c is the specific heat capacity, and ΔT is the change in temperature.
We can first calculate the amount of heat that needs to be transferred from the liquid water to the ice cubes:
Q = m × c × ΔT
Q = 800.0 g × 4.184 J/g°C × (-20°C)
Q = -67,072 J
The negative sign indicates that heat is leaving the liquid water and being absorbed by the ice cubes.
Next, we need to determine how many moles of water are in 800.0 g of liquid water:
n = m/M
n = 800.0 g ÷ 18.015 g/mol
n = 44.4 mol
Therefore, we need at least 44.4 ice cubes, each containing one mole of water, to cool the liquid water from 20°C to 0°C. However, this assumes that all of the heat transferred from the liquid water is used to melt the ice cubes, and none of it is lost to the environment. In reality, we would need more ice cubes to account for any heat loss.

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The states of matter of the materials;

1) Dispersion forces - Yes

2) Hydrogen bonding - No

3) Ionic - No

4) Dispersion forces - No

5)  Dispersion forces - Yes

6) Ionic  - No

7) Hydrogen bonding - No

Sublimation is a physical process in which a substance transitions directly from its solid phase to its gaseous phase without passing through the intermediate liquid phase. In sublimation, the solid substance is heated, and the resulting gas molecules escape from the solid lattice structure without the need for melting.

One common example of sublimation is the process of dry ice. Dry ice is solid carbon dioxide (CO2) that sublimes at a temperature of -78.5 degrees Celsius (-109.3 degrees Fahrenheit). When dry ice is exposed to room temperature, it transitions directly from a solid to a gas, producing a fog-like effect.

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Answer: F

Explanation:

The enantiomeric excess (e.e.) of the mixture containing 5.70 g of (-)-glyceraldehyde and 2.0 g of (+)-glyceraldehyde is 48%.

To calculate the enantiomeric excess (e.e.) of a mixture, we need to determine the difference in the amounts of the two enantiomers and express it as a percentage of the total amount.

Given;

Mass of (-)-glyceraldehyde = 5.70 g

Mass of (+)-glyceraldehyde = 2.0 g

Calculate the total amount of glyceraldehyde in the mixture.

Total mass of glyceraldehyde = Mass of (-)-glyceraldehyde + Mass of (+)-glyceraldehyde

= 5.70 g + 2.0 g

= 7.70 g

Calculate the individual amounts of each enantiomer as a fraction of the total amount.

Fraction of (-)-glyceraldehyde = Mass of (-)-glyceraldehyde / Total mass of glyceraldehyde

= 5.70 g / 7.70 g

= 0.740

Fraction of (+)-glyceraldehyde = Mass of (+)-glyceraldehyde / Total mass of glyceraldehyde

= 2.0 g / 7.70 g

= 0.260

Calculate the enantiomeric excess (e.e.).

e.e. = (Fraction of (-)-glyceraldehyde - Fraction of (+)-glyceraldehyde) × 100%

= (0.740 - 0.260) × 100%

= 0.480 × 100%

= 48%

Therefore, the enantiomeric excess (e.e.) of the mixture containing 5.70 g of (-)-glyceraldehyde and 2.0 g of (+)-glyceraldehyde is 48%.

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The molar mass of  tin(II) chloride is: 84.9 g

Calculate the molar mass of  tin(II) chloride?

The number of moles n1 is thus:

n1= m1/M1 = 2.25 mol

According to the balanced reaction, the ratio by number of moles n of tin(II) chloride produced to the number of moles n1 of HF used is 1:2

As such, the number of moles of tin(II) chloride produced is :

n = 1/2 \(n_{1}\) = 0.45 mol

The molar mass of tin(II) chloride is:

M= A\(_{r}\)(Sn)+2A\(_{r}\)(Cl) = 188.7 g/mol

The mass m produced is thus:

m = nM

= 0.45 mol × 188.7 g/mol

≈ 84.9 g

Therefore, the molar mass of  tin(II) chloride is: 84.9 g.

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Answer:

The oxygen we breathe is not in atomic form. It is in its molecular form, which is two oxygen atoms joined together by bonds, and between its two atoms, this molecule has 16 protons, 16 electrons, and most commonly 16 neutrons. Answer 5: An oxygen atom contains eight protons.

Answer:

Quantum numbers of the outermost electron in potassium:

Explanation:

Refer to the electron configuration of a potassium atom. The outermost electron in a ground-state potassium atom is in the \(4s\) orbital (fourth \(s\) orbital.)

The quantum number \(n\) (the principal quantum number) specifies the main energy shell of an electron. This electron is in the fourth main energy shell (as seen in the number four in the orbital.) Hence, \(n = 4\) for this electron.

The quantum number \(l\) (the angular momentum quantum number) specifies the shape (\(s\), \(p\), \(d\), etc.) of an electron. \(l = 1\) for \(s\!\) orbitals (such as the one that contains this electron.

Quantum numbers \(n\) and \(l\) specify the shape of an orbital. On the other hand, the magnetic quantum number \(m_l\) specifies the orientation of these orbitals in space.

However, \(s\) orbitals are spherical. Regardless of the value of \(n\), the only possible \(m_l\) value for electrons in \(s\!\) orbitals is \(m_l = 0\).

The spin quantum number \(m_s\) distinguishes between the two electrons in an orbital. The two possible values of \(m_s \!\) are \((+1/2)\) and \((-1/2)\). Typically, the first electron in an orbital is assigned an upward (\(\uparrow\)) spin, which corresponds to \(m_s = (+1/2)\).

Answer:

D) Ba < Pb < P

Explanation:

Barium (Ba): 5,2117

Lead (Pb): 7,4167

Phosphorus (P): 10,4867

The strength of dipole interactions are mostly determined by the difference in electronegativity between the two bonded atoms i.e. option A is correct.

Electronegetivity is the measure of the ability of the atoms to attract the electrons towards itself. If there exists electronegativity difference between the atoms in a covalant comound, the electrons will be unequally shared. It will lead to the formation of partial positive and negetive charges. This ultimately causes dipole movement. Dipole movement is the seperation of electrical charges of the atoms in a molecule.

Greater the electronegativity difference amongst the atoms of a comound, stronger will be the dipole-dipole interaction between the molecules.

Therefore, the strength of dipole movement are mostly determined by the difference in electronegativity between the two bonded atoms.

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Answer: A mole of something means that there are 6.02 X 10^23 of that something. So, a mole of methane molecules is 6.02 X 10^23 methane molecules. So, 1.5 moles of methane will contain 1.5*(6.02 X 10^23) = 9.0 X 10^23 methane molecules

Explanation: