Students in a science class were shown three identical bulbs, each with a resistance of 50 Ω, connected to a 1.5-volt battery as shown in the diagram. The students were told to assume the resistance of the wire is 0 Ω and make a claim as to which bulb has the most current. Which student has correctly justified a claim?

Answer:7.92 m/s

Explanation:

A ball is thrown horizontally from the roof of a building 50. m tall and lands 45 m from the base then the ball's initial speed is 14.10 m/s

The rate of change of position of an object in any direction is called speed. Speed is scalar quantity.

speed = distance/time

s=d/t

Where,

s is the speed in m/sec

d is the distance travaled in m

t is the time taken in sec

Given that in the question ball travel a height from building of 50 m to a distance 45 m from the base so total distance travelled is given as 45 m.

Body is travelling downward under the influence of gravity.

Using equation of motion under gravity,

y = ut + ½gt² , where u = 0 m/s in y direction  and

y = ½gt²

t² = 2y / g

t² = 2*50/9.8

t  =  3.19 sec

ball's initial speed in x direction is given as

u = 45/3.19

u= 14.10 m/sec.

The balls initial speed is given as 14.10 m/sec.

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Round-nosed bullets with low velocities are specifically designed for improved accuracy and safety in target shooting and hunting scenarios. The round-nosed shape reduces air resistance, allowing for stable trajectory and accuracy at lower velocities. They are also safer for shooting in close quarters and reduce the risk of over-penetration.

Round-nosed bullets with low velocities are specifically designed for certain purposes in firearms. These bullets are commonly used in target shooting and hunting scenarios. The round-nosed shape of the bullet helps to reduce air resistance, allowing it to maintain a stable trajectory and accuracy at lower velocities. This makes them suitable for shooting at shorter distances or when precision is required.

Additionally, the low velocity of these bullets reduces the risk of over-penetration, making them safer for shooting in close quarters or in situations where there may be a risk of unintended collateral damage. The round-nosed design also helps to transfer energy more efficiently upon impact, which can be beneficial for hunting applications.

Overall, round-nosed bullets with low velocities offer improved accuracy and safety in specific shooting scenarios.

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Answer:The answer is C: any fundamental force

Explanation:

A P E X

The speed of the bullet immediately before impact was 361.7 m/s.

The speed of the bullet immediately before impact can be calculated using the law of conservation of momentum and the work-energy theorem.

The impact of the bullet causes the wooden block to move with kinetic energy, which is then dissipated through kinetic friction as it slides to a stop.

The equation for this process is:Initial momentum = Final momentum(12.0 g)(v) = (12.0 g + 98 g)(v')where v is the initial speed of the bullet and v' is the final speed of the block and bullet after impact.

Using the work-energy theorem, we can relate the kinetic energy of the block and bullet to the work done by

kinetic friction:Initial kinetic energy = Work done by kinetic friction(1/2)(12.0 g + 98 g)(v')^2 = (0.650)(12.0 g + 98 g)(9.8 m/s^2)(7.5 m)

Solving for v' and substituting back into the initial momentum equation gives:

(12.0 g)(v) = (12.0 g + 98 g)(√[(0.650)(12.0 g + 98 g)(9.8 m/s^2)(7.5 m)] / (12.0 g + 98 g))v = √[(0.650)(12.0 g + 98 g)(9.8 m/s^2)(7.5 m)] / (12.0 g)v = 361.7 m/s

Therefore, the speed of the bullet immediately before impact was 361.7 m/s.

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Answer:

2n answer of 6

place it at the place of ?mark

The average angular acceleration of an object from t = 0.00s to t = 1.00s, with initial angular velocity 0 rad/s and final angular velocity 2 rad/s, is 2 rad/s².

To find the average angular acceleration (a_avg), we can use the formula:

\(a_{avg} = (\omega_f - \omega_i)\) / Δt

where \(\omega_f\) is the final angular velocity, \(\omega_i\) is the initial angular velocity, and Δt is the change in time.

Given:

\(\omega_i\) = 0 rad/s (initial angular velocity)

\(\omega_f\) = 2 rad/s (final angular velocity)

Δt = 1.00 s (time interval)

Using the formula, we can calculate \(a_{avg\):

\(a_{avg\) = (\(\omega_f - \omega_i\)) / Δt

= (2 rad/s - 0 rad/s) / 1.00 s

= 2 rad/s / 1.00 s

= 2 rad/s²

Therefore, the average angular acceleration of the object from t = 0.00s to t = 1.00s is 2 rad/s².

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The appropriate question is:

What is the average angular acceleration of an object from t=0.00s to t=1.00s also \(\omega_i\) = 0 rad/s (initial angular velocity), \(\omega_f\) = 2 rad/s (final angular velocity).

Answer:

True

Explanation:

Since acceleration is inversely proportional to mass, decreasing mass will make the object lighter, and thus easier to speed up. So acceleration increases as mass decreases and vice versa

Answer: TRUE                                                                        Explanation:Newton's second law of motion can be formally stated as follows: The acceleration of an object as produced by a net force is directly proportional to the magnitude of the net force, in the same direction as the net force, and inversely proportional to the mass of the object.

Answer:

F' = (4/9)F

Explanation:

The electrostatic force between two charged objects is given by Coulomb's Law:

F = kq₁q₂/r²   -------------------- equation (1)

where,

F = Electrostatic Force

k = Coulomb's Constant

q₁ = magnitude of first charge

q₂ = magnitude of second charge

r = distance between charges

Now, when the charges and distance altered as follows:

q₁' = 2q₁

q₂' = 2q₂

r' = 3r

Then,

F' = kq₁'q₂'/r'²

F' = k(2q₁)(2q₂)/(3r)²

F' = (4/9)kq₁q₂/r²

using equation (1):

F' = (4/9)F

False: Adjusting the test-mass riser along the platform changes the radius of the circular path.

What is circular path ?

A circular path is a path that follows a circular shape or loop, as opposed to a linear path which follows a straight line. It is a type of motion that is common in physics, engineering, and mathematics. In engineering, circular paths are often used to describe the motion of objects such as wheels, gears, and pulleys.

In mathematics, circular paths are commonly used to describe rotations, orbits, circles, and other types of curves. Circular paths can also be used in artwork, architecture, and design.

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Quantities are equal to the sum of the individual values for both the voltage and current in a serial circuit.

The obstruction to current flow in an electrical circuit is measured by resistance. The Greek letter omega () represents resistance, which is measured in ohms.

When two or more resistances are connected between two sites and each has a different current direction, the resistances are said to be connected in parallel. In such circuits, the branches cross at a common point, splitting the current and recombining it.

The voltage on the resistances will differ if they are linked in parallel, but both resistances will still produce the same amount of current.

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Scientist’s work is supported by this observation. The correct answer is : d. Aristotle

Which scientist’s work is supported by this observation?

Aristotle's work in physics is supported by this observation, as he proposed that heavier objects fall faster than lighter objects. Since both the large and small branches take the same amount of time to fall to the ground, it indicates that the weight of the branches does not affect the time it takes for them to fall. This supports Aristotle's theory that the speed of falling objects is independent of their weight. Aristotle proposed that objects fall at a constant speed regardless of their weight. This is due to the fact that the force of gravity is constant and it accelerates all objects at the same rate.

This is why both the large and small branches take the same amount of time to fall to the ground.

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Answer:

Why can no one eve give a correct answer

the real answer is Galileo

Explanation:

Answer: B

Explanation:

Your'e asking about how waves get closer and louder A it isn't moving so no, C it's not saying if it's near or not and D is going trough another procedure so that leaves B behind

The angle of incline of the hill above the horizontal is 8.81°.

Since the hill has a 15.5% grade is one that rises 15.5 m vertically for every 100.0 m of distance in the horizontal direction.

The tangent of the angle of the incline of the hill, Ф is

tanФ = vertical rise/horizontal distance = grade of hill

Now, the vertical rise = 15.5 m and the horizontal distance = 100.0 m

So, substituting the values of the variables into the equation, we have

tanФ = vertical rise/horizontal run

tanФ = 15.5 m/100.0 m

tanФ = 0.155

Taking inverse tan of both sides, we have

Ф = tan⁻¹(0.155)

Ф = 8.81°

So, the angle of incline of the hill above the horizontal is 8.81°.

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The particle will achieve the maximum positive x-coordinate when its velocity in the x-direction becomes zero.

1. To find the time it takes for the particle to reach the maximum positive x-coordinate, we can use the equation of motion in the x-direction:

x = ut + (1/2)at², where x is the displacement, u is the initial velocity, a is the acceleration, and t is the time. We know the initial velocity is 1.3 m/s and the acceleration in the x-direction is -5.9 m/s².

2. Setting x = 0 and solving the equation for t, we get:

0 = (1.3)t + (1/2)(-5.9)t². This is a quadratic equation which can be solved to find the time t.

3. Once we have the time t, we can substitute it back into the equation of motion to find the distance from the origin at this point. The equation becomes:

x = (1.3)t + (1/2)(-5.9)t²

To find the distance from the origin when the particle achieves the maximum positive x-coordinate, we need to find the time it takes for the particle to reach this point. Using the equation of motion in the x-direction, x = ut + (1/2)at², we can set x = 0 and solve for t. This gives us a quadratic equation:

0 = (1.3)t + (1/2)(-5.9)t².

Solving this equation will give us the time it takes for the particle to reach the maximum positive x-coordinate. Once we have the time, we can substitute it back into the equation of motion to find the distance from the origin.

The equation becomes:

x = (1.3)t + (1/2)(-5.9)t². By evaluating this equation, we can determine the distance traveled by the particle when it achieves the maximum positive x-coordinate.

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Answer:

roots

Explanation:

Answer:

A.

Explanation:

The amount of energy (in joules) required to warm 4.37 g of silver by ΔT degrees Celsius can be calculated using the equation Q = 1.0488 * ΔT.

The specific heat capacity (C) of a substance is the amount of energy required to raise the temperature of 1 gram of that substance by 1 degree Celsius. In this case, the specific heat capacity of silver is 0.24 J/g°C.

To calculate the energy required to warm 4.37 g of silver, we need to multiply the mass (m) by the specific heat capacity (C) and the change in temperature (ΔT). The change in temperature is not provided in the question, so we'll assume it is given.

Let's assume the change in temperature is ΔT°C. The formula to calculate the energy (Q) is:

Q = m * C * ΔT

Substituting the given values:

Q = 4.37 g * 0.24 J/g°C * ΔT

The units of grams cancel out, and we are left with:

Q = 1.0488 J/°C * ΔT

So, the amount of energy (in joules) required to warm 4.37 g of silver by ΔT degrees Celsius can be calculated using the equation Q = 1.0488 * ΔT.

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Using Runge-Kutta 2nd order Heun's method, the speed (w) at t = 0.8s is approximately 0.0081.

Given:

Voltage input (V) = 30V

Initial speed (w) = 0

Step size (h) = 0.4s

Time at which speed is to be determined (t) = 0.8s

We need to determine the speed (w) at t = 0.8s using Heun's method.

We have k₁ = f(t₁, W₁) = 0.02 + 0.06w₁ (using the given equation)

At t = 0 and w = 0 (initial conditions), we have:

k₁ = 0.02 + 0.06(0) = 0.02

We have k₂ = f(t₁ + h, w₁ + k₁h) = 0.02 + 0.06(w₁ + 0.02h)

So, at t = 0.4s and w = 0 (initial conditions), we have:

k₂ = 0.02 + 0.06(0.02 * 0.4) = 0.02 + 0.00048 = 0.02048

So, W₂ = w₁ + (k₁ + k₂)(h/2)

   = 0 + (0.02 + 0.02048)(0.4/2)

   = 0.04048(0.2)

   = 0.008096

Therefore, using Runge-Kutta 2nd order Heun's method, the speed (w) at t = 0.8s is approximately 0.0081.

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The complete question is:

The speed of a motor supplied with a voltage input of 30V, assuming the system is without damping, can be expressed as 30 = (0.02)+(0.06)w dt If the initial speed is zero and a step size of h = 0.4 s, determine the speed w at t = 0.8 s by using the Runge-Kutta 2nd order Heun's method. Heun's method: Wi+1=W₁ = w₁ + (-/-^₁ + = -K ₂ ) h where, k₁ = f(t₁, W₁) and k₂ = f(t₁ + h, w₁ + k₁h), the speed (w) at t = 0.8s is approximately 0.0081.

Answer:

true

Explanation:

it is right

In Fluorescence spectroscopy, the absorption wavelength is also called: excitation wave length. The correct option is b.

In fluorescence spectroscopy, the absorption wavelength refers to the specific wavelength of light that is absorbed by a fluorophore, which is a molecule capable of fluorescence. When a fluorophore absorbs light at its absorption wavelength, it undergoes an electronic transition, moving from a ground state to an excited state.

The absorbed energy promotes an electron to a higher energy level. This excitation is temporary and unstable, and the electron quickly returns to its ground state, releasing the excess energy as fluorescence. The emitted light has a longer wavelength than the absorbed light, giving rise to the characteristic fluorescence spectrum.

The term "emission wavelength" refers to the wavelength of the light that is emitted during fluorescence. It corresponds to the energy difference between the excited state and the ground state of the fluorophore. Therefore, the emission wavelength is distinct from the absorption wavelength.

On the other hand, the term "excitation wavelength" refers to the specific wavelength of light that is required to excite the fluorophore and induce fluorescence. This is the wavelength at which the fluorophore has maximum absorbance and is capable of absorbing light energy.

So, the correct answer is (b) Excitation wavelength. The absorption wavelength and excitation wavelength are equivalent terms in fluorescence spectroscopy, as they both refer to the wavelength of light required to initiate fluorescence in a fluorophore. The emission wavelength, on the other hand, refers to the wavelength of light emitted during fluorescence.

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An electric field is produced when a wire is bent into a circular shape lying flat on the table. The magnitude and direction of the electric field produced by the wire at a point 4.00 cm directly above its center can be found using the Biot-Savart law.

The formula for the Biot-Savart law is given below;

\(`dB = µI(dl × r) / (4πr²)\)`Where dB is the magnetic field at a point, µ is the permeability of free space, I is the current, dl is the current element, r is the distance between the point and the current element, and θ is the angle between the vectors dl and r.

The wire is carrying a current I and has a radius R, which means that the current element can be expressed as `dl = R dθ`. The magnetic field at a point P located at a distance z above the center of the wire is given by;

\(`B = µI / 4π ∫ (R dθ / r² + z²)½`\)The angle between dl and r is 90° because the current element is perpendicular to the point.

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Answer:

64 ohms =R

Explanation:

R is directly proportional to V

R is inversely proportional to I(Current

2269 × 10-³ m can be written in scientific notation as follows: 2.269 × 10⁰.

Scientific notation is a method of writing, or of displaying real numbers as a decimal number between 1 and 10 followed by an integer power of 10.

It is an alternative format of such a decimal number immediately followed by E and an integer.

According to this question, 2269 × 10-³ metres is to be converted to scientific notation. We do this by shifting the decimal place backwards three times to obtain the following;

2.269 × 10⁰

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Answer:

B. compound

Explanation:

Because Salt (NaCl), sodium chloride, mineral substance of great importance to human and animal health, as well as to industry. The mineral form halite, or rock salt, is sometimes called common salt to distinguish it from a class of chemical compounds called salts.

Answer:

B and either C or D

Explanation:

The vector sum of the forces imposed by the other two particles is the net force acting on particle \(q_1\). By applying Coulomb's law, we may determine the size of the force \(q_2\) has on  \(q_1\):

A method called an experiment is used to test a hypothesis or educated estimate in order to confirm or deny it. In order to investigate novel occurrences or to confirm and validate accepted theories or principles, experiments are carried out.

\(F_{12} = (k*q1*q2)/(0.10m)^2\\\\F_{12}=(8.99*10^9 N*m^2/C^2)*(8*10^{-6} C)*(3.5*10^{-6} C)/(0.10m)^2\\\\F_{12}=2.8*10^{-4} N\)

In a similar manner, we can determine the strength of the force that \(q_3\) has on \(q_1\):

The vector sum of the two forces equals the net force acting on \(q_1\). The force due to  \(q_2\)  is directed to the right whereas the force due to \(q_3\)  is pointing to the left because  \(q_2\)  has a positive charge and \(q_3\)  has a charge that is negatively charged. Consequently, the net force on \(q_1\) is equal to and is to the right.

\(F_{net}=F_{12 }+ F_{13}\\\\F_{net}=2.8*10^{-4 N} + (-1.9*10^{-4 N})\\\\F_{net}=0.9*10^{-4} N.\)

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Answer:

its A

Explanation:

trust me i just took the test hope it helps

The statement that accurately explains the reactivity of the alkali metals is A. Alkali metals have very low density, which makes them very reactive, because they want to gain energy and become stable.

Alkali metals are elements in group 1 and they include Lithium (Li), Sodium (Na), Potassium (K), Rubidium (Rb), Cesium (Cs) and Francium (Fr).

So, the statement that accurately explains the reactivity of the alkali metals is A. Alkali metals have very low density, which makes them very reactive, because they want to gain energy and become stable.

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Answer:

It can be identified using physical properties such as density

Explanation:

Matter is any substance that has mass and takes up space. Therefore, it can be identified using physical properties such as density

Explanation:

We can identify matter by:

1.physical properties.

2.chemical properties.

Hope this helps...

Answer:

100 m

Explanation:

From the question,

R = Lρ/A.................... Equation 1

Where R = resistance of the wire, L = length of the wire, ρ = resistivity of the wire, A = cross sectional area of the wire.

But,

A = πr².................... Equation 2

Where r = radius of the wire.

Substitute equation 2 into equation 1

R = Lρ/πr²

Make L the subject of the equation

L = Rπr²/ρ...................... Equation 3

Given: R = 40 Ω, r = 5×10⁻⁴ m, ρ = 3.14×10⁻⁷ Ωm

Constant: π = 3.14

Substitute these values into equation 3

L = [40×3.14×( 5×10⁻⁴)²]/ (3.14×10⁻⁷)

L = 40×3.14×25×10⁻⁸/(3.14×10⁻⁷)

L = 100 m

Hence the length of the wire is 100 m