Answer:
Equilibrium.
Explanation:
Streams compensate for changes in their systems by adjusting other factors in order to return to equilibrium because so as to maintain their watershed. When the surface runoff move downslope, it also cause a concentration in small areas and create small channels of streams. These channels normally allow the flow of water during rainfall.
A solid sphere with a diameter of 0.20 m is released from rest; it then rolls without slipping down a ramp, dropping through a vertical height of h1 = 0.49 m. The ball leaves the bottom of the ramp, which is h2 = 1.31 m above the floor, moving horizontally.
(a) Through what horizontal distance d does the ball travel before landing?
answer in m
(b) How many revolutions does the ball make during its fall?
answer in rev
(a) To find the horizontal distance d that the ball travels before landing, we can use the equation d = (Vx)t, where Vx is the horizontal velocity of the ball and t is the time it takes for the ball to fall from the ramp to the floor.
First, we need to find the horizontal velocity of the ball when it leaves the ramp. Since the ball is rolling without slipping, we can use the equation V = ωR, where V is the linear velocity, ω is the angular velocity, and R is the radius of the ball. The radius of the ball is 0.20 m / 2 = 0.10 m.
Next, we need to find the angular velocity of the ball. We can use the equation ω = √(2gh/R), where g is the acceleration due to gravity (9.8 m/s^2), h is the vertical height that the ball drops (0.49 m), and R is the radius of the ball (0.10 m). Plugging in the values gives us:
ω = √(2(9.8)(0.49)/0.10) = 31.3 rad/s
Now we can find the horizontal velocity of the ball:
V = ωR = (31.3)(0.10) = 3.13 m/s
Finally, we can find the time it takes for the ball to fall from the ramp to the floor using the equation h = 0.5gt^2, where h is the vertical height (1.31 m) and g is the acceleration due to gravity (9.8 m/s^2). Rearranging the equation and plugging in the values gives us:
t = √(2h/g) = √(2(1.31)/9.8) = 0.52 s
Now we can find the horizontal distance d that the ball travels before landing:
d = (Vx)t = (3.13)(0.52) = 1.63 m
Answer: The ball travels 1.63 m before landing.
(b) To find the number of revolutions that the ball makes during its fall, we can use the equation θ = ωt, where θ is the angular displacement, ω is the angular velocity, and t is the time. The angular displacement is equal to the number of revolutions times 2π, so we can rearrange the equation to solve for the number of revolutions:
θ / 2π = ωt / 2π = (31.3)(0.52) / 2π = 2.59 rev
Answer: The ball makes 2.59 revolutions during its fall.
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Newton’s universal law of gravity tells us that F = G(m1m2/d2). Newton’s second law tells us that a = Fnet/m.
(a) With a bit of algebraic reasoning show that your gravitational acceleration toward any planet of mass M a distance d from its center is a = GM/d2.
(b) How does this equation tell you whether or not your gravitational acceleration depends on your mass?
D. c. why are all gases not
element.
Answer:
Explanation:
Comment
Elements are only those items found on the periodic table. There are just over a hundred different elements on the periodic table. Oxygen is one of them and it is also a gas.
However CO2 (Carabon Dioxide) is also a gas. It is not an element simply because it is made of two elements from the periodic table (Carbon and Oxygen). CO2 is a compound.
Answer:
Explanation:
because some gasses are compounds with multiple elements inside of it
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A spherical balloon has a radius of 6.95m and is filled with helium. The density of helium is 0.179 kg/m3, and the density of air is 1.29 kg/m3. The skin and structure of the balloon has a mass of 960kg . Neglect the buoyant force on the cargo volume itself. Determine the largest mass of cargo the balloon can lift.
Answer:
602.27 kg
Explanation:
The computation of the largest mass of cargo the balloon can lift is shown below:-
Volume of helium inside the ballon= (4 ÷ 3) × π × r^3
= (4 ÷ 3) × 3.14 × 6.953
= 1406.19 m3
Mass the balloon can carry = volume × (density of air-density of helium)
= 1406.19 × (1.29-0.179)
= 1562.27 kg
Mass of cargo it can carry = Mass it can carry - Mass of structure
= 1562.27 - 960
= 602.27 kg
a vector has a magnitude of 34 meters and an angle of 26 degrees what is the y-component of the vector? (i'd appreciate if anyone could answer this)
The y-component of the vector is approximately 14.67 meters.
To find the y-component of the vector, we need to use trigonometry. Given that the vector has a magnitude of 34 meters and an angle of 26 degrees, we can break down the vector into its x and y components.
Step 1: Identify the known values:
Magnitude of the vector (r) = 34 meters
Angle (θ) = 26 degrees
Step 2: Determine the y-component using trigonometry:
The y-component can be found using the formula:
y = r * sin(θ)
Step 3: Calculate the y-component:
Substituting the known values into the formula:
y = 34 * sin(26 degrees)
y ≈ 14.67 meters
Therefore, the y-component of the vector is approximately 14.67 meters.
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HElp meee
explain how to do this also
Answer:
\(\huge\boxed{\sf x = 18\°}\)
Explanation:
If ∠ABC and ∠DEF are complementary angles, this means they add up to 90 degrees.
So,
∠ABC + ∠DEF = 90°
72 + x = 90
Subtract 72 to both sides
x = 90 - 72
x = 18°
\(\rule[225]{225}{2}\)
How does the lens from which you view the world shape your approach to research inquiry?
Why is it important as a scholar-practitioner engaged in research to acknowledge your worldview ?
LEARNING RESOURCES Required Readings
Babbie, E. (2017). Basics of social research (7th ed.). Boston, MA: Cengage Learning.
Chapter 1, “Human Inquiry and Science”
Burkholder, G. J., Cox, K. A., Crawford, L. M., & Hitchcock, J. H. (Eds.). (2020). Research designs and methods: An applied guide for the scholar-practitioner. Thousand Oaks, CA: Sage.
Chapter 1, "Introduction to Research"
Chapter 2, “Philosophical Foundations and the Role of Theory in Research”
Acknowledging one's worldview as a scholar-practitioner is crucial as it influences research inquiry. It shapes research questions, methods, and interpretations. Recognizing biases and being open to diverse perspectives ensures reliable and valid research.
As a scholar-practitioner engaged in research, it is important to acknowledge your worldview because your worldview affects the approach you take to research inquiry. It shapes your research questions, methods, and interpretations. The lens through which you view the world is informed by your background, culture, experiences, and beliefs. Therefore, two scholars may approach the same research question differently based on their worldviews. For instance, a scholar from an individualistic culture may approach a research question on teamwork differently from a scholar from a collectivistic culture. The individualistic scholar may focus on the individual's contribution to the team, while the collectivistic scholar may focus on the team's contribution to the individual.To conduct research that is reliable and valid, it is crucial for the scholar-practitioner to acknowledge their worldview and recognize that it shapes their approach to research inquiry. By acknowledging their worldview, the scholar-practitioner can identify and manage their biases and take steps to minimize them. They can also be open to multiple perspectives and incorporate them into their research to enhance its credibility. In conclusion, acknowledging your worldview as a scholar-practitioner is essential for conducting research that is reliable and valid. It helps you identify and manage your biases and be open to multiple perspectives.For more questions on interpretations
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A circuit that has only one branch for electrons to follow is a(n) ____.
Question 1 options:
circuit diagram
electron circuit
parallel circuit
series circuit
Answer: series circuit
Explanation:
First 2 answers are garbage. In Parallel circuits electrons have 2 or more paths to follow. In Series circuits, there is only one path.
similarities and differences between a lunar eclipse and the disappearing sun. HELP FAST
Answer: A solar eclipse results when the moon passes in between the earth and the sun hiding the sun fully or partly for some time. A lunar eclipse occurs when the earth passes in between the moon and the sun casting its shadow on the moon and thus hiding it fully or partly for some time.
6. The image to the right shows a moment of inertia
demonstrator device. This device can spin its four arms
around its center. On each arm is a weight that can be
adjusted closer or farther from the center of rotation.
A student says, “Moving the weights away from the center
of mass does not change the moment of inertia, since the
total diameter of the device does not change." Do you
agree with this statement? Explain.
The moment of inertia is the rotational analog of mass, and it is given by
the product of mass and the square of the distance from the axis.
The moment of inertia changes as the position of the weight is changed, which indicates that; statement is incorrectReasons:
The weight on each arm that have adjustable positions can be considered as point masses.
The moment of inertia of a point mass is I = m·r²
Where;
m = The mass of the weight
r = The distance (position) from the center to which the weight is adjusted
Therefore;
The moment of inertia, I ∝ r²
Which gives;
Doubling the distance from the center of rotation, increases the moment of inertia by factor of 4.
Therefore, the statement contradicts the relationship between the radius of rotation and moment of inertia.
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What is the relationship of the wavelength of a
particle and its mass?
a
The wavelength of a particle cannot
be measured.
b They are directly related.
C
The mass of a particle does not affect
its wavelength.
d They are inversely related.
The relationship of the wavelength of a particle and its mass is they are inversely related.
Option D is correct.
What is de Broglie frequency condition?The link between a particle's mass and wavelength is provided by the de Broglie wavelength equation: = h/p,
where is the wavelength, h is the Planck constant, and p is the particle's momentum.
This condition shows that a molecule's energy is contrarily relative to its frequency. Because momentum (p = mv) is defined as the product of mass and velocity, we can also say that a particle's wavelength is inversely proportional to its mass.
What is the Wavelength?A wavelength is the distance between two identical points (adjacent crests) in consecutive cycles of a waveform signal that travels in space or down a wire. In wireless systems, its length is typically measured in meters (m), centimeters (cm), or millimeters (mm).
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Question attached in image below
A) Therefore, the amount of work performed by heart is \($2.9289 \times 10^{-3} \mathrm{~J}\)
b) Therefore, the power require is \($0.013313 \mathrm{~W}\)
c) Therefore, the efficiency of heart is\($0.2219 \%$.\)
What work is done by the heart?A) Calculate the amount of the work performed by the heart during the systole by using the following relation:
\($$\begin{aligned}W & =\frac{1}{2} m_b v^2 \\& =\frac{1}{2}\left(\rho_b A v\right) v^2 \\& =\frac{1}{2} \rho_b A v^3 \\& =\frac{1}{2} \rho_b\left(\frac{\pi}{4} d^2\right) v^3 \\& =\frac{1}{2} \times 1.057 \times 10^3 \times\left(\frac{\pi}{4} \times(0.029)^2\right) \times(0.2032)^3 \\& =2.9289 \times 10^{-2} \mathrm{~J}\end{aligned}$$\)
Therefore, the amount of work performed by heart is \($2.9289 \times 10^{-3} \mathrm{~J}$.\)
b) Calculate the power during systole by using the following relation:
\($$\begin{aligned}P & =\frac{W}{t} \\& =\frac{2.9289 \times 10^{-3}}{0.22} \\& =0.013313 \mathrm{~W}\end{aligned}$$\)
Therefore, the power require is \($0.013313 \mathrm{~W}$.\)
C) Calculate the efficiency of the heart by using the following relation:
\($$\begin{aligned}\eta & =\frac{P_{\text {out }}}{P_{\text {ov }}} \\& =\frac{0.013313}{6} \\& =0.0022188(0.2219 \%)\end{aligned}$$\)
Therefore, the efficiency of heart is\($0.2219 \%$.\)
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10. Liquids are poured into a container and separate. They form a green layer on
the bottom, a blue layer in the middle, and a red layer on the top. What's true about
the density of the liquids?
A. The red liquid is the least dense.
B. The green liquid is the least dense.
C. The blue liquid is the least dense.
D. They all have the same density.
Option A is true: the red liquid is the least dense.
What happens when different liquids are poured into a container?When different liquids are poured into a container, they will typically separate based on their densities. Liquids with higher densities will sink to the bottom, while liquids with lower densities will float on top.
In the scenario described in the question, we are told that the liquids have separated into three distinct layers: green on the bottom, blue in the middle, and red on top. Based on this layering, we can infer that the red liquid must be the least dense, since it is floating on top of the other two liquids.
Similarly, we can infer that the blue liquid is denser than the red liquid, but less dense than the green liquid, since it is sandwiched between them. And we can infer that the green liquid is the most dense, since it is at the bottom.
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A race car accelerates from rest to a velocity of +90 m/s over a distance of 423m. Determine the acceleration of the race car.
Answer:
9.57m/s²
Explanation:
Given parameters:
Initial velocity = 0m/s
Final velocity = 90m/s
Distance = 423m
Unknown:
Acceleration of the race car = ?
Solution:
To solve this problem, we should apply one of the appropriate motion equations;
V² = U² + 2as
Where V is the final velocity
U is the initial velocity
a is the acceleration
s is the distance
90² = 0² + 2 x a x 423
8100 = 846a
a = 9.57m/s²
A shaving or makeup mirror is designed to magnify your face by a factor of 1.40 when your face is placed 20.0cm in front of it
a) What type of mirror is it?
b) Describe the type of image that it makes of your face.
c) Calculate the required radius of curvature for the mirror.
Answer:
(a) convex mirror
(b) virtual and magnified
(c) 23.3 cm
Explanation:
The having mirror is convex mirror.
distance of object, u = - 20 cm
magnification, m = 1.4
(a) As the image is magnified and virtual , so the mirror is convex in nature.
(b) The image is virtual and magnified.
(c) Let the distance of image is v.
Use the formula of magnification.
\(m =-\frac{v}{u}\\1.4=-\frac{v}{-20}\\v =28 cm\)
Use the mirror equation, let the focal length is f.
\(\frac{1}{f}=\frac{1}{v}+\frac{1}{u}\\\frac{1}{f}=\frac{1}{28}+\frac{1}{20}\\\frac{1}{f}=\frac{28+20}{560}\\f=11.67cm\)
Radius of curvature, R = 2 f = 2 x 11.67 = 23.3 cm
1)What is the pressure at point D in kPa ?
2)Temperature at point D
3)What is the net work done on the gas as it is taken through four cycles?
4)What is the internal energy of the gas when it is at point A?
5)What is the total change in internal energy of this gas during four complete cycles?
The answer is 1) The pressure at point D is 80 kPa. 2) The temperature at point D is 800 K. 3) The net work done on the gas over four cycles is zero. 4) The internal energy of the gas at point A is 100 J. 5) The total change in internal energy during four complete cycles is zero.
The total change in internal energy of this gas during four complete cycles is zero. The given diagram represents the Carnot cycle involving four stages. The four stages of the Carnot cycle are reversible and follow an ideal gas that is placed in a cylinder with a movable piston.Let's solve each question asked one by one.1) From the graph, it can be observed that the pressure at point D is 0.08 M Pa, which is equal to 80 kPa. Hence, the pressure at point D in kPa is 80 kPa.2) Temperature at point D The isotherm at point D is about 800 K. Hence, the temperature at point D is 800 K.3) The net work done on the gas as it is taken through four cycles is zero because the Carnot cycle is a cycle that has four stages. In each cycle, the net work done is the area enclosed by the cycle. Therefore, for a complete cycle, the net work done is zero because the area enclosed is a loop.4) The internal energy of the gas when it is at point A is 100 J because the internal energy of the gas is directly proportional to the temperature and volume. Here, at point A, the temperature is 500 K, and the volume is 2 m³, so the internal energy of the gas when it is at point A is 100 J.5) The Carnot cycle is a reversible cycle that is used to determine the efficiency of heat engines. It is a closed cycle that does not involve any net energy exchange with the surroundings. Therefore, the total change in internal energy of this gas during four complete cycles is zero since the initial and final states are the same. Hence, the total change in internal energy of this gas during four complete cycles is zero.For more questions on the Carnot cycle, click on:
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Which two statements are true about redox reactions?
A.
They are single-replacement reactions.
B.
An acid gains an electron lost by a base.
C.
Electrons are both gained and lost.
D.
All types of reactions are redox reactions.
Answer:
C. Electrons are both gained and lost
Answer:
A. They are single-replacement reactions.
C.Electrons are both gained and lost.
Explanation:
.........................
A child sits on a merry-go-round, 1.5 meters from the center. The merry-go-round is turning at a constant rate, and the child is observed to have a radial acceleration of 2.3 m/s2. How long does it take for the merry-go-round to make one revolution
Answer:
5 .07 s .
Explanation:
The child will move on a circle of radius r
r = 1.5 m
Let the velocity of rotation = v
radial acceleration = v² / r
v² / r = 2.3
v² = 2.3 r = 2.3 x 1.5
= 3.45
v = 1.857 m /s
Time of revolution = 2π r / v
= 2 x 3.14 x 1.5 / 1.857
= 5 .07 s .
The merry-go round will take 5.07 s to complete one complete revolution.
Given data:
The distance of child from the center is, r = 1.5 m.
The magnitude of radial acceleration is, \(a = 2.3 \;\rm m/s^{2}\).
Since, the child is on merry-go round, which is undergoing a rotational motion. And radial acceleration means that it is under the acceleration, whose value is given as,
\(a=\dfrac{v^{2}}{r}\\\\v=\sqrt{a \times r}\)
Here, v is the linear velocity.
Solving as,
\(v=\sqrt{2.3 \times 1.5} \\\\v=1.857 \;\rm m/s\)
Now, we to obtain the time taken by merry-go round to complete one revolution. Then the expression for the time taken to complete one revolution is,
\(T=\dfrac{2 \pi r}{v}\\\\T=\dfrac{2 \pi \times 1.5}{1.857}\\\\T = 5.07 \;\rm s\)
Thus, we can conclude that the merry-go round will take 5.07 s to complete one revolution.
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A ball is projected with an initial velocity 50m/s at an angle 30 degree from the top of a tower 55m high.calculate the total time the ball was on the air and the maximum horizontal distance
Time of flight = 1.6 s
Horizontal distance = 64 m
What is a projectile motion?Projectile motion is the form of motion experienced by an object or particle projected into a gravitational field, such as from the surface of the Earth, and moves along a curvilinear path only under the action of gravity.
For the given case,
h = vt + ¹/₂gt²
h = height of tower
v = initial velocity
t = time of flight
55 = 50sin30t + ¹/₂9.8t²
55 = 25t + 4.9t²
4.9t² + 25t - 55 = 0
t = 1.6 s
X = vₓt
X = horizontal distance
vₓ = horizontal velocity
t = time of flight
X = (50 x cos30) x 1.6
X = 64 m
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What type of tv uses a VfL for backlighting
A VfL (Vertical Field LED) backlighting system is commonly used in LCD (Liquid Crystal Display) televisions.
LCD TVs rely on a backlight to illuminate the liquid crystal layer, which controls the passage of light to create the visual image. The VfL technology is a specific type of LED backlighting arrangement used in certain LCD TV models. In a VfL backlighting system, the LEDs (Light-Emitting Diodes) are positioned vertically along the edges of the LCD panel.
The light emitted by these LEDs is directed across the panel using light guides or optical films, illuminating the liquid crystal layer uniformly. One advantage of VfL backlighting is its ability to provide consistent illumination across the LCD panel, reducing any potential inconsistencies in brightness or color uniformity. The vertical orientation of the LEDs allows for more precise control over light distribution, improving overall image quality.
Additionally, VfL backlighting offers potential advantages in terms of power efficiency. By selectively dimming or turning off specific zones of LEDs, local dimming techniques can be employed to enhance contrast and black levels, resulting in improved picture quality while conserving energy. It's important to note that VfL backlighting is just one of several backlighting technologies available for LCD TVs.
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Describe nuclear fission and how the chain reaction in a nuclear reactor is controlled.
Answer:
Nuclear fission is a reaction in which the nucleus of an atom splits into two or more smaller nuclei. The moderator helps slow down the neutrons produced by fission to sustain a chain of reaction. The chains are controlled by Boron control rods when Boron absorbs the neutrons then the chain reaction will slow down due to the lack of neutrons producing reactions due to the absorbent of Boron. Their reaction initiates its own repetition.
Nuclear fission is the splitting of nucleus into two smaller nuclei and high amount of energy.
Nuclear fission is a reaction in which the nucleus of an atom splits into two or more smaller nuclei as well as very high amount of energy. The nuclear fission process produces gamma photons, and releases a very large amount of energy.
Most reactors are controlled with the help of control rods that are made of a strongly neutron-absorbent material such as boron or cadmium so we can conclude that nuclear fission is the splitting of nucleus into two smaller nuclei and high amount of energy.
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If the length of the pendulum in pendulum clock increases by 0.1 % , then the error in time per day is
a) 86.4s
b) 4.32s
c) 43.2s
d) 8.64s
JEE Mains 2022
When the length of the pendulum in pendulum clock increases by 0.1 % , then the error in time per day is c) 43.2s
How to calculate the time?Let the pendulum = L
The time in a day will be: = 60 × 60 × 24
When the length is increased, the new length will be:
= L + 0.001L
New time period will be:
T =✓0.001s
Now, the error in a day will be:
= ✓0.001 × 60 × 60 × 24 - 1 × 60 × 60 × 24.
= 60 × 60 × 24(✓1.001 - 1)
= 43.2 seconds.
Therefore, the correct option is C.
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9kg-ball is moving at 12m/s. What is the kinetic energy from this motion?
Answer:
ke=648J
Explanation:
ke=1/2mv²
m=9kg
v=12m/s
1/2(9)(12)²
=648J
what is ice wedging?(pls answer now)
Answer:
When the cold weather fills hard surfaces with water, it causes it to freeze and expand, causing cracks in the surface.
Impervious surfaces prevent water from flowing through them.
True or false?
Answer: the answer is true
Explanation:
Consider the circuit in Figure 5 with e(t) = 12sin(120pit) V. When S1 and S2 are
open, i leads e by 30°. When SI is closed and S2 is open, i lags e by 30°. When S1 and S2 are closed, i has an amplitude 0.5A. What are R, L, and C?
Based on the information, it should be noted that the resistance R is 0.5 Ω.
How to calculate the resistanceWhen S1 and S2 are open, i leads e by 30°. In this case, the circuit consists of only the inductor (L) and the capacitor (C) in series. Therefore, the impedance of the circuit can be written as:
Z = jωL - 1/(jωC)
Since i leads e by 30°, we can express the phasor relationship as:
I = k * e^(j(ωt + θ))
Z = jωL - 1/(jωC) = j(120π)L - 1/(j(120π)C)
Re(Z) = 0
By equating the real parts, we get:
0 = 0 - 1/(120πC)
Let's assume that there is a resistance (R) in series with the inductor and capacitor. The impedance equation becomes:
Z = R + jωL - 1/(jωC)
Z = R + jωL
Im(Z) = ωL > 0
Substituting the angular frequency and rearranging the inequality, we have:
120πL > 0
L > 0
This condition implies that the inductance L must be greater than zero.
When S1 and S2 are closed, i has an amplitude of 0.5 A. In this case, the impedance is:
Z = R + jωL - 1/(jωC)
Since the amplitude of i is given as 0.5 A, we can express the phasor relationship as:
I = 0.5 * e^(j(ωt + θ))
By substituting this phasor relationship into the impedance equation, we can determine the value of R. The real part of the impedance must be equal to R:
Re(Z) = R
Since the amplitude of i is 0.5 A, the real part of the impedance must be equal to 0.5 A: 0.5 = R
Therefore, the resistance R is 0.5 Ω.
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Which of the following is true about the following lever?
Answer:
It will rotate counter-clockwise.
Explanation:
The reason is that there is more Nm on the left side which will lift the lever towards the left side.
The lever would rotate counterclockwise as the torque on the left is higher, so, option B is correct.
What is torque?The force which causes the object to rotate about any axis is called perpendicular distance.
Torque is a twisting or turning force that frequently results in rotation around an axis, which may be a fixed point or the center of mass. The ability of something rotating, such as a gear or a shaft, to overcome turning resistance is another way to think of torque.
Given:
The force on the left side, f = 40 N,
The force on the right side, F = 80 N,
The distance of the pivot from the left side, d = 9 m,
The distance of the pivot from the right side, d = 3 m,
Calculate the torque on both side as shown below,
Torque on the left side = 40 × 9
Torque on the left side = 360 Nm
Torque on the right side = 80 × 3
Torque on the right side = 240 Nm,
Here, the torque on the left side is more,
Thus, the lever will rotate counterclockwise.
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A disk-shaped platform has a known rotational inertia. The platform is mounted on a fixed axle and rotates in a horizontal plane, as shown above. A student wishes to determine the frictional torque exerted on the platform by the axle as the platform rotates. The student has access to equipment that would usually be found in a school physics laborator
The frictional torque exerted on the platform by the axle as the platform rotates will be;
\(\rm T_f \theta =\frac{1}{2} I [\omega^2-\omega_0^2]\)
What is torque?Torque is the force's twisting action about the axis of rotation. Torque is the term used to describe the instant of force. It is the rotational equivalent of force. Torque is a force that acts in a turn or twist.
The amount of torque is equal to force multiplied by the perpendicular distance between the point of application of force and the axis of rotation.
Work done by the frictional torque = Change in the rotational kinetic energy of the wheel
\(\rm T_f \theta =\frac{1}{2} I [\omega^2-\omega_0^2]\)
Where,
\(\rm T_f\) is the frictional torque
\(\rm \omega\) is the final angular velocity
\(\rm \omega_0\) is the initial angular velocity
\(\rm \theta\) is the angular displacement
Hence, the frictional torque exerted on the platform by the axle as the platform rotates will be;
\(\rm T_f \theta =\frac{1}{2} I [\omega^2-\omega_0^2]\)
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A tennis player tosses a tennis ball straight up and then catches it after 2.21 s at the same height as the point of release.
(a) What is the acceleration of the ball while it is in flight?
magnitude
_____ m/s2
direction
---Select---
(b) What is the velocity of the ball when it reaches its maximum height?
magnitude
_____ m/s
direction
---Select---
(c) Find the initial velocity of the ball.
____ m/s upward
(d) Find the maximum height it reaches.
____ m
(a) To determine the acceleration of the ball while it is in flight, we can use the equation of motion:
v = u + at
where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time.
In this case, the ball is thrown straight up, so its final velocity at the highest point is 0 m/s. The initial velocity is unknown, the acceleration is due to gravity and is approximately -9.8 m/s^2 (negative since it acts in the opposite direction of motion), and the time of flight is 2.21 s.
Using the equation, we can solve for the acceleration:
0 = u - 9.8 * 2.21
u = 9.8 * 2.21
u ≈ 21.658 m/s
Therefore, the acceleration of the ball, while it is in flight, is approximately 21.658 m/s^2 in the upward direction.
(b) When the ball reaches its maximum height, its velocity is 0 m/s. This occurs when the ball is momentarily at rest before falling back down. Therefore, the magnitude of the velocity when the ball reaches its maximum height is 0 m/s.
(c) To find the initial velocity of the ball, we can use the equation:
v = u + at
At the highest point, the final velocity is 0 m/s, the acceleration is -9.8 m/s^2 (due to gravity), and the time is 2.21 s.
0 = u - 9.8 * 2.21
u = 9.8 * 2.21
u ≈ 21.658 m/s upward
Therefore, the initial velocity of the ball is approximately 21.658 m/s upward.
(d) The maximum height reached by the ball can be determined using the equation for vertical displacement:
s = ut + (1/2)at^2
At the highest point, the final displacement is 0 m, the initial velocity is 21.658 m/s upward, and the time of flight is 2.21 s.
0 = 21.658 * 2.21 + (1/2) * (-9.8) * (2.21)^2
0 = 47.864 + (-5.5294)
5.5294 = 47.864
Therefore, there seems to be an error in the calculations as the equation does not hold true. Please check the given values and equations to ensure accuracy.
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03: Hook's law suggests that F is directly proportional to -x, how much true you have found this statement in your experiment? Explain any differences.
Hooke's Law can be given as follows sometimes:
The restoring force of a spring is equal to the spring constant multiplied by the displacement from its normal position:
F = -kx
Where, F = Restoring force of a spring (Newtons, N)
k = Spring constant (N/m)
x = Displacement of the spring (m)
The negative sign relates to the direction of the applied force and by convention, the minus or negative sign is present in F = -kx. The restoring force F is directly proportional to the displacement (x), according to Hooke's law. When the spring is compressed, the displacement (x) is negative. It is zero when the spring is at its original length and positive when the spring is extended.
Practically, Hooke's Law is applicable only within a limited frame of reference, and through experimenting, this statement proves to be true. Because materials cannot be compressed beyond a certain size or expanded beyond a certain size without some permanent deformation or change of their original state.
The law only applies under some conditions such as a limited amount of force or deformation. Factually, many materials will noticeably deviate from Hooke's law even before those elastic limits are reached.
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