Yes, the minimum Stopping Sight Distance (SSD) is available for vehicles moving at 60 mph through this curve.
The solution to this problem requires the use of the SSD formula, which can be used to determine if the minimum SSD is available for vehicles moving at 60 mph through the curve. The SSD (Stopping Sight Distance) on horizontal curves is given by the following formula: SSD = S + R where S is the stopping distance and R is the sight distance. The stopping distance can be determined using the formula: S = V² / (2gf), where V is the velocity, g is the gravitational acceleration (32.2 ft/sec²), and f is the coefficient of friction.
The sight distance can be determined using the formula: R = K x √L, where K is the sight distance factor, and L is the length of the curve in feet, which can be determined using the following formula: L = (180 / π) x A, where A is the angle of the curve in radians. The sight distance factor (K) is given by: K = (1.47 + V/60 x 0.057) x D, where V is the velocity in mph and D is the superelevation rate as a decimal fraction. The superelevation rate is given by e = (V² / 15R) x 100, where R is the radius of the curve in feet.
The minimum SSD is 95% of the sum of the stopping distance and the sight distance. Therefore, if the minimum SSD is less than the actual SSD, then the driver's ability to see the road ahead is limited, and it may result in a collision or accident. Given that the superelevation rates do not exceed 6 percent, we can determine the SSD for a vehicle moving at 60 mph as follows: Radius of the curve = 1,670 feet (using the formula R = 5730 / A, where A = 20°)Superelevation rate (e) = (60² / (15 x 1,670)) x 100 = 2.16%The sight distance factor (K) = (1.47 + 60/60 x 0.057) x 2.16 = 0.264The length of the curve (L) = (180/π) x (20/360) = 31.42 feet. The stopping distance (S) = (60² / (2 x 32.2 x 0.4)) = 262.37 feet. The sight distance (R) = 0.264 x √31.42 = 1.64 x 5.61 = 9.20 feet. Therefore, SSD = S + R = 262.37 + 9.20 = 271.57 feet. The minimum SSD is 0.95 x 271.57 = 258.00 feet. Since the actual SSD of 271.57 feet is greater than the minimum SSD of 258.00 feet, the minimum SSD is available for vehicles moving at 60 mph through this curve.
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Two solid cylindrical rods AB and BC are welded together at B and loaded as shown. Take d1 = 30 mm, d2 = 50 mm, and P = 50 kN.Find the average normal stress at the midsection of rod AB.The average normal stress at the midsection of rod AB is MPa.
The average normal stress at the midsection of rod AB will be 25.8 MPa.
What are stress and pressure?Stress is the force exerted on a material divided by the cross-sectional area of the substance. Strain is the material's displacement or distortion as a result of applied stress. Note: The length change of a material (L - L0) is sometimes shown as.
How do we calculate stress in the question?Given, d1 = 30 mm
d2 = 50mm
P = 50kN
now, stress = force/ area
stress = 50/ 1.9635×10⁻³
stress = 25.8×10⁶ Pa
stress = 25.8 MPa
The average normal stress at the midsection of rod AB is 25.8 MPa.
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How do cars moves? and explain Please.
Answer:
when car vroom it go electric
Explanation:
i think then it goes to some spinny thing that spins and make the electric and the electic spins the spinny thing and the smoke comes outside the back
relevance of engineering law and ethic in contemporary society
Answer:
Engineering law and ethics are the moral codes associated with the field in which engineers are meant to adhere strictly to.
These ethics help in the safety of the engineers as a result of wearing protective clothing being a part of the ethics . Accuracy should also be taken important in research and daily activities. Corrupt practices and activities which poses risk to the environment is also strictly prohibited.
A driver is traveling at 90 km/h down a 3% grade on good, wet pavement. An accident
investigation team noted that braking skid marks started 75m before a parked car was
hit at an estimated 45 km/h. Ignoring air resistance, calculate the theoretical friction
coefficient.
Answer:
0.35
Explanation:
We resolve the component of the weight of the car along and perpendicular to the grade. We have mgsinФ and mgcosФ where Ф = angle of grade.
Now, the frictional force f = μN = μmgcosФ where μ = coefficient of friction
So, the net force along the grade is F = mgsinФ - μmgcosФ.
The work done by this force moving a distance, d along the grade is
W = (mgsinФ - μmgcosФ)d
This work equals the change in kinetic energy of the car. So ΔK = 1/2m(v₂² - v₁²) = W = (mgsinФ - μmgcosФ)d
1/2m(v₂² - v₁²) = (mgsinФ - μmgcosФ)d
1/2(v₂² - v₁²) = (gsinФ - μgcosФ)d
(v₂² - v₁²)/2d = (gsinФ - μgcosФ)
dividing through by gcosФ, we have
(v₂² - v₁²)/2dgcosФ = (gsinФ/gcosФ) - μgcosФ/gcosФ
(v₂² - v₁²)/2dgcosФ = tanФ - μ
μ = tanФ - (v₂² - v₁²)/2dgcosФ
given that tanФ = 3% = 3/100 and 1 + tan²Ф = 1/cos²Ф, cosФ = 1/(√1 + tan²Ф) = 1/(√1 + (3/100)²) = 1/(√1 + (9/10000)) = 1/(√10000 + 9/10000) = 1/√(10009/10000) = 100/√10009 = 100/100.05 = 0.9995.
Also, given that v₁ = 90 km/h = 90 × 1000/3600 m/s = 25 m/s and v₂ = 45 km/h = 45 × 1000/3600 m/s = 12.5 m/s, d = 75 m and g = 9.8 m/s².
So, substituting the values of the variables into the equation, we have
μ = tanФ - (v₂² - v₁²)/2dgcosФ
μ = 3/100 - ((12.5 m/s)² - (25 m/s)²)/(2 × 75 m × 9.8 m/s² × 0.9995)
μ = 3/100 - ((156.25 m/s)² - (625 m/s)²)/1,469.265 m²/s²
μ = 3/100 - (-468.75 m²/s²)/1,469.265 m²/s²
μ = 3/100 + 468.75 m²/s²/1,469.265 m²/s²
μ = 0.03 + 0.32
μ = 0.35
So, theoretical friction coefficient is 0.35
calculate the quantities of materials required for the first class brickwork in 1:6 cement mortar for 10 cu.m. assume the suitable data.
The * key is used for ____.
what is a lintel? question 7 options: upright beam beam used to span an opening a form of volcanic stone a type of marble
Answer: A lintel is a type of beam that spans openings such as portals, doors, windows and fireplaces. It can be a decorative architectural element, or a combined ornamented structural item
A 100 n uniform ladder of length 8 m rests against a smooth vertical wall. It the coefficient of static friction between the ladder and the floor is. 4, what is the maximum angle that the ladder can make with the floor before it slips?.
The correct response is E. 39. The maximum angle that the ladder can make with the floor before it slips is 39.
solitary-pole ladders Ladders that extend (maximum length 15 metres) Ladders, Step (maximum height 6.1 metres) Given that you shouldn't be standing on the top three treads of the leaning ladder, a single-story home with a height of at least 4 meters would be suitable. You would require an extension ladder with an extension of about 7 meters for a two-story residence. The short answer is no, leaning a ladder against a gutter is not safe. "For a leaning ladder, you should secure it and have a sturdy top resting point, i.e. do not rest a ladder against weak upper surfaces." It is not a good idea to lean your ladder against a gutter as the gutter could not be strong enough to hold it.
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A 100-N uniform ladder, 8.0 m long, rests against a smooth vertical wall. The coefficient of static friction between ladder and floor is 0.40. What minimum angle can the ladder make with the floor before it slips?
A. 42
B. 22
C. 18
D. 51
E. 39
Three single-phase loads in parallel are supplied from a 1400V (RMS), 60 Hz supply. The loads are as follows: Load 1: Inductive load: 125 kVA, 0.28 power factor Load 2: Capacitive load: 10 kW, 40 kVAR Load 3: Resistive load: 15 kW Find the total kW, kVAR, kVA, and supply power factor. (5 points) Find the capacitive correction (in kVARs) required to improve the power factor to 0.8 and calculate the supply current with this correction in place. (10 points) What is the least current that can service these three loads and how much compensation would it require
Answer:
The answer is below
Explanation:
\(\theta_1=cos^{-1}0.28=73.74^o\ lagging\\\\S_1=125\angle 73.74^o=35\ kW+j120\ kVAR\\\\S_2=10\ kW-j40\ kVAR\\\\S_3=15\ kW\)
Total power = P = 35 kW + 10 kW + 15 kW = 60 kW
Total kVAR = 120 kVAR - 40 kVAR = 80 kVAR
\(Total\ apparent \ power =S= S_1+S_2+S_3=(35+j120)+(10-j40)+(15)\\\\S=60\ kW+j80\ kVAR=100\angle 53.13^o\\\\Current(I)=\frac{S^*}{V^*} \frac{100000\angle -53.13^o}{1400\angle0}=71.43\angle-53.13^o\\ \\Power\ factor (PF)=cos(53.13)=0.6\ lagging\\\\The \ new\ power\ factor\ is\ to \ be\ 0.8[cos^{-1}0.8=36.87^o], hence\ since\ the\ total\ \\real\ power(P)= 60\ kW, the\ capacitor\ kVAR(Q_c)\ is:\\\\Q_c=60tan(53.13)-60tan(36.87)=80-45=35\ kVAR\\\\\)
\(C=\frac{Q_c}{wV^2} =\frac{35000\ VAR}{2\pi*60\ Hz*1400\ V}=47.38\ \mu f\)
New current (I') = \(\frac{S'^*}{V^*}=\frac{60000-j45000}{1400}=53.57\angle-36.87^o\)
Current reduce from 71.43 A to 53.57 A
Home safety and security is an __________ process.
家庭安全和安保是一个电气过程或电气过程，你在电脑上吗？我不是
If water is inserted between plates of a capacitor, what do you think will happen?
Answer:
We well know that water is a conductor of charges. So, when it is between capacitor plates, the charges flow from positive plate to negative plate hence discharge occurs
Explanation:
\({}\)
The operating sequence to light the main burners on an intermittent pilot system is:______.
A copper wire of diameter 1 cm and a resistance 0.15 ohms.Itv was drawn under pressure so that it's diameter was reduced to 50%. what is the new resistance of the wire?
The new resistance of the wire is 2.4.
How to calculate the resistanceIt should be noted that to solve for the new resistance of the wire after it has been drawn under pressure, we need to find the new cross-sectional area of the wire. We are told that the diameter of the wire has been reduced to 50% of its original value.
The cross-sectional area of a circle is proportional to the square of its diameter, so if the diameter is reduced by a factor of 2, the area is reduced by a factor of 4. Therefore, the new cross-sectional area of the wire is 1/4 of its original value.
It should be noted that R' = 16R
New resistance will be:
= 16 × 0.15
= 2.4
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dentify the recommended practices when putting a tip on a micropipette. Select one or more: Gently push the micropipette into the tip and tap lightly to load the tip. Hold the micropipette at a 45 degree angle to the tip rack. Use the tip size designed for the micropipette size in use. Remove the tip from the rack and place it on micropipette by hand.
Answer:
Gently push the micropipette into the tip box and tag tightly to load the tip.
Explanation:
The recommended practice when putting a tip on a micropipette is ; Gently push the micropipette into the tip box and tag tightly to load the tip.
Given that it is not advisable to remove tip from rack so as not to contaminate it, if we want to put a tip on a micropipette we should gently push the micropipette into the tip box.
Which mode specifier will open a file but not let you change the file or write to it?
A. 'e
B.'a'
C. 'r'
D. 'w'
The mode specifier that will open a file but not let you change the file or write to it is: "r" (Option C)
What is a mode specifier?A mode specifier is a one-word value that specifies the screen mode. It is dealt with as follows: It is presumed to be a mode number if it is a value between 0 and 255.
A mode specifier is a one-word value that specifies the screen mode. It is dealt with as follows: It is presumed to be a mode number if it is a value between 0 and 255. Otherwise, it is presumed to be a Sprite Mode Word if the bottom bit is set (describing a RISC OS 3.5 or RISC OS 5 format sprite).
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A spherical tank with a radius of 0.25 m is filled with water (ρ = 1000 kg/m3). Calculate the mass and weight of the water in SI units.
The mass of the water is 65.5 kg. The weight of the water is 641.9 kgm/s²
What is the mass of a spherical tank?The mass of a spherical tank is the space contained in the tank. The mass of the spherical tank can be determined by first finding the volume of the tank, then using the relation of density, mass, and volume to find the mass.
From the given parameter:
The radius of the tank = 0.25 mThe density of the water = 1000 kg/m³The volume of the tank can be determined by using the formula:
\(\mathbf{V = \dfrac{4}{3}\pi r^3}\)
\(\mathbf{V = \dfrac{4}{3}\pi (0.25)^3}\)
V = 0.0655 m³
Using the relation that:
\(\mathbf{Density = \dfrac{mass}{volume}}\)
\(\mathbf{1000 \ kg/m^3= \dfrac{mass}{0.0655 \ m^3}}\)
mass = 1000 kg/m³ × 0.0655 m³
mass = 65.5 kg
The weight of the water can be determined by using the formula:
Weight = mass × gravity (i.e. acceleration due to gravity)
Weight = 65.5 kg × 9.8 m/s²
Weight = 641.9 kgm/s²
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The mass of the water in spherical tank is 65.4kg.
The weight of the water in spherical tank is 640.8 Newtons.
Given the data in the question:
Radius of the spherical tank; \(r = 0.25m\)Density of water; \(p = 1000kg/m^3\)Mass of water; \(m_w = \ ?\)
Weight of water; \(Ww = \ ?\)
DensityDensity \(p\) is simply the measure of the compactness of the mass of a substance. It is expressed as;
\(Density = \frac{Mass}{Volume}\)
To determine the mass and weight of the water in spherical tank,
we calculate the Volume of the spherical tank.
\(V = \frac{4}{3}\pi r^3\)
We substitute in our given values
\(V = \frac{4}{3} * \pi * (0.25m)^3\\ \\V = \frac{4}{3} * \pi * 0.015625m^3\\\\V = 0.0654 m^3\)
Now, we calculate the mass of the water; using the expression above.
\(Density = \frac{Mass}{Volume}\\Mass = Density * Volume\\\)
We substitute in our values
\(Mass = 1000kg/m^3 \ *\ 0.0654m^3\\\\Mass = 65.4kg\)
Hence, the mass of the water in spherical tank is 65.4kg.
Next we calculate the Weight which is expressed as;
\(Weight = mass\ *\ Acceleration\ of\ gravity\)
Where acceleration of gravity \(g = 9.8m/s^2\)
We substitute in our values
\(Weight = 65.4kg * 9.8m/s^2\\\\Weight = 640.8kgm/s^2\\\\Weight = 640.8N\)
Therefore, the weight of the water in spherical tank is 640.8 Newtons.
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1. The reference OSHA standard requires several important characteristics of a PFAS:
It must limit the maximum arresting force imparted to the body to
with the full
body harness.
The reference OSHA standard requires several important characteristics of a PFAS. The employer must ensure that personal fall arrest systems (PFAs) must:
a. Limit the maximum arresting force on the employee to 1,800 pounds (8 kN). The figure used above must be based on the use of a full body harness.
Maximum arresting force is the highest amount of force that the fall protection system and the individual attached to the system will face as gotten by the deceleration device.OSHA regulations gives the system performance criteria for a personal fall arrest system.
From the above, we can therefore say that The reference OSHA standard requires several important characteristics of personal fall arrest systems (PFAs) as employers must reduce the maximum arresting force on the employee to 1,800 pounds (8 kN) using full body harness.
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6. What is the resistance of a curling iron that draws 12 A of current on a 120 V circuit?
Answer:
10 ohms Ω
Explanation:
V = IR
120 = I(12)
120/12 = 10Ω
(a) briefly describe the phenomenon of coring and why it occurs.
The phenomenon of coring occurs when there is a difference in the density of the material being poured, causing the solidifying material to pull away from the center, creating a cavity or hole.
How do we describe the phenomenon of coring?
This commonly occurs in casting or molding processes where there is a gradient of temperature or composition within the material being poured. Coring can also occur due to improper gating or venting. To prevent coring, it is essential to ensure uniformity in the material being poured and to use proper gating and venting techniques.
Coring is a defect in an alloy (e.g., a copper-nickel alloy) that occurs when a heated alloy is cooled too fast for diffusion to occur. This causes the alloy to be in a non-equilibrium condition because the exterior portion cools and solidifies before the interior portion, which remains hot and soft.
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what is the condition for sampling frequency to reconstruct the information signal ?
what's the best way to plan an organized
Answer:
Get ready and comfortable.
List all of the tasks you need to accomplish over the next week. .
Next schedule everything.
Get a planner/calender.
Cut those tasks that do not fit into your
In a parallel circuit, as more resistances are added, what happens to the total circuit current?
Answer:
the equivalent resistance of the circuit decreases and the total current of the circuit increases.
Explanation:
hope this helps
What are some tangible steps you can take to increase driving
forces? Reduce restraining forces?
Take tangible steps to increase driving forces and reduce restraining forces for a smoother transition and greater acceptance of change.
To increase driving forces and reduce restraining forces, you can take several tangible steps. These include:
Identify and communicate the benefits: Clearly articulate the advantages and positive outcomes associated with the desired change. Highlight how it aligns with individual and organizational goals.
Provide resources and support: Ensure that individuals have the necessary tools, training, and resources to facilitate the change. Offer guidance, coaching, and mentorship to help overcome obstacles.
Foster a positive culture: Create an environment that encourages innovation, collaboration, and open communication. Recognize and reward individuals who embrace the change and contribute to its success.
Address concerns and resistance: Actively listen to concerns and address them transparently. Involve individuals in the change process, seeking their input and involvement to alleviate resistance.
Break down the change into manageable steps: Divide the change into smaller, achievable milestones to make it less overwhelming. Celebrate progress along the way to maintain motivation.
Lead by example: Demonstrate your commitment to the change by modeling the desired behaviors and actively participating in the change process. Inspire and motivate others through your actions.
Continuous evaluation and improvement: Regularly assess the progress of the change effort and make necessary adjustments. Solicit feedback from individuals and adapt the approach as needed.
By implementing these tangible steps, you can increase driving forces and reduce restraining forces, leading to a smoother transition and greater acceptance of change.
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A franchise agreement between Software2 Company and Games3, Inc., is silent on a time for termination of the franchise. Software2 may a. never terminate. b. terminate at any time. c. terminate on reasonable notice. d. terminate on three days notice.
A franchise agreement between Software2 Company and Games3, Inc., is silent on a time for termination of the franchise. Software2 may terminate on reasonable notice. The Option C is correct.
What is termination of a franchise agreement ?The franchisor cancels the agreement before the end of the contract term in a termination, whereas a non-renewal occurs when the franchisor refuses to renew the agreement at the end of its term.
A franchisor or franchisee may attempt to terminate an agreement before the term expires. The termination options for both the franchisor and the franchisee must be specified in the franchise agreement and summarized in the disclosure document.
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_______ is a road able to support heavy loads. it was made out of crushed, packed stones/gravel and clay.
A cobblestone road is a road able to support heavy loads. it was made out of crushed, packed stones/gravel and clay.
What is a Cobblestone Road?
A cobblestone road is a type of paved road that was commonly used in the past and is still used in some parts of the world today. It consists of small, rounded stones that are tightly packed together and held in place by a mixture of clay or sand.
The stones used in cobblestone roads are typically made of granite or another hard, durable material that can withstand the weight of heavy loads and resist erosion. Cobblestone roads are known for their durability and long lifespan, and they were often used in cities and towns to provide a smooth surface for horse-drawn carriages and other forms of transportation. They continue to be used today in historic areas and as decorative features in landscaping.
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All of these are true about GMA (MIG) welding EXCEPT that:
O both the base metal and electrode are melted.
O shielding gas protects the well, tiom contamination.
O heat is produced using a short electric arc.
the welding gun liner regulates the shielding gas.
Answer:
the welding gun liner regulates the shielding gas.
Explanation:
The purpose of the welding gun liner is to properly position the welding wire from the wire feeder till it gets to the nozzle or contact tip of the gun. Regulation of the shielding gas depends on factors such as the speed, current, and type of gas being used. In gas metal arc welding, an electric arc is used to generate heat which melts both the electrode and the workpiece or base metal.
The electric arc produced is shielded from contamination by the shielding gas. The heat generated by the short electric arc is low.
frobenius method: solve xy''+y=0
Answer: X=0
Explanation: I think
The Routh's array is formed from the following characteristic equation and determines that the system is unstable. Which of the following answers is the element in the first column of the Routh's array which is negative? Setup a Routh's array to find the element and submit your calculations. s4 + 9s³ + 5s² +8s + 4 = 0 a)-0.7568 b)None of these answers c)-0.6654 d)-0.9235
None of the provided options matches the calculated value of 3.1111, so the correct answer is: B) None of these answers
Routh's array and system stability?To set up the Routh's array for the given characteristic equation, let's write down the coefficients of each power of 's':
\(s^4 + 9s^3 + 5s^2 + 8s + 4 = 0\)
The coefficients are:
a0 = 1
a1 = 9
a2 = 5
a3 = 8
a4 = 4
Now, let's construct the Routh's array:
Row 1: a0, a2, a4
Row 2: a1, a3
Row 3: (1st element)
Row 4: (2nd element)
To find the element in the first column of the Routh's array that is negative, we need to calculate the missing elements. Let's proceed with the calculations:
Row 1: 1, 5, 4
Row 2: 9, 8
Row 3: (1st element) = \((a1 * a2 - a0 * a3) / a1 = (9 * 4 - 1 * 8) / 9 = (36 - 8) / 9 = 28 / 9 ≈ 3.1111\)
Row 4: (2nd element) =(a1 * a2 - a0 * a3) / a1 = (9 * 4 - 1 * 8) / 9 = (36 - 8) / 9 = 28 / 9 ≈ 3.1111\((a1 * a2 - a0 * a3) / a1 = (9 * 4 - 1 * 8) / 9 = (36 - 8) / 9 = 28 / 9 ≈ 3.1111\)
Now, let's check which option corresponds to the negative element in the first column of the Routh's array:
a) -0.7568
b) None of these answers
c) -0.6654
d) -0.9235
None of the provided options matches the calculated value of 3.1111, so the correct answer is:
b) None of these answers
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a pediatrician would use this instrument for viewing the interior of the eye
A pediatrician would use an ophthalmoscope for viewing the interior of the eyes.
Ophthalmoscope is an instrument used by pediatricians and other physicians to examine the interior of the eye.
The ophthalmoscope, an important diagnostic tool in ophthalmology, enables doctors to view the retina, optic disc, macula, and other parts of the eye in detail.
The ophthalmoscope is designed to allow physicians to view the interior of the eye through the pupil. With the help of an ophthalmoscope, doctors can diagnose and monitor a variety of eye disorders, such as glaucoma, cataracts, and macular degeneration.
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A pediatrician is a doctor who specializes in treating babies, toddlers, and children up to the age of 18. Pediatricians are well-equipped to diagnose, treat, and illnesses. Because they deal with such young patients, pediatricians must have access to a variety of specialized medical instruments,
One such instrument is an ophthalmoscope. An ophthalmoscope is a handheld instrument that is used to view the interior of the eye. It allows doctors to examine the retina, optic disc, and other structures of the eye to identify any signs of damage or disease.
Pediatricians might use an ophthalmoscope to diagnose a variety of eye conditions in children. For example, they might use it to look for signs of strabismus (a misalignment of the eyes), cataracts (cloudy areas on the lens of the eye), or glaucoma (increased pressure in the eye that can damage the optic nerve)
In addition to an ophthalmoscope, they might also use other specialized instruments to examine different parts of the eye.
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Find the magnitude of the two pulling forces P and Q when their resultant is 50 N at 20° with Q. P 20°