Answers
Related Questions
Please help It is Anatomy and Phys
Think about the last time you had your temperature taken. Describe the circumstances that led you to have your temperature taken, including the mechanism by which your temperature was measured (oral thermometer, ear thermometer, etc.), so that given the right equipment, you could demonstrate the technique yourself to another person. What would have been considered an abnormal temperature in that situation?
Answers
Answer:
the last time i had my tempature taken was at disney prings about a week ago -_- they used one of those gun things that dont touch u and the SHOVED me forward so i guess i was fine
Explanation:
Answer:
thermometer
Explanation:
what i have learned
complete the statements below. write your answers on a separate sheet of paper
even before the advent of the telescope ancient aastronomers were able to observe the following
Answers
Even before the advent of the telescope, ancient astronomers were able to observe the following:
1. Celestial Bodies: Ancient astronomers could observe celestial bodies such as the Sun, Moon, stars, and planets. They could track their movements across the sky and study their patterns and behaviors.
2. Solar and Lunar Eclipses: By carefully observing the positions of the Sun, Moon, and Earth, ancient astronomers could predict and witness solar and lunar eclipses. They noticed that during a solar eclipse, the Moon blocks the Sun's light, creating a temporary darkness on Earth, while during a lunar eclipse, the Earth casts a shadow on the Moon, causing it to appear reddish or darkened.
3. Stellar Positions: Ancient astronomers mapped and observed the positions of stars in the night sky. They recognized patterns and constellations, which helped them navigate and keep track of time.
4. Seasons and Celestial Movements: By observing the changing positions of the Sun and its daily and yearly motions, ancient astronomers could understand the changing seasons. They could determine solstices, equinoxes, and the length of days and nights.
5. Comet Appearances: Ancient astronomers were able to observe and document the appearance of comets in the night sky. They recognized these celestial objects as distinct from stars and noted their unusual and transient nature.
These observations formed the basis of ancient astronomy and laid the groundwork for the development of more advanced astronomical techniques and instruments, including the telescope.
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You launch a model rocket from ground level. It moves directly upward with a constant acceleration of 71.0 m/s2 for 1.45 seconds, at which point it runs out of fuel. Assuming air resistance on the rocket is negligible, what is the maximum altitude (above the ground) achieved by the rocket?
m
Answers
Answer:
74.0 meters
Explanation:
We can use the kinematic equation for displacement with constant acceleration to solve this problem:
Δy = v0t + 1/2at^2
where Δy is the displacement (i.e., the change in height), v0 is the initial velocity (which is 0), a is the constant acceleration, and t is the time taken.
Plugging in the given values, we get:
Δy = 0 + 1/2(71.0 m/s^2)(1.45 s)^2
Δy = 74.0 m
Therefore, the maximum altitude achieved by the rocket is 74.0 meters above the ground.
A good baseball pitcher can throw a baseball toward home plate at 97 mi/h with a spin of 1540 rev/min. How many revolutions does the baseball make on its way to home plate
Answers
Answer:
10778292789403987593790
Explanation:
I am a Cow'
About 1.75% of water on Earth is in Greenland and Antarctica's icecaps, and about 97.5% is in the oceans. Assume the icecaps have an average temperature of -28°C, and the oceans have an average temperature of 4.8°C. If all the icecaps slid into the ocean and melted, how much would the average temperature of the ocean decrease?
Answers
If all the icecaps slid into the ocean and melted, the average temperature of the ocean would decrease by approximately 0.28°C.
To calculate the decrease in the average temperature of the ocean when all the icecaps melt, we need to consider the heat exchange between the icecaps and the ocean.
Let's start by calculating the heat released by the icecaps when they melt. We can use the specific heat capacity formula:
Heat released = Mass of icecaps × Specific heat capacity of ice × Temperature change
Since the icecaps constitute 1.75% of the Earth's water, the mass of icecaps is 0.0175 times the total mass of water on Earth.
Assuming the icecaps have an average temperature of -28°C and melt into liquid water at 0°C, the temperature change is 0°C - (-28°C) = 28°C.
Next, we need to calculate the heat absorbed by the ocean when the icecaps melt. Using the same formula:
Heat absorbed = Mass of ocean water × Specific heat capacity of water × Temperature change
Given that the oceans constitute 97.5% of the Earth's water, the mass of the ocean water is 0.975 times the total mass of water on Earth.
Assuming the oceans have an average temperature of 4.8°C, the temperature change is 4.8°C - 0°C = 4.8°C.
Now we can calculate the change in temperature of the ocean:
Change in temperature = Heat released / (Mass of ocean water × Specific heat capacity of water)
Substituting the values, we get:
Change in temperature = (0.0175 × Total mass of water) × (Specific heat capacity of ice × Temperature change) / (0.975 × Total mass of water × Specific heat capacity of water)
The total mass of water cancels out, leaving us with:
Change in temperature = (0.0175 × Specific heat capacity of ice × Temperature change) / (0.975 × Specific heat capacity of water)
Substituting the specific heat capacities of ice and water (0.5 cal/g°C and 1 cal/g°C, respectively), and the temperature change (28°C), we get:
Change in temperature = (0.0175 × 0.5 cal/g°C × 28°C) / (0.975 × 1 cal/g°C)
Simplifying the equation, we find:
Change in temperature ≈ -0.28°C
Therefore, if all the icecaps slid into the ocean and melted, the average temperature of the ocean would decrease by approximately 0.28°C.
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1. At t=0s, a particle moving in the x-y plane with constant acceleration has a velocity ofv; = (3î-2)) m/s, and is at the origin. At t=3s, the particle's velocity is f = (91+7j) m/s. Find (a)the acceleration of the particle (b) Its coordinates at t=3s
Answers
Answer:
the particle is at coordinates (18,15/2)
Explanation:
To find the acceleration of the particle, we can use the formula for velocity: v = v0 + at, where v0 is the initial velocity, a is the acceleration, and t is the time. Since we know the initial and final velocities, as well as the time interval, we can solve for the acceleration:
a = (v - v0)/t = [(9i + 7j) - (3i - 2j)]/3 = (6i + 9j)/3 = 2i + 3j
So the acceleration of the particle is a = 2i + 3j m/s².
To find the coordinates of the particle at t=3s, we can use the formula for position: r = r0 + v0t + 1/2at², where r0 is the initial position. Since the particle starts at the origin, r0 = 0. Plugging in the values we have:
r = 0 + (3i - 2j)(3) + 1/2(2i + 3j)(3)² = 9i - 6j + 9i + 27/2 j = 18i + 15/2 j
We can use the kinematic equations of motion to solve this problem.
Let the acceleration of the particle be a = axî + ayj.
(a) Using the equation of motion v = u + at, where u is the initial velocity:
f = v = u + at
Substituting the given values, we get:
(91+7j) = (3î-2j) + a(3î + 3j)
Equating the real and imaginary parts, we get:
91 = 3a + 3a (coefficients of î are equated)
7 = -2a + 3a (coefficients of j are equated)
Solving these equations simultaneously, we get:
a = î(23/6) + j(1/2)
So the acceleration of the particle is a = (23/6)î + (1/2)j.
(b) Using the equation of motion s = ut + (1/2)at^2, where s is the displacement and u is the initial velocity:
At t = 3s, the displacement of the particle is:
s = ut + (1/2)at^2
Substituting the given values, we get:
s = (3î-2j)(3) + (1/2)(23/6)î(3)^2 + (1/2)(1/2)j(3)^2
Simplifying, we get:
s = 9î + (17/2)j
So the coordinates of the particle at t=3s are (9, 17/2).
A cat pushes a porcelain statue off a bookshelf with a speed of 0.5 m/s and it smashed on the floor 0.85 sec later.
Answers
Answer:
167?
Explanation:
i added both
consider a car at rest, parked on level ground. the force of friction between a car tire and the ground .
Answers
The force of friction between car tire and ground is : umg.
Friction is defined as the resistance offered by the surfaces that are in contact when they move past each other.Friction is caused due to the irregularities on the two surfaces in contact. So, when one object moves over the other, these irregularities on the surface get entangled, giving rise to friction. The more the roughness, the more irregularities and more significant will be the friction.It is impossible to have zero friction because every surface will have minor irregularities no matter how lubricated.Static friction is a variable resistive force which is equal and opposite to the external force until it surpasses the threshold of motion when the slipping starts. Hence, static friction is a self-adjusting force.Since the car is at rest , static friction will come into action. So the force of friction between car tire and ground is : umg , where
u = coefficient of friction ,
m = mass of car and
g = acceleration due to gravity
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If a yellow ball is rolled with an average speed of 5 m/s, how far will it travel
in 5 seconds? (just type the number, no need for units).
*
Answers
Explanation:
5m/s if 5 seconds pass then 5 • 5, you get 25m
Hope this helps!
To test the performance of its tires, a car
travels along a perfectly flat (no banking) circular track of radius 96.6 m. The car increases
its speed at uniform rate of
at ≡((d |v|)/dt) = 4.87 m/s^2
until the tires start to skid.
If the tires start to skid when the car reaches
a speed of 21.1 m/s, what is the coefficient of
static friction between the tires and the road?
The acceleration of gravity is 9.8 m/s^2
Answers
The coefficient of static friction between the tires and the road is 1.987.
What is Static friction?Radius of the track, r = 516 m, Tangential Acceleration = 3.89 m/s^2 and Speed,v = 32.8 m/s
The radial Acceleration is given by, Now the total acceleration is The frictional force on the car will be f = ma------------(1)
And the force due to gravity is W = mg--------------------(2)
Now the coefficient of static friction is, From (1) and (2), Substituting the values, we get friction is 1.987.
Therefore, The coefficient of static friction between the tires and the road is 1.987.
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A 1.3 KG blocks flies along a frictionless surface at 1.0 M/S.a2 block sliding at a faster 5.0 M/S collides with the first from behind and sticks to it. The final velocity of the combine blocks is 2.0 M/S. What was the mass of the second block?
Answers
the initial momentum of the system of block m1 and block m2 is
Pi= m1v1 + m2v2
the final momentum of the combine blocks is
Pf= (m1+m2)V
according to the law of convervation of momentum
Pi = Pf
m1v1 + m2v2 = (m1+m2)V
1.3 × 1 + 5m2 = 1.3 × 2 + 2m2
m2= 1.3/3 kg
Can someone help me with my physics sheet? I don’t understand it.. thank you
Answers
Acceleration of the skydiver during the free fall is 4.13 m/s².
1) Mass of the skydiver, m = 83 kg
Weight, W = mg = 83 x 9.8
W = 813.4 N
Free fall acceleration is the acceleration that a body travelling in free fall experiences due to only the gravitational pull of the earth. This is the acceleration brought on by gravity.
Since there is no air resistance, the acceleration of the skydiver during the free fall is the acceleration due to gravity, g.
Freebody diagram is given in Fig.1.
2) Mass of the skydiver, m = 78 kg
Air resistance acting on him, F' = 470 N
mg - 470 = ma
813.4 - 470 = ma
a = 343.4/83
a = 4.13 m/s²
Freebody diagram is given in fig.2.
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At perihelion a planet in another solar system is 175 x 106 km from its sun at traveling at 40 km/s. At aphelion it is 250 x 106 km distant. What is its speed at aphelion
Answers
The speed at aphelion is mathematically given as
v2 = 21.43 km/s
What is its speed at aphelion?
Question Parameter(s):
At perihelion a planet in another solar system is 175 x 106 km from its sun at traveling at 40 km/s.
At aphelion it is 250 x 106 km distant.
Generally, the equation for the angular momentum conservation is mathematically given as
I1*w1 = I2*w2
Therefore
(0.5*m*R1^2)*v1/R1 = (0.5*m*R2^2)*v2/R2
Where
v1*R1 = v2*R2
v2 = v1*(R1/R2) = (30*10^3)*(2.50*10^11)/(3.50*10^11)
v2 = 2.1428*10^4 m/s
v2 = 21.43 km/s
In conclusion, speed is
v2 = 21.43 km/s
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A small car moving at 20 m/sec collides head on with an oncoming large truck moving at 25 m/sec. Which vehicle undergoes the largest change in its momentum
Answers
Answer:
The truck will undergo the largest change in momentum if it has a greater mass than the small car.
Explanation:
The change in momentum of an object can be calculated using the equation:
Δp = m * Δv
where Δp represents the change in momentum, m represents the mass of the object, and Δv represents the change in velocity.
Since we are comparing the change in momentum of the car and the truck, we need to consider the masses of both vehicles.
Let's assume the mass of the car is represented by m_car, and the mass of the truck is represented by m_truck.
Since both vehicles collide head-on, the change in velocity (Δv) will be the difference between their initial velocities, considering that they are moving in opposite directions:
Δv = v_truck - v_car
Now, let's compare the change in momentum for the car and the truck:
For the car:
Δp_car = m_car * Δv
For the truck:
Δp_truck = m_truck * Δv
Comparing the magnitudes of the change in momentum, we can neglect the negative sign:
|Δp_car| = |m_car * Δv|
|Δp_truck| = |m_truck * Δv|
Since both Δv and Δp are positive values, we can conclude that the vehicle with the greater mass will undergo the largest change in its momentum.
Therefore, if the mass of the truck (m_truck) is greater than the mass of the car (m_car), then the truck will undergo the largest change in its momentum. Conversely, if the mass of the car is greater, then the car will undergo the largest change in its momentum.
A safety plug is designed to melt when the pressure inside a metal tank becomes too high. A gas
at 51.0 atm and a temperature of 23.0°C is contained in the tank, but the plug melts when the
pressure reaches 75.0 atm. What temperature did the gas reach?
Answers
Two very large, nonconducting plastic sheets, each 10.0 cm thick, carry uniform charge densities σ1,σ2,σ3 and σ4 on their surfaces, as shown in the following figure (Figure 1). These surface charge densities have the values σ1 = -5.40 μC/m2, σ2=5.00μC/m2, σ3 = 1.30 μC/m2, and σ4=4.00μC/m2. Use Gauss's law to find the magnitude and direction of the electric field at the following points, far from the edges of these sheets.
point A is to the left, B is between (1.25 cm from the right sheet) , and C is to the right
surface charge densities are assigned left to right
Answers
The electric field at point A due to the two sheets is equal to 4.9e and similarly the electric field at B is also equal to 4.9e.
What is the gauss law for electric charges?Gauss law states that a net electric field in a Gaussian surface is equal to the charge closed by the Gaussian surface divided by the permittivity constant.
What is the Gaussian surface?A Gaussian surface is an imaginary surface enclosing an electric charge. A Gaussian surface can be of any shape but generally while taking a Gaussian surface symmetry is preferred.
Given:
Net charge on surface 1 = 0.1×(-0.4)
Net charge on surface 1 = -0.04 C
Net charge on surface 2 = 0.1×(5.3)
Net charge on surface 2 = 0.53 C
Now with the help of the gauss law we can easily find the electric field.
Equation of gauss law,
E × A × cos(p) = q/e
Where,
E is the electric field
A is the total surface area of Gaussian surface
p is angle between electric field and Gaussian surface
q is the net charge enclosed
e is permittivity constant
Electric field at point A = (053-0.04) × e ×10
Electric field at point A = 4.9e
Electric field at point B = 0.49 × permittivity constant × 10
Electric field at point B = 4.9e
The answer in both the cases is the same as the electric field by plane sheet is independent of the distance.
Therefore, The electric field at point A due to the two sheets is equal to 4.9e and similarly the electric field at B is also equal to 4.9e.
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Every household has at least one refrigerator, many hotels have ice makers. you may have wondered how much heat energy a refrigerator / ice maker takes
from water to make ice. Compute the amount of energy an
ice maker extracts from 200g of water at 34°c to manufacture ice at 0°c.
Answers
Answer:
1.heading
2.photo
3.boldface text
4.caption
5.bulleted list
Explanation:
you welcome
label the following parts of a wave using the terms: crest, trough, wavelength, frequency, and amplitude
Answers
We have that Crest ,trough, frequency, wavelength, amplitude you will be able to label the wave in Question.
What is wavelentgh?Wavelength can be defined as the distance between two successive crests or throughs of a wave.
From the question we are told
Label the parts of a wave the terms : crest ,trough, frequency, wavelength, amplitude
Generally
Crest
This is the defined as the vertical distance coveted by a wave.
Troughs
This speaks of lowest point of a wave the inversely of the crest
Frequency
This is the is defined as the inverse of
Wavelength
This is defined as the peaks to peak distance of a wave
Amplitude
This defines the maximum height attained by the wave.
Therefore
With above definition of Crest ,trough, frequency, wavelength, amplitude you will be able to label the graph in Question.
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1. Wind
A. Definition
B. What Heat Transfer Causes
c. Types
Answers
Answer:
B . a heat transfer caused
An object moving 20 m/s
experiences an acceleration of 4 m/s' for 8
seconds. How far did it move in that time?
Variables:
Equation and Solve:
Answers
Answer:
We are given:
initial velocity (u) = 20m/s
acceleration (a) = 4 m/s²
time (t) = 8 seconds
displacement (s) = s m
Solving for Displacement:
From the seconds equation of motion:
s = ut + 1/2 * at²
replacing the variables
s = 20(8) + 1/2 * (4)*(8)*(8)
s = 160 + 128
s = 288 m
During a neighborhood baseball game in a vacant lot, a particularly wild hit sends a 0.144 kg baseball crashing through the pane of a second-floor window in a nearby building. The ball strikes the glass at 14.9 m/s , shatters the glass as it passes through, and leaves the window at 10.5 m/s with no change of direction.
Requied:
a. What is the direction of the impulse that the glass imparts to the baseball?
b. Calculate the magnitude of this impulse (a positive number).
Answers
Answer:
a)The direction of the impulse that the glass imparts to the baseball Is opposite the direction of the balls motion
b) \(I=0.6336Ns\)
Explanation:
From the Question we are told that:
Mass \(m=0.144kg\)
Initial Speed \(v_1=14.9m/s\)
Final speed \(v_2=10.5\)
a)The direction of the impulse that the glass imparts to the baseball Is opposite the direction of the balls motion
b)
Generally the equation for impluse magnitude is mathematically given by
\(I=m(v_1-v_2)\)
Therefore
\(I=0.144(14.9-10.5)\)
\(I=0.6336Ns\)
A car accelerated at 10 m/s/s from a speed of 20 m/s to 45 m/s. How
long did this take?
Answers
Answer:
The answer is
2.5 sExplanation:
From the question we are finding the time it took for the object to move from it's initial speed to it's final speed
To find the time we use the formula
\(t = \frac{v - u}{a} \\ \)
where
t is the time taken
v is the final velocity
u is the initial velocity
a is the acceleration
From the question
v = 45 m/s
u = 20 m/s
a = 10 m/s²
The time taken is
\(t = \frac{45 - 20}{10} = \frac{25}{10} = \frac{5}{2} \\ \)
We have the final answer as
2.5 sHope this helps you
What does the slope represent? v^2/h = what variable?
Answers
Answer:
Slope measures the rate of change in the dependent variable as the independent variable changes.
Explanation:
40 points
For this assignment, you will research how to design and build a solar cooker. Search reliable online sites
for “solar cookers.” After getting the materials you need from your teacher, you will present your initial
design as a drawing or illustration. You will then build your device and test its efficiency by warming up a
hot dog until it reaches an internal temperature of 165°F, recording how long it took you to reach this
temperature. Based on your tests, you will make recommendations on how to improve the design of your
solar cooker, and then present your final design and the logic that supports it in a lab report. Your lab
report should include a title, a list of materials that you used to build your solar cooker, a drawing of your
initial design, observations from your experimental tests, recommendations for a final design based on
what you know about radiation, a drawing of your final design, and the results of the efficiency test. To
help you write your lab report, there is a Student Worksheet on the last few pages of this document.
Answers
Answer:
Ideas for Prototype Design
Similar to a cardboard oven just smaller and solar powered
Preliminary Sketches (attach separate paper, if needed)
Option A: i gave the picture
____________________________________________________________
Advantages: Disadvantages:
● the tin foil will attract the sun● if theres enough heat for the food to warm up
●the plastic will keep bugs and/or animal away from getting it ● it might take longer
●the box gives the food something to be in instead of the ground
Option B: i think im going to stay with my original plan i can always make changes
__________________________________________________________
More advantages and disadvantges
Advantages: Disadvantages:
●reducing my carbon footprint by alot ● heat varies so the food my take really really long
●using no energy other than the sun
__________________________________________________________
Which of the three designs will you move forward with? Explain your reasons for selecting this design.
I will be moving forward with option A bc i personally can't think of another way or design and i think option A has more advantages than disadvantages
__________________________________________________________
Building the Prototype
What modifications, if any, did you make to the basic design during the construction process?
I used skewers to hold the flap up
__________________________________________________________
Predictions
Will your device warm the hot dog to a temperature of 165°F? How will your device do this?
Well i guess it depends n alot of things such as where i will place my solar cooker and the weather changes i will most likely put my solar cooker on the black paper because darker colors absorb more heat then lighter ones, then i will wait maybe 10 -20 minutes and check on my hotdog
__________________________________________________________
Will your device efficiently warm the hot dog in 20 to 25 minutes? How will your device do this? so my device will do this by attracting the suns rays and energy towards the box
__________________________________________________________
Will your device reach a temperature well above that of its surroundings? How will your device do this?
I think so especially if i put it in direct sunlight around a darker surface and of course the aluminium foil will help with this as well
__________________________________________________________
Observations
Record your observations and the results of the experimental tests of your device below. Temperature of the surroundings (in °F): ______68_______
Maximum temperature reached inside the solar cooker (in °F): _____59_____
__________________________________________________________
i added a picture but i will also put the numbers here althought keep in mind u might want to switch them up because its based off of my temperatures
Use this table to record the internal temperature of the hot dog every 2 minutes. Use a separate sheet of paper, if necessary.
time: Temperature (°F)
4:00 20
4:02 20
4:04 25
4:06 26
4:08 30
4:10 34
4:12 38
4:14 40
4:16 44
4:18 46
4:20 50
4:22 55
4:24 57
4:26 60
4:28 65
4:33 72
4:35 75
4:37 76
4:39 80
__________________________________________________________
Evaluating Your Prototype
What worked well?
i would say definitely the black paper and tin foil sin they attracted most of the suns energy
__________________________________________________________
Which features can be improved upon?
i think maybe if i did t on a different day it would have gotten hotter
__________________________________________________________
How could the overall design of this device be improved?
Position the flap more so that the hotdogs can get more sun
Doing it on a hotter day
Letting it cook longer
__________________________________________________________
Why would this change be an improvement? What concepts related to thermal energy transfer is this improvement based on?
this change would be an improvement by the hotdogs getting warmed to the right temperature this is related to thermal energy by the position of the flap i think if i angled it more in an abtuse angle the sun would have transferred to the foil to the bottom foil with the hotdogs
__________________________________________________________
Sketch of Your Final Design
Draw a well-labeled sketch of the final design.
i provided a sketch it should be the last picture
OKAY FINALLY PLZ DONT REORT THIS I WORKED SO HARD ON IT LAST TIME AND IT GOT DELETED IF U HAVE ANY QUESTIONS ABOUT THE PROJECT I WILL TRY TO HELP YOU IN THE COMMENTS THANK YOUUUU - ( if your wndering what grade i got on this got a 100 percent )
OH AND PEACE.
Answer:
I am simply adding another answer so the one above can get a brainliest
Explanation:
I do not care about the points that I will wind up getting for this and they are right here just answer with gibberish
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edit: in an attempt to return your points my question was taken down ill will return these
somehow
someway
sometime
Which is a characteristic of diatoms?
A)whip-like tail
B)heterotrophic
C)multicellular
D)glass-ive cell wall
Answers
Answer:
b
Explanation:
Answer:
The correct answer is D, diatoms have glass-like cell walls.
A gas at 110atm and 303K filled a container of 2L. If the temperature is raised to 353 K and the pressure is increased to 440atm, what is the new volume
Question 4 options:
5.8 L
0.58 L
58 L
10.6 L
Answers
Answer:
0.58 L
Explanation:
For this problem we need to simply use the ideal gas equation to create a proportional comparison for the initial information to the final information.
(P_1 * V_1) / T_1 = (P_2 * V_2) / T_2
Using this, we can solve for V_2 to find the new volume of the gas once pressure and temperature changes.
(P_1 * V_1) * T_2 / T_1 = (P_2 * V_2)
(P_1 * V_1) * T_2 / (T_1 * P_2) = V_2
Consider our givens:
P_1 = 110atm
T_1 = 303K
V_1 = 2L
P_2 = 440atm
T_2 = 353K
Now we simply plug in these values to the equation to find the new volume, V_2.
(P_1 * V_1) * T_2 / (T_1 * P_2) = V_2
(110atm * 2L) * 353K / (303K * 440atm) = V_2
77660 atm*L*K / 133320 K*atm = V_2
0.583 L = V_2
Hence, the new volume is 0.583 L.
Cheers.
What do you do to find the manipulated variable in a line graph?
Answers
Answer: Days and Height (cm).
Explanation:
A wire 50.0 m long and 2.00 mm in diameter is connected to a source with a potential difference of 9.11 V, and the current is found to be 36.0 A. Find the resistivity of the material.
Answers
Answer:
ρ = 1.6*10⁻⁸ Ω/m.
Explanation:
Applying Ohm's Law to the wire, assuming that it can be treated as a pure resistance, the resistance of the wire can be obtained as follows:\(R = \frac{V}{I} = \frac{9.11V}{36.0A} = 0.253 \Omega (1)\)
At the same time, we know that there exists a relationship between the resistance, the resistivity ρ, the length L and the area A of the wire, that is given for the following expression:\(R = \rho* \frac{L}{A} (2)\)
The area of the circular section of the wire, can be expressed as a function of the diameter d, as follows:\(A = \frac{\pi*d^{2} }{4} = \frac{\pi*(0.002m)^{2}}{4} = \pi*10e-6 (3)\)
Replacing the left side of (2) by (1), and (3) on the right side, we can solve for the resistivity ρ as follows:\(\rho = \frac{R*A}{L} = \frac{0.253\Omega*\pi*10e-6}{50.0m} = 1.6e-8 \Omega/m\)
ρ = 1.6*10⁻⁸ Ω/mA spring is resting vertically on a table. A small box is dropped onto the top of the spring and compresses it. Suppose the spring has a
spring constant of 300 N/m and the box has a mass of 1.9 kg. The speed of the box just before it makes contact with the spring is 0.39
m/s.
(a) Determine the magnitude of the spring's displacement at an instant when the acceleration of the box is zero.
(b) What is the magnitude of the spring's displacement when the spring is fully compressed?
Answers
(a) The magnitude of the spring's displacement when the acceleration of the box is zero can be determined by equating the initial gravitational potential energy to the elastic potential energy stored in the spring.
(b) The magnitude of the spring's displacement when the spring is fully compressed can be determined by equating the initial gravitational potential energy to the elastic potential energy stored in the spring.
(a) To determine the magnitude of the spring's displacement when the acceleration of the box is zero, we need to apply the principles of conservation of energy.
Initially, the box has gravitational potential energy given by mgh, where m is the mass of the box, g is the acceleration due to gravity, and h is the height from which the box was dropped. The initial gravitational potential energy is converted into the elastic potential energy stored in the compressed spring and the kinetic energy of the box just before it makes contact with the spring.
The gravitational potential energy is given by:
mgh = (1.9 kg)\((9.8 m/s^2)h\)
The elastic potential energy stored in the spring is given by:
1/2 kx^2\(kx^2\), where k is the spring constant and x is the displacement of the spring.
The kinetic energy of the box just before it makes contact with the spring is given by:
\(1/2 mv^2,\) where m is the mass of the box and v is the speed of the box.
Since the acceleration of the box is zero at the instant when the spring's displacement is maximum, the kinetic energy is zero. Therefore, we can equate the initial gravitational potential energy to the elastic potential energy to find the spring's displacement.
mgh = 1/2 \(kx^2\)
Substituting the given values, we have:
\((1.9 kg)(9.8 m/s^2)h = 1/2 (300 N/m)x^2\)
Solving for x, the magnitude of the spring's displacement, we can determine its value at the instant when the acceleration is zero.
(b) To find the magnitude of the spring's displacement when the spring is fully compressed, we need to consider the conservation of mechanical energy once again.
At maximum compression, all the initial gravitational potential energy is converted into the elastic potential energy stored in the compressed spring.
mgh = 1/2 \(kx^2\)
Substituting the given values and solving for x, the magnitude of the spring's displacement, we can determine its value when the spring is fully compressed.
It's important to note that in both cases, the negative sign of the displacement indicates that the spring is being compressed. The magnitude of the displacement will be a positive value.
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detergents are used to clean the clothes why
Answers
Answer:Detergent mixes with water to remove dirt and oil from clothes. Water can't remove oil and dirt from clothes. Detergent cleans by causing a chemical reaction with water to force dirt and debris out of clothing. Detergents work with water to loosen the dirt trapped in the material of clothing and clean them away.
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