Static equilibrium involves the sensation of linear acceleration as well as changes in head rotation. Hair cells receptive to changes in static equilibrium are found in this structure. Chemically sensitive microvilli found in this structure. Chemically sensitive cilia are found in this structure.

Answer:

i think the answer is b but dont knock me if its not

Explanation:

Answer:

Here's a diagram.

Explanation:

Answer:

All stars are formed from collapsing clouds of gas and dust, often called nebulae or molecular clouds. Over the course of millions of years, these protostars settle down into a state of equilibrium, becoming what is known as a main-sequence star. Nuclear fusion powers a star for most of its existence.

Explanation:

The mass of the precipitate, CrPO₄ formed when 45.5 mL of 0.300 M Na₃PO₄ react with 42.5mL of 0.200 M Cr(NO3)₃ is 1.25 g

We'll begin by calculating the number of mole of Na₃PO₄ and Cr(NO3)₃ present in the solution.

Molarity of Na₃PO₄ = 0.3 M

Volume = 45.5 mL = 45.5 / 1000 = 0.0455 L

Mole = Molarity × Volume

Mole of Na₃PO₄ = 0.3 × 0.0455

Molarity of Cr(NO3)₃  = 0.2 M

Volume = 42.5 mL = 42.5 / 1000 = 0.0425 L

Mole = Molarity × Volume

Mole of Cr(NO3)₃ = 0.2 × 0.0425

Next, we shall determine the limiting reactant.

Na₃PO₄(aq) + Cr(NO₃)₃(aq) —> CrPO₄(s) + 3NaNO₃(aq)

1 mole       :      1 mole

0.01365    :      0.0085 mole

Thus, Cr(NO₃)₃ is the limiting reactant.

Next, we shall determine the number of mole of CrPO₄ produced from the reaction.

From the balanced equation above,

1 mole of Cr(NO₃)₃ reacted to produce 1 mole of CrPO₄.

Therefore,

0.0085 mole of Cr(NO₃)₃ will also react to produce 0.0085 mole of CrPO₄.

Finally, we shall determine the mass of 0.0085 mole of CrPO₄.

Mole of CrPO₄ = 0.0085 mole

Molar mass of CrPO₄ = 52 + 31 + (16×4)

= 52 + 31 + 64

= 147 g/mol

Mass = mole × molar mass

Mass of CrPO₄ = 0.0085 × 147

Therefore, the mass of the precipitate, CrPO₄ formed is 1.25 g

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Answer:

The answer would be B.

Explanation:

The mass of CaF₂ formed when 47.8 mL of 0.334 M NaF is treated with an excess of aqueous calcium nitrate, Ca(NO₃)₂ is 0.624 g

We'll begin by calculating the number of mole of NaF in the solution. This can be obtained as follow:

Volume = 47.8 mL = 47.8 / 1000 = 0.0478 L

Molarity of NaF = 0.334 M

Mole = Molarity x Volume

Mole of NaF = 0.334 × 0.0478

2NaF + Ca(NO₃)₂ —> CaF₂ + 2NaNO₃

NOTE: This is a double displacement reaction.

From the balanced equation above,

2 moles of NaF reacted to produce 1 mole of CaF₂.

Therefore,

0.016 mole of NaF will react to produce = 0.016 / 2 = 0.008 mole of CaF₂.

Mole of CaF₂ = 0.008 mole

Molar mass of CaF₂ = 40 + (19×2) = 78 g/mol

Mass = mole × molar mass

Mass of CaF₂ = 0.008 × 78

Therefore, the mass of CaF₂ formed when 47.8mL of 0.334 M NaF is treated with an excess of aqueous calcium nitrate, Ca(NO₃)₂ is 0.624 g

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Answer:

0.623

Explanation:

Answer:

snovd vosb r

Explanation:

The molar mass of the gas is approximately 20.72 g/mol.

To determine the molar mass of the gas, we can use the ideal gas law equation:

PV = nRT

where:

P = pressure (in atm)

V = volume (in liters)

n = number of moles

R = ideal gas constant (0.0821 L·atm/(mol·K))

T = temperature (in Kelvin)

First, let's convert the given values to the appropriate units:

Pressure = 432 torr = 432/760 atm

Volume = 333 mL = 333/1000 L

Temperature = 23°C = 23 + 273.15 K

Substituting the values into the ideal gas law equation:

(432/760) atm * (333/1000) L = n * 0.0821 L·atm/(mol·K) * (23 + 273.15) K

Simplifying the equation:

0.191 atm * 0.333 L = n * 0.0821 L·atm/(mol·K) * 296.15 K

Solving for the number of moles (n):

n = (0.191 atm * 0.333 L) / (0.0821 L·atm/(mol·K) * 296.15 K)

n ≈ 0.01012 moles

Finally, we can calculate the molar mass using the formula:

Molar mass = mass of the gas sample / moles of gas

Molar mass = 0.210 g / 0.01012 moles

Molar mass ≈ 20.72 g/mol

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Answer:Gaseous C4H8 + oxygen gas ---> carbon dioxide + water

C4H8(g) + 6O2(g) ---> 4CO2(g) + 4H2O(g)

Not the one u want but its similar so u can get an idea of what the one u want is like  

It is important to record all accidents and breakages that occur in the laboratory to prevent them from happening again.

Laboratory accident is defined as the type of accident that occurs in the laboratory leading to harm.

Example of laboratory accidents include the following:

A record of these type of laboratory accidents would hel prevent it's reoccurrence.

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Answer:

Bacteria

Explanation:

Bacteria and are all unicellular prokaryotes

Answer:

bacteria

Explanation:

prokaryotic has no nucleus and bacteria is unicellular

pH determines the acidic or alkaline a solution is using the pH scale, which has a range of 0 to 14. An alkaline pH is greater than 7, while an acidic pH is less than 7.

Thus, The pH of a solution is defined mathematically as the negative logarithm of the molar concentration of hydrogen ions therein.

NaOH is a strong alkaline, as indicated by a pH testing strip, but in order to determine its exact pH, you must first determine its molarity.

A scale known as pH is used to describe how basic or acidic a water-based solution is. Basic solutions have a higher pH than acidic solutions, which have a lower pH.

Thus, pH determines the acidic or alkaline a solution is using the pH scale, which has a range of 0 to 14. An alkaline pH is greater than 7, while an acidic pH is less than 7.

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The pH of HNO₂ is 2.15, pH of NH₄OH is 10.98 and pH of H₂S is 3.76.

pH is defined as the negative logarithm of H⁺ ion concentration.

pH is a measure of how acidic or basic a substance is. In our everyday routine, we encounter and drink many liquids with different pH. Water is a neutral substance. Soda and coffee are often acidic.

The pH is an important property, since it affects how substances interact with one another and with our bodies. In our lakes and oceans, pH determines what creatures are able to survive in the water.

Given,

1. Concentration = 0.1

Ka = 4.5 × 10⁻⁴

\(pH = \frac{1}{2} (pka - log c)\)

pH = 0.5 × ( 3.3 + 1)

= 2.15

2.  Concentration = 0.05

Ka = 1.8 × 10⁻⁵

\(pOH = \frac{1}{2} (pkb - log c)\)

pOH = 0.5 × ( 4.74 + 1.3)

= 3.02

pH = 14 - pOH

= 14 - 3.02

= 10.98

3. Concentration = 0.3

Ka = 1 × 10⁻⁷

\(pH = \frac{1}{2} (pka - log c)\)

pH =  0.5 × ( 7 + 0.52)

= 3.76

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The half-life of the radioactive substance is approximately 2.06 hours.

The half-life of a radioactive substance is the amount of time required for half of the initial amount of the substance to decay. If the rate of decay is proportional to the amount of the substance present at time t, the half-life of the substance can be determined as follows:

Let t be the half-life of the substance, then after t hours, the amount of the substance present will be 100 mg × (1/2) = 50 mg.

At time 4 hours, the amount of the substance present is 100 mg × (1 - 3%) = 97 mg.

Since the rate of decay is proportional to the amount of substance present, the half-life can be calculated as follows: t = 4 hours × (50 mg / 97 mg) = 2.06 hours.

Therefore, the half-life of the radioactive substance is approximately 2.06 hours.

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Answer:

Explanation:

Answer:

b is the answer

Explanation:

Gypsum products are offered as fine powders that must be dissolved in water to create a fluid mass or slurry that can be poured and moulded before setting up into a stiff, stable mass.

Thus,  Gypsum compounds are mostly used to create accurate replicas or positive reproductions of oral structures.

These copies, which are also known as casts, dies, or models, are made from negative reproductions like alginate imprints. Every replica serves a particular function and gypsum.

To create a replica from an imprint, gypsum ingredients are combined with water. Dental hygienists, assistants, and lab workers all employ gypsum products in dental clinics and labs.

Thus, Gypsum products are offered as fine powders that must be dissolved in water to create a fluid mass or slurry that can be poured and moulded before setting up into a stiff, stable mass.

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If a reaction has a negative ΔG and a positive ΔS, the reaction will be spontaneous at all temperatures.

If a reaction is spontaneous at all temperatures, it implies that the reaction will occur without the need for any external intervention, such as the addition of energy. For a reaction to be spontaneous, it must satisfy the criteria of thermodynamic favorability, which is determined by the change in Gibbs free energy (ΔG) associated with the reaction.

The relationship between ΔG, temperature (T), and the equilibrium constant (K) of a reaction is described by the equation ΔG = ΔH - TΔS, where ΔH is the change in enthalpy and ΔS is the change in entropy.

To ensure spontaneity at all temperatures, two conditions must be met:

ΔG must be negative: A negative ΔG indicates a thermodynamically favorable reaction, meaning the products have a lower Gibbs free energy than the reactants. If ΔG is negative, the reaction will proceed spontaneously in the forward direction.

ΔS must be positive: A positive ΔS signifies an increase in the overall entropy of the system. Higher entropy means more disorder, and spontaneous reactions often involve an increase in randomness. When ΔS is positive, it can compensate for the enthalpic term, ΔH, allowing the reaction to proceed spontaneously.

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When the pressure decreases from left to right, the acceleration also decreases.

This is defined as the rate at which velocity changes with time and it has a direct relationship with pressure.

This however means that when pressure decreases there will be a corresponding decrease in acceleration and vice versa.

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The exit gas stream average molecular weight is 28.97 g/mol, and there will be 3.0 kg of leftover Phenanthrene in the reactor.

The balanced combustion equation for Phenanthrene is:

C₁₄H₁₀ + 21O₂ → 14CO₂ + 5H₂O

From the equation, we can see that 21 moles of oxygen are needed to combust 1 mole of Phenanthrene. Thus, to burn 10 kg of Phenanthrene, we need:

and

However, the supplied air is 30% less than the requirement, which means only 70% of the required O₂ will be supplied. Therefore, the actual amount of O₂ supplied will be:

Assuming the air is mostly nitrogen, we can calculate the exit gas stream average molecular weight using the following formula:

where 0.79 and 0.21 are the mole fractions of nitrogen and oxygen in air, respectively, and 28.01 and 32 are the molecular weights of nitrogen and oxygen, respectively.

Finally, we can calculate the amount of leftover Phenanthrene in the reactor:

However, this amount is negligible due to the large scale of the reaction. Therefore, we can round it off to:

Leftover Phenanthrene = 3.0 kg

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For an electron as a particle, E = \(1/2mv^2\)

For an electron as a particle, the energy E can be described using the equation:

E =  \(1/2mv^2\)

where

This equation represents the kinetic energy of the electron, which is the E is the energy

energy associated with its motion.

This equation assumes classical mechanics and does not take into account relativistic effects that become significant at high speeds close to the speed of light.

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Answer:

Explanation:

The volume of the object can be found by using the formula

volume = final volume of water - initial volume of water

final volume = 46.7 ml

initial volume = 36.7 mL

We have

volume = 46.7 - 36.7 = 10 mL

We have the final answer as

Hope this helps you

The reduction half-reactions for O, P, and Cu:

• O: O2 + 4 e- → 2 O2-

• P: HPO42- + 2 H+ + 2 e- → H3PO4

• Cu: Cu2+ + 2 e- → Cu+

To write the reduction half-reactions for O, P, and Cu, we need to determine the oxidation numbers for each element. The guidelines for assigning oxidation numbers are:

Using these guidelines, we can determine the oxidation numbers for O, P, and Cu:

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Answer:

0.1443194637888042 moles

Explanation:

Hope This Helps

Have A Great Day

~Zero~

Answer:

a mole is the number of molecules in 22.4 dm³ for all gases at all temperatures and pressures

The heat of fusion of water is 79.9 cal/g. If a 7.2 g piece of ice melts in 105 g of water at 34.3 deg C in an insulated bottle, 35071.6 °C is the  final temperature of the water.

The physical concept of temperature indicates in numerical form how hot or cold something is. A thermometer is used to determine temperature. Thermometers are calibrated using a variety of temperature scales, which historically defined distinct reference points or thermometric substances.

The most popular scales were the Celsius scale, sometimes known as centigrade, with the unit symbol °C, the scale of Fahrenheit (°F), or the Kelvin scale (K), with the latter being mostly used for scientific purposes.

Δ T = T(initial) - T(final)

T(final)= m × c × q - T(initial)

T(final)= 79.9 x 4.184 x 105 - 30.0

T(final)= 35071.6 °C

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In order to properly balance an equation, we need to make sure that the same amount of elements on the reactants side matches the number of elements on the products side, we can do that by increasing the number in front of each molecule, the so called stoichiometric coefficient. In the reaction from the question we can properly balance by adding the following stoichiometric coefficients

For our question, we have:

2 Ag2S -> 4 Ag + S2

Answer:

In the reaction between vinegar and baking soda, the reactants are vinegar (acetic acid) and baking soda (sodium bicarbonate). The products are sodium acetate, water, and carbon dioxide gas.

Nuclear Fission

Nuclear fission, subdivision of a heavy atomic nucleus, such as that of uranium or plutonium, into two fragments of roughly equal mass. The process is accompanied by the release of a large amount of energy. In nuclear fission the nucleus of an atom breaks up into two lighter nuclei.

Nuclear fission is a process where the nucleus of an atom is split into two or more smaller nuclei, known as fission products. The fission of heavy elements is an exothermic reaction, and huge amounts of energy are released in the process.

Answer:

See below.

Explanation:

To determine the electron pair geometry of Carbonothioyl dibromide, we need to first draw its Lewis structure:

Br Br

\ /

C=S

/

Br Br

Carbonothioyl dibromide has four electron groups around the central sulfur atom: two single bonds with the two bromine atoms, one double bond with the carbon atom, and one lone pair of electrons on the sulfur atom.

Using VSEPR theory, we can predict the electron pair geometry by considering both the bonding and the lone pairs of electrons. In this case, the electron pair geometry of Carbonothioyl dibromide is tetrahedral because it has four electron groups around the central sulfur atom.

However, the molecular geometry of Carbonothioyl dibromide is trigonal pyramidal due to the presence of one lone pair of electrons on the sulfur atom.

Answer:

1. Dehydration of alcohols

2. Dehydrohalogenation of alkyl halides

3. Decarboxylation of carboxylic acids

4. Pyrolysis of esters

5. Deamination of amino acids

6. Dealkylation of ethers

7. Dehalogenation of aryl halides

8. Dehydration of amides

9. Dehydrogenation of alkanes

10. Dehydrogenation of alkenes.

Explanation: