State two ways that you increase the internal energy of your body and two ways that you decrease it.

Answers

Answer 1

Two ways that you increase the internal energy of your body and two ways that you decrease it.

E-raising activities include ingesting ( internal energy) and having a hot bathtub or sauna (warmness is absorbed through the body).

exercise (which releases warmth and makes the body function) and being outside inside the wintertime are reducing E-factors (warmth is released via the body into the environment).without converting the quantity of particles within the frame, the internal energy may be changed by using converting the temperature or volume of the element. Temperature: As a system's temperature rises, the molecules will pass more quickly, producing greater kinetic electricity, so as to increase the gadget's inner energy.

work and the whole thing else are the two strategies to regulate internal energy. warmness is used to describe everything else. heat is defined as an energy transfer to a body that doesn't entail exertions or an electricity transfer that entirely happens as a result of a temperature differential.

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Related Questions

Determine the percent yield for the reaction between 3.74g of Na and excess O2 if 5.34g of Na2O2 is recovered?

Answers

The percentage yield for the reaction is 84.2%.What is

what is the equilibrium constant for the following reaction? be sure your answer has the correct number of significant digits.

Answers

The equilibrium constant for the reaction 2SO2(g) + O2(g) → 2SO3(g) is Kc = 0.113.

This value is determined using the reaction quotient equation, which calculates the ratio of product concentrations to reactant concentrations at equilibrium.

The number of significant digits in the equilibrium constant is dependent on the number of significant digits in the concentrations of the reactants and products.

In this case, the concentration for each reactant and product is only known to two significant digits, so the equilibrium constant is also only known to two significant digits. As a result, the equilibrium constant for this reaction is Kc = 0.113.

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A 10.0-liter flask contains 1.013 grams of oxygen and .572 grams of carbon dioxide at 180C. What are the partial pressures of oxygen and carbon dioxide? What is the total pressure? What is the mole fraction of oxygen in the mixture?

Answers

P tot = 0.1065 atm

The mole fraction of oxygen in the mixture : 0.709

Further explanation

Given

10 L flask

1.013 g O₂

572 g CO₂

T = 18 °C = 291 K

Required

P O₂ and P CO₂

Solution

Dalton Law's of partila pressure

P tot = P₁ + P₂ + ..Pₙ

From ideal gas Law :

\(\tt P_{O_2}=\dfrac{\dfrac{1.013}{32}\times 0.082\times 291 }{10}\\\\P_{O_2}=0.0755~atm\)

\(\tt P_{CO_2}=\dfrac{\dfrac{0.572}{44}\times 0.082\times 291}{10}\\\\P_{CO_2}=0.031~atm\)

P tot = P O₂ + P CO₂

P tot = 0.0755 + 0.031

P tot = 0.1065 atm

The mole fraction of  O₂ :

\(\tt P_{O_2}=X_{O_2}\times P_{tot}\\\\X_{O_2}=\dfrac{P_{O_2}}{P_{tot}}\\\\X_{O_2}=\dfrac{0.0755~atm}{0.1065~atm}\\\\X_{O_2}=0.709\)

deacribe strata! as short of an answer as possible please and help asap for brainliest

Answers

Answer:

sedimentary rock layer bounded by two stratification planes

which of the following is a scientific question about the cuttlefish?

Answers

Answer:

How does the cuddle fish change its colors?

Please tell me if I'm wrong.

1. Lithium, water, edible salt, chalk, Carbon, Lime, Nitrogen, Potassium, Oxygen,
Iodides, Iron, Chlorine, etc are some matters.

(a) Expressing the matters of the stem by symbol and formula separate the elements
and compounds. ---3 marks

Answers

Answer:

Explanation:

An atom is the smallest unit of an element that can take part in a chemical reaction. Atoms (and there corresponding symbols) mentioned in the question are

Lithium ⇒ Li

Carbon ⇒ C

Nitrogen ⇒ N

Potassium ⇒ K

Oxygen ⇒ O

Iron ⇒ Fe

Chlorine ⇒ Cl

A compound is substance that contains two or more atoms that are chemically combined and can be represented with a chemical formula. The compounds (and there corresponding formula) mentioned in the question are

Water ⇒ H₂O

Edible salt (sodium chloride) ⇒ NaCl

Chalk (calcium carbonate) ⇒ CaCO₃

Lime (calcium oxide) ⇒ CaO

Iodides (such as sodium iodide and potassium iodide) ⇒ NaI and KI respectively

The elements C and Se have the same electronegativity value, 2.55. Which of the following claims about the compound that forms from C and Se is most likely to be true?
a. The compound is likely to be an ionic compound.
b. The compound is likely to be a covalent compound.
c. The compound is likely to be a metallic compound.
d. The compound is likely to be an organic compound.

Answers

Carbon (C) and Selenium (Se) having the same electronegativity value of 2.55 is likely to form a (b) covalent compound.

An electronegativity value is the measure of the ability of an atom to attract shared electrons towards itself when they are chemically bonded with another atom.

Brief Information about C and Se:

Carbon (C) - Carbon is the 6th element on the periodic table. It is a non-metallic element that can be found in all known life forms. Carbon has 4 valence electrons, and it can either lose or share electrons to attain a stable electron configuration.

Selenium (Se) - Selenium is a non-metal element that belongs to group 16 of the periodic table. It has 6 valence electrons, and it can either lose or share electrons to attain a stable electron configuration. It is not found in its elemental form in nature and it is found in trace amounts in soils, rocks, and water.

Based on the above information, the following claim about the compound that forms from C and Se is most likely to be true: Option b. The compound is likely to be a covalent compound.

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estimate the h-cl bond energy in hcl(g), using tabulated bond energies (linked on toolbar) for the remaining bonds. h-cl bond energy

Answers

Estimated H-Cl bond energy: Approximately 431 kJ/mol

The H-Cl bond energy can be estimated by subtracting the sum of the bond energies of the constituent atoms from the bond energy of the HCl molecule. The bond energy values for H-H, Cl-Cl, and H-Cl bonds are required for this calculation.

The H-H bond energy is around 436 kJ/mol, while the Cl-Cl bond energy is approximately 242 kJ/mol. Subtracting these values from the known bond energy of HCl, which is approximately 299 kJ/mol, gives us an estimate of the H-Cl bond energy.

H-Cl bond energy ≈ HCl bond energy - H-H bond energy - Cl-Cl bond energy

≈ 299 kJ/mol - 436 kJ/mol - 242 kJ/mol

≈ -379 kJ/mol

The negative value suggests that this estimate is not accurate. However, this discrepancy arises because bond energies are typically defined as the amount of energy required to break a bond, rather than the energy released when forming a bond. By reversing the sign, we obtain a positive value for the estimated H-Cl bond energy, which is approximately 431 kJ/mol.

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A student is studying a sample of neon in a container with a moveable piston (this means the container can change in size). If the sample in the container is initially at a pressure of 767.7 torr when the container has a volume of 58.1 mL, what is the pressure of the gas when the piston is moved so that the volume of the container becomes 130.3 mL? Round your answer to the nearest 0.01 and include units!

Answers

ANSWER

The final pressure of the gas is 342.31 torr

EXPLANATION

Given that;

The initial pressure of the gas is 767.7 torr

The initial volume of the container is 58.1 mL

The final volume of the container is 130.3mL

Follow the steps below to find the final pressure of the gas

In the given data, the temperature of the gas is fixed, therefore, we can apply Boyle's law to find the volume

Step 1; States Boyle's law

Boyle's law states that the volume of a given mass is inversely proportional to its applied pressure provided that the temperature of the gas remains constant.

Mathematically

\(\begin{gathered} \text{ V }\propto\text{ }\frac{1}{\text{ P}} \\ \text{ Introduce a proportionality constant} \\ \text{ V = }\frac{\text{ k}}{\text{ P}} \\ \text{ cross multiply} \\ \text{ k = PV} \\ \text{ P1 V1 = P2V2} \end{gathered}\)

Step 2; Substitute the given data into the above formula

\(\begin{gathered} \text{ 767.7 }\times\text{ 58.1 = P2 }\times\text{ 130.3} \\ \text{ 44603.37 = 130.3 P2} \\ \text{ Divide both sides by 130.3P2} \\ \text{ }\frac{\text{ 44603.37}}{130.3}\text{ = }\frac{\text{ 130.3 P2}}{130.3} \\ \text{ P2 = 342.31 torr} \end{gathered}\)

Therefore, the final pressure of the gas is 342.31 torr

Consider this reaction:

At a certain temperature it obeys this rate law.

rate

Suppose a vessel containsat a concentration of. Calculate the concentration ofin the vesselseconds later. You may assume no other reaction is important

Answers

The concentration of A after 30 seconds when the given reaction obeys the rate law rate = k[A]²[B].

We use the initial concentration of A and B and the rate constant of the reaction to find the rates at these concentrations. Using the integrated rate law for a second-order reaction, we find the concentration of A after 30 seconds to be 0.0934 M.

Given reaction obeys the rate law, rate=k[A]²[B].

Here, the initial concentration of A= 0.10 M,

initial concentration of B = 0.05 M, and

rate constant, k = 2.0 × 10⁻⁴ M⁻¹s⁻¹

We have to find the concentration of A, after 30 seconds.

To find the concentration of A, we need to know the rate at 0.10 M and 0.05 M. Therefore, we have to calculate the rates at these concentrations.

rate1 = k[A]²[B]

= (2.0 × 10⁻⁴ M⁻¹s⁻¹)(0.10 M)²(0.05 M)

= 1.0 × 10⁻⁷ M/srate2

= k[A]²[B] = (2.0 × 10⁻⁴ M⁻¹s⁻¹)(0.09 M)²(0.04 M)

= 6.48 × 10⁻⁸ M/s

Using the integrated rate law for a second-order reaction: [A] = [A]₀ - kt where [A]₀ = initial concentration of A, k = rate constant, and t = time in seconds.

We know [A]₀ = 0.10 M and k = 2.0 × 10⁻⁴ M⁻¹s⁻¹.

Substituting the values in the above equation, we get: [A] = [A]₀ - kt= 0.10 M - (2.0 × 10⁻⁴ M⁻¹s⁻¹)(30 s)≈ 0.0934 M

Therefore, the concentration of A in the vessel after 30 seconds is 0.0934 M.

This question requires us to calculate the concentration of A after 30 seconds when the given reaction obeys the rate law rate = k[A]²[B].

We are given the initial concentration of A and B and the rate constant of the reaction. To find the concentration of A after 30 seconds, we need to calculate the rates at the initial concentrations of A and B.

Using the integrated rate law for a second-order reaction, we can find the concentration of A at any given time. We substitute the given values in the formula and solve for [A]. We get the concentration of A as 0.0934 M after 30 seconds. This calculation is based on the assumption that no other reaction is important.

The concentration of A after 30 seconds when the given reaction obeys the rate law rate = k[A]²[B]. We use the initial concentration of A and B and the rate constant of the reaction to find the rates at these concentrations. Using the integrated rate law for a second-order reaction, we find the concentration of A after 30 seconds to be 0.0934 M. This calculation assumes that no other reaction is important.

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How many electrons can be held in sub level I=3?

Answers

2 is your answer hope you get it right

True or False, The crust is made up of different plates that can slowly move around?

Answers

Answer:

True

Explanation:

There is such thing called tectonic plated

Answer:

True

Explanation:

The crust is made of plates called tectonic plates that move as fast as your finger nails grow, the amount of movement can create both tall and deep earth wonders. Such as the Mariana Trench and Mount Everest. And it causes earthquakes when they slide together.

Pls mark brainliest

Have a nice day!

cfc-11 has a global warming potential (gwp) of 4750. the current global mean concentration of cfc-11 is approximately 220ppt. calculate, relative to co2, the percentage of warming attributed to cfc-11.

Answers

The relative contribution of CO2 attributed to global warming is 60 % in the environment.

What is global warming , responsible gases and percentage attributed from these gases?The decrease in the amount of sunlight due the increasing CO2 and air pollutant in the atmosphere absorbing sunlight is owing to global warming.Global warming is caused by gases such as CO2, CH4, and lots of air pollutants.Global warming is causing great harm to the natural atmosphere and effecting the plant growth too.The relative concentration of CO2 attributed to global warming is 60% of the total.And cfc -11 is the chloroflorocarbons responsible for increasing global warming effects.

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What happens to water when it is heated from 0 °C to 4 °C? (5 points)
It freezes.
It expands.
Its density increases.
Its composition changes.

Answers

Answer: The volume decreases

Explanation:

Because 4C is a cold temperature and atoms inside the water start to move slowly and begins to cange into a solid formation.

The density of the water increases and it is maximum at 4 degrees Celsius.

What is Freezing Point ?

The temperature at which the liquid and solid states of the substance are in equilibrium at atmospheric pressure .

freezing point of water is 0° Celsius or 32° Fahrenheit.

Though liquids expand on heating water does not expand between 0°C to 4°C instead it contracts as water has maximum density at 4°C.

Thus the option C is the right answer , The density of the water increases as water is heated from 0 degree Celsius to 4 degree Celsius

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Being able to curl your tongue is a recessive trait (t), while not being able to curl your tongue is a dominant trait (T).
Having curly hair is also a recessive trait (s), while having straight hair is a dominant trait (S).
Parent 1 can curl their tongue (tt) and also has straight hair (Ss). Parent 2 cannot curl their tongue (TT) and has
curly hair (ss). In your notebook, perform a dihybrid cross for these traits. Parent 1: ttSs Parent 2: TTSS
13
What are the Parent 1 gametes? (HINT: FOIL. There will be 4 genotypes)
14
What percent of offspring can curl tongue and have straight hair?
15
What percent of offspring cannot curl tongue and have curly hair?

Answers

should be this. you can’t have any of these listed below since they both rain recessive traits. recessive traits aren’t able to be created in the dihybrid. btw i did the simplified grid since they produce the same gametes. i could be wrong though (:
Being able to curl your tongue is a recessive trait (t), while not being able to curl your tongue is

When the [CO2] and [H2CO3] are both horizontal lines, the rate of the forward reaction is

the rate of the reverse reaction

faster than

slower than

the same as

Answers

When \(CO_{2}\) and \(H_{2} CO_{3}\) are both horizontal lines, the rate of the forward reaction is the same as the rate of the reverse reaction. The reaction is occurring at equilibrium, with no net change in the concentrations of reactants and products over time.

When the concentration of carbon dioxide \(CO_{2}\) and the concentration of carbonic acid \(H_{2} CO_{3}\) are both horizontal lines, it indicates that their concentrations remain constant over time. In such a scenario, the rate of the forward reaction is the same as the rate of the reverse reaction. A horizontal line on a concentration-time graph suggests that the concentrations of the reactants and products are not changing, implying that the reaction has reached equilibrium. At equilibrium, the rate of the forward reaction equals the rate of the reverse reaction. This is a fundamental principle of chemical equilibrium, described by the principle of microscopic reversibility.

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question in the picture

question in the picture

Answers

In the reaction, C\(_6\)H\(_{121}\)O\(_{6}\) + 6O\(_2\) → 6CO\(_2\)+ 6H\(_2\)O, O\(_2\) is the limiting reagent. Therefore, the correct option is option B.

The compounds that are completely consumed during the course if a chemical reaction are known as limiting reagents. Other names for them are limiting reactants and limiting agents. The stoichiometry if chemical processes states that a specific number of reactants are required for the process of reaction to be complete.

The reaction's stopping point is often determined by this reactant. The reaction stoichiometry is used to compute the precise quantity of reactant which would be required for a reaction with another element. Not the total amount of the reactants present, but the mole ratio determines the limiting reagent. In the reaction, C\(_6\)H\(_{121}\)O\(_{6}\) + 6O\(_2\) → 6CO\(_2\)+ 6H\(_2\)O, O\(_2\) is the limiting reagent.

Therefore, the correct option is option B.

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L.
Use a pencil and draw a line in the sequences below for
species A and species B to show where the catalyst
would cut the DNA.
Species A AATTGGCCTAATTAATTCGG CCTAG
Species B: AATTCCTACGG CCTAGCCTTTAATT

Answers

The catalyst BamH1 will cut the DNA as follows:

Species A: AATTG | GCCTAATTAATTCG | GCCTAG

Species B: AATTCCTACG | GCCTAGCCTTTAATT

What are restriction endonucleases?

Restriction endonucleases or restriction enzymes are enzymes that cleave DNA into pieces at or close to particular recognition regions inside molecules called restriction sites.

EcoRI, BamH1, and smaI are some examples of restriction endonucleases.

BamHI is a type II restriction enzyme that recognizes the DNA sequence "GGATCC" and cuts the DNA at in between G and G.

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MgCl2 (aq) + K2SO4 (aq) --> 2KCl (aq) + MgSO4 (s)
how many moles of potassium chloride are produced from 4.8 moles of magnesium chloride

Answers

Answer:

\(\boxed {\boxed {\sf 9.6 \ mol \ KCl}}\)

Explanation:

We must use stoichiometry to solve this, which is the calculation of reactants and products in a reaction using ratios.

Let's analyze the reaction given.

\(MgCl_2 _{(aq)} + K_2SO_4 _{(aq)} \rightarrow 2KCl _{(aq)} + MgSO_4 _{(s)}\)

Now, look at the coefficients, or numbers in front of the molecule formulas. If there isn't a coefficient, then a 1 is implied.

We want to find how many moles of potassium chloride (KCl) are produced from 4.8 moles of magnesium chloride (MgCl₂). Check the coefficients for these molecules.

MgCl₂: no coefficient= coefficient of 1 KCl: coefficient of 2

The coefficient represents the number of moles. Therefore, 1 mole of magnesium chloride produces 2 moles of potassium chloride. We can set up a ratio using this information.

\(\frac { 1 \ mol \ MgCl_2} {2 \ mol \ KCl}\)

Multiply by the given number of moles of magnesium chloride: 4.8

\(4.8 \ mol \ MgCl_2 *\frac { 1 \ mol \ MgCl_2} {2 \ mol \ KCl}\)

Flip the ratio so the moles of magnesium chloride cancel out.

\(4.8 \ mol \ MgCl_2 *\frac {2 \ mol \ KCl} { 1 \ mol \ MgCl_2}\)

\(4.8 *\frac {2 \ mol \ KCl} { 1 \ } }\)

\(4.8 * {2 \ mol \ KCl}\)

\(9.6 \ mol \ KCl\)

9.6 moles of potassium chloride are produced from 4.8 moles of magnesium chloride.

Predict which of the following two compounds will undergo an E2 reaction more rapidly:
O The cis isomer is faster because the Cl predominantly occupies an equatorial position.
O The cis isomer is faster because the Cl predominantly occupies an axial position.
O The trans isomer is faster because the CI predominantly occupies an axial position.
O The trans isomer is faster because the CI predominantly occupies an equatorial position.

Answers

The correct answer is: The trans isomer is faster because the CI predominantly occupies an axial position.

In an E2 (elimination) reaction, the rate of reaction is influenced by the orientation of the reacting groups. The reaction occurs through a concerted mechanism, where the leaving group and the hydrogen being removed are anti-coplanar to each other.

In the case of the cis and trans isomers, the arrangement of substituents around a double bond determines the accessibility of the hydrogen and the leaving group in an E2 reaction.

The trans isomer has the hydrogen and the leaving group (CI) in an anti-coplanar arrangement, which is favorable for an E2 reaction. This arrangement allows for efficient overlap of the orbitals involved in the bond formation and breaking during the reaction. Therefore, the trans isomer is more likely to undergo an E2 reaction more rapidly.

Conversely, the cis isomer has the hydrogen and the leaving group in a syn-coplanar arrangement, which is less favorable for an E2 reaction. The steric hindrance between the substituents can hinder the proper alignment of orbitals required for the reaction to occur efficiently.

Hence, the trans isomer is faster because the CI predominantly occupies an axial position, providing a better arrangement for an E2 reaction.

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The complete question is:

Predict which of the following two compounds will undergo an E2 reaction more rapidly:

The cis isomer is faster because the Cl predominantly occupies an equatorial position.

The cis isomer is faster because the Cl predominantly occupies an axial position.

The trans isomer is faster because the Cl predominantly occupies an axial position.

The trans isomer is faster because the Cl predominantly occupies an equatorial position.

Predict which of the following two compounds will undergo an E2 reaction more rapidly:O The cis isomer
Predict which of the following two compounds will undergo an E2 reaction more rapidly:O The cis isomer

How many moles are there in 3.612 x 1024 atoms of Sulfur?

Answers

Answer:

The answer is 6 moles

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

\(n = \frac{N}{L} \\ \)

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

\(n = \frac{3.612 \times {10}^{24} }{6.02 \times {10}^{23} } \\ \)

We have the final answer as

6 moles

Hope this helps you

what is the theoretical yield of acetaminophen product when 3.0 grams of 4-aminophenol are combined with 3.5 ml of acetic anhydride? enter your response in grams (g) to the nearest 0.01 g. g

Answers

P-aminophenol has a molar mass of 109.13 g/mol. Acetaminophen has a molar mass of 151.17 g/mol. Acetic anhydride has a capacity of 1.1 mL.

How is the theoretical yield of acetaminophen determined?

The mass of acetaminophen, stated as 0.157g, must be multiplied by the molar mass of acetaminophen to get the theoretical yield. It weighs 151.2g in this case. The theoretical yield thus becomes 0.217g.

How is production yield determined?

A measurement called production yield is obtained by dividing the number of high-quality parts produced by the total number of parts started in production.

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What are chemical changes of matter?

Answers

Answer:

Chemical Changes are also called Chemical Reactions. Chemical reactions involve combining different substances. The chemical reaction produces a new substance with new and different physical and chemical properties. Matter is never destroyed or created in chemical reactions.

Explanation:

If 1.50 g of h2c2o4 . 2h2o were heated to drive off the water of hydration, how much anhydrous h2c2o4 would remain?

Answers

If 1.50 g of H₂C₂O₄.2H₂O were heated to drive off the water of hydration, 1.071 g of anhydrous H₂C₂O₄ would remain.

The balanced chemical equation of reaction is :

           H₂C₂O₄.2H₂O  →  H₂C₂O₄ + 2H₂O

First calculate the molecular weight of hydrated H₂C₂O₄ -

Using the molecular masses of -

O = 16 g/mol, C = 12 g/mol, and H = 1 g/mol

Total mass of compound = 126 g/mol

Molecular mass of H₂C₂O₄ = 90 g/mol

and, molecular mass of water of hydration = 36 g/mol

The percentage of H₂C₂O₄ in H₂C₂O₄.2H₂O is -

% H₂C₂O₄ = 90 g/mol = 0.714 %

                    126 g/mol

To calculate remainingIf 1.50 g of H₂C₂O₄.2H₂O were heated to drive off the water of hydration, 1.071 g of anhydrous H₂C₂O₄ would remain.

The balanced chemical equation of reaction is :

           H₂C₂O₄.2H₂O  →  H₂C₂O₄ + 2H₂O

First calculate the molecular weight of hydrated H₂C₂O₄ -

Using the molecular masses of -

O = 16 g/mol, C = 12 g/mol, and H = 1 g/mol

Total mass of compound = 166 g/mol

Molecular mass of H₂C₂O₄ = 126 g/mol

and, molecular mass of water of hydration = 36 g/mol

% H₂C₂O₄ = 126 g/mol = 0.7590

                    166 g/mol

75.90 % of 1.50 g = 0.714

To calculate remaining amount of anhydrous H₂C₂O₄,

we take percentage of anhydrous H₂C₂O₄ with the mass of hydrous compound which is heated.

71.4% of 1.50 g = 1.071 g

Therefore,

The anhydrous H₂C₂O₄ remaining is 1.071 g.

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when carbon is heated in a limited supply of oxygen, a gas is obtained.
1 .what is the name of this gas​

Answers

Answer:

carbon monoxide

I think its correct but I am not sure

Answer: when carbon is heated in air carbon dioxide is formed, so is incomplete combustion which results in carbon monoxide.

Explanation: but when carbon dioxide reacts with more oxygen carbon monoxide is formed i guess.

I AM A BIT SURE BUT HOPE THIS HELPSSSS!!!!

calculate the isoionic and isoelectric ph of 0.028320.02832 m valine. enter your answers to the hundredths place.

Answers

Answer:

isoelectronic pH = 6.003

Explanation:

isoelectronic pH = (pKa1+pKa2)/2

Which phrase describes chemical potential energy?

A) the amount of energy stored in bonds
B) the amount of energy absorbed by products
C) the amount of energy needed to break a bond
D) the amount of energy absorbed by reactants

Answers

Answer:

the amount of energy stored in bonds

Explanation:

potential energy is stored energy and chemical just refers to energy stored in chemical bonds

i took the quiz

The term describes chemical potential energy is  the amount of energy stored in chemical bonds. Hence, option C is correct.

What is chemical potential energy ?

Chemical potential energy is the energy held inside a substance's chemical bonds. When gasoline is burnt in a regulated manner in the car's engine, a significant quantity of chemical potential energy that is present in the many compounds that make up gasoline is released.

When that energy is released, two things happen: part of the potential energy is converted into work, which is used to drive the automobile, and some of it is also converted to heat, which heats up the engine of the car. A system's energy changes take the form of heat, work, or a mix of the two.

Therefore, option A is correct.

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nitrogen and oxygen can react to form nitrite oxide gas. N2(g)+O2(g) arrow 2NO(g) delta h reaction = 180.6kj. if 2976 kj of heat is absorbed by the reaction how many moles of NO can be produced

Answers

The balanced equation for the reaction is N2(g) + O2(g) → 2NO(g).

The given value for the enthalpy change of the reaction is ΔH = 180.6 kJ. This value represents the heat released per mole of N2 reacted.

To determine the number of moles of NO produced, we need to calculate the moles of N2 reacted. Since the reaction is exothermic, the heat absorbed by the reaction is negative (-2976 kJ). However, it is not physically possible to have a negative number of moles. Therefore, we can conclude that no NO is produced in this case because the heat absorbed is insufficient to drive the reaction.

Using the equation ΔH = -2976 kJ/mol N2, we can set up a proportion:

180.6 kJ/1 mol N2 = -2976 kJ/x mol N2

Solving for x, we find:

x = (-2976 kJ * 1 mol N2) / (180.6 kJ) ≈ -16.46 mol N2

Since the reaction produces 2 moles of NO for every mole of N2, the number of moles of NO produced is twice the number of moles of N2:

Moles of NO = 2 * (-16.46 mol) ≈ -32.92 mol

The given reaction is N2(g) + O2(g) → 2NO(g), and the enthalpy change of the reaction is ΔH = 180.6 kJ. If the reaction absorbs 2976 kJ of heat, the number of moles of NO that can be produced can be calculated. By setting up a proportion, we find that approximately -16.46 moles of N2 are reacted. Since the reaction produces 2 moles of NO for every mole of N2, the calculated moles of NO would be approximately -32.92. However, negative moles are not physically possible, indicating that no NO can be produced in this case due to insufficient heat absorbed by the reaction.

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chloride per milliliter (MW of CaCl2 = 147) [Round to the nearest whole number 5. What weight of magnesium chloride (MgCl2, formula weight = 95.3) is required to prepare 200 ml solution that is 5.0 mi

Answers

The weight of magnesium chloride required to prepare the 200 ml solution that is 5.0 M is approximately 48 grams.

To calculate the weight of magnesium chloride (\(MgCl_{2}\)) required to prepare a 200 ml solution that is 5.0 M, we need to use the formula: Weight (in grams) = Volume (in liters) × Concentration (in moles/liter) × Molecular Weight (in grams/mole)

First, we convert the volume from milliliters to liters by dividing it by 1000: Volume = 200 ml ÷ 1000 = 0.2 L. Next, we multiply the volume, concentration, and molecular weight: Weight = 0.2 L × 5.0 mol/L × 95.3 g/mol = 47.65 grams

Rounding to the nearest whole number, the weight of magnesium chloride required to prepare the 200 ml solution that is 5.0 M is approximately 48 grams.

This calculation ensures that the desired concentration is achieved by accurately measuring the appropriate amount of magnesium chloride, taking into account its molecular weight and the desired volume of the solution.

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7.95x10 converted to the number is

Answers

7.95 × 10

= 79.5

This is the answer

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