State the size of the total drag force when the car is travelling at constant speed

Answer:

The International Building Code (IBC) is a model code that provides minimum requirements to safeguard the public health, safety and general welfare of the occupants of new and existing buildings and structures.

Explanation:

it is undesirable that all of the points should fall extremely near, or exactly on, the centerline of the control chart Because:

If a data point falls is said to outside the control limits, we can say that the process is said to be out of one's control and it is good that an investigation is done to ascertain and remove the cause or causes.

So, it is undesirable that all of the points should fall extremely near, or exactly on, the centerline of the control chart Because:

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Answer:

1) The three possible assumptions are

a) All processes are reversible internally

b) Air, which is the working fluid circulates continuously in a closed loop

cycle

c) The process of combustion is depicted as a heat addition process

2) The diagrams are attached

5) The net work per cycle is 845.88 kJ/kg

The power developed in horsepower ≈ 45374 hP

Explanation:

1) The three possible assumptions are

a) All processes are reversible internally

b) Air, which is the working fluid circulates continuously in a closed loop

cycle

c) The process of combustion is depicted as a heat addition process

2) The diagrams are attached

5) The dimension of the cylinder bore diameter = 3.7 in. = 0.09398 m

Stroke length = 3.4 in. = 0.08636 m.

The volume of the cylinder v₁= 0.08636 ×(0.09398²)/4 = 5.99×10⁻⁴ m³

The clearance volume = 16% of cylinder volume = 0.16×5.99×10⁻⁴ m³

The clearance volume, v₂  = 9.59 × 10⁻⁵ m³

p₁ = 14.5 lbf/in.² = 99973.981 Pa

T₁ = 60 F = 288.706 K

\(\dfrac{T_{2}}{T_{1}} = \left (\dfrac{v_{1}}{v_{2}} \right )^{K-1}\)

Otto cycle T-S diagram

T₂ = 288.706*\(6.25^{0.393}\) = 592.984 K

The maximum temperature = T₃ = 5200 R = 2888.89 K

\(\dfrac{T_{3}}{T_{4}} = \left (\dfrac{v_{4}}{v_{3}} \right )^{K-1}\)

T₄ = 2888.89 / \(6.25^{0.393}\) = 1406.5 K

Work done, W = \(c_v\)×(T₃ - T₂) - \(c_v\)×(T₄ - T₁)

0.718×(2888.89  - 592.984) - 0.718×(1406.5 - 288.706) = 845.88 kJ/kg

The power developed in an Otto cycle = W×Cycle per second

= 845.88 × 2400 / 60  = 33,835.377 kW = 45373.99 ≈ 45374 hP.

Answer:

The appropriate answer will be "2353.8 K". A further solution is given below.

Explanation:

The given values are:

Ultimate capacity,

= 1700kN

Resistance factor,

F.S = 0.65

According to the the LRFD, the allowable bearing pressure will be:

⇒ \(Pallo w = \phi_c\times \frac{Pn}{F.S}\)

On substituting the values, we get

⇒             \(=0.9\times \frac{1700}{0.65}\)

⇒             \(=2353.8 \ K\)

According to the the ASD, the allowable bearing pressure will be:

⇒ \(Pallow=\frac{Pn}{\Omega \times F.S}\)

On substituting the values, we get

⇒             \(=\frac{1700}{1.67\times 0.65}\)

⇒             \(= \frac{1700}{1.0855}\)

⇒             \(=1845.35 \ K\)

Answer:

yes.

Explanation:

Answer:

a. \(Total\ Cost = \$2667\)

b. \(Total\ Cost = \$667\)

Explanation:

(a)

Given

\(Distance = 10000\ miles\)

\(Rate = 15\ miles/gallon\)

\(Price = \$4.00/gallon\)

Required

Determine the total amount spent in a year

First, we need to determine the number of gallons used in a year;

\(Total\ Gallons = Distance/Rate\)

\(Total\ Gallons = 10000miles /\frac{15miles}{gallon}\)

\(Total\ Gallons = 10000miles * \frac{1\ gallon}{15\ miles}\)

\(Total\ Gallons = 10000 * \frac{1\ gallon}{15}\)

\(Total\ Gallons = \frac{10000\ gallons}{15}\)

\(Total\ Gallons = \frac{10000}{15}\ gallons\)

Next, is to determine the total cost:

\(Total\ Cost = Total\ Gallons * Price\)

\(Total\ Cost = \frac{10000}{15}\ gallon * \frac{\$4}{gallon}\)

\(Total\ Cost = \frac{10000}{15} * \$4\)

\(Total\ Cost = \frac{10000 * \$4}{15}\)

\(Total\ Cost = \frac{\$40000}{15}\)

\(Total\ Cost = $2666.66666667\)

\(Total\ Cost = \$2667\) (approximated)

(b)

Given

\(Rate = 60\ miles/gallon\)

Required

Determine the total amount spent in a year

First, we need to determine the number of gallons used in a year;

\(Total\ Gallons = Distance/Rate\)

\(Total\ Gallons = 10000miles /\frac{60\ miles}{gallon}\)

\(Total\ Gallons = 10000miles * \frac{1\ gallon}{60\ miles}\)

\(Total\ Gallons = 10000 * \frac{1\ gallon}{60}\)

\(Total\ Gallons = \frac{10000\ gallons}{60}\)

\(Total\ Gallons = \frac{10000}{60}\ gallons\)

Next, is to determine the total cost:

\(Total\ Cost = Total\ Gallons * Price\)

\(Total\ Cost = \frac{10000}{60}\ gallon * \frac{\$4}{gallon}\)

\(Total\ Cost = \frac{10000}{60} * \$4\)

\(Total\ Cost = \frac{10000 * \$4}{60}\)

\(Total\ Cost = \frac{\$40000}{60}\)

\(Total\ Cost = \$666.666666667\)

\(Total\ Cost = \$667\) (approximated)

"Use a theory that accounts for material yielding" to avoid false answers that use the method of finite elements based on linear elastic material model assumptions.

Thus, "Use a theory that accounts for material yielding" to avoid false answers that use the method of finite elements based on linear elastic material model assumptions.

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The TCP/IP configuration parameter that identifies the router used to reach hosts on remote networks is:

6) Default Gateway.

The Default Gateway is the TCP/IP configuration parameter that identifies the router responsible for forwarding traffic to hosts on remote networks. It acts as an intermediary device that helps devices on a local network communicate with devices on different networks.

The default gateway is typically assigned an IP address, and it must be configured on each device within a network to enable communication with devices outside of that network.

It acts as the intermediary between the local network and external networks, such as the internet. When a device wants to communicate with a destination that is not within its local network, it sends the packet to the default gateway, which determines the next hop or the appropriate path for the packet to reach its destination.

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An analog signal is a continuous waveform that carries information as a variable voltage, while a digital signal is a series of discrete values that represent a sequence of logic states.

What is analog signal?
An analog signal is a type of continuous signal that represents physical measurements in a continuous fashion. Analog signals are typically used to transmit information that can vary over a wide range of values, such as sound or temperature. Analog signals are created by encoding the information in a sine wave or other repeating waveform. The signal varies in amplitude, frequency, or phase in order to convey the information. Analog signals are generally transmitted through wires or cables, although wireless transmission is also possible. Analog signals can suffer from noise, distortion, and signal loss during transmission, which can reduce the accuracy of the information being sent. To reduce these issues, digital signal processing is commonly used to convert analog signals into digital signals.

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Answer:

Objects that float on water have densities less than the density of water; those that do not float on water have densisties greater than the density of water:

Float on water:  d < 0.0361 lb/in³ (where d denotes denisity)

Do not float on water:  d > 0.0361 lb/in³

Explanation:

I don't know if this works for it or not?

Answer:

hola

Explanation:

Explanation:

so its an question?..........

I would honestly select every one of the given options. Gor a company evaluating this new material it would be very valuable to hit each of these factors.

Excess resources is not a common challenge of the Six Sigma Methodology within an organization. The common challenges are lack of support, poor project execution, and lack of access to data.

The Six Sigma Methodology is a process improvement methodology focused on reducing defects and increasing customer satisfaction. Common challenges of this methodology within an organization include lack of support, poor project execution, and lack of access to data. Excess resources, however, is not a common challenge as this would not directly impact the success of the methodology. Lack of support is often seen when senior management doesn’t understand the value of the methodology and fails to provide resources or support for its implementation. Poor project execution is common when the methodology isn’t applied correctly or if the organization lacks the necessary training or skills to complete the project successfully. Finally, lack of access to data is a common challenge when the organization does not have adequate data to identify problems and create solutions. Therefore, excess resources is not a common challenge of the Six Sigma Methodology within an organization.

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Answer:

  infinite

Explanation:

The impedance of an ideal parallel resonant circuit is infinite at the resonant frequency. The sum of the admittances of the branches of the circuit is zero.

The diameter, bolt M27 is known to be 3.0mm in pitch and 41mm across flats.

This is a term that is often seen as the Major diameter. The diameter of a bolt is known to be a kind of a Shank diameter which is said to be often shown or expressed in the unit called millimeters in regards to Metric bolts.

This is so due to the  fact that it is almost the same as the Major or Thread diameter.

Therefore, The diameter, bolt M27 is known to be 3.0mm in pitch and 41mm across flats.

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The wired networking standard that specifies the order in which data is sent through the network is Ethernet.

Ethernet is a widely used wired networking standard that defines the protocols and specifications for data transmission over a local area network (LAN). It specifies the order in which data is sent through the network by utilizing the Carrier Sense Multiple Access with Collision Detection (CSMA/CD) algorithm.

The CSMA/CD algorithm ensures that multiple devices connected to an Ethernet network can share the same communication medium without interfering with each other. Before transmitting data, a device using Ethernet listens to the network to detect if it is clear to send data. If the network is busy, it waits for an opportune moment. Once the network is clear, the device sends the data, constantly monitoring for collisions. If a collision occurs (when two or more devices transmit data simultaneously), they stop transmitting, wait for a random period of time, and then retry.

By following this protocol, Ethernet ensures orderly and efficient data transmission within the network, minimizing collisions and maximizing data throughput. It has become the de facto standard for wired local area networks due to its reliability, scalability, and widespread adoption.

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Answer: 75,000 Hz

Explanation:

To calculate the frequency of the supply voltage, we need to use the formula:

frequency = 1 / time period

where the time period is the time it takes for one complete cycle of the waveform. For a sine wave, the time period is given by:

time period = 2π / angular frequency

where the angular frequency is the rate of change of the angle with respect to time and is given by:

angular frequency = 2π × frequency

Comparing the given voltage expression v = 240 sin (471,239t) V to the general form of a sine wave:

v = Vm sin(ωt + θ)

where Vm is the amplitude, ω is the angular frequency, t is time, and θ is the phase angle, we can see that the amplitude is 240 V, the angular frequency is 471,239 rad/s, and there is no phase angle (θ = 0).

Using the formula for angular frequency, we can find the frequency:

angular frequency = 2π × frequency

471,239 = 2π × frequency

frequency = 471,239 / (2π) ≈ 75,000 Hz

Therefore, the frequency of the supply voltage is approximately 75,000 Hz.

Hope this helps, :^)

Answer: A. The output DC voltage will be lower

Explanation:

Using a resistor in a power-supply filter instead of an inductor will lead to a lower DC voltage output as resistors reduce voltage.

It would therefore be ideal to use an inductor as it does not lower DC voltage but inductors are expensive and can be quite large which is why it is more common to see resistors used in power-supply filter circuits.

Answer:

Explanation:

Given that:

diameter = 100 mm

initial temperature = 500 ° C

Conventional coefficient = 500 W/m^2 K

length  = 1 m

We obtain the following data from the tables A-1;

For the stainless steel of the rod \(\overline T = 548 \ K\)

\(\rho = 7900 \ kg/m^3\)

\(K = 19.0 \ W/mk \\ \\ C_p = 545 \ J/kg.K\)

\(\alpha = 4.40 \times 10^{-6} \ m^2/s \\ \\ B_i = \dfrac{h(\rho/4)}{K} \\ \\ =0.657\)

Here, we can't apply the lumped capacitance method, since Bi > 0.1

\(\theta_o = \dfrac{T_o-T_{\infty}}{T_i -T_\infty}} \\ \\ \theta_o = \dfrac{50-30}{500 -30}} \\ \\ \theta_o = 0.0426\\\)

\(0.0426 = c_1 \ exp (- E^2_1 F_o_)\\ \\ \\ 0.0426 = 1.1382 \ exp (-10.9287)^2 \ f_o \\ \\ = f_o = \dfrac{In(0.0374)}{0.863} \\ \\ f_o = 3.81\)

\(t_f = \dfrac{f_o r^2}{\alpha} \\ \\ t_f = \dfrac{3.81 \times (0.05)^2}{4.40 \times 10^{-6}} \\ \\ t_f= 2162.5 \\ \\ t_f = 36 mins\)

However, on a single rod, the energy extracted is:

\(\theta = pcv (T_i - T_{\infty} )(1 - \dfrac{2 \theta}{c} J_1 (\zeta) ) \\ \\ = 7900 \\times 546 \times 0.007854 \times (500 -300) (1 - \dfrac{2 \times 0.0426}{1.3643}) \\ \\ \theta = 1.54 \times 10^7 \ J\)

Hence, for centerline temperature at 50 °C;

The surface temperature is:

\(T(r_o,t) = T_{\infty} +(T_1 -T_{\infty}) \theta_o \ J_o(\zeta_1) \\ \\ = 30 + (500-30) \times 0.0426 \times 0.5386 \\ \\ \mathbf{T(r_o,t) = 41.69 ^0 \ C}\)

Rigid schedule 80 pvc shall have a minimum burial depth of 18 inches.

Rigid schedule 80 PVC is a type of polyvinyl chloride pipe commonly used in various applications, including underground installations. The minimum burial depth refers to the depth at which the pipe should be buried to ensure proper protection and structural integrity.

The required minimum burial depth for rigid schedule 80 PVC is determined by factors such as the type of soil, traffic loads, and environmental conditions. It is essential to follow local building codes and regulations, as they may specify specific requirements for burial depths. Generally, the recommended minimum burial depth for rigid schedule 80 PVC ranges from 18 to 24 inches.

Proper burial depth helps protect the PVC pipe from external stresses, such as vehicle traffic or ground movement. It also safeguards the pipe from potential damage caused by temperature fluctuations or exposure to sunlight. By burying the pipe at the appropriate depth, the risk of accidental damage and potential leaks or breaks is significantly reduced.

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Answer:

sorry di ko alam

Explanation:

The ideal linear response equation for the sound measurement element is V(P) = mP + b, where m is the slope and b is the y-intercept.

In a linear response equation, the output is directly proportional to the input. In this case, the output voltage (V) is proportional to the input pressure (P).

To find the slope and y-intercept, we can rewrite the calibration function as V(P) = 21 + 2000/P = (2000/P)P + 21, which is in the form of y = mx + b. Therefore, the slope is m = 2000/P and the y-intercept is b = 21.

The ideal linear response equation for the sound measurement element is V(P) = 2000/P * P + 21, which simplifies to V(P) = 2000 + 21P/P.

However, since P cannot equal zero, the actual linear response equation should be V(P) = 2000/P * P + 21 for P > 0. This equation shows how the output voltage changes with respect to the input pressure, which can be useful for accurately measuring and analyzing sound.

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Answer:

yes

Explanation:

an idea could be a jack o lantern monster since it Halloween tomorrow  

Answer:

Explanation:

Like requested the following function is written in JavaScript and prompts the user for a total amount of Kenyan Currency that needs to be converted. It then places that value in a variable and divides it by 115 Ksh so that it gives us the USD value of that currency. Then that value is returned. The function can be attached to any button but it must be done manually when creating the button's onClick method.

function convertCurrency() {

 var KenyanAmount = prompt("Please enter the amount of Kenyan you want to convert.");

 var usdValue = "$" + (KenyanAmount / 115);

 return usdValue;

}

The program is a sequential program, and does not require loops and conditional statements

The function in JavaScript where comments are used to explain each line is as follows:

//This defines the function

function convertCurrency() {

//This gets input for the amount to convert

var Amount = prompt("Kenyan Shillings: ");

//This converts the Kenyan Shillings to US Dollars

var usdValue = KenyanAmount / 115;

//This returns the converted amount to the main method

return usdValue;

}

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Answer:

  3.2 mV

Explanation:

The cutoff frequency is the frequency at which the circuit power output is half the peak value. That means the voltage is (√2/2) times the peak voltage:

  (√2/2)(4.5 mV) ≈ 3.2 mV

The maverick hybrid powertrain is an innovative system that combines a 2.5L Atkinson-cycle I-4 gasoline engine with an electric motor. When these two power sources work together, they can produce a considerable amount of power.

The gasoline engine in the maverick hybrid powertrain is designed using the Atkinson cycle, which is a thermodynamic cycle that improves fuel efficiency by reducing energy losses during combustion. This engine alone can produce up to 162 horsepower and 155 lb-ft of torque.

However, when the electric motor is added to the equation, the total power output of the hybrid powertrain increases significantly. The electric motor can provide up to 94 horsepower and 173 lb-ft of torque, which is a significant boost to the overall power output of the system.

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