Sport is an attractive activity for young people, and is often used as a draw card to recruit children and ...................... people to health andeducation programs.​

Answer:

Light from the Sun reaches Earth very quickly. The (4) speed of light is 186,000 miles per second! We capture sunlight using (5) solar panels, which are devices that use the (6) photovoltaic effect to convert light to electricity. As atoms absorb energy, the electrons get “excited” and release energy as (7) photons. Whatever light that is not absorbed will (8) reflect off the surface of the object and bounce back toward the source.

Change of state due to cooling is due to the removal of thermal energy from a substance. A substance changes states, such as from a gas to a liquid or from a liquid to a solid, when its particles lose kinetic energy as it loses heat and moves more slowly. Eventually, the particles reorganize into a more ordered form with less energy. The term "solidification" or "freezing" refers to this process.

Answer:

Looks like  streak color.

Explanation:

Answer:

Aluminum foil is negatively charged and gold fillings are positively charged.

Hope this helps :)

The kinetic energy of the flywheel after 1 minute of rotation, given that it has a mass of 50 and radius of 40 cm is 32.4 KJ (Option D)

We'll begin by obtaining the velocity of the flywheel. This is shown below:

v = at

v = 0.6 × 60

v = 36 m/s

Finally, we shall determine the kinetic energy of the flywheel. Details below:

KE = ½mv²

KE = ½ × 50 × 36²

KE = 25 × 1296

KE = 32400 J

Divide by 1000 to express in KJ

KE = 32400 / 1000

KE = 32.4 KJ

Thus, the kinetic energy is 32.4 KJ (Option D)

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Explanation:

Friction acts between two surfaces in contact only and opposes the movement of one body with respect to another. Therefore friction is a force which opposes the relative motion between two bodies. If a body is moving it is slowed down by frictional force applied on it by the surface on which it is moving.

Answer:

Explanation:

Before you can find the force, you need to find the acceleration.

Givens

vi = 0

vf = 30 m/s

t = 7 seconds

Formula

a = (vf - vi) / t

Solution

a = (30 - 0)/7

a = 4.28 m/s

Now you can look at the Force

F = m * a

F = 1.00*10^3 * 4.28

F = 4.28 * 10^3 N

The spring stiffness is quantified by the spring constant, or k. For various springs and materials, it varies.

The stiffer the spring is and the harder it is to stretch, the larger the spring constant.

Springs are pliable mechanical devices that regain their previous shape after deforming, i.e. after being stretched or compressed. They are an essential part of many different mechanical devices.

The well-known metal coil has evolved into an essential element in the modern world, appearing in everything from engines to appliances to tools to automobiles to medical equipment and even basic ball-point pens. The spring's ability to store mechanical energy accounts for its widespread use and applications.

Therefore, The spring stiffness is quantified by the spring constant, or k. For various springs and materials, it varies.

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Answer:

The answer is 0.042 Hz (rounded)

or 0.0417 Hz

Explanation:

Hope it helps

Answer:

The answer is 0.041Hz

Explanation:

The answer is 0.041Hz

I guess

The car is moving at approximately 12.5 meters per second.

The kinetic energy (KE) of an object can be calculated using the formula:

KE = 1/2 * m * \(v^2\)

where

KE = kinetic energy,

m =Mass of the object, and

v = velocity.

In this case, we are given the mass (m) of the car as 1600 kg and the kinetic energy (KE) as 125,000 J. To find the velocity .

Substituting the  values , we have:

125,000 J = 1/2 * 1600 kg *\(v^2\)

Now, we can solve for v by rearranging the equation:

\(v^2\) = (2 * 125,000 J) / 1600 kg

\(v^2\) = 156.25 \(m^2/s^2\)

Taking the square root, we find:

v = √156.25\(m^2/s^2\)

v ≈ 12.5 m/s

Therefore, the car is moving at approximately 12.5 meters per second.

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Answer:

Explanation:

1. eectromagnetic Fields. Most of the processes that accelerate particles to relativistic speeds work with electromagnetic fields to the same force that keeps magnets on your fridge!

Magnetic Explosions

Wave-Particle Interaction's

At 30°C, the rms speed of a sample of oxygen with a molar mass of 16 g/mol is approximately 482.34 m/s.

The root mean square (rms) speed of a gas molecule is a measure of the average speed of the gas particles in a sample. It can be calculated using the formula:

vrms = √(3kT/m)

Where:

vrms is the rms speed

k is the Boltzmann constant (1.38 x 10^-23 J/K)

T is the temperature in Kelvin

m is the molar mass of the gas in kilograms

To calculate the rms speed of oxygen at 30°C (303 Kelvin) with a molar mass of 16 g/mol, we need to convert the molar mass to kilograms by dividing it by 1000:

m = 16 g/mol = 0.016 kg/mol

Substituting the values into the formula, we have:

vrms = √((3 * 1.38 x 10^-23 J/K * 303 K) / (0.016 kg/mol))

Calculating this expression yields the rms speed of the oxygen sample:

vrms ≈ 482.34 m/s

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Gary's weight at 300 km above Earth's surface is 91% of his weight at the surface.

The Earth's surface is a living union of its solid crust, atmosphere, hydrosphere, and biosphere, all of which have worked together to create a continually regenerating and dynamic symphony of form. From the Solar System Encyclopedia.

It has a substantial and dynamic surface with mountains, valleys, canyons, plains, and a variety of other features. Earth is unique in that it is an ocean world. 70% of the Earth's surface is covered by water. The Earth's atmosphere is mainly nitrogen, with enough of oxygen for humans to breathe.

a) The mass of an object is an intrinsic attribute, which means that it is determined only by the qualities of the thing and is not affected by its position. As a result, Gary's mass at 300 kilometers above the Earth's surface equals his mass at the Earth's surface.

b) The weight of an object is given by, W = mg

where

m is the mass and g = GM /r²

It is the gravitational acceleration at the location of the object, with G being the gravitational constant, M the mass of the planet and r the distance of the object from the center of the planet.

At the Earth's surface, g = 9.81 m/sec²

so Gary's weight is W = mg

W = 9.81 m  ...........(1)

where m is Gary's mass.

Then, we must calculate the value of g at 300 km above Earth's surface. the Earth's radius is, R = 6370 Km.

So the distance of Gary from the Earth's center is:

r = R + h

r = (6370 +300) Km

r = 6670 km

r = 6.67 × 10⁶ m

The Earth's mass is M = 5.97 × 10²⁴ Kg , so the gravitational acceleration is, g₁ = GM /r²

g₁ = [(6.67 10⁻¹¹ m³ kg⁻¹ s⁻²) × (5.97 × 10²⁴ Kg)] ÷ (6.67 × 10⁶ m)²

g₁ = 8.95 m/sec²

Therefore, Gary's weight at 300 km above Earth's surface is:

W₁ = mg₁

W₁ = 8.95 m  ............(2)

If we compare (1) and (2), we find that Gary's weight has changed by

W₁/W = 8.95 m/ 9.81 m

W₁/W = 0.91

So, Gary's weight at 300 km above Earth's surface is 91% of his weight at the surface.

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Answer:

No

Explanation:

because there is no pressure

Answer: 3.38 km per hour

Explanation:

(a) The maximum acceleration the car can have without causing the cup to slide is 1.96 m/s².

(b) The smallest amount of time in which the person can accelerate the car from rest to the final speed is 12.25 seconds.

The maximum acceleration the car can have without causing the cup to slide is calculated as follows;

For the car not to slide, the applied force must equal the force of friction, so the that the acceleration of the car is zero.

F - Ff = ma

F - Ff = 0

F = Ff

ma = μmg

a = μg

where;

a = 0.2 x 9.8 m/s²

a = 1.96 m/s²

The smallest amount of time in which the person can accelerate the car from rest to the final speed is calculated as follows;

v = u + at

v = 0 + at

t = v/a

t = (24 m/s) / (1.96)

t = 12.25 s

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In order to measure the resistance in the circuit, we need to know the voltage V and the current I in the circuit, this way we can calculate the resistance using the formula:

In order to calculate the current, we can use an amperemeter that must be in series with the circuit, this way it will not affect the circuit.

And in order to calculate the voltage, we can use a voltmeter that must be in parallel with the resistance, this way it will not affect the circuit.

The correct option that shows an amperemeter in series and a voltmeter in parallel is the fourth option.

Answer:

\(force = mass \times acceleration \\ 100 = 50 \times a \\ a = 2 \: {ms}^{ - 2} \\ from : \: \: v = u + at \\ 150 = 100 + (2 \times t) \\ 50 = 2t \\ time = 25 \: seconds\)

Answer:

48.4 m

Explanation:

To calculate the horizontal distance we need to find the flight time:

\( y_{f} = y_{0} + v_{0y}*t - \frac{1}{2}gt^{2} \)

Where:

\(y_{f}\) is the final height

\(y_{0}\) is the initial height

\(v_{0y}\) is the initial vertical speed

t is the time

g is the gravity

\( 0 = 36.0 m - \frac{1}{2}9.81t^{2} \)

\(t = \sqrt{\frac{2*36.0 m}{9.81 m/s^{2}}} = 2.71 s\)

Now, we can find the distance:

\( x_{f} = x_{0} + v_{0x}*t + \frac{1}{2}at^{2} \)

\(x_{f} = 12.0 m/s*2.71 s + \frac{1}{2}1.60 m/s^{3}(2.71 s)^{3} = 48.4 m\)

Therefore, the horizontal distance traveled by the rocket is 48.4 m.

I hope it helps you!

The power loss over the given distance in which the current is carried is 12 MW.

option D is the correct answer.

The current carried in the power line is calculated by applying Ohms law as follows;

V = IR

P = IV

I = P/V

where;

I = (250 x 10⁶) / (230,000)

I = 1,086.96 A

The power loss over the given distance in which the current is carried is calculated as;

P = I²R

where;

P = (1,086.96²) x 10

P = 11.8 x 10⁶ W

P ≈ 12 x 10⁶ W

P = 12 MW

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The answers are 4. The distance from where the ball was kicked is 38.06 meters, 5. The speed of the ball 2.5 seconds after it was kicked is 13.82 m/s, and  6. The ball is 21.88 meters above the ground 2.5 seconds after it is kicked.

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Answer: When substances are chemically combined, the properties of the new substances that are formed are often different from the properties of the original substances.

Explanation:

Answer:

A dekagram is thousand (1000) times larger than a centigram.

Explanation:

→ [1 dekagram = 1,000 centigrams]

→ 1 dekagram = 10 grams

→ 10 grams = 100 decigrams

→ 100 decigrams = 1,000 centigrams

Answer:

organizing

Explanation:

thinking about where things should go, to make it so that everybody has an easy experience when inside of my store.

The half-life of hypothetical element  technetium-99 is 210,936 years.

Half-life of the hypothetical element From the graph provided in the question, the half-life of the hypothetical element can be obtained by finding the time taken for the element to reduce to half its original quantity. Here, it can be seen from the graph that the quantity of the element reduces from 40 to 20 on day 4. Therefore, the half-life of the hypothetical element is 4 days.2. Time taken for a sample to decay from 100 grams to 25 gramsIf the half-life of a given substance is 65 days, then the quantity of the substance reduces to half every 65 days. From 100 grams to 50 grams, it takes one half-life cycle. From 50 grams to 25 grams, it will take another half-life cycle.

Therefore, it will take two half-life cycles, which is 2 × 65 = 130 days, for a 100-gram sample of the substance to decay until there is only 25 grams of the radioactive material remaining.3. Half-life of a sample that decays from 200 grams to 50 grams in 60 minutesIt is given that the sample of radioactive isotopes takes 60 minutes to decay from 200 grams to 50 grams. To find the half-life, we need to determine how many times the sample has lost half of its mass, which tells you how many half-life cycles have occurred.At 30 minutes, the sample reduces to half its original quantity, which is 100 grams. At 45 minutes, it reduces to 50 grams, which is half of 100 grams. Therefore, it takes two half-life cycles to reduce from 200 grams to 50 grams in 60 minutes. Hence, the half-life of the isotope is 15 minutes.4. Half-life of technetium-99 that decays from 500.0 g to 62.5 g in 639,000 yearsIt is given that a 500.0 g sample of technetium-99 decays to 62.5 g of technetium-99 remaining in 639,000 years. We can use the half-life formula to find the half-life of technetium-99.t1/2 = (t × log2) / log(N0 / Nt) Where,t1/2 = half-life of the substanceN0 = initial quantity of the substance Nt = quantity of the substance left after time t (in years)t = time (in years)From the given data,t1/2 = (639000 × log2) / log(500.0 / 62.5)t1/2 = 210,936 years.

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Answer:

Because the out in a video

Answer: it is gradual, fairly intense

Explanation:

Answer:

Mechanical waves are waves that require a medium. This means that they have to have some sort of matter to travel through. These waves travel when molecules in the medium collide with each other passing on energy. One example of a mechanical wave is sound.

Answer:

\(T=326.928K\)

Explanation:

From the question we are told that:

Emissivity \(e=0.44\)

Absorptivity \(\alpha =0.3\)

Rate of solar Radiation \(R=0.3\)

Generally the equation for Surface absorbed energy is mathematically given by

 \(E=\alpha R\)

 \(E=0.3*950\)

 \(E=285W/m^2\)

Generally the equation for Emitted Radiation is mathematically given by

 \(\mu=e(\sigmaT^4)\)

Where

T=Temperature

 \(\sigma=5.67*10^8Wm^{-2}K_{-4}\)

Therefore

 \(\alpha*E=e \sigma T^4\)

 \(0.3*(950)=0.44(5.67*10^-8)T^4\)

 \(T=326.928K\)

The original two light bulbs will appear brighter when the third resistor is added in parallel.

When a third resistor is added in parallel to the other two resistors in a circuit, it will have an impact on the overall brightness of the original two light bulbs.

In a parallel circuit, each resistor has its own branch connected to the power source. The current flowing through each branch is inversely proportional to the resistance of that branch. Adding a third resistor in parallel means an additional path for current to flow.

The introduction of the third resistor reduces the total resistance of the circuit. As a result, the total current drawn from the power source increases, as per Ohm's Law (I = V/R). The increased current is distributed among the parallel branches, including the original two light bulbs.

Since the current through the bulbs is now greater, their brightness will also increase. This is because the brightness of an incandescent light bulb is directly proportional to the current passing through it.

It's worth noting that the specific effect on brightness depends on the resistance values of the resistors and the characteristics of the light bulbs. However, in general, adding a resistor in parallel reduces the overall resistance, increases the current, and subsequently enhances the brightness of the light bulbs in the circuit.

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