The surface temperature of the asteroid, assuming it is a blackbody, is approximately 72.45 K, based on the peak wavelength of 40 μm.
To find the surface temperature of the asteroid, we can use Wien's displacement law, which states that the peak wavelength of radiation emitted by a blackbody is inversely proportional to its temperature. Given that the power per unit wavelength peaks at 40 μm, we can calculate the surface temperature of the asteroid.
1. According to Wien's displacement law, the peak wavelength (λ) is related to the temperature (T) by the equation: λ_max = (b / T), where b is Wien's displacement constant equal to 2898 μm·K.
2. We are given that the peak wavelength is 40 μm. Substituting this value into the equation, we have: 40 μm = (2898 μm·K / T).
3. Rearranging the equation, we find: T = (2898 μm·K) / (40 μm).
4. Calculating the values, we get: T = 72.45 K.
Therefore, the surface temperature of the asteroid, assuming it is a blackbody, is approximately 72.45 K.
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If in the figure below, the friction between the block and the incline is negligible, (a) how much must the object on the right weigh if the 200-N block is to remain at rest? Ans: 115 N (b) if the system remains at rest when F= 220 N. What are the magnitude and direction of the friction force on the 200-N block? Ans: 105 N down the incline 200 N Fw 35.0⁰
The magnitude of the acceleration and its direction however depends on the resultant force.
What is the resultant force?
In a system of forces, the resultant force is the force that has the same effect in magnitude and direction as all the forces acting together.
In an inclined plane, the friction, weight and applied force all act together on the object. The magnitude of the acceleration and its direction however depends on the resultant force.
This question is incomplete as the diagrams are missing hence the numerical values can not be computed.
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How do I find the mass in kg
To find the mass in kilograms, you need to know the object's weight in newtons and the acceleration due to gravity. The formula for finding mass is mass = weight / acceleration due to gravity. So if you have an object with a weight of 100 N and the acceleration due to gravity is 9.8 m/s^2, the mass would be 10.204 kg.
The mass of the block is 0.025 kg or 25 g, when the spring has k = 28 N/m, and compresses 0.11 m before bringing the block to rest.
When a block is dropped onto a spring with k=28 N/m, the block has a speed of 3.2 m/s just before it strikes the spring. If the spring compresses an amount of 0.11 m before bringing the block to rest, what is the mass of the block?The formula for the spring potential energy is given as follows; PE = (1/2) kx² where k is the spring constant and x is the amount of deformation of the spring. Substituting the values given;PE = (1/2) 28 (0.11)²PE = 0.16972 J. According to the law of conservation of energy, the potential energy stored in the spring at maximum compression is equal to the kinetic energy the block had before it struck the spring;KE = (1/2) mv²where m is the mass of the block and v is its velocity.Substituting the values;0.16972 = (1/2) m (3.2)²m = 0.025 kg or 25 gTherefore, the mass of the block is 0.025 kg or 25 g.For more questions on mass
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what is the formula of magnetic force
Answer:
F = qvB sinθ
(Hope this helps! Btw, I am the first to answer. Brainliest pls! :D)
Why do charged particles interact with each other?(1 point)
because they are small
because they are small
because they are in the same molecule
because they are in the same molecule
because of their electric and magnetic fields
because of their electric and magnetic fields
because they have opposite charges
Answer:
because they have opposite charges
Explanation:
If you're talking about magnetism and electricity, the laws are that like charges attact and and unlike charges repel.
Charged particles interact with each other because they have opposite charges.
How charged particles interact with each other?When charged particles are close to each other, their electric fields interact. So particles with opposite charges attract each other whereas particles with similar charges repel each other.
So we can conclude that Charged particles interact with each other because they have opposite charges.
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1.What is the mass of an object that weighs 98 N?
Answer:
10 kg
Explanation:
Why do fingerprints grow back in the same
pattern if they are destroyed?
Answer:You can scar your fingerprints with a cut, or temporarily lose them through abrasion, acid or certain skin conditions, but fingerprints lost in this way will grow back within a month. As you age, skin on your fingertips becomes less elastic and the ridges get thicker.
Explanation:
explain the Kepler s law of planetary motion
How long would it take a machine to do 5.000
joules of work if the power rating of the machine
is 100 watts?
A. 5,000 sec
B.
50 sec
C.
10 sec
D. 0.2 sec
Answer : B
Answer:
a
Explanation:
How long would it take a machine to do 5.000
joules of work if the power rating of the machine
is 100 watts?
The given machine will take 50 s to complete the work. the power is the rate of performing work.
What is power?It can be defined as the rate of performing work. It can also be written as the amount of work divided by the time it takes to complete the work.
\(p = \dfrac wt\)
So
\(t = \dfrac w p\)
Where,
\(p\) - power = 100 watt = 100 J/s
\(t\) - time = ?
\(w\)- work = 5000 J
Put the values in the formula,
\(t = \dfrac{ 5000 \rm \ J} {100 \rm \ J/s}\\\\t = 50 \rm \ s\)
Therefore, the given machine will take 50 s to complete the work.
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Use the vocabulary words from
“Read It” to complete the
following sentences.
Light from the Sun reaches Earth very
quickly. The (4)_____ is 186,000 miles per
second! We capture sunlight using
(5)_____, which are devices that use the
(6)_____ to convert light to electricity. As
atoms absorb energy, the electrons get
“excited” and release energy as (7)_____.
Whatever light that is not absorbed will
(8)_____ off the surface of the object and
bounce back toward the source.
Answer:
Light from the Sun reaches Earth very quickly. The (4) speed of light is 186,000 miles per second! We capture sunlight using (5) solar panels, which are devices that use the (6) photovoltaic effect to convert light to electricity. As atoms absorb energy, the electrons get “excited” and release energy as (7) photons. Whatever light that is not absorbed will (8) reflect off the surface of the object and bounce back toward the source.
Archaeological samples are often dated by radiocarbon dating. The half-life of carbon-14 is 5,700 years.
After how many half-lives will the sample have only 1/64 as much carbon-14 as it originally contained?
How much time will have passed?
If the daughter product of carbon-14 is present in the sample when it forms (even before any radioactive decay happens), you cannot assume that every daughter you see is the result of carbon-14 decay. If you did make this assumption, would you overestimate or underestimate the age of the sample?
There are six half lives that have passed within 34,200 years. When we assume that we have some of the products present initially, then we overestimate the age of the sample.
What is the half life?The half life is the time taken to obtain only half of the number of atoms that were originally present in the radioactive material. We know that living things do contain the carbon- 14 isotope together with the carbon - 12 isotope in the substance. When the organism dies, the carbon - 14 which is radioactive begins to decay and its half life could be used to estimate the age of the sample as we know.
Given that after each half life, we have only half of the original amount that remains. We would have 1/64 of the original amount left after six half lives and this means that 34,200 years have passed.
If we the daughter product of carbon-14 is present in the sample when it forms (even before any radioactive decay happens), then we would over estimate the age of the sample.
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A 2.0 g metal cube and a 4.0 g metal cube are 6.0 cm apart, measured between their centers, on a horizontal surface. For both, the coefficient of static friction is 0.65. Both cubes, initially neutral, are charged at a rate of 7.0 nC/s .
(a) Which cube moves first?
(b) How long after charging begins does one cube begin to slide away?
Draw a Sketch of the Problem and Create a "Parameter Panel" for the Problem.
Cube moves first, that the cube which is neutral in nature. Hence, the cube which is neutral will move.
To solve this problem, we need to calculate the electrostatic force between the two charged cubes and compare it with the force of static friction between the cubes and the surface. The cube with the smaller force of friction will begin to move first. The parameter panel and sketch of the problem are shown below:
Parameter Panel:
Mass of cube 1 (m1) = 2.0 g = 0.002 kg
Mass of cube 2 (m2) = 4.0 g = 0.004 kg
Distance between the centers of the cubes (d) = 6.0 cm = 0.06 m
Charge rate of each cube (q) = 7.0 nC/s
Coefficient of static friction (μ) = 0.65
Sketch:
|-----------| |-----------|
| 2 | | 1 |
|-----------| |-----------|
| |
d=6.0 cm d=6.0 cm
| |
|-----------------|
(a) To determine which cube moves first, we need to calculate the electrostatic force between the charged cubes and compare it with the force of static friction between the cubes and the surface. The electrostatic force between two charged objects is given by Coulomb's law:
F = (k * q1 * q2) / d^2
where k is the Coulomb constant (9.0 x 10^9 N m^2/C^2), q1 and q2 are the charges on the cubes, and d is the distance between them. For each cube, the charge is increasing at a rate of 7.0 nC/s, so the charge at any time t is given by:
q = 7.0 x 10^-9 C/s * t
At t = 0, the cubes are neutral and have no charge. At some later time t, the charges on the cubes are:
q1 = 7.0 x 10^-9 C/s * t
q2 = 7.0 x 10^-9 C/s * t
The electrostatic force between the cubes is then:
F = (9.0 x 10^9 N m^2/C^2) * (q1 * q2) / d^2
= (9.0 x 10^9 N m^2/C^2) * [(7.0 x 10^-9 C/s * t)^2 / (0.06 m)^2]
The force of static friction between each cube and the surface is:
Ff = μ * N
= μ * m * g
where N is the normal force, m is the mass of the cube, μ is the coefficient of static friction, and g is the acceleration due to gravity (9.81 m/s^2).
The normal force N is the force exerted by the surface on the cube, and is equal in magnitude to the weight of the cube:
N = m * g
Plugging in the values for each cube, we get:
Ff1 = μ * m1 * g
= 0.65 * 0.002 kg * 9.81 m/s^2
= 0.0127 N
Ff2 = μ * m2 * g
= 0.65 * 0.004 kg * 9.81 m/s^2
= 0.0254 N
Comparing the electrostatic force between the cubes and the force of static friction, we find:
F - Ff1 = (9.0 x 10^9 N)
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Hint: sin2θ + cos2θ = 1 .
Consider the 692 N weight held by two
cables shown below. The left-hand cable had
tension 570 N and makes an angle of θ2 with
the ceiling. The right-hand cable had tension
530 N and makes an angle of θ1 with the
ceiling. a) What is the angle θ1 which the righthand cable makes with respect to the ceiling?
Answer in units of ◦.
b) What is the angle θ2 which the left-hand
cable makes with respect to the ceiling?
Answer in units of ◦.
a) The angle θ1 which the righthand cable makes with respect to the ceiling is sin^(-1)(692 N / 530 N).
b) The angle θ2 which the left-hand cable makes with respect to the ceiling is sin^(-1)(692 N / 570 N).
We may utilise the tension of the right-hand cable as well as its vertical and horizontal components to determine the angle 1. θ2 = sin^(-1)(692 N / 570 N).
We may apply the ideas of trigonometry and vector addition to address this issue.
a) The tension of the right-hand wire as well as its vertical and horizontal components can be used to determine the angle 1.
T1sin(1) calculates the vertical component of the right-hand cable's tension, which is equal to the object's weight (692 N).
T1sin(θ1) = 692 N
We may rearrange the equation to find 1:
θ1 = sin^(-1)(692 N / T1)
We can find 1 by substituting the given tension value, T1 = 530 N:
θ1 = sin^(-1)(692 N / 530 N)
b) Similarly, we can use the formula to determine the angle 2 the left-hand cable's tension and its vertical and horizontal components.
The vertical component of the left-hand cable's tension is given by T2sin(θ2), and it should also be equal to the weight of the object (692 N).
T2sin(θ2) = 692 N
To find θ2, we can rearrange the equation:
θ2 = sin^(-1)(692 N / T2)
Substituting the given tension value T2 = 570 N, we can solve for θ2:
θ2 = sin^(-1)(692 N / 570 N)
Calculating these angles using the given tension values will provide the answers in degrees.
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A 39.4 kg beam is attached to a wall with a link and its far end is supported by a cable such that the angle between the beam and the cable is 90 degrees. If the beam is inclined at an angle of theta = 33.1 degrees with respect to horizontal, what is the magnitude of the horizontal component of the force exerted by the link on the beam?
Answer:
192.6N
Explanation:
Let's consider the forces acting on the beam:
Weight of the beam (W): It acts vertically downward and has a magnitude of W = mass * gravitational acceleration = 39.4 kg * 9.8 m/s^2.
Force exerted by the link on the beam (F_link): It acts at an angle of 90 degrees with respect to the beam and has two components: the vertical component and the horizontal component.
Tension in the cable (T): It supports the far end of the beam and acts at an angle of 90 degrees with respect to the beam. Since the angle between the beam and the cable is 90 degrees, the tension in the cable only has a vertical component.
Let's break down the forces acting on the beam:
Vertical forces:
W (weight of the beam) - T (vertical component of tension) = 0
T = W
Horizontal forces:
F_link (horizontal component of the force exerted by the link) = ?
To find the magnitude of the horizontal component of the force exerted by the link on the beam (F_link), we need to consider the equilibrium of forces in the horizontal direction.
Since the beam is inclined at an angle of θ = 33.1 degrees with respect to the horizontal, the horizontal equilibrium equation can be written as:
F_link = W * sin(θ)
Let's substitute the given values:
W = 39.4 kg * 9.8 m/s^2
θ = 33.1 degrees
F_link ≈ (39.4 kg * 9.8 m/s^2) * sin(33.1 degrees)
Using a calculator, we find that the magnitude of the horizontal component of the force exerted by the link on the beam (F_link) is approximately 192.6 N.
If you mix 2 grams of any solid and 6 grams of any liquid, how many grams
should there be when they were combined and did NOT react?
no mass because there was no reaction
8.
12
3
Answer:
8
Explanation:
The mass is always equal to the amount of reactants, 6+2=8
In a DC generator, the generated emf is directly proportional to the
In a DC generator, the generated electromotive force (emf) is directly proportional to the rotational speed of the generator's armature and the strength of the magnetic field within the generator.
This relationship is described by the equation for the generated emf in a DC generator:
Emf = Φ * N * A * Z / 60
Where:
Emf is the generated electromotive force (in volts),
Φ is the magnetic flux density (in Weber/meter^2\(meter^2\) or Tesla),
N is the number of turns in the armature winding,
A is the effective area of the armature coil (in square meters),
Z is the total number of armature conductors, and
60 is a constant representing the conversion from seconds to minutes.
From this equation, we can see that the generated emf is directly proportional to the magnetic flux density (Φ) and the product of the number of turns (N), effective area (A), and the total number of armature conductors (Z). This means that increasing any of these factors will result in a higher generated emf.
The magnetic flux density (Φ) can be increased by using stronger permanent magnets or increasing the strength of the field windings in the generator.
The number of turns (N) and the effective area (A) are design parameters and can be optimized for a specific generator. Increasing the number of turns or the effective area will result in a higher generated emf.
Similarly, the total number of armature conductors (Z) can be increased to enhance the generated emf.
By controlling and optimizing these factors, the generated emf in a DC generator can be increased, resulting in higher electrical output. However, it is important to note that there are practical limits to these factors based on the design and construction of the generator.
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Read the text below. Each sentence is about one, two or no energy at all. (5 points) Name the type (s) of energy for each sentence, or leave the space blank (if in the sentence no energy is mentioned). Artan decided to paint the house. He moved the furniture, climbed the stairs, and began work. After two hours he took a break, ate lunch and turned on the radio to listen to some music. When done, turn on a heater to allow the paint to dry as quickly as possible. At dinner everything had ended. a) ............................................................................................................................................ b) ............................................................................................................................................ c) ............................................................................................................................................ d) ............................................................................................................................................ e) ............................................................................................................................................
The moon has a radius of 1,738,000 m and a mass of 7.35 x 1022 kg. It orbits the
earth at a radius of 3.84 x 10¹¹ m. The earth's mass is 6 x 1024 kg. What is the
force gravity between the earth and the moon?
Does the weight of the projectile affect the horizontal range?
Answer:
no
Explanation:
This downward force and acceleration results in a downward displacement from the position that the object would be if there were no gravity. The force of gravity does not affect the horizontal component of motion; a projectile maintains a constant horizontal velocity since there are no horizontal forces acting upon it.
A vertical, 1.10 m length of 18 gauge (diameter of 1.024 mm) copper wire has a 110.0 N
ball hanging from it.
A 550.0 N ball now replaces the original ball. What is the change in the wavelength of the third harmonic caused by replacing the light ball with the heavy one? Hint: Young's Modulus for copper is 11×1010Pa
.
The wavelength has not changed because the tension in the wire is proportional to the weight of the hanging object, and the wave speed depends only on the tension and the linear mass density of the string.
To calculate the change in wavelength of the third harmonic caused by replacing the light ball with the heavy one, we can use the equation for the wavelength of a standing wave on a string:
λ = 2L/n
where λ is the wavelength, L is the length of the string, and n is the harmonic number.
For the third harmonic, n = 3, so the original wavelength is:
λ₁ = 2(1.10 m)/3
λ₁ = 0.733 m
To find the tension in the wire with the original ball, we can use the formula:
F = mg + T
where F is the tension in the wire, m is the mass of the ball, g is the acceleration due to gravity, and T is the tension due to the wire itself.
Solving for T, we get:
T = F - mg
T = 110.0 N - (0.110 kg)(9.81 m/s²)
T = 108.82 N
Now that we have the tension, we can use the formula for the wave speed on a string:
v = √(F/μ)
where v is the wave speed, F is the tension, and μ is the linear mass density of the string.
The linear mass density can be found using the formula:
μ = m/LA
where m is the mass of the wire, L is the length of the wire, and A is the cross-sectional area of the wire.
μ = (π/4)(0.001024 m)²(1.10 m)/(0.018 kg/m³)
μ = 1.41×10⁻⁶ kg/m
Now we can find the wave speed:
v₁ = √(108.82 N/1.41×10⁻⁶ kg/m)
v₁ = 296.48 m/s
Using the equation for the wavelength of a standing wave on a string, we can find the new wavelength with the heavier ball:
λ₂ = 2L/n = 2(1.10 m)/3 = 0.733 m
The wavelength has not changed because the tension in the wire is proportional to the weight of the hanging object, and the wave speed depends only on the tension and the linear mass density of the string. Therefore, the change in the weight of the ball does not affect the wave speed or the wavelength.
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How does the decrease in gravitational potential energy of a falling ball compare to its increase in kinetic energy? (Ignore air friction.)
Answer:
for every decrease in potential energy, a kinetic energy proportional to 2gΔh is gained.
Explanation:
Let us consider a ball falling from its maximum height
For a body falling from its maximum height to a point p
change in height = Δh
The potential energy decrease is then proportional to
ΔPE = mgΔh
where
ΔPE is the decrease in kinetic energy
m is the mass of the ball
g is acceleration due to gravity
Δh is the change in height
For a body falling from its maximum height, the increase change in velocity
Δv = u + 2gΔh (at maximum height u = 0)
where
u is the initial kinetic energy of the ball
Δv = 0 + 2gΔh
Δv = 2gΔh
The kinetic energy increases by
ΔKE = \(\frac{1}{2}\)m(Δv)^2
but Δv = 2gΔh
therefore
ΔKE = \(\frac{1}{2}\)m(2gΔh)^2 = 2m(gΔh)^2
comparing the increase in kinetic energy to the decrease in potential energy, we have
(2m(gΔh)^2)/(mgΔh) = 2gΔh
This means that for every decrease in potential energy, a kinetic energy proportional to 2gΔh is gained.
find the rms speed of a sample of oxygen at 30° C and having a molar mass of 16 g/mol.
At 30°C, the rms speed of a sample of oxygen with a molar mass of 16 g/mol is approximately 482.34 m/s.
The root mean square (rms) speed of a gas molecule is a measure of the average speed of the gas particles in a sample. It can be calculated using the formula:
vrms = √(3kT/m)
Where:
vrms is the rms speed
k is the Boltzmann constant (1.38 x 10^-23 J/K)
T is the temperature in Kelvin
m is the molar mass of the gas in kilograms
To calculate the rms speed of oxygen at 30°C (303 Kelvin) with a molar mass of 16 g/mol, we need to convert the molar mass to kilograms by dividing it by 1000:
m = 16 g/mol = 0.016 kg/mol
Substituting the values into the formula, we have:
vrms = √((3 * 1.38 x 10^-23 J/K * 303 K) / (0.016 kg/mol))
Calculating this expression yields the rms speed of the oxygen sample:
vrms ≈ 482.34 m/s
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Describe 2 ways in which a giant boulder by the ocean may change over time.
Answer:
I'm not sure if they're right but...
1. It would erode because of the water
2. It would probably become a home for the ocean creatures
The two (2) ways in which a giant boulder by the ocean may change over time are:
1. The ocean water would change the boulder's appearance and texture.
2. The giant boulder would be transformed into sediments due to erosion and weathering through dissolution.
A boulder can be defined as a large (giant) rounded mass of rock fragment that is formed through its detachment from a parent consolidated rock, especially due to erosion and weathering.
Basically, the size of a boulder is greater than 256 millimeters (25.6 centimeters or 10.1 inches) in diameter.
The reason why giant (large) boulders are present in steep mountain streams or oceans is mainly because they are usually too heavy for them to be moved by the body of water.
This ultimately implies that, water cannot move a giant (large) boulder that is present in an ocean because of its size and weight.
However, a giant (large) boulder that is present in an ocean would be affected in these two (2) ways:
Ocean water would change the boulder's appearance and texture. The giant boulder would be transformed into sediments due to the actions of erosion and weathering through dissolution.
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Students are studying the two-dimensional motion of objects as they move through the air. Specifically, they are examining the behavior of a sphere that is launched horizontally from a location above the floor with an initial velocity vo in the +3 direction, as shown in the figure. The students assume that the positive directions are along the sphere's initial velocity for horizontal motion and downward for vertical motion.
The horizontal displacement of the object from its starting point is x, and the vertical displacement of the object from its starting point is y. One of the students derives an equation for y in terms of xx and other quantities. After examining the equation, the student claims that y is proportional to x^2.
Required:
Derive an equation for the vertical coordinate y of the sphere as a function of x, v0, and physical constants, as appropriate.
Answer:
y = - (½ g / v₀²) x²
Explanation:
This is a projectile launch exercise where there is no acceleration on the x-axis so
x = v₀ₓ t
v₀ₓ = v₀ cos tea
y = \(v_{oy}\) t - ½ g t2
v_{oy} = v₀ sin θ
as the sphere is thrown horizontally, the angle is tea = 0º, so the initial velocity remains
v₀ₓ = v₀
v_{oy} = 0
we substitute in our equations
x = v₀ t
y = - ½ g t²
we eliminate the time from these equations, we substitute the first in the second
y = - ½ g (x / v₀)²
y = - (½ g / v₀²) x²
this is the equation of a parabola
These waves are traveling at the same speed. Which wave has the highest frequency? A. Wave frequency With line crossing in the middle B. A wave frequency with line crossing in the middle C. A wave frequency with line crossing in the middle D. A wave frequency with line crossing it Reset Next
These waves are traveling at the same speed. The wave with the highest frequency is option C, "A wave frequency with line crossing in the middle."
Frequency is a measure of the number of complete cycles or oscillations of a wave that occur in one second. It is typically measured in hertz (Hz). The higher the frequency, the more cycles or oscillations occur per unit of time.In the given question, it is stated that all the waves are traveling at the same speed. This means that the speed of propagation is constant for all the waves. However, the frequency of a wave is independent of its speed.By looking at the options, we notice that all the waves have the same wave pattern with a line crossing in the middle. The difference lies in the spacing between the waves, which corresponds to the frequency.The wave with the highest frequency will have the shortest wavelength and the most closely spaced wave crests. Since option C has the shortest spacing between the wave crests, it indicates a higher frequency compared to the other options.Therefore, based on the given information, option C, "A wave frequency with line crossing in the middle," has the highest frequency among the given choices.Please note that the question does not provide specific frequency values or any other information to determine the exact frequencies of the waves. We can only compare the relative frequencies based on the given visual representation.For more such questions on waves, click on:
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When using Fleming's Left Hand Rule to determine the direction of the force on an electron moving in a magnetic field, the velocity vector (V) is represented by the direction of your ___________.
thumb
index finger
middle finger
None of the above
Which of the following is a type of physical change?
You throw a baseball directly upward at time =0 at an initial speed of 12.5 m/s. Ignore air resistance and take =9.80 m/s^2.
Relative to the point where it leaves your hand, what is the maximum height ℎmax
reached by the ball?
At what times t 1/2, up and 1/2, down does the ball pass through half the maximum height on the way up and the way down, respectively?
The ball passes through half the maximum height on the way up and down at approximately 1.28 seconds.
To determine the maximum height reached by the baseball and the times at which it passes through half the maximum height on the way up and down, we can use the equations of motion for vertical motion.
Maximum height (hmax):
The initial velocity (u) is 12.5 m/s and the acceleration due to gravity (g) is -9.8 m/s^2 (negative because it acts downward). The maximum height reached by the ball can be calculated using the equation:
hmax = (u^2) / (2g)
Substituting the given values:
hmax = (12.5^2) / (2 * 9.8) ≈ 8.04 meters
Therefore, the maximum height reached by the ball is approximately 8.04 meters.
Time at half maximum height (t1/2, up and t1/2, down):
The time taken for the ball to reach half the maximum height on the way up and on the way down will be the same. We can calculate this time using the equation:
t1/2 = (u - v) / g
Where v is the final velocity, which is 0 m/s at the highest point of the trajectory.
t1/2 = (12.5 - 0) / 9.8 ≈ 1.28 seconds
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A 1.50x103-kilogram car is traveling east at 30 meters per second.
The brakes are applied and the car is brought to rest in 9.00 seconds.
A. Calculate the magnitude of the total impulse applied to the car to
bring it to rest. [Show all work, including the equation and
substitution with units.]
B. State the direction of the impulse applied to the car. [East or
West?]
PLEASE HELP!!!!
Answer:
\(39000\ \text{kg m/s}\)
West
Explanation:
m = Mass of car = \(1.3\times 10^{3}\ \text{kg}\)
t = Time = 9 seconds
u = Initial velocity = 30 m/s
v = Final velocity = 0
Impulse is given by
\(J=m(v-u)\\\Rightarrow J=1.3\times 10^3(0-30)\\\Rightarrow J=-39000\ \text{kg m/s}\)
The magnitude of the total impulse applied to the car to bring it to rest is \(39000\ \text{kg m/s}\).
The direction is towards west as the sign is negative.
Describe the change to the graph of Y= X +3 when Y=2X -3 is graphed 
Answer: a stretch of 2
Explanation: because it 2 (x) - 3
The graph below shows the motion of a person leaving a theater. Three segments of their journey have been identified as A, B, and C.
What does line segment C represent?
The person is moving away from the theater.
The person is standing still.
The person is moving closer to the theater.
The person is slowing down.
The graph below shows the motion of a person leaving theater, line segment C represent : The person is moving away from the theater.
What is meant by motion?In physics, motion is a change with time of the position or orientation of a body. Motion along a line or a curve is called as translation whereas motion that changes orientation of a body is called rotation.
Motion is a change in position of an object over the time and is described in terms of displacement, distance, velocity, acceleration, time and speed.
Change in position of a body with time when compared with another body is known as motion.
To know more about motion, refer
https://brainly.com/question/26083484
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