Sophia pushes with a 40-N horizontal force on a 4.0-kg box resting on a lab bench. The box slides against a horizontal friction force of 24 N. show that the box acceleration at 4.0 m/s2

Answer:

Work Function = 3.53 x 10⁻¹⁹ J = 2.2 eV

Explanation:

The work function of the metal metal can be found as follows:

Energy of Photon = Work Function + K.E

hc/λ = Work Function + K.E

Work Function = hc/λ - K.E

where,

h = Plank's Constant = 6.625 x 10⁻³⁴ J.s

c = speed of light  = 3 x 10⁸ m/s

λ = wavelength of photons = 240 nm = 2.4 x 10⁻⁷ m

K.E = Maximum Kinetic Energy = (2.97 eV)(1.6 x 10⁻¹⁹ J/1 eV) =  4.752 x 10⁻¹⁹ J

Therefore,

Work Function = (6.625 x 10⁻³⁴ J.s)(3 x 10⁸ m/s)/(2.4 x 10⁻⁷ m) - 4.752 x 10⁻¹⁹ J

Work Function = 8.281 x 10⁻¹⁹ J - 4.752 x 10⁻¹⁹ J

Work Function = 3.53 x 10⁻¹⁹ J = 2.2 eV

A 66.1-kg boy is surfing and catches a wave which gives him an initial speed of 1.60 m/s. He then drops through a height of 1.59 m, and ends with a speed of 8.51 m/s. The nonconservative work done on the boy is approximately -42.7 kilojoules.

To find the nonconservative work done on the boy, we need to consider the change in the boy's mechanical energy during the process. Mechanical energy is the sum of the boy's kinetic energy (KE) and gravitational potential energy (PE).

The initial mechanical energy of the boy is given by the sum of his kinetic energy and potential energy when he catches the wave:

E_initial = KE_initial + PE_initial

The final mechanical energy of the boy is given by the sum of his kinetic energy and potential energy after he drops through the height:

E_final = KE_final + PE_final

The nonconservative work done on the boy is equal to the change in mechanical energy:

Work_nonconservative = E_final - E_initial

Let's calculate each term:

KE_initial = (1/2) * m * v_initial^2

= (1/2) * 66.1 kg * (1.60 m/s)^2

PE_initial = m * g * h_initial

= 66.1 kg * 9.8 m/s^2 * 1.59 m

KE_final = (1/2) * m * v_final^2

= (1/2) * 66.1 kg * (8.51 m/s)^2

PE_final = m * g * h_final

= 66.1 kg * 9.8 m/s^2 * 0

Since the boy ends at ground level, the final potential energy is zero.

Substituting the values into the equation for nonconservative work:

Work_nonconservative = (KE_final + PE_final) - (KE_initial + PE_initial)

Simplifying:

Work_nonconservative = KE_final - KE_initial - PE_initial

Calculating the values:

KE_initial = (1/2) * 66.1 kg * (1.60 m/s)^2

PE_initial = 66.1 kg * 9.8 m/s^2 * 1.59 m

KE_final = (1/2) * 66.1 kg * (8.51 m/s)^2

Substituting the values:

Work_nonconservative = [(1/2) * 66.1 kg * (8.51 m/s)^2] - [(1/2) * 66.1 kg * (1.60 m/s)^2 - 66.1 kg * 9.8 m/s^2 * 1.59 m]

Calculating the result:

Work_nonconservative ≈ -42.7 kJ

Therefore, the nonconservative work done on the boy is approximately -42.7 kilojoules. The negative sign indicates that work is done on the boy, meaning that energy is transferred away from the boy during the process.

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Answer:

I'm pretty sure that the answer is C. Hope this helps.

Explanation:

Answer:

Answer is A. Under any conditions

Explanation:

Just got it correct on A p e x

Answer:

The height from which the diver jumped can be calculated using the laws of motion and the principle of conservation of energy.

Let's assume that the diver jumped from a platform with an initial velocity of zero. The potential energy (PE) of the diver at the top of the platform is given by:

PE = mgh

Where m is the mass of the diver, g is the acceleration due to gravity (9.8 m/s^2), and h is the height from which the diver jumped.

When the diver jumps, the potential energy is converted into kinetic energy (KE) as the diver moves downwards. The kinetic energy of the diver just before hitting the water is given by:

KE = (1/2)mv^2

Where v is the velocity of the diver just before hitting the water.

According to the principle of conservation of energy, the potential energy at the top of the platform is equal to the kinetic energy just before hitting the water. Therefore, we can equate the two equations above and solve for h:

mgh = (1/2)mv^2

h = (1/2)v^2/g

We need to find the value of v to calculate h. We can use the kinematic equation:

v^2 = u^2 + 2as

Where u is the initial velocity (which is zero in this case), a is the acceleration due to gravity (9.8 m/s^2), and s is the distance travelled by the diver (which is equal to h).

Substituting the values, we get:

v^2 = 2gh

v^2 = 2 * 9.8 * h

v^2 = 19.6h

Therefore:

h = v^2/(19.6)

Now, let's assume that the velocity of the diver just before hitting the water was 10 m/s (a reasonable value for a diving competition). Then:

h = (10^2)/(2*9.8) = 51 meters

Therefore, the height from which the diver jumped is approximately 51 meters.

Answer:

Amplitud (dinámica)

Explanation:

La amplitud de una onda de sonido determina su volumen relativo. En música, el volumen de una nota se denomina nivel dinámico.

Answer:

Yes. Something similar occurs here on Earth.

Explanation:

Gravity tends to pull objects perpendicularly to the ground. In space, the absence of this force means there is no compression on the spine due to gravity trying to pull it down. This means that astronauts undergo an increase in height in space.

Here on Earth, we experience gravity pull on our spine during the day. At night when we sleep, we lie down with our spine parallel to the ground, which means that our spine is no longer under compression from gravity force. The result is that we are a few centimetres taller in the morning when we wake up, than we are before going to bed at night. The increase is not much pronounced here on Earth because there is a repeated cycle of compression and decompression of our spine due to gravity, unlike when compared to that of astronauts that spend long duration in space, all the while without gravity forces on their spine

Answer:

600 J

Explanation:

900 j = 300j = 600 j lost due to friction

Energy lost due to friction is 600 J.

The kinetic energy before and after friction is given as 900J and 300J.

   The force that resists the sliding or rolling over one object with another is called friction. The energy which possess in virtue of being in motion is said to be Kinetic Energy.

                                   f = μN

                      Energy lost = 900J - 300J

                                          =  600J

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Answer:

0

Explanation:

0 is the answer

Hello!!

For calculate the work let's applicate the formula:

\(\boxed{W=Fd}\)

\(\textbf{Being:}\)

\(\sqrt{}\) W = Work = ?

\(\sqrt{}\) F = Force = 1525 N

\(\sqrt{}\) d = Distance = 381 m

⇒ \(\text{Then let's \textbf{replace it according} we information:}\)

W = 1525 N * 381 m

⇒ \(\text{Let's resolve it: }\)

W = 581025 J

\(\textbf{Result:}\\\text{The work is \textbf{581025 Joules}}\)

Work done on an object is the product of force and displacement. The work done on the car by the force of 1525 N making a displacement of 381 m is 581 KJ.

When a force applied to an object make a displacement of  the body or stopes its motion, the force is said to be work done on the object. Thus, work done can be taken as the product of force and displacement.

Work done like force is a vector quantity thus characterized with magnitude and direction.  Work done is equivalent to the energy required to make the object displaced.

Given the force = 1525 N

displacement = 381 m

work done  = force × displacement

w = 1525 N × 381 m = 581 KJ.

Therefore, the work done on the car is 581 KJ.

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a. Upthrust on the solid:

\(Upthrust = volume of solid * density of fluid * g = 1000 kg/m^3 * volume of solid * 10 m/s^2\)

b. Volume of the solid:

\(volume = mass/density = 1.3 kg / (1000 kg/m^3) = 1.3 x 10^-3 m^3\)

c. Density of the solid:

So,\(density = mass/volume = 1.3 kg / (1.3 x 10^-3 m^3) = 1000 kg/m^3\)

Upthrust is the upward force exerted on an object immersed in a fluid. It is equal to the weight of the fluid displaced by the object and acts in the opposite direction to gravity. Upthrust helps to counteract the weight of the object and keep it afloat.

a. The upthrust on an object immersed in a fluid is equal to the weight of fluid displaced by the object. The weight of fluid displaced can be calculated using the formula:

Weight of fluid = volume of fluid * density of fluid * g

Since the solid is completely immersed in water, the volume of the fluid displaced is equal to the volume of the solid. The density of water is given as 1000 kg/m^3, and the acceleration due to gravity is given as\(10 m/s^2.\)

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Explanation:

Yes, there are differences in the shapes of position-time graphs for uniform acceleration and uniform deceleration in different directions. Let's consider each case separately:\(\hrulefill\)

(1) - Uniform acceleration towards the positive direction:

In this case, the object is moving in the positive direction with a constant acceleration. The displacement-time graph will typically be a curve that starts from an initial position and shows a steady increase in displacement over time. The shape of the graph will depend on the specific acceleration value.

(2) - Uniform acceleration towards the negative direction:

In this case, the object is moving in the negative direction with a constant acceleration. The displacement-time graph will also be a curve, but it will show a steady decrease in displacement over time.

(3) - Uniform deceleration towards the positive direction:

In this case, the object is initially moving in the positive direction but is slowing down with a constant deceleration. The displacement-time graph will be a curve that starts with a positive slope and gradually levels off.

(4) - Uniform deceleration towards the negative direction:

In this case, the object is initially moving in the negative direction but is slowing down with a constant deceleration. The displacement-time graph will be a curve that starts with a negative slope and gradually levels off.

The statement that describes the transformation of the graph of function f onto the graph of function g is: The graph shifts 2 units right and 7 units down.

To determine the transformation of the graph of function f onto the graph of function g, we compare the two functions f(x) and g(x) and observe the changes in the equations.

The function f(x) = (1/x - 3) + 1 represents a reciprocal function that is shifted vertically 1 unit up and horizontally 3 units to the right. The reciprocal function is reflected about the line y = x.

The function g(x) = (1/(1 + 4)) + 3 simplifies to g(x) = 4 + 3 = 7, which is a constant function representing a horizontal line at y = 7.

By comparing the equations, we can see that the transformation from f(x) to g(x) involves the following changes:

The term 1/x in f(x) is replaced by the constant 1/(1 + 4) in g(x), resulting in a vertical shift of 7 units up.

The term -3 in f(x) is replaced by 3 in g(x), resulting in a vertical shift of 3 units up.

The +1 in f(x) is replaced by +3 in g(x), resulting in an additional vertical shift of 2 units up.

Therefore, the overall transformation is a shift of 2 units to the right and 7 units down.

Hence, the correct statement is: The graph shifts 2 units right and 7 units down.

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a. The results should be repeated is 40.

b. because because it's not accurate.

c. Jamaal draw a line of best fit at the middle of the reflection angel and incidence angle.

The angle created when a sunlight ray strikes a line that is perpendicular to a surface; for instance, a surface facing the sun directly has an angle of incidence of 0, while a surface parallel to the sun (such as sunlight striking a horizontal rooftop) has an angle of incidence of 90°.

The light ray that reflects off the surface is referred to as the reflected ray, and the angle at which the reflected ray reflects off the surface is referred to as the reflection angle. The law of reflection states that the angle of incidence and angle of reflection are equal.

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Answer:

Explanation:

We can use the work-energy principle to solve this problem. The work-energy principle states that the work done on an object is equal to the change in kinetic energy of the object.

We can begin by finding the spring constant (k) of the spring. The spring constant is the force required to compress a spring by a certain distance. We can use the information given to us in the problem to find the spring constant:

k = F / x = 334 N / 0.024 m = 13,916.67 N/m

Now we can use the spring constant, the compression distance (3.5 cm) and the mass of the block (1.15 kg) to find the work done on the block as it compresses the spring:

work = 1/2 * k * x^2 = 1/2 * 13,916.67 N/m * (0.035 m)^2 = 97.4 J

Since the block is released from rest, its initial kinetic energy is zero. So, the work done on the block as it compresses the spring is equal to its final kinetic energy.

We know that the block slides down on a frictionless incline, so we need to consider the work done by gravity on the block during its motion. The work done by gravity is given by the equation:

work = force * distance * cos(theta)

where force is the force of gravity acting on the block, distance is the distance the block slides down the incline and theta is the angle of the incline with the ground.

force = m * g , where m = 1.15 kg and g = 9.8 m/s^2

distance = s

theta = 35°

substituting the values

work = (1.15 kg * 9.8 m/s^2) * s * cos(35°)

Now we can add the work done by gravity to the work done by the spring to find the total work done on the block.

work = 97.4 J + (1.15 kg * 9.8 m/s^2) * s * cos(35°) = 97.4 J + (11.37 N) * s * cos(35°)

Now we can solve for s, the distance the block travelled.

s = (97.4 J) / (11.37 N * cos(35°))

The final answer will be in meters.

Correct statements are

The universe is continuing to expand.

A massive explosion caused matter and energy to expand and form the universe.

Answer:

1.45

Explanation:

Answer:

We're no strangers to love

You know the rules and so do I

A full commitment's what I'm thinking of

You wouldn't get this from any other guy

I just wanna tell you how I'm feeling

Gotta make you understand

Never gonna give you up

Never gonna let you down

Never gonna run around and desert you

Never gonna make you cry

Never gonna say goodbye

Never gonna tell a lie and hurt you

We've known each other for so long

Your heart's been aching but you're too shy to say it

Inside we both know what's been going on

We know the game and we're gonna play it

And if you ask me how I'm feeling

Don't tell me you're too blind to see

Never gonna give you up

Never gonna let you down

Never gonna run around and desert you

Never gonna make you cry

Never gonna say goodbye

Never gonna tell a lie and hurt you

No, I'm never gonna give you up

No, I'm never gonna let you down

No, I'll never run around and hurt you

Never, ever desert you

We've known each other for so long

Your heart's been aching but

Never gonna give you up

Never gonna let you down

Never gonna run around and desert you

Never gonna make you cry

Never gonna say goodbye

Never gonna tell a lie and hurt you

No, I'm never gonna give you up

No, I'm never gonna let you down

No, I'll never run around and hurt you

I'll never, ever desert you

Explanation:

RICK ROLLED

Answer:

B. period of the sound wave

Solution:

1. millimeter, centimeter

 1 centimeter = 10 millimeter

 So, centimeter is the larger unit here.

2. kilogram, megagram

    1 megagram = 1000 kilogram

   So, megagram is the larger unit here.

3. microsecond, millisecond

    1 millisecond = 1000 microsecond

   So, millisecond is the larger unit here.

4.dL, mL

  1 dL = 100 mL

So, dL is the larger unit here.  

5.mg, kg

  1 mg = 0.000001 kg

 So, kg is the larger unit here.

6. Mm,mm

   1 mm = 1 mm

  Both are same

7. S, cs

   1 second = 100 centisecond

So, S is the larger unit.  

8. M, mm

   1 M  = 1000 mm

So, M is the larger unit here.  

9. U s, ks

   Us is larger.

A. Identity vs role confusion: Mo's uncertainty about post-graduation plans.

B. Integrity vs despair: Mo's questioning of life accomplishments as an older adult.

C. Sensorimotor stage: Mo's development of motor skills and object permanence.

D. Intimacy vs isolation: Mo's struggle with forming relationships.

E. Concrete operational stage: Mo's ability to think logically and understand conservation.

A. The example matches with the Erikson stage of "identity vs role confusion." During this stage, individuals go through a period of exploration and self-discovery to establish a sense of identity and determine their roles and goals in life. Mo's uncertainty about what he wants to do after graduation reflects the challenges and decision-making processes associated with identity formation.

B. The example matches with the Erikson stage of "integrity vs despair." This stage occurs in late adulthood, where individuals reflect on their life choices, accomplishments, and experiences. Mo, as an older adult questioning his accomplishments, is facing the task of finding a sense of integrity and satisfaction with the life they have lived or experiencing feelings of despair and regret.

C. The example matches with the Piaget stage of "sensorimotor stage." This stage occurs in infancy, where children develop coordination and motor skills and begin to understand object permanence, which is the understanding that objects continue to exist even when they are out of sight. Mo's acquisition of motor skills and developing object permanence aligns with the characteristics of the sensorimotor stage.

D. The example matches with the Erikson stage of "intimacy vs isolation." This stage occurs during early adulthood, where individuals seek to form deep and meaningful relationships with others. Mo's struggle with forming a relationship with a significant other reflects the challenges and conflicts associated with the intimacy vs isolation stage.

E. The example matches with the Piaget stage of "concrete operational stage." This stage occurs in middle childhood, where children develop logical thinking and can grasp the concept of conservation. Mo's ability to think logically and understand the law of conservation aligns with the characteristics of the concrete operational stage.

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Answer:

Gravitational force is an attraction between masses. The greater the size of the masses, the greater the size of the gravitational force (also called the gravity force). The gravitational force weakens rapidly with increasing distance between masses

Answer:

Tarzan will be moving at 7.4 m/s.

Explanation:

From the question given above, the following data were obtained:

Height (h) of cliff = 2.8 m

Initial velocity (u) = 0 m/s

Final velocity (v) =?

NOTE: Acceleration due to gravity (g) = 9.8 m/s²

Finally, we shall determine how fast (i.e final velocity) Tarzan will be moving at the bottom. This can be obtained as follow:

v² = u² + 2gh

v² = 0² + (2 × 9.8 × 2.8)

v² = 0 + 54.88

v² = 54.88

Take the square root of both side

v = √54.88

v = 7.4 m/s

Therefore, Tarzan will be moving at 7.4 m/s at the bottom.

Answer:

m = \(\frac{k}{g}\) x,

graph of x vs m

Explanation:

For this exercise, the simplest way to determine the mass of the cylinder is to take a spring and hang the mass, measure how much the spring has stretched and calculate the mass, using the translational equilibrium equation

              F_e -W = 0

              k x = m g

              m = \(\frac{k}{g}\) x

We are assuming that you know the constant k of the spring, if it is not known you must carry out a previous step, calibrate the spring, for this a series of known masses are taken and hung by measuring the elongation (x) from the equilibrium position, with these data a graph of x vs m is made to serve as a spring calibration.

  In the latter case, the elongation measured with the cylinder is found on the graph and the corresponding ordinate is the mass

Answer:

Yes

Explanation:

As a personification

Answer: heat,h2o,food

Explanation:

It is all Physical properties

Answer:

v = 172 km/h

Explanation:

For the first 12  hours, it traveled at an average speed of 185 km/h. Let d₁ is distance. So,

\(d_1=v_1\times t_1\\\\d_1=185\ km/h\times 12\ h\\\\d_1=2220\ km\)

For the  next 13 hours, it traveled at an average speed of 160 km/h. Let d₂ is the distance. So,

\(d_2=v_2\times t_2\\\\d_2=160\ km/h\times 13\ h\\\\d_2=2080\ km\)

Average speed = total distance/time taken

So,

\(v=\dfrac{d_1+d_2}{t_1+t_2}\\\\v=\dfrac{2220+2080}{12+13}\\\\v=172\ km/h\)

So, the average speed of the whole journey is 172 km/h.

Answer:

if the distance between the two charges is doubled, the attraction or repulsion becomes weaker, decreasing to one-fourth of the original value. If the charges come 10 times closer, the size of the force increases by a factor of 100. The size of the force is proportional to the value of each charge.

When charges are 3 centimeters apart if the distance between the charges is doubled, the force between them is reduced by a factor of four.

Coulomb's law can be stated as the product of the charges and the square of the distance between them determine the force of attraction or repulsion acting in a straight line between two electric charges.

F= k Q₁Q₂/r²

Where F is the force between two charges

As given in the problem, the two charges are 3 centimeters apart, then we have to find out what will happen to this force if the distance between the charges is doubled.

As per Coulomb's law, the force is inversely proportional to the square of the distance between charges.

Thus, the force between them is reduced by a factor of four.

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Considering the Coulomb's Law, the magnitude of the charge on each particle is 4.2426 C.

Coulomb's law or law of electrostatics is the relationship between the interactions of electric charges, that is, it explains the force experienced by two electric charges at rest.

This law says that the electric force with which two point charges at rest attract or repel each other is directly proportional to the product of the magnitude of both charges and inversely proportional to the square of the distance that separates them, expressed mathematically as:

\(F=k\frac{Qq}{d^{2} }\)

where:

The force is attractive if the charges are of opposite sign and repulsive if they are of the same sign.

In this case, you know that:

Replacing in the Coulomb's Law:

\(1.8x10^{-8} N=9x10^{9} \frac{Nm^{2} }{C^{2} }\frac{Qq}{(0.3 m)^{2} }\)

Being Q=q:

\(1.8x10^{-8} N=9x10^{9} \frac{Nm^{2} }{C^{2} }\frac{q^{2} }{(0.3 m)^{2} }\)

Solving:

1.8×10⁻⁸ N÷ 9×10⁹ \(\frac{Nm^{2} }{C^{2} }\)= q²÷ (0.3 m)²

2×10⁻¹⁸ C²/m²= q²÷ (0.3 m)²

2×10⁻¹⁸ C²/m²= q²÷ 0.09 m²

2×10⁻¹⁸ C²/m² ×0.09 m²= q²

1.8×10⁻¹⁹ C²= q²

√1.8×10⁻¹⁹ C²= q

4.2426 C= q= Q

Finally, each charge has a value of 4.2426 C.

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If the impulse is strong enough and lasts for a sufficient amount of time, the go-kart will eventually come to a stop.

Option A is correct.

impulse is described as the integral of a force, F, over the time interval, t, for which it acts. Since force is a vector quantity, impulse is also a vector quantity.

If the force is insufficient to stop the go-kart entirely, it will slow down but continue to move. The force and duration of the impulse, along with the mass and speed of the go-kart, will all affect how much deceleration occurs.

Given that momentum plus impulse equals zero, the go-kart's change in momentum as a result of the impulse will be equal in amount but will move in the opposite direction of its original momentum.

As a result, the go-kart's final momentum will be zero, suggesting that it has either stopped or is travelling very slowly.

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equal in magnitude but opposite in direction

Baded on the law of conservation of energy, the total energy in a systemis constant even though it change form.

Energy is defined as the ability to do work.

Energy occurs in many forms such as:

Energy according to law of conservation of energy, cannot be created nor destroyed, but change from one form to another.

For example, electrical energy can be converted to light and sound energy. However, the total energy remains constant.

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