Someone please help !

The appropriate synthetic route is; Br₂ (bromine), H₂O (water), H₂O₂ (hydrogen peroxide), NaOH (sodium hydroxide).

To convert 5-methyl-1-hexene into 5-methylhexanal, the appropriate synthetic route would involve oxidation of the double bond followed by hydrolysis of the resulting intermediate. The correct sequence of steps would be:

Br₂ (bromine): Bromine adds across the double bond, resulting in the formation of 5-bromo-5-methylhexane.

H₂O (water): The bromine atom is replaced by a hydroxyl group (-OH) through a nucleophilic substitution reaction, forming 5-methylhexanol.

H₂O₂ (hydrogen peroxide), NaOH (sodium hydroxide): The oxidation of 5-methylhexanol using hydrogen peroxide in the presence of sodium hydroxide leads to the formation of 5-methylhexanal.

Therefore, the appropriate synthetic route is;

Br₂

H₂O

H₂O₂, NaOH

This sequence of steps allows the conversion of 5-methyl-1-hexene to 5-methylhexanal.

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The mass of lithium phosphate (Li₃PO₄) is needed to prepare 500 mL of a solution having a lithium ion concentration of 0.125 M is 20.58 g (Option E).

To calculate the mass of lithium phosphate required to prepare this solution, we need the molar mass of lithium phosphate (Li₋PO₄):

Molar mass of Li₃PO₄ = (3 × molar mass of Li) + molar mass of P + (4 × molar mass of O)

= (3 × 6.941) + 30.974 + (4 × 15.999)

= 109.854 g/mol

Now let's calculate the mass of lithium phosphate required:

Number of moles of Li in the solution = C × V

= 0.125 × 0.5

= 0.0625 mol

Number of moles of Li in lithium phosphate = 3 × number of moles of Li₃PO₄

= 3 × 0.0625

= 0.1875 mol

Mass of lithium phosphate = number of moles of Li₃PO₄ × molar mass of Li₃PO₄

= 0.1875 × 109.854

= 20.58 g

Hence, option E is the correct answer.

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The magnitude of the concentration that LiOH(aq) employs to neutralize the reaction is 0.125 M.

\(M__{H_{2}SO_4 }\) = M₁ = 0,050 M

\(V__{H_{2}SO_4 }\) = V₁  = 20,0 ml

\(V__{LiOH }\) = V₂ = 8,00 ml

Thus, solving for the final morality is:

M₁V₁ = M₂V₂

M₂ = \(\frac{M_1V_1}{V_{2}}\)

So, plugging in the values we obtain:

M₂ =  \(\frac{0,050x20,0}{8,00}\)

M₂ = 1 : 8,00

M₂ = 0,125 M

Then the magnitude of the concentration that LiOH employs to neutralize the reaction is 0.125 M.

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Answer:

The formula for barium ion is Ba2+ and the formula for nitride ion is N3-. When combined, they form barium nitride with the formula Ba3N2.

Explanation:

The formula for the barium ion is Ba²⁺, the formula for the nitride ion is N³⁻.

In order to acquire a stable conformation, the metallic element barium from Group 2 of the periodic table readily loses two electrons.

The production of the Ba²⁺ ion, which has a 2+ charge as a result of the elimination of two negative charges, is the result of the loss of these two electrons.

The nitride ion has the formula N³⁻. A nonmetal element belonging to Group 15 of the periodic table is nitrogen.

To finish its valence shell and obtain a stable electron configuration, it can gain three electrons. The N³⁻ ion is created when nitrogen gains three electrons and three more negative charges, giving it a 3-charge.

Thus, the correct answer is Ba²⁺, and N³⁻.

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Answer:

0.01 moles

Explanation:

14 g contains 1 mole

0.14g contains> (0.14*1)/14

= 0.01 moles

The name of pb(no3)2 is Lead(II) nitrate.

pb(no3)2 is an ionic compound.

How to name ionic compound?

Name of pb(no3)2:

The charge of nitrate ion NO3 is -1. To find the charge of lead, we'll take it as x. Hence,

x+2(-1)=0

x=2

The charge of lead cation in this ionic compound is calculated as +2.

Therefore the name of pb(no3)2 is confirmed as Lead(II) Nitrate.

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Answer:

A and D

Explanation:

Answer:

A & D

Explanation:

Temperature remains the same as the amount of heat and the concentration remains the same..

When 100cm3 of 1.0 mol dm-3 hcl is mixed with 100 cm3 of 1.0 mol dm-3 of NaOH the temperature remains the same. Here, the volume of the solution gets half .mass and heat released reduced by half.so, temperature remains the same as the concentration of the solution does not change.concentration of the solution is the amount of solute present in the given solution.

So, the temperature remains the same as 5C.We know this from calculating heat exchange using specific heat capacities.This process explains when two or more substances at different temperature are brought together to the environment they eventually reach the same temperature.

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Answer:

These are Kepler's Laws of Planetary Motion

Explanation:

Answer:

its Keplers third law,

then first law,

then second law

Explanation:

3.

Na₃PO₄ + ___ KOH ----> ___ NaOH + K₃PO₄

The first step to balance this equation is to determine the number of atoms of each element that we have on each side of the equation.

Na₃PO₄ + ___ KOH ----> ___ NaOH + K₃PO₄

Na: 3 Na: 1

P: 1 P: 1

K: 1 K: 3

H: 1 H: 1

O: 5 O: 5

We can start balancing the Na, we have 3 atoms on the left and 1 atom of right side of the equation. To balance the Na we can change the coefficient for NaOH and write a 3 there.

Na₃PO₄ + ___ KOH ----> 3 NaOH + K₃PO₄

Na: 3 Na: 3

P: 1 P: 1

K: 1 K: 3

H: 1 H: 3

O: 5 O: 7

The P is already balanced, but the K is not. We have 3 atoms on the right side of the equation but only 1 atom of the left. We can change the coefficient of KOH and write a 3 there.

Na₃PO₄ + 3 KOH ----> 3 NaOH + K₃PO₄

Na: 3 Na: 3

P: 1 P: 1

K: 3 K: 3

H: 3 H: 3

O: 7 O: 7

And the equation now is balanced.

Answer: Na₃PO₄ + 3 KOH ----> 3 NaOH + K₃PO₄

4,

__ P + O₂ ----> P₂O₂

O: 2 O: 2

P: 1 P: 2

In this one O is already balanced but P is not. We have two atoms of P on the right and only 1 on the left. We can write a 2 as the coefficient of P.

2 P + O₂ ----> P₂O₂

O: 2 O: 2

P: 1 P: 2

The equation is balanced.

Answer: 2 P + O₂ ----> P₂O₂

The U.S. Treasuries act as benchmark bonds implies that they're measured in terms of the spread with regards to other treasuries.

A benchmark bond simply means the standard measure of the risk of a bond against the other bonds.

When we say that U.S. Treasuries act as benchmark bonds we mean that yields on other bonds are measured in terms of the spread over treasuries.

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1228 gram of oxygen gas is required to complete the combustion of 702g of C8H18 .

This involves the combustion reaction. A combustion reaction is a reaction in which a substance reacts with oxygen gas, releasing energy in the form of light and heat. The given reaction is the combustion of gasoline which is a hydrocarbon. On combustion hydrocarbons produce carbon dioxide and water.

     C8H18 + 12.5 O2 -----> 8 CO2 + 9 H2O

From the balanced equation it is clear that 1mole of  require 12.5 moles of oxygen for complete combustion.

Molar mass of  = 114.23 g/mol

           number of moles = given mass / molar mass .

Substitute 702 g for given mass and 114.23 g/mol for molar mass.

Hence 702 g of C8H18 have 6.14 moles of C8H181 .

1mole of C8H18 require 12.5 moles of oxygen for complete conversion.

then we have to Calculate the number of moles of oxygen  required for the complete combustion of 6.14 moles of C8H18 .

Number of moles of oxygen required ,

           ( 12.5 * 6.14 ) = 76.65 moles

Therefore, 76.75 moles of oxygen is required for the complete combustion of 702 g of C8H18.

Now Convert 76.75 moles of oxygen into mass.

mass = number of moles / molar mass .

           = 76.65 moles / 16 gram/mole

           = 1228 g          

Substituting 76.75 moles for number of moles and 16 g/mole for molar mass of oxygen we get 1228 g of oxygen .

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The charge on the titanium ion if 0.12A of current passes through the solution for 500 seconds is 8.

The charge of an electrolytic circuit can be calculated using the following formula:

Q = It

Where;

According to this question, 0.12A current was electrolyzed through the solution for 500 second. The charge is calculated thus;

Q = 0.12 × 500

Q = 60C

Using M = QM / Fz

Where:

0.015 = 60 × 189.679 ÷ 96485.332 × z

1447.28z = 11380.74

z = 7.9

z = 8

Therefore, the charge on the titanium ion if 0.12A of current passes through the solution for 500 seconds is 8.

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The correct order for lipogenesis (the synthesis of triglycerides) starting with the carbohydrate glucose is as follows:

Here's a brief explanation of each step:

Glucose: Glucose is a monosaccharide and serves as the starting point for lipogenesis. It is derived from dietary carbohydrates and can be broken down through glycolysis to produce pyruvate.

Pyruvate: Pyruvate is a three-carbon molecule that is formed from glucose during glycolysis.

Acetyl-CoA: Acetyl-CoA is a two-carbon molecule that is formed from pyruvate through a process called pyruvate decarboxylation. Acetyl-CoA serves as a precursor for fatty acid synthesis.

Fatty acid: Fatty acids are synthesized from acetyl-CoA through a series of enzymatic reactions in the cytoplasm.

Triglyceride: Triglycerides are formed by combining three fatty acids to glycerol molecule. This esterification reaction results in the formation of a triglyceride molecule, which is the primary storage form of fatty acids in adipose tissue.

It's important to note that lipogenesis is a complex metabolic process regulated by various enzymes and hormonal signals. The conversion of glucose to triglycerides occurs primarily in the liver and adipose tissue.

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Answer:

it should be 310.18 g/mol :)

Answer:

animal cells would because of the vacuole

the producers' surplus at a price of $14 and MC = $6 would be $8.

The first step is to find the quantity supplied at the given price of $14. Substituting p = 14 in the supply equation, we get:
14 = 10 + 2q
4 = 2q
q = 2
Therefore, at a price of $14, the quantity supplied is 2 units. To calculate the producers' surplus, we need to find the area between the supply curve and the price line, up to the quantity supplied. This is a right triangle with base 2 (the quantity) and height (p - MC), where MC is the marginal cost of producing one unit. The marginal cost is not given, so we cannot calculate the exact value of producers' surplus. However, we can say that it will be positive as long as the price is above the marginal cost. If we assume a marginal cost of $6, for example, then the height of the triangle would be 14 - 6 = 8. The area would be (1/2) x 2 x 8 = $8. Therefore, the producers' surplus at a price of $14 and MC = $6 would be $8.

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The empitical formula shows the simplest ratio of elements in a compound (not the total number of atoms in the molecule).

So to find the empirical formula we need to calculate how many moles of each atom we have in this sample. Then we will see the ratio of each element.

We are given the mass, so to convert it to moles we use the molar mass. For this we go to the periodic table and see that the values for each element are:

Na (sodium): 22,99 g/mol

H (hydrogen): 1 g/mol

P (phosphorus): 25,81 g/mol

So we calculate the moles of each element as follows:

And as we see, for every 0.833 moles of Na we have the same number of moles of P, so the ratio of these elements in the molecule is 1 to 1.

As for the hydrogen:

So the ratio Na to H is 1 to 2.

Now we can write the empirical formula as follows=

The bond order for a second-period diatomic particle containing five electrons in antibonding molecular orbitals and eight electrons in bonding molecular orbitals is 1.5

Bond order is defined as the number of electrons in bonding molecular orbitals minus the number of electrons in antibonding molecular orbitals divided by two. As a result, we may determine the bond order of this diatomic particle by the formula: Bond order = (number of bonding electrons - number of antibonding electrons) / 2

Bond order = (8 - 5) / 2

Bond order = 1.5.

This diatomic molecule, according to the bond order, is a stable molecule since the bond order is greater than 1, indicating that it is a double bond. The molecule has an overall bond strength that is greater than a single bond, but not as strong as a triple bond. So therefore he bond order for a second-period diatomic particle containing five electrons in antibonding molecular orbitals and eight electrons in bonding molecular orbitals is 1.5

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Answer:

Moles to grams: 73.05346250000001

Answer:

is there an answier choice u have to choose from or no

Explanation:

Answer:

Hair color

Eye color

Birth weight

Explanation:

Answer:

partly ionic and partly covalent

The required volume of 6M acetic acid (CH3COOH) that reacts with 0.5g of sodium bicarbonate (NaHCO3) is 0.035ml .

Firstly we need to understand the chemical reaction between acetic acid and sodium bicarbonate

CH3COOH + NaHCO3 --------> CH3COONa + H2O + CO2

From the equation we can say that the mole ratio between the NaHCO3 and CH3COOH is 1:1 and as we had given that the mass of sodium bicarbonate is 0.5g , we can calculate the number of moles of sodium bicarbonate that are able to react with 6M acetic acid .

Hence no. of moles of sodium bicarbonate is

               \(0.5g X \frac{ mole}{molar mass}\)

The molar mass of NaHCO3 is 23 +1+12+(16x3) = 84 g/mol

Hence the no. of moles  =  \(\frac{0.5 g}{84 g/mol}\)

                                          =  0.0059 moles

Therefore the volume of 6M acetic acid is

0.0059 moles X 1000 ml X \(\frac{6M}{1000ml}\)

                0.0059 X 6 = 0.035 ml

Therefore the required volume is 0.035ml of 6M acetic acid that fully reacts with 0.5g of sodium bicarbonate

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The molar mass of the metal is 191.1g/mol.

Solution:

Since the formula for faraday's law of electrolysis is given by

Since m = 0.1427g, I = 144.2mA = 144.2mA *(1A/1000mA) = 0.1442 A= 0.1442C/s, t = 16min39s = 16min*(60s/1min) = 960+39 = 999 second Z = 2e-mol

Now put all values in the above formula

0.1427 g = (0.1442 C*999s*M*1 mole e-*1 mol/96485C*s*2e-mol)

M = (0.1427g*96485*2/0.1442*999*1)

M = 191.1538 g/mol = 191.1g/mol

Therefore the molar mass of metal will be 191.1g/mol.

For chemical elements that do not have isolated molecules such as carbon and metals, the molar mass is instead calculated by dividing by the number of atomic moles. Molar mass is defined as the mass in grams of one mole of a substance. The unit of molar mass is gram/mole, abbreviated g/mol.

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Answer:

The shapes of continents fit together like a puzzle.

Explanation:

Just look at the east coast of South America and the west coast of Africa—it's almost a perfect fit! Identical rocks have been found on different continents. These rocks formed millions of years ago before the continents separated.

Answer:

2.05g

Explanation:

The weight of butane gas present in the system with the specified temperature and pressure is 2.05 g. We can use ideal gas law here.

Ideal gas law states the relation between temperature, pressure and volume  and mathematically written as below:

PV = nRT

Here, P and V be the pressure and volume and n be the no.of moles and R be the universal  gas constant. T is the absolute temperature in kelvin.

The system have a volume of 3000 mL or 3 L and pressure of 760 torr and temperature of 1000 K. The no. of moles n is the ratio of taken weight to the molar mass. R has the value 62.36 L torr/(K mol)

Apply these values into ideal gas law as given below:

(3 L × 760 torr)  = (w/56.1 g/mol) × 62.36 L torr/(K mol) × 1000 K. From this,

\(2280 \textup{ torr L} = \frac{w}{56.1 g/mol} \times 62360 \textup{ L torr/mol}\)

\(w = \frac{2280\textup{ torr L}\times 56.1\textup{ g/mol}}{62360 \textup{ L torr/mol}} =2.05 g\)

Therefore, the amount of butane gas for the given system is 2.05 g.

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Suppose that 9 good fuses and 4 defective ones have been mixed up. The defective fuses, we test them one-by-one, at random. The probability that we are lucky and find both of the defective fuses in the first two tests is 1/13.

We can use the concept of probability. There are 13 fuses in total, and we are looking for a specific order of the first two being defective. For the first test, the probability of selecting a defective fuse is 4/13 (since there are 4 defective fuses and 13 total fuses). Once we have found one defective fuse, there are now 3 defective fuses remaining and a total of 12 fuses. For the second test, the probability of selecting another defective fuse is 3/12, which can be simplified to 1/4.

To find the probability of both events happening consecutively, we multiply the probabilities of each individual event: (4/13) * (1/4) = 4/52, which simplifies to 1/13.  So, the probability of finding both defective fuses in the first two tests when there are 9 good fuses and 4 defective ones is 1/13.

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(a) When the density of gold is 19.32 g/\(cm^{3}\) than area of the gold leaf is approximately 0.4386 cm².

(b) The length of the gold fiber is given by h = 0.4386 cm³ / (π * (2.500 × 10⁻⁴ cm)²).

To solve these problems, we can use the formula for the volume of a shape and the given density of gold.

(a) To find the area of the leaf, we can use the formula for the volume of a rectangular shape: V = A * h, where V is the volume, A is the area, and h is the thickness.

Given the mass of gold (m = 8.489 g) and density (ρ = 19.32 g/cm³), we can find the volume: V = m / ρ.

Substituting the values, we have V = 8.489 g / 19.32 g/cm³ = 0.4386 cm³.

Since the leaf is pressed into a thin shape, we can assume it has a rectangular shape, and the volume is approximately equal to the area: A ≈ V = 0.4386 cm².

(b) To find the length of the fiber, we can use the formula for the volume of a cylindrical shape: V = π * r² * h, where V is the volume, r is the radius, and h is the length.

Given the mass of gold (m = 8.489 g) and density (ρ = 19.32 g/cm³), we can find the volume: V = m / ρ.

Substituting the values, we have V = 8.489 g / 19.32 g/cm³ = 0.4386 cm³.

The volume of a cylinder is also equal to the product of the cross-sectional area (π * r²) and the length (h), so we have: π * r² * h = 0.4386 cm³.

Substituting the radius (r = 2.500 μm = 2.500 × 10⁻⁴ cm), we can solve for the length: h = 0.4386 cm³ / (π * (2.500 × 10⁻⁴ cm)²).

To summarize:

(a) The area of the gold leaf is approximately 0.4386 cm².

(b) The length of the gold fiber is given by h = 0.4386 cm³ / (π * (2.500 × 10⁻⁴ cm)²).

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Based on the chemical equation of the reaction, S (sulfur) was oxidized and N (nitrogen) was reduced.

The correct option is C.

A redox reaction is a name for a reduction-oxidation reaction.

In a redox reaction, oxidation and reduction occur during the reaction.

Oxidation involves a loss of electrons and results in an increase in the oxidation number of the oxidized species.

Reduction involves a gain of electrons and results in a decrease in the oxidation number of the reduced species.

Considering the given equation of reaction:

3 SO₂ + 2 HNO₃ + 2 H₂O → 3 H₂SO₄ + 2 NO

The oxidation number of nitrogen changes from +5 in HNO₃to +2 in NO. Hence, it is reduced.

The oxidation number of sulfur changes from +4 tin SO₂ to +6 in H₂SO₄. Hence it is oxidized.

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Answer:

electrons

Explanation:

electricity is the flow of electrons through a conductor

Answer:

protons

Explanation:

and neutrons never move from object to object. The energy that comes from these charged particles is called electrical energy.