HELP!! *I WILL MARK BRAINLIEST*
The manager of the cafeteria kept track of the number of each type of lunch sold in October and made this table. Which graph best correctly and completely represents the data in the table?
Answer:
C
Step-by-step explanation:
Find the total price, including tax of a $15.99 hat with 6% tax
Show Work!
The total price of the hat including the tax is $ 16.9494 .
How to calculate percentage and how is it determined?
A percentage is a figure or ratio that can be stated as a fraction of 100 in mathematics. If we need to determine a percentage of a number, multiply it by 100 and divide it by the total. So, a part per hundred is what the percentage refers to. Percent signifies for every 100. The sign "%" is used to denote it. No dimension exists for percentages. Thus, it is referred to as a dimensionless number. The value must be divided by the entire value, and the resulting number must then be multiplied by 100 to get the percentage.
Mathematically, Percentage formula = (Value/Total value) × 100
Given, cost price of hat (total value) = $ 15.99
Percentage tax imposed on the hat = 6%
Now, using the formula established in the literature above, we have:
Percentage = (Value/Total Value)×100
⇒ Value = (Percentage × Total Value)/100 = (6×15.99)/100 = $ 0.9594
Therefore, the total price of hat = Cost Price + Value = $ (15.99 + 0.9594) = $ 16.9494
Thus, the total price of the hat including the tax is $ 16.9494 .
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what is the algebraic nature of the function f(x)= x2 -6X+5
Answer:
Step-by-step explanation:
It is a positive, or upwards-opening, quadratic; this implies it is parabolic in shape. It has 2 real zeros of x = 5 and x = 1, a y-intercept of (0, 5), and a vertex located at (3, -4). Not sure what else you can possibly need to know about this parabola.
THE ^ MEANS IT IS AN EXPONENT AND THE ? MEANS THATS WHERE I HAVE TO PUT AN EXPONENT fill in the question marks 5^? x 5^3 = 5^?
In this equation, we have two exponential terms with the same base, 5. To solve for the missing exponents, we can use the laws of exponents, specifically the product law of exponents the missing exponent is 3, and we can write:\(5^? x 5^3 = 5^(?+3) = 5^6\)
What are the laws of exponents?Using the laws of exponents, we know that when we multiply two exponential expressions with the same base, we add their exponents. Thus:
\(5^? x 5^3 = 5^(?+3)\)
Now, we can use the fact that the two expressions on either side of the equation are equal to fill in the missing exponents:
\(5^? x 5^3 = 5^(?+3)\)
\(5^? x 125 = 5^(?+3)\)
Now we can simplify by dividing both sides of the equation by 5^?:
\(125 = 5^3\)
Therefore, the missing exponent is 3, and we can write\(5^? x 5^3 = 5^(?+3) = 5^6\)
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The missing term in the equation \(5^? * 5^3 = 5^2\) is x = -1.
What is the exponent law of the same base?The Exponent Product Rule is as follows: \(a^{m} * a^{n} = a^{m+n}\) Add the exponents to obtain the product of two numbers with the same base. The Exponent Quotient Rule: \(\frac{a^{m} }{a^{n} } = a^{m-n}\). Subtract the exponent of the denominator from the exponent of the numerator to determine the quotient of two numbers with the same base.
The given equation is \(5^? * 5^3 = 5^2\)
Suppose we are considering ? as x, therefore we can rewrite the equation as,
\(5^{x} * 5^{3} = 5^{2} \\\)
As the base of the LHS exponent is is same, we can add the exponent
\(5^{x +3}\) = \(5^{2}\)
Now the base of both sides is equal, so we can compare the exponent.
x + 3 = 2
x = 2 - 3
x = -1
Therefore the missing term is x = -1.
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Complete question:
Find the missing term, \(5^? * 5^3 = 5^2\)
Which of these transformations satisfy T(v+w) = T(v) +T(w) and which satisfy T(cv) = cT (v)? (a) T(v) = v/||v|| (b) T(v) = v1+V2+V3 (c) T(v) = (v₁, 2v2, 3v3) (d) T(v) largest component of v. = Suppose a linear T transforms (1, 1) to (2, 2) and (2,0) to (0,0). Find T(v): (a) v = (2, 2) (b) V= = (3,1) (c) v = (-1, 1) (d) V= = (a, b)
To determine which of the given transformations satisfy T(v+w) = T(v) + T(w) and T(cv) = cT(v), we can evaluate each transformation using the given conditions.
(a) T(v) = v/||v||
Let's test if it satisfies the conditions:
T(v + w) = (v + w) / ||v + w|| = v/||v|| + w/||w|| = T(v) + T(w)
T(cv) = (cv) / ||cv|| = c(v/||v||) = cT(v)
Therefore, transformation T(v) = v/||v|| satisfies both conditions.
(b) T(v) = v1 + v2 + v3
Let's test if it satisfies the conditions:
T(v + w) = (v1 + w1) + (v2 + w2) + (v3 + w3) ≠ (v1 + v2 + v3) + (w1 + w2 + w3) = T(v) + T(w)
T(cv) = (cv1) + (cv2) + (cv3) ≠ c(v1 + v2 + v3) = cT(v)
Therefore, transformation T(v) = v1 + v2 + v3 does not satisfy the condition T(v+w) = T(v) + T(w), but it does satisfy T(cv) = cT(v).
(c) T(v) = (v₁, 2v₂, 3v₃)
Let's test if it satisfies the conditions:
T(v + w) = (v₁ + w₁, 2(v₂ + w₂), 3(v₃ + w₃)) ≠ (v₁, 2v₂, 3v₃) + (w₁, 2w₂, 3w₃) = T(v) + T(w)
T(cv) = (cv₁, 2cv₂, 3cv₃) ≠ c(v₁, 2v₂, 3v₃) = cT(v)
Therefore, transformation T(v) = (v₁, 2v₂, 3v₃) does not satisfy the condition T(v+w) = T(v) + T(w), but it does satisfy T(cv) = cT(v).
(d) T(v) largest component of v
Let's test if it satisfies the conditions:
T(v + w) = largest component of (v + w) ≠ largest component of v + largest component of w = T(v) + T(w)
T(cv) = largest component of (cv) ≠ c(largest component of v) = cT(v)
Therefore, transformation T(v) largest component of v does not satisfy either condition.
For the given linear transformation T:
(1, 1) → (2, 2)
(2, 0) → (0, 0)
We can determine the transformation matrix T(v) as follows:
T(v) = A * v
where A is the transformation matrix. To find A, we can set up a system of equations using the given transformation conditions:
A * (1, 1) = (2, 2)
A * (2, 0) = (0, 0)
Solving the system of equations, we find:
A = (1, 1)
(1, 1)
Therefore, T(v) = (1, 1) * v, where v is a vector.
(a) v = (2, 2):
T(v) = (1, 1) * (2, 2) = (4, 4)
(b) v = (3, 1):
T(v) = (1, 1) * (3, 1) = (4, 4)
(c) v = (-1, 1):
T(v) = (1, 1) * (-1, 1) = (0, 0)
(d) v = (a, b):
T(v) = (1, 1) * (a, b) = (a + b, a + b)
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please explain clearly
Explain your answer !!
Have a nice day
Answer:
x=2
y=10
Step-by-step explanation:
sub y=3x+4 into 2x-3y=-26
2x-3(3x+4)=-26
2x-9x-12=-26
7x=14
x=2
subt x=2 into y=3x+4, y=3(2)+4
=10
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Element X decays radioactively with a half life of 13 minutes. If there are 430 grams of Element X, how long, to the nearest tenth of a minute, would it take the element to decay to 6 grams?
\(y=a(.5)^\frac{t}{h}\)
It will take 80.63 minutes for the element X to decay to 6 grams.
What is substitution method?
Find the value of any one of the variables from one equation in terms of the other variable is called the substitution method.
Given that;
Element X decays radioactively with a half life of 13 minutes.
There are 430 grams of Element X.
Since, The half life formula to solve the problem is;
\(A = a (0.5)^{\frac{t}{h}\)
Where, A is final amount, a is initial amount, t is time and h is half life.
Now, We have;
A = 6, a = 430, h = 13
Substitute in above equation we get;
\(6 = 430 (0.5)^{\frac{t}{13} }\)
Solve for t as;
Divide by 430,
\(\frac{6}{430} = (0.5)^{\frac{t}{13} }\)
\(\frac{3}{215} = (0.5)^{\frac{t}{13} }\)
Take log both side;
\(ln\frac{3}{215} = ln(0.5)^{\frac{t}{13} }\)
\(ln 3 - ln 215 =\frac{t}{13} ln(0.5)\)
Substitute values of all the log as;
1.09 - 5.37 = t / 13 (-0.69)
- 4.28 = t/ 13 (-0.69)
13 x 4.28 = 0.69t
55.64 = 0.69t
t = 55.64 / 0.69
t = 80.63
Thus, It will take 80.63 minutes for the element X to decay to 6 grams.
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Please someone help me!
Answer:
domain-r
range-3
function-function
Step-by-step explanation:
a=b(1/c-1/d) solve for c
Answer:
c = bd ⁄ ad+b
How many real numbers are solutions for x2 − 5x 7 0?
There are two real number solutions for x2 − 5x + 7 = 0: x = 2 and x = 7.
1. x2 − 5x + 7 = 0
2. (x - 2)(x - 7) = 0
3. x = 2 or x = 7
When solving for the real number solutions of x2 − 5x + 7 = 0, we first need to factor the equation into two linear terms: (x - 2)(x - 7) = 0. From here, we can use the Zero Product Property to determine that x = 2 and x = 7 are the two real number solutions of this equation. This means that when x is equal to 2 or 7, the equation will equal 0 and all other values of x will result in a non-zero answer. Therefore, the only two real number solutions of x2 − 5x + 7 = 0 are x = 2 and x = 7.
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I answered the rest of my questions but this one is confusing me
Answer:
the answer is 36ft by 48ft
Step-by-step explanation:
We first need to find the measurements of the green squares. Given the drawing is to scale we can say that each green square has equivalent measurements. Since there are 144 feet on each side of the original drawing, and 12 green squares on each side as well, then we need to divide 144 by 12 to find the measurements of one square. 144/12=12. the green squares are each 12ft by 12ft. to find the measurement of the jungle gym, we see how many green squares are on each side (there are 3 and 4) then multiply that number by 12. 4*12 I 48, and 3*12 is 36. Hence the measurements of 36ft by 48ft.
Linda got a prepaid debit card with $20 on it. For her first purchase with the card, she bought some bulk ribbon at a craft store. The price of the ribbon was 14 cents per yard. If after that purchase there was $17. 06 left on the card, how many yards of ribbon did Linda buy?
Therefore, Linda bought 21 yards of ribbon. Hence, Linda bought 94 yards of ribbon.
The number of yards of ribbon Linda bought, we need to calculate the difference between the initial balance on the card and the remaining balance after the purchase.
The initial balance on the card was $20. To find the amount spent on ribbon, we subtract the remaining balance ($17.06) from the initial balance. $20 - $17.06 = $2.94
Now, we need to determine how many yards of ribbon Linda could purchase with $2.94, given that the price of the ribbon is 14 cents per yard.
To find the number of yards, we divide the total amount spent ($2.94) by the price per yard (14 cents): $2.94 ÷ $0.14 = 21
Therefore, Linda bought 21 yards of ribbon.
Hence, Linda bought 94 yards of ribbon.
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(5/6z+5) + (-1/2-4)?
.
Answer: \(\frac{5}{6}z+\frac{1}{2}\)
Step-by-step explanation:
\(\frac{5}{6}z+5-\frac{1}{2}-4\\\\\frac{5}{6}z+1-\frac{1}{2}\\\\\frac{5}{6}z+\frac{1}{2}\)
i. The Cartesian equation of the parametric equations x = sint, y=1-cost, 05152x is given by
A. x² + (y− 1)² = 1
B. x² + y² = 1
C. x²-(y+1)²=1
D. x² + (y + 1)² = 1
ii. Parametric equations that represent the line segment from (-3, 4) to (12, -8) are
A. x=-3-15t, y=4-121, 0sis1
B. x=-3-15t, y=4-121, 0≤t≤2
C. x=8-151, y=4-121, 0≤1S2
D. x=-3+15t, y=4-121, 0≤t≤1 E
(a) The Cartesian equation of the given parametric equations is D. x² + (y + 1)² = 1.
(b) The parametric equations that represent the line segment from (-3, 4) to (12, -8) are B. x = -3 - 15t, y = 4 - 12t, 0 ≤ t ≤ 2.
(a) To find the Cartesian equation of the parametric equations x = sint and y = 1 - cost, we can eliminate the parameter t.
From x = sint, we get sint = x, and from y = 1 - cost, we get cost = 1 - y.
Squaring both equations, we have (sint)² = x² and (1 - cost)² = (1 - y)².
Adding these equations, we get (sint)² + (1 - cost)² = x² + (1 - y)².
Simplifying further, we have x² + 2sint - 2cost + y² - 2y = x² + y² - 2y + 1.
Canceling out the x² and y² terms, we obtain 2sint - 2cost = 2y - 1.
Dividing both sides by 2, we get sint - cost = y - 1/2.
Since sint - cost = 2sin((t - π/4)/2)cos((t + π/4)/2), we can rewrite the equation as 2sin((t - π/4)/2)cos((t + π/4)/2) = y - 1/2.
Simplifying further, we have sin((t - π/4)/2)cos((t + π/4)/2) = (y - 1/2)/2.
Using the double-angle formula for sine, sin(A + B) = sin(A)cos(B) + cos(A)sin(B), we can rewrite the equation as sin((t - π/4)/2 + (t + π/4)/2) = (y - 1/2)/2.
This simplifies to sin(t/2) = (y - 1/2)/2.
Squaring both sides, we get sin²(t/2) = (y - 1/2)²/4.
Since sin²(t/2) = (1 - cos t)/2, the equation becomes (1 - cos t)/2 = (y - 1/2)²/4.
Multiplying both sides by 2, we have 1 - cos t = (y - 1/2)²/2.
Simplifying further, we get 2 - 2cos t = (y - 1/2)².
Rearranging the terms, we obtain x² + (y + 1)² = 1, which is option D.
(b) To find the parametric equations representing the line segment from (-3, 4) to (12, -8), we need to find equations for x and y in terms of a parameter t.
Let's calculate the differences between the x-coordinates and y-coordinates of the two points:
Δx = 12 - (-3) = 15
Δy = -8 - 4 = -12
We can use these differences to create the parametric equations:
x = -3 + Δx * t = -3 + 15t
y = 4 + Δy * t = 4 - 12t
The parameter t ranges from 0 to 1 to cover the entire line segment. Therefore, the correct option is B, which states x = -3 - 15t and y = 4 - 12t, with 0 ≤ t ≤ 2.
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If d(3) = 4 and d(x)= 7x - k, what is k?
Answer:
k = 17
Step-by-step explanation:
x=3
4 = 7x - k
4= 7(3) - k
4= 21 - k
21 - 4 = 17
k = 17
round to nearest hundredth :3,353
Answer:
3,000
Step-by-step explanation:
Since the next number is less than 5 you round down
what is 70 percent bof 500
Answer:
70 percent of 500 would equal to 14 percent!
Step-by-step explanation:
Solve for x.
5x - 4 = -3x+ 12
X = 2
X=6
X=-4
Answer:
x = 2
Step-by-step explanation:
Given
5x - 4 = - 3x + 12 ( add 3x to both sides )
8x - 4 = 12 ( add 4 to both sides )
8x = 16 ( divide both sides by 8 )
x = 2
Solve the question.
I'm lowkey stuck on this ;-;
Answer:
x = -149/20
General Formulas and Concepts:
Pre-Algebra
Order of Operations: BPEMDASEquality PropertiesStep-by-step explanation:
Step 1: Define equation
2(x + 469/20) = 32
Step 2: Solve for x
Distribute 2: 2x + 469/10 = 32Isolate x term: 2x = -149/10Isolate x: x = -149/20Step 3: Check
Plug in x to verify it's a solution.
Substitute: 2(-149/20 + 469/20) = 32Add: 2(16) = 32Multiply: 32 = 32Here we see that 32 does indeed equal 32. ∴ x = -149/20 is a solution of the equation.
And we have our final answer!
Find the missing side lengths. Leave your answers as radicals in simplest form
Answer:
Step-by-step explanation:
Hi Mia, are you aware that the last name Hamilton is a famous math person? :) anyway,
The triangle in the picture is an isosceles triangle, we know that b/c the angle of the one is 45° meaning the other side must also be a 45° angle. So we know the two sides are the same length.
side n = 7 \(\sqrt{2}\) / 2
then use Pythagoras to find m
\(c^{2}\) = ( 7 \(\sqrt{2}\) / 2)^2 + ( 7 \(\sqrt{2}\) / 2)^2
\(c^{2}\) = 49*2/4 + 49*2/4
\(c^{2}\) = 49/2 + 49/2
\(c^{2}\) = 98/2
\(c^{2}\) = 49
c = 7
side m = 7 :) nice, huh ?
a) Sin X = O/H
Sin 45 = \(7\sqrt{2}\)/2/H
H= \(7\sqrt{2}\)/2/ Sin 45
m= 7
b) cos X = A/H
cos 45= A/7
A= cos45*7
n= 4.95
A farmer has 2400 sheep, he loses 32,5% due to the drought. After that he loses 15% due to sickness. How many sheep does he have now?
The farmer now has 1377 sheep. If the farmer loses 32.5% of his 2400 sheep due to the drought, then he will have: 2400 * (1 - 0.325) = 1620 sheep left after the drought.
The farmer had 2400 sheep, but he lost 32.5% of them due to drought. Using the formula for finding percentages, we can calculate that 32.5% of 2400 is 780. So, the farmer had 2400 - 780 = 1620 sheep left after the drought. However, he then lost 15% of those remaining sheep due to sickness. Using the same formula, we can calculate that 15% of 1620 is 243. Therefore, the farmer had 1620 - 243 = 1377 sheep left after the sickness. So, the final number of sheep the farmer has now is 1377.
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HELP ME PLEASE GOOD NIGHT
ME PUEDES AYUDAR POR FAVOR BUENAS NOCHES
please help me it is urgent
Answer:
y=x(t)+y-int
Step-by-step explanation:
Where:
Y= distance
x=speed
t=time
y-int= starting height
If you can post a rate and starting height I can answer part B
Keep in mind if she is traveling down then y-int will be 0<x and the rate will be negative
Using the empirical rule in a normal distribution, what percent of the data falls within three standard deviations of the mean?
a. 50%
b. 68%
c. 95%
d. 99.7%
The empirical rule in a normal distribution states that 99.7% of the data falls within three standard deviations of the mean. Hence, option D is the correct option.
The empirical rule in a normal distribution is also referred to as the three-sigma rule or 68-95-99.7 rule. It is a rule in statistics that tells us that for a normal distribution, all of the observed data fall within the three standard deviations of the mean (denoted by σ) or within the average (denoted by µ).
According to this rule, 68% of the observations fall under the first standard deviation (µ ± σ), and 95% within the first two standard deviations (µ ± 2σ). In addition to this, 99.7% of the data falls within three standard deviations of the mean. Hence, we know that option D is the correct option.
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Consider the LP below. The BFS ("corners") are (0,0) (0,4) (1,4) (3,2) (3,0). The optimal solution is at x_{1} = 3 and x_{2} = 2
max z = 2x_{1} + x_{2}
s.t.
matrix x 1 +x 2 &<= 0 \\ x 1 &<=3\\ x 2 &<4 matrix
x_{1}, x_{2} >= 0
(a). What is the range of c_{1} the objective coefficient of x_{1} (currently 2) for which this BFS remains optimal:
(b). What is the range of b_{2} the right hand side of the second constraint (currently 3) for which this BFS remains optimal:
(c). What is the dual price of the second constraint?
(a) The range of c₁ (the objective coefficient of x₁) for which this BFS remains optimal is c₁ ≤ 2.
(b) The range of b₂ (the right-hand side of the second constraint) for which this BFS remains optimal is 3 ≤ b₂ < 4.
(c) The dual price of the second constraint is 0.
(a) The optimality condition for a linear programming problem requires that the objective coefficient of a non-basic variable (here, x₁) should not increase beyond the dual price of the corresponding constraint. In this case, the dual price of the second constraint is 0, indicating that increasing the coefficient of x₁ will not affect the optimality of the basic feasible solution. Therefore, the range of c₁ for which the BFS remains optimal is c₁ ≤ 2.
(b) The range of b₂ for which the BFS remains optimal is determined by the allowable range of the corresponding dual variable. In this case, the dual price of the second constraint is 0, implying that the dual variable associated with that constraint can vary within any range. As long as 3 ≤ b₂ < 4, the dual variable remains within its allowable range, and thus, the BFS remains optimal.
(c) The dual price of a constraint represents the rate of change in the objective function value per unit change in the right-hand side of the constraint, while keeping all other variables fixed. In this case, the dual price of the second constraint is 0, indicating that the objective function value does not change with variations in the right-hand side of that constraint.
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Y=x^2+6x-72 write the equation in vertex form
The answer is y = 1(x + 3)^2 - 81.
Rewrite the problem using substitution and simplify the expression using order of operations and show your work.
3. Evaluate:
Suppose you want to buy something for $60, and you have $15 saved up so far. Then your grandmother calls and says she will chip in for your purchase. She doesn’t tell you the amount of money she will give you yet, so you just consider it x dollars.
The algebraic expression for the scenario is 15 + x = 60
How to evaluate the algebraic expression for the statement?From the question, we have the following parameters that can be used in our computation:
Amount saved up = $15
Cost of item = $60
Amount gifted by your grandma = x
The above parameters means that the mathematical statement is an equation statement
So, we have the following representation
Amount saved up + Amount gifted by your grandma = Cost of item
Substitute the known values in the above equation, so, we have the following representation
15 + x = 60
Hence, the algebraic expression is 15 + x = 60
The question does not require that the equation be solved
However, when it is solved, we have:
15 + x = 60
Subtract 15 from both sides
x = 45
So, the amount is 45
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A florist has 36 tulips and 21 carnations. If the florist wants to create identical bouquets
without any leftover flowers, what is the greatest number of bouquets the florist can make?
Answer:
3
Step-by-step explanation:
21 can be divided by 3 also 36
Answer:
3 bouquets
Step-by-step explanation:
Both numbers are divisible by 3, so after division we have 3 groups of 7 carnations, and 3 groups of 12 tulips. 7 is no longer divisible, so if the desire is an even bouquet then we can only make 3 bouquets of 7 carnations and 12 tulips
you want to enclose a rectangular region with an area of 1200 square feet and a length of 40 feet, 50 feet, or 60 feet. find the perimeter for each possible region.
The circumference is 160 feet for a length of 40 feet. The perimeter is 200 feet for a length of 50 feet. The circumference is 240 feet for a length of 60 feet.
A rectangular region with a 1200 square foot area will have a different perimeter depending on how long it is. The perimeter will be 160 feet if the area is 40 feet long. The length of 40 feet is multiplied by four to get a final measurement of 160 feet. In a similar manner, if the area is 50 feet long, the perimeter will be 200 feet.
The length of 50 feet is multiplied by four to get a final result of 200 feet. Finally, the perimeter will be 240 feet if the area is 60 feet long. The length of 60 feet is multiplied by four to get a final measurement of 240 feet. A rectangular region with an area of 1200 square feet will therefore have a different perimeter depending on its length, with a length of 40 feet resulting in a perimeter of 160 feet, a length of 50 feet resulting in a perimeter of 200 feet, and a length of 60 feet resulting in a perimeter of 240 feet.
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PLS HELP ILL AWARD BRANLIEST
The center of a hyperbola is (-5,8). The length of the conjugate axis is 6 units, and the length of the transverse axis is 14 units. The transverse axis is parallel to the y axis.
What is the equation of the hyperbola in standard form?
Answer:
Here is the answer to your question it is in this picture