Solve the inequality.

2>6-3r

The solution is

Answer:

12

Step-by-step explanation:

Seema’s little sister is 2 years more than ¼ of Seema’s age, so you should subtract 2 from 5 to find ¼ of Seema’s age. If 3 is ¼ of Seema’s age, all you do is multiply it by 4 to get the original number. 3x4 is 12, so the final answer is that Seema is 12.

Percent of free throws = (number of free throws made / total attempts) x 100

Percent = (80/100) x 100 = 80%

The answer is 80%

Answer:

80%

Step-by-step explanation:

In fraction form, the answer is 1/4, which represents the simplified probability of the given event occurring.

To find the probability of picking a prime number and then picking another prime number, we first need to determine the total number of possible outcomes and the number of favorable outcomes.

Given the four numbers: 5, 6, 7, and 8, we can see that there are two prime numbers (5 and 7) and two non-prime numbers (6 and 8).

The total number of possible outcomes is 4 since there are four cards to choose from.

Now, let's consider the favorable outcomes, which are picking a prime number and then picking another prime number.

The probability of picking a prime number on the first draw is 2/4, as there are two prime numbers out of the four total cards.

Since we replace the card before the second draw, the probability of picking a prime number on the second draw is also 2/4.

To find the probability of both events occurring, we multiply the individual probabilities:

(2/4) * (2/4) = 4/16 = 1/4

Therefore, the probability of picking a prime number and then picking another prime number is 1/4.

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Answer:

x = 4

m<AXC = 150

Step-by-step explanation:

m<1 + m<2 = m<AXC

102 + 10x + 8 = 6(6x + 1)

10x + 110 = 36x + 6

26x = 104

x = 4

m<AXC = 6(6x + 1)

m<AXC = 6(24 + 1)

m<AXC = 150

The expression that shows the total oranges amir got in total is x-12 = 4. And amir got 16 oranges in all

A linear expression is an algebraic statement where each term is either a constant or a variable raised to the first power. In other words, none of the exponents can be greater than 1. For example, x² is a variable raised to the second power, but x is a variable raised to the first power.

example of linear expression is 2x+2y = 5. This is a linear expression with two variables x and y.

Let's represent the total no of oranges by x.

Therefore ,

2 bags of oranges with 6 in each bag will amount to 2×6 = 12 oranges.

an addition of 4 loose oranges . Therefore the total number of oranges = 12+4 = x

x = 12+4 or x-12 = 4

= 16

therefore amir got 16 oranges in all

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Answer:

  -6

Step-by-step explanation:

You seem to want the value of q₃ in the matrix Q⁻¹.

The inverse matrix, Q⁻¹, is the transpose of the cofactor matrix, divided by the determinant. That makes q₃ = -q₂₁/det(Q):

  q₃ = -(-2/3)/((-1(-1/9) -(-2/3)(-1/3))

  q₃ = (2/3)/(1/9 -2/9) = (6/9)/(-1/9)

  q₃ = -6

__

Additional comment

The transpose of the cofactor matrix of a 2×2 matrix is the original with the diagonal terms swapped, and the off-diagonal terms negated. Basically, the only math involved in computing the inverse is finding the determinant, and dividing by it.

Answer:

38

Step-by-step explanation:

25+13=38

Answer:

I believe the total change in altitude would be 38 feet.

Step-by-step explanation:

25 + 13 = 38

Given that a function, g, has a domain of -20 ≤ x ≤ 5 and a range of -5 ≤ g(x) ≤ 45 and that g(0) = -2 and g(-9) = 6, the statement that could be true for g is: D. g(-13) = 20.

In Mathematics, a range can be defined as the set of all real numbers that connects with the elements of a domain.

From the information provided, the domain and range of this function g(x) in interval notation is given by:

Function g(0) = 2 is false because it was stated that g(0) = -2. Also, g(-4) = -11 is outside the scope of the given range for this function.

Furthermore, function g(7) = -1 is not within the domain for the given function. However, g(-13) = 20 is within the domain for the given function and produces an output that is within the scope of the given range for this function.

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Answer:

18624 to nearest 1000= 19000

hope this helps <3

Answer:

19000

Step-by-step explanation:

624 is more than 499 therefore it is 19000

Answer:

B).

Step-by-step explanation:

Add 8 to half the difference of 6 and 2 then subtract 1.

Answer:

I apologize but I haven't worked for an answer. but my mind is, what is the point of this question? everyone is familiar with the "when am I ever going to use this in life and why do I need to learn this?" but this is a whole new level of w t f.

Answer:

factor using 12 (gcf)

12(5x-2)

\( - 17y - 16z + 4\)

Step-by-step explanation:

1) Collect like terms.

\(( - y - 16y) + (9z - 25z) + 4\)

2) Simplify.

\( - 17y - 16z + 4\)

So, therefor, the answer is -17y - 16z + 4.

\( \huge \boxed{\mathfrak{Question} \downarrow}\)

\( \large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}\)

\( \sf (-6) \: squared\)

This will be equal to..

\( \sf( - 6 ) ^ { 2 }\)

Multiply -6 by itself (squaring a number means to multiply the number by itself twice)

\( \sf- 6 \times - 6 \\ \)

-6 multiplied by-6 will get you 36 as the answer.

\( = \boxed{\boxed{\bf \: 36}}\)

Answer:

180

Step-by-step explanation:

So, in the first 4 games, they score 10 points. If this continues to happen in the remaining 18 games, it would be 180.

             10 x 18 = 180.

Answer:111

Step-by-step explanation:

1111

The measure of angle ADM is 45.0°, as the intercepted arc AD is congruent to arc CD.

To find the measure of angle ADM, we need to consider that angle ADM is an inscribed angle and its measure is half the measure of the intercepted arc AD.

Given that the measure of arc CD equals the measure of arc DA, it means that these arcs are congruent.

Therefore, the intercepted arcs AD and CD have equal measures.

Since angle ADM is an inscribed angle intercepting arc AD, the measure of angle ADM is half the measure of arc AD.

Therefore, the measure of angle ADM is 45.0°, as the intercepted arc AD is congruent to arc CD.

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Answer:

AC = 12

Step-by-step explanation:

If BC is parallel to DE then ∠D ≅ ∠B and ∠E ≅ ∠C. Therefore

ΔABC is similar to ΔADE.

The sides of smaller triangle are in proportion with sides of bigger triangle.

Therefore we have the equation:

AC/AE = AB/AD

Substitute the given numbers:

x/x+15 =8/18

18x= 8(x+15)

18x = 8x+120

10x = 120

x = 12

AC=12

The expression in the options which is equivalent to the given expression is D. (22x + 48) / (x² - 36).

Given expression is,

[15 / (x - 6)] + [7 / (x + 6)]

Cross multiplying the two fractional expressions,

= [15 (x + 6) + 7 (x - 6)] / [(x - 6) (x + 6)]

= [15x + 90 + 7x - 42] / [x² - 6²]

= (22x + 48) / (x² - 36)

Hence the equivalent expression is D.

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Answer:

f^-1(x) = 4(x+5)/3

Step-by-step explanation:

Let f(x) = y

So, y = (3/4)x - 5

y + 5 = (3/4)x

4(y+5)/3 = x

The steps are first to make a variable that holds the same value as the function, then from there you simplify and eventually make x the subject of the equation.

Step-by-step explanation:

Log(x²+8)=log 10+ log x

Log(x²+8)=log(10×x)

x²+8=10x

x² - 10x + 8=0

x is approximately to - 1 and - 8✅

The solutions to the given equation are x = -1 and x = 8.

Option A is the correct answer.

Solutions are the values of an equation where the values are substituted in the variables of the equation and make the equality in the equation true.

We also find the solution in a system of equations using the substitution or elimination method.

Example:

2x + 4 = 8

The solution is x = 2.

We have,

Using logarithmic properties, we can simplify the given equation:

logs(x² + 8) = 1 + log g(x)

logs(x² + 8) - log g(x) = 1

log[(x² + 8)/g(x)] = 1

(x² + 8)/g(x) = 10

x² + 8 = 10g(x)

Now we can solve for x by substituting the given answer options and solving for g(x):

For x = -2 and x = -4:

x = -2:

(-2)² + 8 = 12, which is not equal to 10 g(x) for any value of g(x).

So x = -2 is not a solution.

x = -4:

(-4)² + 8 = 24, which is also not equal to 10g(x) for any value of g(x).

So x = -4 is not a solution.

For x = -1 and x = 8:

x = -1:

(-1)² + 8 = 9, which is equal to 10g(x) when g(x) = 0.9.

So x = -1 is a solution.

x = 8:

(8)² + 8 = 72, which is equal to 10g(x) when g(x) = 7.2.

So x = 8 is a solution.

For x = 1 and x = -8:

x = 1:

(1)² + 8 = 9, which is equal to 10g(x) when g(x) = 0.9.

So x = 1 is a solution.

x = -8:

(-8)² + 8 = 56, which is not equal to 10g(x) for any value of g(x).

So x = -8 is not a solution.

Therefore,

The solutions to the given equation are x = -1 and x = 8.

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Answer:

1048

Step-by-step explanation:

53(20)- 12

1060 - 12

1048

hope this helps

Answer:

16/15 or 1  1/15

Step-by-step explanation:

4/5 divided by 3/4

Flip 3/4 so it is 4/3

Multiply 4/5 by 4/3

16/15

Answer:

$51.05

Step-by-step explanation:

the answer is $51.05

Answer:

wheres A

Step-by-step explanation:

Answer:

Step-by-step explanation:

If u = 6 then substitute so

6(6+6)=6 know solve but this isn't going to be correct because 6 plus 6 is 12 times 6 isn't 3

So your answer isn't correct. I think it would be a negative number or decimal because 6 is larger than 3. Hope this helps!

it is u(u+6)=3

I got u=6

In set 1, when we multiply two numbers with the same base, we can add the exponents. In set 2,  when we raise a number to a negative exponent, we can rewrite it as the reciprocal of the number raised to the positive exponent. In set 3, when we multiply two negative numbers with the same base, we can add the exponents.

In mathematics, a set is a well-defined collection of distinct objects or elements, which can be anything such as numbers, letters, people, animals, or even other sets. The objects in a set are called its members or elements, and they are listed inside curly brackets {}.

For example, the set of all positive even integers can be written as {2, 4, 6, 8, ...}, while the set of vowels in the English alphabet can be written as {a, e, i, o, u}. It is important to note that the order of elements in a set is not significant and each element can appear only once in a set.

Sets can be described by listing their elements explicitly, or by using set-builder notation, which describes the set in terms of a property that its members satisfy. For example, the set of all integers greater than 5 can be written as {n | n > 5}, which means "the set of all n such that n is greater than 5."

In Set 1, we notice that when we multiply two numbers with the same base, we can add the exponents. When we divide two numbers with the same base, we can subtract the exponents. We also notice that any number to the power of 0 is equal to 1.

In Set 2, we notice that when we raise a number to a negative exponent, we can rewrite it as the reciprocal of the number raised to the positive exponent. When we multiply two numbers with the same base, we can add the exponents. When we divide two numbers with the same base, we can subtract the exponents.

In Set 3, we notice that when we multiply two negative numbers with the same base, we can add the exponents. When we divide two negative numbers with the same base, we can subtract the exponents. We also notice that any negative number to an even power is positive, and any negative number to an odd power is negative. Finally, we notice that any number to the power of 0 is equal to 1.

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Set 1, when we multiply two numbers with the same base, we can add the exponents.

Set 2, when we raise a number to a negative exponent, we can rewrite it as the reciprocal of the number raised to the positive exponent.

Set 3, when we multiply two negative numbers with the same base, we can add the exponents.

In mathematics, a set is a well-defined collection of discrete objects or elements, which can be anything from numbers, letters, people, animals, or any other set. Objects in the set are called members or elements and are enclosed in curly braces {}.

For example, the set of all positive even integers can be written as {2, 4, 6, 8, ...}, while the set of vowels in the English alphabet can be written as {a, e, i, o, u. can be described. }. Note that the order of the elements in the set does not matter and each element appears only once in the set.

Set 1 tells us that when we multiply two numbers with the same base, we can add exponents. If you divide two numbers with the same base, you can subtract the exponent. Also note that all numbers to the power of 0 are equal to 1.

Note that in Set 2, if a number is raised to a negative power, it can be rewritten as the reciprocal of the number raised to a positive power. Multiplying two numbers in the same base allows you to add exponents. If you divide two numbers with the same base, you can subtract the exponent.

Set 3 tells us that if we multiply two negative numbers by the same base, we can add exponents. If you divide two negative numbers with the same base, you can subtract the exponent. Also note that all negative numbers are even positive and all negative numbers are odd high negative. Finally, remember that all numbers raised to the power of 0 are equal to 1.  

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Answer:

Tn=12n(n+1)

Step-by-step explanation:

Explanation:

These are the triangular numbers - each term in the sequence being the sum of the first n positive integers:

T1=1=1

T2=3=1+2

T3=6=1+2+3

etc.

Notice that:

2Tn=(0)+1+(0)+2+...+(n−1)+(0)+n

2Tn+(0)+n+(n−1)+...+(0)+2+(0)+1

2Tn=(n+1)+(n+1)+...+(n+1)+(n+1)

2Tn=n(n+1)

So:

Tn=12n(n+1)

Answer:

\(a_{n} = \frac{n^{2}}{2} +\frac{3n}{2} +1\)

hope this helps! <3

Okay so you put -6 in where y is then solve and youll get your answer

-8x-7(-6)=-6

Answer:

14 (insert less than or equal symbol)8x+6

Hope this helps! i hope the symbol is right!