-12 \(\geq\) 24x
divide both sides by 24
-0.5\(\geq\)x
Answer:
-0.5 ≥ x
Step-by-step explanation:
12 ≥ 24x. 12/24 ≥ 24/24x. -0.5 ≥ x
Find a polynomial function f(x) of degree 3 with zeros, 2, -3 , 5 and f(3)=6
A polynomial function f(x) of degree 3 with given zeros, 2, -3 , 5 and condition f(3)=6 is given by f(x) = -1/2 (x-2)(x+3)(x-5).
Degree of the polynomial function is equal to 3.
Zero's of the polynomial function is equal to 2, -3 , 5 .
And f(3) = 6
If 2, -3, and 5 are zeros of f(x), then we can write function as,
f(x) = a(x-2)(x+3)(x-5)
where a is some constant.
To determine the value of a, we can use the fact that f(3) = 6.
Substituting x = 3 into the equation above, we get,
f(3) = a(3-2)(3+3)(3-5)
= -12a
Here we have,
f(3) = 6, so we can set these two expressions equal to each other and solve for a,
⇒ -12a = 6
⇒ a = -1/2
Now we can substitute this value of a back into the equation for f(x) that we found earlier,
⇒ f(x) = -1/2 (x-2)(x+3)(x-5)
Therefore, a polynomial function f(x) of degree 3 with zeros 2, -3, 5, and f(3) = 6 is equal to f(x) = -1/2 (x-2)(x+3)(x-5).
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Sandra owns a rectangular pice of farmland that is 2/3 miles wide and has an area 5/9 square mile what is the leght of sandras farmalnd
Answer:
5/6 mile
Step-by-step explanation:
The formula for the area of a rectangle can be used with the given values to write an equation for the length of the farmland.
__
Here is the equation for the area of a rectangle.
A = LW . . . . . area is the product of length and width
When we fill in the area and width, we have ...
5/9 mi² = L(2/3 mi) . . . . . equation for the length of the farmland
Solving this equation gives ...
L = (5/9)/(2/3) mi . . . . . . . . divide by the coefficient of L
L = (5/9)/(6/9) mi = 5/6 mi . . . . . perform the division
The length of Sandra's farmland is 5/6 mile.
Perform the following mathematical operation, and report the answer to the appropriate number of significant figures.
1204.2 + 4.72613 = [?]
The answer is not 1208.92613 / 1200
Answer:
1,208.92613
Step-by-step explanation:
this is the answer
Question 4Mple Choice Worth 2 points)
Ares of Polygons and Composite Figures MC)
A composte figure is shown
024413
028.445²
1.15 in
Which of the following represents the total area of the figure?
010 663 ²
034.335 ²
4.6 in.
3h 563
P
The total area of the composite figure which has triangle and rectangle is 24.41 square inches
The given composite figure has two triangles and one rectangle
Area of rectangle =length × width
=4.6×3.15
=14.49 square inches
Area of left side triangle, it has base of 3.3 in and height 3.15 inches
Area of triangle = 1/2×3.3×3.15
=5.1975 square inches
Area of triangle on right side
Base = 3 in
Height = 6.3-3.15=3.15 in
Area of triangle = 1/2×3×3.15
=4.725 square inches
Total area = 14.49 + 5.1975 + 4.725
=24.41 square inches
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(4,-8)and(6,-9) written in point-slope form,slope-intercept form, and standard form
Answer:
Point slope- y + 8 = − 1 2 ⋅ ( x − 4 )
Slope Intercept Form- y = − 1/ 2 x − 6
Slope- m=-1/2
Step-by-step explanation:
Point slope- y-y₁=m(x-x₁)
Slope Intercept form- y=mx+b\
Slope- rise/run= y2-y1/x2-x1
The following data represent the pH of rain for a random sample of 12 rain dates. A normal probability plot suggests the data could come from a population that is normally distributed.
5.20, 5.02, 4.87, 5.72, 4.57, 4.76, 4.99, 4.74, 4.56, 4.80, 5.19, 4.68
1) Determine a point estimate for the population mean.
2) Construct and Interpret a 95% confidence interval for the mean pH of rainwater.
a) if repeated samoles are taken, 95% of them will have a sample pH of rain water between [ ] & [ ].
b) there is a 95% chance that the true mean pH of rain water is between [ ] & [ ].
c) there is 95% confidence that the population mean pH of rain water is between [ ] & [ ].
3) Construct and interpret a 99% confidence interval for the mean pH of rainwater.
a) there is 99% confidence that the population mean pH of rain water is between [ ] & [ ].
b) there is a 99% chance that the true mean pH of rain water is between [ ] & [ ].
c) if repeated samoles are taken, 99% of them will have a sample pH of rain water between [ ] & [ ].
4) What happens to the interval as the level of confidence is changed? Explain why is a logical result.
As the level of confidence increases l, the width of the interval_____this makes sense since the_____,______.
Answer:
(1) The point estimate for the population mean is 4.925.
(2) Therefore, a 95% confidence interval for the population mean pH of rainwater is [4.715, 5.135] .
(3) Therefore, a 99% confidence interval for the population mean pH of rainwater is [4.629, 5.221] .
(4) As the level of confidence increases, the width of the interval increases.
Step-by-step explanation:
We are given that the following data represent the pH of rain for a random sample of 12 rain dates.
X = 5.20, 5.02, 4.87, 5.72, 4.57, 4.76, 4.99, 4.74, 4.56, 4.80, 5.19, 4.68.
(1) The point estimate for the population mean is given by;
Point estimate, \(\bar X\) = \(\frac{\sum X}{n}\)
= \(\frac{5.20+5.02+ 4.87+5.72+ 4.57+ 4.76+4.99+ 4.74+ 4.56+ 4.80+5.19+ 4.68}{12}\)
= \(\frac{59.1}{12}\) = 4.925
(2) Let \(\mu\) = mean pH of rainwater
Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;
P.Q. = \(\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }\) ~ \(t_n_-_1\)
where, \(\bar X\) = sample mean = 4.925
s = sample standard deviation = 0.33
n = sample of rain dates = 12
\(\mu\) = population mean pH of rainwater
Here for constructing a 95% confidence interval we have used a One-sample t-test statistics as we don't know about population standard deviation.
So, 95% confidence interval for the population mean, \(\mu\) is ;
P(-2.201 < \(t_1_1\) < 2.201) = 0.95 {As the critical value of t at 11 degrees of
freedom are -2.201 & 2.201 with P = 2.5%}
P(-2.201 < \(\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }\) < 2.201) = 0.95
P( \(-2.201 \times {\frac{s}{\sqrt{n} } }\) < \({\bar X-\mu}\) < \(2.201 \times {\frac{s}{\sqrt{n} } }\) ) = 0.95
P( \(\bar X-2.201 \times {\frac{s}{\sqrt{n} } }\) < \(\mu\) < \(\bar X+2.201 \times {\frac{s}{\sqrt{n} } }\) ) = 0.95
95% confidence interval for \(\mu\) = [ \(\bar X-2.201 \times {\frac{s}{\sqrt{n} } }\) , \(\bar X+2.201 \times {\frac{s}{\sqrt{n} } }\) ]
= [ \(4.925-2.201 \times {\frac{0.33}{\sqrt{12} } }\) , \(4.925+2.201 \times {\frac{0.33}{\sqrt{12} } }\) ]
= [4.715, 5.135]
Therefore, a 95% confidence interval for the population mean pH of rainwater is [4.715, 5.135] .
The interpretation of the above confidence interval is that we are 95% confident that the population mean pH of rainwater is between 4.715 & 5.135.
(3) Now, 99% confidence interval for the population mean, \(\mu\) is ;
P(-3.106 < \(t_1_1\) < 3.106) = 0.99 {As the critical value of t at 11 degrees of
freedom are -3.106 & 3.106 with P = 0.5%}
P(-3.106 < \(\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }\) < 3.106) = 0.99
P( \(-3.106 \times {\frac{s}{\sqrt{n} } }\) < \({\bar X-\mu}\) < \(3.106 \times {\frac{s}{\sqrt{n} } }\) ) = 0.99
P( \(\bar X-3.106 \times {\frac{s}{\sqrt{n} } }\) < \(\mu\) < \(\bar X+3.106 \times {\frac{s}{\sqrt{n} } }\) ) = 0.99
99% confidence interval for \(\mu\) = [ \(\bar X-3.106 \times {\frac{s}{\sqrt{n} } }\) , \(\bar X+3.106 \times {\frac{s}{\sqrt{n} } }\) ]
= [ \(4.925-3.106 \times {\frac{0.33}{\sqrt{12} } }\) , \(4.925+3.106 \times {\frac{0.33}{\sqrt{12} } }\) ]
= [4.629, 5.221]
Therefore, a 99% confidence interval for the population mean pH of rainwater is [4.629, 5.221] .
The interpretation of the above confidence interval is that we are 99% confident that the population mean pH of rainwater is between 4.629 & 5.221.
(4) As the level of confidence increases, the width of the interval increases as we can see above that the 99% confidence interval is wider as compared to the 95% confidence interval.
How many solutions does this system have? no solutions one unique solution O O two solutions O or an infinite number of solutions
Answer:
no solutions
Step-by-step explanation:
the equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
equation of blue line is y = x + 2 , in slope- intercept form
with slope m = 1
equation of red line is y = x - 3 , in slope- intercept form
with slope m = 1
• Parallel lines have equal slopes
then the blue and red lines are parallel.
the solution to the system is at the point of intersection of the 2 lines
since the lines are parallel then they do not intersect each other.
thus the system shown has no solution.
Consider the line 3x+2y=-1.
Find the equation of the line that is perpendicular to this line and passes through the point (5, 3).
Find the equation of the line that is parallel to this line and passes through the point (5, 3).
Note that the ALEKS graphing calculator may be helpful in checking your answer.
Equation of perpendicular line:
Equation of parallel line:
0
help me fast rapidly is of khan academy:
Answer:
0 hundreds
0 tens
7 ones
.
4 tenths
0 hundredths
8 thousandths
Standard form=7.408
Step-by-step explanation:
Lets first solve (7x1)+(4x1/10)+(8x1/1000)
7+0.4+0.008
Simplify:
7.408
PLEASE MARK AS BRAINLIESTSolve the inequality for y 2.9 < 5.6+y simplify your answer as much as possible
Answer:
-2.7 < y
Step-by-step explanation:
2.9 < 5.6+y
Subtract 5.6 from each side
2.9-5.6 < 5.6-5.6+y
-2.7 < y
Tamara needs tiles to make a border for her bathroom wall.The border will be 9 ft long and 1/3 ft wide.Each tile measures 1/3 ft by 1/3 ft.Each box of tiles contains 6 tiles.How many boxes of tiles does Tamara need?
The number of tiles required is 27 tiles. Then the number of boxes of tiles that Tamara needs will be 5.
What is the area of the rectangle?Let W be the rectangle's width and L its length. Then the rectangle's area will be written as,
Area of the rectangle = L × W square units
The area of the border is given as,
A = 9 x (1/3)
A = 3 square feet
The area of each tile is given as,
a = (1/3) x (1/3)
a = 1 / 9
The number of tiles required is given as,
⇒ A/a
⇒ 9 / (1/3)
⇒ 9 x 3
⇒ 27
The number of boxes of tiles that Tamara needs is given as,
⇒ 27 / 6
⇒ 4.5 ≈ 5
The number of tiles required is 27 tiles. Then the number of boxes of tiles that Tamara needs will be 5.
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Select all side lengths that would form a right triangle.
6 inches, 9 inches, 12 inches
9 meters, 40 meters, 41 meters
9 yards. 12 yards, 15 yards
15 miles. 8 miles. 17 miles
53 inches, 28 inches, 45 inches
41 feet, 32 feet, 19 feet
The sides of a right triangle that would form a right triangle is 9 m, 40 m, 41 m. 9 yards. 12 yards, 15 yards and 15 miles. 8 miles. 17 miles
An equation is an expression that shows the relationship between two or more numbers and variables.
Pythagoras theorem states that for a right angled triangle, the sides of the triangle are related to each other using the expression:
(hypotenuse side)² = (adjacent side)² + (opposite side)²
The sides of a right triangle that would form a right triangle is 9 m, 40 m, 41 m, because:
41² = 40² + 9²
Also, 9 yards. 12 yards, 15 yards, because:
15² = 9² + 12²
15 miles. 8 miles. 17 miles, because
17² = 15² + 8²
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how many one third cup servings are in 16 cups
Which equation can be used to find 60 percent of 50
Answer:
x = 0.6 * 50
Step-by-step explanation:
x = 60% of 50
x = 60% * 50
x = 0.6 * 50
Answer:
60% of 50 = 60 / 100 × 50 = ⅗ × 50 = 150 / 5 = 30
________
x% of y = x / 100 × y = xy / 100
The number of water droplets in a specific body of water is 123,000,000,000,000. Write this number in scientific notation.
How did you get this answer?
Answer:
\(1.23 \times 10^{14}\)
Step-by-step explanation:
A number written in scientific notation consists of two parts that are multiplied.
The first part is a number that is greater than or equal to 1 and less than 10.
The second part is an integer power of 10.
Start with your number, 123,000,000,000,000.
All the zeros are place holders. To get a number out of it that is greater than or equal to 1 and less than 10, you move the decimal place to just to the right of the 1, like this: 1.23
Now you know very well that 1.23 is much, much smaller than the original number, but if you multiply it by a power of 10, you will get the original number.
To know the exponent of 10 you need to use, count the number of decimal places that the original number changed to become 1.23.
Original number: 123,000,000,000,000.
Notice the decimal place is all the way at the right after the last zero.
The new number is
1.23000000000000
How many places did the decimal place move? 14
Therefore, the answer is
\(1.23 \times 10^{14}\)
For many important processes that occur in the body, direct measurement of characteristics of the process is not possible. In many cases, however, we can measure a biomarker, a biochemical substance that is relatively easy to measure and is associated with the process of interest. Bone turnover is the net effect of two processes: the breaking down of old bone, called resorption, and the building of new bone, called formation. A biomarker for bone formation measured was osteocalcin (OC), measured in the blood. The units are nanograms per milliliter (ng/ml). For the 31 subjects in the study the mean was 33.4 ng/ml. Assume that the standard deviation is known to be 19.6 ng/ml.
Required:
Give the margin of error and find a 95% confidence interval for the mean TRAP amount in young women represented by this sample.
Answer:
The margin of error is \(E = 6.9 \)
The 95% confidence interval is \( 26.5 < \mu < 40.3 \)
Step-by-step explanation:
From the question we are told that
The sample size is n = 31
The mean is \(\mu = 33.4 \ ng/ml\)
The standard deviation is \(\sigma = 19.6 \ ng/ml\)
From the question we are told the confidence level is 95% , hence the level of significance is
\(\alpha = (100 - 95 ) \%\)
=> \(\alpha = 0.05\)
Generally from the normal distribution table the critical value of \(\frac{\alpha }{2}\) is
\(Z_{\frac{\alpha }{2} } = 1.96\)
Generally the margin of error is mathematically represented as
\(E = Z_{\frac{\alpha }{2} } * \frac{\sigma }{\sqrt{n} }\)
=> \(E = 1.96 * \frac{19.6 }{\sqrt{31 } }\)
=> \(E = 6.9 \)
Generally 95% confidence interval is mathematically represented as
\(\= x -E < \mu < \=x +E\)
=> \( 33.4 - 6.9 < \mu < 33.4 + 6.9 \)
=> \( 26.5 < \mu < 40.3 \)
Combine the like terms to create an equivalent expression 4p+6-3
Answer:
-3/4
Step-by-step explanation:
4p+6-3=0
4p+3=0
4p=-3
p= -3/4
In ΔEFG, e = 34 inches, f = 73 inches and g=89 inches. Find the area of ΔEFG to the nearest square inch.
Step-by-step explanation:
Heron's formula when all 3 sides (a, b, c) are given :
s = (a + b + c)/2
A = sqrt(s(s-a)(s-b)(s-c))
in our case
s = (34+73+89)/2 = 98
A = sqrt(98(98-34)(98-73)(98-89)) =
= sqrt(98×64×25×9) = sqrt(98)×8×5×3 =
= sqrt(2×49)×120 = sqrt(2)×7×120 =
= sqrt(2)×840 = 1,187.939392... ≈ 1,188 in²
4z (y+1); use y=3, and z=2
Circle A has a radius of 5in. what is the area?
Answer:
The area of a circle with a radius of 5 inches will be 78.54 inches.
Step-by-step explanation:
The formula to find the area of a circle is \(A=\pi r^{2}\)
We know that the radius is 5 inches. Let's plug that into the equation.
\(A=\pi\) × \(5^{2}\)
5 squared is the same as multiplying 5 by itself, which gives us 25. Our equation now looks like:
\(A=\pi\) × \(25\)
In this equation, we'll be rounding pi into 3.14
3.14 × 25 = 78.54
Here's your answer! I hope it's correct ^u^
Janet wants to purchase a new car. At the car dealership, a salesperson tells her she can choose from 10 car models, 7 exterior
colors, and 9 interior colors.
How many ways can Janet customize a car? Enter your answer as a whole number, like this: 425
evious
Janet has 630 options to customize a car based on the given features.
How to solve the question?
To determine the number of ways Janet can customize a car, we need to multiply the number of choices she has for each feature. Therefore, the total number of ways Janet can customize a car can be calculated as:
10 car models x 7 exterior colors x 9 interior colors = 630
Thus, Janet has 630 options to customize a car based on the given features.
It's worth noting that this calculation assumes that each feature (car model, exterior color, and interior color) can be combined with any other feature, without any restrictions or dependencies. However, in reality, certain car models may not be available in certain exterior or interior colors, or there may be other restrictions on the customization options.
Additionally, there may be other features that Janet can customize, such as the type of engine, transmission, or other options. Therefore, the total number of customization options may be even greater than what we have calculated here.
In summary, based on the given information, Janet has 630 ways to customize a car, but in reality, the actual number of options may be more limited or varied depending on other factors.
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Work out
m
and
c
for the line:
y
=
11
x
Answer: m=11
Step-by-step explanation:
5. A conical shaped pile of sand at the beach has a base circumference of 16.5 feet
and stands 10.4 feet high. The Department of Public Works is going to remove
75% of the sand. How much sand will be left in the pile after they remove 75% of
the sand?
Answer: 18.78 cubic feet
Step-by-step explanation:
The detailed analysis is attached below.
-0.75(12x+60) = -x-8x - 15.
Answer:
Step-by-step explanation:
-9x - 45 = -7x - 15 (Distribute -0.75 to (12x+60)) (x-8x = -7x)
-30 = 2x (add 15 to both sides and add 9x to both sides)
-15 = x (divide both sides by 2)
What is the maximum y?
Answer:
100/9 ≈ 11.11...(repeating)
Step-by-step explanation:
You want the maximum value of 0.3^x on the interval [-2, 2].
DecreasingThe base of 0.3 is less than 1, so you know the function is decreasing. The maximum value will be at the left end of the interval, where x = -2.
y = (0.3)^-2 = 1/0.09 = 100/9 ≈ 11.11...(repeating)
find the missing number that makes the sentence true
Answer:
2+5/9 is the answer
If you add 2 to 5/9, that makes the statement true
At a cinema a child's ticket costs £4.20 and an adult's ticket costs £7.70. When a group of adults and children went to see a film, the total cost was £, where is a whole number greater than 90 and less than 96. What is the value of ?
Answer:
Step-by-step explanation:
Let's use the following variables to solve the problem:
Let's call the number of adult tickets sold "a"
Let's call the number of child tickets sold "c"
Let's call the total cost "C" (in pounds)
From the problem statement, we know the following:
The cost of an adult ticket is £7.70
The cost of a child ticket is £4.20
The total cost of all the tickets sold is C
We can set up an equation based on this information:
C = 7.7a + 4.2c
We also know that the value of C is a whole number greater than 90 and less than 96. So we can write:
90 < C < 96
We need to find the value of C that satisfies both of these conditions. We can start by trying some values of a and c and seeing if they give us a value of C that satisfies the conditions. One way to do this is to use trial and error.
Let's start with a = 10 (meaning 10 adult tickets were sold). We can plug this into our equation and solve for c:
C = 7.7a + 4.2c
C = 7.7(10) + 4.2c
C = 77 + 4.2c
To satisfy the conditions, C must be greater than 90 and less than 96. Let's see if any value of c satisfies these conditions:
90 < C < 96
90 < 77 + 4.2c < 96
Subtract 77 from all parts of the inequality:
13 < 4.2c < 19
Divide all parts of the inequality by 4.2:
3.1 < c < 4.5
Since c must be a whole number, the only possible value is 4. But let's check if this value of c gives us a value of C that satisfies the conditions:
C = 77 + 4.2c
C = 77 + 4.2(4)
C = 94.8
This value of C is very close to 95, which satisfies both conditions (greater than 90 and less than 96). So the value of C is approximately £94.80.
_____________________Complete Question:At a cinema a child's ticket costs £4.20 and an adult's ticket costs
£7.70. When a group of adults and children went to see a film, the
total cost was £C, where C is a whole number greater than 90 and
less than 96.
What is the value of C?
I need help please and thank you!
A - The distribution of the data is symmetrical for both data sets
B - The median of the data is the same for both data sets
C - The mode of the data is the same for both data sets
D - The range of the data is the same for both data sets
Answer:
it should be answer C- the mode of the data is same for both data sets
NO LINKS!! Please help me with the Domain and Range and Functions Part 1bb
Domain - the set of possible x-coordinates of a function.
Range - the set of possible y-coordinates of a function.
Question 21Domain is:
x ∈ [- 4, 2], both ends included as part of the graph or closed circle..Range is:
y ∈ (-6, 6], the lowest point is excluded as open circle, the highest value is included as closed circle..This is not a function as it fails the vertical line test.
Question 22Domain is:
x ∈ [- 6, 2], both ends included as part of the graph.Range is:
y ∈ [-7, 7], both ends included as part of the graph.This is not a function as it fails the vertical line test.
Question 23Domain is:
x ∈ [ -2, 0], both ends included as closed circle or part of the graph.Range is:
y ∈ (-7, 5], the -7 is excluded as open circle, the 5 is included as closed circle.This is not a function as it fails the vertical line test.
Question 24Domain is:
x ∈ [- 6, 6), One end is included and the other end is excluded.Range is:
y ∈ [-7, 1], both ends included as closed circle or part of the graph.This is a function as it passes the vertical line test.
Use the given information to find the unknown value.
2. y varies
1. y varies directly as the square root
inversely with the cube of x.
of x. When x = 16, then y = 4. Find y
y = 1. Find y when x = 1.
when x = 36.
When x = 3, then
3. The distances that an object falls varies directly with the
square of the time, t, of the fall. If an object falls 16 feet in one
second, how long for it to fall 144 feet?
4. The rate of vibration of a string under constant tension varies
inversely with the length of the string. If a string is 24 inches long
and vibrates 128 times per second, what is the length of a string
that vibrates 64 times per second?
Applying the definition of variation, we have:
1. When x = 36, y = 6.
2. When x = 1, y = 27.
3. It takes 3 seconds for the object to fall 144 feet.
4. Length of a string that vibrates 64 times per second is 48 inches.
What is an Inverse Variation?Inverse variation is a type of relationship between two variables in which one variable increases while the other decreases, or vice versa, in a way that the product of the two variables remains constant.
In other words, if we have two variables x and y that are inversely proportional, we can write:
x × y = k, where k is a constant.
1. We are given that y varies directly as the square root of x. This means that we can write:
y = k√x
where k is a constant of proportionality. To find the value of k, we can use the given information that when x = 16, y = 4:
4 = k√16
4 = 4k
k = 1
Now we can use this value of k to find y when x = 36:
y = 1√36
y = 6
Therefore, when x = 36, y = 6.
2. We are given that y varies inversely with the cube of x. This means that we can write:
y = k/x³
where k is a constant of proportionality. To find the value of k, we can use the given information that when x = 3, y = 1:
1 = k/3³
1 = k/27
k = 27
Now we can use this value of k to find y when x = 1:
y = 27/1³
y = 27
Therefore, when x = 1, y = 27.
3. We are given that the distance that an object falls varies directly with the square of the time, t, of the fall. This means that we can write:
d = kt²
where d is the distance, k is a constant of proportionality, and t is the time. To find the value of k, we can use the given information that when t = 1, d = 16:
16 = k(1)²
16 = k
k = 16
Now we can use this value of k to find the time it takes for the object to fall 144 feet:
144 = 16t²
9 = t²
t = 3
Therefore, it takes 3 seconds for the object to fall 144 feet.
4. We are given that the rate of vibration of a string under constant tension varies inversely with the length of the string. This means that we can write:
r = k/L
where r is the rate of vibration, L is the length of the string, and k is a constant of proportionality.
To find the value of k, we can use the given information that when L = 24 inches, r = 128 vibrations per second:
128 = k/24
k = 3072
Now we can use this value of k to find the length of a string that vibrates 64 times per second:
64 = 3072/L
L = 48 inches
Therefore, the length of a string that vibrates 64 times per second is 48 inches.
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