The solution of the equation -9x + 1 = -x + 17 is option B. x = -2.
Given is an equation,
-9x + 1 = -x + 17
We have to find the value of x.
Adding x on both sides, we get,
-9x + x + 1 = 17
-8x + 1 = 17
Subtracting 1 from both sides, we get,
-8x = 16
Dividing both sides by -8,
x = -2
On solving, we get the value of x as -2.
Hence the value of x is -2.
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What would be the quantity demanded if a price ceiling is set at $200? 1.500 500 3.500 1,000 200
We cannot determine the quantity demanded if a price ceiling is set at $200, therefore, the answer is none of the options given in the question.
A price ceiling is a legal maximum amount for a good or service. A ceiling price means that a price is not allowed to be charged that is higher than the ceiling. Price ceilings are usually set by governments.
Therefore, if the price ceiling is set at $200, it means that the price of a product cannot be higher than $200.
The quantity demanded would depend on the price and the consumer's willingness to pay.
So, it cannot be determined by just knowing the price ceiling. Hence, we cannot determine the quantity demanded if a price ceiling is set at $200. We need additional information like demand curves, prices, and other factors that affect the demand for the product.
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find the area. please help
Answer:
36
8 times 9 equals 72 and then you just divide that by two and it would be 36
Ryan has 7 black pairs of socks, 3 pair of brown socks, and 8 white pairs of socks in his wardrobe. He randomly picks one pair. Find P(NOT Black) in fraction form
Answer:
Black socks pairs = 7
Brown socks pairs = 3
White socks pairs = 8
P(not black) = ?
First, you need to add the brown & white socks pairs,
\(3 + 8 = 11\)
Then you need to add the total number of socks pairs,
\(7 + 3 + 8 \\ = 7 + 11 \\ = 18\)
P(not black)
\( = \frac{11}{18} \)
Step-by-step explanation:
solution given:
total pair of socks[S]=(7+3+8)=18
total pair of black socks[B]=7
total pair of brown socks [C]=3
total pair of white socks[W]=8
total no of orange marbles[O]=2
now
the P( not black) =?
we have
P( not black) =1-\( \frac{n[B]}{n[S]} \)
P( not black) =1-\( \frac{7}{18} \)
P( not black) =\( \frac{18-7}{18} \)
P( not black) =\( \frac{11}{18} \)
so 11/18 is a required probabilty.
Solve the inequality
6(x/2+4)≥9
3x+24=9
3x=9-24
3x=-15
x=-5
1. 2. 4 journal:Algebraic Properties and expressions
The distributive property states that we can distribute a factor across a sum or difference, add or subtract like terms by adding or subtracting their coefficients and The power rule states that when raising a power to another power, we multiply the exponents. and Algebraic Properties explained as
Journal Entry 1:
Today, I learned about the algebraic properties of addition and multiplication. These properties are commutative, associative, and distributive. The commutative property states that the order in which we add or multiply numbers does not affect the result. For example, 2+3 is the same as 3+2, and 2x3 is the same as 3x2. The associative property states that we can group numbers in different ways without changing the result. For example, (2+3)+4 is the same as 2+(3+4), and (2x3)x4 is the same as 2x(3x4). The distributive property states that we can distribute a factor across a sum or difference. For example, 2x(3+4) is the same as 2x3 + 2x4.
Journal Entry 2:
Today, I learned about algebraic expressions and how to simplify them using the properties of addition and multiplication. An algebraic expression is a combination of numbers, variables, and operations. For example, 2x + 3y - 4z is an algebraic expression. To simplify an expression, we use the properties of addition and multiplication to combine like terms and simplify the expression as much as possible. Like terms are terms that have the same variables raised to the same powers. For example, 2x and 5x are like terms, but 2x and 5y are not. We can add or subtract like terms by adding or subtracting their coefficients. For example, 2x + 5x is 7x. We can also multiply terms by using the distributive property. For example, 2(3x + 4y) is 6x + 8y.
Journal Entry 3:
Today, I learned about algebraic expressions with exponents. An exponent is a small number written to the right of a base number that indicates how many times to multiply the base by itself. For example, in 2³, the base is 2 and the exponent is 3. To simplify an expression with exponents, we use the properties of exponents, such as the product rule and the power rule. The product rule states that when multiplying two powers with the same base, we add their exponents. For example, 2³ x 2² is 2^(3+2) or 2^5. The power rule states that when raising a power to another power, we multiply the exponents. For example, (2²)³ is 2^(2x3) or 2^6. We can also simplify expressions with exponents by combining like terms, just like we did with expressions without exponents.
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1.2.4Journal: Algebraic Properties and ExpressionsJournalAlgebra I Sem 1Name:Date:Scenario:The ArcadeInstructions:
•View the video found on page 1 of this journal activity
.•Using the information provided in the video, answer the questions below
.•Show your work for all calculation
Describe the error in solving the inequality or graphing the solution.
On the left side, the inequality should have been reversed.
The graph should have closed circles, not open circles.
On the right side, 8 should have been added to –2.
The graph should have opposite rays, not 1 segment.
Question 2
Correct the error.
The solution is
or
.
Answer:
d
Step-by-step explanation:
The value of x cannot be less than 5 and canot be greater than -10, so two different rays are required.
Question Four Consider the following production function: y = f(z)=z¼/^z/2. Assuming that the price of the output is p and the prices of inputs are w, and w₂ respectively: (a) State the firm's profit maximization problem. (2 marks). (b) Derive the firm's factor demand functions for z; and zo. (10 marks). (c) Derive the firm's supply function. (5 marks). = 2. (d) Derive the firm's profit function. (3 marks). an (e) Verify Hotelling's lemma for q(w, p), z₁(w, p) and z₂(w, p). (6 marks). az (f) State the firm's cost minimization problem. (2 marks), (g) Derive the firm's conditional factor demand functions. (8 marks). (h) Derive the firm's cost function. (4 marks). Cond: 69 Porat funct
The text discusses a production function and addresses various aspects of a firm's decision-making. It covers profit maximization, factor demand functions, supply function, profit function, Hotelling's lemma, cost minimization, conditional factor demand functions, and the cost function. These concepts are derived using mathematical calculations and formulas. Hotelling's lemma is verified, and the cost function is determined.
(a) The firm's profit maximization problem can be stated as follows: Maximize profits (π) by choosing the optimal levels of inputs (z and zo) that maximize the output (y) given the prices of output (p) and inputs (w, w₂).
(b) To derive the firm's factor demand functions, we need to find the conditions that maximize profits.
The first-order condition for input z is given by:
∂π/∂z = p * (∂f/∂z) - w = 0
Substituting the production function f(z) = z^(1/4) / z^(1/2) into the above equation, we have:
p * (1/4 * z^(-3/4) / z^(1/2)) - w = 0
Simplifying, we get:
p * (1/4 * z^(-7/4)) - w = 0
Solving for z, we find:
z = (4w/p)^(4/7)
Similarly, for input zo, the first-order condition is:
∂π/∂zo = p * (∂f/∂zo) - w₂ = 0
Substituting the production function f(zo) = z^(1/4) / z^(1/2) into the above equation, we have:
p * (1/2 * z^(1/4) * zo^(-3/2)) - w₂ = 0
Simplifying, we get:
p * (1/2 * z^(1/4) * zo^(-3/2)) - w₂ = 0
Solving for zo, we find:
zo = (2w₂ / (pz^(1/4)))^(2/3)
(c) To derive the firm's supply function, we need to find the level of output (y) that maximizes profits.
Using the production function f(z), we can express y as a function of z:
y = z^(1/4) / z^(1/2)
Given the factor demand functions for z and zo, we can substitute them into the production function to obtain the supply function for y:
y = (4w/p)^(4/7)^(1/4) / (4w/p)^(4/7)^(1/2)
Simplifying, we get:
y = (4w/p)^(1/7)
(d) The firm's profit function is given by:
π = p * y - w * z - w₂ * zo
Substituting the expressions for y, z, and zo derived earlier, we have:
π = p * ((4w/p)^(1/7)) - w * ((4w/p)^(4/7)) - w₂ * ((2w₂ / (pz^(1/4)))^(2/3))
(e) To verify Hotelling's lemma, we need to calculate the partial derivatives of the profit function with respect to the prices of output (p), input z (z₁), and input zo (z₂).
Hotelling's lemma states that the partial derivatives of the profit function with respect to the prices are equal to the respective factor demands:
∂π/∂p = y - z * (∂y/∂z) - zo * (∂y/∂zo) = 0
∂π/∂z₁ = -w + p * (∂y/∂z₁) = 0
∂π/∂z₂ = -w₂ + p * (∂y/∂z₂) = 0
By calculating these partial derivatives and equating them to zero, we can verify Hotelling's lemma.
(f) The firm's cost minimization problem can be stated as follows: Minimize the cost of production (C) given the level of output (y), prices of inputs (w, w₂), and factor demand functions for inputs (z, zo).
(g) To derive the firm's conditional factor demand functions, we need to find the conditions that minimize costs. We can express the cost function as follows:
C = w * z + w₂ * zo
Taking the derivative of the cost function with respect to z and setting it to zero, we get:
∂C/∂z = w - p * (∂y/∂z) = 0
Simplifying, we have:
w = p * (1/4 * z^(-3/4) / z^(1/2))
Solving for z, we find the conditional factor demand for z.
Similarly, taking the derivative of the cost function with respect to zo and setting it to zero, we get:
∂C/∂zo = w₂ - p * (∂y/∂zo) = 0
Simplifying, we have:
w₂ = p * (1/2 * z^(1/4) * zo^(-3/2))
Solving for zo, we find the conditional factor demand for zo.
(h) The firm's cost function is given by:
C = w * z + w₂ * zo
Substituting the expressions for z and zo derived earlier, we have:
C = w * ((4w/p)^(4/7)) + w₂ * ((2w₂ / (pz^(1/4)))^(2/3))
This represents the firm's cost function.
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One scientist involved in the study believes that large islands (those with areas greater than 25 square kilometers) are more effective than small islands (those with areas of no more than 25 square kilometers) for protecting at-risk species. The scientist noted that for this study, a total of 19 of the 208 species on the large island became extinct, whereas a total of 66 of the 299 species on the small island became extinct. Assume that the probability of extinction is the same for all at-risk species on large islands and the same for all at-risk species on small islands. Do these data support the scientist’s belief? Give appropriate statistical justification for your answer.
Yes, these data support the scientist's belief that large islands are more effective at protecting at-risk species than small islands. To provide statistical justification, we can compare the probability of extinction for each island size: For large islands, the probability of extinction is 19/208, or approximately 0.091. For small islands, the probability of extinction is 66/299, or approximately 0.221.
The data provided can support the scientist's belief that large islands are more effective than small islands for protecting at-risk species. We can use the concept of probability to calculate the likelihood of extinction for both large and small islands.
For the large island, the probability of extinction for any given species is 19/208 or approximately 0.091. For the small island, the probability of extinction for any given species is 66/299 or approximately 0.221.
Comparing these probabilities, we see that the probability of extinction is higher for at-risk species on small islands than on large islands. This supports the scientist's belief that large islands are more effective for protecting at-risk species.
Additionally, we can use statistical tests such as a chi-square test or a two-sample t-test to confirm whether the difference in extinction rates between large and small islands is statistically significant.
These tests would require more information such as sample size and variance, but based on the provided data alone, the probability calculations suggest that the scientist's belief is supported.
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REEEEEEEEEEEEEEEEEEEEEEEEEEEE
Answer:
im not writing all that lol
Step-by-step explanation:
So 1 would be 100%, 10/10 and 0 would be, 0/10 and 0% so for 50% for example would be 5/10, 0.5 and so on..
then just think of things that have a 100% chance and all the other percentages... example The sun rising tomorrow. and no chance 0% example the school flying away
22c4 +23c² simplified form
Answer: c^2(22c^2+23)
Step-by-step explanation:
Apply exponent rule : a^{b+c}=a^ba^c
=22c^2c^2+23c^2
Factor out common term c^2:
c^2(22c^2+23)
last month 15 homes were sold in town x. the average (arithmetic mean) sale price of the homes was $150,000 and the median sale price was $130,000. which of the following statements must be true? i. at least one of the homes was sold for more than $165,000. ii. at least one of the homes was sold for more than $130,000 and less than $150,000. iii. at least one of the homes was sold for less than $130,000.
Statement ii "at least one of the homes was sold for more than $130,000 and less than $150,000." must be true. Because Since the arithmetic mean sale price is $130,000, it means that half of the homes were sold for more than $130,000 and half were sold for less than $130,000. So, the correct option is Statement ii.
Since the arithmetic mean sale price is $150,000, it means that the total sale price of all 15 homes combined was $150,000 x 15 = $2,250,000. However, this does not necessarily mean that at least one of the homes was sold for more than $165,000, as some homes could have been sold for less than the mean to bring the average down. Therefore, statement i is not necessarily true.
On the other hand, statement iii is not necessarily true either, as we have no information about the sale price of the lowest-priced home or any other individual home. It is possible that all 15 homes were sold for more than $130,000, in which case statement iii would be false.
So, the correct answer is statement ii.
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PLEASE HELP!!!!! AS SOON AS POSSIBLE > WILL GIVE BRAINLY TO CORRECT ANSWER
Answer:
D
Step-by-step explanation:
Using Pythagoras' identity in the right triangle.
The square on the hypotenuse is equal to the sum of the squares on the other 2 sides, that is
a² + 12² = 13²
a² + 144 = 169 ( subtract 144 from both sides )
a² = 25 ( take the square root of both sides )
a = \(\sqrt{25}\) = 5 → D
The effect of pH on the action of a certain enzyme
is shown on the accompanying graph.
Rate of Enzyme Action
0 1 2 3 4 5 6 7 8 9 10 11 12 13
pH
What is the domain of this function?
1) 4
2) 4sys 13
3) 20
4 y20
Answer:
4 <(less than or Equal to) y (less than or Equal to) 13
Step-by-step explanation:
1 divided by 3 x a = -5
What's the variable?
Answer:
1 Is the Variable
Step-by-step explanation:
now say you sample 10 independent customers. what is the probability that less than or equal to 5 (five) of them will take more than 3 minutes to check out their groceries? round to the nearest hundredths/second decimal place,
The probability that less than or equal to 5 of the 10 independent customers will take more than 3 minutes to check out their groceries is approximately 0.9245.
To calculate this probability, we can use the binomial probability formula. Let's denote X as the number of customers taking more than 3 minutes to check out. We want to find P(X ≤ 5) when n = 10 (number of trials) and p (probability of success) is not given explicitly.
Step 1: Determine the probability of success (p).
Since the probability of each customer taking more than 3 minutes is not provided, we need to make an assumption or use historical data. Let's assume that the probability of a customer taking more than 3 minutes is 0.2.
Step 2: Calculate the probability of X ≤ 5.
Using the binomial probability formula, we can calculate the cumulative probability:
P(X ≤ 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5)
P(X ≤ 5) = C(10, 0) * p^0 * (1 - p)^(10 - 0) + C(10, 1) * p^1 * (1 - p)^(10 - 1) + C(10, 2) * p^2 * (1 - p)^(10 - 2) + C(10, 3) * p^3 * (1 - p)^(10 - 3) + C(10, 4) * p^4 * (1 - p)^(10 - 4) + C(10, 5) * p^5 * (1 - p)^(10 - 5)
Substituting p = 0.2 into the formula and performing the calculations:
P(X ≤ 5) ≈ 0.1074 + 0.2686 + 0.3020 + 0.2013 + 0.0889 + 0.0246
P(X ≤ 5) ≈ 0.9928
Rounding this probability to the nearest hundredth/second decimal place, we get approximately 0.99. However, the question asks for the probability that less than or equal to 5 customers take more than 3 minutes, so we subtract the probability of all 10 customers taking more than 3 minutes from 1:
P(X ≤ 5) = 1 - P(X = 10)
P(X ≤ 5) ≈ 1 - 0.9928
P(X ≤ 5) ≈ 0.0072
Therefore, the probability that less than or equal to 5 customers out of 10 will take more than 3 minutes to check out their groceries is approximately 0.0072 or 0.72%.
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Formal proof organized by statements and reasons in logical order of
statements with reasons using theorems, properties or definitions for each
statement.
The number of students at the start of the week that had a late library book was 200 students. By the end of the week there were only 80 students with a late library book? Is it a increase or decrease in by what percentage? 
On solving the provided question, we can say that - so, percentage - 400/500 X 100 = 80%
What is percentage?A percentage in mathematics is a figure or ratio that is stated as a fraction of 100. The abbreviations "pct.," "pct," and "pc" are also occasionally used. It is frequently denoted using the percent symbol "%," though. The amount of percentages has no dimensions. With a denominator of 100, percentages are basically fractions. To show that a number is a percentage, place a percent symbol (%) next to it. For instance, if you correctly answer 75 out of 100 questions on a test (75/100), you receive a 75%. To compute percentages, divide the amount by the total and multiply the result by 100. The percentage is calculated using the formula (value/total) x 100%.
here,
total is 500
obtained is 400
so, percentage - 400/500 X 100 = 80%
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find the missing number 9:4::63: ?
Answer: 28
Step-by-step explanation:
28 is thhe missing number
grantly is creating a design for a sitting room off his client's master bedroom. he plans to use a few chairs, an end table, and some rugs to create a cozy space. how close should grantly place the chairs?
Grantly must place the chairs close enough so that people can easily speak with one another
Grantly is designing a sitting area that will be located outside of his client's master bedroom. He intends to furnish the area with a few rugs, an end table, and chairs. The seats should be spaced apart just enough to allow for easy conversation while seated, but not too much that it seems crowded. For easy access, end table should be positioned close to the seats. The placement of rugs should be such that they both define seating area and add to overall attractiveness of the space.
To make sure that chairs, end table, and rugs fit properly without giving area a claustrophobic feeling, Grantly should take measurements of the available space in the sitting room. He should also consider how the master bedroom is organised as well as any existing furnishings or fixtures that could have an impact on how the sitting room furniture is arranged. Additionally, seating should be set up so that conversing with one another while seated is simple. Conversation can be facilitated and a cosy environment can be created by positioning chairs in a circula configuration, facing one another.
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helppppppp meeee plsssssWhich construction could this be?Inscribed SquareInscribed HexagonInscribed RectangleInscribed Octagon
1) Judging by the picture, which resembles a construction done with a compass with the same distance, therefore we can tell a regular polygon.
2) We can also trace some line segments then we'll have a:
\(Inscribed\:Hexagon\)
Consider the function f(x,y) = 8x3 + y3 - 6xy + 2 a.) Find the critical points of the function. b.) Use the Second Derivative Test to classify each critical point as a local maximum, local minimum, or a saddle point.
The critical points are (0, 0) and (1/2, 1/8).
To find the critical points of the function f(x, y) = 8x^3 + y^3 - 6xy + 2, we need to find the points where the partial derivatives of f with respect to x and y are equal to zero.
a.) Finding the critical points:
∂f/∂x = 24x^2 - 6y = 0
∂f/∂y = 3y^2 - 6x = 0
From the first equation, we have:
24x^2 - 6y = 0
4x^2 - y = 0
y = 4x^2
Substituting y = 4x^2 into the second equation:
3(4x^2)^2 - 6x = 0
48x^4 - 6x = 0
6x(8x^3 - 1) = 0
This gives two possible cases:
6x = 0, which implies x = 0.
8x^3 - 1 = 0, which implies 8x^3 = 1 and x^3 = 1/8. Solving this equation, we find x = 1/2.
For x = 0, we can substitute it back into y = 4x^2 to find y = 0.
So, the critical points are (0, 0) and (1/2, 1/8).
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AABC is reflected across the x-axis and then translated 4 units up to create AA'BC. What are the coordinates of the vertices of AABC?
OA A'(-3, 3), B(-1, 1). C(-2.3)
ОВ.
A'(3.-3), B(1,-1), C(2.-3)
OC. A'(3.-5), B(1, -7), C(3.-5)
OD. A'(-3, 3), B(-1, 1), C(-2,-
Answer:
A
Step-by-step explanation:
Under a reflection in the x- axis
a point (x, y ) → (x, - y ) , then
A(- 3, 1 ) → (- 3, - 1 )
B(- 1, 3 ) → (- 1, - 3 )
C(- 2, 1 ) → (- 2, - 1 )
A translation of 4 units up means adding 4 to the y- coordinate
( - 3, - 1 ) → A' (- 3, - 1 + 4 ) → A' (- 3, 3 )
(- 1, - 3 ) →B' (- 1, - 3 + 4 ) → B' (- 1, 1 )
(- 2, - 1 ) → C' (- 2, - 1 + 4 ) → C' (- 2, 3 )
the baker family goes out for supper and the price of the meal is $58. the sales tax on the meal is 6.5% and the family leaves a 20% tip on the pre- tax amount. what is the total cost of the meal?
Answer:
$73.37 is the new price.
Step-by-step explanation:
0.065 x 58 = 3.77
0.2 x 58 = 11.6
3.77 + 11.6 = 15.37
15.37 + 58 = 73.37
Let an = 5n/4n + 1 Determine whether {an) is convergent. convergent divergent
To determine whether the sequence {an} = 5n/4n + 1 is convergent or divergent, we can analyze its behavior as n approaches infinity.
First, let's rewrite the expression for the nth term of the sequence:
an = 5n / (4n + 1)
As n approaches infinity, the denominator 4n + 1 becomes dominant compared to the numerator 5n. Therefore, we can simplify the expression by neglecting the term 5n:
an ≈ n / (4n + 1)
Now, we can consider the limit of the sequence as n approaches infinity:
lim(n→∞) n / (4n + 1)
To evaluate this limit, we can divide both the numerator and denominator by n:
lim(n→∞) (1 / 4 + 1/n)
As n approaches infinity, the term 1/n approaches zero, leaving us with:
lim(n→∞) 1 / 4 = 1/4
Since the limit of the sequence is a finite value (1/4), we can conclude that the sequence {an} = 5n/4n + 1 is convergent.
In other words, as n gets larger and larger, the terms of the sequence {an} get closer and closer to the limit of 1/4. This indicates that the sequence approaches a fixed value and does not exhibit wild oscillations or diverge to infinity. Therefore, we can say that the sequence is convergent.
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Find the perimeter of the following shape, rounded to the nearest tenth: coordinate plane with quadrilateral ABCD at A 0 comma 0, B 5 comma negative 1, C 3 comma negative 5, and D negative 2 comma negative 4 19.1 20.39 22.8 24.4
The perimeter of a figure is the sum of the lengths of the sides used to make the given figure. The perimeter of the shape ABCD is 19.1(5.099+4.4721+5.099+4.4721).
What is the perimeter?The perimeter of a figure is the sum of the lengths of the sides used to make the given figure.
The perimeter of the shape can be found by finding the length of the different sides, therefore,
\(AB = \sqrt{(5-0)^2+(-1-0)^2} = \sqrt{26} = 5.099\)
\(BC = \sqrt{(3-5)^2+(-5+1)^2} = \sqrt{20} = 4.4721\)
\(CD = \sqrt{(-2-3)^2+(-4+5)^2} = \sqrt{26} = 5.099\)
\(AD=\sqrt{(-2-0)^2+(-4-0)}=\sqrt{20} = 4.4721\)
Hence, the perimeter of the shape ABCD is 19.1(5.099+4.4721+5.099+4.4721).
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Luanne is filling bag with bouncy balls and candy. A package of candy has 88 pieces, and the bouncy balls are in a package of 56. She wants an equal amount of each item in a bag. What is the greatest number of each item that will go in each bag?
Answer choices:
2
4
8
11
Answer:
kk
Step-by-step explanation:
kk
You are given two functions, f: RR, f (x) = 3x and g:R+R, 9(r) = x+1 a. Find and record the function created by the composition of f and g, denoted gof. b. Prove that your recorded function of step (a.) is both one-to-one and onto. That is prove, gof:R R; (gof)(x) = g(f (r)). is well-defined where indicates go f is a bijection. For full credit you must explicitly prove that go f is both one-to-one and onto, using the definitions of one-to-one and onto in your proof. Do not appeal to theorems. You must give your proof line-by-line, with each line a statement with its justification. You must show explicit, formal start and termination statements as shown in lecture examples. You can use the Canvas math editor or write your math statements in English. For example, the statement to be proved was written in the Canvas math editor. In English it would be: Prove that the composition of functions fand g is both one-to-one and onto.
a) The function gof is gof(x) = 3x + 3.
b) The function gof: RR is well-defined.
a. The value of function gof(x) = 3x + 3.
To find the composition gof, we substitute the expression for g into f:
gof(x) = f(g(x))
= f(x + 1)
= 3(x + 1)
= 3x + 3
b. To prove that gof is both one-to-one and onto, we need to show the following:
(i) One-to-one: For any two different inputs x1 and x2, if gof(x1) = gof(x2), then x1 = x2.
(ii) Onto: For every y in the range of gof, there exists an x such that gof(x) = y.
Proof of one-to-one:
Let x1 and x2 be two different inputs. Assume that gof(x1) = gof(x2).
Then, 3x1 + 3 = 3x2 + 3.
Subtracting 3 from both sides, we have 3x1 = 3x2.
Dividing both sides by 3, we obtain x1 = x2.
Therefore, gof is one-to-one.
Proof of onto:
Let y be any real number in the range of gof, which is the set of all real numbers.
We need to find an x such that gof(x) = y.
Consider the equation 3x + 3 = y.
Subtracting 3 from both sides, we have 3x = y - 3.
Dividing both sides by 3, we obtain x = (y - 3)/3.
Thus, for any y in the range of gof, we can find an x such that gof(x) = y.
Therefore, gof is onto.
Since gof is both one-to-one and onto, it is a bijection.
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Need Help on math question
Answer:
36 yards
Step-by-step explanation:
The triangle is a 3-4-5 right triangle with a scaling factor of 12. No complicated Pythagorean theorem has to be used in this case.
60/12 = 5
48/12 = 4
3 is the only base number remaining.
3(12) =36
whats the answer giving brainliest
Answer:
A is ...................
Answer:
A
Step-by-step explanation:
what times 85 dives you 2790
Answer:
34.875
Step-by-step explanation: