Solve the equation on the interval [0,2π). 7 sec x-7=0, x=?

Let's assume that the corresponding side of the second triangle is \(\displaystyle\sf x\).

The ratio of the areas of two similar triangles is equal to the square of the ratio of their corresponding sides. Therefore, we can set up the following proportion:

\(\displaystyle\sf \left( \dfrac{x}{6.3} \right)^{2} =\dfrac{49}{81}\)

To find \(\displaystyle\sf x\), we can solve the proportion above:

\(\displaystyle\sf \left( \dfrac{x}{6.3} \right)^{2} =\dfrac{49}{81}\)

Taking the square root of both sides:

\(\displaystyle\sf \dfrac{x}{6.3} =\sqrt{\dfrac{49}{81}}\)

Simplifying the square root:

\(\displaystyle\sf \dfrac{x}{6.3} =\dfrac{7}{9}\)

Cross-multiplying:

\(\displaystyle\sf 9x = 6.3 \times 7\)

Dividing both sides by 9:

\(\displaystyle\sf x = \dfrac{6.3 \times 7}{9}\)

Calculating the value:

\(\displaystyle\sf x = 4.9\)

Therefore, the corresponding side of the second triangle is \(\displaystyle\sf 4.9 \, cm\).

\(\huge{\mathfrak{\colorbox{black}{\textcolor{lime}{I\:hope\:this\:helps\:!\:\:}}}}\)

♥️ \(\large{\underline{\textcolor{red}{\mathcal{SUMIT\:\:ROY\:\:(:\:\:}}}}\)

Answer:

Step-by-step explanation:

let's assume that the corresponding side of the second triangle is .

The ratio of the areas of two similar triangles is equal to the square of the ratio of their corresponding sides. Therefore, we can set up the following proportion:

To find , we can solve the proportion above:

Taking the square root of both sides:

Simplifying the square root:

Cross-multiplying:

Dividing both sides by 9:

Calculating the value:

Therefore, the corresponding side of the second triangle is 4.9cm


hope it helped u dear...........

Answer:

b because you sub the 2 numbers i think

Answer:

Yes

Step-by-step explanation:

125 grams is 0.125 kilograms, 0.125 < 0.2

Answer:

y = x + 1

Step-by-step explanation:

Parallel lines have same slope.

y = x - 1

Compare with the equation of line in slope y-intercept form: y = mx +b

Here, m is the slope and b is the y-intercept.

m =1

Now, the equation is,

         y = x + b

The required line passes through (-3 ,-2). Substitute in the above equation and find y-intercept,

        -2 = -3 + b

  -2 + 3 = b

         \(\boxed{b= 1}\)

    Equation of line in slope-intercept form:

                  \(\boxed{\bf y = x + 1}\)      

The equation is :

Solution:

If two lines are parallel to each other, then their slopes are equal. The slope of y = x - 1 is 1. Hence, the slope of the line that is parallel to that line is 1.

We shouldn't forget about a point on the line : (-3, -2).

I plug that into a point-slope which is :

\(\sf{y-y_1=m(x-x_1)}\)

Slope is 1 so

\(\sf{y-y_1=1(x-x_1)}\)

Simplify

\(\sf{y-y_1=x-x_1}\)

Now I plug in the other numbers.

-3 and -2 are x and y, respectively.

\(\sf{y-(-2)=x-(-3)}\)

Simplify

\(\sf{y+2=x+3}\)

We're almost there, the objective is to have an equation in y = mx + b form.

So now I subtract 2 from each side

\(\sf{y=x+1}\)

Answer:

(2,1)

Step-by-step explanation:

The line 4y - 2x = 0 can be written in slope-intercept form as y = 1/2x.

So any point that satisfies this equation will lie on the line. For example, the point (2,1) satisfies the equation:

4(1) - 2(2) = 0

So the point (2,1) is on the line.

Answer:

cscsc

Step-by-step explanation:

zcscc

Answer:

hehehehehehehehehehehehehehehehehehehehehehehehe

Step-by-step explanation:

lelelelelelelelelelelelelelelelelelelelelelelelelelelelelelelelelelele

Chicken Nuggets.

Ending Inventory Cost and Cost of Goods Sold using different inventory methods:

FIFO Method:

Ending Inventory Cost: $11,920

Cost of Goods Sold: $15,068

LIFO Method:

Ending Inventory Cost: $11,996

Cost of Goods Sold: $15,123

Weighted Average Cost Method:

Ending Inventory Cost: $11,974

Cost of Goods Sold: $15,087

Using the FIFO (First-In, First-Out) method, the cost of the ending inventory is determined by assuming that the oldest units (those acquired first) are sold last. In this case, the cost of the ending inventory is calculated by taking the cost of the most recent purchases (70 units at $142 per unit) plus the cost of the remaining 10 units from the March 10 purchase.

This totals to $11,920. The cost of goods sold is calculated by taking the cost of the units sold (50 units from the Jan. 1 inventory at $124 per unit, 60 units from the March 10 purchase at $132 per unit, and 20 units from the August 30 purchase at $138 per unit), which totals to $15,068.

Using the LIFO (Last-In, First-Out) method, the cost of the ending inventory is determined by assuming that the most recent units (those acquired last) are sold first. In this case, the cost of the ending inventory is calculated by taking the cost of the remaining 10 units from the December 12 purchase, which amounts to $1,420, plus the cost of the 70 units from the August 30 purchase, which amounts to $10,576.

This totals to $11,996. The cost of goods sold is calculated by taking the cost of the units sold (50 units from the Jan. 1 inventory, 60 units from the March 10 purchase, and 20 units from the August 30 purchase), which totals to $15,123.

Using the Weighted Average Cost method, the cost of the ending inventory is determined by calculating the weighted average cost per unit based on all the purchases. In this case, the total cost of all the purchases is $46,360, and the total number of units is 200.

Therefore, the weighted average cost per unit is $231.80. Multiplying this by the 80 units in the physical inventory at December 31 gives a total cost of $11,974 for the ending inventory. The cost of goods sold is calculated by taking the cost of the units sold (50 units from the Jan. 1 inventory, 60 units from the March 10 purchase, and 20 units from the August 30 purchase), which totals to $15,087.

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The least common multiple of 598 and 45 is 26, 910

To find the least common multiple of 598 and 45, you can use the prime factorization method. This involves finding the prime factors of both 598 and 45 and then multiplying these prime factors when they are in their highest power.

This gives:

598 prime factorization :

2 x 13 x 23 = 598

45 prime factorization :

3 x 3 x 5 = 45

The least common multiple is;

= 2 x 13 x 23 x 3 x 3 x 5

= 26, 910

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Answer:

C

Step-by-step explanation:

Answer:

It is c / 40 square meters

Step-by-step explanation:

I took the test

Therefore, the solutions to the quadratic equation x² + 7x - 8 = 0 are -8 and 1. The answers are D and E.

An equation is a mathematical statement that shows that two expressions are equal. It typically consists of variables, constants, and mathematical operations. Equations can be solved by manipulating the expressions to find the value of the variables that satisfy the equation. Equations can be used to model real-world situations, and they are an important tool in many fields, including mathematics, physics, engineering, and economics.

Here,

To check which values are solutions to the quadratic equation, we can substitute each value into the equation and see if it equals zero.

Substituting -1 into the equation:

(-1)² + 7(-1) - 8 = 1 - 7 - 8 = -14, which is not equal to zero.

Substituting 2 into the equation:

2² + 7(2) - 8 = 4 + 14 - 8 = 10, which is not equal to zero.

Substituting -4 into the equation:

(-4)² + 7(-4) - 8 = 16 - 28 - 8 = -20, which is not equal to zero.

Substituting -8 into the equation:

(-8)² + 7(-8) - 8 = 64 - 56 - 8 = 0, which is equal to zero. Therefore, -8 is a solution to the equation.

Substituting 1 into the equation:

1² + 7(1) - 8 = 1 + 7 - 8 = 0, which is equal to zero. Therefore, 1 is a solution to the equation.

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Yes, Timothy is correct because triangle AKLM was dilated by using a scale factor of 1.5 centered at the origin.

In Mathematics, dilation can be defined as a type of transformation that is typically used for enlarging or reducing the size of a geometric object but not its shape, based on the scale factor.

For the given coordinates of the preimage triangle KLM, the dilation with a scale factor of 1.5 from the origin (0, 0) would be calculated as follows:

Coordinate K (-1, 3) → Coordinate K' (-1 × 1.5, 3 × 1.5) = Coordinate K' (-1.5, 4.5).

Coordinate L (8, 4) → Coordinate L' (8 × 1.5, 4 × 1.5) = Coordinate L' (12, 6).

Coordinate M (10, -3) → Coordinate M' (10 × 1.5, -3 × 1.5) = Coordinate M' (15, -4.5).

In conclusion, the coordinates of the image triangle K'L'M after a dilation with a scale factor of 1.5 from the origin are (-1.5, 4.5), (12, 6), and (15, -4.5) as shown in the graph above, therefore, Timothy is correct.

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Answer:

\(r=-3/5=-0.6\)

Step-by-step explanation:

We have the equation:

\(6^{-3r}=6^{2r+3}\)

Since their bases are the same, the exponents must be equivalent. So:

\(-3r=2r+3\)

Solve for r, subtract 2r from both sides:

\(-5r=3\)

Divide both sides by -5:

\(r=-3/5=-0.6\)

So, the value of r is -3/5.

And we're done!

Answer:

64 miles per hour.

Step-by-step explanation:

we are asked to look for the velocity of this car. to find it, we use the equation \(velocity = \frac{distance}{time}\). we substitute the given to the equation:

\(velocity = \frac{224 m}{3.5 hr}\)

velocity = 64 miles per hour

\(\huge\fbox{Answer ☘}\)

\(\bold{3( \frac{27}{8} ) {}^{ \frac{2}{3} \times - 1} = 2( \frac{32}{243} ) {}^{2x} }\\ \\3(( \frac{3}{2} ) {}^{3} ) {}^{ \frac{2}{3} \times - 1 } = 2(( \frac{2}{3} ) {}^{5} ) {}^{2x} \\\\ 3( \frac{3}{2} ) {}^{2 \times - 1} = 2( \frac{2}{3} ) {}^{10x} \\\\ 3( \frac{2}{3} ) {}^{2} = 2( \frac{2}{3} ) {}^{10x} \\\\

3( \frac{4}{9} ) = 2( \frac{4}{9} ) {}^{5x} \\\\\bold\pink{ comparing \: powers }\\\\5x = 1 \\\\ \bold\blue{x = \frac{1}{5} } \)

hope helpful~

In order to compare the figures and find the one that is not like the others, let's compare the proportion of their width and height:

We can see that figure C has a different proportion, therefore figure C is the one that is not like the others.

Step-by-step explanation:

21x²-2x +1/2 = 0

x² - 2x ×21 + 1/2× 21 = 0

The linear relationship illustrated in the provided table can be effectively described by the equation Y = -4x + 2. Option D.

To determine the equation that represents the given table with the values of x and y, we can observe the pattern and find the equation of the line that fits these points.

Given the table:

X: 2 0 4

Y: -4 3 1

We can plot these points on a graph and see that they form a straight line.

Plotting the points (2, -4), (0, 3), and (4, 1), we can see that they lie on a line that has a negative slope.

Based on the given options, we can now evaluate each equation to see which one represents the line:

Y = 1/2x + 5

When we substitute the x-values from the table into this equation, we get the following corresponding y-values: -3, 5, and 6. These values do not match the given table, so this equation does not represent the table.

Y = -1/2x + 3

When we substitute the x-values from the table into this equation, we get the corresponding y-values: 4, 3, and 2. These values also do not match the given table, so this equation does not represent the table.

Y = 2x - 3

When we substitute the x-values from the table into this equation, we get the corresponding y-values: -4, -3, and 5. These values do not match the given table, so this equation does not represent the table.

Y = -4x + 2

When we substitute the x-values from the table into this equation, we get the corresponding y-values: -6, 2, and -14. Interestingly, these values match the y-values in the given table. Therefore, the equation Y = -4x + 2 represents the table.

In conclusion, the equation Y = -4x + 2 represents the linear relationship described by the given table. So Option D is correct.

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Given data:

The given discount is D=25%.

The original cost of tablet is T=$499.

The expression for the final amount is,

A=(100%-D)(T)

Substitute the given values in the above expression.

A=(100%-25%)($499)

=(75%)(499)

=(0.75)(499)

=$374.25

Thus, the finl price to be paid is $374.25.

Yes, A circle could be circumscribed about the quadrilateral below.

A circle is a closed two-dimensional figure in which the set of all the points in the plane is equidistant from a given point called “centre”. The perimeter around the circle is known as the circumference.

here, we have,

A circle can be circumscribed around the four vertices of a quadrilateral

if and only if,

both pair of opposite angles inscribed in the quadrilateral are supplementary to each other.

By supplementary to each other we mean that their sum is equal to 180°.

we have,

In this case we have opposite interior angles supplementary to each other hence we can circumscribe a circle around it.

Such Quadrilateral are called cyclic quadrilateral.

Hence, Yes, A circle could be circumscribed about the quadrilateral below.

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The scatter plot shows a [positive linear] association.

From the question, we have the following parameters that can be used in our computation:

The image of the scatter plot

On the scatter plot, we can see that

The points appear to be on a straight line

Also, we can see that

As the x values increases the y values increases

This represents a positive linear association.

Hence, the association is a positive linear association.

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Answer:

x=1 maybe ,but I am not sure for this answer.

Answer: It's X = 4

Step-by-step explanation:

I just took the test and got x = 1 wrong

The domain of the quadratic function in this problem is given as follows:

All real values.

The domain of a function is the set of all the possible input values that can be assumed by the function.

On the graph, the domain of the function is given by the values of x of the function.

A quadratic function has no restrictions on the domain, hence it is defined by all the real values.

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The y-intercept of a function is the value of y when x = 0, which is represented as the value of b in the slope-intercept equation y = mx + b. b is the y-intercept.

If an equation of graph that represents a function is given in slope-intercept form as y = mx + b, the value of b in the function is the value of the y-intercept of the y-intercept.

The y-intercept of the function is the same as the value of y when the value of x is 0, or the point where the line of the function intercepts the y-axis on a given graph that represents the function.

For example, if we are given the equation of a graph that represents a function as, y = 3x + 4, the y-intercept of the function would be 4.

In summary, the y-intercept of the function is the value of b in the equation of the function that is expressed as y = mx + b in slope-intercept form.

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Answer:

B

Step-by-step explanation:

Answer:

D. Because the same answer

Step-by-step explanation:

Answer:

yes-

Step-by-step explanation:

im not to sure if its right but

7+7=14

12+12=24

Answer:

Step-by-step explanation:

sum of angles in a triangle=180º

90+60x+30x=180

90+90x=180

90(1+x)=180

1+x=2

x=1

angle A=30º

Let us begin by defining important terms:

A rectangular equation, or an equation in rectangular form is an equation composed of variables like x and y which can be graphed on a regular Cartesian plane. For example y=4x+3 is a rectangular equation.

A curve in the plane is said to be parameterized if the set of coordinates on the curve, (x,y) , are represented as functions of a variable t .

x=f(t)

y=g(t)

Given:

The rectangular equation is defined as:

If y = t -5

The parametric equation for x is obtained by substitution:

Hence, the parametric equation for x is: