solve pls brainliest

 The 27th term of the sequence is –8..The seventh term of the arithmetic sequence is 19.

To find the 27th term of the sequence given by the formula = –4 + 100, we can substitute = 27 into the formula:

27 = –4(27) + 100

27 = –108 + 100

27 = –8

Therefore, the 27th term of the sequence is –8.

Now, let's find 7, the seventh term of an arithmetic sequence when the first two terms are 7 and 9.

We know that the common difference between consecutive terms in an arithmetic sequence remains constant. Let's denote the common difference as .

The formula to find the -th term of an arithmetic sequence is:

= 1 + ( – 1)

We are given that 1 = 7 and 2 = 9. Substituting these values into the formula, we get:

7 = 1 + (1 – 1)

9 = 1 + (2 – 1)

Simplifying the equations, we have:

7 = 1

9 = 1 +

From the first equation, we know that 1 = 7. Substituting this value into the second equation, we can solve for :

9 = 7 +

= 9 – 7

= 2

So, the common difference is 2.

Now we can find 7 using the formula:

7 = 1 + (7 – 1)

7 = 7 + (6)2

7 = 7 + 12

7 = 19

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The margin of error is 0.0348 and we can say, with 90% confidence, that the difference between the percentage of Democrats and Republicans who prioritize protecting the environment lies between 41.5% and 48.5%.

To construct a 90% confidence interval estimate of the overall difference in the percentages of Democrats and Republicans that prioritize protecting the environment, we can use the following formula:

CI = (p₁ - p₂) ± Z * √((p₁ * (1 - p₁) / n₁) + (p₂ * (1 - p₂) / n₂))

where:

Given:

Calculating the confidence interval:

CI = (0.84 - 0.39) ± 1.645 * √((0.84 * (1 - 0.84) / 700) + (0.39 * (1 - 0.39) / 900))

CI = 0.45 ± 1.645 * √((0.84 * 0.16 / 700) + (0.39 * 0.61 / 900))

CI = 0.45 ± 1.645 * √(0.000192 + 0.000257)

CI = 0.45 ± 1.645 * √(0.000449)

CI = 0.45 ± 1.645 * 0.0212

CI = 0.45 ± 0.0348

CI = (0.4152, 0.4848)

The margin of error is 0.0348 (rounded to three decimal places).

We can say, with 90% confidence, that the difference between the percentage of Democrats and Republicans who prioritize protecting the environment lies between 41.5% and 48.5% (rounded to the nearest tenth of a percent).

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Total Productive Maintenance (TPM) practices ensure D. equipment downtime is maximized

According to TPM, operators are in charge of sanitizing, enhancing, and maintaining their workstations to guarantee quality and safety throughout production cycles. The objective of TPM is to maintain equipment in top working order to ensure that production processes go without hiccups or delays.

Through the optimization of equipment availability and performance, TPM seeks to increase overall productivity and quality. The 5S methodology, a method of workforce organization that aids in streamlining and standardizing facility procedures, is the foundation on which TPM is based.

Therefore, the correct option is D.

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If I were to hypothesize that communication students will have a higher average score on the oral communication measures,

I would have a research hypothesis. A research hypothesis is a statement that is used to explain a relationship between two or more variables,

in this case, the relationship between being a communication student and having a higher score on oral communication measures.

The hypothesis can then be tested through research and analysis of data to determine if there is a significant correlation between the two variables. In order to fully test this hypothesis,

it would be necessary to gather data on both communication students and non-communication students and compare their scores on oral communication measures.

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Answer:

Below in bold.

Step-by-step explanation:

As they are similar corresponding sides are in the same proportion so

3/2 = BC/3

2BC = 3*3

2BC = 9

BC = 4.5.

3/2 = 5/DF

3DF = 2*5

DF = 2*5 / 3

= 3.33...

Perimeter of ABC = 3 + 4.5 + 5 = 12.5.

Perimeter of DEF =  2 + 3 + 3.33.. = 8.33...

Answer:

BC = 4.5 cm

DF = 10/3 cm

Step-by-step explanation:

Corresponding sides of similar triangles are in same ratio

\(\frac{BC}{EF}=\frac{AB}{DE}\\\\\frac{BC}{3} =\frac{3}{2}\\\\BC = \frac{3}{2}*3\\\\BC = \frac{9}{2}\\\\BC = 4.5 cm\)

\(\frac{DF}{AC}=\frac{DE}{AB}\\\\\frac{DF}{5}=\frac{2}{3}\\\\DF = \frac{2}{3}*5\\\\DF = \frac{10}{3}\)

Perimeter of ΔABC = 3 + 5 +4.5 = 12.5cm

Perimeter of ΔDEF = 2 + 3 + 3.3 = 8.3 cm

The equation of the path of the parabola is y = a(x - 13)² + 27

Given data ,

To represent the path of Al's toss, we can assume that the path is a parabolic trajectory.

The equation of a parabola in vertex form is given by:

y = a(x - h)² + k

where (h, k) represents the vertex of the parabola

Now , the balloon was released from the 10-yard line and landed at the 16-yard line, we can determine the x-values for the vertex of the parabola.

The x-coordinate of the vertex is the average of the two x-values (10 and 16) where the balloon was released and landed:

h = (10 + 16) / 2 = 13

Since the height of the balloon reached 27 yards, we have the vertex point (13, 27)

Now, let's substitute the vertex coordinates (h, k) into the general equation:

y = a(x - 13)² + k

Substituting the vertex coordinates (13, 27)

y = a(x - 13)² + 27

To determine the value of 'a', we need another point on the parabolic path. Let's assume that the highest point reached by the balloon is the vertex (13, 27).

This means that the highest point (13, 27) lies on the parabola

Substituting the vertex coordinates (13, 27) into the equation

27 = a(13 - 13)² + 27

27 = a(0) + 27

27 = 27

Hence , the equation representing the path of Al's toss is y = a(x - 13)² + 27, where 'a' can be any real number

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After answering the prοvided questiοn, we can cοnclude that As a result, cylinder the cοmpοsite sοlid figure has a surface area οf apprοximately 320.63 square units.

A cylinder is a twο half shape οbject made up οf twο parallel cοngruent circular bases and an arched surface that cοnnects the bases. The bases οf a cylinder are still perpendicular tοward its axis, fοrming an illusοry straight line Centre line οf bοth bases. The vοlume οf a cylinder is the sum οf its base and height. A cylinder's vοlume is measured as V = r²h, where "V" symbοlizes the vοlume, "r" reflects the radius οf the bοttοm, and "h" symbοlises the height οf the cylinder.

Tο calculate the surface area οf the cοmpοsite sοlid figure, add the surface areas οf all the individual shapes that cοmprise the figure.

A rectangular prism's surface area equals 2(lw + lh + wh).

\($\begin{array}{l}{{2(6x5+6x4+5x4)}}\\ {{2(30+24+20)}}\\ {{2(74)}}\\ {{148}}\end{array}$\)

Surface area οf a cylinder = 2πr² + 2πrh

\($\begin{array}{l}{{=2\pi(2.5)^{2}+2\pi(2.5)(6)}}\\ {{=2\pi(6.25)+2\pi(2.5)(6)}}\\ {{=12.5\pi+30\pi}}\\=42.5 \pi\\ {{=133.36}}\end{array}$\)

Finally, let's find the surface area οf the hemisphere:

Surface area οf a hemisphere = 2πr²

\($\begin{array}{c}{{=2\pi(2.5)^{2}=2\pi}}\\ {{(6.25)=12.5\pi}}\\ {{=39.27}}\end{array}$\)

Tο calculate the surface area οf the cοmpοsite sοlid figure, add the areas οf the rectangular prism, cylinder, and hemisphere:

Surface area οf cοmpοsite sοlid figure = 148 + 133.36 + 39.27 = 320.63 surface area οf rectangular prism + surface area οf cylinder + surface area οf hemisphere

As a result, the cοmpοsite sοlid figure has a surface area οf apprοximately 320.63 square units.

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Answer:

631,125

Step-by-step explanation:

25x9x11x17x3x5= 631,125

Answer: yes

Step-by-step explanation:

25cm x 9 cm x 11 cm x 17cm x 3 cm x 5cm

631125cm 6

It is gonna be cm power 6

Sorry I do no hw to power 6 above cm on my phone.

Answer:

It has to be either HEADS or TAILS (obviously). If it's a “Fair” coin the probability of getting either a Heads or Tails is (1/2) for each option.

Conclusion(so far):

Prob (Heads Coin 1) = (1/2) AND

Prob (Tails Coin 1) = (1/2)

To meet the requirements of the question, the second coin toss must have the same result as for the first coin toss.

So if the result for Coin 1 was Heads then the result for Coin 2 must also be Heads.

So

(Prob (Heads Coin 1 AND Heads Coin 2) = (Prob Heads Coin1) * (Prob Heads Coin 2) = (1/2)*(1/2) = (1/4)

Conclusion (so far) (2 coins tossed):

Prob of two coin tosses BOTH giving Heads is (1/2)*(1/2) = (1/4)

AND similarly

Prob of two coin tosses BOTH giving Tails is also (1/2)*(1/2) = (1/4)

To meet the requirements of the question, the third coin toss will, by definition be either HEADS or TAILS.

AND

Prob (Coin 3 Heads) = (1/2) AND

Prob (Coin 3 Tails) = (1/2)

The question is clear: We are asked to find the Probability that the (3 tosses) are the same.

That is, if the first toss (Coin 1) is Heads, then the results for Coin 2 and Coin 3 tosses must also be Heads.

Similarly if the the first toss (Coin 1) is Tails, then the results for Coin 2 and Coin 3 tosses must also be Tails.

So for the tosses for Coins 1, 2 and 3 to each be Heads, we have:

Prob (Coin 1 Heads, Coin 2 Heads, Coin 3 Heads) = (1/2)*(1/2)*(1/2) = (1/8)

AND

Prob (Coin 1 Tails, Coin 2 Tails, Coin 3 Tails) = (1/2)*(1/2)*(1/2) = (1/8)

There are NO OTHER NUMBER COMBINATIONS WHICH MEET THE REQUIREMENTS OF THE QUESTION other than 3 Heads AND 3 Tails.

It is important to note THAT THE SITUATIONS ABOVE (3 Heads AND 3 Tails) are BOTH VALID SOLUTIONS.

Therefore

The Probability for 3 Heads is (1/8)

AND

The Probability for 3 Tails is (1/8)

BUT BOTH THESE SOLUTIONS ARE VALID PROBABILITIES and BOTH meet the requirements of the question.

Therefore the overall probability is THE SUM OF BOTH PROBABILITIES, that is:

The probability that after 3 tosses, the tosses of each coin ALL give the same result is:

(1/8) + (1/8) = (2/8) = (1/4) or 0.25 or 25%

This means that after 3 coin tosses there is a 25% probability that we will get either 3 Heads or 3 Tails.

(A note of interest: It would be an error to ignore the fact that there are TWO valid number combinations which meet the requirements of the question, not one).

(In my analysis above I have identified ONLY the valid-number combination)

Step-by-step explanation:

This is an example of interviewer bias where the gender of the interviewer may have impacted the replies of the unmarried males in the poll.

This is an example of interviewer bias, where the gender of the interviewer may have influenced the responses of the unmarried men in the survey. The results may not accurately reflect the true opinions of the participants as their answers could have been affected by their desire to impress or please the interviewer.

This situation is an example of response bias, specifically interviewer bias, which occurs when the respondent's answer is influenced by the gender or characteristics of the interviewer, rather than their true preferences or opinions.

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Answer:

Dtidgjxjgसमदफछघबथधम छधढधदबम

To find the sum of an infinite geometric series, we need to check if the common ratio (r) of the series lies between -1 and 1.

If the common ratio is within this range, the series converges and has a finite sum. Otherwise, if the common ratio is outside this range, the series diverges and does not have a finite sum. In this case, the common ratio (r) is given by: r = 0.222 / 0.117 = 1.897 Since the absolute value of the common ratio (|r| = 1.897) is greater than 1, the infinite geometric series diverges. Therefore, the sum of the series does not exist.

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Answer:

The coach ticket she bought was =$142 and the

The first ticket was =$1002

That is so the amount of coach ticket she bought was 1560 and the first class ticket is 11880

Answer:

how many blanks are their

Step-by-step explanation:

Answer: Even though an image was not provided, I would continue with 96, 100, 104, 108, 112, 116, and so on.

Step-by-step explanation:

92 + 4 = 96 + 4 = 100 + 4, and so on.

There's not really anything else to this.

a. there are 524,288 frames in the system. b. the maximum number of frames is determined by the number of bits required to represent the page number, and the number of pages that can be addressed is limited by the size of the logical address space. c. 3 bits are needed to represent the page number 8, and 12 bits are needed to represent the offset 12.

a) The system has 524,288 frames. This can be calculated by dividing the maximum size of the logical address space (1MB) by the size of each frame (4KB).

1MB = 2^20 bytes

4KB = 2^12 bytes

Number of frames = (1MB / 4KB) = (2^20 / 2^12) = 2^(20-12) = 2^8 = 256

Therefore, there are 524,288 frames in the system.

b) The maximum number of frames that can be allocated to a process in this system is 256. This is because the maximum number of frames is determined by the number of bits required to represent the page number, and the number of pages that can be addressed is limited by the size of the logical address space.

c) i. The page number 8 can be represented using 3 bits. This is because there are 2^3 = 8 possible page numbers (0 to 7).

ii. The offset 12 can be represented using 12 bits. This is because there are 2^12 = 4,096 possible offsets (0 to 4,095).

Therefore, 3 bits are needed to represent the page number 8, and 12 bits are needed to represent the offset 12.

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The area of the rectangle = 13.12 square units.

Perimeter of the rectangle = 21.77 units.

In response to the given question;

To determine the perimeter of the rectangle ABCD, first determine the length of each side.

Determine the lengths DA and DC using the distance formula.

(x2 - x1)2 + (y2 - y1)2 = DA

Enter the coordinates of points D and A.

DA = √(8 - 1)² + (2 - 0)²

= √49 + 4

= √53 units.

Now,  we have to find length of DC

Here , DC  = √(3 - 1)² + (3 - 0)²

= √4 + 9

= √13 units.

Here,

DA = CB = √53 units.

And,

DC = AB =  √13 units.

So Perimeter of rectangle = DA + CB + DC + AB

= 2√53 + 2√13 units

= 2(√53 + √13) units.

= 21.77 units.

To find area,

Area = (1/2) base × height

Here area,

= (1/2) CB × CD

= (1/2) × √53 × √13

= 26.24/2

∴ Area = 13.12 sq. unit.

Thus, area = 13.12squnits

perimeter  = 21.77 units .

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Answer:

shorter leg = 6 cm

Step-by-step explanation:

let n be the shorter leg then n + 2 is the longer leg.

using Pythagoras' identity in the right triangle

the square on the hypotenuse is equal to the sum of the squares on the other 2 sides.

n² + (n + 2)² = 10² , that is

n² + n² + 4n + 4 = 100

2n² + 4n + 4 = 100 ( subtract 100 from both sides )

2n² + 4n - 96 = 0 ( divide through by 2 )

n² + 2n - 48 = 0 ← in standard form

(n + 8)(n - 6) = 0 ← in factored form

equate each factor to zero and solve for n

n + 8 = 0 ⇒ n = - 8

n - 6 = 0 ⇒ n = 6

However , n > 0 then n = 6

the shorter leg is 6 cm long

Teniendo en cuenta la definición de sistema de ecuaciones lineales, las edades de los hermanos son 15 y 23 años.

Un sistema de ecuaciones lineales es un conjunto de dos o más ecuaciones de primer grado, en el cual se relacionan dos o más incógnitas.

Resolver un sistema de ecuaciones consiste en encontrar el valor de cada incógnita para que se cumplan todas las ecuaciones del sistema. Es decir, se debe buscar los valores de las incógnitas, con los cuales al reemplazar, deben dar la solución planteada en ambas ecuaciones.

En este caso, se debe plantear un sistema de ecuaciones lineales teniendo en cuenta que:

Por un lado, las edades de dos hermanos suman 38 años. Esto se expresa mediante: x+y= 38

Por otro lado, la edad de uno es superior en 8 años a la edad del otro, expresado mediante x=y +8

Entonces, el sistema de ecuaciones a resolver es:

\(\left \{ {{x+y=38} \atop {x=y+8}} \right.\)

Existiendo diversos métodos para resolver un sistema de ecuaciones, se decide resolver mediante el método de sustitución, que consiste en despejar una de las dos variables en una de las ecuaciones del sistema y sustituir su valor en la otra ecuación.

En este caso, en la segunda ecuación la variable "x" ya se encuentra aislada. Entonces, reemplazando dicha expresión en la primer ecuación se llega a:

y +8 +y= 38

Resolviendo:

2y + 8=38

2y= 38 -8

2y=30

y=30 ÷2

y=15

Finalmente, para obtener el valor de y se reemplaza en la  segunda ecuación, y resolviendo se obtiene:

x= y + 8

x= 15 + 8

x=23

Finalmente, las edades de los hermanos son 15 y 23 años.

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We have f '(x) = 2 cos x − 2 sin x, so f"(x) = -2 sin(x) – 2 cos(x) which equals 0 when tan(x) = -1 . Hence, in the interval \(0\leq x\leq 2\pi\), f"(x) = 0 when X = \(\frac{3\pi }{4}\) and x = \(\frac{7\pi }{4}\)

To find when f"(x) = 0 with the given f"(x) = -2 sin(x) - 2 cos(x), we need to solve the equation:
-2 sin(x) - 2 cos(x) = 0
First, divide both sides of the equation by -2 to simplify:
sin(x) + cos(x) = 0
Now, we want to find when tan(x) is equal to a certain value. Recall that tan(x) = sin(x) / cos(x). To do this, we can rearrange the equation:
sin(x) = -cos(x)
Then, divide both sides by cos(x):
sin(x) / cos(x) = -1
Now, we have:
tan(x) = -1
In the given interval 0 ≤ x ≤ 2π, tan(x) = -1 at:
x = 3π/4 and x = 7π/4.
So, in the interval 0 ≤ x ≤ 2π, f"(x) = 0 when x = 3π/4 and x = 7π/4.

The complete question is:-

we have f '(x) = 2 cos x − 2 sin x, so f"(x) = -2 sin(x) – 2 cos(x) which equals 0 when tan(x) = __ . Hence, in the interval \(0\leq x\leq 2\pi\), f"(x) = 0 when X = \(\frac{3\pi }{4}\) and x = \(\frac{7\pi }{4}\)

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The percent needed on the final test is 99.6% in order to earn 93% on all 4 tests combined.

Let x be the percentage of the final test in order to earn 93% on all 4 tests combined.

To solve the problem, we will have to use weighted averages.

It is a method used to determine the mean of a set of data, where each observation has a different weight or frequency.

Let's first find the weighted average of the three tests you have already taken.

Given that you earned scores of 88%, 94%, and 90% on the first three tests, and each test was worth 150 points.

88% of 150 points = 132 points

94% of 150 points = 141 points

90% of 150 points = 135 points

The sum of the points you earned = 132 + 141 + 135 = 408 points

The total possible points = 450 points, which is the sum of 150 points for each of the 3 tests.

So, the weighted average of the first three tests = 408/450 × 100% = 90.67%.

To earn a 93% average on all 4 tests combined, the sum of the total points earned must be 93% of the total possible points.

93% of (450 + 250) = 657 points

The total points earned on the first three tests = 408 points

So, the points required on the final test are 657 - 408 = 249 points.

The final test is worth 250 points, so you need to earn 249/250 × 100% = 99.6%.

Therefore, you need to earn 99.6% on the final test to earn a 93% average on all 4 tests combined.

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Answer:

43/18

Step-by-step explanation:

Hope this helps

Answer:43/18 or 2 7/18 or 2.38

Step-by-step explanation:5/6-4/9+2

Answer:  Out of £750 and 3 bums

Caroline = 225

Bridget = 225 * 3 = 675

Step-by-step explanation:

Answer:

Step-by-step explanation:

Given:

We have equations:

Substitute s with b and b with c as above into first equation:

Find b:

Bridget gets £228

Answer:

Step-by-step explanation:its 27

Answer:4.3216*10^-3

Step-by-step explanation:

Answer:

4.3216*10^(-3)

Step-by-step explanation:

Moving the decimal point 3 places to the right results in 4.3216*10^(-3), which is in standard form.

Answer:

= 14/3

Step-by-step explanation:

add 3  to both sides of the equation

Answer:

biomass energy (such as ethanol), hydropower, geothermal power, wind energy, and solar energy.

Answer:

9

Step-by-step explanation:

To be a composite number, it has to be divisible by something other than 1 and itself.

5, 2, and 11 are all prime numbers, meaning their only factors are 1 and itself.

9 is composite, as it can be multiplied by 1•9 OR 3•3. Since it can be multiplied by something other than 1 and itself (aka the 3 is a factor) is is composite.

Step-by-step explanation:

9 is the composite number

309 is not divisible by 38

The statement is given as:

Is 309 divisible by 38

This means that

309/38

Using a calculator, we have:

309/38 = 8.10526315789

This means that 309 is not divisible by 38

This is because of the fractional parts in 8.10526315789

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By using the concept of factors and multiples, it can be inferred that

Product of a and b i.e. ab has atleast (m + n) trailing zeroes which is greater than both m and n

What are factors and multiples?

Suppose the number is k. Factors of k are those numbers that divide k.

For example: Factors of 6 are 1, 2, 3 and 6

Multiples of k are those numbers which are divided by k.

For example Multiples of 6 are 6, 12, 18, ....

Since the factors are of multiple of 10, then the factors will have atleast one trailing zero. Let the factors be a and b

Suppose a has m trailing zeroes and b has n trailing zeroes.

Product of a and b i.e. ab has (m + n) atleast trailing zeroes which is greater than both m and n

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When we apply the concept of factors and multiples, we concluded that the product of a and b i.e. ab has at least (m + n) trailing zeroes that are greater than both m and n.

What are factors and multiples?

A multiple is a number that, up to a given number of times, can be divided by another number without leaving a leftover.

A factor is a pair of integers or more that divide a given number by itself without leaving a residue.

Here,

the factors are of multiple of 10, then the factors will have at least one trailing zero.

We let the factors be a and b

Suppose a has m trailing zeroes and b has n trailing zeroes then, the Product of a and b i.e. ab has (m + n) at least trailing zeroes which are greater than both m and n.

Hence, we concluded that the product of a and b i.e. ab has at least (m + n) trailing zeroes that are greater than both m and n.

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