solve n/3 - 2 = -0.5​

Solve N/3 - 2 = -0.5

Answers

Answer 1

Answer:

Answer: Option H

Step-by-step explanation:

Hey there!

Given;

\( \frac{n}{3} - 2 = - 0.5\)

Shift (-2) in right side.

\( \frac{n}{3} = - 0.5 + 2\)

\( \frac{n}{3} = 1.5 \)

Multiply 3×1.5

\(n = 1.5 \times 3\)

Therefore the value of n is 4.5.

Hope it helps...


Related Questions

(HELP AS FAST AS YOU CAN)!!! This dot plot is symmetric, and the data set has no
extreme values.
1 2
3
4 5
6
7
8
9 10
Which of these measures is the best measure of variability for the dot plot?
O A. Mean
B. Mean absolute deviation (MAD)
O C. Median
D. Interquartile range (IQR)

(HELP AS FAST AS YOU CAN)!!! This dot plot is symmetric, and the data set has noextreme values.1 234

Answers

Answer:

d. interquartile range

Step-by-step explanation:

the iqr measures the first, second, and third quartile, and the median.

Ricardo's employer pays 90% of the total cost of his family's health insurance plan, while ricardo pays the rest. if the total cost of the plan will increase from $550 mer month how much more will ricardo have to pay each month?

Answers

Answer: $700×10%=$700×0.1=$70

Step-by-step explanation:

Explanation:

Ricardo's employer pays 90% of his family's health insurance. So Ricardo pays 10%.

(100%−90%=10%)

The plan increases by $700/month - how much more does Ricardo pay?

We know that he pays 10%, so he'll pay 10% of the increase. So we can write:

$700×10%=$700×0.1=$70


ABC is a right triangle. If AC = 7 and BC 8, find AB. Leave your answer in simplest radical form.

Answers

Step-by-step explanation:

We don't know if AB is a hypotenuse or leg.

If AB is hypotenuse:

\(AB=\sqrt{AC^2+BC^2} =\sqrt{7^2+8^2} =\sqrt{49+64} =\sqrt{113}\)

If AB is leg:

\(AB=\sqrt{BC^2-AC^2} =\sqrt{8^2-7^2} =\sqrt{64-49} =\sqrt{15}\)

For base/Perpendicular

AB²=8²-7²AB²=64-49AB²=15AB=√15

For Hypotenuse

AB²=8²+7²=64+49AB²=113AB=√113

plz amswer this for me​

plz amswer this for me

Answers

Answer:

$5

Step-by-step explanation:

$14 x 30% (0.30) = $4.2

$14 + $4.2 = $18.2

\(\frac{18.2}{4}\) = 4.55

Round to the nearest dollar:

4.55 = 5

FOR EACH SITUATION IDENTIFY IT AS AN EXPONENTIAL GROWTH OR EXPONENTIAL DECAY. town's population was 3800 in 2005 and growing at a rate of 2% every year.​

Answers

The function of the town's population is an exponential growth

How to classify the function as growth or decay

From the question, we have the following parameters that can be used in our computation:

Initial population = 3800

Growth  rate = 2% every year

From the above, we understand that

There is a growth in the population by 2% every year

Using the above as a guide, we have the following:

This means that the function is an exponential growth

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13. A line y-mx +8 makes an angle of 75.970 with the x-axis, find the co-ordinates of the point where the
line cuts the x-axis.
(4 marks

Answers

The coordinates of the point of the line y=mx+8 which makes an angle \(75.97^0\) cut the x-axis is (-2,0).

Given that the line is \(y=mx+8\). The angle made by the line with the positive x-axis is \(75.97^0\).

Comparing the given equation with the equation of the line (slope-intercept form) \(y=mx+c\), we get

\(c=8\)

which is the y-intercept of the line.

The slope of the line \(y=mx+c\) with an angle \(\theta\) is given by \(m=tan\theta\).

By using the above formula, the slope of the line is,

\(m=tan(75.97^0)\)

\(m=4.001\)

\(m\approx4\)

By the y-intercept, the line passing through the point (0,8) must satisfy the line point-slope equation \(y-y_{1}=m(x-x_{1})\).

\(y-8=4(x-0)\)

\(y=4x+8\)

Given that the line cuts the x-axis, so the value of y must be zero.

\(0=4x+8\)

\(4x=-8\)

\(x=-2\)

Therefore, the coordinates of the point where the line cuts the x-axis is (-2,0).

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Please help with this question. I need help this is too hard for my friend and I do not have time.

Please help with this question. I need help this is too hard for my friend and I do not have time.

Answers

The  frequency table formed using tally marks can be analyzed by using the numbers indicated by the tally  marks as follows;

The true statements are as follows;

Twice as many students prefer green than purpleTwo more students prefer blue than purpleThe same number of students prefer yellow or purple as the number who prefer blue

What are tally marks in  a frequency table?

Tally marks makes use of vertical lines to represent data, in which the fifth count is represented by a diagonal line across four vertical lines;

The data in the table are as follows

The number of students that prefer red = 5 + 1 = 6

The number of students that prefer yellow = 2

The number of students that prefer Blue = 5

The number of students that prefer purple = 3

The number of students that prefer Green = 6

Therefore;

Twice as many students prefer green than purpleTwo more students prefer blue than purpleThe  same number of students prefer  yellow or purple as the number who prefer blue

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what is the solution to the inequality -2x + 1 < 3?

Answers

Answer:

x>-1

Step-by-step explanation:

-2x+1<3

-2x<-3+1

-2x<2 /-2

x>-1

Answer is x > -1

Step by step

-2x + 1 < 3
Subtract 1 from both sides to isolate variable

-2x +1 -1 < 3 -1
Simplify

-2x < 2

Divide both sides by -2 to solve

-2/-2x < 2/-2

x < -1

**Since we divided an inequality by a negative, the rule says to flip the sign

Your answer is x > -1

14. Write an equation with vanables on each
side of the equals sign that has a solution
of -2.

Answers

Answer:

2x + 3 = 4x + 7

Step-by-step explanation:

\(2x + 3 = 4x + 7\\-2x = 4\\x = -2\)

HELP WHAT"S THE ANSWER FOR THIS

HELP WHAT"S THE ANSWER FOR THIS

Answers

Answer:

50+48+2=100

and walnut is half

so ans shld be 30

will give brainliest to someone that provides the right answer and SHOWS WORK preferably with descriptions! :)

Which statement is true about the discontinuities of the function f(x)= x^2-4/ x^3-x^2-2x​

a) there is a hole at x=2
b) there are asymptotes at x=0 and x=-1
c) there are asymptotes at x=0 and x=-1 and a hole at (2,2/3).

Answers

The correct answer is (c) there are asymptotes at x=0 and x=-1 and a hole at (2,2/3).To determine the discontinuities of the function f(x), we need to look for values of x that make the denominator of the fraction zero, since division by zero is undefined. Thus, we set the denominator equal to zero and solve for x:

x^3 - x^2 - 2x = 0

Factorizing, we get:

x(x^2 - x - 2) = 0

x(x - 2)(x + 1) = 0

So, the discontinuities of the function occur at x = 0, x = -1, and x = 2.

Now, we need to determine the type of discontinuity at each of these values. We can do this by looking at the behavior of the function as x approaches each of these values.

As x approaches 0 or -1, the denominator of the fraction approaches zero, but the numerator does not. Therefore, the function has vertical asymptotes at x = 0 and x = -1.

As x approaches 2, both the numerator and denominator approach zero, but they do so in a way that can be "simplified" by canceling out the common factor of (x - 2). Thus, the function has a hole at (2,2/3).

Therefore, the correct answer is (c) there are asymptotes at x=0 and x=-1 and a hole at (2,2/3). The person who provided this answer with a clear explanation and work would receive the brainiest!
To determine the discontinuities of the function f(x) = (x^2 - 4) / (x^3 - x^2 - 2x), we will first find any holes or vertical asymptotes by simplifying and factoring the function.

Step 1: Factor the numerator and the denominator.
f(x) = (x^2 - 4) / (x^3 - x^2 - 2x)
= ((x + 2)(x - 2)) / (x(x^2 - x - 2))

Step 2: Factor the quadratic in the denominator.
= ((x + 2)(x - 2)) / (x((x - 2)(x + 1)))

Step 3: Simplify by canceling common factors.
= (x + 2) / (x(x + 1))

Now, we can analyze the discontinuities.

1. Holes: A hole occurs when a factor is canceled from both the numerator and the denominator. In this case, we canceled the (x - 2) factor, which means there is a hole at x = 2.

2. Vertical Asymptotes: Vertical asymptotes occur when the denominator equals zero and the factor is not canceled out. The factors x and (x + 1) were not canceled, so we have vertical asymptotes at x = 0 and x = -1. Based on our analysis, the correct statement about the discontinuities of f(x) is:c) There are asymptotes at x=0 and x=-1 and a hole at x=2.

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(The last 22 and 23)


1)Evaluate the expression for x = 3
18+ x2
2)Evaluate the expression for x = 0
5x - 8




I WILL GIVE 35 POINTS

(The last 22 and 23)1)Evaluate the expression for x = 318+ x22)Evaluate the expression for x = 05x -

Answers

1) 24
2) (-8)


Hope this helps

What is an equation of the line that passes through the points (-3, -4) and
(-4, -6)?

Answers

\((\stackrel{x_1}{-3}~,~\stackrel{y_1}{-4})\qquad (\stackrel{x_2}{-4}~,~\stackrel{y_2}{-6}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{-6}-\stackrel{y1}{(-4)}}}{\underset{run} {\underset{x_2}{-4}-\underset{x_1}{(-3)}}} \implies \cfrac{-6 +4}{-4 +3} \implies \cfrac{ -2 }{ -1 } \implies 2\)

\(\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-4)}=\stackrel{m}{ 2}(x-\stackrel{x_1}{(-3)}) \implies y +4 = 2 ( x +3) \\\\\\ y+4=2x+6\implies {\Large \begin{array}{llll} y=2x+2 \end{array}}\)




The 4-It wall shown here slands 28 ft from the building. Find the length of the shortest straight bearn that will reach to the side of the building from the ground outside the wall. Bcom 2 Building 1'

Answers

The length of the shortest straight  is approximately 28.01 ft.

What is the right triangle?

A right triangle is" a type of triangle that has one angle measuring 90 degrees (a right angle). The other two angles in a right triangle are acute angles, meaning they are less than 90 degrees".

To find the length of the shortest straight beam,we can use the Pythagorean theorem.

Let's denote the length of the beam as L and  a right triangle formed by the beam, the wall, and the ground. The wall is 28 ft tall, and the distance from the wall to the building is 1 ft.

Using the Pythagorean theorem,

\(L^2 = (28 ft)^2 + (1 ft)^2\)

Simplifying the equation:

\(L^2 = 784 ft^2 + 1 ft^2\\ L^2 = 785 ft^2\)

\(L = \sqrt{785}ft\)

Calculating the value of L:

L ≈ 28.01 ft

Therefore, the length of the shortest straight beam  is approximately 28.01 ft.

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what is the standard notation for the distance of 2.4x10^5 miles

Answers

Answer:

240,000

Step-by-step explanation:

You have to add 4 zeros to the answer and remove the decimal point to get the answer.

If you liked this answer please mark "Brainliest".

Triangle ABC has vertices at A(2 , 2), B(4, 7), and C(6, 2). Classify the triangle according to the side lengths.

Answers

Answer

the triangle is a triangle

Step-by-step explanation:

Answer:

Equilateral triangle

Step-by-step explanation:

Company A has a risk percentage of 55% and a return of 14%. Company B has a risk percentage of 3% and a return of 14%. Compute the Coefficient of Variation for each company. Which company is riskier? Why?

Answers

Company A has a higher risk percentage (55%) compared to Company B (3%).

To compute the Coefficient of Variation (CV) for each company, we need to use the formula:

CV = (Standard Deviation / Mean) * 100

Let's calculate the CV for each company:

For Company A:

Risk Percentage = 55%

Return = 14%

For Company B:

Risk Percentage = 3%

Return = 14%

Since we don't have the standard deviation values for each company, we cannot calculate the exact CV. However, we can still compare the riskiness of the two companies based on the provided information.

The Coefficient of Variation measures the risk relative to the return. A higher CV indicates higher risk relative to the return, while a lower CV indicates lower risk relative to the return.

In this case, Company A has a higher risk percentage (55%) compared to Company B (3%), which suggests that Company A is riskier. However, without the standard deviation values, we cannot make a definitive conclusion about the riskiness based solely on the provided information. The CV would provide a more accurate measure for comparison if we had the standard deviation values for both companies.

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PLEASE please need help

PLEASE please need help

Answers

3 is 93 and 4 is -18 i hope this helped

Answer:

Question 3: 93    Question 4: -18

Step-by-step explanation:

Use Order of Operations (BEDMAS - Brackets Exponents Division Multiplication Addition and Subtraction).

Question 3:

Start with the numbers inside the brackets.

3^2 (4+6) + 3

= 3^2 (10) + 3

Then, solve the exponents.

= 9 (10) + 3

Multiply 9 and 10.

= 90 + 3

Add the numbers.

= 93

Question 4:

Again, start with the brackets.

3 (4+2) - 6^2

= 3 (6) - 6^2

Then, solve the exponent.

= 3 (6) - 36

Multiply 3 and 6.

= 18 - 36

Subtract the numbers.

= -18 (You can do 36 - 18 which is 18, then add the negative sign)

the measure of an angle is 65 what is the measure of its complementary angle

Answers

Answer:

25 degrees

Step-by-step explanation:

complementary angles are 90 degrees

90-65=25 degrees

Simplify

5/4 + 4 ( 3/4 - 1/2 )

Answers

Answer:

the correct answer is 2.25

draw similar rectangles that are in the ratio of 2/3. What is the ratio of the areas of the rectangles you drew.

Answers

The ratio of the areas of the rectangles will be 4:9.

What is the similarity?

If two objects are having the same shape then they will be termed as similar. So in mathematics, if two figures have the same shapes, lines or angles then they are called similar.

We know that the sides cannot be the same because it is a rectangle, therefore there is a width and length.

For the width, which is the shortest side, we will keep the radius as it is, that is, for rectangle 1 it will be 2 and for rectangle 2 it will be 3.

For the length, which is the longest side, we multiply the radius by two, which means that rectangle 1 will be 4 (2 x 2) and for rectangle 2 it would be 6 (2 x 3)

If we calculate the area it would be:

Rectangle 1:

2 x 4 = 8

Rectangle 2:

3 x 6 = 18

This means that the radius is 8/18 = 4/9

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What is the measure of the arc in the
picture above?
I will make BRAINLIEST !

What is the measure of the arc in thepicture above?I will make BRAINLIEST !

Answers

Answer:

9.42 km

Step-by-step explanation:

Measure of the arc

\( = \frac{ \theta}{360 \degree} \times 2\pi r \\ \\ = \frac{45 \degree}{360 \degree} \times 2 \times 3.14 \times 12 \\ \\ = \frac{1}{8} \times 75.36 \\ \\ = 9.42 \: km\)

express in simplified exponential notation.

x^3 •x^5=

Answers

The simplified exponential notation of the given expression is x⁸.

Given that, simplified exponential notation, x³·x⁵,

x³·x⁵ we need to simplify it,

We know that,

mᵃ × mᵇ = mᵃ⁺ᵇ

x³·x⁵ = x³⁺⁵

x³·x⁵ = x⁸

Hence, the simplified exponential notation of the given expression is x⁸.

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Find the difference using the number line. A number line ranging from seven to eight, with increments of one-tenth units. Drag and drop a number into the box to match the subtraction problem with its difference. 7.4−0.2
and the answers or opposition are
A.)9.4
B.)5.4
C.)7.2
D.) 7.6

Answers

Answer:

7.2

Step-by-step explanation:

Answer:

The answer is 7.2

Step-by-step explanation:

7.4 - 0.2 = 7.2

7.4

0.2

____

7.2

|x+3| if x>5 pls hepl fasttt

Answers

8 if you mean x=5

but if you meant greater than well x could be 6 or higher

What is the percent of decrease from 250 to 200? Round your answer to the nearest tenth.

Answers

Using the percentage formula to solve the problem. Then the percentage of decrease from 250 to 200 is 80%.

What is the percentage?

The amount of something is expressed as if it is a part of the total which is a hundred. The ratio can be expressed as a fraction of 100. The word percent means per 100. It is represented by the symbol ‘%’.

Given

The percent of decreases from 250 to 200.

The percentage is given by the formula.

\( \rm Percentage = \dfrac{Value}{Total \ value}*100 \)

We have

Value = 200

Total value = 250

Then the percentage will be

\( \rm Percentage = \dfrac{200}{250}*100 \\\\ Percentage =0.8*100 \\\\ Percentage = 80 \% \)

Thus, the percentage of decrease from 250 to 200 is 80%.

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What scale is used on the graph below


a). no scale
b). 2 cm to 2 units on both axes
c). 1 cm to 2 units on both axes
d). 1 cm to 1 unit on both axes

What scale is used on the graph belowa). no scale b). 2 cm to 2 units on both axesc). 1 cm to 2 units

Answers

\(\orange{\underline{{\bold{\mathbb{\blue{ \huge{QUESTION}}}}}}} \)

What scale is used on the graph

\( \huge \bf {\red A \pink{N}\purple{S} \blue{W} \orange{ER}}\)

b). 2 cm to 2 units on both axes

As we can se there is gap of 2 boxes (side length= 1cm of one box so 2 boxes side length= 2cm) between 2 units so we can conclude that scale is equal to 2 cm to 2 units on both axes

\( \bold \red{DEFINATION \: \: OF \: \: SCALE }\)

IT IS THE RELATIONSHIP BETWEEN THE UNIT USED AND ACTUAL VALUE ON THE GRAPH


Help me pls

Solve the following system of equations graphically on the set of axes below

Y=x+6
Y=-2x-3

Help me pls Solve the following system of equations graphically on the set of axes below Y=x+6Y=-2x-3

Answers

I think you can find it graphically by points through a table you create like:

let x = 0, and find the value of y

for example for the first equation when we let x = 0 you find y = 6 and be in the form of (0,6) then draw them or you can let x = -2 or -3 , etc as you like

to be more accurate you can find 3 pionts and start graphing them

these two equations are straight lines and they will intersect in a point

find zero f(x)=2x^4-5x^3+x^2+2x

Answers

x= 0, -1/2, 2, 1
Hope this helpssss

Help me I give ur brainlist :)

Help me I give ur brainlist :)

Answers

Answer:

Total number of copies sold to date = 361628.

Step-by-step explanation:

Let the number of copies sold to date = a

It's given that number of copies sold in the first month = 31100

These copies were 8.6% of the number of copies sold to date.

Therefore, 8.6% of a = 31100

a × \(\frac{8.6}{100}=31100\)

a = \(\frac{31100}{0.086}\)

a = 361627.907

a ≈ 361628

Therefore, total number of copies sold to date = 361628.

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