Solve for y:
0=12-y+18x
Please provide steps

Answer:

1500 cm^3

Step-by-step explanation:

Volume formula is Length times Width times Height.

50 is the length, 30 is the width and 90 is thr height so we get

\(135000\)

cm^3

length = 50 cm

breadth = 30 cm

height = 90 cm

We will use the formula volume of cuboid = l × b × h

volume of cuboid = l × b × h

V = 50 cm × 30 cm × 90 cm

V = 1500 cm² × 90 cm

V = 135000 cm³

ANSWER =

volume of cuboid is 135000 cm³

The expression represents the possible values of n, in feet

x-1<n<3x+5

If a, b and c are the lengths of the triangle's sides, then

a+b>c

a+c>b

b+c>a

Since,a=2x+2

b=x+3

z=n

2x+2+x+3>n

n<3x+5

2x+2+n>x+3=2x+2

n>x-1

Therefore the simplest form of the answer is x-1<n<3x+5.

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According to the given series, the correct answer is :

C. The series converges because it is the sum of two geometric series, each with |r| < 1.

The sum of the series is 59/60.

To see why, note that we can write the series as:

∑ (4^n / 10^n) + ∑ (7^n / 10^n)

The first sum is a geometric series with first term 1 and common ratio 4/10 = 2/5, which converges to 5/3.

The second sum is a geometric series with first term 1 and common ratio 7/10, which converges to 10/3.

Therefore, the original series converges to (5/3) + (10/3) = 59/60.

The sum of the series is (4/6)+(7/10)=59/60.

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The answer of the given question based on the reaction distance and braking distance the answer is 40 mi/h 44 ft 88 ft , 30 mi/h 33 ft 49.5 ft , 20 mi/h 22 ft 22 ft , 15 mi/h 16.5 ft 9.9 ft , 5 mi/h 5.5 ft 1.4 ft.

Braking distance is  distance that  vehicle travels from time the brakes are applied until vehicle comes to  complete stop. It is affected by various factors like the speed of the vehicle, the condition of brakes and the tires, and the road surface conditions.

The reaction distance and braking distance are both functions of the speed of the vehicle, and can be calculated using the following formulas:

Reaction distance = (speed / 2) × (time to react)

Braking distance = (speed^2 / 2 × deceleration)

where deceleration is the rate at which the vehicle slows down when the brakes are applied, and is typically expressed in meters per second squared.

Using these formulas, we can complete the chart as follows:

Speed Reaction Distance Braking Distance

40 mi/h 44 ft 88 ft

30 mi/h 33 ft 49.5 ft

20 mi/h 22 ft 22 ft

15 mi/h 16.5 ft 9.9 ft

5 mi/h 5.5 ft 1.4 ft

Note that these distances are approximate and may vary depending on the specific vehicle, road conditions, and driver behavior.

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The entries on the chart for reaction distance and braking distance is mentioned below:

Speed                          Reaction Distance          Braking Distance

40 mi/h                                44 ft                                  88 ft

30 mi/h                                33 ft                                  49.5 ft

20 mi/h                                22 ft                                  22 ft

15 mi/h                                 16.5 ft                                9.9 ft

5 mi/h                                   5.5 ft                                  1.4 ft

Braking distance is distance that  vehicle travels from time the brakes are applied until vehicle comes to complete stop. It is affected by various factors like the speed of the vehicle, the condition of brakes and the tires, and the road surface conditions.

The reaction distance and braking distance are both functions of the speed of the vehicle, and can be calculated using the following formulas:

Reaction distance = (speed / 2) × (time to react)

Braking distance = (speed² / 2 × deceleration)

where deceleration is the rate at which the vehicle slows down when the brakes are applied, and is typically expressed in meters per second squared.

Note that these distances are approximate and may vary depending on the specific vehicle, road conditions, and driver behavior.

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The complete question is as follows:

Answer:

Below.

Step-by-step explanation:

As the 2 sides are both cut in half by the horizontal line,  7x-1 = 1/2 * the base line, so:

2(7x - 1) = 48

14x - 2 = 48

14x = 50

x = 50/14

= 25/7.

Answer:

x = \(\frac{25}{7}\)

Step-by-step explanation:

A segment joining the midpoints of 2 sides of a triangle is half the length of the third side, that is

7x - 1 = \(\frac{1}{2}\) × 48 = 24 ( add 1 to both sides )

7x = 25 ( divide both sides by 7 )

x = \(\frac{25}{7}\)

Answer:

= 6x

Step-by-step Evaluation:

Evaluate for x=6

((−2)(−3))(6)

((−2)(−3))(6)

=36

(hope this helps you) :)

the general equatin of a line is

where m is the slope and b the y-intercept

firs find the slope using

where (x2,y2) is a right point from (x1,y1)

on this case (x2,y2) is (6,2)

so replacing

the slope is one

now to calculate b we replace the slope and a point and solve b

i will use (3,5)

now replacing the slope and b, the equation of the line is

Answer:

he needs to save $38.25

Step-by-step explanation:

The single loop with a total loop length of 2400 ft, it represents a first-order leveling.

To prepare the level notes, we start by listing the known information. We are given that the elevation of BM 7 is 2303.45 ft. We'll assume that the leveling survey is conducted in a closed loop, meaning it starts and ends at the same point. The total loop length is stated as 2400 ft.

Let's represent the elevation of BM 7 as E7 = 2303.45 ft.

We'll denote the elevation of the reference point as E0 = 0 ft.

Now, we can proceed with the leveling process and compute the elevations of other points in the loop. As we move along the loop, we'll measure the vertical height differences (rise or fall) between adjacent points. We'll denote these differences as Δh.

For example, let's say the difference in elevation between the reference point (0 ft) and the next point (P1) is Δh1 ft. The elevation of P1 can be calculated by adding the difference to the reference elevation:

E1 = E0 + Δh1

Similarly, we continue this process for each consecutive point in the loop. At the end of the loop, we should return to the starting reference point, completing the closed loop.

CF = ΔE / Total Loop Length

Next, we apply this correction factor to each elevation difference (Δh) in the loop. We adjust the elevations by multiplying each Δh by the correction factor:

Adjusted Δh = Δh * CF

By applying this adjustment to all the elevation differences in the loop, we can ensure that the disclosure is distributed evenly and the elevation of the reference point matches the elevation of the final point.

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The area of the triangle by the given points i.e. P(1,1,1) , Q(-2,-7,-1) and R(-7,-1,4) is √4773/2. The area of the triangle is \(\frac{1}{2}\)  |PQ × PR|.

From the points that is  given in the question with the adjacent sides,

P(1,1,1) , Q(-2,-7,-1) and R(-7,-1,4)

Area of the triangle = \(\frac{1}{2}\)  |PQ × PR|

then, from the above points,

PQ = <-3,-8,-2>

and PR = <-8,-2,3>

now, The matrices can be written as,

PQ × PR = \(\left[\begin{array}{ccc}i&j&k\\-3&-8&-2\\-8&-2&3\end{array}\right]\)  

by calculating the above matrices we get,

= -28i + 25j - 58k

| PQ × PR | = \(\sqrt{28^{2} + 25^{2} + 58^{2}\)

=√4773

However, the Area of the triangle = √4773 / 2

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The question is-

Find the area of the triangle determined by the points P(1,1,1) , Q(-2,-7,-1) and R(-7,-1,4).

Answer:

3124

Step-by-step explanation:

1000 rats caught on Monday. 10% of 1000 is 100 so, 1000-100=900 so 900 rats caught on Tuesday. 20% of 900 is 180 so, 900-180=720 so 720 rats caught on Wednesday. 30% of 720 is 216 so, 720-216=504 so 504 rats caught on Thursday. None were caught on Friday.

Add up the numbers and you'll get your answer;

1000+900+720+504= 3124

Answer:

3124

Step-by-step explanation:

1000 rats caught on Monday. 10% of 1000 is 100 so, 1000-100=900 so 900 rats caught on Tuesday. 20% of 900 is 180 so, 900-180=720 so 720 rats caught on Wednesday. 30% of 720 is 216 so, 720-216=504 so 504 rats caught on Thursday. None were caught on Friday.

Add up the numbers and you'll get your answer;

1000+900+720+504= 3124

To find the speed at which the Salisbury family was driving, we can use the formula: Speed = Distance / Time. So, the Salisbury family was driving at a speed of 89 kilometers per hour.

The distance they traveled is the difference between their initial distance from home (750 km) and their distance from home after 4 hours (394 km):
Distance = 750 km - 394 km = 356 km
The time they took to cover this distance is 4 hours.

Now we can calculate the speed:
Speed = 356 km / 4 h = 89 km/h
Therefore, the Salisbury family was driving at a speed of 89 kilometers per hour.

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Answer:

Step-by-step explanation:

To find the x- and y-intercepts of the graph of the equation 6x + 5y = 366, we set one of the variables to zero and solve for the other variable.

x-intercept: To find the x-intercept, we set y to zero and solve for x.

6x + 5(0) = 366

6x = 366

x = 366/6

x = 61

Therefore, the x-intercept is (61, 0).

y-intercept: To find the y-intercept, we set x to zero and solve for y.

6(0) + 5y = 366

5y = 366

y = 366/5

Therefore, the y-intercept is (0, 366/5) or (0, 73.2) as a decimal.

In summary, the x-intercept is (61, 0) and the y-intercept is (0, 73.2) or (0, 366/5) in fractional form.

Step-by-step explanation:

To find the x-intercept, we set y to zero and solve for x.

6x + 5y = 366

When y = 0:

6x + 5(0) = 366

6x = 366

x = 366/6

x = 61

Therefore, the x-intercept is 61.

To find the y-intercept, we set x to zero and solve for y.

6x + 5y = 366

When x = 0:

6(0) + 5y = 366

5y = 366

y = 366/5

Therefore, the y-intercept is 366/5, which cannot be simplified further.

In simplest form, the x-intercept is 61 and the y-intercept is 366/5.

Based on the given data, it is advisable for management at Kelsh to eliminate the North Division in order to avoid the traceable fixed expenses associated with it, while keeping the total common corporate expenses unaffected.

When considering the elimination of a division, it is crucial to analyze the impact on expenses and overall profitability. In this case, the information states that if the North Division is eliminated, its traceable fixed expenses can be avoided. Traceable fixed expenses refer to the costs that are directly associated with a specific division or segment of a company. By eliminating the North Division, Kelsh can avoid incurring these interests, potentially improving the company's financial performance.

Furthermore, the data states that the total common corporate expenses would be unaffected by the elimination of the North Division. Common corporate expenses are costs incurred at the corporate level that are not directly attributable to any specific division or segment.

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Answer:

equation: c-13=-2

solution: c=11

Step-by-step explanation:

c-13=-2

add 13 on both sides

c-13+13=-2+13

c=11

ANSWER CHECK

substitute C for 11

11-13=-2

The value of c is 11.

An expression contains one or more terms with addition, subtraction, multiplication, and division.

We always combine the like terms in an expression when we simplify.

We also keep all the like terms on one side of the expression if we are dealing with two sides of an expression.

Example:

1 + 3x + 4y = 7 is an expression.

3 + 4 is an expression.

2 x 4 + 6 x 7 – 9 is an expression.

33 + 77 – 88 is an expression.

We have,

Number = c

We can make an expression as,

c - 13 = -2

Now,

Solve for c.

c - 13 = -2

Add 13 on both sides.

c = -2 + 13

c = 11

Thus,

The value of c is 11.

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Answer: troy is correct

Step-by-step explanation:

m

(a) The amount in the account at the end of 1 year is $3330

(b) The amount in the account at the end of 2 year is $3696.3

It is given that Deon deposit $3000 that pays 11% interest compounded each year .

(a) Putting P = $3000, R =  11%  , T = 1 year in equation (1) , we get

           \(A=3000(1+\frac{11}{100} )^1\\\\A=3000(1+0.11)\\A=3000(1.11)\\A=3330\)

(b) Putting P = $3000, R =  11%  , T = 2 year in equation (1) , we get

       \(A=3000(1+\frac{11}{100} )^2\\\\A=3000(1+0.11)^2\\A=3000(1.11)^2\\A=3000\times1.23\\A=3696.3\)

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Answer: eeeeeeeeeeeeeee

Step-by-step explanation:

In a class of 50 students, there are 365! / 315! ways that no two students will have the same birth date.

The total number of outcomes of two or more independent events equals the product of the number of outcomes of each individual event, according to this concept. A youngster, for example, who chooses six flavors of ice cream and three types of cones will have 6 x 3 = 18 distinct icecream options. According to the fundamental counting principle, if there are p ways to do one thing and q ways to do another, then there are pq ways to accomplish both.

Here,

There are 365 ways to choose the first student's birth date, 364 ways to choose the second student's birth date (since it can't be the same as the first student's), and so on, down to 316 ways to choose the 50th student's birth date (since it can't be the same as any of the first 49 students' birth dates).

So, the number of ways to choose the birth dates of 50 students so that no two are the same is,

= 365 × 364 × ... × 316

= 365! / (365 - 50)!

= 365! / 315!

There are 365! / 315! ways that no two students will have the same birth date in a class of size 50.

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Answer:

5

Step-by-step explanation:

formula is y=kx where k is constant of variation

then k=15/3=5

the Option  B of the subsequent query is correct this is 1345


given that regular disbursed with rating became 1509, and the standard deviation of the ratings is 312.
score=1509
standard deviation=312


P(Z.3
From z score table we get P(Z<-0.52) =0.three
Then Zo= -0.52
X-rating/general deviation= -zero. 52


X= -0. 52× 312 + 150
= 1346.76
= 1345 approx


A standard deviation (or σ) is a measure of how dispersed the data is when it comes to the mean. Low standard deviation means data are clustered across the imply, and high standard deviation indicates facts are extra unfold out.


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It is not possible to find two numbers with two decimal places that round to 312 when rounded to one decimal place and have a total of 62.4.

To solve this problem systematically, we can break it down into smaller steps:

Let's assume the two numbers are x and y, both with two decimal places.

We can represent them as x = a.b and y = c.d, where a, b, c, and d are digits.

Rounding x and y to one decimal place gives us the following equations:

Round(x) = a.b ≈ 312

Round(y) = c.d ≈ 312

Since the total of the numbers is 62.4, we have the equation:

x + y = a.b + c.d

= 62.4

From Step 2, we know that both a.b and c.d are approximately equal to 312.

So, we can write:

a.b ≈ 312

c.d ≈ 312

Since a.b and c.d are rounded to one decimal place, we can rewrite them as:

a.b = 312 + p

c.d = 312 + q

p and q are the decimal parts that were rounded.

Substituting the new representations of a.b and c.d into the equation from Step 3, we get:

(312 + p) + (312 + q) = 62.4

Simplifying the equation gives us:

624 + (p + q) = 62.4

Solving for (p + q), we have:

p + q = 62.4 - 624

= -561.6

Since p and q are decimal parts, they must be between 0 and 1. -561.6 is outside this range, which means there are no values for p and q that satisfy the given conditions.

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Rewrite (2z^2 - 11)z^2 + 4 as a sum: 2z^4 - 11z^2 + 4.

Rewriting an expression means expressing the same mathematical idea or function using a different form or notation, while retaining its original meaning. The process of rewriting an expression can involve simplifying, factoring, expanding, or rearranging the terms of the expression to make it easier to read, understand, or solve.

To rewrite (2z^2 - 11)z^2 + 4 as a sum, we need to simplify the expression by multiplying the terms inside the brackets by z^2 and then adding the constant term 4.

So,

(2z^2 - 11)z^2 + 4

= 2z^4 - 11z^2 + 4

Thus, we have rewritten the expression as a sum of the terms 2z^4, -11z^2, and 4.

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Answer: I think it should be −325x−63

Step-by-step explanation:

Answer:

angle 1=90, angle 2=110,angle 3=120, angle 4=90, angle 5=39

Step-by-step explanation:

The possible values of a for which x^2+ax+25 is the square of a binomial are +10 and -10

If x^2+ax+25 is the square of a binomial, then it can be expressed in the form (x+b)^2 = x^2+2bx+b^2. Comparing the two expressions, we get:

a = 2b

25 = b^2

Solving for b in the second equation, we get:

b = ±5

Substituting this into the first equation, we get:

a = ±10

Therefore, the possible values of a for which x^2+ax+25 is the square of a binomial are +10 and -10, and these values will make b equal to +5 or -5, respectively.

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Given that the test's p-value is 0.0562>0.05, there is enough data to conclude that the machines' manufacturer should perform a new calibration.

A statistic employed in statistical hypothesis testing is known as a test statistic. A test statistic, which can be thought of as a numerical summary of a data set that condenses the data into a single value that can be used to conduct the hypothesis test, is how a hypothesis test is commonly expressed.

Here,

x=4.88 cm

μ=5 cm

σ=0.44 cm

n=49

The test statistic,

=(4.88-5)/(0.44/7)

z=-1.909

The p-value of the test is the probability that the sample mean is different by at least 4.88 - 5 = 0.12 from the target value, which is P(|z| > -1.909), which is 2 multiplied by the p-value of z = -1.909

At z=-1.909, p-value=0.0281

2*0.0281=0.0562

The test's p-value is 0.0562>0.05, indicating that there is enough data to conclude that the machines' manufacturer should perform a recalibration.

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