Solve for x
-2x+14+8x=44

Answers

Answer 1

Answer:

x = 5

Step-by-step explanation:

6x + 14 = 44

6x = 30

x = 5


Related Questions

Cara uses nylon cord to make necklaces. Each necklace requires 18.75 inches of cord. Cara has 281.25 inches of the cord on hand. If she uses all of it, how many necklaces can Cara make?

Answers

Answer:

Cara can make 15 nylon cord necklaces exactly.

Step-by-step explanation:

This looks like a simple division problem, just divide 281.25 by 18.75 and you should get 15.

HELP MEEEEEEEEEEEEEEEEEEEEEEEE PLEASEEEEEEEEEEEEEEEEEEEEE!!!!!!!!!!!!!!!!!!!!!!!

HELP MEEEEEEEEEEEEEEEEEEEEEEEE PLEASEEEEEEEEEEEEEEEEEEEEE!!!!!!!!!!!!!!!!!!!!!!!

Answers

Answer: 636,000

Step-by-step explanation:

1. 8% of 300,000 is 24,000

2. Multiply 24,000 by 14 to get 336,000

3. Add 300,000 to 336,000

If this is incorrect, I think I know what I could have done wrong so just lmk

Solve for u.
12.5 = 5u

Answers

Answer:

U=2.5

Step-by-step explanation:

Searched it

Answer:

u=2.5

Step-by-step explanation:

12.5/5=u

simplify 12.5/5 to 2.5

2.5=u so u=2.5

Type the expressions as radicals. s^6/5 100 points

Answers

Answer:

You cannot convert to radicals

Step-by-step explanation:

I tried

A publisher reports that 54T% of their readers own a laptop. A marketing executive wants to test the claim that the percentage is actually different from the reported percentage. A random sample of 110110 found that 50P% of the readers owned a laptop. Is there sufficient evidence at the 0.100.10 level to support the executive's claim

Answers

There is not sufficient evidence at the 0.10 level to support the marketing executive's claim that the percentage of readers owning a laptop is different from the reported percentage of 54T%.

To test whether the sample proportion of 50P% is significantly different from the reported proportion of 54T%, we can use a one-sample z-test.

The null hypothesis is that the true proportion is equal to 54T%, and the alternative hypothesis is that the true proportion is different from 54T%.

The test statistic is calculated as:

z = (p - p₀) / √(p₀(1-p₀)/n)

where p is the sample proportion, p₀ is the hypothesized proportion, and n is the sample size.

Plugging in the values, we get:

z = (0.50 - 0.54) / √(0.54(1-0.54)/110) ≈ -1.38

The critical value for a two-tailed test at the 0.10 level with a sample size of 110 is ±1.645. Since the calculated test statistic (-1.38) does not exceed the critical value (-1.645), we fail to reject the null hypothesis.

Therefore, there is not sufficient evidence at the 0.10 level to support the marketing executive's claim that the percentage of readers owning a laptop is different from the reported percentage of 54T%.

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Please help, need help on problem will mark BRAINLIEST AND 5 STARS

Please help, need help on problem will mark BRAINLIEST AND 5 STARS

Answers

Answer: positive, linear association

Step-by-step explanation: that is the answer, because the dots are rising up in a slope

Answer:

The answer is simple: Positive, linear association. Why is that? It is moving from left to right, increasing as it goes. That is a sign of a positive slope. And, this has a linear association because the points are jumbled together in a clear direction, so we know that we can place a line of best fit.

Guys, I’m back from nearly a year later went on hiatus on The Brainly because of myself as an anxiety and a very stressful year with A.D.H.D., and I really need help from my own schoolwork from my own school about, “A Perimeter Of The Composite Figures” with only 2 more perimeter questions left to go as soon as possible before it’s too late, please! :O

Please read it as soon as possible before answering to 2 of my own perimeter questions and thank you guys. :)

There’s only 55 points for you to answer to my own 2 of my own perimeter questions, guys! :D

Well good luck, guys! :D

Guys, Im back from nearly a year later went on hiatus on The Brainly because of myself as an anxiety

Answers

Answer:

  2. 26.2 m

  3. 117.2 cm

Step-by-step explanation:

You want the perimeters of two figures involving that are a composite of parts of circles and parts of rectangles.

2. Semicircular arch

The circumference of a circle is given by ...

  C = πd . . . . . where d is the diameter

The length of the semicircle of diameter 12.6 m will be ...

  1/2C = 1/2(π)(12.6 m) = 6.3π m ≈ 19.8 m

The two lighted sides of the rectangle have a total length of ...

  3.2 m + 3.2 m = 6.4 m

The length of the light string is the sum of these values:

  19.8 m + 6.4 m = 26.2 m

The length of the string of lights is about 26.2 meters.

3. Fan shape

The perimeter of the figure is the sum of four quarter-circles of radius 11.4 cm, and 4 straight edges of length 11.4 cm.

Four quarter-circles total one full circle in length, so we can use the formula for the circumference of a circle:

  C = 2πr

  C = 2π·(11.4 cm) = 22.8π cm ≈ 71.6 cm

The four straight sides total ...

  4 × 11.4 cm = 45.6 cm

The perimeter of the figure is the sum of the lengths of the curved sides and the straight sides:

  71.6 cm + 45.6 cm = 117.2 cm

The design has a perimeter of about 117.2 cm.

__

Additional comment

The bottom 12.6 m edge in the figure of problem 2 is part of the perimeter of the shape, but is not included in the length of the light string.

<95141404393>

If we know that the probability for z > 1.5 is 0.067, then we can say that
a) the probability of exceeding the mean by more than 1.5 standard deviations is 0.067
b) the probability of being more than 1.5 standard deviations away from the mean is 0.134
c) 86.6% of the scores are less than 1.5 standard deviations from the mean
d) all of the above

Answers

b) the probability of being more than 1.5 standard deviations away from the mean is 0.134.

If we assume that the distribution is normal, then we know that the probability of a standard normal variable z being greater than 1.5 is approximately 0.067. This means that the area to the right of 1.5 on the standard normal distribution is 0.067.

Since the standard normal distribution has mean 0 and standard deviation 1, the probability of being more than 1.5 standard deviations away from the mean is twice the probability of being greater than 1.5. So the answer is 2*0.067=0.134, which is option b).

Option a) is incorrect because we don't know the standard deviation or mean of the distribution, so we cannot say anything about standard deviations. Option c) is incorrect because we only know about the probability of a specific value, not the percentage of scores that fall within a certain distance from the mean.

Therefore, the correct answer is b).

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solve an equation (3xe²+2y)dx + (x²e" + x)dy=0 2 dy_ y(x²y³ - 4) dx X

Answers

ANSWER :  dy = - [3(x²e²/2) + 2xy + C] / (x²e" + x)

To solve the equation (3xe²+2y)dx + (x²e" + x)dy=0, we can use the method of exact differential equations.

First, let's check if the equation is exact by calculating the partial derivatives of the given expression with respect to x and y.
                              ∂/∂x (3xe²+2y) = 3e²
                              ∂/∂y (x²e" + x) = 1

Since the partial derivatives are not equal, the equation is not exact.
To make the equation exact, we can multiply the entire equation by an integrating factor, which is the reciprocal of the coefficient of dy. In this case, the coefficient of dy is 1, so the integrating factor is 1/1, which is 1.
Multiplying the equation by 1, we have:
                   (3xe²+2y)dx + (x²e" + x)dy = 0

Now, the equation becomes:
                   (3xe²+2y)dx + (x²e" + x)dy = 0
We can now rearrange the equation to isolate dy:
                   dy = - (3xe²+2y)dx / (x²e" + x)
To integrate this equation, we need to find an antiderivative of the expression on the right-hand side with respect to x.
Integrating the right-hand side:
                   ∫ (3xe²+2y)dx = 3∫xe²dx + 2∫ydx
Using the power rule of integration, we have:
                           = 3(x²e²/2) + 2xy + C
Where C is the constant of integration.

Substituting this result back into the equation, we have:
         dy = - [3(x²e²/2) + 2xy + C] / (x²e" + x)
This equation is the general solution to the given equation.

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What is the y intersect. Pls help

What is the y intersect. Pls help

Answers

Answer:

total shipping cost

Step-by-step explanation:

i’m really confused please help

im really confused please help

Answers

Answer: probly d

Step-by-step explanation:

a ,b ,and c are subtracting makeing it hard top get something that was not in the problem

Determine whether the number is rational or irrational and round it to the nearest hundredth. - 3/7​

Answers

Answer:

Yes, it's a rational number

Step-by-step explanation:

-3/7. It is a rational because. It can be written as p/q form. Where p/q are non zero number. And in decimal it would be -0.42

Answer:

-3/7 is a rational because as it can be written as p/q form where p/q are integers and q≠0.

-3/7 = -0.4285

To the nearest hundredth,

=> -0.43

estimating e^1.45 using a taylor polynomial about x=2, what is the least degree of the polynomial that assures an error smalle than 0.001

Answers

Answer:

The least degree of the polynomial that assures an error smaller than 0.001 is 4.

The Lagrange error bound for the Taylor polynomial of degree n centered at x=2 for e^x is given by:

```

|e^x - T_n(x)| < \frac{e^2}{(n+1)!}|x-2|^{n+1}

```

where T_n(x) is the Taylor polynomial of degree n centered at x=2.

We want the error to be less than 0.001, so we have:

```

\frac{e^2}{(n+1)!}|x-2|^{n+1} < 0.001

```

We can solve for n to get:

```

n+1 > \frac{e^2 \cdot 1000}{|x-2|}

```

We know that |x-2| = 0.45, so we have:

```

n+1 > \frac{e^2 \cdot 1000}{0.45} \approx 6900

```

Therefore, n > 6899.

The least integer greater than 6899 is 6900, so the least degree of the polynomial that assures an error smaller than 0.001 is 4.

The fourth-degree Taylor polynomial centered at x=2 for e^x is given by:

```

T_4(x) = 1 + 2x + \frac{x^2}{2} + \frac{x^3}{6} + \frac{x^4}{24}

```

We can use this polynomial to estimate e^1.45 as follows:

```

e^1.45 \approx T_4(1.45) = 4.38201

```

The actual value of e^1.45 is 4.38202, so the error in this approximation is less than 0.001.

Step-by-step explanation:

Consider a Diamond-Dybvig economy with a single consumption good and three dates (t = 0, 1, and 2). There is a large number of ex ante identical consumers. The size of the population is N > 0. Each consumer receives one unit of good as an initial endowment at t = 0. This unit of good can be either consumed or invested.
At t = 1, each consumer finds out whether he/she is a patient consumer or an impatient consumer. The probability of being an impatient consumer is 1∈(0,1) and the probability of being a patient one is 2=1−1. Impatient consumers only value consumption at t = 1. Their utility function is (1), where 1 denotes consumption at t = 1. Patient consumers only value consumption at t = 2. Their utility function is given by (2), where 2 denotes consumption at t = 2 and ∈(0,1) is the subjective discount factor. The function () is strictly increasing and strictly concave, i.e., ′()>0 and ′′()<0.
Consumers can buy or sell a single risk-free bond after knowing their type (patient or impatient) at t = 1. The price of the bond is p at t = 1 and it promises to pay one unit of good at t = 2. There is a simple storage technology. Each unit of good stored today will return one unit of good in the next time period. Finally, there is an illiquid asset. Each unit of illiquid investment will return >1 units of good at t = 2, but only ∈(0,1) units if terminated prematurely at t = 1.
(a) Let be the optimal level of illiquid investment for an individual consumer. Derive the first-order condition for an interior solution of . Show your work and explain your answers. [10 marks]
(b) Explain why the bond market is in equilibrium only when p =1. Derive the optimal level of illiquid investment in the bond market equilibrium.

Answers

The bond price is 1, it implies that the payoff of the bond at t=2 is equal to the consumption at t=2. Therefore, there is no need for the consumers to invest in illiquid assets when the bond market is in equilibrium.

(a) To derive the first-order condition for the optimal level of illiquid investment for an individual consumer, we need to maximize their utility function subject to their budget constraint.

For an impatient consumer, the utility function is given by:

U_i(t=1) = ln(C_i(t=1))

where C_i(t=1) represents the consumption of the impatient consumer at t=1.

For a patient consumer, the utility function is given by:

U_p(t=2) = ln(C_p(t=2))

where C_p(t=2) represents the consumption of the patient consumer at t=2.

Let I_i represent the investment in illiquid assets for the impatient consumer and I_p represent the investment in illiquid assets for the patient consumer.

The budget constraint for both consumers at t=1 is:

C_i(t=1) + I_i = 1

The budget constraint for the patient consumer at t=2 is:

C_p(t=2) + (1-p)I_p = 1

where p represents the price of the bond at t=1.

To find the optimal level of illiquid investment for an individual consumer, we need to maximize their utility function subject to the budget constraint. We can set up the Lagrangian function for the impatient consumer as follows:

L_i = ln(C_i(t=1)) + λ_i(C_i(t=1) + I_i - 1)

Taking the derivative with respect to C_i(t=1) and setting it equal to zero, we have:

∂L_i/∂C_i(t=1) = 1/C_i(t=1) + λ_i = 0

Solving for λ_i, we get:

λ_i = -1/C_i(t=1)

Similarly, we can set up the Lagrangian function for the patient consumer as follows:

L_p = ln(C_p(t=2)) + λ_p(C_p(t=2) + (1-p)I_p - 1)

Taking the derivative with respect to C_p(t=2) and setting it equal to zero, we have:

∂L_p/∂C_p(t=2) = 1/C_p(t=2) + λ_p = 0

Solving for λ_p, we get:

λ_p = -1/C_p(t=2)

To find the optimal level of illiquid investment for each consumer, we need to solve their respective first-order conditions:

For the impatient consumer:

1/C_i(t=1) = λ_i

1/C_i(t=1) = -1/C_i(t=1)

Simplifying, we get:

C_i(t=1) = 1

Therefore, the optimal level of illiquid investment for the impatient consumer is I_i = 0.

For the patient consumer:

1/C_p(t=2) = λ_p

1/C_p(t=2) = -1/C_p(t=2)

Simplifying, we get:

C_p(t=2) = 1

Therefore, the optimal level of illiquid investment for the patient consumer is:

C_p(t=2) + (1-p)I_p = 1

(1-p)I_p = 0

I_p = 0

In summary, the optimal level of illiquid investment for both the impatient and patient consumers is 0.

(b) The bond market is in equilibrium only when p = 1 because the impatient consumers have no incentive to invest in illiquid assets when the bond price is equal to 1. In this case, they can simply sell the bond at t=1 and consume the proceeds at t=2, which gives them the same utility as investing in illiquid assets.

The optimal level of illiquid investment in the bond market equilibrium is 0 for both the impatient and patient consumers. Since the bond price is 1, it implies that the payoff of the bond at t=2 is equal to the consumption at t=2. Therefore, there is no need for the consumers to invest in illiquid assets when the bond market is in equilibrium.

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describe the graph of the solution​

describe the graph of the solution

Answers

First, we want to note two things:

We have a solid circle at -10, so -10 IS part of the solution.We have shading to the right of -10, meaning we also need to include numbers to the right of -10, or numbers greater than -10.

We can describe this with an inequality:  x ≥ -10
Be sure you use ≥ and not >, since -10 is included.

We can describe this with interval notation: [ -10, infty )
Be sure you use [ and not ( on -10, since -10 is included.

You can also use set-builder notation: { x | x ≥ -10 }

A can of soda is placed inside a cooler. As the soda cools, its temperature C (t) in degrees Celsius after t minutes is given by the following exponential function.
C (t) = 19 (0.96)

Find the initial temperature.
__ C

Does the function represent growth or decay?
O growth
O decay

By what percent does the temperature change each minute?
__%

Answers

The temperature decreases by 4% each minute.

What is the exponential decay

Exponential decay is a process in which a quantity decreases over time and the rate of decrease is proportional to the current value of the quantity. This means that as the quantity decreases, the rate of decrease slows down.

I believe there is an error in the given function. It seems to be missing the exponent for 0.96. Assuming that it should be "\(C(t) = 19(0.96)^t\)", I can provide the following solutions:

The initial temperature is the temperature when t = 0. Plugging in t = 0 into the function, we get:

\(C(0) = 19(0.96)^0 = 19(1) = 19\)

Therefore, the initial temperature is 19 degrees Celsius.

The function represents decay because the base of the exponential term (0.96) is between 0 and 1, causing the function to approach 0 as time goes on.

The percent change in temperature each minute can be calculated using the following formula:

Percent Change = (New Value - Old Value) / Old Value x 100%

For each minute that passes, the temperature decreases by a factor of 0.96. Therefore, the new temperature is 0.96 times the old temperature. Using the initial temperature of 19 degrees Celsius, we can calculate the percent change in temperature each minute as follows:

Percent Change = \((0.96 * 19 - 19) / 19 * 100%\)

= -4%

Hence, the temperature decreases by 4% each minute.

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What property is 4(x+5)=(x+5)4

Answers

Answer:

Distributive propery

Take the first 4 digits of your student number as the first number and the last 3 digits as the second number. Write the matlab code to find the greatest common divisor of these numbers using the Euclidean algorithm.

Answers

The required Matlab code to find the greatest common divisor of a number using the Euclidean algorithm is shown.

To find the greatest common divisor (GCD) of two numbers using the Euclidean algorithm in MATLAB, you can use the following code:

% Replace '12345678' with your actual student number

studentNumber = '12345678';

% Extract the first 4 digits as the first number

firstNumber = str2double(studentNumber(1:4));

% Extract the last 3 digits as the second number

secondNumber = str2double(studentNumber(end-2:end));

% Find the GCD using the Euclidean algorithm

gcdValue = gcd(firstNumber, secondNumber);

% Display the result

disp(['The GCD of ' num2str(firstNumber) ' and ' num2str(secondNumber) ' is ' num2str(gcdValue) '.']);

Make sure to replace '12345678' with your actual student number. The code extracts the first 4 digits as the first number and the last 3 digits as the second number using string indexing. Then, the gcd function in MATLAB is used to calculate the GCD of the two numbers. Finally, the result is displayed using the disp function.

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Does x=y-1 represent a fraction ?

Answers

Answer: Yes

Step-by-step explanation:

Answer:

yes it does represent as a fraction

Calculate the slope between the points: (-4, 5) and (0, -2)

Answers

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

\(slope = \frac{ - 2 - 5}{0 - ( - 4)} \\ \)

\(slope = \frac{ - 7}{4} \\ \)

\(slope = - \frac{7}{4} \\ \)

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

Answer:

-7/4

Step-by-step explanation:

-2-5/0-(-4)

-2-5/0+4

-7/4

how much is (3+2)(5-1)

Answers

hope this helped buddy

Peace

how much is (3+2)(5-1)

Data was collected on the amount of time that a random sample of 8 students spent studying for a test and the grades they earned on the test. a scatter plot and line of fit were created for the data. scatter plot titled students' data, with points plotted at 1 comma 60, 2 comma 60, 2 comma 70, 2 comma 80, 3 comma 80, 3 comma 90, 4 comma 95, and 4 comma 100, and a line of fit drawn passing through the points 0 comma 40 and 2 comma 70. determine the equation of the line of fit. a. y = 15x + 70 b. y = 15x + 40 c. y = 30x + 70 d. y = 30x + 40

Answers

Answer:

y = 30x + 40

Step-by-step explanation:

Answer:

  b.  y = 15x + 40

Step-by-step explanation:

You want the equation of the line of best fit through the given data.

Regression line

The graphing calculator in the attachment shows the line of best fit to be about y = 13x +45 (red).

The green line shown is what appears to be the nearest answer choice:

  B.  y = 15x +40

<95141404393>

Data was collected on the amount of time that a random sample of 8 students spent studying for a test

Activity 2 Synthesis
1. Precious says you can estimate the area of a circle by calculating 32. What do you think
each part of her expression means?
2. Do you agree with Precious? Use your earlier work to help support your thinking.

Activity 2 Synthesis1. Precious says you can estimate the area of a circle by calculating 32. What do

Answers

yes,

3r2 ÷ 2 = 3r
3r = 3r2

Mike and his friends bought cheese waters for $4 per packet and chocolate wafers for $3 per packet at a camival. They spent a total of $36 to buy a total of 10 packets of waters of the two varieties
Part A: Write a system of equations that can be solved to find the number of packets of cheese wafers and the number of packets of chocolate wafers that Mike and his friends bought at the camival Define the variables used in the
equations (4 points)
Part B: How many packets of chocolate wafers and cheese wafers did they buy? Explain how you got the answer and why you selected a particular method to get the answer

Answers

The system of equations is:

x + y = 10

4x + 3y = 36

The solution is x = 6 and y = 4.

How to write the system of equations?

A)

Let's define the variables:

x = number of cheese wafers.y = number of chocolate wafers.

We can write the system of equations:

x + y = 10

4x + 3y = 36

Isolate x on the first equation to get:

x = 10 - y

Replace that in the other one:

4*(10 - y) + 3y = 36

40 - 4y + 3y = 36

40 - y = 36

40 - 36 = y

4 = y

And thus, the value of x is:

x = 10 - y = 10 - 4 = 6

They bought 6 cheese wafers and 4 chocolate ones.

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A ___________ is used to visualize sample data graphically and to draw preliminary conclusions about the possible relationship between the variables.

Answers

A scatter plot is used to visualize sample data graphically and to draw preliminary conclusions about the possible relationship between the variables.

A scatter plot is used to visualize sample data graphically and to draw preliminary conclusions about the possible relationship between the variables. It is a type of mathematical diagram that utilizes Cartesian coordinates to display values for typically two variables for a set of data.

The data is displayed as a collection of points, each with the value of one variable determining the position on the horizontal axis and the value of the other variable determining the position on the vertical axis. Scatter plots are extremely useful when there are a large number of data points.

Summery:A scatter plot is used to visualize sample data graphically and to draw preliminary conclusions about the possible relationship between the variables.

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kenny is practicing for a typing test to obtain a job as a paralegal. the number of words he can type is proportional to the number of minutes he types. if the test is 18 minutes long, how many words will kenny be able to type?

Answers

Kenny will be able to type 18 times the number of words he can type in one minute.

Assuming that Kenny's typing speed remains constant over time, we can use the concept of direct proportionality to determine the number of words he can type in 18 minutes. Let's say Kenny can type w words per minute, then we can write:

w ∝ minutes

This means that the number of words he can type is directly proportional to the number of minutes he types. We can express this proportionality as:

w = k * minutes

where k is the constant of proportionality that relates the number of words typed to the time taken. To find the value of k, we need to use the given information that Kenny's typing speed is proportional to the number of minutes he types. If we know the number of words he can type in one minute, we can find the value of k. Let's say he can type x words in one minute, then we can write:

x = k * 1

Solving for k, we get:

k = x

Therefore, the equation for the number of words he can type is:

w = x * minutes

If we substitute minutes = 18, we get:

w = x * 18

So, Kenny will be able to type 18 times the number of words he can type in one minute.

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If m TUV = 64, mZTUW = 7x - 2,
and mZWUV = 24, find the value of x.
1
ud
V
X =

If m TUV = 64, mZTUW = 7x - 2,and mZWUV = 24, find the value of x.1udVX =

Answers

X=6

The easiest way to solve is
64-24=40
40/7= 6
X=6

Can one help me out with this problem it due today

Can one help me out with this problem it due today

Answers

Step-by-step explanation:

the solution is in the picture

Can one help me out with this problem it due today
the answer is 50,000

EMERGENCY NEED HELP PLEASE HELP THE QUESTION IS ATTACHED TO THE QUESTION THING PLEASE HELP!!!

EMERGENCY NEED HELP PLEASE HELP THE QUESTION IS ATTACHED TO THE QUESTION THING PLEASE HELP!!!
EMERGENCY NEED HELP PLEASE HELP THE QUESTION IS ATTACHED TO THE QUESTION THING PLEASE HELP!!!

Answers

The required graph of the system of linear equations has been attached below.

What is the Linear equation?

A linear equation is defined as an equation in which the highest power of the variable is always one.

The system of linear equations is given in the question, as follows:

2x + y = 8      .....(i)

-x + 2y = 6    .....(ii)

To graph the equations using the slope and y-intercept,

1) To determine the slope m and the y-intercept, write the equation in the form y = mx + b. (0, b).

Plot the y-intercept next.

3) Depending on whether the slope is positive or negative, go up, down, or left or right from the y-intercept.

Thus, the required graph of the system of linear equations.

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How do you find the t value of a 95 confidence interval?

Answers

With a significance level of 0.05 (i.e., a confidence level of 95%), the confidence interval is calculated using the T function.

As a result, the range between 190,078.9152 and 209,921.0852 is represented by the confidence interval of 200,000 9921.0848.

What is the 95 percent confidence interval's t critical value?

Find the 0.025 critical value t* for 129 degrees of freedom in order to determine a 95% confidence interval for the mean based on the sample mean of 98.249 and sample standard deviation of 0.733. The critical value for 100 degrees of freedom is roughly 1.962.

Use the crucial value of t to determine a confidence interval for a mean by doing the following four steps:

Depending on the degree of confidence you want to have, choose the significance level. The two-tailed t table's =.05 corresponds to the most typical confidence level of 95%.

In the two-tailed t table, determine the critical value of t.

Add s/n to the crucial value of t.

Calculate the top limit of the confidence interval by adding this value to the mean, and the lower limit by deducting this value from the mean.

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