Solve for x. (Attachment Is Below.)
^Please let me know if you can see the pic below or not. It is prior to the question. Tysm!


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Answer:

49 2 will be the answer

Step-by-step explanation:

when will u send me request in fb

Answer:

p = 49

hope it's helpful ❤❤❤❤❤

THANK YOU.

Answer:

Step-by-step explanation:

Given the expression \(sin^{-1} 1/2\), the following steps must be taken to evaluate the expression.

\(Let\ y = sin^{-1}1/2\)

\(y = sin^{-1} 0.5\)

From the calculator, the value of y wil give;

\(y = 30\\\\y = 30.00 (to\ the \ nearest \ hundredth)\)

Hence \(sin^{-1} 0.5 = 30.00\).

Answer:

Step-by-step explanation:

The answer is 0.52

Hope that helped

I hope it is helpful for you ....

10 times 7 = 70

10 - 6 = 4

70 + 4 = 74

Answer:

70x+4

Step-by-step explanation:

simplify the expression

tip: u can use mäthwäy next time ;) its really helpful

It would grow by approximately 1.6668 inches to 1.2504 inches

In Lixue's garden, the green pepper plants grew 5 inches in 3-4 months. To find out how many feet they can grow in one month, we can use the given information.

Let's start by converting the inches to feet. Since there are 12 inches in a foot, we divide 5 inches by 12 to get the equivalent in feet: 5 inches ÷ 12 = 0.4167 feet (rounded to four decimal places).

Now, we need to determine how much they can grow in one month. Since the plants grew 0.4167 feet in 3-4 months, we divide this amount by the number of months to find their average monthly growth.

If we assume that the plants grew 0.4167 feet in 3 months, their monthly growth rate would be 0.4167 feet ÷ 3 months = 0.1389 feet per month (rounded to four decimal places).

If we assume that the plants grew 0.4167 feet in 4 months, their monthly growth rate would be 0.4167 feet ÷ 4 months = 0.1042 feet per month (rounded to four decimal places).

Therefore, based on the given information, the green pepper plants can grow approximately 0.1389 feet to 0.1042 feet in one month, depending on whether we consider a 3-month or 4-month timeframe.

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Answer:

Quotient means answer in the first place.

How do you find the quotient?

ans:Uou divide the dividend by the diviser to get the quotient.

Answer:

its D I think........ not 100% sure

Answer:

about 45%

Step-by-step explanation:

it should be right

This is given point in the fourth quadrant.

In this point, the adjacent is

The opposite is y.

Find hypotenuse h using the pythagorean theorem:

is equal to hypotenuse by adjacent.

is equal to adjacent by opposite.

In the fourth quadrant,

is positive , and

is negative.

So,

Answer:

huh I'm confused I dont know

Adding the fractions 1/8 and 1/12 by using the LCM of 8 and 12 as the common denominator exists 5/24.

A fraction is a piece of the entire. In mathematics, the number is represented as a quotient, where the numerator and denominator are divided. Both are integers in a straightforward fraction. In the numerator or denominator of a complex fraction is a fraction. A correct fraction has a numerator that is lower than its denominator.

An element of a whole or, more broadly, any number of equal pieces, is represented by a fraction. When used in conversational English, a fraction indicates the number of components of a particular size, as in one-half, eight-fifths, and three-quarters.

Let the fractions be 1/8 and 1/12

8 = 2 × 4

12 = 3 × 4

By using LCM, we get

\($2 \times 3 \times 4=24 \quad\{L C M\}$\)

= 1/8 + 1/12

simplifying the equation, we get

\($=\frac{1 \times 3}{8 \times 3}+\frac{1 \times 2}{12 \times 2}$\)

= 3/24 + 2/24

= 5/24

Therefore, adding the fractions 1/8 and 1/12 by using the LCM of 8 and 12 as the common denominator exists 5/24.

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Reducing the variation of a process will increase the width of a given confidence interval relative to that process.

Option C is correct .

In statistics, the probability that a population parameter will fall between a set of values for a predetermined percentage of the time is referred to as a confidence interval. By employing the dimensions of values used in the computation of the intervals, it is simple to establish the link between components of two confidence intervals. The width is a fundamental component in these range estimates, which are affected by sample size, etc.

Hence, reducing the variation of a process will increase the width of a given confidence interval relative to that process is false.

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The wrong value in Sally's list is 36. Sally did not have $36 left after she found $16 and put it in her pocket. She actually had $48 left.

Let x be the amount of money Sally started with.

She spent $12 on a hat, leaving her with x - 12 dollars.

She then spent one-third of her remaining money on some music. This means she spent

(1/3)(x - 12) dollars.

After that, she found $16 on the ground and put it in her pocket.

Sally now has (1/3)(x - 12) + 16 dollars.

Finally, Sally spent half of her remaining money on a new dress, leaving her with just $18.

Therefore, (1/2)[(1/3)(x - 12) + 16] = 18.

Now we can solve for x and determine how much money Sally started with.

(1/6)(x - 12) + 8 = 18

(1/6)(x - 12) = 10

x - 12 = 60

x = 72

So Sally started with $72. After each transaction, Sally had the following amounts of money: $72, $60, $20, $48, $18.

To check whether Sally's list is correct, we can work backward.

Starting with $18, we can reverse the process by adding $18 to the amount Sally had after each transaction.

After spending half of her remaining money on a new dress, Sally had (2)(18) = 36 dollars.

However, Sally actually had $48 left after she found $16 and put it in her pocket.

Therefore, the wrong value in Sally's list is 36.

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Answer:

780

Step-by-step explanation:

i think sorry if it is wrong

Answer:

the one that looks like a v

Step-by-step explanation:

bc for every y-input, there is only one output-x

Answer:

Answer vary :

0.25884

Step-by-step explanation:

honestly in my opinion that’s the answer.

1. 21.57 times 0.12 = 2.5884

then divide 2.5884 by the power of ten, wich is moving the decimal to left with how many zeros their are.

-0.25884

since in 10 their is only one 0 we moved the decimal only one time to the left.

and that’s how I came to that solution.

a) For chi-squared distribution with v=3 degrees of freedom, the statistic that can be constructed using Xi's is:

X2 = Σ i=1 3 (Xi − i)2 / 3.

X2 has chi-squared distribution with 3 degrees of freedom.

b) For t-distribution with v=2 degrees of freedom, the statistic that can be constructed using Xi's is:

T = (X1 − 1) / [(X2/2)0.5].

T has t-distribution with 2 degrees of freedom.

c) For F-distribution with v1=1 and v=2 degrees of freedom, the statistic that can be constructed using Xi's is:

F = [(X1 − 1)/1] / [(Σi=2 to 3 Xi2) / 2].

F has F-distribution with 1 and 2 degrees of freedom.

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Answer:

i cant see a parrellogram!

please post a picture

The probability that less than 2 of the 5 are 65 years or older is 70.32%

To calculate the probability that less than 2 out of 5 randomly selected persons from the population of Arizona are 65 years or older, we need to calculate the probabilities of selecting 0 and 1 persons who are 65 years or older and then sum them.

The probability of selecting 0 persons who are 65 years or older can be calculated using the binomial probability formula:

P(X = k) = C(n, k) * p^k * (1 - p)^(n - k)

Where:

P(X = k) is the probability of selecting k persons who are 65 years or older,

C(n, k) is the number of combinations of selecting k items from a set of n items,

p is the probability of selecting a person who is 65 years or older,

(1 - p) is the probability of selecting a person who is not 65 years or older,

n is the total number of trials (sample size).

Using this formula, we can calculate the probability of selecting 0 persons who are 65 years or older:

P(X = 0) = C(5, 0) * 0.14^0 * (1 - 0.14)^(5 - 0)

Similarly, we can calculate the probability of selecting 1 person who is 65 years or older:

P(X = 1) = C(5, 1) * 0.14^1 * (1 - 0.14)^(5 - 1)

Finally, we can sum these probabilities to get the probability of less than 2 persons who are 65 years or older:

P(X < 2) = P(X = 0) + P(X = 1)

Calculating these probabilities:

P(X = 0) = C(5, 0) * 0.14^0 * (1 - 0.14)^(5 - 0) = 1 * 1 * 0.86^5 = 0.2968 (approximately)

P(X = 1) = C(5, 1) * 0.14^1 * (1 - 0.14)^(5 - 1) = 5 * 0.14 * 0.86^4 = 0.4064 (approximately)

P(X < 2) = P(X = 0) + P(X = 1) = 0.2968 + 0.4064 = 0.7032 (approximately)

Therefore, the probability that less than 2 out of 5 randomly selected persons from the population of Arizona are 65 years or older is approximately 0.7032 or 70.32%.

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Answer:

\( \boxed{two \: point \: three \: two}\)

Answer:

\(y=4-3x\)

Step-by-step explanation:

\(3x+y=4\)

Subtract 3x from both sides:

\(3x+y-3x=4-3x\)

\(y=4-3x\)

Answer:

its answer is

y=4-3x ok

The figures that have the same volume are

Since the volume of a cylinder is given by the formula

height = h

and the volume of a cone is given by the formula

height = 3h

Equating both as given in the equation

volume of a cylinder = volume of a cone

base area * height  = 1/3 * base area * height

h = 1/3 * 3h

h = h

hence the volume will be equal

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We cannot infer that the data is not normal based on the given sample frequencies.

To determine if the given data is normal or not, we will use the chi-square goodness-of-fit test at a significance level of α = 0.10.

First, we need to calculate the expected frequencies assuming the data is normal. For this, we will assume a standard normal distribution and calculate the probabilities for the given intervals:

Interval Probability Expected Frequency

Z < -1 0.1587 (0.1587)50 = 7.935

-1 < Z < 1 0.6826 (0.6826)50 = 34.13

0 < Z < 1 0.3413 (0.3413)50 = 17.065

Z > 1 0.1587 (0.1587)50 = 7.935

Next, we will calculate the chi-square test statistic:

χ2 = Σ[(Observed Frequency - Expected Frequency)2 / Expected Frequency]

χ2 = [(6 - 7.935)2 / 7.935] + [(27 - 34.13)2 / 34.13] + [(14 - 17.065)2 / 17.065] + [(3 - 7.935)2 / 7.935]

χ2 = 2.910

The critical value of chi-square with 3 degrees of freedom and a significance level of α = 0.10 is 6.251. Since the calculated χ2 value (2.910) is less than the critical value (6.251), we fail to reject the null hypothesis that the data is normally distributed at the α = 0.10 level.

Therefore, we cannot infer that the data is not normal based on the given sample frequencies.

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The derivatives of the given functions are:

z'(x) = (6x - 2)(2x - 7)^4 + 8(3x^2 - 2x)(2x - 7)^3

f'(x) = 18(6x - 1)^2 - 15(6x - 1)^3(5x + 3)^2

f'(x) = -16x^3 + 84x^2

To find the derivatives of the given functions, we'll use the power rule, product rule, quotient rule, chain rule, exponential rule, and logarithmic rule where applicable. Let's solve each problem one by one:

Given: z(x) = (3x^2 - 2x)(2x - 7)^4

To find the derivative, we'll apply the product rule. The product rule states that if we have a function u(x) multiplied by another function v(x), the derivative of the product is given by:

(d/dx)(u(x) * v(x)) = u'(x) * v(x) + u(x) * v'(x)

Let's apply the product rule to z(x):

z'(x) = (3x^2 - 2x)' * (2x - 7)^4 + (3x^2 - 2x) * ((2x - 7)^4)'

Taking the derivatives of each term:

z'(x) = (6x - 2) * (2x - 7)^4 + (3x^2 - 2x) * 4(2x - 7)^3 * 2

Simplifying the expression:

z'(x) = (6x - 2)(2x - 7)^4 + 8(3x^2 - 2x)(2x - 7)^3

Given: f(x) = (6x - 1)^3 / (5x + 3)^3

To find the derivative, we'll apply the quotient rule. The quotient rule states that if we have a function u(x) divided by another function v(x), the derivative of the quotient is given by:

(d/dx)(u(x) / v(x)) = (u'(x) * v(x) - u(x) * v'(x)) / v(x)^2

Let's apply the quotient rule to f(x):

f'(x) = ((6x - 1)^3)' * (5x + 3)^3 - (6x - 1)^3 * ((5x + 3)^3)'

Taking the derivatives of each term:

f'(x) = 3(6x - 1)^2 * 6 - (6x - 1)^3 * 3(5x + 3)^2 * 5

Simplifying the expression:

f'(x) = 18(6x - 1)^2 - 15(6x - 1)^3(5x + 3)^2

Given: f(x) = 4x^3 / (-2x + 7)

To find the derivative, we'll apply the quotient rule again:

f'(x) = (4x^3)' * (-2x + 7) - 4x^3 * (-2x + 7)'

Taking the derivatives of each term:

f'(x) = 12x^2 * (-2x + 7) - 4x^3 * (-2)

Simplifying the expression:

f'(x) = -24x^3 + 84x^2 + 8x^3

f'(x) = -16x^3 + 84x^2

So, the derivatives of the given functions are:

z'(x) = (6x - 2)(2x - 7)^4 + 8(3x^2 - 2x)(2x - 7)^3

f'(x) = 18(6x - 1)^2 - 15(6x - 1)^3(5x + 3)^2

f'(x) = -16x^3 + 84x^2

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Answer:

121212

Step-by-step explanation:

f12121

Answer:

Step-by-step explanation:

We'll start with going form exponential to radical, since it may be easier to follow. For example,

\(x^{\frac{4}{3}\) can be written, in radical form, as

\(\sqrt[3]{x^4}\). What happens is that the denominator of the fraction serves as the index (the number that sits in the bend of the radical) and the numerator serves as the power on the variable (or number, if that's the case). Let's look at another one:

\(4^{\frac{2}{3}\) becomes

\(\sqrt[3]{4^2}=\sqrt[3]{16}=\sqrt[3]{8*2}=2\sqrt[3]2}\)

And you can go the other way with it. For example,

\(\sqrt[5]{x^4}\) becomes

\(x^{\frac{4}{5}\), etc. Get it?

Answer:

When you're given a problem in radical form, you may have an easier time if you You can rewrite every radical as an exponent by using the following property — the top ... For example, 643/2 is easier if you write it as (641/2)3 = 83 = 512 rather than (643)1/2,  Rewrite the entire expression using rational exponents.

Answer:

The area is twice the circumference

Area = 2 * circumference

Step-by-step explanation:

Proof:

r = 2

Circumference = 2\(\pi\)r

Circumference = 12.566

Area = \(\pi\)r^2

Area = 25.132

25.132/12.566 ≈ 2

Answer:

the (area) is (1/2) times the (radius) times the circumference.

Step-by-step explanation:

i dont know how to explain it exactly but i found the cerect answer.

Therefore, Caleb paid approximately $14,067.90 for the shares.

Let's assume the amount Caleb paid for the shares is represented by the variable "x". According to the given information, his selling price was 130% of the amount he paid.

Selling price = 130% of the amount paid

$18,189.27 = 1.3 * x

To find the amount he paid for the shares, we can solve the equation for "x" by dividing both sides by 1.3:

x = $18,189.27 / 1.3

Calculating this, we find:

x ≈ $14,067.90

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The test to use when there's an independent group design and ordinal data is the Kruskal Wallis test

Given: Independent group and ordinal data. To find which test to use.

What's the Kruskal Wallis test?

The Kruskal Wallis test is used when you have one independent variable with two or further situations and an ordinal dependent variable. In other words, it's thenon-parametric interpretation of ANOVA and a generalized form of the Mann- Whitney test system since it permits two or further groups.

The Kruskal Wallis test is used when you have one independent variable with two or further situations and an ordinal dependent variable. In other words, it's thenon-parametric interpretation of ANOVA and a generalized form of the Mann- Whitney test system since it permits two or further groups.

The null thesis for the Kruskal- Wallis test simply states that there are no methodical or harmonious differences among the treatments being compared.

How to calculate the Kruskal Wallis test?

The computation of the Kruskal- Wallis statistic requires

Hence as is mentioned for an independent group design and ordinal data so we use the Kruskal Wallis test.

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We can use the Kruskal Wallis test when we have an independent group design and ordinal data.

We are given an independent group design and ordinate data.

We need to tell which test to use on them.

The Kruskal Wallis test is used when you have one independent variable with two or more situations and one ordinal dependent variable. In other words, it is an interpretation of ANOVA table and a generalized form of the Mann- Whitney test system.

The null hypothesis for the Kruskal- Wallis test tells us that:

There are no methodical or harmonious differences among the treatments being compared.

Therefore, we can use the Kruskal Wallis test when we have an independent group design and ordinal data.

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Answer:

-

He spent 1 hour in total

-

1 hour

There's two Xs on the graph indicating that he had two 1/2 hour hikes, so you just add that up. And that's 1 hour woo