Solve for x. Assume that lines which appear tangent are tangent.

The solution of the expression will be 3, -2, and -22 respectively.

The mathematical expression combines numerical variables and operations denoted by addition, subtraction, multiplication, and division signs.

Mathematical symbols can be used to represent numbers (constants), variables, operations, functions, brackets, punctuation, and grouping. They can also denote the logical syntax's operation order and other properties.

Given that the expressions are:-

2x²−3x−2 if x is less than or equal to -1

E = 2x²−3x−2

E = 2 (-1) ² - 3 x -1 -2

E = 2 + 3 - 2

E = 3

E = −x²+2x+1 if -1

E = -(-1)² + 2 x -1 + 1

E = -1 - 2 + 1

E = -2

E = −2x²−x−1

E = -2 ( 3 )² - 3 - 1

E = -18 - 3 - 1

E = -22

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Answer:

45% of people attending supported the home team

The information that is needed to write the equation of a line in point-slope form is the location of one ordered pair that lies on the line and the line's slope. The correct option is the first option

From the question, we are to determine the information that is needed to write the equation of a line in point-slope form.

The point-slope form of a line is given as

y - y₁ = m(x - x₁)

Where, (x₁, y₁) is a point on the line

and m is the slope of the line

Thus, in order to write the equation of a line in the point-slope form, the information that are needed are:

1. An ordered pair on the line

2. The slope of the line

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95% confident that the true difference in these proportions is between 0.118 and 0.242.

Assuming that the conditions for inference have been met, we can use the following formula to calculate a 95% confidence interval for the difference between two proportions:

(pD - pI) ± zsqrt((pD(1-pD)/nD) + (pI*(1-pI)/nI))

where pD is the proportion of adults older than 50 who do not support the attack, pI is the proportion of adults aged between 30-50 who do not support the attack, nD is the sample size of adults older than 50, nI is the sample size of adults aged between 30-50, and z* is the critical value from the standard normal distribution corresponding to a 95% confidence level, which is approximately 1.96.

Substituting the given values, we get:

(pD - pI) ± 1.96sqrt((pD(1-pD)/nD) + (pI*(1-pI)/nI))

Plugging in the values from the table, we get:

(0.46 - 0.28) ± 1.96sqrt((0.46(1-0.46)/400) + (0.28*(1-0.28)/600))

= 0.18 ± 0.062

So the 95% confidence interval for the difference between the proportion of adults older than 50 and the adults aged between 30-50, who do not support the attack, is (0.118, 0.242). This means that we are 95% confident that the true difference between these two proportions falls within this interval.

Interpreting this in context, we can say that based on the sample data, there is strong evidence to suggest that a higher proportion of adults older than 50 do not support the attack compared to adults aged between 30-50.

Specifically, we can be 95% confident that the true difference in these proportions is between 0.118 and 0.242.

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The probability that more than the expected number of Sikh youths wear a turban in a random sample of five is 0.3671 (rounded to 4 decimal places).

a. Using the binomial distribution formula, we can determine the likelihood that two out of a random sample of five Sikh teenagers are turban-wearing:

\(P(X = 2) = (5 pick 2) (5 choose 2) * (0.75)^3 * (0.25)^2\)

"X" indicates the proportion of Sikh adolescents who wear turbans, "5 choose 2" indicates the number of possible methods to select 2 Sikhs from a group of 5, and "0.75" and "0.25" indicate the likelihoods that a Sikh youngster will not be wearing a turban and will be wearing one, respectively.

This expression can be made simpler by using a calculator to become:

P(X = 2) = 10 * 0.421875 * 0.0625 = 0.2659

Hence, 0.2659 percent chance exists that two out of every five Sikh youngsters in a random sample will be turban-wearing (rounded to 4 decimal places).

Using the complement rule, we can determine the likelihood that two or more of a random sample of five Sikh teenagers are wearing turbans:

P(X >= 2) = 1 - P(X 2)

where X is the proportion of young Sikhs who are turban-wearing.

P(X 2) is the likelihood that fewer than 2 of five Sikh teenagers chosen at random will be turban-wearing.

This can be calculated as:

P(X 2) equals P(X = 0) plus P(X = 1).

P(X = 0) = (5 select 0) * (0.75) * (5 select 0) * (0.25) * 0 = 0.2373

P(X = 1) = (5 select 1) * (0.75) * (4 select 1) * (0.25) * 1 = 0.3956

P(X 2) = 0.2373 + 0.3956 = 0.6329 as a result.

We can then compute P(X >= 2) = 1 - 0.6329 = 0.3671 using the complement rule.

Consequently, there is a 0.3671 percent chance that two or more of five Sikh teenagers chosen at random will be turban-wearing (rounded to 4 decimal places).

c. The following formula can be used to determine how many Sikh teenagers in a random sample of five are likely to wear a turban:

E(X) = n * p = 5 * 0.25 = 1.25

Using the cumulative binomial distribution function, we can determine the likelihood that more Sikh teenagers than predicted in a random sample of five wear turbans:

P(X > 1) = 1 - P(X <= 1)

P(X = 1) equals P(X = 0) plus P(X = 1).

P(X = 0) = (5 select 0) * (0.75) * (5 select 0) * (0.25) * 0 = 0.2373

P(X = 1) = (5 select 1) * (0.75) * (4 select 1) * (0.25) * 1 = 0.3956

Therefore,

P(X <= 1) = 0.2373 + 0.3956 = 0.6329

The complement rule can then be used to determine:

P(X > 1)

P(X > 1) = 1 - 0.6329 = 0.3671

Hence, in a random sample of five Sikh adolescents, the likelihood that there are more turban-wearing Sikh youths than expected is 0.3671. (rounded to 4 decimal places).

d. To determine the likelihood that more than predicted will occur.

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Answer:

So try 0-6

Step-by-step explanation:

Answer:

I can't solve this completely for you, but I'll help you figure it out.

Step-by-step explanation:

All you need to do is choose a number to plug in for x, I'd start with zero and work my way up. Do this for all equations to solve for solutions to your problem.

The system of equations [x - 3y = -1 and -6x + 19y = 6] can be solved, resulting in x = -1 and y = 0.

To solve the system of equations [x - 3y = -1 and -6x + 19y = 6], we can use the method of substitution or elimination.

Let's solve it using the method of elimination.

First, we can multiply the first equation by 6 and the second equation by -1 to eliminate the x terms.

This gives us [6x - 18y = -6 and 6x - 19y = -6].

Now, subtracting the first equation from the second eliminates the x terms, leaving us with -y = 0. Solving for y, we find y = 0.

Substituting this value back into the first equation, we get x - 3(0) = -1, which simplifies to x = -1.

Therefore, the solution to the system of equations is x = -1 and y = 0.

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Answer:

1/30

Step-by-step explanation:

We multiply all the terms by the denominator

-6×5x+1=0

Wy multiply elements

-30x+1=0

We move all terms containing x to the left, all other terms to the right

-30x=-1

x=-1/-30

x=1/30

The critical value of the function is ∅ is an empty set.

Given data:

To find the critical points of the function f(x) = (x² - 9) / (x² - 4x + 3), we need to find the values of x where the derivative of the function is either zero or undefined.

First, let's find the derivative of f(x) with respect to x:

f'(x) = [(2x)(x² - 4x + 3) - (x² - 9)(2x - 4)] / (x² - 4x + 3)²

Simplifying the numerator:

f'(x) = [2x³ - 8x² + 6x - 2x³ + 4x² - 18x + 8x - 36] / (x² - 4x + 3)²

= (-4x² - 10x - 36) / (x² - 4x + 3)²

To find the critical points, we need to solve the equation f'(x) = 0:

(-4x² - 10x - 36) / (x² - 4x + 3)² = 0

Since the numerator of the fraction can be zero, we need to solve the equation -4x² - 10x - 36 = 0:

4x² + 10x + 36 = 0

We can attempt to factor or use the quadratic formula to solve this equation:

Using the quadratic formula:

x = (-b ± √(b² - 4ac)) / (2a)

In this case, a = 4, b = 10, and c = 36:

x = (-10 ± √(10² - 4 * 4 * 36)) / (2 * 4)

x = (-10 ± √(100 - 576)) / 8

x = (-10 ± √(-476)) / 8

Since the discriminant is negative, the equation has no real solutions. Therefore, there are no critical points for the given function.

Hence, the critical points are ∅ (empty set).

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Answer:

700

Step-by-step explanation:

Answer:

see below

Step-by-step explanation:

5(2a+2b+2c)

you must distribute the 5 among the values in parenthesis

4(x-3)

you must distribute the 4 among the values in parenthesis

Hope this helps! :)

Answer:

sorry I don't know

Step-by-step explanation:

OK

OK jsjzjxjxndzkxk

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a. The control limits for the 3-sigma x-bar chart are: UCL x-bar = 61.744 lb. and LCL x-bar = 59.756 lb.

b. The control limit for the 3-sigma R-chart is UCL R = 4.051 lb., rounded to three decimal places.

(a) To determine the control limits for the 3-sigma x-bar chart, we need to use the given information of the sample size, overall mean, and average range.

For the x-bar chart, the control limits are calculated using the formula:

Upper Control Limit (UCL x-bar) = overall mean + (A2 * average range)

Lower Control Limit (LCL x-bar) = overall mean - (A2 * average range)

Where A2 is a constant depending on the sample size. For a sample size of 7, the value of A2 is 0.577.

Substituting the values into the formula, we get:

Upper Control Limit (UCL x-bar) = 60.75 + (0.577 * 1.78) = 61.744

Lower Control Limit (LCL x-bar) = 60.75 - (0.577 * 1.78) = 59.756

Therefore, the control limits for the 3-sigma x-bar chart are: UCL x-bar = 61.744 lb. and LCL x-bar = 59.756 lb.

(b) To calculate the control limits for the 3-sigma R-chart, we only need the value of the average range.

The control limits for the R-chart are calculated as follows:

Upper Control Limit (UCL R) = D4 * average range

Lower Control Limit (LCL R) = D3 * average range

For a sample size of 7, the values of D3 and D4 are 0 and 2.282, respectively.

Substituting the values into the formula, we get:

Upper Control Limit (UCL R) = 2.282 * 1.78 = 4.051 lb.

Therefore, the control limit for the 3-sigma R-chart is UCL R = 4.051 lb., rounded to three decimal places.

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The bride and groom can form 252 different groups of five people from the total of 10 people at the rehearsal dinner, as they need to assign them to two tables of five people each.

To determine the number of different groups of five people that can be formed, we can use the concept of combinations. In this scenario, we have 10 people who need to be divided into two groups of five people each.

The number of ways to choose five people out of 10 can be calculated using the combination formula. The formula for combinations is given by:

C(n, r) = n! / (r! * (n - r)!)

Where n represents the total number of people and r represents the number of people to be chosen. In this case, n = 10 and r = 5.

Plugging these values into the formula, we get:

C(10, 5) = 10! / (5! * (10 - 5)!)

= (10 * 9 * 8 * 7 * 6 * 5!) / (5! * 5 * 4 * 3 * 2 * 1)

= (10 * 9 * 8 * 7 * 6) / (5 * 4 * 3 * 2 * 1)

= 252

Therefore, the bride and groom can form 252 different groups of five people from the total of 10 people at the rehearsal dinner. This means that there are 252 distinct ways to divide the 10 people into two tables of five people each, providing flexibility in creating diverse groups for the dinner.

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Binary integer variables are variables whose values consist of two values, 0 and 1.

Correct answer will be :- b. Variables with values 0 and 1.

These values are also known as bits, which are represented as 0 and 1 in computers. Binary integer variables are used in computing as a way to represent numbers, characters, and instructions. Binary integer variables are used to represent information in digital systems, because they can be used to represent any value with a single bit.

For example, a single bit can represent a number, letter, or instruction. Binary integer variables are also used in computer programming, as they can be used to represent boolean values, such as true and false. Additionally, they can be used to represent various types of data, such as numbers, characters, and images.

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Answer:

The test  has 10 3-point questions and 14 5-point questions.

Step-by-step explanation:

x + y = 24

3x + 5y = 100

From the first equation:

3x + 3y = 72

Subtracting:

3x - 3x + 5y - 3y = 100 -72

2y = 28

so y = 14

x + 14 = 24 so x = 10.

10*3 + 5*14

= 30 + 70 = 100 points.

Answer is in attachment.

k=6

We are provided with ;

\({:\implies \quad \bf f(x)=\displaystyle \begin{cases}\bf \dfrac{k\cos (x)}{\pi -2x}\:\:,\:\: x\neq \dfrac{\pi}{2}\\ \\ \bf 3\:\:,\:\: x=\dfrac{\pi}{2}\end{cases}}\)

Also we are given with ;

\({:\implies \quad \displaystyle \bf \lim_{x\to \footnotesize \dfrac{\pi}{2}}f(x)=f\left(\dfrac{\pi}{2}\right)}\)

At first , let's define the function at x = π/2 . Now , as given that f(x) = 3 , x = π/2. Implies , f(π/2) = 3

Now , we have ;

\({:\implies \quad \displaystyle \sf \lim_{x\to \footnotesize \dfrac{\pi}{2}}f(x)=3}\)

Now , As in RHS , x is approaching π/2 , means that x is in neighbourhood of π/2 , x is coming towards π/2 , but it's not π/2 , implies f(x) for the limit in LHS is defined for x ≠ π/2 or we don't have to take value of x as π/2 , means x ≠ π/2 in that case , means we have to take f(x) = {kcos(x)}/π-2x , x ≠ π/2 for the limit given in LHS ,

\({:\implies \quad \displaystyle \sf \lim_{x\to \footnotesize \dfrac{\pi}{2}}\dfrac{k\cos (x)}{\pi -2x}=3}\)

Now , As k is constant , so take it out of the limit

\({:\implies \quad \displaystyle \sf k \lim_{x\to \footnotesize \dfrac{\pi}{2}}\dfrac{\cos (x)}{\pi -2x}=3}\)

For , further evaluation of the limit , we will use substitution , putting ;

\({:\implies \quad \sf x=\dfrac{\pi}{2}-y\:\: , as\:\: x\to \dfrac{\pi}{2}\:\:,\: So\:\: y\to0}\)

Putting ;

\({:\implies \quad \displaystyle \sf k \lim_{y\to0}\dfrac{\cos \left(\dfrac{\pi}{2}-y\right)}{\pi -2\left(\dfrac{\pi}{2}-y\right)}=3}\)

Now , we knows that

Using this , we have :

\({:\implies \quad \displaystyle \sf k \lim_{y\to0}\dfrac{\sin (y)}{\pi -\bigg\{2\left(\dfrac{\pi}{2}\right)-2y\bigg\}}=3}\)

\({:\implies \quad \displaystyle \sf k \lim_{y\to0}\dfrac{\sin (y)}{\pi -(\pi -2y)}=3}\)

\({:\implies \quad \displaystyle \sf k \lim_{y\to0}\dfrac{\sin (y)}{\cancel{\pi}-\cancel{\pi} +2y}=3}\)

\({:\implies \quad \displaystyle \sf k \lim_{y\to0}\dfrac{\sin (y)}{2y}=3}\)

Take ½ out of the limit as it's too constant ;

\({:\implies \quad \displaystyle \sf \dfrac{k}{2} \lim_{y\to0}\dfrac{\sin (y)}{y}=3}\)

Now , we also knows that ;

Using this we have ;

\({:\implies \quad \sf \dfrac{k}{2}=3}\)

\({:\implies \quad \bf \therefore \quad \underline{\underline{k=6}}}\)

Answer:

The answer to the question provided is 45.

Step-by-step explanation:

You add by ten.

The amount of time I seen this question-

Answer:

B

Step-by-step explanation:

Answer:

B. \(\frac{x^2}{3^2} +\frac{y^3}{2^2} =1\)

Step-by-step explanation:

Answer:

x= -5/3

Step-by-step explanation:

(you dont have to apologize for not knowing something <3)

Answer:

y = - 9

Step-by-step explanation:

Substitute in -1 for x

8(-1) - 2y = 10

-8 - 2y = 10

Subtract -8 from both sides

-8 - (-8) cancels out to 0

10 - (-8) = 18

We are left with:

-2y = 18

Divide by -2 on both sides.

-2y/-2 = y

18/-2 = -9

y = -9

The experimental probability of rolling a 1 or a 2 is 0.2.

Hence, Option A is correct.

We know that,

The experimental probability of an event is defined as the number of times the event occurred divided by the total number of trials.

In this case,

The event is rolling a 1 or a 3,

Which occurred ⇒  3 + 1

                           = 4 times.

Given that there are total number of trials = 20.

Therefore,

The experimental probability of rolling a 1 or a 3 = 4/20,

                                                                                = 1/5

                                                                                 = 0.2

Hence, the required probability is 0.2.

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The complete question is:

Sarah is playing a game in which she rolls a number cube 20 times. The results are recorded in the chart below. What is the experimental probability of rolling a 1 or a 3?

Number on cube:1,2,3,4,5,6

Number of times event occurs:3,6,1,5,3,2

A.0.2

B.0.3

C.0.6

D.0.83

Answer:

4 1/2

Step-by-step explanation:

Answer:

The answer is 90/20

Step-by-step explanation:

3 3/4:

3x4=12+3=15/4

Find out 5/6 reciprocal (Just turn it around)

6/5

Then your left with  15/4 x 6/5 (psssst You have to change the division symbol to multiplication!!)

15/4 x 6/5= 90/20

Answer:

35

Step-by-step explanation:

Add them together and then divide

Answer:

b + b + h + h

Step-by-step explanation:

You are finding the perimeter of the given rectangle. Note that by definition of a rectangle, the opposite parallel sides will have the same measurement. In this case, Terrance gives the expression of 2b + 2h, and so simply just expand the expression:

2b + 2h = b + b + h + h

~

Answer:

15c = m

Step-by-step explanation:

for every car she washes she learns 15 dollars. So you would multiply the number of cars she washes by 15 to get the amount she earns

Answer:

C

X=-16

Step-by-step explanation:

Answer:

f(3) = 4

Step-by-step explanation:

Give x = 3 in the interval x ≥ 1 then f(x) = x + 1 , and

f(3) = 3 + 1 = 4