Solve each problem. Show all work.
1. If the mass of an object is 5 kg and its velocity is 7.3 m/s, calculate the kinetic
energy

Option A provides the best minimum resolution distance among the given options, with a minimum resolution distance of approximately 233.33 nm.

To determine the best minimum resolution distance among the given options, we need to consider the principles of microscopy and the factors that affect resolution.

Resolution in microscopy is determined by the numerical aperture (NA) and the wavelength of light used. The formula for calculating the minimum resolvable distance (d) is given by:

d = λ / (2 * NA)

Where λ is the wavelength of light and NA is the numerical aperture.

Let's evaluate each option:

A. System using a wavelength of 280 nm with a numerical aperture of 0.6 in air.

d = 280 nm / (2 * 0.6) ≈ 233.33 nm

B. System using a wavelength of 250 nm with a sine of the angle of the light cone equal to 0.33 in immersion oil.

Here, we are not given the numerical aperture directly, but the sine of the angle (which is related to NA) and the immersion oil indicates a higher refractive index compared to air. However, we cannot directly compare this option to the others without more information.

C. System using a wavelength of 400 nm with a numerical aperture of 0.75 in air.

d = 400 nm / (2 * 0.75) ≈ 266.67 nm

D. System using a wavelength of 400 nm with an angle of the light cone being 72° in air.

Similarly to option B, we don't have the numerical aperture, only the angle of the light cone. Therefore, we cannot directly compare this option to the others.

E. Minimum resolution distance of 240 nm (no other information provided).

Comparing the calculated minimum resolution distances:

Option A: 233.33 nm

Option C: 266.67 nm

Option E: 240 nm

Based on these calculations, Option A provides the best minimum resolution distance among the given options, with a minimum resolution distance of approximately 233.33 nm.

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Answer:

Given

mass (m) =5kg

velocity (v) =6m/s

momentum (p) =?

Form

p=mv

5kgx6m/s

p=30kg.m/s

momentum =30kg.m/s

The correct diagram that represents magnetic field lines between two north magnetic poles is the option D. In a magnetic field, the field lines always emerge from the North Pole and enter the South Pole.

The magnetic field lines exert a force on other magnets, producing attraction or repulsion between them. The strength of the magnetic field depends on the distance between the poles, with the strength decreasing as the distance increases. The direction of the magnetic field is determined by the direction of the current. When two north magnetic poles are brought close together, they repel each other because they have the same polarity. On the other hand, two south poles will also repel each other. In contrast, a north pole and a south pole will attract each other.The magnetic field between two north poles can be visualized using magnetic field lines. These lines always travel from the north pole to the south pole and are drawn in a way that indicates the direction of the field at any given point. The diagram that represents magnetic field lines between two north magnetic poles is option D, as shown below: Therefore, the correct option is D.

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Answer:

any two difference between negative and positive charge

➢The matter is positively charged if it contains more protons than electrons, and it is negatively charged if it contains more electrons than protons.

Explanation:

I hope it will help you.....

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Explanation of how to solve a problem using the method of substitution. Please provide the problem that you need help with so that I can provide a detailed explanation.

Here is the general process for solving a problem using the method of substitution.

Step 1: Identify the function that can be expressed in terms of the other function.

Step 2: Express one of the variables in terms of the other by rearranging the equation.

Step 3: Substitute the expression for the variable in terms of the other variable into the other equation.

Step 4: Simplify the equation by combining like terms and solve for the remaining variable.

Step 5: Use the value of one of the variables to find the value of the other variable.

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A burette filled with water to a volume of 28 cm cubic is represented as a long cylindrical tube with a narrow neck, a stopcock, and a water level at 28 cm.

A burette is a laboratory equipment that is used to measure the volume of a liquid with a high degree of accuracy. It is usually made of glass and has a long,  cylindrical shape with a narrow neck and a stopcock at the bottom.

The burette is commonly used in chemistry experiments, particularly in titrations, to measure the volume of a liquid that is being added to a solution.

To draw a burette filled with water to a volume of 28 cm cubic, first, you will need to set up the burette on a stand. The burette should be clamped securely to the stand, and the stopcock should be closed to prevent any liquid from flowing out.

Next, you will need to fill the burette with water. To do this, you can use a funnel and slowly pour the water into the burette through the funnel. Make sure that there are no air bubbles in the burette and that the water level is below the zero mark on the burette.

To fill the burette to the desired volume of 28 cm cubic, you will need to slowly open the stopcock and let the water flow out until the water level reaches 28 cm cubic on the burette scale. It is important to take your time when filling the burette to ensure that you do not overshoot the desired volume.

Once you have filled the burette to the desired volume, you can close the stopcock to stop the flow of water. You should now have a burette filled with water to a volume of 28 cm cubic. Remember to record the volume measurement accurately to ensure the accuracy of your experiment.

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Answer:

Qualitative

Explanation:

Qualitative data is data that is measuring objects or anything physical with words.

Quantitative data is data that is measured using numerical factors like numbers.

So, to make a model of food you are measuring qualitative data since you're measuring types of food: ex-hamburgers, strawberries, cookies, etc.

Answer:

The correct answer is "64 J".

Explanation:

The given values are:

Mass,

m = 52 kg

Velocity,

v = 6 m/s

Mechanical energy,

= 1000 J

Now,

The gravitational potential energy will be:

⇒ \(P.E=1000-\frac{1}{2}mv^2\)

           \(=1000-\frac{1}{2}\times 52\times (6)^2\)

           \(=1000-26\times 36\)

           \(=1000-936\)

           \(=64 \ J\)

Answer: 6,277,647m

Explanation:

Radius of Earth = 6400km

To calculate the gravitational acceleration of a planet, we use the following formula:

g = mG/r^2

Gravitational acceleration is equal to the mass of the planet multiplied by the gravitational constant all divided by the radius of the planet squared.

We already know what the gravitational acceleration will be, 2.45m/s^2.

So, 2.45m/s^2 = mG/r^2

the mass of the earth is equal to 5.9*10^24.

And the gravitational constant is equal to 6.67408 * 10^-11.

We don't know the radius though.

2.45m/s^2 = 5.9*10^24 * 6.67408 * 10^-11 divided by r^2

2.45m/s^2 = 3.93 * 10^14 divide by r^2

Now, we can cross-multiply.

2.45m/s^2 * r^2 = 3.93 * 10^14

divide r^2 from both sides.

r^2 = 3.93 * 10^14 divided by 2.45m/s^2

r^2 = 1.6*10^14.

Now, take the square root of both sides.

r = 12,677,647 meters from the center of the Earth.

To calculate the height from the surface of the Earth, we need to subtract r by the Earth's radius.

That will be 12,677,647-6.400.000m = 6,277,647m from the surface of Earth.

Two details from the passage to show that the glowworm is a very unusual and beautiful insect are:

Glowworms are the larvae of certain species of insects that belong to the family Lampyridae, which includes fireflies. These larvae are bioluminescent, which means they can produce light through a chemical reaction in their bodies.

Glowworms are most often seen in dark environments, such as caves or forests at night. They use their light to attract prey, which includes small insects and other invertebrates.  The beauty and unusual nature of glowworms has captured the imagination of people for centuries. They are often associated with magic and mystery, and their ability to produce light without heat has been the subject of scientific investigation for many years.

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Answer:

I learned about human body, and cause of global warming.

Explanation:

These topics were so great to learn because I didn't know about Endocrine system, but now I know the job and the importance of  the Endocrine system. Also, I learned about global warming and I never knew what the cause of it was and it was great to learn new things!

Answer: Any chemical reaction is an example of a chemical change. Examples include: Combining baking soda and vinegar (which bubbles off carbon dioxide gas)Jan 13, 2020

Explanation:

If the bear is sliding down the tree at a constant velocity, that means that the net force acting on the bear is zero.

The force of gravity is pulling the bear downwards, while the friction force between the tree and the bear is acting upwards, opposing the force of gravity. We can use Newton's second law of motion, which states that the net force on an object is equal to the product of its mass and acceleration. In this case, the acceleration of the bear is zero, so the net force on the bear must also be zero. Therefore, the magnitude of the friction force must be equal to the magnitude of the force of gravity, which can be calculated as:
force of gravity = mass x acceleration due to gravity
force of gravity = \(200 kg * 9.81 m/s^2\)
force of gravity = 1962.0 N
So, the friction force between the tree and the bear is also 1962.0 N, and it acts upwards to balance the force of gravity.

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The force acting on the 12 kg mass would be 11 N.

To solve this problem, we need to use the work-energy principle, which states that the work done by a force on an object is equal to the change in the object's kinetic energy.

First, we need to calculate the initial and final kinetic energy of the 12 kg mass.

The initial kinetic energy is given by:

K₁ = (1/2) * m * v₁²

= (1/2) * 12 kg * (11 m/s)²

= 726 J

The final kinetic energy is given by:

K₂ = (1/2) * m * v₂²

= (1/2) * 12 kg * (26 m/s)²

= 936 J

The change in kinetic energy is:

ΔK = K₂ - K₁

= 936 J - 726 J

= 210 J

Next, we need to calculate the work done by the unknown force. We can do this by using the formula:

W = F * d * cosθ

where W is the work done, F is the force, d is the displacement, and θ is the angle between the force and displacement vectors.

In this case, the displacement is 22 meters, and the angle θ is 30 degrees. So we have:

W = F * d * cosθ

= F * 22 m * cos(30°)

= 19.1 F

Finally, we can use the work-energy principle to solve for the unknown force:

W = ΔK

19.1 F = 210 J

F = 11 N

Therefore, the force acting on the 12 kg mass is 11 N.

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Answer:

a. Yes, because the acceleration of the crate is 2.0 m/s².

Explanation:

Given

\(Force = 6N\) --- f

\(Mass = 3kg\) --- m

\(Time = 1.5s\) --- t

\(Velocity = 3.0m/s\) --- v

Required

Does the system support \(F=ma\)

Yes, it does and this is shown below

The crate is initially at rest; so:

\(u = 0\)

Using the first equation of motion

\(v = u + at\)

Substitute values for v, u and t

\(3 = 0 + a*1.5\)

\(3 = 1.5a\)

Make a the subject

\(a = 3/1.5\)

\(a = 2\)

Using \(F = ma\)

Substitute values for F and m

\(6 = 3 * a\)

Divide both sides by 3

\(6/3 = 3/3 * a\)

\(2 = a\)

\(a = 2\)

In both cases:

\(a = 2\)

Hence, option (a) is correct.

During vegetative propagation, a new plant grows from parts of the parent plant.

During binary fission, a cell divides to produce a new genetically identical cell.

Asexual reproduction involves fission, budding, fragmentation, and parthenogenesis, whereas sexual reproduction is achieved by combining the germ cells of two individuals. The statement describing asexual reproduction is Offspring are born that have the same DNA as the parent.

Only one parent is needed to produce a child. Includes cell division similar to cell division in mitosis. Asexual reproduction is a form of reproduction in which the offspring produced are exactly like their parents. Also, there is no formation of two different gametes, nor the involvement of two different sexes. In unicellular organisms, mitosis is the mode of asexual reproduction.

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Answer:     I

dk what rhe answer is but here is my prediction :)

Explanation:

If the rope is horizontal and the ball's speed is 10 m/s, what is the tension in the ... A 2 kg iron ball is swung in a horizontal circular path at the end of a 1.6 m length of rope. ... Freddie swings a 2 kg stone at the end of a thin rope of length 1.2 m. ... of an automobile tire that turns with a frequency of 11 Hz and has a linear speed ...

If the net force remains the same while the mass increases, the acceleration will be reduced.

The equation representing this relationship is

a = Fnet / m

Where "a" is the acceleration, "Fnet" is the net force, and "m" is the mass.

In the given scenario, the net force stays constant, meaning Fnet remains the same. However, the mass of the system increases.

When the mass of the system increases while the net force remains constant, the acceleration of the system decreases. This can be observed from the equation: if mass increases, the denominator of the equation increases, leading to a smaller overall result for acceleration.

In simpler terms, a larger mass requires more force to achieve the same acceleration. So, if the net force remains the same while the mass increases, the acceleration will be reduced.

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Answer:

positive direction with a changing velocity. An object which moves in the positive direction has a positive velocity. If the object is slowing down then its acceleration vector is directed in the opposite direction as its motion (in this case, a negative acceleration

1 ) Acceleration of the ball just before it strikes the ground = 10.67 m/s²

2 ) The initial speed of the ball = 1.15 m / s

3 ) The initial speed of the ball if the ball lands at 5.0 m/s = 3.2 m / s

v² = u² + 2 a s

v = Final velocity

u = Initial velocity

a = Acceleration

s = Displacement

1 ) In vertical motion,

v = 4 m / s

s = 0.75 m

u = 0

4² = 0 + ( 2 * a * 0.75 )

a = 16 / 1.5

a = 10.67 m / s²

2 ) The initial speed of the ball,

Resolving the velocity into its horizontal and vertical components,

\(V_{y}\)² = \(U_{y}\)² + 2 a s

\(V_{y}\)² = 0 + ( 2 * 9.8 * 0.75 )

\(V_{y}\) = 3.83 m / s²

V² = \(V_{x}\)² + \(V_{y}\)²

4² = \(V_{x}\)² + 3.83²

\(V_{x}\) = √ 16 - 14.67

\(V_{x}\) = 1.15 m / s

\(V_{x}\) = \(U_{x}\) = 1.15 m / s

3 ) If the ball lands with a speed of 5.0 m/s,

V² = \(V_{x}\)² + \(V_{y}\)²

5² = \(V_{x}\)² + 3.83²

\(V_{x}\) = √ 25 - 14.67

\(V_{x}\) = 3.2 m / s

\(V_{x}\) = \(U_{x}\) = 3.2 m / s

Therefore,

1 ) Acceleration of the ball just before it strikes the ground = 10.67 m/s²

2 ) The initial speed of the ball = 1.15 m / s

3 ) The initial speed of the ball if the ball lands at 5.0 m/s = 3.2 m / s

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Answer:

This is Newton's second law.

Newton's second law text:

(If a resultant force acts on a body, then an acceleration will give it an acceleration, the magnitude of which is directly proportional to the amount of the net force, and a direction is in the direction of the net force itself)

F=ma

net force = mass x acceleration

I hope I helped you^_^

Answer:

where is the box? how can we answer if your question is lack given? how do we know what box is it your talking about

Answer:

The correct option is;

c. 12.8 cm

Explanation:

The given parameters are;

The length of each spring = 12 m  = 0.12 m

Given that the masses and the springs are vertically oriented, we have;

The mass on the first spring = 3 × 6.4 = 19.2 kg

The weight on the first spring = 19.2 kg × 9.81 m/s² = 188.352 N

The extension of the first spring = 188.352 N/7,800 N/m ≈ 0.02415 m

The mass on the second spring = 2 × 6.4 = 12.8 kg

The weight on the second spring = 12.8 kg × 9.81 m/s² = 125.568 N

The extension of the second spring = 125.568 N/7,800 N/m ≈ 0.016098 m

The mass on the third spring = 1 × 6.4 = 6.4 kg

The weight on the third spring = 6.4 kg × 9.81 m/s² = 62.784 N

The extension of the third (bottom) spring = 62.784 N/7,800 N/m ≈ 0.00805 m

The total length of the bottom spring = Original length of the bottom spring + Extension of the bottom spring

The total length of the bottom spring ≈ 0.12 m + 0.00805 m = 0.12805 m

The total length of the bottom spring ≈ 0.12805 m ≈ 12.81 cm

The bottom spring will be approximately 12.81 cm long.

Biker 1's acceleration:

(25 mph) / (3 s) = ((25 mi/h) • (1/3600 h/s)) / (3 s) ≈ 0.00231 mi/s²

Biker 2's acceleration:

(85 mph) / (8 s) = ((85 mi/h) • (1/3600 h/s)) / (8 s) ≈ 0.00295 mi/s²

Biker 2 has the greater acceleration.

Answer:

The object would weight 63 N on the Earth surface

Explanation:

We can use the general expression for the gravitational force between two objects to solve this problem, considering that in both cases, the mass of the Earth is the same. Notice as well that we know the gravitational force (weight) of the object at 3200 km from the Earth surface, which is (3200 + 6400 = 9600 km) from the center of the Earth:

\(F_G=G\,\frac{M_E\,m}{d^2} \\28\,\,N=G\,\frac{M_E\,m}{9600000^2}\)

Now, if the body is on the surface of the Earth, its weight (w) would be:

\(F_G=G\,\frac{M_E\,m}{d^2} \\w=G\,\frac{M_E\,m}{6400000^2}\)

Now we can divide term by term the two equations above, to cancel out common factors and end up with a simple proportion:

\(\frac{w}{28} =\frac{9600000^2}{6400000^2} \\\frac{w}{28} =\frac{9}{4} \\\\ \\w=\frac{9\,*\,28}{4}\,\,\,N\\w=63\,\,N \\\)

The velocity v of the ocean freighter traveling 30° south of east is approximately are v = (25.98 km/hr eastward) + (15 km/hr southward)

To find the velocity v of an ocean freighter traveling 30° south of east at 30 km/hr, we can break down the velocity into its eastward and southward components.

Magnitude of velocity = 30 km/hr

Direction of velocity = 30° south of east

To find the eastward component, we can use trigonometry. The eastward component can be determined by multiplying the magnitude of the velocity by the cosine of the angle:

Eastward component = 30 km/hr * cos(30°)

Calculating the value:

Eastward component = 30 km/hr * cos(30°)

Eastward component = 30 km/hr * √3/2

Eastward component ≈ 30 km/hr * 0.866

Eastward component ≈ 25.98 km/hr

To find the southward component, we can again use trigonometry. The southward component can be determined by multiplying the magnitude of the velocity by the sine of the angle:

Southward component = 30 km/hr * sin(30°)

Calculating the value:

Southward component = 30 km/hr * sin(30°)

Southward component = 30 km/hr * 1/2

Southward component = 15 km/hr

Therefore, the velocity v of the ocean freighter traveling 30° south of east is approximately:

v = (25.98 km/hr eastward) + (15 km/hr southward)

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Answer: A. When half the parent nuclei in a sample have become daughter nuclei

Explanation:

Answer:

fluid transfer of heat by the motion of the particles of gas or fluid