Answer:
b= -8
Step-by-step explanation:
just trust me dude. I know what I'm doing
A bowling ball has a diameter of 8.5 inches. If it is rolled down a 60-foot bowling lane, how many complete revolutions will it make? Round to the nearest tenth.
Worth 25 points!!
Answer:
27 revolutions
Step-by-step explanation:
Things to remember :
One revolution = distance of circumference coveredcircumference = 2πrdiameter = 2 x radiusSolving
One revolution = 2 x π x d/2 = πdOne revolution = 3.14 x 8.5One revolution = 26.69 inchesNo. of revolutions = Distance / one revolutionNo. of revolutions = 60 x 12 / 26.69No. of revolutions = 720 / 26.69No. of revolutions = 27 revolutionsSuppose you want to test the claim that μ > 28.6. Given a sample size of n = 62 and a level of significance of . When should you reject H0?
We reject H0 when the calculated t-statistic is greater than 1.67.
To determine when to reject the null hypothesis (H0) that μ = 28.6, we need to conduct a hypothesis test using a t-test with a one-tailed alternative hypothesis. Since the alternative hypothesis is μ > 28.6, this is a right-tailed test.
First, we need to calculate the t-statistic using the formula:
t = (x - μ) / (s / √(n))
where x is the sample mean, μ is the hypothesized population mean, s is the sample standard deviation, and n is the sample size.
Next, we need to find the critical t-value from the t-distribution table using the degrees of freedom (df) which is n - 1. Since the level of significance is not given in the question, we will assume it to be 0.05. This means that the critical t-value for a one-tailed test with 61 degrees of freedom is 1.67.
If the calculated t-statistic is greater than the critical t-value, we reject the null hypothesis. If the calculated t-statistic is less than or equal to the critical t-value, we fail to reject the null hypothesis.
Therefore, we reject H0 when the calculated t-statistic is greater than 1.67.
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2
The table represents a linear function.
Input
-8
-6
2
Output
18
13
-7
-17
6
Which equation best represents the function?
A y = -52 - 2
By = -52 +3
5
2
- 3
For the following function find the coordinates of all local maxima and local minima. y = ln x – x?, with x > 0 Use the second derivative test to confirm whether the turning points are local maxima or local minima.
The function y = ln(x) - x^2 has two local maxima at x = √(1/2) and x = -√(1/2).
To find the local maxima and minima of the function y = ln(x) - x^2, we need to find the critical points by taking the derivative and setting it equal to zero:
y = ln(x) - x^2
y' = 1/x - 2x
Setting y' = 0, we have:
1/x - 2x = 0
Simplifying, we get:
1 - 2x^2 = 0
2x^2 = 1
x^2 = 1/2
x = ±√(1/2)
So the critical points are x = √(1/2) and x = -√(1/2). To determine whether these critical points correspond to local maxima or minima, we can use the second derivative test.
Taking the second derivative of the function:
y'' = -1/x^2 - 2
For x = √(1/2):
y'' = -1/(√(1/2))^2 - 2 = -1/1/2 - 2 = -2 - 2 = -4
Since the second derivative is negative, this confirms that x = √(1/2) is a local maximum.
For x = -√(1/2):
y'' = -1/(-√(1/2))^2 - 2 = -1/1/2 - 2 = -2 - 2 = -4
Again, the second derivative is negative, confirming that x = -√(1/2) is also a local maximum.
Therefore, the function y = ln(x) - x^2 has two local maxima at x = √(1/2) and x = -√(1/2).
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What is answer to x+4
Answer:
4x
Step-by-step explanation:
I think the answer is 4X.on the other hand, I think the answer is x + 4 because we were told you can't mix goats with cows.it is the same thing with x + 4 so if the answer isn't 4 x it is x + 4 I'm not quite sure which is the answer hope it helps.
Need help ASAP really lost
Answer:63
Step-by-step explanation:
Unit 3 parallel and perpendicular lines Homework 2, please help quickly
Answer:
Step-by-step explanation:
Since, lines l and m are parallel and a transverse is intersecting these lines.
5). (9x + 2)° = 119° [Alternate intrior angles]
9x = 117 ⇒ x = 13
6). (12x - 8)° + 104° = 180°
12x = 180 - 96
x = \(\frac{84}{12}\) ⇒ x = 7
7). (5x + 7) = (8x - 71) [Alternate exterior angles]
8x - 5x = 71 + 7
3x = 78
x = 26
8). (4x - 7) = (7x - 61) [Corresponding angles]
7x - 4x = -7 + 61
3x = 54
x = 18
9). (9x + 25) = (13x - 19) [Corresponding angles]
13x - 9x = 25 + 19
4x = 44
x = 11
(13x - 19)° + (17y + 5)° = 180°[Linear pair of angles are supplementary]
(13×11) - 19 + 17y + 5 = 180
129 + 17y = 180
17y = 180 - 129
y = 3
10). (3x - 29) + (8y + 17) = 180 [linear pair of angles are supplementary]
3x + 8y = 180 + 12
3x + 8y = 192 -----(1)
(8y + 17) = (6x - 7) [Alternate exterior angles]
6x - 8y = 24
3x - 4y = 12 -----(2)
Equation (1) - equation (2)
(3x + 8y) - (3x - 4y) = 192 - 12
12y = 180
y = 15
From equation (1),
3x + 8(15) = 192
3x + 120 = 192
x = 24
11). (3x + 49)° = (7x - 23)° [Corresponding angles]
7x - 3x = 49 + 23
4x = 72 ⇒ x = 18
(11y - 1)° = (3x)° [Corresponding angles]
11y = 3×18 + 1
11y = 55 ⇒ y = 5
12). (5x - 38)° = (3x - 4)° [Corresponding angles]
5x - 3x = 38 - 4
2x = 34
x = 17
(7y - 20)° + (5x - 38)° + 90° = 180°
[Sum of interior angles of a triangle = 180°]
7y + 5x - 58 = 90
5x + 7y = 148
5×17 + 7y = 148
85 + 7y = 148
7y = 148 - 85
y = \(\frac{63}{7}=9\)
Angles can be congruent based n several theorems; some of these theorems are: corresponding angles, vertical angles, alternate exterior angles and several others.
The values of x and y are:
5. \(\mathbf{x = 13}\)6. \(\mathbf{x = 7}\)7. \(\mathbf{x= 26}\)8. \(\mathbf{x = 18}\)9. \(\mathbf{x = 11}\) and \(\mathbf{y = 7}\)10. \(\mathbf{x = 24}\) and \(\mathbf{y = 15}\)11. \(\mathbf{x = 18}\) and \(\mathbf{y =5}\)12. \(\mathbf{x = 17}\) and \(\mathbf{y=9}\)Question 5:
Angles (9x + 2) and 119 are alternate angles.
Alternate angles are equal. So, we have:
\(\mathbf{9x +2 = 119}\)
Subtract 2 from both sides
\(\mathbf{9x = 117}\)
Divide both sides by 9
\(\mathbf{x = 13}\)
Question 6:
Angles (12x - 8) and 104 are interior angles.
Interior angles add up to 180. So, we have:
\(\mathbf{12x -8 + 104 = 180}\)
Collect like terms
\(\mathbf{12x = 180 - 104 + 8}\)
\(\mathbf{12x = 84}\)
Divide both sides by 12
\(\mathbf{x = 7}\)
Question 7:
Angles (5x + 7) and (8x - 71) are alternate exterior angles.
Alternate exterior angles are equal. So, we have:
\(\mathbf{5x + 7 = 8x - 71}\)
Collect like terms
\(\mathbf{8x - 5x= 71 + 7}\)
\(\mathbf{3x= 78}\)
Divide both sides by 3
\(\mathbf{x= 26}\)
Question 8:
Angles (4x - 7) and (7x - 61) are corresponding angles.
Corresponding angles are equal. So, we have:
\(\mathbf{4x - 7 = 7x - 61}\)
Collect like terms
\(\mathbf{4x - 7x = 7 - 61}\)
\(\mathbf{- 3x = -54}\)
Divide both sides by -3
\(\mathbf{x = 18}\)
Question 9:
Angles (9x + 25) and (13x - 19) are corresponding angles.
Corresponding angles are equal. So, we have:
\(\mathbf{9x + 25 = 13x - 19}\)
Collect like terms
\(\mathbf{9x -13x = -25 - 19}\)
\(\mathbf{-4x = -44}\)
Divide both sides by -4
\(\mathbf{x = 11}\)
Angles (17y + 5) and (13x - 19) are supplementary angles.
So, we have:
\(\mathbf{17y + 5 = 13x - 19}\)
Substitute 11 for x
\(\mathbf{17y + 5 = 13\times 11 - 19}\)
\(\mathbf{17y + 5 = 124}\)
Subtract 5 from both sides
\(\mathbf{17y = 119}\)
Divide both sides by 17
\(\mathbf{y = 7}\)
Question 10:
Angles (3x - 29) and (6x - 7) add up to 180
So, we have:
\(\mathbf{3x -29 + 6x - 7 = 180}\)
Collect like terms
\(\mathbf{3x + 6x = 180 + 7 + 29}\)
\(\mathbf{9x = 216}\)
Divide both sides by 9
\(\mathbf{x = 24}\)
Angles (3x - 29) and (8y + 17) are supplementary angles.
So, we have:
\(\mathbf{3x - 29 + 8y + 17 = 180}\)
Substitute 24 for x
\(\mathbf{3 \times 24 - 29 + 8y + 17 = 180}\)
\(\mathbf{43 + 8y + 17 = 180}\)
Collect like terms
\(\mathbf{8y = 180 - 43 - 17}\)
\(\mathbf{8y = 120}\)
Divide both sides by 8
\(\mathbf{y = 15}\)
Question 11:
Angles (7x - 23) and (49 + 3x) are corresponding angles
So, we have:
\(\mathbf{7x - 23 = 49 + 3x}\)
Collect like terms
\(\mathbf{7x - 3x = 49 + 23}\)
\(\mathbf{4x = 72}\)
Divide both sides by 4
\(\mathbf{x = 18}\)
Angles 3x and (11y - 1) are corresponding angles.
So, we have:
\(\mathbf{3x = 11y - 1}\)
Substitute 18 for x
\(\mathbf{3 \times 18 = 11y - 1}\)
\(\mathbf{54 = 11y - 1}\)
Collect like terms
\(\mathbf{11y =54+ 1}\)
\(\mathbf{11y =55}\)
Divide both sides by 11
\(\mathbf{y =5}\)
Question 12:
Angles (5x - 38) and (3x - 4) are corresponding angles
So, we have:
\(\mathbf{5x - 38 = 3x - 4}\)
Collect like terms
\(\mathbf{5x - 3x = 38 - 4}\)
\(\mathbf{2x = 34}\)
Divide both sides by 2
\(\mathbf{x = 17}\)
Angles (7y - 20) and (5x - 38) are angles at the other legs of a right-angled triangle.
So, we have:
\(\mathbf{7y - 20 +5x - 38 = 90}\)
Substitute 17 for x
\(\mathbf{7y - 20 +5 \times 17 - 38 = 90}\)
\(\mathbf{7y+ 27 = 90}\)
Collect like terms
\(\mathbf{7y=- 27 +90}\)
\(\mathbf{7y=63}\)
Divide both sides by 7
\(\mathbf{y=9}\)
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Thirty-seven students in a math course, which was 96% of the students registered in the course, earned a passing grade for the course. Find the number of students registered for the math course.
Answer:
39
Step-by-step explanation:
37 = 96 %
x = 100%
\(x =\frac{37(100)}{96} =38.54= 39\)
\(\huge\boxed{39\ \text{students}}\)
Note: The numbers in this problem are a little weird and don't work out perfectly. I'll demonstrate at the end of this answer how something seems a little off in the problem, but we'll get as close as possible.
SolvingWe know from the problem that 37 students are equal to 96% of the class.
Let's write this as an equation:
\(37=0.96x\)
Divide both sides of the equation by \(0.96\) to isolate \(x\).
\(38.54\approx x\)
We'll round this to \(39\) as the final answer.
Why this doesn't seem quite rightIt's important to note that you can't have partial students, only whole numbers.
If we do the math here, 37 out of 39 students is about 95%.
Also, 37 out of 38 is about 97%.
I'm not sure how the original writer of the question got 96%, but I suppose 39 is the best answer with what's been given.
what is the difference between brackets and parentheses in math?
41
3) Simplify
es is
and evaluate the below expressions for x = 2, y = 1
9x²-
i) 9x² - xy + 6x -4y + 5xy - 4x + 2x² + 3y
ху
+2x+
Answer:
Step-by-step explanation:
\(11x^{2} + 4 x y + 2x - y\)
suppose ax=b has a solution. explain why the solution is unique precisely when ax=0 has only the trivial solution.
Translation of the Ax=0 solution set yields the Ax-b solution set since Ax-b is consistent. The Ax = b solution set is therefore a single vector if and only if the Ax = 0 solution set is a single vector, which occurs if and only if Ax 0 has only the trivial solution.
what is solution ?Finding the solution to an equation is like finding the solution to a puzzle. A mathematical equation proves the equality of two algebraic expressions. Determine the values of the variables that make the equation a true statement in order to solve an equation. An equation's solution is any value that causes the equation to be true.
given
Let's suppose that there is a solution to the equation ax = b.
Now, we want to demonstrate that the trivial solution exists for the equation ax = b when ax = 0.
Ax = 0 is homogeneous.
In the event that this equation was true for b, we define
To be a set of vectors with the form ax = b
w = m + gh
The subscript "h"
A solution to ax = 0 is gh.
Ax=b is in the form of w= m+gh based on the information we know had.
with
m = ax=solution b's
Soulution of gh = ax=0
Only a simple solution, ax = 0, exists.
gh = 0
where gh = 0
The relationship between ax=b and w=m
Ax = b thus has no alternative solutions.
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which is the value of x makes this inequality true?
thank you for helping!
x +9 < 4x
a.1
b.3
c.4
d.2
Answer:
x>3
Step-by-step explanation:
x+9<4x
9<4x-x
9<3x
3x>9
x>9/3
x>3
Please help me! Find the value of z!!!!
Answer:
20 degrees
Step-by-step explanation:
Angles on the edge of the circle are equal to 1/2 of the arc it forms, so that means angle z is one half of 40 degrees. 1/2 * 40 = 20 degrees.
Find the value of r so the line that passes through each pair of points has the given slope: 5/6. Pair of points are (5,2) and (-7,r).
Answer:
r = -8
Step-by-step explanation:
The slope of a line can be found using the slope formula or
\(m=\frac{y_{2}-y_{1} }{x_{2} -x_{2} }\), where x2 and y2 are any of the two coordinate and x1 and y1 are the other pair of coordinates.
Since we have the slope and three points, we find r by plugging everything in:
\(\frac{5}{6}=\frac{r-2}{-7-5}\\ \frac{5}{6}=\frac{r-2}{-12}\\ -10=r-2\\ -8=r\)
What is the y-intercept of 2x y =- 3?
The y-intercept of the equation 2x - y = -3 is 3 and in ordered pair form is (0,3).
What is the y-intercept of the given equation?The slope-intercept formula is expressed as;
y = mx + b
Where m is slope and b is y-intercept.
Given the equation in the question
2x - y = -3
First, we solve form for y and reorder in slope intercept form.
2x - y = -3
Subtract 2x from both sides
2x - 2x- y = -3 - 2x
- y = -3 - 2x
Divide each term by -1
y = 3 + 2x
Reorder in slope intercept form
y = 2x + 3
To find the y-intercept, replace x with zero and solve for y
y = 2(0) + 3
y = 3
Therefore, the y-intercept is 3.
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yo someone answer this and FAST. At Westside Middle School, 10 percent, or 140 students, participate in soccer. How many students are in the school? Check all that apply.
The total number of students is greater than 140.
The total number of students is less than 140.
(10)(14) = 140, so 100(14) = 1,400 students.
140 + 10 = 150, so 150 + 140 = 290 students.
There are 140 + 10 = 150 students at Westside Middle School.
The percent as a part to the whole ratio is StartFraction 140 Over 100 EndFraction
The percent as a part to the whole ratio is StartFraction 10 Over 100 EndFraction
Answer:
1400
Step-by-step explanation:
Let x= total number of students
10% of students is also 140 students
i.e 10% of x =140
10/100*x=140
10x/100=140
10x=14000
x=14000/10
x=1400
In parallelogram HIJK, the measure of angle H is 45∘.
Find the measure of angle J. Explain how you know.
Find the measure of angle K. Explain how you know.
Answer:
Step-by-step explanation:
Prior to May 1, Fortune Company has never had any treasury stock transactions. The company repurchased 240 shares of its common stock on May 1 for $12,000. On July 1, it reissued 120 of these shares at $52 per share. On August 1, it reissued the remaining treasury shares at $49 per share. What is the balance in the Paid-in Capital, Treasury Stock account on August 2
According to the situation in question, the balance in the Paid-in Capital, Treasury Stock account on August 2 is -$120. This suggests that there is a deficit in the account for the company.
We must determine the treasury stock transactions and figure out the net impact on the account in order to ascertain the amount in the Paid-in Capital, Treasury Stock account on August 2.
On May 1, for a total of $12,000, Fortune Company repurchased 240 shares of its ordinary stock. The Paid-in Capital, Treasury Stock account's balance is decreased by this transaction. A debit is made from the Treasury Stock account to reflect the cost of the Treasury stock.Treasury Stock (debit) = $12000
On July 1, 120 of these shares were reissued by the business for $52 each. The Paid-in Capital, Treasury Stock account now has more money in it as a result of this transaction. Treasury Stock account is recorded as receiving a credit for the reissued stock's proceeds.Treasury Stock: $52 x 120 = $6,240(credit)
On August 1, The remaining treasury shares were reissued for $49 each. This raises the balance in the Paid-in Capital, Treasury Stock account in a manner similar to the preceding transaction.Treasury Stock: $49 x 120 = $5,880 (credit)
We must determine the net impact of these transactions in order to determine the balance in the Paid-in Capital and Treasury Stock account on August 2. We deduct all of the credits from all of the debits.
Total Debits = $12,000.
Total credits: $12,120 ($6,240 + $5,880).
Paid-in Capital and Treasury Stock account balance as of August 2:
$12,000 (debt) - $12,120 (credit) = -$120.
Therefore, on August 2, there are -$120 in the Paid-in Capital, Treasury Stock account.
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What is the conversion of 2/5 in decimal ?
The conversion of a fraction number with denominator 5 and numerator 2 , 2/5 in decimals is equals to the 0.4 value.
A decimal number can be defined as a number whose whole number part and fractional part are separated by a decimal point. Writing 2/5 as a decimal number by converting the denominator to powers of 10. We multiply the numerator and denominator by a number so that the denominator is a power of 10.
2/5 = (2 × 2) / (5 × 2) = 4/10
Now move the decimal point to the left as many places as there are zeros in the denominator, which is a power of 10.
The decimal moved one place to the left because the denominator was 10. Therefore, 4/10 = 0.4. Hence, required value is 0.4.
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By selling a watch on 400 and 460’. Loss and profit happened respectively.if the loss and profit are equal, find cp.
Answer:
430
Step-by-step explanation:
Given :-
By selling a watch on 400 and 460’. Loss and profit happened respectively.The loss and profit are equal.And we need to find out the CP .So ,
Let :-
CP be xProfit and Lost be y .According to the Question :-
\(:\implies\) 460 = x + y ( Profit)
\(:\implies\) 400 = x - y ( Loss)
Adding both :-
\(:\implies\) 460 + 400 = x + y + x - y
\(:\implies\) 860 = 2x
\(:\implies\) x = 860/2
\(:\implies\) x = 430
Hence the Cost price of the watch is 430 .
Please help will give brainlest
Consider the simple random graph constructed as follows. There are n > 2 vertices V1, V2, ..., Vn that comprise the vertex set V. Each pair of vertices is adjacent with probability p, where pe [0, 1], independently of other pairs of vertices. Let G' be a fixed graph such that • The vertex set of G' is V' = {V1, V2, Vm}, with 2 1 edges. = ...) What is the probability that G' is a subgraph of G?
The probability that a fixed graph G' with vertex set V' and edge set E' is a subgraph of a simple random graph G with vertex set V and edge set E can be calculated using the probability parameter p.
To determine the probability that G' is a subgraph of G, we consider the edges in G' and calculate the probability that each edge exists in G. Since the edges in G are determined independently with probability p, the probability that each edge in G' is present in G is simply p. As there are 2^(|E'|) possible subgraphs of G' and each has a probability of p^(|E'|) of occurring, the probability of G' being a subgraph of G is (p^|E'|).
Note that this analysis assumes that the graph G is a simple random graph, where each pair of vertices is adjacent with probability p independently. The specific value of p and the structure of G' determine the probability of G' being a subgraph of G.
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Round 6.09933418366 to 4 decimal places.
Answer:
6.0993
.................
Answer:
Step-by-step explanation:
If you want to round to 4 decimal places, look onto the 5th decimal place. If 5th decimal place is 5 ,6,7,8 or 9 then add to the 4th decimal place. If the 5th decimal place hold 1,2,3 or 4 then write the 4th decimal place as it is.
6.09933418366
Here, 5th decimal place is 3.
So, 6.0993 is the answer
what fraction is not equivalent to 2/6? 1/3, 12/36, 4/12, 6/9
Answer:
6/9
Step-by-step explanation:
1/3 is half 12/36 is 2×6 and 6×6 4/12 is 2×2 and 6×2 making 6/9 the odd one out as 6 can't go into 9 without making a decimal
Given the following information calculate the EAC and select from list below. Project is planned for 12 months
PV $30000
EV $26000
AC$29000
BAC $252000
a. $293,023.25
b. $296,023.78
c. $197, 043.96
d. $256,354,47
The correct answer for the Estimate at Completion (EAC) based on the given information is not among the provided options. The calculated EAC = $319,772.19.
Given the following information calculate the EAC and select from the list below. The project is planned for 12 months PV $30000 EV $26000 AC$29000 BAC $252000.The correct answer is option A) $293,023.25.
What is EAC? EAC (Estimate at Completion) refers to the total expected cost of the project. EAC includes the actual cost incurred to date as well as the expected cost required to complete the remaining project work.
The formula for EAC is as follows:
EAC = AC + (BAC - EV) / (CPI * SPI)
EAC= Estimated Cost at Completion, BAC= Budget at Completion, AC= Actual Cost, CPI= Cost Performance Index, SPI= Schedule Performance Index, EV= Earned Value, and PV= Planned Value.
Given, PV (Planned Value) = $30000EV, (Earned Value) = $26000, AC (Actual Cost) = $29000, BAC (Budget at Completion) = $252000.
Now, calculate CPI and SPI.
CPI (Cost Performance Index) = EV / AC = 26000 / 29000 = 0.8965SPI
(Schedule Performance Index) = EV / PV = 26000 / 30000 = 0.8667
Calculate EAC using the following formula:
EAC = AC + [(BAC - EV) / (CPI * SPI)]EAC = 29000 + [(252000 - 26000) / (0.8965 * 0.8667)]
EAC = 29000 + [226000 / 0.7773]
EAC = 29000 + 290772.19
EAC = $319,772.19
Therefore, the correct answer is not in the given options.
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Select the correct answer from each drop-down menu. (Will give brainliest)
(Picture below options are 19.5, 29, 58 for both multiple choice)
The angle BAC will be 29 and the angle BOC will be 58.
What is the circle theorem?The angle in a circle's centre is twice that at its perimeter when two angles are subtended by the same arc. So, angle AOB = 2 angle ACB. Angles that the same arc subtends at its circumference are equal. As a result, angles inside a section are equal.
Here the given angle is ∠BDC = 29 so from the given theorem the angle BEC will be equal to the angle BDC.
∠BDC = 29
The centre angle BOC will be twice the angle at the circumference so the angle will be twice.
∠BOC = 59
Therefore the angle BAC will be 29 and the angle BOC will be 58.
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On a photograph an ant is enlarged at a scale 25:1. In the photo, the ants leg is 15 cm. What is the actual length of the ants leg?
Answer:
0.6cm
Step-by-step explanation:
25 : 1
1 : 0.04
15 : 0.6
Consider the value of t such that the area under the curve between Il and ll equals 0.95 Step 2 of 2: Assuming the degrees of freedom equals 8, select the t value from the t table. Answer TablesKeypad To select a value from the table either click the cell at the intersection of the row and column or use the arrow keys to find the appropriate cell in the table and select it using the Space key. To change the sign of the selected value, use the +1- button.
The value of t such that the area under the curve between 1 and 11 equals 0.95, assuming the degrees of freedom is 8, is 1.86.
What is degree of freedom?Degree of freedom refers to the number of independent variables that can be varied in a statistical experiment or analysis. It is a measure of the flexibility of the experiment or analysis to accommodate new data or observations.
In this case, the degrees of freedom is 8. To find the t-value, the t-table must be consulted. The t-table is a chart of t-values for different degrees of freedom. The t-value is the value at which the area under the curve between 1 and 11 equals 0.95. The t-table is organized such that the rows represent the degrees of freedom and the columns represent the area under the curve. For example, if the degrees of freedom is 8 and the area under the curve is 0.95, the t-value can be found in the row for 8 degrees of freedom and the column for 0.95 area under the curve. The t-value from the t-table in this case is 1.86.
Therefore, the value of t such that the area under the curve between 1 and 11 equals 0.95, assuming the degrees of freedom is 8, is 1.86.
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The value of t such that the area under the curve between 1 and 11 equals 0.95, assuming the degrees of freedom is 8, is 1.86.
What is degree of freedom?Degrees of freedom refer to the number of independent variables that can be varied in a statistical experiment or analysis. It is a measure of experimental or analytical flexibility to accommodate new data or observations.
In this case there are 8 degrees of freedom. To find the t value, we need to refer to the t table. A t-table is a plot of t-values for different degrees of freedom. The t-value is the value at which the area under the curve between 1 and 11 is 0.95. The t-table is organized so that rows represent the degrees of freedom and columns represent the area under the curve. For example, if you have 8 degrees of freedom and the area under the curve is 0.95, find the t-value in the row with 8 degrees of freedom and the column with area under the curve of 0.95. In this case, the t-value in the t-table is 1.86.
Therefore, the value of t is such that the area under the curve between 1 and 11 is 0.95, assuming 8 degrees of freedom is 1.86.
The area between -t and t = 0.95
P(t₈ > t) = P(t₈ - t)
= 0.025
As t - distⁿ is symmetrical and are under the curve is 1 and degree of freedom is 8.
Hence, from t - table; the t - value = 2.306
i.e. P(t₈ > 2.306) = 0.025
or P(-2.306 < t₈ < 2.306) = 0.95
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The complete question is as follows:
pls pls pls help me Find x.
Answer:
29 degrees
Step-by-step explanation:
The arc intercepted by inscribed angle x = 360 -180 -122 = 58 degrees
inscribed angles intercept twice as many degrees of arc
x = 58/2 = 29 degrees
*Binomial Distribution*
(5 pts) A certain insecticide kills 70% of all insects in laboratory experiments. A sample of 10 insects is exposed to the insecticide in a particular experiment. What is the probability that exactly
The probability that exactly 5 insects will die from the sample is 0.0761.
Binomial distribution is a probability distribution of random variables with two possible outcomes. It applies when the following conditions are met: the outcome of the trial is binary, each trial is independent, the probability of success is constant and the number of trials is fixed.In a certain experiment, an insecticide killed 70% of all insects. A sample of 10 insects is exposed to the insecticide. The probability of the sample size is given by Binomial distribution. To find the probability that exactly a certain number of insects die from the sample, we use the following formula:
P (X = k) = n C k * p^k * (1 - p)^(n-k)
Where, n is the sample size,
p is the probability of success,
k is the number of successes and
C represents the combination.
P (X = k) is the probability of getting exactly k successes.
The probability of killing exactly x insects is shown as:P(X= x) = C(10,x) (0.7)^x (0.3)^(10-x)P(X = x) = (10!/(x! * (10 - x)!) * (0.7)^x * (0.3)^(10-x)
Thus, for exactly, five insects dying, the probability is:P(X = 5) = C(10,5) (0.7)^5 (0.3)^5P(X = 5) = 252 * 0.16807 * 0.00243P(X = 5) = 0.0761
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