Solve -3(x+4) = 7x + 4 all steps

Converting expressions with negative exponents to equivalent forms without negative exponents involves applying rules such as taking reciprocals and transforming negative exponents into positive exponents.

(2/5)⁻¹ = 5/2
6/x⁻² = 6x²
(-3/2)⁻³ = (-2/3)³ = 8/27
6xy/3x⁻¹y⁻² = 2xy²
(2x²/3x⁻¹)⁻² = (3x/2x²)² = (3/4x)² = 9/16x²

Converting expressions with negative exponents to equivalent forms without negative exponents requires applying specific rules. These rules include taking the reciprocal of a fraction to swap the numerator and denominator, transforming negative exponents into positive exponents by changing their position in the fraction, and simplifying expressions by combining like terms. By following these rules, we can convert the given expressions into equivalent forms without negative exponents.

For example, converting (2/5)⁻¹ results in 5/2 by taking the reciprocal. Likewise, 6/x⁻² becomes 6x² by changing the position of x⁻² to 1/x². Similarly, (-3/2)⁻³ transforms into 8/27 by changing the position of -3 to 2 and taking the reciprocal. The expression 6xy/3x⁻¹y⁻² simplifies to 2xy² by changing x⁻¹ to 1/x and y⁻² to 1/y². Lastly, (2x²/3x⁻¹)⁻² simplifies to 9/16x² by changing the position of the entire fraction and eliminating the negative exponent.

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Answer:

(3, 2)

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Equality Properties

Algebra I

Step-by-step explanation:

Step 1: Define Systems

y = 2x - 4

y = -x + 5

Step 2: Solve for x

Substitution

Step 3: Solve for y

The frequencies are 3, 4, 4, 3, and 2 and the required histogram is given below.

A histogram is a graphical representation of the distribution of numerical data. It consists of a series of rectangles, where the area of each rectangle corresponds to the frequency or proportion of observations falling within a certain class or bin.

The horizontal axis of a histogram represents the range of values in the data, which is divided into equal-sized intervals called bins. The vertical axis represents the frequency or proportion of observations that fall into each bin.

Here we have

The scores of sixteen students are

77, 86, 83, 89, 73, 79, 82, 74, 84, 80, 78, 90, 74, 81, 85, 78  

To calculate the frequencies count the number of marks in given intervals

Hence, The frequencies are

Test scores       Frequency

72 - 75                3        

76 - 79                4    

80 - 83                4

84 - 87                 3  

88 - 91                 2    

As per the given explanation, we can draw the histogram as shown below

Therefore,

The frequencies are 3, 4, 4, 3, and 2 and the required histogram is given below.

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The slope and y-intercept of the given equations of line are shown below.

When any equation is represented in the y = mx +c form, it is called the slope intercept from of the equation.

Here m is slope and c is constant.

(1)

y = 3x + 3

Slope m = 3

y intercept, at x =0,

y = 3

(2)

y = 3x - 3

Slope m = 3

y intercept, at x =0,

y = - 3

(3)

y = (1/3)x + 3

Slope m = 1/3

y intercept, at x =0,

y = 3

(4)

y = -(1/3)x + 3

Slope m = -1/3

y intercept, at x =0,

y = 3

(5)

y = (1/3)x - 3

Slope m = 1/3

y intercept, at x =0,

y = -3

(6)

y = -(1/3)x - 3

Slope m = -1/3

y intercept, at x =0,

y = -3

(7)

y = -3x + 3

Slope m = -3

y intercept, at x =0,

y = 3

(8)

y = -3x - 3

Slope m = -3

y intercept, at x =0,

y = - 3

The slope and y-intercept are shown above.

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Answer: x = 136.4 minutes

Step-by-step explanation:

x = (100/22)(30) minutes = 136.4 minutes

rand() % 6 expression is most appropriate for randomly choosing a day of the week .

Rand generates random number and This number is produced using an algorithm that, each time it is run, outputs a string of numerical values that seem unrelated.

A % B generates the number less than or equal to the B.

Therefore , for randomly choosing a day of the week we can use  rand() % 6 as there are 7 days in a week and  rand() % 6 returns any number between 0 to 6 as Total 7 days.

The best statement for choosing a day of the week at random is rand()% 6.

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Answer:

144

Step-by-step explanation:

12 * 12 = 144

Answer:

It's 144.

..............

Using the sine rule and triangle ABC,   the height  is 14.43375ft. BAC=40° and ABC=30°

if C is 20° and  A is 50°

ABC=50°-20°=30°

BCA=20°+90°=110°

ABC+BCA+BAC=180°

30°+110°+BAC=180°

BAC=180°-140°=40°

Using the sine rule and triangle ABC,

opposite=x

adjacent =25 m.

tanθ =x/25

Multiplying both sides by 25 gives

x=25* tan 30° =25* 0.57735.=14.43375

To put it another way, there is only one plane that contains all of the triangles. All triangles are enclosed in a single plane on the Euclidean plane, however this is no longer true in higher-dimensional Euclidean spaces. Unless otherwise specified, this article deals with triangles in Euclidean geometry, specifically the Euclidean plane.

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The 95% confidence interval for the mean times teenagers think about food in one day is (97.22, 102.78).

A study of 50 teenagers revealed that the average number of times they thought about food in one day was 100 times with a standard deviation of 10. Develop a 95% confidence interval of the mean times teenagers think about food in one day.

In order to develop the 95% confidence interval, we must determine the test statistics.

The z-test is used to determine the test statistics, and it is defined as the difference between the sample mean and the population mean divided by the standard deviation:

z = (X - μ) / (σ / √n)

Where, X = sample mean

μ = population mean

σ = standard deviation

n = sample size

Substitute the given values, σ = 10, n = 50, μ = 100.

Using the above formula, we can determine the test statistics,

z = (X - μ) / (σ / √n)

z = (100 - 100) / (10 / √50)

z = 0

Thus, the test statistics is 0. Now, we can use the test statistics and a z-table to find the critical value of z for a 95% confidence interval. The z-table indicates that the critical value of z for a 95% confidence interval is 1.96.

Using this value and the formula for the confidence interval, we can determine the 95% confidence interval of the mean times teenagers think about food in one day: CI = X ± (z * σ / √n)

CI = 100 ± (1.96 * 10 / √50)

CI = 100 ± 2.78

Therefore, the 95% confidence interval for the mean times teenagers think about food in one day is (97.22, 102.78).

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Kindly, check below

1) As we can see, this is a piecewise function. So, let's plot that accordingly to each interval.

2) So, we can represent that this way:

Note that the open dot does not include the endpoint. And closed dots include the endpoints.

Thus, this is the answer.

1 / [π(a^2 + y^2)]  is the probability density function of the Cauchy distribution, which means that Y is a Cauchy random variable.

To show that Y is a Cauchy random variable, we need to show that it has the Cauchy distribution.
First, we note that X is uniformly distributed in the interval (-1, 1), which means that the probability density function of X is f(x) = 1/2 for -1 < x < 1, and 0 otherwise.
Next, we use the transformation method to find the probability density function of Y. Let u = a tan x, so that x = tan^{-1}(u/a). Then, by the chain rule of differentiation, we have
f_Y(y) = f_X(x) |dx/dy|
where f_X(x) is the probability density function of X, and dx/dy is the derivative of x with respect to y.
Taking the derivative of x = tan^{-1}(u/a) with respect to u, we get
dx/du = a / (a^2 + u^2)
Substituting this into the expression for f_Y(y), we get
f_Y(y) = f_X(tan^{-1}(y/a)) |a / (a^2 + y^2)|
= 1 / [π(a^2 + y^2)]
where we have used the identity tan(tan^{-1}(x)) = x.
This is the probability density function of the Cauchy distribution, which means that Y is a Cauchy random variable.

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The statement you provided mentions two separate events involving different companies lower rates

1. Hertz runs a sale: Hertz, a car rental company, is having a sale. This implies that they are offering in  discounted prices or promotional deals on their rental services.

2. Avis buys new cars and Budget lowers rates: Avis, another car rental company, is purchasing that  new cars to add to their fleet. On the other hand, Budget, yet another car rental   the company, is reducing their rental rates.

These events indicate of independent actions taken by the respective companies and are not directly connected to each other.

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There are two types of classifications for triangles, Classification according to internal angles and Classification according to the length of its sides.

A geometrical shape with three vertices, angles and sides, whose sum of internal angles is 180° is considered as a triangle.

Classification of triangles :-

There are two ways to classify triangles,

1) Based on the Angle :-

a) Acute Angled Triangle :- A triangle that has all three angles less than 90° is an acute angle triangle.

b) Right-Angled Triangle :- A triangle that has one angle that measures exactly 90° is a right-angle triangle.

c) Oblique Angled Triangle :- A triangle that has one angle that measures more than 90° is an obtuse angle triangle.

2) Based on the Sides :-

a) Scalene Angled Triangle :- A triangle that has all three sides of different lengths is a scalene triangle.

b) Isosceles Angled Triangle :- A triangle that has two sides of the same length and the third side of a different length is an isosceles triangle.

c) Equilateral Angled triangle :- A triangle that has all three sides of the same length is an equilateral triangle.

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Step-by-step explanation:

bonjour quelqu'un peut-il se joindre à zo om Numéro d'identification 77974021488 le mot de passe 9taPHH

In a continuous probability distribution, a random variable can take any value in a specified range. (Option D)

A probability distribution refers to the mathematical function that provides the probabilities of occurrence of different possible outcomes for an experiment. Continuous probability distribution refers to a probability distribution with continuous types of data or random variables where the random variable can take on any value and is continuous. As there are infinite values that the variable can assume, the probability of the variable assuming any one specific value is zero. A continuous distribution is characterized by a range of values that are infinite, and therefore uncountable. The normal distribution is one example of a continuous distribution.

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Answer:

parentheses

Step-by-step explanation:

PEMDAS

Answer:

parentheses

Step-by-step explanation:

PEMDAS

Answer:

Get to know your empoyees and what they want

Communicate

Listen to your boss and empoyees

Be a MOTIVATOR

Be a leader

Improve yourself not just other

Step-by-step explanation:

Answer : The expression will be

( c - 7 ) / 3

Step-by-step explanation:

Let's say Adam has c pieces of candy

He took ten pieces for himself which means we can write this as c-7

He then divided this amount between his 3 children (c-7)/3

Answer:

y = 25x – 300

Step-by-step explanation:hope I helped

Given the functions f, v, and w, we can compute various vector operations such as the gradient (grad), divergence (div), curl, and scalar/vector products. We will evaluate these operations at specific points and provide the results. The calculations involve

partial derivatives and vector manipulations.

32. To find the gradient (grad) of f, we take the partial derivatives of f with respect to x, y, and z. The gradient vector is given by grad f = (∂f/∂x, ∂f/∂y, ∂f/∂z). Evaluating grad f at the point P(2, 7, 0), we substitute the coordinates into the partial derivatives to obtain the gradient vector at that point.

To find the divergence (div) of v and w, we take the dot product of the gradient operator (∇) with the respective vectors. The divergence of a vector v is div v = ∇ · v.

We evaluate div v and div w by substituting the components of each vector into the partial derivative expression.

To find the curl of v and w, we use the cross product of the gradient operator (∇) with the respective vectors. The curl of a vector v is curl v = ∇ × v. We calculate curl v and curl w by computing the cross product using the components of each vector.

The divergence of the gradient of f (div(grad f)) represents the Laplacian operator (∇²) acting on f. The magnitude of vector v squared (V²) is calculated as the dot product of v with itself. The expression ²(xyƒ) denotes the double dot product of the vectors v, v, and w, respectively.

Evaluating (curl w) · v at the point (4, 0, 2), we substitute the coordinates into the expressions for curl w and v, then take the dot product of the resulting vectors.

To find grad (div w), we calculate the gradient of the divergence of w. This involves taking the partial derivatives of div w with respect to x, y, and z.

To find Df (the total differential of f) at the point P(1, 1, 2), we take the partial derivatives of f with respect to x, y, and z and substitute the coordinates of P into the derivatives.

To find Dwf (the total differential of w) at the point P(3, 0, 2), we take the partial derivatives of each component of w with respect to x, y, and z and substitute the coordinates of P into the derivatives.

Evaluating v · ((curl w) × v), we first calculate the cross product of curl w with v, then take the dot product of the resulting vector with v.

Please note that due to the complexity of the calculations and the need for specific coordinate values, I'm unable to provide the detailed step-by-step solution for each question here. It is recommended to use appropriate software or perform the calculations manually to obtain the exact results.

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According to the given speed, the minimum rate of climb must be maintained to meet the required climb rate to 4,800 feet as specified on the instrument departure procedures is option (d) 870 feet per minute.

Speed:

In math speed refers the rate of change of position of an object in any direction.

Given,

Here we have using an average ground speed of 120 knots and taking off on runway 14.

Now, we need to find in what minimum rate of climb must be maintained to meet the required climb rate (in feet per nm) to 4,800 feet as specified on the instrument departure procedures.

While we looking into the given question, we have identified that,

Speed = 120

Distance = 4800

Then the  minimum rate of climb must be maintained to meet the required climb rate  is calculated as,

Here we also note in the bottom left corner of the overhead view of the departure requires 435 ft/nm climb gradient to 4800' for obstacle clearance.

Therefore, the minimum rate is 870 feet per minute.

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When collecting data and receiving different results from participants, it is important to reevaluate the accuracy of the data.

Variations in results can occur due to several factors such as measurement errors, sampling bias, or inconsistencies in data collection methods. Ignoring the results altogether would be unwise as it dismisses valuable information that could contribute to a comprehensive analysis.

While it is normal to expect some degree of variability in samples, it is essential to assess the consistency and reliability of the data. One approach could be to examine potential sources of discrepancies, identify any outliers or inconsistencies, and ensure the data collection process was conducted in a standardized manner.

Additionally, comparing individual scores with the participant mean and exploring any significant differences could provide insights into potential biases or errors.

Therefore, the goal is to ensure the data is as accurate and reliable as possible for meaningful analysis and decision-making.

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When procedures are mandated by third party payers, the modifier -32 (mandated services) is used. This modifier is used to indicate that a service or procedure is mandated by a third party payer, such as Medicare or Medicaid.

It is used to ensure that the service or procedure is reimbursed appropriately and to avoid denials. The use of the -32 modifier is important to accurately reflect the requirements of the payer and to avoid any potential billing or coding errors. It is important to check with the specific payer to determine if the use of this modifier is required for a particular service or procedure.

When procedures are "mandated" by third-party payers, you would use the modifier -32. This modifier indicates that a service or procedure is being performed due to specific requirements from a third-party payer. It helps to provide the necessary information for reimbursement and ensures that the claim is processed correctly by the payer. Remember to attach the modifier -32 to the appropriate procedure code on the claim form when submitting it to the third-party payer. This will help avoid any potential delays or denials in payment due to insufficient documentation.

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The are of square is 100 ft² and perimeter is 40 ft.

Given that,

The length of side = 10 ft

We know that all sides of square are equal.

Since we also know that area of square = side x side

                                                                   = 10 x 10

                                                                   = 100 ft²

And perimeter of square = 4 x side

                                         = 4 x 10

                                         = 40 ft

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Answer:

1/2

Step-by-step explanation:

Change 2/3 to 4/6 so there are common denominators.

4/6 - 1/6 = 3/6 = 1/2

Answer:

2/3 - 1/6 is equal to 1/2.

Step-by-step explanation:

To evaluate 2/3 - 1/6, we need to find a common denominator for the two fractions. The smallest common denominator for 3 and 6 is 6.

We can convert 2/3 to an equivalent fraction with a denominator of 6 by multiplying both the numerator and denominator by 2:

2/3 = (22)/(32) = 4/6

We can leave 1/6 as it is since its denominator is already 6.

Now, we can subtract the two fractions by subtracting the numerators and keeping the denominator the same:

2/3 - 1/6 = 4/6 - 1/6 = (4-1)/6 = 3/6

The fraction 3/6 can be simplified by dividing both the numerator and denominator by their greatest common factor, which is 3:

3/6 = (3/3) / (6/3) = 1/2

Therefore, 2/3 - 1/6 is equal to 1/2.

Answer:

it is the last one or third one