So can someone do this all for me except bmi ty whoever

Answer:

1.454 m

Explanation:

From the question,

L₂ = L₁+α(T₂-T₁).................. Equation 1

Where L₂ = Final Length, L₁ = Initial Length, α = Coefficient of Linear expansion, T₁ = Initial Temperature, T₂ = final Temperature.

Given: L₁ = 1.5 m, α = 23×10⁻⁶ K⁻¹, T₁ = 200 °C, T₂ = -1800 °C

Substitute these values into equation 1

L₂ = 1.5+[23×10⁻⁶ ×( -1800-200)

L₂ = 1.5+(23×10⁻⁶×2000)

L₂ = 1.5+(-0.046)

L₂ = 1.5-0.046

L₂= 1.454 m.

u= coefficient of friction = 0.77

g= gravity = 10 m/s^2

m= mass = 38.4 kg

v= speed = 0.77 m/s

Apply Newton's second law:

Sum of forces = mass x acceleration

Net Force = f - umg

a = 0 (constant speed)

F = umg = 0.77 x 38.4 x 10 = 295.68 N

Answer:

550 meters west

Explanation:

Givens: Inital velocity/vi= 5.0m/s, time/t=60.0s, acceleration/a= 0 because a constant velocity means 0 acceleration, inital position/xi=250m

Unknown: final position/xf=?

Formula: xf=xi+vi(t)+1/2at^2

xf=250m+5.0m/s(60.0s)+1/2(0)(60.0s)^2

xf=250m+300m

xf=550m west

its still west because he never chhanged direction therefore his postion kept increasing.

Answer:

In terms of both price and availability, the Birkin bag is as elusive as it is exclusive. For more than two decades, the bag has been the most sought item in the handbag industry. For such a modest bag, that's a lot of staying power (in looks alone, the design itself takes some 18 hours and is done by a single craftsman).

Of course, it's likely that the bag's rarity is what keeps it at the top of every want list. It is difficult, for example, to stroll into a Hermès store and buy a bag –– even if you could afford to pay the minimum price of $10,000. No, you have to be on an elite list to receive a Birkin.

Explanation:

There are alot more things like the Birkin Bag that use the same marketing skills and it works for alot of companies.

The speed of the moving train is approximately 33.5 m/s.

The beat frequency is given by the difference in frequency between the two horns, which is equal to the Doppler shift in frequency due to the motion of the moving train. Using the formula for the Doppler effect, we can solve for the speed of the train:

\(f_b = f_s\dfrac{(v + v_o)}{(v + v_s)}\)

where \(f_b\) is the beat frequency, \(f_s\) is the horn frequency, v is the speed of sound, \(v_o\) is the observer's speed, and \(v_s\) is the speed of the source.

We know that \(f_s\) = 410 Hz and \(f_b\) = 35 Hz. The speed of sound in air at standard temperature and pressure is approximately 343 m/s. Since the observer is stationary, \(v_o\) = 0.

Solving for \(v_s\), we get:

\(v_s = \dfrac{(f_s + f_b)}{f_s - 1} \times v\)

\(v_s\) = ((410 Hz + 35 Hz) / 410 Hz - 1) * 343 m/s

\(v_s\) = 33.5 m/s

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The voltage across the capacitor at the instant when the current is momentarily zero can either have its maximum value (choice c) in a series LC circuit or its minimum value in a parallel LC circuit. Therefore, the correct answer is (c) It has its maximum value.

The voltage across the capacitor in an LC circuit when the current is momentarily zero depends on the specific configuration of the circuit at that instant. To determine the voltage across the capacitor, we need to consider the behavior of the circuit before and after the current becomes zero.

In an LC circuit, the current and voltage oscillate between the capacitor and the inductor. When the current is at its maximum value, the voltage across the capacitor is also at its maximum value. This occurs when the energy stored in the capacitor is maximum and the energy stored in the inductor is zero.

As the current starts decreasing from its maximum value, the voltage across the capacitor starts decreasing as well. When the current becomes zero at a certain instant, the voltage across the capacitor depends on whether the circuit is in a series or parallel configuration.

- In a series LC circuit, the voltage across the capacitor is maximum when the current is zero. This is because the energy is transferred from the inductor to the capacitor, and the capacitor stores the maximum amount of energy.
- In a parallel LC circuit, the voltage across the capacitor is minimum when the current is zero. This is because the energy is transferred from the capacitor to the inductor, and the capacitor stores the minimum amount of energy.

So, the voltage across the capacitor at the instant when the current is momentarily zero can either have its maximum value (choice c) in a series LC circuit or its minimum value in a parallel LC circuit. Therefore, the correct answer is (c) It has its maximum value.

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The height of the cliff from which the stone was dropped is equal to 196 ft.

The equations of motion can be applied to establish the relationship between the velocity (v and u), acceleration (a), time, and displacement (s) of a moving object.

The mathematical representations of the equations of motions are:

\(v= u+ at\\S = ut+\frac{1}{2}at^2\\ v^2-u^2=2aS\)

Given, the final speed of the stone, v = 112 ft/s

The initial speed of the stone will be, u = 0

The acceleration due to gravity, a = 32 ft/s²

From the equation of motion, find the time taken by the stone to reach the ground:

v = u + at

112 = 0 + (32) t

t = 3.5 sec

The equation of motion can be used to find the height of the cliff:

H = ut + (1/2)gt²

H = 0 + (1/2)× 32×(3.5)²

H = 196 ft

Therefore, the height of the cliff is 196 feet.

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Answer:

The velocity after 2.5 seconds is 11.3 m/s

Explanation:

Given;

u = 35.8 m/s

t = 2.50s

g = 9.8 m/s^2

Mathematically;

V = U-gt

Substituting these values;

V = 35.8-2.5(9.8)

V = 35.8-24.5

V = 11.3 m/s

Answer:

As its speed increases.......

The kinetic energy of an object increases as its speed increases. So, option B.

The type of energy that an object possesses as a result of its motion is called kinetic energy.

The kinetic energy of an object is described as the amount of effort required to accelerate a body of a specific mass from rest to its specified velocity.

The body keeps its kinetic energy after gaining it during acceleration, barring changes in speed.

When slowing down from its current pace to a condition of rest, the body expends the same amount of energy.

A force must be applied to an object in order to accelerate it. We must put in effort in order to apply a force. After the work is finished, energy is transferred to the item, which then moves at a new, constant speed.

The kinetic energy of the object,

KE = 1/mv²

where m is the mass and v is the speed of the object.

Since, the mass is a constant, the increase in speed can increase the kinetic energy of the object.

Hence,

The kinetic energy of an object increases as its speed increases.

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Answer:

55 km

pls give brainliest hope it help

Explanation:

Answer:

A. True

Explanation:

The vertical columns on the periodic table are called groups or families because of their similar chemical behavior.

Brainlist Pls!

Answer:

c. 15.4 s

Explanation:

Given the following data;

Mass, m = 50kg

Force, F = 130N

Initial velocity, u = 20m/s

Final velocity, v = 60m/s

To find the time;

First of all, we would solve for acceleration using the formula below;

Force = mass * acceleration

130 = 50*acceleration

Acceleration = 130/50

Acceleration = 2.6m/s²

Now, we would use the first equation of motion to find the time.

V = U + at

60 = 20 + 2.6t

2.6t = 60 - 20

2.6t = 40

t = 40/2.6

Time, t = 15.39 ≈ 15.4 seconds.

The time taken will be 15.4 seconds approximately. The correct answer is option c

NEWTON SECOND LAW

Newton's second law state that, the rate of change of momentum is proportional to the force applied.

Given that  a force of 130 N be applied to an object of mass 50 kg to change its speed from 20 m/s to 60 m/s. The given parameters are;

from Newton's second law,

Ft = m(v - u)

Substitute all the parameters into the formula

130t = 50 (60 - 20)

130t = 50 x 40

130t = 2000

t = 2000/130

t = 15.38 seconds

Therefore, the time taken will be 15.4 seconds approximately. The correct answer is option c

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Answer:

with 75kg --> 165.35 pound(lb)

Explanation:

\( \frac{75}{0.45359237} \)

Answer:

To solve this problem, we can use the formula for the potential energy stored in a stretched spring or rubber band: U = (1/2) k x^2

where U is the potential energy, k is the spring constant, and x is the amount of stretch.

We can rearrange this formula to solve for k: k = 2 U / x^2

The velocity of the pebble can be found using conservation of energy:

(1/2) m v^2 = U

where m is the mass of the pebble and v is its velocity.

Rearranging this formula, we get: v = sqrt(2 U / m)

We can combine these formulas to solve for the length of the rubber band:

k = (4 U) / (0.25 L^2)

v = sqrt((8 U) / (0.006))

where L is the original length of the rubber band.

Since the width and thickness of the rubber band are given, we can calculate its cross-sectional area:

A = (9 mm) x (1.55 mm) = 13.95 mm^2 = 1.395 x 10^-5 m^2

Using the Young's modulus given in the problem, we can calculate the spring constant: k = (A / L) x (Y / 4)

where Y is the Young's modulus.

The formula for k above, we get: (4 A Y / L^3) x (U / 0.25) = 0.006 v^2

Solving for L, we get: L = (4 A Y U / 0.006 v^2)^1/3

Substituting the given values and solving, we get: L = 34.86 cm

Therefore, the length of the rubber band should be approximately 34.86 cm to achieve the desired velocity of the pebble

Before we solve this, we should know this fact:

According to Newton's Law of Gravitation, the force between two objects is directly proportional to the product of their masses and inversely proportional to the square of the distance between them. The force acts along the line joining the centres of the two objects. It can be shown by this:

\(F ∝ \frac{Mm}{ {d}^{2} } \)

Now, let us check all the options.

A. As we move to higher altitudes, the force of gravity on us decreases.

This statement is true.

The force of gravity is inversely proportional to the square of distance from the centre of the earth. If, we go up the surface of the earth, the distance from the centre of the earth increases and hence the value of force of gravity decrease. So, force of gravity decreases with altitude.

B. As we move to higher altitudes, the force of gravity on us increases.

This statement is false.

We have already got the result in option A. that the force of gravity decreases with altitude. It never increases with altitude.

C. As we gain mass, the force of gravity on us decreases.

This statement is false.

The force of gravity is directly proportional to the product of the masses. So, if increase our mass, then the force of gravity will also increase and if we decrease our mass, then the force of gravity decreases.

D. As we gain mass, the force of gravity on us increases.

This statement is true.

As mentioned earlier in option C., the force of gravity is directly proportional to the product of the masses of the earth and another object. So, as we gain mass, the force of gravity on us increases.

E. As we move faster, the force of gravity on us increases.

This statement is true.

Here, we have to consider a different formula. According to Newton's Second Law,

F = ma, where F is the force, m is the mass and a is the acceleration.

In other words,

F ∝ a, i.e., force is directly proportional to acceleration.

We know, acceleration is the rate of change of velocity of an body within a time period.

So, if speed is increased, then acceleration will also be greater, which results in the increase of force. So, as we move faster, the force of gravity on us increases.

Answers:

A: As we move to higher altitudes, the force of gravity on us decreases.

D: As we gain mass, the force of gravity on us increases.

E: As we move faster, the force of gravity on us increases.

Hope you could understand.

If you have any query, feel free to ask.

Given data,

Mass of the bus is m = 9800 kg,

Speed of the bus is v = 40 mph,

Converting speed of the bus in m/s, {1 miles per hour = 0.447 meter per second}

v = 40*0.447

v = 17.88

Calculating momentum of the bus,

To source component parts such as casters, laminate, and plastic to make the office furniture, genevieve works in d. resources.

A furniture maker's hallmark is a manufacturing tag, label, or stamp with the name of the maker. Such marks and labels may have been on the drawers of old dressers, the back of dressers, or under the seats of chairs and sofas.

His four types of manufactures office furniture that are common in all types of workspaces include desks, chairs, tables and storage units. While desks are primarily intended for employee workstations, chairs can be used for both employees and customers/suppliers/customers.

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Disclaimer:- your question is incomplete, please see below for the comlete question.

a. outcomes.

b. products

c. services.

d. resources.

e. output management

From the given data,

Part A: -In opposite direction Greatest impulse B>C>A>D>E smallest impulse

Part B: -increasing constantly thus acceleration is increasing resulting in increase of velocity and momentum as well.

Part C: -\(Force $=m$ a $\) =\($m \frac{\Delta v}{\Delta t}=\) \(m$ momentum\)

       \(F=\frac{m}{\Delta t}\)

Mass of box  \(=10kg\)

Impulse = \(F_{average}\) At

A. 0-2 seconds

Impulse = 1.5×2 = 3N sec

B. 2-4 sec

Impulse = 3×2 = 6N sec

C. 4-6 sec

Impulse = 2.75×2 =5.5N sec

D. 6-8 sec

Impulse = 1×2 = 2N sec

E. 8-10 sec

Impulse = 1×2 = 2N sec

In opposite direction Greatest impulse B>C>A>D>E smallest impulse.

For the first two seconds force is increasing constantly thus acceleration is increasing resulting in increase of velocity and momentum as well. Now for the next three seconds a constant force is acting on the box resulting in constant acceleration. After that for the next three seconds force goes on decreasing constantly thus deacceleration and decrease of impulse and velocity. In last 2 seconds deacceleration is in opposite direction that is how box starts moving in opposite direction

\((1) Force $=m$ a $\)\($=m \frac{\Delta v}{\Delta t}=\)\(m$ momentum\)

             \(F=\frac{m}{\Delta t}\)

(2) Area under the curve gives the momentum

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Answer:

7/20

Explanation:

0.35 as a fraction =35/100

35/100 can b divided by 5 so =7/20

0.350 simplified as a fraction is 7/20

Answer:

7/20

Explanation:

Answer:

A

Explanation:

Answer:

125 m/s^2

Explanation:

At 0.9 cm from the toroid's center, there is a 0.053 T magnetic field present.

the details provided;

The toroid's inner radius is 1.3 cm (0.013 m) and

its outer radius is 2.6 cm (0.026 m).

There are 1080 revolutions in the toroid.

carries a current of 2.1.

The following formula is used to compute the magnetic field at a distance of 1.95 cm from the toroid's center:

B= (μNI)/2\(\pi\)R

B=(4\(\pi\)*\(10^{-7}\))*(1080)*(2.1)/2\(\pi\)*0.0195

B=0.023 T.

The magnetic field is the area in which a magnet produces its magnetic effects. To describe how the magnetic force is dispersed in the area around and inside something magnetic in nature, we utilize the magnetic field as a tool.

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Answer:

I think it is A

Explanation:

The change in energy of the system is negative 496 J.

The change in energy of the system can be calculated using the first law of thermodynamics, which states that the change in energy of a system is equal to the heat added to the system minus the work done by the system:

ΔE = Q - W

Where:

ΔE is the change in energy of the system

Q is the heat added to the system

W is the work done by the system

In this case, the gas does P-V work on the system, which is positive since work is being done on the system. Therefore, W = 280 J.

The gas also releases heat to the surroundings, which is negative since heat is leaving the system. Therefore, Q = -216 J.

Substituting these values into the equation, we have:

ΔE = -216 J - 280 J

ΔE = -496 J

The change in energy of the system is -496 J. The negative sign indicates that the system has lost energy.

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The force applied to raise a table to a height of 8m when 120 Joules of work is done is 15 N. That is, Force F = 15N

Work is the product of force and distance in the direction of force. Work is done on an object when the displacement of the object is in the direction of the force applied. That is,

W = F x S

The S.I unit of work is Joule.

Given that a table to a height of 8m and 120J of work was done. To find the force applies, the parameters to consider are

Make force F the subject of formula from the formula written above. That is,

F = W/S

F = 120 / 8

F = 15 N

Therefore, if the 120 Joule of work is done, the force applied to raise a table to a height of 8m is 15 Newtons.

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Answer:

hear

Explanation:

stuff stuff moaning and stuff

Answer:

Friction is caused in roller coasters by the rubbing of the car wheels on the track and by the rubbing of air (and sometimes water!) against the cars.

Explanation:

The quantity of heat required is 1229.1 J

The specific heat capacity of a substance is the quantity of heat required to increase the temperature of a unit mass of the substance by 1°C or 1k. it measure in J/kg/k.

The specific heat capacity of a substance is denoted by 'C'. And it is expressed as C = Q/m∆t

where ∆t is the change in temperature, Q is the quantity of heat energy required and m is the mass of the substance.

therefore Q=mCΔt

Q= 96.7× 0.874×(69.2-31.7)

Q= 1229.1J

Thereore the heat required to increase the temperature from 31.7°C to 69.2°C is 1229.1J

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a) z = (-6) / (-24/5) = 5/2  

  y = (5 - 4z) / 5 = -1/2

  x = (-2 + z - y) / 2 = 1/2

b) z = (2/5) / (-9/5) = -2/9

  y = (-2 - z) / -5 = 2/5

  x = (2 - 2y - z) / 1 = 4/9

c)    x = t

      y = (1 + t) / 3

      z = t

(a) To solve the system of equations using Gaussian elimination:

1. Write the augmented matrix:

  [2 -2 -1 | -2]

  [4 1 2 | 1]

  [-2 1 -3 | -3]

2. Apply row operations to transform the matrix into row-echelon form:

  R2 = R2 - 2R1

  R3 = R3 + R1

  The resulting matrix is:

  [2 -2 -1 | -2]

  [0 5 4 | 5]

  [0 1 -4 | -5]

3. Further row operations:

  R3 = R3 - (1/5)R2

  The matrix becomes:

  [2 -2 -1 | -2]

  [0 5 4 | 5]

  [0 0 -24/5 | -6]

4. Solve for the variables using back substitution:

  z = (-6) / (-24/5) = 5/2

  y = (5 - 4z) / 5 = -1/2

  x = (-2 + z - y) / 2 = 1/2

(b) To solve the system of equations using Gaussian elimination:

1. Write the augmented matrix:

  [1 2 1 | 2]

  [2 -1 1 | 2]

  [0 3 1 | 4]

2. Apply row operations to achieve row-echelon form:

  R2 = R2 - 2R1

  R3 = R3 - 2R1

  The resulting matrix is:

  [1 2 1 | 2]

  [0 -5 -1 | -2]

  [0 -1 -1 | 0]

3. Further row operations:

  R3 = R3 - (1/5)R2

  The matrix becomes:

  [1 2 1 | 2]

  [0 -5 -1 | -2]

  [0 0 -9/5 | 2/5]

4. Solve for the variables using back substitution:

  z = (2/5) / (-9/5) = -2/9

  y = (-2 - z) / -5 = 2/5

  x = (2 - 2y - z) / 1 = 4/9

(c) To solve the system of equations using Gaussian elimination:

1. Write the augmented matrix:

  [2 1 -4 | -7]

  [1 -1 1 | -2]

  [-1 3 -2 | 6]

2. Apply row operations to obtain row-echelon form:

  R2 = R2 - (1/2)R1

  R3 = R3 + R1

  The resulting matrix is:

  [2 1 -4 | -7]

  [0 -3 3 | 1]

  [0 4 -6 | -1]

3. Further row operations:

  R3 = R3 + (4/3)R2

  The matrix becomes:

  [2 1 -4 | -7]

  [0 -3 3 | 1]

  [0 0 0 | 0]

4. Solve for the variables using back substitution:

  Let's denote a free variable as t.

  x = t

  y = (1 + t) / 3

  z = t

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To solve the system of equations, we can use Gaussian elimination and convert the equations to an augmented matrix. However, in this case, the row-echelon form shows that the system is inconsistent and has no solution.

To solve the system of equations using Gaussian elimination, we can use the augmented matrix. First we convert the system of equations into augmented matrix form:

Now, we perform row operations to obtain the row-echelon form:

From the row-echelon form, we can see that the system of equations is inconsistent as the last equation is always satisfied. Therefore, there is no solution for this system.

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