simplify the numerical expression
12-2³

Answer:

  $50,000

Step-by-step explanation:

The given relations can be used to write and solve an equation for the amount invested in stocks.

Let s represent the amount invested in stocks. Then (120,000-s) is the amount invested in bonds. The total earnings by the two investments were ...

  0.18s +0.12(120,000 -s) = 17,400

Simplifying the equation, we have ...

  0.06s +14,400 = 17,400

  0.06s = 3000 . . . . . . . . . . subtract 14,400

  s = 50,000 . . . . . . . . . . . . divide by 0.06

Neal invested $50,000 in stocks.

__

Additional comment

The amount invested in bonds was 70,000. The profit earned was ...

  0.18(50,000) +0.12(70,000) = 9,000 +8,400 = 17,400

a) To find the number of students getting more than 45 marks, we count the students whose marks are greater than 45 in the given list.

In the given list, the students with marks greater than 45 are: 50, 49, 47, 48, 49, 48, 47, 49, 48, 50, 47, 49, 48, 46, 47, 48, 47.

Counting these numbers, we find that there are 17 students who obtained more than 45 marks.

b) To find the number of students getting less than 45 marks, we count the students whose marks are less than 45 in the given list.

In the given list, the students with marks less than 45 are: 44, 44, 42, 41, 41, 42, 41, 44, 44, 42, 45, 45, 45, 44, 45.

Counting these numbers, we find that there are 15 students who obtained less than 45 marks.

c) To find the maximum number of students getting the same marks, we look for the mark that appears most frequently in the given list.

In the given list, the marks obtained by the students are: 44, 50, 44, 49, 42, 47, 45, 42, 44, 48, 49, 48, 47, 49, 47, 41, 45, 48, 41, 48, 41, 42, 47, 49, 49, 48, 50, 47, 49, 48, 46, 44, 45, 45, 46, 44, 42, 47, 48, 45.

Counting the frequency of each mark, we find that the marks 47 and 48 appear most frequently, with a count of 6 each. Therefore, the maximum number of students getting the same marks is 6.

d) To find the average marks obtained by the students in the class, we sum up all the marks and divide by the total number of students.

Total marks = 44 + 50 + 44 + 49 + 42 + 47 + 45 + 42 + 44 + 48 + 49 + 48 + 47 + 49 + 47 + 41 + 45 + 48 + 41 + 48 + 41 + 42 + 47 + 49 + 49 + 48 + 50 + 47 + 49 + 48 + 46 + 44 + 45 + 45 + 46 + 44 + 42 + 47 + 48 + 45

           = 1912

Total number of students = 40

Average marks = Total marks / Total number of students

                 = 1912 / 40

                 = 47.8

Therefore, the average marks obtained by the students in the class is 47.8.

e) To find the number of students getting more than the average marks, we count the students whose marks are greater than 47.8.

In the given list, the students with marks greater than 47.8 are: 50, 50, 49, 48, 49, 48, 49, 48, 50, 49, 49, 48, 48, 50, 49, 49, 48, 48, 47, 49, 49, 48, 50, 47,

49, 49, 48, 50, 47, 49, 49, 48, 48, 49, 48, 47, 48, 49, 49, 48, 50, 49.

Counting these numbers, we find that there are 40 students who obtained more than the average marks.

Answer:

Step-by-step explanation:

It is given that length and width of a rectangle is 11 cm and 10 cm.

We know the formula of Perimeter of rectangle

\(:\implies \: \) Perimeter = 2(L + B)

Where 'L' denote the length of the rectangle and 'B' denotes the breadth of the Rectangle.

Now Let's substitute the value of Length= 11 cm and Breadth = 10 cm in the above formula .

\(:\implies \: \) 2(11 + 10)

\(:\implies \: \) 2 × 21

\(:\implies \: \) 42 cm

Henceforth The perimeter of the rectangle is 42 cm

The perimeter of a rectangle is calculated by multiplying by 2 the sum of its length and width. So, in this case, the rectangle's perimeter is 42 cm.

The subject of this question is on calculating the perimeter of a rectangle. The formula for finding the perimeter of a rectangle is 2*(length + width). Applying the values given, that is length = 11 cm and width = 10 cm.

So, the perimeter of a rectangle = 2*(11 + 10) cm = 2*21 cm = 42 cm

Therefore, the correct option is OC. 42 cm.

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Answer:

He started climbing 9 feet up into the tree, so we can assume that the initial position is 9ft above the ground.

Then if he wants to get back into the ground, he must "descend" or climb down 9 ft again.

Then the integer is -9 (because he is climbing down now).

In this case, the 0 represents that he does not move.

So the integer 0 is related to: +0ft or -0ft

This means that he climbs up 0ft or down -0ft, which is the same as not moving at all.

The area of the triangle FGH is equal to  13√10 unit²

Given that the vertices;

F(-5,-7), G(-2,-5), and H(-6,-2)

We have to find the area of the triangle as;

Area of triangle = 1/2bh²

Here,

Area of triangle FGH = 1/2 (GH) (FG)²

Now,

Length of FG =  √26

Length of GH =  √10

Then,

Area of triangle FGH = 1/2 (GH) (FG)²

Area of triangle = 1/2 × √10 × √26²

Area of triangle = 1/2 × √10 × 26

Area of triangle FGH = 13√10

Therefore,

The area of the triangle FGH = 13√10 unit²

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Answer:  

Not so sure but I think it x,y= (3,0)

Step-by-step explanation:

5×(6y+3)+3y=15

33y=0

y=0

x=6y+3 y=0

x=6(-0/14261512)+3 =3

xy= (3,0/14261512)

Answer:

5x+3y=15 x-6y=3

x=3+6y

substituting x=3+6y

5(3+6y)+3y=15

15+30y+3y=15

15+33y=15

33y=15-15

y=0/33

y=0

substituting y=0

x-6y=3

x-6(0)=3

x=3

Answer:

  A)  6.86×10⁴

Step-by-step explanation:

You want to write 68600 in scientific notation.

The number 68600 can be written in expanded form with exponents as ...

  68600 = 6×10⁴ +8×10³ +6×10² +0×10¹ +0×10⁰

The left-most term of this sum tells you the exponent in scientific notation:

  68600 = 6.86×10⁴

Answer: E

Because the X is A positive and Y is a negative.

Answer: I'm a 7th grader too :)

E.

Explanation:

Graphing with axis's is ( x, y ) written like that.

For this the x axis of A is between 1 and 2 = 1.5

For the y axis of A, it is between -1.5 and -2 = -1.75

= ( 1.5, -1.75 )

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The number whose product of 5 and the difference between a number and 7 is 75 is, 22.

A numerical expression is a mathematical statement written in the form of numbers and unknown variables. We can form numerical expressions from statements.

The given statement is The product of 5 and the difference

between a number and 7 is 75.

Let, The unknown number be 'n'.

∴ 5(n - 7) = 75.

Now, 5 will move from the numerator to the denominator.

n - 7 = 75/5.

n - 7 = 15.

Now, we'll move the constant to the other side such that the variable and the constants are on different sides for our further calculation.

n = 15 + 7.

n = 22.

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\(\qquad\qquad\huge\underline{{\sf Answer}}\)

Let's evaluate ~

\(\qquad \sf  \dashrightarrow \: \sqrt{{x}^{2} - 6x + 9 }\)

\(\qquad \sf  \dashrightarrow \: \sqrt{{x}^{2} - 3x - 3x+ 9 }\)

\(\qquad \sf  \dashrightarrow \: \sqrt{{x(}^{} x- 3) - 3(x - 3) }\)

\(\qquad \sf  \dashrightarrow \: \sqrt{( x- 3) (x - 3) }\)

\(\qquad \sf  \dashrightarrow \: \sqrt{( x- 3) {}^{2} }\)

\(\qquad \sf  \dashrightarrow \: {( x- 3) {}^{} }\)

I hope you understood the procedure ~ let me know if you have doubts ~

Answered by James ~ ( Teeny fr )

The total height of the three jumps is A = 20.744 feet

Given data ,

1st high jump score: 7.016 feet

2nd high jump score: 5.42 feet

3rd high jump score: 8.308 feet

On adding the scores , we get

7.016 + 5.42 + 8.308 = 20.744 feet

On simplifying the equation , we get

A = 20.744 feet

Hence , Oliver jumped a total of 20.744 feet in the three high jumps

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Answer:

2

Step-by-step explanation:

c  

2

=a  

2

+b  

2

c^2=1^2+1^2c  

2

=1  

2

+1  

2

c^2=1+1=2c  

2

=1+1=2

c=\sqrt{2}c=  

2

sin45° = \frac{1}{\sqrt{2}}=  

2

​

1

​

\cos 45cos45° = \frac{1}{\sqrt{2}}=  

2

​

1

​

\tan 45tan45° = \frac{1}{1}=1=  

1

1

​

=1

​

Answer:

Aircraft A: 403 seats

Aircraft B: 298 seats

Step-by-step explanation:

Let's x represent the seats in Aircraft B

We have the equations:

Aircraft A: (x + 105)

Aircraft B: x

We Know

Their total number of seats is 701; find the number of seats for each aircraft.

We Take

x + (x + 105) = 701

2x + 105 = 701

2x = 596

x = 298 seats

So, there are 298 seats in Aircraft B

Aircraft A has how many seats?

We Take

701 - 298 = 403 seats

So, there are 403 seats in Aircraft A

Final Answers:

Aircraft A: 403 seats

Aircraft B: 298 seats

The two column proof showing that  ΔWXZ ≅ ΔYXZ is as shown below

From the given triangle, we see that;

Given: WX ≅ XY, XZ bisects WXY

Prove: ΔWXZ ≅ ΔYXZ

The two column proof for the above is as follows;

Statement 1;  WX ≅ XY, XZ bisects 2

Reason 1; Given

Statement 2: ∠WXZ ≅ YXZ

Reason 2; Angle bisector

Statement 3; XZ ≅ XZ

Reason 3: Reflexive property of congruence

Statement 4:  ΔWXZ  ≅ ΔYXZ

Reason 4:  SAS Congruence Postulate

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Answer:

cost of paint set = $ 13.64

cost of sketch book = $ 6.82

cost of brush = $ 4.55

Step-by-step explanation:

Let the cost of paint set is s.

cost of sketch book = s/2

cost of brush = s/3

Money spent = $ 28 - $ 3 = $ 25

So,

s +  s/2 + s/3 = 25

6 s + 3 s + 2 s = 150

11 s = 150

s = $ 13.64

cost of paint set = $ 13.64

cost of sketch book = $ 6.82

cost of brush = $ 4.55

Answer:

\(4+x=22\)

Step-by-step explanation:

Hope this helps

Answer:

16.

Step-by-step explanation:

since given the radius and the formula of the circumference of a circle is 2pie*r

For a line with a slope a and a known point (h, k), the point-slope form is:

y = a*(x - h) + k

A general linear equation can be written in slope-intercept form as:

y = a*x + b

Where a is the slope and b is the y-intercept.

If we know that a line passes through a point (h, k), then the point-slope form of that line is:

y = a*(x - h) + k

Notice that particularly, the y-intercept can be written as (0, b), then the slope-intercept form is also a point-slope:

y = a*(x - 0) + b

y = a*x + b

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The matrix representing the profit from the sales of book A for each store is:

[  $4  ]

[  $4  ]

[  $4  ]

To represent the profit from the sales of book A for each store, we can use a matrix where the rows correspond to the stores (X, Y, Z) and the columns correspond to the book A.

The matrix representing the profit from the sales of book A for each store is as follows:

Store Book A

X $4

Y $4

Z $4

Therefore, the matrix representing the profit from the sales of book A for each store is:

[  $4  ]

[  $4  ]

[  $4  ]

Each element in the matrix represents the profit from the sales of book A in a specific store, which is $4 for all stores (X, Y, Z).

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Answer:

{(20 , 6)}

Step-by-step explanation:

\(\begin{cases}\frac{x}{5} +\frac{y}{3} =6&\\ x-2y=8&\end{cases}\)

We multiply both sides of the first equation by 15

\(\begin{cases}3x+5y=6\times 15=90&\\ x=2y+8&\end{cases}\)

Now we substitute x by 2y+8 in the first equation

\(\begin{cases}3\left( 2y+8\right) +5y=90&\\ x=2y+8&\end{cases}\)

\(\begin{cases}6y+24 +5y=90&\\ x=2y+8&\end{cases}\)

\(\begin{cases}11y=90-24=66&\\ x=2y+8&\end{cases}\)

\(\begin{cases}y=\frac{66}{11} =6&\\ x=2y+8&\end{cases}\)

\(\begin{cases}y=6&\\ x=2(6)+8=20&\end{cases}\)

\(\begin{cases}y=6&\\ x=20&\end{cases}\)

Answer:

2x

Step-by-step explanation:

Since the tigers hit 2 times the number of x you would get that the tigers hit 2 times x or 2x balls

Answer:

2x.

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The standard deviation of the data sample is 2.55.

The standard deviation of the data sample is calculated by applying the following formula;

S.D = √ (x -  μ)²/(n - 1)

where;

The given parameters;

mean,  μ = 64

x, = 12

number of samples = 9

The standard deviation of the data sample is calculated as;

S.D = √ (12 -  64)²/(9 - 1)

S.D = 2.55

Thus, the standard deviation of the data sample is calculated by applying the formula for standard deviation.

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The solution to the variables are x = 7 and y = 4

From the question, we have the following parameters that can be used in our computation:

Shape = Triangle

The marks on the triangles imply that

So, we have the following representation

3x - 5 = 5y - 4

3x - 5 = y + 12

Substitute 3x - 5 = y + 12 in 3x - 5 = 5y - 4

y + 12 = 5y - 4

Evaluate the like terms

4y = 16

So, we have

y = 4

Substitute y = 4 in 3x - 5 = y + 12

3x - 5 = 4 + 12

So, we have

3x = 21

This gives

x = 7

Hence, the values are x = 7 and y = 4

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Answer:

Maddy wrote a pattern for all the x coordinates starting at 3 and followed the rule "add 2.".

Step-by-step explanation:

Answer: Maddy wrote a pattern for all the x coordinates starting at 3 and followed the rule "add 2.".

Step-by-step explanation:

The expression using the common factor is 1/12xy(x² + 5y)

From the question, we have the following parameters that can be used in our computation:

1/12 x^3 y + 5/12 xy^2

Rewrite properly

So, we have

1/12x³y + 5/12xy²

Factor out 1/12 from the expression

So, we have the following representation

1/12(x³y + 5xy²)

Factor out x from the expression

So, we have the following representation

1/12x(x²y + 5y²)

Factor out y from the expression

So, we have the following representation

1/12xy(x² + 5y)

Hence, the expression is (c) 1/12xy(x² + 5y)

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Answer:The expression using the common factor is 1/12xy(x² + 5y)

Step-by-step explanation:

The value of integral is 3.

Let's evaluate the integral over the positive half of the interval:

∫[0 to π] (cos(x) / √(4 + 3sin(x))) dx

Let u = 4 + 3sin(x), then du = 3cos(x) dx.

Substituting these expressions into the integral, we have:

∫[0 to π] (cos(x) / sqrt(4 + 3sin(x))) dx = ∫[0 to π] (1 / (3√u)) du

Using the power rule of integration, the integral becomes:

∫[0 to π] (1 / (3√u)) du = (2/3) . 2√u ∣[0 to π]

Evaluating the definite integral at the limits of integration:

(2/3)2√u ∣[0 to π] = (2/3) 2(√(4 + 3sin(π)) - √(4 + 3sin(0)))

(2/3) x 2(√(4) - √(4)) = (2/3) x 2(2 - 2) = (2/3) x 2(0) = 0

So, the value of integral is

= 3-0

= 3

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Answer:

\(3-\displaystyle \int^{\pi}_{-\pi} \dfrac{\cos x}{\sqrt{4+3 \sin x}}\; \text{d}x\approx 0.806\; \sf (3\;d.p.)\)

Step-by-step explanation:

First, compute the indefinite integral:

\(\displaystyle \int \dfrac{\cos x}{\sqrt{4+3\sin x}}\; \text{d}x\)

To evaluate the indefinite integral, use the method of substitution.

\(\textsf{Let} \;\;u = 4 + 3 \sin x\)

Find du/dx and rewrite it so that dx is on its own:

\(\dfrac{\text{d}u}{\text{d}x}=3 \cos x \implies \text{d}x=\dfrac{1}{3 \cos x}\; \text{d}u\)

Rewrite the original integral in terms of u and du, and evaluate:

\(\begin{aligned}\displaystyle \int \dfrac{\cos x}{\sqrt{4+3\sin x}}\; \text{d}x&=\int \dfrac{\cos x}{\sqrt{u}}\cdot \dfrac{1}{3 \cos x}\; \text{d}u\\\\&=\int \dfrac{1}{3\sqrt{u}}\; \text{d}u\\\\&=\int\dfrac{1}{3}u^{-\frac{1}{2}}\; \text{d}u\\\\&=\dfrac{1}{-\frac{1}{2}+1} \cdot \dfrac{1}{3}u^{-\frac{1}{2}+1}+C\\\\&=\dfrac{2}{3}\sqrt{u}+C\end{aligned}\)

Substitute back u = 4 + 3 sin x:

                            \(= \dfrac{2}{3}\sqrt{4+3\sin x}+C\)

Therefore:

\(\displaystyle \int \dfrac{\cos x}{\sqrt{4+3\sin x}}\; \text{d}x= \dfrac{2}{3}\sqrt{4+3\sin x}+C\)

To evaluate the definite integral, we must first determine any intervals within the given interval -π ≤ x ≤ π where the curve lies below the x-axis. This is because when we integrate a function that lies below the x-axis, it will give a negative area value.

Find the x-intercepts by setting the function to zero and solving for x in the given interval -π ≤ x ≤ π.

\(\begin{aligned}\dfrac{\cos x}{\sqrt{4+3\sin x}}&=0\\\\\cos x&=0\\\\x&=\arccos0\\\\\implies x&=-\dfrac{\pi }{2}, \dfrac{\pi }{2}\end{aligned}\)

Therefore, the curve of the function is:

So to calculate the total area, we need to calculate the positive and negative areas separately and then add them together, remembering that if you integrate a function to find an area that lies below the x-axis, it will give a negative value.

Integrate the function between -π and -π/2.

As the area is below the x-axis, we need to negate the integral so that the resulting area is positive:

\(\begin{aligned}A_1=-\displaystyle \int^{-\frac{\pi}{2}}_{-\pi} \dfrac{\cos x}{\sqrt{4+3\sin x}}\; \text{d}x&=- \left[\dfrac{2}{3}\sqrt{4+3\sin x}\right]^{-\frac{\pi}{2}}_{-\pi}\\\\&=-\dfrac{2}{3}\sqrt{4+3 \sin \left(-\frac{\pi}{2}\right)}+\dfrac{2}{3}\sqrt{4+3 \sin \left(-\pi\right)}\\\\&=-\dfrac{2}{3}\sqrt{4+3 (-1)}+\dfrac{2}{3}\sqrt{4+3 (0)}\\\\&=-\dfrac{2}{3}+\dfrac{4}{3}\\\\&=\dfrac{2}{3}\end{aligned}\)

Integrate the function between -π/2 and π/2:

\(\begin{aligned}A_2=\displaystyle \int^{\frac{\pi}{2}}_{-\frac{\pi}{2}} \dfrac{\cos x}{\sqrt{4+3\sin x}}\; \text{d}x&= \left[\dfrac{2}{3}\sqrt{4+3\sin x}\right]^{\frac{\pi}{2}}_{-\frac{\pi}{2}}\\\\&=\dfrac{2}{3}\sqrt{4+3 \sin \left(\frac{\pi}{2}\right)}-\dfrac{2}{3}\sqrt{4+3 \sin \left(-\frac{\pi}{2}\right)}\\\\&=\dfrac{2}{3}\sqrt{4+3 (1)}-\dfrac{2}{3}\sqrt{4+3 (-1)}\\\\&=\dfrac{2\sqrt{7}}{3}-\dfrac{2}{3}\\\\&=\dfrac{2\sqrt{7}-2}{3}\end{aligned}\)

Integrate the function between π/2 and π.

As the area is below the x-axis, we need to negate the integral so that the resulting area is positive:

\(\begin{aligned}A_3=-\displaystyle \int^{\pi}_{\frac{\pi}{2}} \dfrac{\cos x}{\sqrt{4+3\sin x}}\; \text{d}x&= -\left[\dfrac{2}{3}\sqrt{4+3\sin x}\right]^{\pi}_{\frac{\pi}{2}}\\\\&=-\dfrac{2}{3}\sqrt{4+3 \sin \left(\pi\right)}+\dfrac{2}{3}\sqrt{4+3 \sin \left(\frac{\pi}{2}\right)}\\\\&=-\dfrac{2}{3}\sqrt{4+3 (0)}+\dfrac{2}{3}\sqrt{4+3 (1)}\\\\&=-\dfrac{4}{3}+\dfrac{2\sqrt{7}}{3}\\\\&=\dfrac{2\sqrt{7}-4}{3}\end{aligned}\)

To evaluate the definite integral, sum A₁, A₂ and A₃:

\(\begin{aligned}\displaystyle \int^{\pi}_{-\pi} \dfrac{\cos x}{\sqrt{4+3\sin x}}\; \text{d}x&=\dfrac{2}{3}+\dfrac{2\sqrt{7}-2}{3}+\dfrac{2\sqrt{7}-4}{3}\\\\&=\dfrac{2+2\sqrt{7}-2+2\sqrt{7}-4}{3}\\\\&=\dfrac{4\sqrt{7}-4}{3}\\\\ &\approx2.194\; \sf (3\;d.p.)\end{aligned}\)

Now we have evaluated the definite integral, we can subtract it from 3 to evaluate the given expression:

\(\begin{aligned}3-\displaystyle \int^{\pi}_{-\pi} \dfrac{\cos x}{\sqrt{4+3 \sin x}}\; \text{d}x&=3-\dfrac{4\sqrt{7}-4}{3}\\\\&=\dfrac{9}{3}-\dfrac{4\sqrt{7}-4}{3}\\\\&=\dfrac{9-(4\sqrt{7}-4)}{3}\\\\&=\dfrac{13-4\sqrt{7}}{3}\\\\&\approx 0.806\; \sf (3\;d.p.)\end{aligned}\)

Therefore, the given expression cannot be zero.

Answer:

The answer would be option A

Step-by-step explanation:

-14 times 8=-122

Answer:

Step-by-step explanation: