Simplify 15./2 - 1) 10./5 + 51 0-10./2 + 51 412

This is the answer to your problem

Step-by-step explanation:

x1 y1 = -3,-3

x2 y2= 4,-3

now using slope formula(m),

(m)= y2-y1

x2-x1

= -3+3

4+3

= 0

7

= 0

hope it helped !!!!!

Answer: 24x2.5=60 but i dont know if thats enough hours

Step-by-step explanation:

Since the given planes are 2x − y + z = 9 and x + y − z = 3 intersect.

Therefore, The parametric equations for the line are x = -2t +6/6 , y = - (3 +t)/3 and z = t.

Parametric Equation:

A parametric equation defines a set of quantities according to one or more independent variables called parameters. Parametric equations are often used to represent the coordinates of points that make up a geometric object such as a curve or a surface, in which case the equations together form a parametric representation, or a parametric system, or a parametric (or spelled) object

According to the Question:

Given equations are

2x - y + z = 9

x +  y - z = 3

Let us consider z = t

2x - y + t = 9

x +  y - t = 3

We can write it as

2x - y  = 9 - t             -------------------------- (1)

x +  y  = 3 - t             ------------------------- (2)

Multiply equation (2) by 2 - equation (1):

    2x - y - (2x +2y) = 9 -t - (6- 2t)

⇒   2x - y -2x -2y = 9 - t - 6+ 2t

⇒ -3y = 3 + t

⇒ y = - (3 +t)/3

Let us substitute the value of y in equation (1)

   2x - {-(3 +t)/3} = 9 - t

⇒ 2x - (-3 -t)/3 = 9- t

⇒ 6x - (-3 -t) = 9 - t

⇒ 6x + 3 + t = 9 - t

⇒ 6x -6 = -2t

⇒ 6x = -2t +6

⇒ x = -2t +6/6

Therefore, the parametric equations for the line are x = -2t +6/6 ,

y = - (3 +t)/3 and z = t.

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Answer:

D

Step-by-step explanation:

become beg an so he just come i will come yesterday

The total distance that needs to be covered from the art gallery to the theater through the described station will be 10 miles so option (C) will be correct.

There are many different ways to define an equation. The definition of an equation in algebra is a mathematical statement that demonstrates the equality of 2 mathematical expressions.

The same sign is used in an equation to indicate that two expressions are equivalent in a formula.

To put it another way, the equation needs to be subject to some constraints.

Distance from the art gallery to the magic shop

7 - 5 = 2 miles.

Distance from magic shop to dry cleaners

7 - 4 = 3 miles.

Distance from dry cleaners to theater

7 - 2 = 5 miles

Total distance covered

2 + 3 + 5 = 10 miles.

Hence the total distance covered will be 10 miles.

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Answer:

None of the above

Step-by-step explanation:

a^2=6.4

Take the square root of each side

sqrt(a^2) = sqrt(6.4)

a =±2.529822128

The number of boys and girls in a team after the selection of participants are 2 and 3, respectively

The number of boys are girls are given as

Boys = 28

Girls = 42

Sections = 6

To form teams with the same number of boys and girls on each team, we need to determine the greatest common factor (GCF) of the number of girls and the number of boys.

Factors of 28: 1, 2, 4, 7, 14, 28

Factors of 42: 1, 2, 3, 6, 7, 14, 21, 42

The greatest common factor of 28 and 42 is 14.

So, we have

Boys = 28/14 = 2

Girls = 42/14 = 3

This means that each team has 2 boys and 3 girl

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Answer:

Step-by-step explanation:

Step one- is solving the left side of the equation using PEMDAS, 1.4x10 = 14

Step two- 14-5 = 9

Step 3 - 2.8 times 10 = 28

Step 4 - 28- 4 = 24

The answer is 9 and 24

Taking the quotient between the mass of the box and the mass of a single ball, we conclude that there are 64 balls in the box.

We want to find the number of balls in a box weighing 10 kg, we need to convert the weight of one ball to kilograms and then divide the total weight of the box by the weight of one ball.

Given that the weight of one ball is (156 + 1/4) g, we can convert it to kilograms:

Weight of one ball = (156 + 1/4) g = (156.25) g = 0.15625 kg

Next, we divide the total weight of the box (10 kg) by the weight of one ball (0.15625 kg):

Number of balls = 10 kg / 0.15625 kg = 64

there are 64 balls in a box weighing 10 kg.

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a. The probability of drawing a red ball from Box 1 is 30%.

b. If a red ball is drawn from Box 1, the probability of drawing another red ball from Box 2 on the second round is 60%.

c. If the first draw from Box 1 was black, the conditional probability of drawing a red ball from Box 3 on the second draw is 80%.

d. The probability of drawing two red balls at both draws, without any prior information, is 46%.

e. The probability of drawing a red ball at the first draw and a black ball at the second draw, without any prior information, is 21%.

a. The probability of drawing a red ball from Box 1 can be calculated by dividing the number of red balls in Box 1 by the total number of balls in Box 1. Therefore, the probability is 3/(3+7) = 3/10 = 0.3 or 30%.

b. Since a red ball was drawn from Box 1, we only consider the balls in Box 2. The probability of drawing a red ball from Box 2 is 6/(6+4) = 6/10 = 0.6 or 60%. Therefore, the probability of drawing another red ball when the first ball drawn from Box 1 is red is 60%.

c. If the first draw from Box 1 was black, we only consider the balls in Box 3. The probability of drawing a red ball from Box 3 is 8/(8+2) = 8/10 = 0.8 or 80%. Therefore, the conditional probability of drawing a red ball from Box 3 when the first ball drawn from Box 1 was black is 80%.

d. Before any draws, the probability of drawing two red balls at both draws can be calculated by multiplying the probabilities of drawing a red ball from Box 1 and a red ball from Box 2. Therefore, the probability is 0.3 * 0.6 = 0.18 or 18%. However, since there are two possible scenarios (drawing red balls from Box 1 and Box 2, or drawing red balls from Box 2 and Box 1), we double the probability to obtain 36%. Adding the individual probabilities of each scenario gives a total probability of 36% + 10% = 46%.

e. Before any draws, the probability of drawing a red ball at the first draw and a black ball at the second draw can be calculated by multiplying the probability of drawing a red ball from Box 1 and the probability of drawing a black ball from Box 2 or Box 3. The probability of drawing a red ball from Box 1 is 0.3, and the probability of drawing a black ball from Box 2 or Box 3 is (7/10) + (2/10) = 0.9. Therefore, the probability is 0.3 * 0.9 = 0.27 or 27%. However, since there are two possible scenarios (drawing a red ball from Box 1 and a black ball from Box 2 or drawing a red ball from Box 1 and a black ball from Box 3), we double the probability to obtain 54%. Adding the individual probabilities of each scenario gives a total probability of 54% + 10% = 64%.

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The missing angles and their reasons are as follows;

a) x = 65°; Opposite angles

b)  y = 71°; Alternate angles

c) z = 44°; sum of angles in a triangle

a) In triangles or line geometry, we know that the angles that are directly opposite to each other are known as opposite angles. They are also referred to as as vertical angles or even vertically opposite angles in some cases and are always congruent to each other.

We see that x is an opposite angle to 65 and so;

x = 65°

b) Alternate angles are gotten on the opposite sides of a transversal line they always have the same size. In this problem, we see that y is an alternate angle to 71° and as such;

y = 71°

c) The sum of angles in a triangle is 180° and as such;

x + y + z = 180°

Thus;

65 + 71 + z = 180

z = 180 - 136

z = 44°

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To estimate the mean number of pages per book in the fiction section of the large school library, we can use a t-test. A t-test is a statistical method for determining the probability that a given sample of data comes from a population with a certain mean value.

Given that the sample size is 35 and the standard deviation is 47.6 pages per book, we can use the t-distribution table to find the t-value for a 99% confidence level.

The t-value for a 99% confidence level and 34 degrees of freedom (sample size - 1) is 2.021.

With this information, we can construct a confidence interval for the mean number of pages per book in the fiction section of the large school library. The confidence interval is given by:

Sample mean ± t-value * (Standard deviation / √Sample size)

Therefore, the confidence interval for the mean number of pages per book in the fiction section of the large school library is:

291.8 ± 2.021 * (47.6 / √35)

The margin of error is approximately 12.2 pages per book.

So the mean number of pages per book in the fiction section of the large school library is between 279.6 and 304 pages per book with a 99% confidence level.

Given that Tyson has a $50 gift card to use at a store. He does not have any additional money to spend at the store. Tyson will purchase a belt that costs $8 and x number of shirts that cost $15 each. The mo appropriate domain of the function is C. 0 < x < 2 where x is an integer.

The function f(x) = 42 - 15x models the balance on the gift card after Tyson makes the purchases. The cost of each shirt is $15.The cost of a belt is $8.The total amount Tyson can spend is $50.

(i) If he buys only one shirt, the cost will be $15 + $8 = $23 and the balance on the gift card will be:$50 - $23 = $27(ii) If he buys two shirts, the cost will be $15 × 2 + $8 = $38 and the balance on the gift card will be:

$50 - $38 = $12

(iii) If he buys three shirts, the cost will be $15 × 3 + $8 = $53 and Tyson cannot purchase all three shirts because he only has $50. Thus, Tyson can buy at most 2 shirts. The domain of the function f(x) = 42 - 15x is such that the total cost of x shirts plus the cost of the belt is less than or equal to $50. Therefore:

15x + 8 ≤ 50

Subtracting 8 from both sides gives:

15x ≤ 42 Dividing both sides by 15 gives: x ≤ 42/15

The largest integer less than or equal to 42/15 is 2, thus the appropriate domain of the function is 0 ≤ x ≤ 2 where x is an integer.

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Answer:

x = 30 degrees

x = 60 degrees

Explanation:

Given the below trig function;

To solve for x, let's take the inverse sine of both sides of the equation, we'll have;

To find the 2nd solution, we know that, in the 1st and 2nd quadrants, the sine function is always positive. So we'll have;

After considering the given data we conclude that there truth table is possible and is placed in the given figures concerning every sub question.

A truth table is a overview that projects  the truth-value of one or more compound propositions for each possible combination of truth-values of the propositions starting up the compound ones.
Every row of the table represents a possible combination of truth-values for the component propositions of the compound, and the count of rows is described by the range of possible combinations.
For instance, if the compound has just two component propositions, it comprises  four possibilities and then four rows to the table. The truth-value of the compound is projected on each row comprising the truth functional operator.
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The account balance in the bank after 5 years is $1,216.65.

An amount of $1,000 is deposited into a bank account that pays 4% annual interest. The amount in the bank account after 5 years can be calculated as follows:

Therefore,

\(A = p(1 + \frac{r}{n} )^{nt}\)

where

Therefore,

p = 1000 dollars

4 = 4 % = 4 / 100 = 0.04

t = 5 years

n = 1

Therefore,

A = 1000(1 + 0.04/1)¹ˣ⁵

A = 1,000(1 + 0.04)⁵

Therefore,

A = $1,216.65

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The Cotton count of the plied yarn is 2093.37.

Given,

Core: 24/1Sheath: 2 × 20/1

Length of the plied yarn = 2 m

The cotton count is the measure of the fineness of yarn which is the number of hanks of yarn required to form 1 lb of yarn.

Length of the core yarn = 2 m

Length of each sheath yarn = 2.12 m

Total length of sheath yarns = 2 × 2.12 m = 4.24 m

Total length of yarn in 2 m of plied yarn = Length of core yarn + Total length of sheath yarns

= 2 m + 4.24 m = 6.24 m

The cotton count of the plied yarn is given by,

Cotton Count = (Length of yarn in hanks × Ply)/Weight of the yarn in lbs

One hank is equal to 840 yards.

Length of yarn in hanks = Length of yarn in meters/0.9144

Length of yarn in hanks = (6.24/0.9144) = 6.819 hanks

The weight of the yarn in lbs is equal to the weight in grams/453.59

Weight of 6.24 m of yarn in grams = Length of yarn in meters × Weight per unit length× Density

= 6.24 × 1 × (1/1.4) g = 4.457 g

Weight of the yarn in lbs = 4.457/453.59 lbs

Cotton Count = (Length of yarn in hanks × Ply)/Weight of the yarn in lbs= (6.819 × 3)/0.0098= 2093.37

Therefore, the Cotton count of the plied yarn is 2093.37.

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Answer:

Step-by-step explanation:

Refer to your previous question:

Radius of the inscribed circle is the apothem of the hexagon.

Apothem (a) and half of the side (s) make a 30-60-90 right triangle.

The ratio of the legs, as per property of 30-60-90 triangle:

Half the side is s = 10 units, then side of the hexagon is 20 units.

The area of the hexagon:

Correct choice is D

Answer:

AnCr+AnCr - 1 = n!/(n - r)!r! + n/(n - r + 1)!(r -

|1)! = n!(n - r+ 1)/(n -r+ 1)!r! + n!r/(n - r + 1)!r!

F n!/(n - r+ 1)!r!(n - r+1 +r) = (n +.

Answer:

D

Step-by-step explanation:

Solving the inequality

- 3x + 5 > 4 ( subtract 5 from both sides )

- 3x > - 1

Divide both sides by - 3, reversing the symbol as a result of dividing by a negative value.

x < \(\frac{1}{3}\)

The only value not less than \(\frac{1}{3}\) is 4 → D

To determine the explicit rule for the nth term of the given geometric sequence 5, 20, 80, 320, 1,280, ..., use the formula:`an = a1 * r^(n - 1)`, where an represents the nth term of the sequence.`a1`represents the first term of the sequence.`r` represents the common ratio between terms of the sequence.

The given sequence is 5, 20, 80, 320, 1,280, ...Let's now apply the formula to find the explicit rule for the nth term of the given sequence.`an = a1 * r^(n - 1)`Where a1 = 5 (first term of the sequence)`r` can be found by dividing any term by the preceding term, as `r = (second term) / (first term)`In this case,`r = (20) / (5) = 4`

Substituting the values in the formula:`an = a1 * r^(n - 1)``an = 5 * 4^(n - 1)` Therefore, the explicit rule for the nth term of the given geometric sequence is `an = 5 * 4^(n - 1)`.You can use this formula to find the value of any term in the sequence, given its position (n) in the sequence.For example, to find the 150th term of the sequence, substitute n = 150 in the formula: `a150 = 5 * 4^(150 - 1)`. This simplifies to `a150 = 1.442 x 10^90`.

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Ninety percent of all students at private universities pay less than approximately $25,692.

To find the amount that ninety percent of all students at private universities pay less than, we need to use the cumulative distribution function of the standard normal distribution.

First, we need to find the z-value corresponding to the cumulative probability of 0.90. Using a standard normal distribution table or calculator, the z-value for a cumulative probability of 0.90 is approximately 1.28 (rounded to 2 decimal places).

Next, we can use the formula for the normal distribution to find the amount. The formula is:
Amount = Mean + (z * Standard Deviation)

Plugging in the given values, we have:
Amount = $20,132 + (1.28 * $4,450)

Calculating this, we get:
Amount ≈ $25,692

Therefore, ninety percent of all students at private universities pay less than approximately $25,692.

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Answer:

Step-by-step explanation: 3×6+1,3×6 is 18+1 is 19/6 is your answer

This is the closed-form expression for the summation, which can be directly computed from k.

The expression "3 + 5 + 7 + 9 + ... + 2k+1" is a finite arithmetic series, which can be expressed in closed form using the formula:

Sn = n/2 * (2a + (n-1)d)

where:

n = number of terms

a = first term

d = common difference

In this case, we have:

n = k

a = 3

d = 2

Substituting the values in the formula, we get:

Sn = k/2 * (2 * 3 + (k-1) * 2)

= k/2 * (6 + 2k - 2)

= k/2 * (2k + 4)

Thus, This is the closed-form expression for the summation, which can be directly computed from k.

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The ratio 3:4 into percentage is 75%.

3/4 is expressed as 75% in terms of percentage.

Percentage:

In mathematics, a percentage is a number or ratio that represents a fraction of 100. This is one way of representing a dimensionless ratio between two numbers. Other methods include ratios, fractions, and decimals. Percentage is often indicated by writing a "%" sign after the number.

According to the Question:

The fraction 3/4 to an equivalent fraction with the denominator equal to 100

(3 × 25) / (4 × 25) = 75/100

Now,

75/100 is expressed as 75% in terms of percentage.

Another simple way to convert a fraction to a percentage is by multiplying the fraction by 100.

In this case, 3/4 × 100 = 75%

Thus, 3/4 is expressed as 75% in terms of percentage.

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The asymptotes of the graph defined by the parametric equations x = 1/(t-1) and y = 2/t are the vertical asymptote t = 1, the horizontal asymptote y = 0 (x-axis), and the horizontal asymptote x = 0 (y-axis).

To find the asymptotes of the graph defined by the parametric equations x = 1/(t-1) and y = 2/t, we need to examine the behavior of the equations as t approaches certain values.

Let's first consider the vertical asymptotes. Vertical asymptotes occur when the denominator of either the x or y equation approaches zero. In this case, the vertical asymptote will occur when the denominator of the x equation, (t-1), approaches zero. Solving for t, we find that t = 1 is the value that makes the denominator zero. Therefore, the vertical asymptote is the line t = 1.

Next, we will determine the horizontal asymptotes. Horizontal asymptotes are defined by the behavior of the x and y equations as t approaches positive or negative infinity. To find the horizontal asymptotes, we need to examine the limits of x and y as t approaches infinity and negative infinity.

As t approaches infinity, the x equation, 1/(t-1), approaches zero since the numerator remains constant while the denominator grows larger. Therefore, the x-coordinate tends to zero as t approaches infinity.

Similarly, as t approaches negative infinity, the x equation approaches zero. Therefore, the x-coordinate tends to zero as t approaches negative infinity.

For the y equation, as t approaches infinity, the y equation, 2/t, approaches zero since the numerator remains constant while the denominator grows larger. Therefore, the y-coordinate tends to zero as t approaches infinity.

As t approaches negative infinity, the y equation approaches zero as well. Therefore, the y-coordinate tends to zero as t approaches negative infinity.

Hence, we have identified that the horizontal asymptotes of the graph defined by the parametric equations x = 1/(t-1) and y = 2/t are the x-axis (y = 0) and the y-axis (x = 0).

To summarize, the asymptotes of the graph defined by the parametric equations x = 1/(t-1) and y = 2/t are the vertical asymptote t = 1, the horizontal asymptote y = 0 (x-axis), and the horizontal asymptote x = 0 (y-axis). These asymptotes provide valuable information about the behavior of the graph as t approaches certain values, helping us understand the overall shape and characteristics of the parametric curve.

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The value of a is -4 from the given system of linear equations.

The system of given equations are ax+12y=-6 and 2x-6y=4.

A system of linear equations consists of two or more equations made up of two or more variables such that all equations in the system are considered simultaneously. The solution to a system of linear equations in two variables is any ordered pair that satisfies each equation independently.

Here, ax+12y=-6 -------(I) and 2x-6y=4 -------(II)

Given, no solution for the system

So, (a1/a2) = (b1/b2) ≠ (c1/c2)

Now, a/2 = 12/(-6)

a=-4

Hence, the value of a is -4 from the given system of linear equations.

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Estimated  large sample size need to be selected for the 90%  of confidence level with standard deviation of $900 is equal to 24.

Standard deviation = $900

Confidence level = 90%

Estimate the required sample size,

Use the formula for the margin of error,

Margin of Error = Z × (standard deviation / √(sample size))

where Z is the z-score corresponding to the desired level of confidence.

Using attached z-score table,

For 90% confidence level, Z = 1.645.

Rearrange the formula to solve for the sample size,

Sample size = (Z × standard deviation / margin of error) ^ 2

Substituting the given values, we get,

⇒ Sample size = (1.645 × 900 / 300) ^ 2

⇒ Sample size = 24.35

Round up to the nearest whole number = 24

Therefore, need a sample size of at least 28 to ensure that it is large enough to achieve the desired level of confidence level.

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The solution for the system of equations:

2x + 3y = 0

-4x - y = 30

is y = 7 and x = -10.5

Here we want to solve the following system of equations:

2x + 3y = 0

-4x - y = 30

By combining the equations.

If we add two times the first equation and the second equation, we will get:

2*(2x + 3y) + (-4x - y) = 0 + 30

We can simplify that to get:

4x + 6y - 4x - y =  30

5y = 30

Now we can solve that for y.

y = 30/5

y = 7

Now to find the value of x, we can replace y by 7 in one of the equations of the system.

2x + 3*7 = 0

2x = -21

x = -21/2

x = -10.5

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