Answer:
-4x+ 1/10
Step-by-step explanation:
−1/2x−1/5−5x+3/10+3/2x
Combine like terms
-1/2x -5x + 3/2x -1/5 + 3/10
Get a common denominator for each group
-1/2x -10/2x + 3/2x -2/10 + 3/10
-8x/2 + 1/10
Simplify
-4x + 1/10
-4x + 1/10
Answer:
-4x+1/10
Step-by-step explanation:
Find all the solutions of each equation by factoring. 27x³=8 .
The solutions to the equation are:
x = 2/3
To solve the equation 27x³ = 8 by factoring, we can rewrite the equation as:
27x³ - 8 = 0
Now, let's consider the difference of cubes formula, which states that:
a³ - b³ = (a - b)(a² + ab + b²)
We can apply this formula to our equation, considering 27x³ as a³ and 8 as b³:
(3x)³ - 2³ = (3x - 2)((3x)² + (3x)(2) + 2²)
Simplifying further:
(3x - 2)((3x)² + 6x + 4) = 0
Now we have two factors:
1) 3x - 2 = 0
2) (3x)² + 6x + 4 = 0
Solving the first factor:
3x - 2 = 0
3x = 2
x = 2/3
Now, let's solve the second factor. We can use the quadratic formula:
For the equation ax² + bx + c = 0, the quadratic formula is:
x = (-b ± √(b² - 4ac)) / (2a)
In our case, a = 3, b = 6, and c = 4. Plugging these values into the formula:
x = (-(6) ± √(6)² - 4(3)(4) / (2(3)
x = (-6 ± √(36 - 48) / 6
x = (-6 ± √(-12) / 6
Since the discriminant (√(b² - 4ac)) is negative, the quadratic equation does not have any real solutions. Therefore, there are no additional real solutions to the equation 27x³ = 8.
The solutions to the equation are:
x = 2/3
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A slab 150 PCF concrete is to be poured 20 feet above an existing floor at depth of 6 inches at a temp of 90 degrees and a pure rate of 10 feet per hour. what is the expected VERTICAL load? a) 943.333 PSF b) 943.333 PCF c) 150 PSF d) 75 PCF e) 75 PSF
The correct answer to the question is option d) 75 PCF.
To calculate the expected vertical load, we need to consider the weight of the concrete slab and the additional load due to the concrete's temperature and pouring rate. The weight of the slab can be calculated by multiplying the density of the concrete (150 PCF) by the depth (6 inches) and the area (1 square foot). This gives us a weight of 75 pounds per square foot (PSF).
The temperature and pouring rate do not directly affect the vertical load. The temperature and pouring rate are factors that may affect the structural integrity of the slab or the time it takes for the concrete to fully cure. However, they do not contribute to the actual load borne by the slab itself. Therefore, the correct answer is 75 PCF, as it represents the weight of the concrete slab alone.
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Complete the table to combine like terms when adding Expression One and Two.
Answer:
10y+6
See diagram below
Explanation:
Given expressions One and Two below:
• Expression One: y+10
,• Expression Two: 9y-4
The completed table showing the addition of the expressions is given below:
Therefore:
\(\begin{gathered} y+9y=10y \\ 10-4=6 \\ \implies(y+10)+(9y-4)=10y+6 \end{gathered}\)The sum is 10y+6.
PLS HELP. I dont understand math
Answer:
a) 2 + 1 = 3
4 + 2 = 6
6 + 3 = 9
b) Yes
c) Yes, since you are adding b to two b, which results in 3b
Step-by-step explanation:
Hope that helps!
Urgent What is the image of (-8,2) after a reflection over the y-axis?
Answer:
(8, 2 )
Step-by-step explanation:
Under a reflection in the y- axis
a point (x, y ) → (- x, y ) , then
(- 8, 2 ) → (8, 2 )
Answer:
the answer is (8,2)
Step-by-step explanation:
hope it helps
Algebra 2
Please help me solve this.
A movie-theater employee notes an inverse relationship between the theater's popcorn sales and its nacho sales. On a given night, the theater makes $1,540 from popcorn sales and $1,330 from nacho sales. If on the next night the employees sell $1,672 of popcorn, how much is earned from nachos?
Using proportions, it is found that $1,225 is earned from nachos.
This question is solved by proportions, using a rule of three.The measures have an inverse relationship, hence line multiplication is applied instead of cross multiplication.When the theater makes $1,540 from popcorn sales, it makes $1,330 from nacho sales. How much is earned from nachos when $1,672 is earned from popcorn?The rule of three is:
$1,540 - $1,330
$1,672 - $x
Applying line multiplication:
\(1672x = 1540 \times 1330\)
\(x = \frac{1540 \times 1330}{1672}\)
\(x = 1225\)
$1,225 is earned from nachos.
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Answer each question.
a truck weighs 9,000 pounds. a repair shop sends a tow truck that can pull 5 tons.can the tow truck tow the truck? explain.
open parentheses fraction numerator f cubed to the power of -2 end exponent over denominator h to the power of negative 1 end exponent end fraction close parentheses to the power of 4.I need this in exponential form, please.
First part
numerator f cubed g to the power of negative 2
The numerator can be written as
\(f^3g^{-2}\)Second part
denorminator h raised to the power of negative 1
The numerator can be written as
\(h^{-1}\)combining part one and two
Open parentheses fraction - fraction - close parentheses to the power of 4
This gives
\((\frac{f^3g^{-2}}{h^{-1}})^4\)simplifying the expression to remove negative exponent
Simplifying the numerator
\(\begin{gathered} f^3g^{-2}=f^3\times g^{-2} \\ f^3g^{-2}=f^3\times\frac{1}{g^2} \\ f^3g^{-2}\text{ = }\frac{f^3}{g^2} \end{gathered}\)simplfying the denorminator
\(h^{-1}\text{ = }\frac{1}{h}\)combining simplfied values for numerator and denorminator in the general form we have
\(\begin{gathered} (\frac{f^3g^{-2}}{h^{-1}})^4\text{ = }(\frac{\frac{f^3}{g^2}}{\frac{1}{h}})^4 \\ (\frac{f^3g^{-2}}{h^{-1}})^4=\text{ (}\frac{f^3}{g^2}\times h)^4\text{ } \\ (\frac{f^3g^{-2}}{h^{-1}})^4\text{ = (}\frac{f^3h}{g^2})^4 \end{gathered}\)Hence, the simplified form of the expression is
\((\frac{f^3h}{g^2})^4\)Michael can clean the store in 6 hours. Together him and Lebron canclean the same store in 2 hours. How long would it take for Lebron toclean the store alone?
Answer:
8 hours to clean I think michael and lebron
Mr. Carlevato and Mr. Burrows get into a debate about two different expressions. · Mr. Carlevato says "2(2x + 3) is equal to 4x + 6". · Mr. Burrows says "Nope, wrong, those are clearly different expressions" Try substituting x=5 into both expressions. Do you get the same answer for both expressions? Show your work!
Answer:
Yes, the same answer is obtained.
Step-by-step explanation:
According to Mr. Carlevato, \(2(2x+3)\) is equal to \(4x+6\). However, \(2(2x+3)\) is not equal to \(4x+6\) according to Mr. Burrows.
Put \(x=5\) in \(2(2x+3)\)
\(2[2(5)+3]=2(10+3)=2(13)=26\)
Put \(x=5\) in \(4x+6\)
\(4x+6=4(5)+6=20+6=26\)
Therefore,
\(2(2x+3)=4x+6\)
Yes, the same answer is obtained.
Guys please help me, I’ve been stuck on this question for a bit. I will mark you brainliest (:
Answer:
The slope is 3
Step-by-step explanation:
m = rise/run
Imma use points (4,1) and (5,4)
rise = 3
run = 1
3/1
m = 3
plz mark as brainliest if correct!
Choose the function represented by the data a polynomial function is represented by the data in the table . 0 1 2 4 f(x) = x ^ 3 - x ^ 2 - 24; f(x) = (x ^ 3)/4 + 2x ^ 2 - 24; f(x); - 24 -14 3/3 * 3/4 24 - 21 3/4; f(x) = - 2 1/4 * x ^ 2 + 24; f(x) = 3/4 * x ^ 2 - 3x + 24
This is because the values of f(x) in the table match the corresponding values obtained by evaluating the polynomial function for the given input values of the function represented by the data a polynomial function is represented by the data is f(x) = x^3 - x^2 - 24.
A polynomial is an expression with more than two algebraic terms, especially the sum of several terms that contain different powers of the same variable. A polynomial function is a function that includes a polynomial expression with an independent variable (x) that can only take on integer values because of its discrete nature.
Choose the function represented by the data: The polynomial function represented by the data is f(x) = x^3 - x^2 - 24.
A table representing the function f(x) = x^3 - x^2 - 24 is shown below:
x | f(x)
0 | -24
1 | -14
2 | 0
4 | 40
Therefore, the function represented by the data is f(x) = x^3 - x^2 - 24.
The provided table displays the values of the function f(x) for different input values of x. By substituting the corresponding values of x into the function, we can observe the corresponding output values. This allows us to identify the pattern and equation that represents the function.
In this case, the table shows that when x is 0, the value of f(x) is -24. When x is 1, f(x) is -14. When x is 2, f(x) is 0. And when x is 4, f(x) is 40.
Based on these data points, we can conclude that the function represented by the data is f(x) = x^3 - x^2 - 24.
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We find that Option 2, f(x) = \((x^3)/4 + 2x^2 - 24\), matches the data given in the table.
Based on the data given in the table, we need to determine the polynomial function that represents the data.
To do this, we can compare the values of f(x) in the table with the given options for the polynomial functions. We are looking for a function that matches the given data points.
Let's evaluate each option using the x-values from the table:
Option 1: f(x) = \(x^3 - x^2 - 24\)
For x = 0,\(f(0) = 0^3 - 0^2 - 24 = -24\) (matches the data)
For x = 1, \(f(1) = 1^3 - 1^2 - 24 = -24 - 1 - 24 = -49\) (does not match the data)
For x = 2,\(f(2) = 2^3 - 2^2 - 24 = 8 - 4 - 24 = -20\) (does not match the data)
Option 2: \(f(x) = (x^3)/4 + 2x^2 - 24\)
For x = 0,\(f(0) = (0^3)/4 + 2(0^2) - 24 = 0 - 0 - 24 = -24\) (matches the data)
For x = 1,\(f(1) = (1^3)/4 + 2(1^2) - 24 = 1/4 + 2 - 24 = -20.75\)(does not match the data)
For x = 2, \(f(2) = (2^3)/4 + 2(2^2) - 24 = 8/4 + 8 - 24 = -14\)(matches the data)
Option 3: f(x) = -24 - 14(3/3)(3/4)
Simplifying, f(x) = -24 - 14(1)(3/4) = -24 - 14(3/4) = -24 - 10.5 = -34.5 (does not match the data)
Option 4: \(f(x) = -2 1/4 * x^2 + 24\)
For x = 0, \(f(0) = -2 1/4 * 0^2 + 24 = 24\) (does not match the data)
For x = 1,\(f(1) = -2 1/4 * 1^2 + 24 = -2 1/4 + 24 = 21.75\) (does not match the data)
For x = 2,\(f(2) = -2 1/4 * 2^2 + 24 = -2 1/4 * 4 + 24 = -9 + 24 = 15\) (does not match the data)
Option 5: \(f(x) = 3/4 * x^2 - 3x + 24\)
For x = 0, \(f(0) = 3/4 * 0^2 - 3(0) + 24 = 24\) (does not match the data)
For x = 1, \(f(1) = 3/4 * 1^2 - 3(1) + 24 = 3/4 - 3 + 24 = 21.75\) (does not match the data)
For x = 2,\(f(2) = 3/4 * 2^2 - 3(2) + 24 = 3/4 * 4 - 6 + 24 = 3 - 6 + 24 = 21\)(matches the data)
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the equation of a line is y equals short dash 2 over 7 x plus 3 over 7. what is the slope of a line perpendicular to this line?
The slope of a line perpendicular to this line is 3.5
How to determine the slope of a line perpendicular to this line?From the question, we have the following parameters that can be used in our computation:
y = -2/7x + 3/7
Using the above as a guide, we have the following:
A linear equation is represented as
y = mx + c
Where
m = slope
So, we have
m = -2/7
The slope of perpendicular lines are opposite reciprocals
So, we have
new slope = -1/(-2/7)
Evaluate
new slope = 3.5
Hence, the slope of a line perpendicular to this line is 3.5
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please help me solve these as much as possible urgent neeeddd.
i think its easy but im just not smart
solve as many as you can. one is enough (but more is better)
Answer:
7. 45
8. 19
9. 15
10. 24
11. 23
12. 6
13. 8
14. 15
15. 12
16. 3
17. 26
18. 12
19. 21
20. 34
21. 2
hope this helps!:)
what is the greatest number of identical bouquets that can be made out of 21 white and 91 red tulips if no flowers are to be left out? (two bouquets are identical whenever the number of red tulips in the two bouquets is equal and the number of white tulips in the two bouquets is equa
The most appropriate choice for HCF will be given by-
Number of identical bouquets that can be made out of 21 white tulips and 91 red tulips if no flowers are left out = 7
What is HCF?
HCF means highest common factor. HCF of two number a and b is the highest number that divides both a and b.
Number of white tulips = 21
Number of red tulips = 91
Number of identical bouquets that can be made out of 21 white tulips and 91 red tulips if no flowers are left out = HCF (21, 91)
Now,
\(21 = 3\times 7\\91 = 7\times 13\\\)
HCF (21, 91) = 7
Number of identical bouquets that can be made out of 21 white tulips and 91 red tulips if no flowers are left out = 7
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Which of the following traingles is Cos B = 0.8?
ANSWER:
EXPLANATION:
Given:
To find:
Which triangle is cos B = 0.8
For the 1st Triangle:
We have to first determine the value of side BC using the Pythagorean theorem as seen below;
\(\begin{gathered} 5^2=4^2+BC^2 \\ 25=16+BC^2 \\ BC=\sqrt{25-16} \\ BC=\sqrt{9} \\ BC=3 \end{gathered}\)So cosine B will be;
\(\begin{gathered} \cos B=\frac{adjacent\text{ }side\text{ }to\text{ }angle\text{ B}}{hypotenuse} \\ \cos B=\frac{3}{5} \\ \cos B=0.6 \end{gathered}\)For the 2nd Triangle:
\(\begin{gathered} \cos B=\frac{adjacent\text{ }side\text{ }to\text{ }angle\text{ B}}{hypotenuse} \\ \cos B=\frac{5}{8} \\ \cos B=0.625 \end{gathered}\)For the 3rd Triangle:
We have to first determine the value of side AB using the Pythagorean theorem as seen below;
\(\begin{gathered} AB^2=4^2+5^2 \\ AB^2=16+25 \\ AB=\sqrt{41} \end{gathered}\)So cosine B will be;
\(\begin{gathered} \cos B=\frac{adjacent\text{ }side\text{ }to\text{ }angle\text{ B}}{hypotenuse} \\ \cos B=\frac{4}{\sqrt{41}} \\ \cos B=0.62 \end{gathered}\)For the 4th Triangle:
\(\begin{gathered} \cos B=\frac{adjacent\text{ }side\text{ }to\text{ }angle\text{ B}}{hypotenuse} \\ \cos B=\frac{4}{5} \\ \cos B=0.8 \end{gathered}\)So in the below triangle cos B = 0.8
What is the time premium (on a per share basis) of a put with a strike price of $25 when the option price is $2 and the underlying common stock sells for $24?
The value of the time premium is $100.
According to the statement
we have to find the time premium from the given information.
So, For this purpose, the given information is:
a strike price of $25 when the option price is $2 and the underlying common stock sells for $24
And
Time premium is the amount by which an option price exceeds its intrinsic value. The value of an option beyond its current exercise value representing the option holder's control until expiration, the risk of the underlying asset, and the risk less return.
So, From the given information and the formula
The value of the time premium is $100.
So, The value of the time premium is $100.
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a) use definition 2 to find an expression for the area under the curve y=x^3 from 0 to 1 as a limit.(b) the following formula for the sum of the cubes of the first n integers is proved in Appendix E. useit to evaluate the limit in part (a).1^3 + 2^3 +3^3+.....n^3 = [n(n+1)/2]^2Definition 2: The area A of the region S that lies under the graph of the continuous function f is the limit of the sum of the areas of approximating.
The area A of the region S that lies under the graph of the continuous function f is \(\frac{1}{4}\).
(a)
\(A =\) \(\int\limits^A_b {f(x)} \, dx\)
= \(\lim_{n \to \infty}\)∑ f(xi) Δ x
a = 0, b = 1 → Δ x = \(\frac{1-0}{n}\) = \(\frac{1}{n}\)
x₀ = 0, x₁ = \(\frac{1}{n}\) , x₂ = \(\frac{2}{n}\), x₃ = \(\frac{3}{n}\), ..., xi = \(\frac{i}{n}\)
f(x) = \(x^{3}\)
f(xi) = \([\frac{i}{n} ]^{3}\) = \(\frac{i^{3} }{n^{3} }\)
Then,
A = \(\lim_{n \to \infty}\) ∑(\(\frac{i^{3} }{n^{3} }\)) * \(\frac{1}{n}\)
(b)
A = \(\lim_{n \to \infty}\) [\(\frac{1}{n}\) * ∑ \(\frac{i^{3} }{n^{3} }\) ]
= \(\lim_{n \to \infty}\) [\(\frac{1}{n}\) * \(\frac{1}{n^{3} }\) ∑ \(i^{3}\)]
= \(\lim_{n \to \infty}\) [\(\frac{1}{n^{4} }\) * [\(\frac{n(n+1)}{2}\)]^2]
= \(\lim_{n \to \infty}\) [\(\frac{1}{n^{4} }\) * \(\frac{n^{2}(n+1)^{2} }{4}\)]
= \(\lim_{n \to \infty}\) \(\frac{(n+1)^{2} }{4n^{2} }\)
= \(\frac{1}{4}\) * \(\lim_{n \to \infty}\) \((\frac{n+1}{n} )^{2}\)
= \(\frac{1}{4}\) * \(1^{2}\)
A = \(\frac{1}{4}\)
Therefore the area A of the region is \(\frac{1}{4}\).
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AB is tangent to circle O. If AO = 8 and BC = 6, what is the length of AB? Round to the nearest tenth, if needed.
In each, fill in the blanks to rewrite the given statement. There is a real number whose product with every number leaves the number unchanged. a. Some ___ has the property that its ___. b. There is a real number r such that the product of r ____. c. There is a real number r with the property that for every real number s, ____.
Plz help I’ll mark brainliest
Answer:
J
Step-by-step explanation:
I did it in my head so?? ya
gl
If 8 boxes of cookies contain 200 cookies in total, how many cookies will 3 boxes of cookies contain?
Answer:
75
Step-by-step explanation:
Aaron has 47 m of fencing to build a three-sided fence around a rectangular plot of land that sits on a riverbank. (The fourth side of the enclosure would be the river.) The area of the land is 266 square meters. List each set of possible dimensions (length and width) of the field.
The possible dimensions (length and width) of the field are:(10 m × 13 m) or (13 m × 10 m) and (11 m × 12 m) or (12 m × 11 m).
Given that Aaron has 47m of fencing to build a three-sided fence around a rectangular plot of land that sits on a riverbank. The fourth side of the enclosure would be the river.
The area of the land is 266 square meters.To find the possible dimensions (length and width) of the field, we can use the given information.The length of fencing required = 47 m.
Since the fence needs to be built on three sides of the rectangular plot, the total length of the sides would be 2l + w = 47.1. When l = 10 and w = 13, we have:
Length of the field, l = 10 m Width of the field, w = 13 mArea of the field = l × w = 10 × 13 = 130 sq. m2. When l = 11 and w = 12,
we have:Length of the field, l = 11 m
Width of the field, w = 12 m
Area of the field = l × w = 11 × 12 = 132 sq. m
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ch 10 sec 5 ex 10 (b) - cross bridges can someone cross all the bridges shown in this map exactly once and return to the starting point?
In exercise 10(b) of Chapter 10, Section 5, the question asks whether it is possible to cross all the bridges shown in a given map exactly once and return to the starting point.
This problem is known as the "Seven Bridges of Königsberg" puzzle, famously solved by Leonhard Euler in the 18th century. The solution involves applying graph theory principles to analyze the connectivity and degree of the bridges. The Seven Bridges of Königsberg problem is a well-known mathematical puzzle that involves a network of bridges and islands. The goal is to determine whether it is possible to cross each bridge exactly once and return to the starting point. This problem was originally posed by the Swiss mathematician Leonhard Euler in 1736 and played a significant role in the development of graph theory.
To solve this problem, we can represent the bridges and islands as a graph. Each island is represented as a vertex, and each bridge is represented as an edge connecting two vertices. By analyzing the connectivity and degree of the vertices in the graph, we can determine whether a solution exists.
In the given map, we would analyze the graph formed by the bridges and islands. If each island has an even degree (an even number of bridges connected to it), then it is possible to find a path that crosses each bridge exactly once and returns to the starting point. This can be proved using Euler's theorem, which states that in a connected graph, if the number of vertices with an odd degree is either 0 or 2, then there exists an Eulerian path or an Eulerian circuit respectively. However, if any island has an odd degree, it is not possible to find a path that satisfies the conditions of crossing each bridge exactly once and returning to the starting point.
Without further information or a specific map, it is not possible to determine the exact solution to exercise 10(b) in Chapter 10, Section 5. The solution would require analyzing the connectivity and degree of the bridges and islands in the given map and applying graph theory principles to determine the possibility of crossing all the bridges exactly once and returning to the starting point.
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If (x+1) is a factor of ax3 + x2 – 2x + 4a – 9, find the value of a
The value of a is \(1 +/- sqrt(16 - 16a).\)
Let’s begin by writing out the given equation: \(ax3 + x2 – 2x + 4a – 9\). We can rearrange this equation to make it easier to solve: (x+1)(ax2 -2a + 4). This indicates that (x+1) is a factor of the equation, and thus we can set the equation equal to 0. By doing so, we can solve for a.
We can now write this equation as 0 = ax2 -2a + 4. We can use the quadratic equation to solve for a. We first need to calculate the discriminant, which is equal to b2 - 4ac. In this case, b2 is (-2)2 = 4 and ac is a(4) = 4a. Thus, the discriminant is equal to 4 - 16a.
Next, we can solve for a using the quadratic equation. The equation is: \(a = [-b +/- sqrt(b2 - 4ac)]/2a\). In this case, \(a = [-(-2) +/- sqrt(4 - 16a)]/2\). By simplifying, we get \(a = [2 +/- sqrt(16 - 16a)]/2.\) This can be further simplified to a = 1 +/- sqrt(16 - 16a). Therefore, the value of a is∀⊅\(1 +/- sqrt(16 - 16a).\)
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A company manufactures 16-oz boxes of cereal. Boxes are randomly weighted to ensure the correct amount. If the discrepancy in weight is more than 0.15 oz, the production is stopped. What is the range of acceptable values for production to continue?
A. 15.15 oz to 16.00 oz
B. 15.85 oz to 16.00 oz
C. 15.85 oz to 16.15 oz
D. 16.15 oz to 16.45 oz
Answer:
It's C
Step-by-step explanation:
took the test
Answer:c
Step-by-step explanation:
One equation 0f a pair of dependent linear equations is -5x+7y=2.The second equation can be a)10x-14y=-4 b)-10x-14y+4=0 c)-10x+14y+4=0 d)10x+14y=-4
Answer:
a) 10x - 14y = -4
Step-by-step explanation:
Two equations linear dependent if you can write one as a multiple of the other. It means that the equation that is a linear dependent with -5x+7y=2 is:
10x - 14y = -4
Because it can be written as:
-2(-5x+7y) = -2(2)
So, this equation is equivalent to -5x + 7y = 2
What is the relationship between centimeters and inches?
Answer:
What do you mean like the the ratio of cm to inches?
Step-by-step explanation:
?