Shown below is a balance. Based on this instrument, identify from the following list all the statements that are true if you were to use
this balance to measure the mass of a sample. (Note, the balance in the picture currently reads "0.00")


Choose one or more:
A. a mass measured on this balance will always have 3 significant digits.
B. the uncertainty is in the hundredth place.
C. the uncertainty is in the ones place.
D. a mass measured on this balance will always have 4 significant digits.
E. the uncertainty is in the tenths place.
F. the mass measured on this balance is known exactly.
G. a mass that falls between 1 gram and 9 grams measured on this balance will always have 3 significant figures.
H. a mass that falls between 10 grams and 80 grams measured on this balance will always have 3 significant figures.
I. a mass that falls between 100 and 200 grams measured on this balance will have 5 significant figures.

Answer:

B. are electrical signals.

Answer:

\(M=174.87g/mol\)

Explanation:

Hello,

In this case, we consider the depression in the freezing point as:

\(\Delta T=-i*m*Kf\)

Whereas the van't hoff factor for ascorbic acid is 1 since it is covalent, thus, we solve for the molality as shown below:

\((-2.34-0)\°C=-m*1.86\°C/m\\\\m=\frac{-2.34\°C}{-1.86\°C/m} =1.26m\)

Next, since molal units are mol/kg, we can compute the present moles of ascorbic acid in the 250 g (0.25kg) of water:

\(n=1.26mol/kg*0.25kg=0.315mol\)

Finally, the molar mass with the given 55.0 g of ascorbic acid:

\(M=\frac{55.0g}{0.315mol}\\ \\M=174.87g/mol\)

Regards.

Answer:

Explanation:

Hey there!

From question;

The molecular mass of NH₄OH is 35.

Avogadro number = 6.023*10²³ molecules.

Then,

From mole concept,

Molecular mass =  Avogadro number

So, 35 grams contains  6.023*10²³ molecules.

1 gram contains \(\frac{ 6.023*10^{23} }{35}\) molecules.

52.1 grams contains \(\frac{6.023*10^{23} }{35} *52.1\) molecules.

Therefore, 52.1 grams contains 8.96*10²³ molecules.

Hope it helps!

Answer:(−NH−CHR−CO−)n is a homopolymer. The reason is that it has a single monomer (NH2−CHR−COOH), α−amino acid.

If a polymer consists of only one kind of monomer then it is called a homopolymer, while a polymer that consists of more than one kind of monomer is called a copolymer

Answer and Explanation:

For the following balanced reaction:

PCl₅(g) ↔ PCl₃(g) + Cl₂(g)

We can see that all reactants and products are gases, so it is an homogeneous equilibrium. The expression for the equilibrium constant Kp can be written from the partial pressures (P) of reactants and products as follows:

\(Kp=\frac{(P PCl_{3})(P Cl_{2})}{(P PCl_{5})}\)

Where PPCl₃ is the partial pressure of PCl₃ (reactant), PCl₂ is the partial pressure of Cl₂ (reactant) and PPCl₅ is the partial pressure of PCl₅ (product).

Answer:

The Work Function is 4.74eV.

Explanation:

The photoelectric effect is a phenomenon in which a beam of light is projected towards a metal plate and this leads to the ejection of electrons from the metal. The minimum amount of energy required for this ejection of electrons is known as the work function. When the energy of the light beam is less than the work function, then the electrons are not emitted.

The photoelectric effect is represented by the equation:

E = φ + KE  where

E = energy of the incident photons

KE = kinetic energy of photoelectrons

φ = Work function of the metal

This can also be written in terms of frequency as:

h = h₀ + \(\frac{1}{2}\) mv²

= frequency of the incident light beam

₀ = frequency of the photoelectrons

m = mass of the electron

v = velocity of the electron

h = Plank's constant 6.623 x 10⁻³⁴Js

Conversion factor: 1eV = 1.602 x 10⁻¹⁹ J

So, 1.05eV = 1.682 10⁻¹⁹ J

Using the formulas,

(6.623 x 10⁻³⁴Js)(1.40x10¹⁵ s⁻¹) = φ + 1.682 x 10⁻¹⁹ J

(9.272 x 10⁻¹⁹) - (1.682 x 10⁻¹⁹) = φ

φ = 7.590 x 10⁻¹⁹ J = 4.74 eV

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Answer:

See below ~

Explanation:

The calculated values of V/n :

⇒ 1.5/0.3 = 5

⇒ 3/0.6 = 5

⇒ 4.5/0.9 = 5

⇒ 6/1.2 = 5

⇒ 7.5/1.5 = 5

1. From this we understand that the calculated values of V/n remain constant, equal to 5 in this case.

2. The volume-mole graph will be a straight line passing through the origin. (Attached below)

Answer:

false

Explanation:

12. A monosaccharide is exactly the type of molecule shown below, which is a carbohydrate.

Carbohydrates are composed of carbon, hydrogen and oxygen in the ratio 1:2:1 in organic molecules. The simplest type of carbohydrate is a monosaccharide, which cannot be broken down further into smaller sugar molecules. They typically have three to seven carbon atoms and are composed of a single sugar molecule.

13. An amino acid is a special type of molecule that is shown in the description. The production and structure of proteins largely depend on amino acids, which are the basic components of proteins.

14. Nucleic acids are primarily used by living things to store and transmit genetic information. DNA (deoxyribonucleic acid) and RNA (ribonucleic acid), two types of nucleic acids, carry instructions necessary for the production of proteins as well as for the operation and growth of cells.

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Answer:

a lower temperature to liquefy

Explanation:

Answer:

The frequency is the answer for your question in the comments

Explanation: For this Question..

B) is the answer in terms of an economic factor that contributes to the stability of a society.

Among the options, option B low tax and interest rates is an economic factor that contributes to the stability of a society.

Tax is a mandatory financial charges imposed on a working person or an owner of a service or property by a governmental organization  for the fund for public expenditure.

The only feasible way to get money to pay for government expenditure on the products and services that the majority of us need is through taxes. But, establishing an effective and fair tax system is far from easy, especially for developing nations that seek to integrate into the global economy.

When trying to set up effective tax systems, developing nations encounter enormous obstacles. First off, most people in these nations work in agriculture or small, unofficial businesses. Their incomes fluctuate since they are rarely paid a regular, fixed wage, and many of them are compensated in cash "off the books."

Therefore, tax which is moderate to be payable by people in all sectors and lo interest rate contribute to the stability of society.

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The heat used to change the temperature of 30 grams of water from 45K to 50 K is equal to 627.6 J.

The specific heat capacity of a material can be defined as the heat required to raise the temperature by one degree Celcius in one unit of substance.

Whenever the heat energy is lost or supplied the temperature of the substance will be changed:

Q = mCΔT

Given, the mass of the water, m = 30 g = 0.030 kg

The change in the temperature = 50 - 45 = 5 K

ΔT = 5 K

The specific heat capacity of the water, C = 4184 J/Kg K

The heat required for the given change in temperatures can be calculated as:

Q = 0.03 × (4184) × 5

Q = 627.6 J

Therefore, the heat required is equal to 627.6 J.

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Answer:

\(0.00153\ \text{gallons}\)

Explanation:

\(1\ \text{milliliter}=0.000264172\ \text{gallons}\)

The given volume of water is \(5.78\ \text{milliliters}\). So,

\(5.78\ \text{milliliters}=(5.78\times 0.000264172)\ \text{gallons}\)

\(=0.00153\ \text{gallons}\)

The volume of the given water in gallons is \(0.00153\ \text{gallons}\).

Carbon atoms 1 - 7 are all sp2 hybridized carbon atoms while carbon 8 is sp3 hybridized.

The term hybridization has to do with the mixing of atomic orbitals in order to obtain molecular orbitals that are of appropriate energy and can be able to participate in bonding. The idea of hybridization is rooted in the valence bond theory.

Now we have the compound as has been shown in the image attached to the question, there are carbon atoms that have been numbered from one to eight. We are to identify the hybridization pattern in each atom.

We can see that atoms 1 - 7 are all sp2 hybridized carbon atoms while carbon 8 is sp3 hybridized.

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The enthalpy of combustion for 1kg of urea is -1223525.84 J/mol.

Urea is a compound that is used in fertilizers and in some plastics.The enthalpy of combustion for urea is the amount of energy that is released when urea is burned. In order to calculate the enthalpy of combustion for 1kg of urea, we need to use the information that is provided to us in the question. Let us start by writing down the balanced equation for the combustion of urea: CO(NH2)2 + 3/2 O2 → CO2 + 2H2O + N2
The balanced equation shows that 1 mole of urea reacts with 1.5 moles of oxygen gas to produce 1 mole of carbon dioxide, 2 moles of water, and 1 mole of nitrogen gas. The enthalpy change for this reaction is equal to the amount of energy that is released when 1 mole of urea is burned.
The heat of combustion (ΔHc) of urea is -632.6 kJ/mol. This means that 632.6 kJ of energy is released when 1 mole of urea is burned. We know that 12g of urea raised the temperature of water by 30°C. We can use this information to calculate the amount of energy that was released when 12g of urea was burned.
The specific heat capacity of water is 4.18 J/g°C. This means that it takes 4.18 J of energy to raise the temperature of 1 gram of water by 1°C. Therefore, it takes 4.18 x 1000 = 4180 J of energy to raise the temperature of 1 kg of water by 1°C.
We know that 12g of urea raised the temperature of water by 30°C. Therefore, the amount of energy that was released when 12g of urea was burned is:
Energy = mass x specific heat capacity x temperature change
Energy = 0.012 kg x 4180 J/kg°C x 30°C
Energy = 1497.6 J
We can now use this information to calculate the enthalpy of combustion for 1kg of urea:
Enthalpy of combustion = energy released / moles of urea burned
Enthalpy of combustion = 1497.6 J / (0.012 kg / 60.06 g/mol)
Enthalpy of combustion = - 1223525.84 J/mol
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Answer:

Cs

Br

Ti

Explanation:

As we move down the group atomic radii increased with increase of atomic number. The addition of electron in next level cause the atomic radii to increased. The hold of nucleus on valance shell become weaker because of shielding of electrons thus size of atom increased.  In this way atomic radii of Cs is larger than K and size of Br is larger than F.

As we move from left to right across the periodic table the number of valance electrons in an atom increase. The atomic size tend to decrease in same period of periodic table because the electrons are added with in the same shell. When the electron are added, at the same time protons are also added in the nucleus. The positive charge is going to increase and this charge is greater in effect than the charge of electrons. This effect lead to the greater nuclear attraction. The electrons are pull towards the nucleus and valance shell get closer to the nucleus. As a result of this greater nuclear attraction atomic radius decreases

Thus size of As is smaller than Ti.

The chemical equation that is balanced is:

2 KClO3 ( s )+ MnO2 (s)→ 2 KCl ( s ) + 3 O2 (g) ​

Potassium chlorate (s) when heated in the presence of a manganese dioxide catalyst: When heated in the presence of a manganese dioxide catalyst, potassium chlorate (s) decomposes to create potassium chloride and oxygen gas.

The chemical equation that is balanced is:

2 KClO3 ( s )+ MnO2 (s)→ 2 KCl ( s ) + 3 O2 (g) ​

When potassium chlorate (KClO3) is heated in the presence of manganese dioxide catalyst, it decomposes to form potassium chloride and oxygen gas. The reaction is termed as decomposition reaction.

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Answer: The answer is 94.25 × 10¯¹² g.

The current passing through the inductor is 3.8 A. The correct option is D. 3.8 A

From the question, we are to determine the current passing through the inductor.

From the formula, for the energy stored in a magnetic field

E = 1/2LI²

Where E is the energy

L is the inductance

and I is the current

From the given information,

E = 3.6 J

L = 0.50 H

Putting the parameters into the formula, we get

3.6 = 1/2 × 0.50 × I²

3.6 = 0.25 × I²

I² = 3.6 ÷ 0.25

I² = 14.4

I = √14.4

I = 3.7947

I ≅ 3.8 A

Hence, the current passing through the inductor is 3.8 A. The correct option is D. 3.8 A

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Answer:

B

Explanation:

FUN is not building block of matter.

The first half-reaction is the oxidation of Cr2O7^2– to Cr^3+ and the second half-reaction is the reduction of I^– to IO3^–. When combined, the overall reaction is Cr2O7^2– + I^– → Cr^3+ + IO3^–.

The electrolytic cell consists of two electrodes, one anode and one cathode, both of which are immersed in an electrolyte solution. At the anode, the Cr2O7^2– ions are oxidized to Cr^3+ ions, releasing electrons into the external circuit.

At the cathode, the I^– ions are reduced to IO3^– ions, and the electrons from the external circuit are used to drive the reaction. The electrolyte solution must contain both Cr2O7^2– and I^– ions in order to facilitate the transfer of electrons between the electrodes.

The overall reaction is driven by the potential difference between the anode and the cathode, which is created by the flow of electrons through the external circuit.

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Answer:

All of the energy from the Sun that reaches the Earth arrives as solar radiation, part of a large collection of energy called the electromagnetic radiation spectrum. Solar radiation includes visible light, ultraviolet light, infrared, radio waves, X-rays, and gamma rays. Radiation is one way to transfer heat.

Answer:

1 kinetic and potential 3 reflective transparent

The mass of the asteroid is C. 1.2 x \(10^{12}\) Kg

To find the mass of the other asteroid, we can rearrange the equation for the gravitational force between two objects:

F = (G * m1 * m2) / \(r^{2}\)

where F is the force of gravity, G is the gravitational constant, m1 and m2 are the masses of the two asteroids, and r is the distance between them.

Given that the distance between the asteroids is 75000 m, the force of gravity between them is 1.14 N, and one asteroid has a mass of 8 x \(10^{7}\) kg, we can substitute these values into the equation and solve for the mass of the other asteroid (m2):

1.14 N = (6.67430 × \(10^{-11}\) N \(m^{2}\)/\(Kg^{2}\) * 8 x \(10^{7}\) kg * \(m2\)) / \((75000 m)^{2}\)

Simplifying and solving the equation, we find that the mass of the other asteroid (m2) is approximately 1.2 x \(10^{12}\) kg. Therefore, Option C is correct.

The question was incomplete. find the full content below:

Two asteroids are 75000 m apart one has a mass of 8 x \(10^{7}\) kg if the force of gravity between them is 1.14 what is the mass of the asteroid

A. 3.4 x \(10^{11}\) kg

B. 8.3 x \(10^{12}\) kg

C. 1.2 x \(10^{12}\) kg

D. 1.2 x \(10^{10}\) kg

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a lab student do to response should be,  If doing so does not cause a delay in the evacuation, leave the room while removing your personal things. Observe the TA's and the lab staff's instructions.

Notify the emergency personnel of any other residents who require help leaving. Close the doors, leave the area, and dial 9-1-1 from a secure location. student can do the experiments they have learnt about in textbooks or from their professors in a scientific lab. They have a better understanding of an experiment's methodology and potential outcomes in this way. a location outfitted for scientific experimentation or for testing and analysis. a research centre. A location that allows for experimentation, observation, or practise in a particular field of study. The abbreviation lab comes from the mediaeval Latin word laboratorium.

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The percent composition of oxygen in beryllium nitrate, Be(NO3)2 is  72.166%.

Percent composition is very straightforward. Percent composition indicates the percentage of each element in a compound by mass. A chemical compound is made up of two or more elements.

Percent composition is important because it allows us to calculate the percentage of each element in a compound. Here, the quantity is measured in terms of grams of the elements present.

For example, if we know the mass and chemical composition of a substance, we can find out the number of moles and calculate the number of atoms or molecules in the sample.

In  Be(NO3)2 the percent composition of Beryllium (Be) is 6.775%, Nitrogenium (N) is 21.060% and Oxygenium (O) is72.166%.

Thus, The percent composition of oxygen in beryllium nitrate, Be(NO3)2 is 72.166%.

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