Shelby the Skater's rocket provides a forward force of
220 Newtons. Shelby has a mass of 60. kg. If friction
provides a resistive force of 30. Newtons, then at what
rate does Shelby accelerate? Show all work.

Answers

Answer 1

Answer:

\(a=3.17\ m/s^2\)

Explanation:

Given that,

Force force acting on the Skater's rocket is 220 N

Resistive force acting on it, F' = 30 N

Mass of Shelby, m = 60 kg

We need to find the acceleration of Shelby. Net force acting on Shelby is given by :

Net force = 220-30

= 190 N

The formula of net force is :

F = ma

a is acceleration of Shelby

\(a=\dfrac{F}{m}\\\\a=\dfrac{190}{60}\\\\a=3.17\ m/s^2\)

So, the acceleration of Shelby is \(3.17\ m/s^2\)


Related Questions

A dog chases a skateboarder travelling at 10.4\,\dfrac{\text{m}}{\text{s}}10.4 sm ​ 10, point, 4, start fraction, start text, m, end text, divided by, start text, s, end text, end fraction. The skateboarder speeds up with a constant acceleration for 39\,\text{m}39m39, start text, m, end text over 3.3\,\text{s}3.3s3, point, 3, start text, s, end text. We want to find the acceleration of the skateboarder over the 3.3\,\text{s}3.3s3, point, 3, start text, s, end text time interval

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Answer:Δx=v0t + 1/2 at 2

The density of air at a pressure of 1x105pa is 1.2kg/m3. What is the root mean
square speed (Vrms) of the air molecules?

Answers

The root mean square speed of the air molecules is 500 m/s.

What is the root mean square velocity?

The term root mean square speed has to do with the average speed of the molecules of a gas. In this case, we need to find the root mean square speed by the use of the pressure and the density of the gas. We have to use the relation;

Root mean square speed = √3 * pressure/ Density

Since 1 Pa = 1 N/m^2

1 x 10^5pa = 1 x 10^5 N/m^2

Then we can now substitute the values;

Root mean square speed = √3 * 1 x 10^5 N/m^2/ 1.2kg/m3

= 500 m/s

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help!!!!!!!! ill give brainliest

help!!!!!!!! ill give brainliest

Answers

Answer:

Below

Explanation:

Final velocity (m/s ) - Initial velocity (m/s)     is the change in velocity

    this will be units of   m/s

   then change in velocity ( m/s)  / change in time (s) = accel ( m/s^2 )

the units of work,energy and power are...............units​

Answers

unit of work is joules

power - watt

energy - joules

Work joul
Energy joul
Power watt or hours

How many millimeters of water can dissolve 5g of lead nitrate

Answers

The solubility of lead nitrate is 52 grams per 100 milliliters of water at 0°C. Since the question does not specify the temperature, we will assume it is 0°C.To calculate the number of millimeters of water required to dissolve 5 g of lead nitrate,

we must first calculate the number of milliliters of water required to dissolve 5 g of lead nitrate.52 grams of lead nitrate can dissolve in 100 milliliters of water. So,5 g of lead nitrate can dissolve in x milliliters of water.= (5 g / 52 g) × 100 mL= 9.6 mLTherefore, 5 g of lead nitrate can dissolve in 9.6 mL of water. However, the question is asking for the number of millimeters of water, not milliliters. Since 1 milliliter of water weighs 1 gram,9.6 milliliters of water will weigh 9.6 grams.Thus, 5 g of lead nitrate can dissolve in 9.6 millimeters of water.

main answer:5 g of lead nitrate can dissolve in 9.6 millimeters of water. :52 grams of lead nitrate can dissolve in 100 milliliters of water. So, 5 g of lead nitrate can dissolve in x milliliters of water.= (5 g / 52 g) × 100 mL= 9.6 mLTherefore, 5 g of lead nitrate can dissolve in 9.6 mL of water. However, the question is asking for the number of millimeters of water, not milliliters. Since 1 milliliter of water weighs 1 gram,9.6 milliliters of water will weigh 9.6 grams.Thus, 5 g of lead nitrate can dissolve in 9.6 millimeters of water.

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Gravitational potential energy is due to....
a. mass and height above the ground
b. the amount of power an object has
c. the speed of an object
d. how far an object is stretched

Answers

Answer:

A

Explanation:

I only think its A because of the gravity part...sorry im not good at explaining

Two tanks A and B are connected by a valve. Tank A contains 3.5 kg of CO at 15∘C and 300kPa. Tank B with a volume =4m3
contains N2​
at 50∘C and 500kPa. The valve connecting the two tanks is opened, and the two gases form a homogeneous mixture at 25∘C. Determine the final pressure in the Ranks.

Answers

The final pressure in the tanks will be determined by the partial pressures of the gases and their respective mole fractions.

When the valve connecting tanks A and B is opened, the CO and N2 gases mix together to form a homogeneous mixture. According to Dalton's Law of Partial Pressures, the total pressure exerted by this mixture is equal to the sum of the partial pressures of each gas. In this case, we need to calculate the partial pressures of CO and N2.

To determine the partial pressures, we first calculate the number of moles of CO and N2 in tanks A and B using the ideal gas law. This involves considering the mass, temperature, and molar mass of each gas. By dividing the number of moles of each gas by the total number of moles in the mixture, we obtain their respective mole fractions.

With the mole fractions in hand, we can calculate the partial pressures of CO and N2 by multiplying their mole fractions by the total pressure in the tanks. Adding these partial pressures together gives us the final pressure in the tanks.

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What would you do with the force and mass to create a situation where the car has the highest acceleration possible?

Answers

from,

F = ma

F is directly proportional to a

a is inversely proportional to m

that is the larger the force the higher the a

the smaller the mass the higher the a

increase the force. decrease the mass.

What is the surface area if the shape?

What is the surface area if the shape?

Answers

Explanation:

Fourteen yard (14) yard

Two kids on roller skates standing facing each other. They push off one another and travel in on opposite directions. If the boy has mass of 60 kg and is going 5.6m/s and the girl is going 7.1 what is the mass of the girl?

Answers

Answer: 37.326 kg

Explanation:
KE = 1/2 mv2,
1/2 m1(v1i)2 + 1/2 m2(vi)2 = 1/2 m1(v1f)2 + 1/2 m2 (v2f)
0.5*60*(5.6)^2 = 0/6*x*(7.1)^2
x = 37.3259

Find the resultant of the following vector

Find the resultant of the following vector

Answers

The resultant is the vector sum of two or more vectors. It is the result of adding two or more vectors together. ... If two or more velocity vectors are added, then the result is a resultant velocity. If two or more force vectors are added, then the result is a resultant force.

if the received power in near earth propagation is -50 dbm at a distance of 4 miles. predict what the received power would be at a range of: a) 2 miles

Answers

The predicted received power at a distance of 2 miles is -44 dBm

The received power in near earth propagation can be predicted using the inverse square law. The inverse square law states that the power received at a given distance is inversely proportional to the square of the distance. In other words, if the distance is doubled, the received power is reduced by a factor of 4.

In this case, the received power at 4 miles is -50 dBm. To predict the received power at 2 miles, we can use the inverse square law:

Received power at 2 miles = Received power at 4 miles + 10*log10(4/2)^2

= -50 dBm + 10*log10(2)^2

= -50 dBm + 6 dB

= -44 dBm

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The Voyager 1 space probe was launched by NASA in 1977. It's now the most distant spacecraft from Earth, as it hurtles into space at over 60,000 km/h. It has run out of fuel, so it can't change its own motion.

One of your friends says, "If Voyager 1 doesn't collide with anything and is too far from anything to be affected by gravity, it will gradually slow down and stop."

I have to either agree or disagree with my friend, then i have to explain.

Answers

The statement, "The Voyager 1 space probe can't change its own motion" is correct and true. The Voyager 1 space probe was launched by NASA in 1977, and since then it has traveled over 14 billion miles away from Earth. It's the most distant spacecraft from Earth.

The Voyager 1 was designed to study the outer solar system and it sent valuable data back to Earth. But, now it has run out of fuel and cannot change its own motion as the thrusters that are responsible for keeping the spacecraft’s antenna pointed toward Earth have to be continuously fired to compensate for the small natural imbalances in its motion. Therefore, the statement is correct that Voyager 1 cannot change its own motion. It is still continuing its journey into space at a speed of over 60,000 km/h and is expected to keep traveling until it reaches other stars and the next galaxy beyond our Milky Way. So, I agree with the statement that the Voyager 1 space probe can't change its own motion.

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A football player threw a football with a velocity of (3.0 m/s x + 5.0m/s y). How far did it travel horizontally?

Answers

The horizontal distance travelled by the football is 3.1 m.

What is the angle of projection of the ball?

The angle of projection of the football is calculated as follows;

tan ( θ ) = Vy / Vx

where;

Vy is the velocity of the ball in the vertical directionVx is the velocity of the ball in the horizontal direction

tan ( θ ) = 5 / 3

tan ( θ ) = 1.667

θ = arc tan (1.667)

θ = 59⁰

The resultant velocity of the ball is calculated as follows;

v = √ (Vx² + Vy²)

v = √ (3² + 5²)

v = 5.83 m/s

The horizontal distance travelled by the football is calculated as follows;

x = v² sin(2θ) /g

where;

v is the resultant velocityg is acceleration due to gravityθ is the angle of projection of the ball

x = [ (5.83)² sin(2 x 59) /9.8 ]

x = 3.1 m

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The process of sediments being compacted and cemented to form sedimentary rocks is called

Answers

Answer:

Lithification is the answer.

when a volcano is about to erupt, the nearby places may also experience an earthquake

TRUE OR FALSE​

Answers

Answer:

True

Explanation:

Volcanically-caused long period earthquakes are produced by vibrations generated by the movement of magma or other fluids within the volcano. Pressure within the system increases and the surrounding rock fails, creating small earthquakes.

An object falling through space by the force of gravity reaches a terminal velocity speed of:_____.

Answers

An object falling through space by the force of gravity reaches a terminal velocity speed of 9.8m/\(s^{2}\)

Terminal velocity Near the surface of the Earth, any object falling freely will have an acceleration of about 9.8 metres per second squared (m/s2).

What is Terminal Velocity?

Terminal velocity is the maximum velocity (speed) attainable by an object as it falls through a fluid (air is the most common example).

It occurs when the sum of the drag force (Fd) and the buoyancy is equal to the downward force of gravity (FG) acting on the object.

Since the net force on the object is zero, the object has zero acceleration.

At terminal velocity, the object moves at a steady speed in a constant direction because the resultant force acting on it is zero.

In fluid dynamics an object is moving at its terminal velocity if its speed is constant due to the restraining force exerted by the fluid through which it is moving.

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CAN SOMEONE DO THIS FOR ME PLEASE CHECK THE COMMENT FOR THE LINK TO THE ASSESSMENT

Answers

Answer:

yes.................

The earth attracts an apple with a force of 15 Newton. taking this as an action force, how much is reaction force? who accepts the reaction force? on which body does a reaction force act?

Answers

Answer:

action = reaction

land accepts

reaction force acts on the apple

Answer:

15 Newton

Explanation:

According to Newton's third law of motion, "Every action has a reaction which is equal in magnitude but opposite in direction" (Right now, we're not talking about direction, so we'll ignore it)

So,

Action Force = Reaction Force

Reaction Force = 15 N

The action force is by the Earth on the Apple, So the reaction force will be by the Apple on the Earth.

Which type radiation can be observed well from Earth's surface?

Answers

Answer:

Eletromagnetic radiation which is also known as visible light.

Explanation:

Answer:

Gamma Ray's as they have the shortest wavelength and highest frequency in the electromagnetic Spectrum.

A student did 24 J of work on a chair. She applied a force of 12 N and moved the chair 2 m. What else do you need to know to determine the amount of power used?

Answers

Answer:

time

Explanation:

power = work done ÷ time

  do batteries produce or make energy

Answers

Batteries Produce energy

Answer:

Batteries are intended to store chemical energy and then it converts into electricidal energy. So overall, batteries produce energy.

Explanation:

HELPPPPP!!!!! ME PLSSSS I don't know the answer!!!****URGENT****

HELPPPPP!!!!! ME PLSSSS I don't know the answer!!!****URGENT****

Answers

Answer:

D is the Answer

Explanation:

I know D is the answer because I calculated it and got answer choice D

find the frequency of oscillation for the spring system of part i where . (round your answer to three decimal places with a leading zero if necessary, i.e. 0.xxx or x.xxx)

Answers

The frequency of oscillation for the spring system of part i is 0.719 Hz.

Explanation: The frequency of a system is a measure of the number of cycles it completes per second, which is proportional to the square root of the ratio of the spring constant to the mass of the system.

In this case, the spring constant is given as k=2.5 N/m and the mass of the system is given as m=0.35 kg. Plugging these values into the equation for frequency, we get frequency (f) = 1/2π * sqrt(k/m) = 1/2π * sqrt(2.5/0.35) = 0.719 Hz. This result can be rounded to three decimal places, giving us 0.719 Hz.

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In what direction is matter displaced in a traverse wave

A. In the same direction of the energy flow

B. In the opposite direction of the energy flow

C. In a spiral around the energy flow

D. At a right angle to the energy flow

Answers

Answer:

In a transverse wave, the matter is displaced perpendicular (at a right angle) to the direction of energy flow. Therefore, the correct answer is D.

Explanation:

A student designed an experiment to show how water is recycled through the atmosphere. The steps of the experiment are shown below. Boil 500 mL of water in a beaker. Hold a hot glass plate a few inches above the beaker with a pair of tongs. Observe water droplets on the glass plate. The student did not see water dripping off the glass plate as expected because the experiment had a flaw. Which of these statements best describes a method to correct the flaw in this experiment?

Hold the glass plate closer to the beaker.

Boil the water in a pan instead of a beaker.

Take more than 500 mL of water in the beaker.

Use a cold glass plate instead of a hot glass plate.

Answers

The flaw in the experiment on water recycling is that the student did not see water dripping off the glass plate as expected. To correct this flaw, the student should use a cold glass plate instead of a hot glass plate.

The correct option to the given question is option 4.

When the student holds the hot glass plate above the beaker, the water vapor in the atmosphere will come into contact with the cold surface of the plate and condense, forming water droplets. However, if the glass plate is already hot, it will not be able to cool down the water vapor quickly enough for condensation to occur.

By using a cold glass plate, the temperature difference between the plate and the water vapor will be greater, allowing for faster condensation. This will result in water droplets forming on the glass plate and dripping off, demonstrating the process of water recycling through the atmosphere.

Therefore, the correct method to correct the flaw in this experiment is to use a cold glass plate instead of a hot glass plate. This will enable the student to observe water droplets on the glass plate as expected.

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The earth rotates once per day about an axis passing through the north and south poles, an axis that is perpendicular to the plane of the equator. Assuming the earth is a sphere with a radius of 6.38 106 m, determine the speed and centripetal acceleration of a person situated at each of the following.(a) the equatorm/sm/s^2(b) a latitude of 63.0° north of the equatorm/sm/s^2

Answers

a) The speed and centripetal acceleration of a person situated at the equator is 463.3 m/s and 3.39 m/s^2.

b)  The speed and centripetal acceleration of a person situated at the latitude of 63.0° north of the equator is 308.5 m/s and 2.06 m/s^2

(a) At the equator, a person is situated at a distance of 6.38 x 10^6 meters from the center of the Earth, and the radius of the Earth is the same at this point. The speed of the person can be calculated using the formula:

v = ωr

where ω is the angular velocity of the Earth, and r is the distance from the center of the Earth. The angular velocity of the Earth can be calculated as the angle swept per unit time, which is 2π radians per day or 7.27 x 10^-5 radians per second.

Substituting these values, we get:

v = 7.27 x 10^-5 x 6.38 x 10^6

v = 463.3 m/s

The centripetal acceleration can be calculated using the formula:

a = v^2/r

Substituting the values, we get:

a = (463.3)^2/6.38 x 10^6

a = 3.39 m/s^2

(b) At a latitude of 63.0° north, the person is situated at a distance of r = 6.38 x 10^6 x cos(63.0°) from the center of the Earth. The speed of the person can be calculated using the same formula as before:

v = ωr

Substituting the values, we get:

v = 7.27 x 10^-5 x 6.38 x 10^6 x cos(63.0°)

v = 308.5 m/s

The centripetal acceleration can be calculated using the same formula as before:

a = v^2/r

Substituting the values, we get:

a = (308.5)^2/(6.38 x 10^6 x cos(63.0°))

a = 2.06 m/s^2

In summary, the speed and centripetal acceleration of a person situated at the equator and a latitude of 63.0° north of the equator can be calculated using the formulas v = ωr and a = v^2/r, where ω is the angular velocity of the Earth, r is the distance from the center of the Earth, and v is the speed of the person.

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If an object that was held steady (0 speed) and then dropped, how many meters would it fall in one second?

Answers

Answer:

h = 4.905 m

Explanation:

In order to find the distance covered by the object in 1 second, we can use the second equation of motion:

\(h = v_i t + \frac{1}{2}gt^2\\\)

where,

h = distance covered = ?

vi = initial speed = 0 m/s

g = acceleration due to gravity = 9.81 m/s²

t = time = 1 s

Therefore,

\(h = (0\ m/s)(1\ s)+\frac{1}{2}(9.81\ m/s^2)(1\ s)^2\\\\\)

h = 4.905 m

what is CHA-CHA-CHA.​

Answers

Answer:

The cha-cha-cha, is a dance of Cuban origin. It is danced to the music of the same name introduced by Cuban composer and violinist Enrique Jorrin in the early 1950s. This rhythm was developed from the danzón-mambo

The average wavelength in a series of ocean waves is 15. 0 meters. A wave crest arrives at the shore an average of every 10. 0 seconds, so the frequency is 0. 100 Hz. What is the average speed of the waves?

Answers

A wave crest arrives on the shore a median of every 10. zero seconds, so the frequency is 0. one hundred Hz. The average speed of the waves is 1.five m/s.

We are to decide the common pace of the waves.

Using the formula

v = fλ

Where

v is the speed

f is the frequency

and λ is the wavelength

From the given information

f = 0.1 Hz

λ = 15.0 m

∴ Speed of the wave = 0.1 × 15.0

Speed of the wave = 1.5 m/s

Average speed is defined as the total distance traveled by an object divided by the time taken to cover that distance. It is the measure of the average rate at which an object covers a certain distance in a given amount of time. Mathematically, the average speed is expressed as: Average speed = Total distance traveled / Time taken

It is important to note that average speed is not the same as instantaneous speed, which refers to the speed of an object at a particular instant in time. Average speed takes into consideration the entire adventure, while instant velocity only reflects the velocity at a unmarried moment. The unit of measurement for average speed is meters per second (m/s) or kilometers per hour (km/h), depending on the system of measurement used.

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