shapley, in order to understand the shape of the milky way, traced out the distribution of . a. globular clusters b. neutrinos c. quasars d. black holes

Answer:

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The rate of increase of the radius of the balloon is  0.12 cm/ sec.

The surface area of a strong object is a degree of the entire vicinity that the floor of the item occupies. The surface area is the general place at the floor of a 3-dimensional shape. To discover the floor location of a cuboid that has 6 square faces, upload the regions of all 6 faces. O

The volume of a sphere is 4/3πr^3

The rate of volume of the balloon is 24πcm^3/s

∴ the radius of the sphere at the volume of 24πcm^3= 4/3πr^3

dividing both sides by π

24= 4/3πr^3

multiply both side by 3/4

r^3 = 24×3/4

r^3= 18

r= √18

r= 2.62cm

∴ the rate of change in radius here is 2.62cm/s since π is constant.

The surface area of the sphere= 4πr^2

the surface area of the balloon is 30πcm^2

therefore 30π= 4πr^2

divide both sides by 4π

r^2= 30/4

r^2= 7.5

r=√7.5

r= 2.74cm

The rate of change in radius here is 2.74cm/s

Hence, the increase in the rate of change of radius is 2.74cm/s - 2.62 cm/s= 0.12cm/s

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If you pound a feather with a hammer, which one feels a greater force always the hammer both feather moves, then it felt the greater force.

What is the force?
Force is an influence that produces a change in the motion of an object. It is measured in units of mass times acceleration, or newtons (N). Force is a vector quantity, meaning it has both magnitude and direction. Force can cause an object to accelerate, decelerate, remain in motion, change direction, or alter shape. Examples of forces include gravity, friction, tension, and magnetism. Forces can also be generated by electrical, thermal, and nuclear energy. All forces are generated by the interaction of two objects and can be balanced or unbalanced. Unbalanced forces will cause an object to move or accelerate and balanced forces will cause an object to remain stationary or in motion at a constant speed.

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Answer:

a) Time = 2.67 s

b) Height = 35.0 m

Explanation:

a) The time of flight can be found using the following equation:

\( x_{f} = x_{0} + v_{0_{x}}t + \frac{1}{2}at^{2} \)   (1)

Where:

\( x_{f}\): is the final position in the horizontal direction = 80 m

\( x_{0}\): is the initial position in the horizontal direction = 0

\(v_{0_{x}}\): is the initial velocity in the horizontal direction = 30 m/s

a: is the acceleration in the horizontal direction = 0 (the stone is only accelerated by gravity)

t: is the time =?  

By entering the above values into equation (1) and solving for "t", we can find the time of flight of the stone:  

\( t = \frac{x_{f}}{v_{0}} = \frac{80 m}{30 m/s} = 2.67 s \)

b) The height of the hill is given by:

\( y_{f} = y_{0} + v_{0_{y}}t - \frac{1}{2}gt^{2} \)

Where:

\( y_{f}\): is the final position in the vertical direction = 0

\( y_{0}\): is the initial position in the vertical direction =?

\(v_{0_{y}}\): is the initial velocity in the vertical direction =0 (the stone is thrown horizontally)            

g: is the acceleration due to gravity = 9.81 m/s²

Hence, the height of the hill is:

\( y_{0} = \frac{1}{2}gt^{2} = \frac{1}{2}9.81 m/s^{2}*(2.67 s)^{2} = 35.0 m \)  

I hope it helps you!

Answer:

I can't really see it sorry

Answer:

Because the more coolant passed through the fins, the more energy can be emitted

We'll need to consider the Doppler Effect and how it affects the perception of an observer. The Doppler Effect refers to the change in frequency or wavelength of a wave in relation to an observer who is moving relative to the source of the wave.

Step 1: Identify the markings of both Empire and Federation ships.
Let's assume Empire ships have a specific wavelength marking "A" and Federation ships have a different wavelength marking "B."

Step 2: Calculate the relative speed required to cause the Doppler Effect.
We need to find the speed at which the Empire ship should travel so that its markings appear to have the wavelength of the Federation ship's markings.

To calculate this, we can use the following Doppler Effect equation for wavelengths:

Observed Wavelength (B) = Source Wavelength (A) * \([(1 + v/c)/(1 - v/c)]^{1/2}\)

Here, "v" is the relative speed of the Empire ship, and "c" is the speed of light.

Step 3: Solve for "v."
Rearrange the equation and solve for "v" to find the required speed:

v = c * ([(B/A)² - 1]/[(B/A)²+ 1])

By substituting the values for "A" and "B" and solving for "v," you will obtain the speed an Empire ship has to travel relative to an observer for its markings to be confused with those of a Federation ship.

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Any circuit diagram given the funda is same .

Answer:

see  picture
Sample Response: The lightbulb will light because this is a parallel circuit. Even though the switch is open in one branch, the branch the lightbulb is in forms a closed circuit, allowing the current to flow through the bulb.

Explanation:

When an air parcel rises from 1000mb to 500mb, unsaturated air cools to around -35°C, while saturated air cools to approximately -25°C.

On the Stüve diagram, the solid, straight green lines represent the dry adiabatic lapse rate, which indicates the temperature change of an unsaturated air parcel undergoing vertical motion in the atmosphere. The dashed, curved blue lines represent the temperature change of saturated air undergoing vertical motion, known as the saturated adiabatic lapse rate.

To determine the temperature of the air parcel at 500mb when it rises as unsaturated air, we follow the solid, straight green dry adiabatic lapse rate line from the starting point (17°C, 1000mb) up to 500mb. Following this line, we find that at 500mb, the temperature of the unsaturated air parcel is approximately -35°C.

On the other hand, if the air parcel rises as saturated air, we follow the dashed, curved blue saturated adiabatic lapse rate line from the starting point (17°C, 1000mb) up to 500mb. By following this line, we determine that at 500mb, the temperature of the saturated air parcel is approximately -25°C.

Comparing the temperatures of the unsaturated and saturated air parcels at 500mb, we find that the temperature of the unsaturated air parcel (-35°C) is lower than the temperature of the saturated air parcel (-25°C). Therefore, at 500mb, the temperature of the unsaturated air parcel is lower than the temperature of the saturated air parcel.

This comparison demonstrates that rising unsaturated, clear air cools more than rising saturated, cloudy air over the same pressure change.

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Answer:

Electromagnetism causes like-charged objects to repel each other and oppositely charged objects to attract each other. The electromagnetic force binds negative electrons to the positive nuclei in atoms and underlies the interactions between atoms.

0.5Ω

Since different currents are passing through the resistors, then the resistors are most probably connected in parallel. This also means that the same voltage will pass across them.

Using Ohm's law, the voltage across a resistor in a circuit is given by;

V = I(R + r)            -----------(i)

For the 1ohm resistor, the voltage across it is given by;

Where;

I = current passing through the 1 ohm resistor = 0.6A

R = resistance of the 1 ohm resistor = 1Ω

r = internal resistance of the cell = r

Substitute these values into equation (i) as follows;

V = 0.6(1 + r)                 -------------------(ii)

For the 4.0ohm resistor, the voltage across it is given by;

Where;

I = current passing through the 4.0 ohms resistor = 0.2A

R = resistance of the 4.0 ohms resistor = 4.0Ω

r = internal resistance of the cell = r

Substitute these values into equation (i) as follows;

V = 0.2(4.0 + r)                 -------------------(iii)

Now solve equations (ii) and (iii) simultaneously;

V = 0.6(1 + r)

V = 0.2(4.0 + r)

Substitute the value of V in equation (ii) into equation (iii). Therefore, we have;

0.6(1 + r) = 0.2(4.0 + r)

Solve for r

0.6 + 0.6r = 0.8 + 0.2r

0.6r - 0.2r = 0.8 - 0.6

0.4r = 0.2

r = \(\frac{0.2}{0.4}\)

r = 0.5

Therefore, the internal resistance of the cell is 0.5Ω

No, the claim is not valid. The coefficient of performance (COP) of a heat pump is defined as the ratio of the desired heat output to the required work input.

The coefficient of performance (COP) of a heat pump is defined as the ratio of the desired heat output to the required work input. It is given by the formula:

COP = Q_out / W_in

Where Q_out is the heat output and W_in is the work input.

In this case, the coefficient of performance is claimed to be 1.8. The heat pump is heating a building with an interior temperature of 300 K and using the atmospheric air surrounding the building at 260 K.

For a heat pump operating between two temperature reservoirs, the ideal maximum COP can be calculated using the Carnot efficiency:

COP_max = T_out / (T_out - T_in)

Where T_out is the higher temperature and T_in is the lower temperature.

Substituting the given values:

COP_max = 300 K / (300 K - 260 K) = 300 K / 40 K = 7.5

The maximum possible COP for the given temperature difference is 7.5. However, the claimed COP is only 1.8, which is significantly lower than the maximum.

Therefore, the claim that the heat pump has a coefficient of performance of 1.8 is not valid. It suggests that the heat pump is not operating efficiently and may require further evaluation or improvement.

The claim of a coefficient of performance of 1.8 for the heat pump is not valid. The calculated maximum COP based on the given temperature difference is 7.5, indicating that the heat pump is not operating at its optimal efficiency.

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The tension force F in a guitar string designed to play a note of 220 Hz, with a mass per unit length of 2.35 g/m and vibrating between points 60.0 cm apart  is approximately 73.92 N.

To find the tension, we can use the formula for the wave speed (v) in terms of frequency (f) and wavelength (λ): v = fλ. The wavelength is twice the distance between the two points of vibration, so λ = 2(60.0 cm) = 120.0 cm = 1.2 m. We know the frequency is 220 Hz.

Rearranging the wave equation, we have v = fλ, and solving for v, we get v = (f/λ). The wave speed is also related to the tension (F) and the mass per unit length (μ) of the string through the formula v = √(F/μ).

Equating these two expressions for the wave speed, we have (f/λ) = √(F/μ). Plugging in the values we know, the equation becomes (220 Hz)/(1.2 m) = √(F/2.35 g/m). Squaring both sides of the equation and rearranging, we find F = (220 Hz)^2 * 2.35 g/m * (1.2 m)^2 = 73.92 N.

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Answer:

1. Range = 153.42 m.

2. Maximum height = 54.78 m

3. Time of flight = 6.69 s

Explanation:

From the question given above, the following data were obtained:

Initial velocity (u) = 40 ms¯¹

Angle of projection (θ) = 55°

1. Determination of the range.

Initial velocity (u) = 40 ms¯¹

Angle of projection (θ) = 55°

Acceleration due to gravity (g) = 9.8 ms¯²

Range (R) =?

The range i.e how far the ball went can be obtained as follow:

R = u² Sine 2θ /g

R = 40² × Sine (2×55) / 9.8

R = 1600 × Sine 110 / 9.8

R = 1600 × 0.9397 /9.8

R = 153.42 m

2. Determination of the maximum height.

Initial velocity (u) = 40 ms¯¹

Angle of projection (θ) = 55°

Acceleration due to gravity (g) = 9.8 ms¯²

Maximum height (H) =?

H = u² Sine² θ / 2g

H = 40² × (Sine 55)² / 2 × 9.8

H = 1600 × (0.8192) ² / 19.6

H = 54.78 m

3. Determination of the time of flight

Initial velocity (u) = 40 ms¯¹

Angle of projection (θ) = 55°

Acceleration due to gravity (g) = 9.8 ms¯²

Time of flight (T) =?

T = 2u Sine θ / g

T = 2 × 40 × Sine 55 / 9.8

T = 80 × 0.8192 / 9.8

T = 6.69 s

When a neutral hard rubber rod is rubbed with wool and the rod becomes negatively charged, an excess of electrons is transferred from the wool to the rod.

When two materials are rubbed together, such as a hard rubber rod and wool, the rubbing action can cause the transfer of electrons between the two materials. This transfer occurs due to differences in the electron affinity of the materials.

In this scenario, as the hard rubber rod is rubbed with wool, electrons are transferred from the wool to the rod. The wool has a higher electron affinity, meaning it has a greater tendency to gain electrons. As a result, the rod gains an excess of electrons, acquiring a negative charge.

Electrons are negatively charged particles, and when the rod gains an excess of electrons, it becomes negatively charged. The transfer of electrons from the wool to the rod leads to a charge separation, with the wool becoming positively charged (due to the loss of electrons) and the rod becoming negatively charged (due to the gain of electrons).

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Neptune's mass, speed, and diameter, as well as those of each moon. when a physicist wants to create a computer model to forecast the impact of gravitational forces.

An example of an amphetamine is speed. It is a psychoactive drug that releases significant amounts of dopamine. A chemical in the brain associated with reward and pleasure is called dopamine. There are several types of amphetamines.

Speed is often compared to words like dispatch, enterprise, haste, and rush. These phrases all refer to "quickness in move or action," but speed implies quick effectiveness in movement or activity.

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Answer: 1.62 m/s

Explanation:

Distance/time=speed

12 hours in minutes is 720

12x60=720

720 minutes in seconds is 43200

720x60=43200

70000/43200=1.62037

1.62 m/s

Answer: time is inversely proportional to acceleration and free-falling bodies have acceleration.

Explanation:

according to the first equation of motion ;

a=V-v/t

where V is the final velocity and v is the initial velocity. putting the value of a as g we get;

g=V-v/t

shows the relation of g and t(gravitational acceleration and time) of free-falling bodies.

Answer:

Vx=15.3*cos65°=6.47m/s

Explanation:

Vx=15.3*cos65°=6.47m/s

Vy=15.3*sin65°=13.87m/s

The magnetic field at point P is approximately 4.915 x 10⁻⁵ T.

To calculate the magnetic field at point P, we need to use the formula for the magnetic field due to a straight current-carrying wire, which is given by:

Magnetic field (B) = (μ₀ × I) / (2 × π × R)

In this formula, μ₀ is the permeability of free space (4π x 10⁻⁷ Tm/A), I is the current in the wire, and R is the distance from the wire to point P.

Given the values a = 1.2 cm, b = 5.45 cm, and I = 21.7 a, we first need to determine the distance R using the Pythagorean theorem:

R² = a² + b²
R² = (1.2 cm)² + (5.45 cm)²
R² = 1.44 + 29.7025
R² = 31.1425
R = √31.1425
R ≈ 5.58 cm

Now, we can calculate the magnetic field (B) at point P:

B = (μ₀ × I) / (2 × π × R)
B = (4π x 10⁻⁷ Tm/A × 21.7 A) / (2 × π × 0.0558 m)
B ≈ (2.743 x 10⁻⁶ T) / 0.0558 m
B ≈ 4.915 x 10⁻⁵ T

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Answer:

Einstein's Big Idea homepage. E = mc2. It's the world's most famous equation, but what does it really mean? "Energy equals mass times the speed of light squared." On the most basic level, the equation says that energy and mass (matter) are interchangeable; they are different forms of the same thing.

Explanation:

hope it helps

Answer:

it means energy is equivalent to the product of the mass of an object and the square of the speed of light.

No, you cannot take your phone in a tanning bed. Tanning beds use ultraviolet (UV) light to help people achieve a dark, even tan. However, this light can damage electronic devices, such as cell phones.

The heat generated by the bulbs and the strong UV radiation can damage the phone’s internal components and cause the phone to overheat. This can lead to short circuits and permanent damage to the phone.

In addition to the damage caused by UV light, the high temperatures of the tanning bed may cause the phone to overheat, leading to further damage, such as battery failure. Overheating may also cause the phone to shut down or restart unexpectedly, resulting in data loss and further damage.

Finally, taking your phone into a tanning bed may be a distraction. Tanning beds require the user to remain still and relaxed in order to achieve optimal results. Having your phone in the bed may disrupt this process and lead to a less effective tanning session.

For all of these reasons, it is not recommended to take your phone into a tanning bed. Doing so may cause irreparable damage to the device and may disrupt the tanning process.

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Answer:

Convex lenses concentrates the light energy to one spot on the paper so that the heat energy accumulates on that one small spot of paper. ... As the heat increases, combustion will occur when the spot becomes too hot and the paper will burn.

Explanation:

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In conclusion, the part of the light that reflects back into the water makes an angle of 20° to the normal.

When a diver shines light upward to the surface of a smooth pond at an angle of 20° to the normal, most of the light will pass into the air above the water.

However, a portion of the light will reflect back into the water.
To determine the angle at which the reflected light makes with the normal, we need to apply the law of reflection. According to this law, the angle of incidence is equal to the angle of reflection.
In this case, the angle of incidence is 20° to the normal. Since the angle of reflection is equal to the angle of incidence, the light will reflect back into the water at an angle of 20° to the normal as well.
In conclusion, the part of the light that reflects back into the water makes an angle of 20° to the normal.

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Answer:

a. 3.75 s b. 28.125 m

Explanation:

Vi = 15 m/s

Vf = 0 m/s

a = -4 m/s²

i) t = ?

ii) S = ?

i) Using Newton's 1st Eq of Motion

Vf = Vi + at

t = (Vf - Vi) / a

t = (0 - 15) / -4

t = 3.75 s

ii) Using Newton's 3rd Eq of Motion

2aS = Vf² - Vi²

S = (Vf² - Vi²) / 2a

S = (0² - 15²) / 2 x -4

S = 28.125 m

Answer: two, wobble, eclipsing

Explanation: I am watching the video now

Answer:

Two Wobble eclipsing

Explanation:

I got it right on the Assignment. :)

The latent image in a flat-panel detector is formed by  A. Trapped electrons.

The latent image in a flat-panel detector is formed by trapped electrons.

A flat-panel detector is a type of digital X-ray detector that is commonly used in medical imaging. It consists of an array of detector elements, also known as pixels, that convert X-rays into electrical signals. These electrical signals are then processed to produce a digital image.

When X-rays pass through the detector material, they interact with atoms in the material, causing the release of electrons. These electrons are then trapped in the detector material, creating a temporary electrical charge in the pixels. This charge distribution forms the latent image.

After the exposure is complete, the electrical charges in the pixels are read out and processed to produce the final image. This is done by applying a voltage to the pixels, which causes the trapped electrons to be released and flow to a readout circuit. The amount of charge that is read out is proportional to the X-ray dose that was absorbed by the pixel.

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