Shane bought an 18 pound bag of dog food. He feeds his dog pound of dog food 5/3 for each meal. If Shane feeds his dog twice a day every day, how many days will the 18 pound bag of dog food last?

Answer:

145

.8x = 116 (80% of class is 116)

x=145

Step-by-step explanation:

if the visitor runs at a rate of 6 mph and swims at a rate of 2.5 mph., then the visitor  would run 14 .45 miles  before swimming to minimize the time it takes to reach the island .

we are given that an island is 1 mi due north of its closest point along a straight shoreline., where the visitor is staying at a cabin on the shore that is 15 mi west of that point, in some point the visitor runs at a rate of 6 mph and swims at a rate of 2.5 mph. Considering x be the distance the visitor runs. so the total time will be :

Time (T)= x/6 + √((15-x)²+1²)/2.5

Differntiating both sides respect to  x , we get

dT/dx = 1/6 -(15-x)/√(15-x)²+1)/2.5

=>1/6 = (15-x)/√(15-x)²+1)/2.5

=>6(15-x) = 2.5√(15-x)²+1)

Now considering   15 - x = y, we get  

=>6y = 2.5√(y²+1)

=>36y² = 6.25y² + 6.25

=>29.75y² = 6.25

y = √(25/119),  therefore ,x = 15 - √(25/119) = 14 .45

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Answer:

Step-by-step explanation:

Candice = 25mph for 4 hours.

Candice has driven= 25 * 4= 100miles.

Liz =50mph

Liz time to catch up to candice= 50 * 2= 100miles.

Therefore, It would have taken Liz two hours to catch up with Candice

To convert a fraction into a decimal you have to divide the numerator by the denominator. For example, to convert 39/8, you need to divide 39 by 8, which is equal to 4.875.

For the matrix the true statement is given by option d. Both A and B are false.

Let's analyze each statement of the matrix as follow,

A) If A is a 3 times 5 matrix and T is a transformation defined by T(x) = Ax, then the domain of T is R⁵.

This statement is false.

The domain of the transformation T is not R⁵.

The domain of T is determined by the dimensionality of the vectors x that can be input into the transformation.

Here, the matrix A is a 3 times 5 matrix, which means the transformation T(x) = Ax can only accept vectors x that have 5 elements.

Therefore, the domain of T is R⁵, but rather a subspace of R⁵.

B) If A is a 3 times 2 matrix, then the transformation x right arrow Ax cannot be onto.

This statement is also false.

The transformation x → Ax can still be onto (surjective) even if A is a 3 times 2 matrix.

The surjectivity of a transformation depends on the rank of the matrix A and the dimensionality of the vector space it maps to.

It is possible for a 3 times 2 matrix to have a rank of 2,

and if the codomain is a vector space of dimension 3 or higher, then the transformation can be onto.

Therefore, as per the matrix both statements are false, the correct answer is d. Both A and B are false.

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The above question is incomplete, the complete question is:

Which of the following best characterizes the following statements:

A) If A is a 3 times 5 matrix and T is a transformation defined by T(x) = Ax, then the domain of T is R^5

B) If A is a 3 times 2 matrix, then the transformation x right arrow Ax cannot be onto

a. Only A is true

b. Only B is true

c. Both A and B are true

d. Both A and B are false

The correct option is B) Not valid. Consider the statement “Since some shoes are sneakers, some non-sneakers are non-shoes.”

We know that all sneakers are shoes, but all shoes are not sneakers.  Hence, some shoes are sneakers. But, this statement does not imply that “some non-sneakers are non-shoes.” This inference cannot be drawn by contraposition. So, it is not valid.Inferences cannot be drawn in contraposition all the time. Contraposition is a type of logical statement that involves reversing and negating the terms of an original proposition. It is a logical relationship between a proposition and its converse. If a proposition is true, the contrapositive is always true.An example of contraposition can be shown as follows:“If a person is a human, then they are mortal.”We can write the contrapositive of this statement as:“If a person is not mortal, then they are not human.”

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The equation of the line of best fit is y = 0.2365x + 66.134, and the absolute value of the correlation coefficient is 0.197.

Given, the relationship between number of pitches and the average speed of the pitches can be shown through a scatter plot as follows. Using the given data, the scatter plot is shown below: From the graph, we observe that the points form a somewhat linear pattern.

Thus, we can add a line of best fit to the graph to understand the relationship between the two variables better. To determine the line of best fit, we will use the linear regression tool on the graphing calculator. For that, we need to select the “Relationship” tab and then select “Linear Regression” from the drop-down menu.

The equation of the line of best fit and the absolute value of the correlation coefficient are given as follows. Line of best fit: y = 0.2365x + 66.134|Correlation Coefficient| = 0.197. Therefore, the equation of the line of best fit is y = 0.2365x + 66.134, and the absolute value of the correlation coefficient is 0.197.

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Answer:

\( \frac{-9x^-1y^-9}{ - 15 {x}^{5} {y}^{ - 3} } = \)

\( = \frac{3}{ {x}^{6 } {y}^{6}5} \)

Step-by-step explanation:

2nd one is the answer

Answer:

b

Step-by-step explanation:

The number the teacher gave Ross is 5127

From the question, we are to determine the number that the teacher gave Ross

From the given information,

Mr. David gave Ross a number and asked him to divide it by 15.

Let the number be x

That is,

x/15

The quotient and remainder obtained by ross are 341 and 12 respectively

That is,

x/15 = 341 + 12/15

Now, we will solve the equation for x

x/15 = 341 + 12/15

Multiply through by 15

x = 15×341 + 12

x = 5115 + 12

x = 5127

Hence, the number the teacher gave Ross is 5127

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Answer:

m∠A = 31°

c = 50.02 feet

Step-by-step explanation:

m∠A = 180° - m∠B - m∠C = 180° - 29° - 120° = 31°

sinB/b = sinC/c

sin(29)/28 = sin(120)/c

c*sin(29) = 28sin(120)

c = 28sin(120)/sin(29)

c ≈ 50.02

Answer: To estimate how many Hershey's Kisses can be made with 200 gallons of liquid chocolate, we need to make a number of assumptions and estimates based on the available information.

First, we need to determine how much liquid chocolate is required to make a single Hershey's Kiss. This information is not readily available, but we can estimate based on the weight of a single Kiss and the density of chocolate. According to Hershey's website, a single Hershey's Kiss weighs about 4.5 grams. The density of chocolate varies depending on the type of chocolate and the specific recipe, but we can assume a density of around 1.2 grams per milliliter.

To convert 200 gallons to milliliters, we can use the conversion factor 1 gallon = 3785.41 milliliters. So:

200 gallons x 3785.41 milliliters/gallon = 757,082 milliliters

Assuming a density of 1.2 grams per milliliter, 757,082 milliliters of liquid chocolate would weigh:

757,082 milliliters x 1.2 grams/milliliter = 908,498 grams

Dividing this total weight of chocolate by the weight of a single Hershey's Kiss (4.5 grams) gives an estimate of the total number of Kisses that could be made with 200 gallons of liquid chocolate:

908,498 grams ÷ 4.5 grams/Kiss ≈ 201,778 Kisses

Of course, this is a rough estimate that makes a number of assumptions and simplifications. In reality, the actual number of Hershey's Kisses that could be made with 200 gallons of liquid chocolate would depend on a variety of factors, including the specific recipe and production process, as well as the size and shape of the Kisses themselves. However, this estimate provides a reasonable starting point for further analysis and exploration.

Step-by-step explanation:

Answer:

7.07070707E15

Step-by-step explanation:

A bridge is to be built across a small lake from a gazebo to a dock. The length of the bridge is 120 feet. The angle between the shore and the line segment connecting the gazebo to the dock is 40 degrees.

How far is the gazebo from the shore?The bridge is to be built from the gazebo to the dock, the shore to the gazebo is the hypotenuse, and the shore to the dock is the opposite side of the angle (40°).Let's use SOH-CAH-TOA to solve the problem.

Step 1: Identify the knowns and unknowns.The length of the bridge = opposite side of 40° angle = 120 feetUnknown: the distance from the gazebo to the shore

Step 2: Use the trigonometric ratio SOH-CAH-TOA.The adjacent side of 40° angle is the distance from the gazebo to the shore.Using the tangent trigonometric ratio, we can write:\[\tan 40^\circ = \frac{\text{opposite}}{\text{adjacent}}\]

Step 3: Substitute the known values and solve for the unknown.\[\begin{aligned}\tan 40^\circ &= \frac{\text{opposite}}{\text{adjacent}} \\ \text{opposite} &= \tan 40^\circ \cdot \text{adjacent} \\ \text{opposite} &= \tan 40^\circ \cdot 120\end{aligned}\]

Now we can calculate the distance from the gazebo to the shore:\[\text{opposite} = \tan 40^\circ \cdot 120 \approx 90.58\,\text{feet}\]

Therefore, the gazebo is approximately 90.58 feet from the shore.

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Answer:

one solution only

Step-by-step explanation:

16y + 7 = -3y + 10 + 8y

16y + 3y - 8y = 10 - 7

11y = 3

y = 3/11

To obtain the equation 2x² + 3xy from x² xy y², you would need to add 1x² and 2xy to the original equation.

In order to obtain the equation 2x² + 3xy from x² xy y², you must add some terms to the original equation. The equation 2x² + 3xy represents a polynomial of degree 2, with x² and xy as the leading terms.

The original equation, x² xy y², is also a polynomial of degree 2, but it does not have the same leading terms as the desired equation.

By adding terms to the original equation, we can change the coefficients of the leading terms to match those of the desired equation. In this case, we need to add 1x² and 2xy to the original equation.

This can be simplified as x² + xy + y² + x² + 2xy = 2x² + 3xy. The polynomial x² and 2xy should be added to x² xy y² to get 2x² + 3xy.

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Answer: 2/5

Step-by-step explanation: hope it helps

The point at which this cable would pass through the road shown is at the y-intercept of (0, -17/2).

Mathematically, the slope of a straight line can be calculated by using this formula;

Slope, m = (Change in y-axis, Δy)/(Change in x-axis, Δx)

Slope, m = (y₂ - y₁)/(x₂ - x₁)

By critically observing the road shown in the graph above, the points on the line include the following:

Points (x, y) = (0, -2)

Points (x, y) = (-3, 0)

Substituting the given points into the formula, we have;

Slope, m = (0 + 2)/(-3 - 0)

Slope, m = 2/-3

Slope, m = -2/3.

In Mathematics, a condition that must be met for two lines to be perpendicular is given by:

m₁ × m₂ = -1

-2/3 × m₂ = -1

-2m₂ = -3

m₂ = 3/2

At point (7, 2), a linear equation for the line can be calculated by using the point-slope form:

y - y₁ = m(x - x₁)

Where:

Substituting the given points into the formula, we have;

y - 2 = 3/2(x - 7)

y - 2 = 3x/2 - 21/2

y = 3x/2 - 21/2 + 2

y = 3x/2 - 17/2

At the y-intercept of (0, -17/2), the cable pass through the road.

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The relative frequency is solved and the table of values is plotted

Given data ,

The lunch order is given by the 2 sets of dishes as

A = { Sandwich , Pastas }

Now , the sports activities are given by 2 sets as

B = { Volleyball , Swimming }

From the table of values , we get

The relative frequency is solved as

Relative Frequency = Subgroup frequency / Total frequency

The percentage of Swimming ( sandwich ) = 26/36

Swimming ( sandwich ) = 72 %

And , the percentage of Swimming ( pasta ) = 10/36

Swimming ( pasta ) = 28 %

Now , the percentage of total sandwich = 45/70 = 64 %

And , the percentage of total pasta = 25/70 = 36 %

Hence , the relative frequency is solved

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The vector z is (7/4, -5/4, -1/4).

To find the vector z, we need to isolate it in the given equation. First, we rearrange the equation to get:

4z = w + 2u

Then, we can substitute the given values for w and u:

4z = 5, -1, -5 + 2(-1, 2, 3)

Simplifying this gives:

4z = 7, -5, -1

Finally, we can solve for z by dividing both sides by 4:

z = 7/4, -5/4, -1/4


In summary, to find the vector z, we rearranged the given equation and substituted the values for w and u. We then solved for z by dividing both sides by 4. The resulting vector is (7/4, -5/4, -1/4).

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If x is the largest of the three consecutive integers, then the three consecutive integers can be represented as x-1, x, and x+1.

The sum of these three consecutive integers is:

(x-1) + x + (x+1)

Simplifying the expression, we get:

3x

Therefore, the expression in terms of the given variables that represents the sum of three consecutive integers when x is the largest is 3x.

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The equation for the linear model in the scatter plot is Y = -2x + 56.

To calculate this equation, we need to find the slope (m) and the y-intercept (b). The slope is calculated with the formula m = (y2 - y1) / (x2 - x1), where x and y represent the coordinates of two points on the graph.

The two points closest to the line in the scatter plot are (2, 48) and (4, 52). Substituting these values into the formula gives us m = (52 - 48) / (4 - 2) = 4/2 = 2.

The y-intercept is the point where the line crosses the y-axis. To find it, we need to substitute the slope and one point's coordinates into the equation y = mx + b. For our equation, we will use the coordinates (2, 48). Substituting these values into the equation gives us 48 = 2x + b, and solving for b gives us b = 48 - 2(2) = 44.

Therefore, the equation for the linear model in the scatter plot is Y = -2x + 56.

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The graph that best represents the Inequality given is; Graph A

We are given the Inequality as;

y ≤ -¹/₃x + 2

Now, the general formula for equation of a line in slope intercept form is written as;

y = mx + c

where;

m is slope

c is y-intercept

Thus, the y-intercept of our graph is y = 2

Now, less than or equal to symbol means we will shade below that line and the only one that has shading below the line is option A.

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Let μ be the mean of the distribution and let σ be its standard deviation.

We know that 54 falls two standard deviations above the mean, this can be express as:

We also know that 42 falls one standard deviation below the mean, this can be express as:

Hence, we have the system of equations:

To find the mean we solve the second equation for the standard deviation:

Now we plug this value in the first equation:

Therefore, the mean of the distribution is 46

The given mixed fraction 5 1/4 can be expressed as 21/4 in improper fraction.

A mixed fraction is one that is represented by both its quotient and remainder. A mixed fraction is, for instance, 2 1/3, where 2 is the quotient and 1 is the remainder. An amalgam of a whole number and a legal fraction is a mixed fraction.

A mixed fraction is one that has both a correct fraction and a whole number portion, and whose value is consistently greater than 1. An example of a mixed number is 325 3 2 5. When the numerator is always higher than or equal to the denominator, the fraction is said to be inappropriate.

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To answer your question, we need to use the Hardy-Weinberg equation, which tells us the expected genotype frequencies in a population. The equation is p^2 + 2pq + q^2 = 1, where p is the frequency of the dominant allele and q is the frequency of the recessive allele.

In this case, we know that q = 0.1, so p = 1 - q = 0.9. We can plug these values into the equation to find the expected genotype frequencies:
(0.9)^2 + 2(0.9)(0.1) + (0.1)^2 = 0.81 + 0.18 + 0.01 = 1.
This means that in a population of 3600, we expect to see 0.01 of individuals with the homozygous recessive genotype (tt), since q^2 represents the frequency of this genotype.

To find out how many people in the population will have Tay-Sachs disease, we simply multiply the expected frequency of the tt genotype by the total population size: 0.01 x 3600 = 36.
Therefore, we would expect 36 individuals in the population of 3600 to have Tay-Sachs disease, assuming that the population is in Hardy-Weinberg equilibrium and that all other assumptions of the model are met.

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The curve x = t^2 − 3t, y = t intersects the y-axis when x = 0, which occurs when t = 0 and t=3. is 8root2/5

When two or more lines cross each other in a plane, they are called intersecting lines. The intersecting lines share a common point, which exists on all the intersecting lines, and is called the point of intersection. Here, lines P and Q intersect at point O, which is the point of intersection.

In general, an intersection curve consists of the common points of two transversally intersecting surfaces, meaning that at any common point the surface normals are not parallel. This restriction excludes cases where the surfaces are touching or have surface parts in common.

A=∫ ​( t)(2t−2)dt

=∫ 2t ^(3/2) −2t ^(1/2)dt

=8root(2)/15

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The interest rate is 10.89%

1. Given,С = 200+ 0.69YI = 80 - 1,000rG = 20NX = 850.09ee = 90M = 115YL = 0.5Y - 200rY = 300Using the equation for National Saving, we get,National Saving = Investment + Government Saving + Net exports(S – I) + (T – G) + (X – M) = 0T = 0, hence (S – I) + (X – M) = 0(1 – t)Y – C – (I + G) + NX = 0Where t = 0, we get,0.5Y – 200r – 200 – 69/100Y + 80 – 850.09e = 0.5Y – 200r – 970.09e – 120 = 0.5Y – 200r – 970.09e – 120 = 0Therefore, Y = 325.0454 - 0.5r + 4.851eThis is the equation for the IS curve.On the other hand, the equation for the LM curve is given by,Ms / P = YL(i)115 / 1 = 0.5Y - 200rTherefore, Y = 400 + 400rThis is the equation for the LM curve.The interest rate is given by the point of intersection of the two curves. Equating Y from both equations, we get,325.0454 - 0.5r + 4.851e = 400 + 400rSolving the above equation for r, we get r = 0.1089 or 10.89%..

The size of the nominal money supply in the new short-run equilibrium is 121.07.

2. From the equilibrium found in Question (1), if the foreign interest rate increases by 0.05, the domestic output will change in two ways, depending on the flexibility of the nominal exchange rate.Flexible Exchange Rates:In this case, the nominal exchange rate will depreciate (e decreases). This will increase net exports and shift the IS curve to the right. The new equilibrium will be at a higher level of output.Real exchange rate will fall.Increase in output will be higher compared to the fixed exchange rate case.Fixed Exchange Rates:In this case, the nominal exchange rate will remain constant. Therefore, there will be no effect on net exports.IS curve will not shift.Real exchange rate will remain unchanged.Increase in output will be less compared to the flexible exchange rate case.The nominal money supply in the new short-run equilibrium will change in the case of Fixed Exchange Rates. In the fixed exchange rate case, the domestic interest rate will increase, leading to an inflow of capital. This will increase the money supply and the LM curve will shift downwards until it intersects the IS curve at the new equilibrium point.

Real exchange rate will remain unchanged.

3. From the equilibrium found in Question (1), if the foreign interest rate increases by 0.05, the domestic output will change in two ways, depending on the flexibility of the nominal exchange rate. Flexible Exchange Rates :In this case, the nominal exchange rate will depreciate (e decreases). This will increase net exports and shift the IS curve to the right. The new equilibrium will be at a higher level of output .Real exchange rate will fall. Value of the real exchange rate in the new equilibrium is 0.891.Fixed Exchange Rates: In this case, the nominal exchange rate will remain constant. Therefore, there will be no effect on net exports.IS curve will not shift.

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Step-by-step explanation:

5x+y=7

20x+2=y

put y value in first equation

5x+(20x+2)=7

25x=5

x=5

now put x value to determine y

as we know 20x+2=y

20(5)+2=y

y=102