Select the higher harmonics of a string fixed at both ends that has a fundamental frequency of 80 Hz 280 Hz b. 400 Hz 160 Hz 200 Hz e.180 Hz

1) The force acting on the object during the time interval 0-3 seconds is 1/3 N.

2) The force acting on the object during the time interval 6-10 seconds is -0.5 N.

3) There is no time interval in which no force acts on the object.

(i) Force acting on the object in time interval 0-3 seconds. Force acting on the object is equal to the product of its mass and acceleration, i.e.,F = ma.

In the given velocity-time graph, the acceleration of the object can be determined by determining the slope of the velocity-time graph from 0 to 3 seconds.

Slope = (change in velocity) / (change in time)= (20-0) / (3-0) = 20/3 m/s^2

Acceleration, a = slope= 20/3 m/s^2

Mass of the object, m = 50 g = 0.05 kg

∴ Force acting on the object, F = ma= 0.05 × 20/3= 1/3 N.

Therefore, the force acting on the object during the time interval 0-3 seconds is 1/3 N.

(ii) Force acting on the object in time interval 6-10 seconds. Similar to the first question, the force acting on the object in time interval 6-10 seconds can be determined by determining the acceleration of the object during this time interval.

The slope of the velocity-time graph from 6 seconds to 10 seconds can be determined as follows:

Slope = (change in velocity) / (change in time)= (-20-20) / (10-6) = -40/4= -10 m/s^2 (negative sign indicates that the object is decelerating)

Mass of the object, m = 50 g = 0.05 kg

∴ Force acting on the object, F = ma= 0.05 × (-10)= -0.5 N.

Therefore, the force acting on the object during the time interval 6-10 seconds is -0.5 N.

(iii) Time interval in which no force acts on the object. There is no time interval in which no force acts on the object. This is because, as per Newton's first law of motion, an object will continue to remain in a state of rest or uniform motion along a straight line unless acted upon by an external unbalanced force.In other words, if the object is moving with a constant velocity, there must be a force acting on the object to maintain its motion.

Therefore, there is no time interval in which no force acts on the object.

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Answer:

Yes. It helps so you can be able to do harder things like backflips and stuff like that. And to become more flexible.

Explanation:

Answer:

B) 0.493

Explanation:

First Crate

Formula: F=ma

120kg*1.05m/s^2= 126N

Second Crate

Formula: F=ma

3*120kg=360kg

360kg*0.71m/s^2=255.6

Find the ratio by dividing

120kg/255.6kg=0.4929

Round 0.4929=0.493

Hope this Helps!!

Answer:

B. 85 N

Explanation:

Newton's second law:

F = ma

F = (85 kg) (1.0 m/s²)

F = 85 N

Answer:

A syncline is visible.

Explanation:

A syncline is visible.

Answer:

These mountains show no evidence of folding.

Hooke's Law can be given as follows sometimes:

The restoring force of a spring is equal to the spring constant multiplied by the displacement from its normal position:

F = -kx

Where, F = Restoring force of a spring (Newtons, N)

k = Spring constant (N/m)

x = Displacement of the spring (m)

The negative sign relates to the direction of the applied force and by convention, the minus or negative sign is present in F = -kx. The restoring force F is directly proportional to the displacement (x), according to Hooke's law. When the spring is compressed, the displacement (x) is negative. It is zero when the spring is at its original length and positive when the spring is extended.

Practically, Hooke's Law is applicable only within a limited frame of reference, and through experimenting, this statement proves to be true. Because materials cannot be compressed beyond a certain size or expanded beyond a certain size without some permanent deformation or change of their original state.

The law only applies under some conditions such as a limited amount of force or deformation. Factually, many materials will noticeably deviate from Hooke's law even before those elastic limits are reached.

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The elastic potential energy stored in the spring is 0.375 J.

The formula for elastic potential energy is:

E = 1/2 * k * x^2

where:

* E is the elastic potential energy in Joules

* k is the spring constant in N/m

* x is the distance the spring is stretched or compressed from its equilibrium position in meters

In this problem, we have:

* k = 3 N/m

* x = 0.5 m (50 cm)

Substituting these values into the formula, we get:

E = 1/2 * 3 * 0.5^2 = 0.375 J

Therefore, the elastic potential energy stored in the spring is 0.375 J.

Answer:

The answer is B since no one answered it :)

Explanation:

Answer:

b

Explanation:

i took the test

Answer:

–50.96

Explanation:

The following data were obtained from the question:

Initial velocity (Vᵢ) = 0 m/s

Acceleration (a) = – 9.8 m/s²

Time (t) = 5.2 s

Final velocity (Vբ) =.?

Acceleration is simply defined as the change of velocity with time. Mathematically, it is expressed as:

Acceleration (a) = Final velocity (Vբ) – Initial velocity (Vᵢ) /Time (t) =

a = (Vբ – Vᵢ) / t

With the above formula, we can determine how fast the object is traveling after 5 s as follow:

Initial velocity (Vᵢ) = 0 m/s

Acceleration (a) = – 9.8 m/s²

Time (t) = 5.2 s

Final velocity (Vբ) =.?

a = (Vբ – Vᵢ) / t

– 9.8 = (Vբ – 0) / 5.2

– 9.8 = Vբ / 5.2

Cross multiply

Vբ = –9.8 × 5.2

Vբ = –50.96 m/s

Therefore, the object is traveling at

–50.96 m/s

2.5 mL of Thallium-201 should be injected to administer a recommended dose of 3.0 mCi.

Thallium-201 is a radioisotope that is used in brain scans to detect brain cancer. It is used in nuclear medicine as a radiopharmaceutical. The recommended dose for Thallium-201 is 3.0 mCi. If a vial of Thallium-201 contains 60. mCi in 50. mL, we can determine the number of milliliters that should be injected by using proportionality.A proportion can be used to compare two ratios and solve for an unknown value. For example, if x is the unknown value we are trying to solve for and a/b and c/d are two ratios that are equal, we can write a proportion:

a/b = c/d.

Cross-multiplying gives us the equation

ad = bc.

This formula can be used to solve for the unknown value x. For this problem, we can use a proportion to solve for the number of milliliters that should be injected. Let x be the number of milliliters that should be injected. Then we have the following ratio:

3.0 mCi / x mL = 60. mCi / 50. mL

To solve for x, we can cross-multiply:

3.0 mCi * 50. mL = 60. mCi * x mL150. mCi mL = 60. mCi x mCx = (150. mCi mL) / (60. mCi) x = 2.5 mL

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Answer:

b. parallel

Explanation:

Answer:

If the size and direction of the forces acting on an object are exactly balanced, then there is no net force acting on the object and the object is said to be in equilibrium. Because the net force is equal to zero, the forces in Example 1 are acting in equilibrium.

Equilibrium of forces means that the net force is 0. It can either be when there is no force acting on the object or when the force acting on the object are balanced.

Answer:

A) b.

Explanation:

all the details are in the attached picture.

A. The acceleration reflected in the data is 38 m/s²

B. The distance traveled by the blood during the period is 0.02 m

Acceleration is defined as the rate of change of velocity with time.

From the question given, we were told the the blood undergoes constant acceleration for 38 m/s².

Thus, we can say that the acceleration reflected in this data is 38 m/s²

The distance traveled by the blood can be obtain as follow:

v² = u² + 2as

1.29² = 0.1² + (2 × 38 × s)

1.6641 = 0.01 + 76s

Collect like terms

76s = 1.6641 - 0.01

76s = 1.6541

Divide both sides by 76

s = 1.6541 / 76

s = 0.02 m

Thus, we can conclude that the distance traveled by the blood during the period is 0.02 m

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A parallel circuit is an electrical circuit with more than one current path and all circuit components are connected between the same two sets of electrically common points. The current supplied by the source in a parallel circuit is equal to the sum of all branch currents in the circuit.

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Answer:

This problem involves the concept of a random walk, which is a mathematical model of a path consisting of a succession of random steps.

The question asks for the distance, R(n), from the center of a star after n steps of a photon, assuming a 2D random walk.

The random walk in two dimensions has a step length of A_i and the direction of the steps is uniformly distributed in [0, 2π). The change in position after each step can be written in Cartesian coordinates (Δx, Δy), where Δx = A_i cos(θ_i) and Δy = A_i sin(θ_i).

The displacement from the center after n steps is given by the vector sum of all the individual steps. This vector sum can be written in terms of its Cartesian coordinates, (X, Y), where X = Σ Δx and Y = Σ Δy. This sum over n random vectors is itself a random variable. The net displacement R(n) from the center of the star after n steps is given by the magnitude of the net displacement vector:

R(n) = √(X² + Y²)

Because each step is independent and has a random direction, the expected value of the cosine and sine for any step is zero. This means that the expected values of X and Y are both zero.

However, the mean square displacement is not zero. Because the steps are independent, the mean square displacement in each direction is additive. For a 2D random walk:

<X²> = Σ <(Δx)²> = n <(A cos θ)²> = n A²/2

<Y²> = Σ <(Δy)²> = n <(A sin θ)²> = n A²/2

Because <X²> = <Y²>, we can write:

<R²> = <X²> + <Y²> = n A²

So, the root mean square distance (the square root of the mean square displacement) after n steps is:

R(n) = √(<R²>) = √(n) * A

Therefore, the distance R(n) that the photon is expected to be from the center of the star after n steps grows as the square root of the number of steps, with each step having a length A. Please note that this result holds for a 2D random walk. A real photon in a star would be performing a 3D random walk, which would have slightly different characteristics.

Answer:

6 gallons

Explanation:

At 30 mph, the fuel mileage is 25 mpg.

After 5 hours, the distance traveled is:

30 mi/hr × 5 hr = 150 mi

The amount of gas used is:

150 mi × (1 gal / 25 mi) = 6 gal

Answer:

d. intrusion

Explanation:

An intrusion is molten rock from the Earth's interior that squeezes into existing rock and cools. Folding Folding occurs when rock layers bend and buckle from Earth's internal forces.

Answer:

1. S = d/t S = speed D = distance traveled T= time elapsed

Explanation:

i can answer more in a minute sorry!!

Answer: what ( younger brothers of hers )

Explanation:

K bye

Answer:

The bulb with higher temperature(4000 K) will be brighter

Explanation:

From the question we are told that

     The color temperature  for first bulb is  \(T_1 = 2000K\)

        The color temperature  for second bulb is  \(T_2 = 4000K\)

Generally the emission power of black body radiation is mathematically represented as

     \(E = \sigma T^4\)

Where  \(\sigma\) is the Stefan-Boltzmann constant  with a value \(\sigma = 5.67 * 10^{-8} W m^{-2} K^{-4.}\)

Now for \(T_1 = 2000K\)

      \(E_1 = 5.67*10^{-8} * (2000)^4\)

       \(E_1 = 907.2 \ W/m^2\)

At  \(T_2 = 4000K\)

       \(E_2 = 5.67*10^{-8} * 4000\)

        \(E_2 = 14515.2 \ KW/m^2\)

Looking at the result we got we see that  the emission power  for the higher temperature bulb is higher, this means that its power to emit in the visible spectrum range would be higher  

So the bulb with higher temperature will be brighter

Answer:

A solar flare as it may harm satellites and aircrafts flying near poles

Explanation:

Since solar flare is electro magnetic waves going to Earth the waves will mostly get absorbed by the north and south poles resulting in the aurora borealis, but if the solar flare is strong enough it may stop communications and engines in satellites and aircrafts and in result harming them

Answer:

A solar flare as it may harm satellites and aircrafts flying near poles

Explanation:

Because they used cutting-edge tools and technology to strengthen the signal and increase the range, the Swedish Space Agency was able to transmit a wifi signal over such a long area.

With a 2.4GHz frequency, Wi-Fi transmissions typically have a range of over 45 metres, or roughly 150 feet. You will have a reach of approximately 15 metres or 50 feet when using a 5Ghz frequency.

802.11g - Indoor effective ranges of 100–150 feet at 54 Mbps wireless throughput using a 2.4GHz transmission frequency. 802.11g and 802.11b can communicate at 11 Mbps.

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Answer:

Electromagnetic waves

Electromagnetic waves bring energy into a system by virtue of their electric and magnetic fields. These fields can exert forces and move charges in the system and, thus, do work on them. However, there is energy in an electromagnetic wave itself, whether it is absorbed or not.

So the answer is B electrical energy

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The total distance covered by the car is 4 kilometers, this is because we are taking into account displacement and not just distance.

Displacement is defined as the change in the position of an object while distance is an object's overall movement in a directionless fashion.

There are many different units that can be used to measure distance (inches, feet, miles, kilometers, and centimeters), but the meter is the SI unit. It is a scalar amount because it does not consider

On the number line, we can see the movement as follows

1 0 -1 -2 -3= 4km

Distance is always positive and never gets smaller as you move. Displacement can be negative, positive, or zero because it refers to the change in the position of an object with respect to its original location.

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The amount the needle on the meter is deflected A. increases

This phenomenon can be explained by Faraday's law of electromagnetic induction. According to this law, when a magnetic field (created by the bar magnet) passes through a coil of wire, it induces an electric current in the wire. This induced current generates its own magnetic field, which interacts with the magnetic field of the bar magnet.

The deflection of the meter needle is a result of this induced current. When the number of coils of wire is increased, there is a greater number of wire loops for the magnetic field to pass through. This leads to a stronger induction of electric current, resulting in a larger deflection of the meter needle.

By increasing the number of coils, more magnetic flux is linked with the wire, resulting in a higher induced electromotive force (emf) and a greater current. This increased current produces a stronger magnetic field around the wire, leading to a larger deflection on the meter. Therefore, increasing the number of coils of wire enhances the magnetic field interaction, resulting in an increased deflection of the meter needle. Therefore, Option A is correct.

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