Select the correct answer.
What is the distance traversed by the particle between 0 seconds and 6 seconds?

A. 2 meters
B. 4 meters
C. 6 meters
D. 8 meters
E. 12 meters

Answer: 6 meters

Explanation:

96 J : 16 N = 6 m

The object was moved 6 meters.

The formula for work is W = F * d,

where W is the work done, F is the force applied, and d is the distance traveled by the object

d = W/F

= 96/16

= 6 m

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A simple pendulum makes 130 complete oscillations in 3.10 min at a location where g = 9.80 m/s²: (a) The period of the pendulum is approximately 1.43 seconds (s). (b) The length of the pendulum is approximately 0.80 meters (m).

(a) The period of a simple pendulum is the time taken for one complete oscillation. We can calculate the period (T) using the formula:

T = (time taken for oscillations) / (number of oscillations)

Given that the pendulum makes 130 complete oscillations in 3.10 minutes, we need to convert the time to seconds:

T = (3.10 min × 60 s/min) / 130

T ≈ 1.43 s

Therefore, the period of the pendulum is approximately 1.43 seconds.

(b) The length of a simple pendulum can be determined using the formula:

L = (g × T²) / (4π²)

Substituting the value of the period (T) calculated in part (a) and the acceleration due to gravity (g = 9.80 m/s²), we can find the length (L):

L = (9.80 m/s² × (1.43 s)²) / (4π²)

L ≈ 0.80 m

Thus, the length of the pendulum is approximately 0.80 meters.

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To produce the sound of 60 dB in the concert hall, the number of oboes required is equal to 100, which means option B is the right answer.

Oboes is the musical instrument which is used to produce sound. It is made up of exotic wood. The sound produced by the oboes has a pitch which is steadier than strings, so it's a more reliable tuning source.

To calculate the number of oboes required to produce 60 dB sound, we first calculate the difference in the sound intensity. Since initial sound intensity is equal to 50 dB and the increased sound intensity is equal to 60 dB, therefore difference is 10 dB.

Applying the formula N2/N1 = 10^(ΔL/10) to determine the number of oboes required, we get following:

N1 = number of oboes producing a sound intensity of 50 dB

N2 = number of oboes needed to produce a sound intensity of 60 dB

ΔL = difference in sound intensity = 60-50 = 10 dB

∵ N2/N1 = 10^(10/10) = 10

Since, N1 = 10 oboes

∴ N2 = N1 × 10 = 10 × 10 = 100

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Answer:

International Bureau of Weights and Measures (BIPM), French Bureau International des Poids et Mesures, international organization founded to bring about the unification of measurement systems, to establish and preserve fundamental international standards and prototypes, to verify national standards, and to determine fundamental physical constants. The bureau was established by a convention signed in Paris on May 20, 1875, effective January 1876. In 1921 a modified convention was signed.

Answer:

its blue

Explanation:

on edg

B) Blue

It is indeed correct on Edge 2021

Answer:

The equation for wavelength is λ = v/f

Explanation:

λ is wavelength

v = velocity

f = frequency

Answer

v= 1/R mark me brainliest pls

Force exerted on the skier is lesser than the weight of the skier.

There is a force which is pulling skier to down which is gravitational force but this force would have two component, because it makes an angle to the earth center.

So the normal force will be = mgcosФ

since the value of cosФ would vary from 0 to 1 , but in case of skis , the values cant be 0 or 1.

So, mgcosФ will always be less than 1.

It means if weight is mg then

mgcosФ < mg

which means normal force will always be less than the weight.

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The change in the momentum of the bullet can be expressed as,

Finally, the bullet moves in the opposite direction therefore, final velocity is taken as negative.

Plug in the known values,

Thus, the change in the momentum of bullet is 12.1 kgm/s.

The car's speed at the top is 0.6 m/s^2

The diameter of loop d = 40 mm

The radius of loop r = 20 mm = 0.02 m

At the top position, we can write,

Weight and Normal reaction combination will provide the centripetal force i.e.

R + W = mv²/R

R = W [apparent weight = Actual weight]

2W = 2mg = mv2/r

v = √2gr

v = 2 x 10 x 0.02 = 0.6 m/s^2

Hence, the car's speed at the top is 0.6 m/s^2

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Answer:

An object's speed or direction can be changed by a force. This means a greater force against a lesser force, and it results in acceleration. This means any push or pull against another equal push or pull. It results in no change of acceleration

Explanation:

The heat energy that must be added to the gas to expand the cylinder length from 14.0 cm to 16.0 cm is approximately 32.5π J.

To solve this problem, we need to use the ideal gas law and the formula for the work done by a gas during expansion.

The ideal gas law is given by PV=nRT, where P is the pressure of the gas, V is its volume, n is the number of moles of gas, R is the gas constant, and T is the temperature of the gas. We can assume that the number of moles of gas remains constant during the expansion, so we can write the ideal gas law as \(P_1V_1=P_2V_2\), where \(P_1\) and \(V_1\) are the initial pressure and volume of the gas, and \(P_2\) and \(V_2\) are the final pressure and volume.

The work done by the gas during expansion is given by W = -PΔV, where ΔV is the change in volume of the gas and P is the pressure of the gas. Since the gas is expanding against a spring, the pressure of the gas is constant and equal to the spring constant k times the amount by which the spring is compressed: P=kx, where x is the compression of the spring.

The heat added to the gas during expansion is given by Q = ΔU + W, where ΔU is the change in the internal energy of the gas. Since the gas is expanding isothermally (at constant temperature), ΔU is zero, so we have Q = W.

Putting all of these equations together, we can solve for the heat added to the gas during expansion:

\(P_1V_1 = P_2V_2\) (from ideal gas law)

P = kx (from the pressure of gas equation)

W = -PΔV = -kxΔV (from work done by gas equation)

Q = W = -kxΔV

We know that the initial cylinder length is 14.0 cm and the spring is compressed by 65.0 cm, so the initial volume of the gas is \($V_{1} = \pi r_{1}^{2}L_{1} = \pi (0.5 \text{ cm})^{2} (14.0 \text{ cm}) = 3.5\pi \text{ cm}^{3}$\). The final cylinder length is 16.0 cm, so the final volume of the gas is \($V_{2} = \pi r_{2}^{2}L_{2} = \pi (0.5 \text{ cm})^{2} (16.0 \text{ cm}) = 4.0\pi \text{ cm}^{3}$\). The change in volume of the gas is therefore \($\Delta V = V_{2} - V_{1} = 0.5\pi \text{ cm}^{3}$\).

To solve for k, we need to know the force required to compress the spring by 65.0 cm. Let's assume that the spring follows Hooke's law, which states that the force required to compress or stretch a spring is proportional to the displacement from its equilibrium position. We can write this as F = -kx, where F is the force required to compress the spring by x and k is the spring constant. If we apply a force of 1 N to the spring, it compresses by 1 cm, so we can solve for k as follows:

k = F/x = (1 N)/(0.01 m) = 100 N/m

Now we can solve for the heat added to the gas during expansion:

\($Q = -kx \Delta V = - (100 \text{ N/m}) (0.65 \text{ m}) (0.5\pi \text{ cm}^{3}) = -32.5\pi \text{ J}$\)

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Complete question:

At 300 K, the gas cylinder length is 14.0 cm and the spring is compressed by 65.0 cm. How much heat energy must be added to the gas to expand the cylinder length to 16.0 cm?

Answer:

Explanation: honestly i don’t speak spanish so please explain with english

Answer:

the cause of variation gravity

Answer:

Heavier Objects Don't Hit the Ground First

The strength of a signal can vary over the frequency range due to the effects of filtering, interference, and propagation losses.

A signal's strength is determined by a number of factors, including the power of the signal itself, the efficiency of the transmitting antenna, and the sensitivity of the receiving antenna.

As a signal travels through the air or over a transmission line, it can experience filtering, which reduces the level of certain frequencies, and interference, which can disrupt the signal and cause it to become weaker.

Additionally, the signal can be attenuated by propagation losses, which occur as the signal spreads out and its energy is absorbed by the surrounding environment.

All of these factors can cause the signal strength to vary over the frequency range, so it is unlikely that the signal strength will remain constant throughout the entire range.

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Answer:

calla gringo de mierda

Explanation:

The length of the two trains is determined as 281 m.

The distance travelled by each train is calculated as follows;

distance travelled by the first train = vt

where;

speed of the first train = 72 km/h = 20 m/s

distance travelled by the first train = 20 m/s  x  7.8 s = 156 m

speed of the second train = 90 km/h = 25 m/s

The distance travelled by the second train = 25 m/s  x  5 s = 125 m

The length of the two trains = 156 m + 125 m = 281 m

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The concentration of nitrogen will be 29.12 kg/m³.

The thickness of the steel sheet, l = 5.0 mm

The diffusion coefficient of nitrogen in steel, D = 46.70 m²/s

The diffusion flux, J = 53.81 kg/m²s

The initial concentration of nitrogen in steel, C1 = 39.52 kg/m³

The final concentration of nitrogen in steel, C2 = 29.12 kg/m³

The required distance, x = ?

The concentration profile is linear. The formula for diffusion flux is J = -D * (dC/dx), where dC/dx is the concentration gradient in the x direction. Here, the negative sign represents the diffusion of nitrogen in the direction of decreasing concentration.

Since the concentration profile is linear, we can use the following equation: dC/dx = (C2 - C1) / x

We can now substitute the given values in the diffusion flux formula:

J = -D * (dC/dx) = -D * (C2 - C1) / x

Solving the above formula for x, we get

x = -D * l / (J * (C2 - C1)) = -46.70 * 5.0 / (53.81 * (29.12 - 39.52))

≈ 1.53 mm

Therefore, the concentration of nitrogen will be 29.12 kg/m³ at a distance of approximately 1.53 mm from the high-pressure surface.

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Answer:

1) Disolver azúcar en agua - Cambio químico - Es un caso de una solución en donde el solvente es el azúcar y el soluto es el agua.

2) Freir una chuleta - Cambio físico - Es un proceso de cocinado por un transferencia de calor y transferencia de masa.

3) Arrugar un papel - Cambio físico - Se aplica fuerzas externas para deformar el papel.

4) El proceso de la digestión - Cambio químico - Reducción de los alimentos a desechos y la absorción de nutrientes por el contacto con jugos gástricos o ambientes intestinales.

5) Secar la ropa al sol - Cambio físico - El secado es un fenómeno de transferencia de masa.

6) Congelar una paleta de agua - Cambio físico - Cambio del estado líquido al estado sólido por transferencia de calor.

7) Hacer un avión de papel - Cambio físico - Aplicación de fuerzas externas para plegar y doblar la hoja de papel.

8) Oxidación del cobre - Cambio químico - Proceso de corrosión por contacto con iones que se transportan en el ambiente.

9) Romper un lápiz - Cambio físico - Proceso de ruptura por esfuerzo normal a causa de un momento como consecuencia de una fuerza externa aplicada sobre el lápiz.

10) Prender fuegos artificiales - Cambio químico - Reacción química de reducción-oxidación.

11) Excavar un hoyo - Cambio físico - Remoción de tierra por trabajo físico.

12) Quemar basura - Cambio químico - Reacción de combustión.

Explanation:

A continuación, veremos que representa cada caso:

1) Disolver azúcar en agua - Cambio químico - Es un caso de una solución en donde el solvente es el azúcar y el soluto es el agua.

2) Freir una chuleta - Cambio físico - Es un proceso de cocinado por un transferencia de calor y transferencia de masa.

3) Arrugar un papel - Cambio físico - Se aplica fuerzas externas para deformar el papel.

4) El proceso de la digestión - Cambio químico - Reducción de los alimentos a desechos y la absorción de nutrientes por el contacto con jugos gástricos o ambientes intestinales.

5) Secar la ropa al sol - Cambio físico - El secado es un fenómeno de transferencia de masa.

6) Congelar una paleta de agua - Cambio físico - Cambio del estado líquido al estado sólido por transferencia de calor.

7) Hacer un avión de papel - Cambio físico - Aplicación de fuerzas externas para plegar y doblar la hoja de papel.

8) Oxidación del cobre - Cambio químico - Proceso de corrosión por contacto con iones que se transportan en el ambiente.

9) Romper un lápiz - Cambio físico - Proceso de ruptura por esfuerzo normal a causa de un momento como consecuencia de una fuerza externa aplicada sobre el lápiz.

10) Prender fuegos artificiales - Cambio químico - Reacción química de reducción-oxidación.

11) Excavar un hoyo - Cambio físico - Remoción de tierra por trabajo físico.

12) Quemar basura - Cambio químico - Reacción de combustión.

20 lb of water requires 1,800 BTU of heat to increase its temperature from 32°F to 212°F.

To find the amount of heat required to increase the temperature of water from one temperature to another, we use the formula:
                                             Q = m x c x ΔT
Where Q is the heat required, m is the mass of water, c is the specific heat capacity of water, and ΔT is the temperature change.
In this case, the mass of water is 20 lb, the specific heat capacity of water is 0.5 BTU/lb/°F, and the temperature change is 212°F - 32°F = 180°F.

Plugging these values into the formula, we get:
Q = 20 lb x 0.5 BTU/lb/°F x 180°F = 1,800 BTU
Therefore, the amount of heat required to increase the temperature of 20 lb of water from 32°F to 212°F is 1,800 BTU.

The correct answer is A. 20 lb x 0.5 x 180°f = 1,800 BTU

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The mechanical energy at top =Mechanical energy at bottom

\(\\ \tt\longmapsto M_{initial}=M_{Final}\)

\(\\ \tt\longmapsto KE=M_{initial}\)

\(\\ \tt\longmapsto KE=P.E_{(Top)}+K.E_{(Top)}\)

\(\\ \tt\longmapsto K.E=mgh+\dfrac{1}{2}mv^2\)

\(\\ \tt\longmapsto K.E=m\left(gh+\dfrac{v^2}{2}\right)\)

\(\\ \tt\longmapsto K.E=54\left((10)(51)+\dfrac{2.6^2}{2}\right)\)

\(\\ \tt\longmapsto K.E=54\left(510+\dfrac{6.76}{2}\right)\)

\(\\ \tt\longmapsto K .E=54(510+3.38)\)

\(\\ \tt\longmapsto K.E=54(513.38)\)

\(\\ \tt\longmapsto K.E=27722.52J\)

\(\\ \tt\longmapsto K.E=27.7KJ\)

Answer:

7.52 × 1022 molecules

Explanation:

We know 32g of oxygen contains 6.022 × 1023 molecules. Therefore, 4g of oxygen have 7.52 × 1022 molecules. ( im not sure if its correct tho)

The fabrication process improves the yield from 0.92 to 0.95. The defects per area unit for 0.92 and 0.95 technology are 0.042 per cm² and 0.026 per cm² respectively

The yield is increased by a manufacturing procedure from 0.92 to 0.95 the defects will be;

Given Data

Suppose the area of the die is 2 cm²

The defects per unit area with a yield of 0.92 and 0.95 must be determined

Solution

Equation for yield

Yield = 1/(1+(defects × die area/2)²

The yield equation has been rearranged

Defects = 2×(1√(yield)-1)/die area

First, we find for the technology of 0.92

Defects = 2×(1√(yield)-1)/die area

Putting the value of yield and die are 0.92 and 2 cm² respectively

Defects =2× (1√(0.92-1)/2

Defects = 0.042 per cm²

Now, find for the technology of 0.95

Putting the value of yield and die which are 0.95 and 2 cm² respectively

Defects=2× (1√(0.95-1)/2

Defects=0.026 per cm²

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A micrometer is used to measure the diameter of a length of copper wire. The zero error and scale reading are as shown.The correct answer should be the micrometer.

The micrometer is an instrument that is capable of measuring the component of an object to very high precision. It is used to obtain accurate measurements in engineering.

In the case of the copper wire, the diameter of 0.3 mm was an approximation and a more accurate measure of the diameter would be obtained by using the micrometer.A micrometer is used to measure the diameter of a length of copper wire. The zero error and scale reading are as shown.The correct answer should be the micrometer.

Therefore, A micrometer is used to measure the diameter of a length of copper wire. The zero error and scale reading are as shown.The correct answer should be the micrometer.

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If the launch speed of the rock from the tower is doubled, the time it takes to hit the ground would be halved.

This is because the launch speed and the time it takes to hit the ground are inversely proportional.

To explain this further, let's use the formula for the vertical displacement of a projectile:

y = v0yt - (1/2)gt2

Where y is the vertical displacement, v0y is the initial vertical velocity (or launch speed), t is the time, and g is the acceleration due to gravity.

If we double the launch speed (v0y), the equation becomes:

y = 2v0yt - (1/2)gt2

Since we want to find the time it takes to hit the ground, we can set y to 0 and solve for t:

0 = 2v0yt - (1/2)gt2

(1/2)gt2 = 2v0yt

t = (2v0y)/((1/2)g)

t = (4v0y)/g

As you can see, the time is now half of what it was before the launch speed was doubled. Therefore, if the launch speed of the rock is doubled, the time it takes to hit the ground is halved.

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Answer:

Subscribe my Gaming channel Sameer Duos

Explanation:

Generally, a seismograph consists of a mass attached to a fixed base. During an earthquake, the base moves and the mass does not. The motion of the base with respect to the mass is commonly transformed into an electrical voltage. The electrical voltage is recorded on paper, magnetic tape, or another recording medium.

Explanation:

a) 9 x 10 ^ 7 hz

b) v= (f) x ( lambda)

3 x10^8 / 9 x 10 ^7 = x

therefore x( lambda) = 3.33 m