Select the correct answer from each drop-down menu. triangle abc is represented. points d and f are marked on side ab and points e and g are marked on side ac. segments de and fg are drawn. if , then line segment is parallel to line segment .

Answer:

11/18

Step-by-step explanation:

KL + MN = 11

Total = 18

Probability of KL or MN = 11/18

Answer:

The error is in Step 3:

She should have calculated the interquartile range as,

Chemistry = 85 - 60 = 25

Biology = 80 - 60 = 20

Step-by-step explanation:

*In a box plot, the median is the point on the number line where a line divides the rectangular box.

Thus, from the information given in the question about the box plots, the median for Chemistry = 80 (this is where a line divides the box)

Median for Biology = 70

The difference in the median = 80 - 70 = 10.

*Lauren didn't make any mistake in Step 1 and 2, as he equally got the same values.

==>The interquartile range in a box plot is simply the difference in the ranges (Q3 - Q1).

From the given information, the interquartile range for Chemistry = 85 - 60 = 25 (this is the difference in the ranges of the box)

Interquartile range for Biology = 80 - 60 = 20

The difference in interquartile range = 25 - 20 = 5

*Lauren made an error in Step 3 when calculating the interquartile range for both Chemistry and Biology, even though he arrive at the same value of the difference in the interquartile range we got as calculated above.

Answer:

to simplyify it the answer is D

Step-by-step explanation:

Answer:

74046 is the correct answer

Answer: there were 12 chocolates in each box. (Originally, before any got eaten)

Step-by-step explanation: let x represent the total amount of chocolates in each box.

8x - 3(8) = 72

8x - 24 = 72 add 24 to both sides

8x = 96 divide both sides by 8

X = 12

Answer:

That means you had 48 chocolates in each box

Step-by-step explanation:

Since you eat 3 chocolates from all 8 boxes, you do this:

8 x 3 which = 24

Now since you have 72 chocolates left you do this:

72 - 24 which = 48

So, therefore, there were originally 48 chocolates in each box

(Don't eat so much chocolate lol you could get sick)

slope=7

Explanation

the slope of a line ( or segment) is given by

so

Step 1

Let

now,replace in the formula

therefore, the slope is 7

I hope this helps you

Answer:

20

Step-by-step explanation:

The distance between two points on the number line is the absolute value of the difference of their coordinates.

coordinate of point D: 9

coordinate of point P: -11

Take the absolute value of their difference. It does not make a difference in which order you subtract the coordinates.

distance = |-11 - 9| = |-20| = 20

Answer: The distance is 20.

The side lengths that cannot form a triangle are: 2 ft, 3 ft, 8 ft.

The correct option is the maximum output per hour for product X is 30 units per hour

To determine the maximum output per hour for product X, we need to find the bottleneck, which is the work center with the lowest hourly unit output rate.

The maximum output per hour is limited by the work center that produces the fewest units per hour.

From the table, we can see that the hourly unit output rate for work center B is the lowest at 30 units per hour.

Therefore, the maximum output per hour for product X is limited by the production capacity of work center B, which is 30 units per hour.

Hence, the maximum output per hour for product X is 30 units per hour.

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To find the measure of angle ∠P in triangle ΔPQR, we can use the dot product formula and the law of cosines.

Let's calculate the vectors from the given points:

→PQ = ⟨4 - 0, 4 - (-1), 1 - 3⟩ = ⟨4, 5, -2⟩

→PR = ⟨-2 - 0, 2 - (-1), 5 - 3⟩ = ⟨-2, 3, 2⟩

Now, we can use the dot product formula to find the dot product of →PQ and →PR:

→PQ ⋅ →PR = (4)(-2) + (5)(3) + (-2)(2) = -8 + 15 - 4 = 3

Next, let's calculate the magnitudes of the vectors:

|→PQ| = √(4^2 + 5^2 + (-2)^2) = √(16 + 25 + 4) = √45 ≈ 6.71

|→PR| = √((-2)^2 + 3^2 + 2^2) = √(4 + 9 + 4) = √17 ≈ 4.12

Now, we can use the law of cosines to find the measure of angle ∠P:

cos(∠P) = (→PQ ⋅ →PR) / (|→PQ| ⋅ |→PR|)

cos(∠P) = 3 / (6.71 * 4.12) ≈ 0.107

Taking the inverse cosine (arccos) of 0.107, we find:

∠P ≈ arccos(0.107) ≈ 84.2 degrees

Therefore, the measure of angle ∠P in triangle ΔPQR is approximately 84.2 degrees.

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15 is the total number of 17-year-old students in Mr. Greene's class

Let the number of 17-year-old students in Mr. Greene's class is x.

Since the total number of students in the class is 20, the number of 18-year-old students would be 20 - x.

The sum of the ages of the 17-year-old students would be 17x, and

the sum of the ages of the 18-year-old students would be 18(20 - x).

The sum of the ages of all the students is 345.

17x + 18(20 - x) = 345

Apply distributive property

17x + 360 - 18x = 345

-x + 360 = 345

Subtract 360 from both sides:

-x = 345 - 360

-x = -15

x = 15

Therefore, the total number of 17-year-old students in Mr. Greene's class is 15

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a) The Empirical Rule, also known as the 68-95-99.7 Rule, applies to data that follows a normal distribution. To estimate the mean and standard deviation of the crayfish weights, we assume the weights are normally distributed.

According to the Empirical Rule:

1. Approximately 68% of the data falls within one standard deviation of the mean.

2. Approximately 99.7% of the data falls within three standard deviations of the mean.

Therefore, the estimated population mean weight is 1376.5gm, and the estimated standard deviation is 250.5gm.

b) i. The percentage of packets less than 492gm can be calculated using the Z-score formula: Z = (492 - 510) / 8 = -2.25. We find that the percentage is approximately 1.87%.

ii. The percentage of packets more than 506gm can be calculated using the Z-score formula: Z = (506 - 510) / 8 = -0.5. We find that the percentage is approximately 30.85%.

iii. To find the percentage of packets between 494gm and 515gm, we calculate the Z-scores for both values: Z1 = (494 - 510) / 8 = -2 and Z2 = (515 - 510) / 8 = 0.625. This gives us approximately 74.48%.

iv. To find the minimum weight bag that would not need to be repacked, we need to determine the weight that corresponds to the 10th percentile. Using the Z-score formula, we find Z = -1.28. We can then calculate the minimum weight as follows: X = (Z * 8) + 510 = (−1.28 * 8) + 510 = 499.36gm.

v. For the middle 90% of packets to be accepted, we need to find the range that corresponds to the central 90% of the standard normal distribution. The Z-scores for the 5th and 95th percentiles are approximately -1.645 and 1.645, respectively. Using the Z-score formula, we can calculate the acceptable weight range: X1 = (-1.645 * 8) + 510 = 495.16gm and X2 = (1.645 * 8) + 510 = 524.84gm.

vi. To find the probability that the sample mean is less than 512gm, we need to calculate the Z-score for this value using the formula: Z = (512 - 514) / (8 / sqrt(48)) = -0.707.  we find that the probability is approximately 24.01%.

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The amount that Josephine will be paid is $644.30.

A percentage is a value or ratio that may be stated as a fraction of 100. If we need to calculate a percentage of a number, we should divide it's entirety and then multiply it by 100. The percentage therefore refers to a component per hundred.

In this situation, Josephine earns a salary of $560.00 per week, plus a commission of 10% on all sales and she sold $843 worth of goods.

The amount she'll be paid will be:

= $560 + (10% × $843)

= $560 + $84.3

= $644.30

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Answer:

Step-by-step explanation:

n x 5

Answer:

2

Step-by-step explanation:

2

89 Step-by-step explanation: 12+-3 = 6

Answer: 5,120

Step-by-step explanation:

Your equation is:

v(t) = 320 • 4^t

You are trying to find v(2) so:

t = 2

Plug in 2 for t:

v(2) = 320 • 4²

Solve:

v(2) = 5,120 views

Hope this helps! :)

When we divide 1/2 by 1/8, we get the answer as 4

Division is the opposite of multiplication. If 3 groups of 4 make 12 in multiplication, 12 divided into 3 equal groups give 4 in each group in division

Here two fractions are given.

We need to divide  1/2 by 1/8

1/2 ÷ 1/8

(1/2)/(1/8)

(1/2)x (8/1)

4

Therefore, upon dividing 1/2 by 1/8 we get the answer as 4

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Using Chebyshev's inequality, the upper bound for the probability of exceeding 85 is 1/2^2 = 1/4 = 0.25.

Using Chebyshev's inequality, the probability of a student scoring between 65 and 85 is at least 1 - 1/2^2 = 1 - 1/4 = 0.75.

a. To give an upper bound for the probability that a student's test score will exceed 85, we can use Chebyshev's inequality. Chebyshev's inequality states that for any random variable, the probability that the value deviates from its mean by more than k standard deviations is at most 1/k^2. In this case, the standard deviation is the square root of the variance, which is 5 (sqrt(25)). To calculate the upper bound for the probability of exceeding 85, we can calculate the number of standard deviations 85 is from the mean of 75 and use the inequality.

Number of standard deviations = (85 - 75) / 5 = 2

b. With the knowledge that the variance is equal to 25, we can also use Chebyshev's inequality to estimate the probability that a student will score between 65 and 85. We calculate the number of standard deviations each score is from the mean and use the inequality to find an upper bound on the probability.

For 65: Number of standard deviations = (65 - 75) / 5 = -2

For 85: Number of standard deviations = (85 - 75) / 5 = 2

c. To ensure with probability at least 0.9 that the class average would be within 5 of 75, we need to determine the minimum sample size. Since we do not use the central limit theorem, we assume that the distribution of individual scores is unknown. However, we can use Chebyshev's inequality to bound the probability of the class average deviating from the mean.

Chebyshev's inequality states that the probability that the class average deviates from the mean by more than k standard deviations is at most 1/k^2. In this case, we want the probability to be at least 0.9, so we set up the inequality:

1/k^2 ≥ 1 - 0.9

1/k^2 ≥ 0.1

k^2 ≤ 10

k ≤ sqrt(10)

We know that k is the number of standard deviations, which is equal to the sample size divided by the square root of the sample size. So we have:

sqrt(10) ≤ n / sqrt(n)

sqrt(10) ≤ sqrt(n)

10 ≤ n

To ensure with probability at least 0.9 that the class average would be within 5 of 75, the minimum number of students that need to take the examination is 10.

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Answer:

49m^2 +( 77+77)m +121

49m^2 + 77m +77m +121

7m (7m +11) +11 (7m +11)

(7m+11) (7m+11)

hope it was helpful

Answer:

\((7m + 11 {)}^{2} \)

Step-by-step explanation:

\(49 {m}^{2} + 154m + 121\)

➡️ \( {7}^{2} {m}^{2} + 2 \times 7m \times 11 + {11}^{2} \)

➡️ \((7 m{)}^{2} + 2 \times 7m \times 11 + {11}^{2} \)

➡️ \( = (7m + 11 {)}^{2} \) ✅

Answer:Rewrite  

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3

x

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4

y

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as  

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Expand  

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(

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x

−

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)

using the FOIL Method.

Tap for fewer steps...

Apply the distributive property.

3

x

(

3

x

−

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)

−

4

y

(

3

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)

Apply the distributive property.

3

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)

+

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Apply the distributive property.

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Simplify and combine like terms

Simplify each term.

9

x

2

−

12

x

y

−

12

y

x

+

16

y

2

Subtract  

12

y

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from  

−

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9

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24

x

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+

16

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Step-by-step explanation:

Answer:

1) Y

2) Y

3) N

4) N

5) N

steps

1) How many bananas did Joe eat yesterday?

The word "many" tells you that its talking about variability.

2) What is the population of Austin, Texas?

The phrase "What is the population..." tells you that its talking about variability.

3) What kind of sandwiches does your class like?

Doesn't talk about variability.

4) What is the name of your teacher?

Doesn't talk about variability.

5) How much do televisions cost?

Doesn't talk about variability.

(YYNNN)

Answer:

Yes what is the question

Answer:

what is the question

Step-by-step explanation:

Answer:

C. 112 cubic inches

Step-by-step explanation:

Two solve this weird-looking house problem, first let's see what it is made of.

Split the area into two volumes.

V = 1/3lwh is the volume for a triangular prism and V = lwh is the volume for a rectangular prism.

Let's now solve for the triangular prism.

The length and width are the same as that of the cube. The cube's length and width is 4 in.

V = 1/3(4)(4)(6) = 32 cubic inches

Now Solve for the cube.

V = lwh = 4(4)(5) = 80 cubic inches

Total Volume = 80 + 32 = 112 cubic inches

Answer:

  3%

Step-by-step explanation:

The interest on the account is given by the simple interest formula:

  I = Prt

where I is the interest, P is the principal invested, r is the annual rate, and t is the number of years

  375 = 2500r(5) . . . . . . using the given values in the formula

  375/12500 = r = 0.03 . . . . . divide by the coefficient of r

Sonnie's account had a 3% interest rate.

Answer:

This cylinders volume, in terms of pi, is 144π m³

This cylinders volume, rounded to the hundredth place, is 452.39 m³

Step-by-step explanation:

volume of cylinder:

→ πr²h

→ π(4)²(9)

→ 144π

→ 452.39 m³ ......rounded to nearest hundredth

\(\\ \tt\hookrightarrow V=\pi r^2h\)

\(\\ \tt\hookrightarrow v=\pi 4^2(9)\)

\(\\ \tt\hookrightarrow v=16(9)\pi\)

\(\\ \tt\hookrightarrow v=144\pi\)

\(\\ \tt\hookrightarrow v=144(3.14)\)

\(\\ \tt\hookrightarrow v=452.16m^3\)

Answer:

6

Step-by-step explanation:

-28-6b=8

-6b=36

b=6

d. Dummy coding. Categorical variables need to be converted into numerical variables to be used in regression analysis. Dummy coding involves creating binary variables for each category of the categorical variable.

For example, if the categorical variable is "color" with categories "red," "green," and "blue," dummy coding would involve creating three binary variables: "red" (0 or 1), "green" (0 or 1), and "blue" (0 or 1). These binary variables can then be used in the regression analysis. In conclusion, to use categorical variables in regression analysis, dummy coding is necessary.


In order to use categorical variables in a regression analysis, they must be converted into numerical values. This process is called dummy coding (also known as one-hot encoding). Dummy coding involves creating new binary variables (0 or 1) for each category of the categorical variable. This allows the regression model to incorporate the categorical data while maintaining its numerical nature.

To use categorical variables in a regression analysis, you must apply dummy coding to convert them into numerical values.

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Answer:

d = 16h²

Step-by-step explanation:

Given

\(\sqrt{d}\) = 4h ( square both sides )

d = (4h)² = 16h²

the 1 is in the 10 million place

The correct statement is: "The domains of g(x) and f(x) are the same, but their ranges are not the same."

The statement "The domains of g(x) and f(x) are not the same, and their ranges are also not the same" is correct. In general, when considering functions g(x) and f(x) derived from a parent function, the transformations applied to the parent function can affect both the domain and the range. The domain of a function refers to the set of all possible input values, while the range represents the set of all possible output values. Through transformations such as shifts, stretches, compressions, or reflections, the domain and range of a function can be altered. Therefore, it is possible for the domains and ranges of g(x) and f(x) to differ from each other and from the parent function.

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Answer:

iuebyefyurbfuyrfbofrvfeybyrvfewqybqwyboiwqebfiwuqefbiwuqefbipuwqefbipuwqefbpiuwqef

Step-by-step explanation: