Select four types of engineers who might be involved in the development of a product such as an iPhone.

(select four)
-hydraulic engineers
-geodetic engineers
-chemical engineers
-electrical engineers
-computer engineers
-manufacturing engineers
-mechanical engineers
-civil engineers

Technician a is correct. The car may veer off course due to loose ball joints. The propensity of a vehicle to veer from one side of the road to the other is known as wander.

The propensity of a vehicle to veer from one side of the road to the other is known as wander. Uneven tire pressure or mismatched tires are potential causes number one. Linkage binding or inadequate lubrication is a potential cause number two. The third potential factor is binding or inadequate lubrication of the steering gear.

The bottom line is that before you start to address poor steering performance, you must identify the underlying source of the issue. Oversteer and understeer have been discussed separately, but we've also included 10 other common steering issues with their likely causes below. You can stop cursing and start fixing your steering problems by locating potential problem areas.

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All of the aforementioned are true characteristics and properties of aluminum except: B. is resistant to galvanic corrosion.

Aluminum can be defined as a silvery white metal and it is considered to be the most abundant metal found in the Earth's crust. Also, it is represented with the chemical symbol "Al" and it has an atomic number of thirteen (13).

This ultimately implies that, aluminum is found in Group 3 on the periodic table because it has three (3) valence electrons, which are found in the outermost shell of its atomic nucleus.

Some of the characteristics and properties of aluminum include the following:

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The maximum shear stress in the tube when the power is transmitted through a 4: 1 gearing is 28.98 MPa.

Power is the energy transferred per unit time.

Torque is find out by

P = 2πNT/60

10000 = 2π x 2000 x T / 60

T =47.74 N.m

The gear ratio Ne / Ns =4/1

Ns =2000/4 = 500

Ts =Ps x 60/(2π x 500)

Ts =190.96 N.m

Maximum shear stress τ = 16/π x (T / (d₀⁴ - d₁⁴))

τ max =T/J x D/2
where d₁ = 30mm = 0.03 m

           d₀ = 30 +(2x 4) = 38mm =0.038 m

Substitute the values into the equation, we get

τ max = 16 x 190.96 x 0.038 /π x (0.038⁴ - 0.03⁴)

τ max = 28.98 MPa.

Thus, the maximum shear stress in the tube is 28.98 MPa.

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[answer removed by author]

You can read about it here https://www.cornellcollege.edu/information-technology/policies/technology-policies/limitations-of-laptops.shtml

Answer:

Shallow foundations, often called footings, are usually embedded about a metre or so into soil. ... Another common type of shallow foundation is the slab-on-grade foundation where the weight of the structure is transferred to the soil through a concrete slab placed at the surface.

Explanation:

Because I said so.

The return interval for a flood with a 5% chance of occurring in a given year is approximately 1.0526 years, or approximately 1 year and 21 days

The return interval for a flood with a 5% chance of occurring in a given year can be calculated using statistical methods. The return interval represents the average time period between occurrences of a specific event, such as a flood, with a certain probability. In this case, we want to determine the return interval for a flood with a 5% chance, also known as the 20-year flood.

To calculate the return interval, we need to use the concept of exceedance probability. The exceedance probability is the probability of a flood of a certain magnitude being equalled or exceeded in any given year.

1. Calculate the exceedance probability:

Exceedance probability = 1 - Probability of occurrence in a given year

In this case, the probability of occurrence in a given year is 5% (or 0.05). Therefore:

Exceedance probability = 1 - 0.05 = 0.95

2. Calculate the return interval:

Return interval = 1 / Exceedance probability

Return interval = 1 / 0.95 = 1.0526

It's important to note that this calculation assumes that the probability of a flood occurrence remains constant over time and that the occurrence of floods follows a random distribution. The return interval is a statistical estimate and should be interpreted as an average value. Actual flood events can vary significantly and may not precisely align with the calculated return interval.

Return intervals are commonly used in hydrology and floodplain management to assess flood risks, design infrastructure, and establish flood insurance rates. They provide a useful framework for understanding the frequency and magnitude of flood events, allowing for informed decision-making in riparian ecohydrology and management.

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The Analytic Hierarchy Process (AHP) can be used to make a decision when selecting a car by considering various criteria and alternatives. AHP provides a structured approach for evaluating and prioritizing different factors.

The AHP method involves breaking down the decision problem into a hierarchy of criteria and sub-criteria. The decision-maker assigns weights to each criterion based on their relative importance. Then, the alternatives (different car options) are evaluated against each criterion, and pairwise comparisons are made to determine their relative performance. These comparisons are converted into numerical values using a scale, such as the Saaty scale, to establish the preference of one alternative over another.

By applying mathematical calculations and aggregating the preferences, the AHP method generates a final ranking of the car alternatives based on their overall performance across the criteria. This enables the decision-maker to select the car that aligns most closely with their preferences and satisfies the desired criteria, considering factors such as price, fuel efficiency, safety features, comfort, reliability, and others.

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Answer:

The ratio of water to flour needed to make tortillas, which is 3 : 4

Explanation:

100 w = 75 f

w/f = 75/100 = 3/4

Wheelbase, trackwidth, and tire load data can be used to determine the longitudinal CG location. The distance in inches between the center of gravity and the front wheel.

Wheelbase, trackwidth, and tire load data can be used to determine a car's longitudinal center of gravity (CG) location. The distance between the centers of the front and rear wheels is known as the wheelbase, while the distance between the left and right tire centerlines is known as the trackwidth. The amount of weight on each of the four tires that are in contact with the ground is known as the tire load. The entire weight of the vehicle is divided by the wheelbase and trackwidth, and the resulting number is multiplied by the wheelbase to determine the longitudinal center of gravity (CG) location. The resultant measurement, taken from the front wheel, is the longitudinal CG location in inches.

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If Jim still wants to recognize the revenue in advance, I would document our conversation and my objections. I   would also recommend that Jim consult with an attorney to discussthe legal implications of his unethical actions.

I would explain to Jim that recognizing revenue in advance is not ethical, a violation of GAAP, and misleading to investors and creditors.

I would document our conversation, recommend that Jim consult with an attorney, and refuse to comply with his request.

In this situation, it is important to explain to Jim that recognizing revenue in advance is unethical, violates accounting principles, and can mislead investors and creditors.

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Answer:

  C. the object is moving forward

Explanation:

A positive slope means position is increasing when time is increasing. Generally, increasing position is "moving forward."

Answer:

C. The object is moving forward

We have that the new bulb 's Price is P  is mathematically given as

P= $100.68

Generally the Arithmetic equation for the life time of new bulb  is mathematically given as

life time = old bulb life / (usage per 24 x 365)

Therefore

L= 14,600 / (19 x 365)

L= 2.10 years

Where

old bulb=(2 x 45.9) (1 + 15/100)2.10 x 2 + 16

Old bulb=$181.11

After tax

tax = 181.11(1 - 40%)

tax= $108.66

Therefore

the new bulb 's Price is P

108.66 = P x (1.7986) x (0.6)

P= $100.68

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Answer:

Mathematics

Explanation:

⁄(⁄ ⁄•⁄ω⁄•⁄ ⁄)⁄

Answer:

It is a field if mathematics

If I had to guess, I'd say the answer is

Drier conditions will likely result in more wildfires

Studies show that warmer and drier areas will double in wildfires by 2050.

Answer:

yes it is very hard you should find a reccomended doctor to aid in your situation. But in the meantime how about you give me that lil brainliest thingy :p

When adding refrigerant in vapor form to a refrigeration system, the system motor/compressor assembly is running. This statement is false.

You MUST flash or throttle the refrigerant when injecting liquid refrigerant into the suction pipe while the compressor is running. Otherwise, liquid refrigerant could enter the compressor, thus this must be done (slugging). The oil in the compressor may be flushed out during slugging. Charge refrigerant vapor into the low side of the refrigeration system while the system is under high evaporator heat loading and continue doing so until the sight glass stops bubbling. When a system runs out of refrigerant, liquid refrigerant can be passed into the king valve on the liquid line or receiver. It passes via the condenser and evaporator. The liquid refrigerant is let to enter a system that is evacuated or vacuumed up until the flow has almost stopped.

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i think it's c. bread.

Answer:I think raw meat because if you eat raw meat you get sick and get stomach aches so always when you cook meat it kill the bacteria

Explanation:what I'm trying to says is stay safe

Answer:

10 cents/kwh

Explanation:

Base monthly charge = $10.00

First 100 kwh at $0.16/kwh = $16.00

Next 200 kwh at $0.10/kwh = $20.00

Remaining 400 kwh at $0.06/kwh = $24.00

Total charge = $10 + $16 + $20 + $24 /(100+200+400)

Average cost = $70/700 or 10 cents/kwh

Answer:

40.7465 \(ft^2\)

Explanation:

The first step for solving this problem is to convert the units from gallons to cubic feet and from millimeters to cubic feet:

1 gallon = 0.133681 cubic feet

10 mm = 0.001 m = 0.0032808 ft

The second step is to divide the volume (the gallon of paint) by the coat thickness. This returns the area.

\(A = \frac{Volume}{thickness}=\frac{0.133681ft^3}{0.0032808ft}=40.7465 ft^2\)

This is the approximate area that the gallon of paint will be able to cover.

Answer:

La diferencia media logarítimica de temperatura del intercambiador en paralelo es aproximadamente 75.466 ºC.

La diferencia media logarítmica de temperatura del intercambiador en contracorriente es aproximadamente 97.881 ºC.

Explanation:

De la teoría de Transferencia de Calor tenemos que un intercambiador de calor en paralelo presenta las siguientes dos características:

1) Tanto el fluido caliente como el fluido frío entran por el mismo lado.

2) Tanto el fluido caliente como el fluido frío salen por el mismo lado.

Mientras que el intercambiador de calor en contracorriente tiene que:

1) El fluido caliente y el fluido frío entran por lados opuestos.

2) El fluido caliente y el fluido frío salen por lados opuestos.

A continuación, anexamos los esquemas de perfil de cada intercambiador.

Ahora, la Diferencia Media Logarítimica de Temperatura (\(\Delta T_{lm}\)), medida en grados Celsius, queda definida como sigue:

\(\Delta T_{lm} = \frac{\Delta T_{1}-\Delta T_{2}}{\ln \frac{\Delta T_{1}}{\Delta T_{2}} }\) (Eq. 1)

Donde \(\Delta T_{1}\) y \(\Delta T_{2}\) son las diferencias de temperatura de los fluidos en cada extremo del intercambiador, medido en grados Celsius.

Procedemos a determinar esas diferencias y la Diferencia Media Logarítimica de Temperatura para cada configuración:

Intercambiador en paralelo

\(\Delta T_{1} = 180\,^{\circ}C-3\,^{\circ}C\)

\(\Delta T_{1} = 177\,^{\circ}C\)

\(\Delta T_{2} = 78\,^{\circ}C - 55\,^{\circ}C\)

\(\Delta T_{2} = 23\,^{\circ}C\)

\(\Delta T_{lm} = \frac{177\,^{\circ}C-23\,^{\circ}C}{\ln \frac{177\,^{\circ}C}{23\,^{\circ}C} }\)

\(\Delta T_{lm} \approx 75.466\,^{\circ}C\)

La diferencia media logarítimica de temperatura del intercambiador en paralelo es aproximadamente 75.466 ºC.

Intercambiador en contracorriente

\(\Delta T_{1} = 180\,^{\circ}C-55\,^{\circ}C\)

\(\Delta T_{1} = 125\,^{\circ}C\)

\(\Delta T_{2} = 78\,^{\circ}C-3\,^{\circ}C\)

\(\Delta T_{2} = 75\,^{\circ}C\)

\(\Delta T_{lm} = \frac{125\,^{\circ}C-75\,^{\circ}C}{\ln \frac{125\,^{\circ}C}{75\,^{\circ}C} }\)

\(\Delta T_{lm} \approx 97.881\,^{\circ}C\)

La diferencia media logarítmica de temperatura del intercambiador en contracorriente es aproximadamente 97.881 ºC.

how am I going to do this, I have a friend that might be able to help I will check

Without damaging the structure or finish of the building or (2) they are exposed and visible without the need for special tools or knowledge to access them.

These definitions provide a framework for understanding what is meant by "accessible" wiring components.What is accessibility?Accessibility is a term used to describe the ease of access to a particular object or component. It may refer to the ease with which it can be reached, examined, or otherwise accessed. In the context of electrical wiring, accessibility is an important consideration because it affects the safety and reliability of the system.The NEC and accessible wiring componentsThe National Electrical Code (NEC) includes specific requirements for wiring component accessibility. These requirements are designed to ensure that electrical wiring is safe, reliable, and easy to maintain. According to the NEC, wiring components are considered accessible when (1) access can be gained without damaging the structure or finish of the building or (2) they are exposed and visible without the need for special tools or knowledge to access them. The NEC also provides specific requirements for the minimum amount of working space required around electrical panels, switchboards, and other wiring components.What are the benefits of accessible wiring components?Accessible wiring components provide a number of benefits, including increased safety, improved reliability, and easier maintenance. By ensuring that wiring components are easy to access, it becomes easier to inspect and maintain them, which helps to reduce the risk of electrical fires and other hazards. Additionally, accessible wiring components are easier to replace or repair, which helps to ensure that the electrical system remains safe and reliable over time.

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Answer:

a) annual thermal energy delivered to the house is 6.3 × 10⁹ J

b) corresponding electricity consumption is 3.15 × 10⁹ J

c) volume is needed if there are no losses from storage is 20.895 m³

d) E = 335 MJ

Explanation:

a)

Given that 1 ton refrigeration is 3.5 kw

so Annual thermal energy delivered to the house is

Energy = power × time

E = 3.5 × ( 500×3600)

we converted 500 hrs to seconds

E = 6.3 × 10⁶ kJ

E = 6.3 × 10⁹ J

therefore annual thermal energy delivered to the house is 6.3 × 10⁹ J

b)

corresponding electricity consumption {Cop = 2}

Electricity consumption = Refrigeration effect / work input

∴ EC = 6.3 × 10⁹J / 2

EC = 3.15 × 10⁹ J

∴ corresponding electricity consumption is 3.15 × 10⁹ J

c)

we know that latent heat of ice is 335 kj/kg = 335 × 10³ J/kg

now let m represent the mass of ice needed for required refrigeration

E = mL

6.3 × 10⁹ j  = m × (335 × 10³J/kg)

m = 6.3 × 10⁹ J / 335 × 10³J/kg

m = 18805.97 kg

Given that density of ice = 0.9ton/m³ = 900 kg/m³

NOW

Volume of ice needed V = mass / density

v = 18805.97 kg / 900 kg/m³

v = 20.895 m³

volume is needed if there are no losses from storage is 20.895 m³

d)

cooling energy of 1 ton ( m = 1000 kg) ice

we know L = 335 kJ

E = mL

E = 1000 × 335KJ

E = 335 MJ

A gravitational force of 4.93 10-12 N in the positive x-direction is applied by the copper sphere to the steel sphere.

Along the line connecting the centres of the two objects, the force is applied. Coulomb's law has an undesirable effect if the two charges have opposing signs. This indicates that there is an attractive force acting on the particles.

\(F = G * m1 * m2 / r^2\)

\(m = rho * (4/3) * pi * r^3\)

r = 65 mm = 0.065 m

a = 3.7r = 0.241 m

b = 2.1r = 0.137 m

c = 0.6r = 0.039 m

m_copper = rho_copper \(* (4/3) * pi * r^3\)

\(= 8,960 kg/m^3 * (4/3) * pi * (0.065 m)^3\)

= 0.0138 kg

m_steel = rho_steel \(* (4/3) * pi * r^3\)

= \(7,860 kg/m^3 * (4/3) * pi * (0.065 m)^3\)

= 0.0119 kg

F = G  m_copper  m_steel / \(r^2\)

= \(6.674 × 10^-11 N·(m/kg)^2 * 0.0138 kg * 0.0119 kg / (0.065 m)^2\)

\(= 4.74 × 10^-11 N\)

u = (0.241 - 0.137)i + 0j + 0k

= 0.104i + 0j + 0k

So the gravitational force F can be expressed as:

\(= 4.74 × 10^-11 N\)

\(= 4.74 × 10^-11 N\)

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The activities that managers choose more frequently today than they did in the past are communicating orally, maintaining diverse contacts, searching for validation, etc.

Contemporary behavioral models may be defined as those models that significantly focus on rational and deliberate decision-making processes rather than emotions or unconscious desires and intentions. These models may eventually include Engel-Kollat-Blackwell (EKB) Model, Black Box Model, and many more.

In this modern era of science and technology, the activities sand working mechanisms of managers to students may widely be changed. All these implementations in the modern era make work efficient and easy for all. This is because all these machines work on the instruction of individuals.

Therefore, communicating orally, maintaining diverse contacts, searching for validation, etc. are activities that managers choose more frequently today than they did in the past.

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Answer:

20368.917N

Explanation:

Frictional force (F) is the product of the Coefficient of friction and the normal reaction.

F = μN

Coefficient of friction, μ = 0.2

Normal reaction = MgCosθ

Mass, m = 12 tonnes = 12 * 1000 = 12000 kg

N = 12000 * 9.8 * cos30

N = 101844.58

F = 0.2 * 101844.58

F = 20368.917N

The military action that involves the use of electromagnetic and directed energy is defined as Electronic Warfare (EW).

Electronic Warfare (EW) refers to military action that uses electromagnetic energy to determine, exploit, impede, or sabotage hostile use of the electromagnetic spectrum and direct energy to deny adversaries the ability to operate effectively.

It involves a wide range of military operations, including electronic intelligence collection, electronic jamming, radar jamming, infrared countermeasures, and high-powered microwave weapons. It may also include cyber warfare, which is the utilization of digital technology to conduct military operations or gain a tactical advantage.

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