Se hacen reaccionar 100 g del agente oxidante con 25 g del agente reductor, según la reacción REDOX LaTeX: N_2\left(g\right)+H_2\left(g\right)\longrightarrow NH_3\left(g\right)N 2 ( g ) + H 2 ( g ) ⟶ N H 3 ( g ) Indique el reactivo en exceso y los gramos de amoniaco formado, si la eficiencia del proceso es del 80 %

The root-mean-square (rms) speed of the molecules of a sample of N2 gas at a temperature of 32.9° C is approximately 448 m/s.

The root-mean-square speed (rms) of molecules in a sample of diatomic nitrogen (N2) gas at a temperature of 32.9° C is given as follows.

The formula for the rms speed of gas molecules is:

vrms = √3kT/m

Boltzmann's constant, denoted as k, has a value of 1.38 × 10−23 J/K.

T is the temperature in Kelvin, and

The mass of the gas molecules is represented by the variable m.

The root mean square (rms) speed of the gas molecules is denoted as v.

Using the provided values of the temperature, the molecular mass of nitrogen, and Boltzmann's constant, we have the following:

Temperature of N2 gas,

The temperature T, originally measured at 32.9°C, can be converted to 305.9 K by adding 273 to the Celsius value.

Mass of N2 molecules, m = 28 × 10−3 kg/mol

Using these values, we can now calculate the rms speed of the N2 molecules in the gas sample:

rms speed,

v = √3kT/m

= √(3 × 1.38 × 10−23 × 305.9)/(28 × 10−3)

= 448 m/s (approx.)

Therefore, the root-mean-square speed of the molecules of a sample of N2 gas at a temperature of 32.9° C is approximately 448 m/s.

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Answer:

A. The equilibrium shifts right to produce more SO3 molecules.

Increasing concentration results in an increased amount of effective collisions in turn leading to a higher reaction rate.

Answer:  2.92%

Explanation:

Explanation:

CaCl2 = 6.02 x 1023 this should be it

Moles of Carbondioxide-CO₂ produced = 20 moles

The combustion of hydrocarbons with excess oxygen will produce carbon dioxide and water(CO₂+H₂O), whereas if there is not much oxygen, carbon monoxide and water(CO+H₂O) will be obtained.

The reaction coefficient in a chemical equation shows the mole ratio of the reacting compounds

Reaction (combustion of butane) :

2C₄H₁₀+13O₂⇒8CO₂+10H₂O

Butane reacts completely, then Butane is the limiting reactant and oxygen as the excess reactant, so the moles of Carbon dioxide are based on the butane moles as the limiting reactant.

moles of butane - C₄H₁₀ = 5 moles

From the reaction, the mol ratio of C₄H₁₀ and CO₂ : 2 : 8, so mol CO₂ :

\(\tt \dfrac{8}{2}\times 5~moles=20~moles\)

Answer:

1.20 mole

Explanation:

1 Mole of Cu reacts to form  =  1 Mole of Hg

(1.20 mol × 1 mol) ÷ 1 mol

1.20 mol of Hg

The phrase that defines bond energy is the energy required to break a chemical bond.

Bond energy is amount of energy needed to break the atoms involved in a chemical bond into free atoms.

The bond energy of each molecule varies with the type of bond in the molecule. Stronger bonds require a higher bond energy and vice versa.

Therefore, the phrase that defines bond energy is the energy required to break a chemical bond.

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Answer:

D. Energy input needed to break bonds of reactants.

Explanation:

Activation energy is the minimum amount of energy required to initiate a chemical reaction by breaking the bonds of the reactants. It is the energy needed to reach the transition state, where the reaction can proceed, and new chemical bonds can be formed to create the products. The activation energy is the energy barrier that must be overcome for a reaction to occur.

Once the reactants have enough energy to overcome the activation energy, the reaction proceeds spontaneously, and energy is released when new bonds form in the products.

PS. I took the quick check.

Because the base is more potent compared to the acid HF in this situation, the salt solution will be basic. The salt HF is going to generate an acidic solution.

Adding a strong base to a weak acid results in a moderately basic solution. The conjugate base containing the weak acid or the conjugate acid containing the strong base are created when the solution containing a weak acid combines with an identical solutions of a strong base.

Depending on how each salt behaves in water, the solution it produces may be acidic, basic, and neutral. Because the base is more potent compared to the acid HF in this situation, the salt solution will be basic. The salt HF is going to generate an acidic solution.

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Answer:

The frequency of photon is 0.75×10¹⁵ s⁻¹.

Explanation:

Given data:

Energy of photon = 5×10⁻¹⁹ J

Frequency of photon = ?

Solution:

Formula;

E = hf

h = planck's constant = 6.63×10⁻³⁴ Js

5×10⁻¹⁹ J =  6.63×10⁻³⁴ Js ×f

f =  5×10⁻¹⁹ J / 6.63×10⁻³⁴ Js

f = 0.75×10¹⁵ s⁻¹

The frequency of photon is 0.75×10¹⁵ s⁻¹.

Answer:

HCl is an acid

C5H5N is a base

Cl- is a base

HC5H5N+ is an acid

Explanation:

To determine the solubility of KNO3 at the given temperatures using a graph, follow these steps:

Step 1: Locate the temperatures on the x-axis of the graph (40°C, 50°C, and 70°C).
Step 2: For each temperature, move vertically up from the x-axis until you reach the curve representing the solubility of KNO3.
Step 3: From the point on the curve, move horizontally to the y-axis to find the solubility value in grams per 100 mL of water.

Using the graph, we can find the solubility of KNO3 in 100 mL of water at the given temperatures:

At 40°C: Approximately __ grams of KNO3 can be dissolved.
At 50°C: Approximately __ grams of KNO3 can be dissolved.
At 70°C: Approximately __ grams of KNO3 can be dissolved.

*Note: Replace the "__" with the actual values from your graph, as these values may vary depending on the specific graph you are using.

A state or condition in which matter exists; a material state or condition as opposed to a spiritual one; (Physics) each of the different modes in which matter can exist, traditionally categorized as solid, liquid, and gas, but extended from the 19th century onwards to other states, such as colloids and plasmas. Hope this helps.

One change in homes that could help save electrical energy is to replace all incandescent bulbs with LED bulbs.

There are different ways one can save electrical energy in their home. Some of them include:

LED bulbs are known as Light-Emitting Diode bulbs. They are energy-saving bulbs, although might be more expensive than their incandescent counterparts.

According to research, LED bulbs have the capacity to save up to 75% of energy compared to other bulbs. Thus, if anyone is looking to save electrical energy and they have incandescent bulbs at some lighting points, they will get very good results by replacing them with LED bulbs.

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Answer: One change in homes that could help save electrical energy is to replace all incandescent bulbs with LED bulbs. They are energy-saving bulbs, although might be more expensive than their incandescent counterparts.According to research, LED bulbs have the capacity to save up to 75% of energy compared to other bulbs. Thus, if anyone is looking to save electrical energy and they have incandescent bulbs at some lighting points, they will get very good results by replacing them with LED bulbs.Turning off all lights and electrical appliances when not in use. Reduction of electrical appliances. For tv, set brightness, contrast and enable power saving mode. These are two other ways to consume less energy in your home.

Explanation: I hope this helps

There are four factors that could change the equilibrium concentrations of reactants and products during a reaction.

First, changes in temperature can shift the equilibrium position. If the reaction is exothermic, increasing the temperature will shift the equilibrium towards the reactants. Second, changes in pressure or volume can shift the equilibrium position. If the reaction involves gases, increasing the pressure or decreasing the volume will shift the equilibrium towards the side with fewer moles of gas. Third, changes in concentration of reactants or products can also shift the equilibrium position. Increasing the concentration of a reactant will shift the equilibrium towards the products. Fourth, the addition of a catalyst can affect the rate of the reaction, but it will not change the equilibrium concentrations.

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A net ionic equation for the overall reaction that occurs when aqueous solutions of sodium hydroxide and oxalic acid is :

H₂C₂O₄  +  2OH⁻  ---->     C₂O₄²⁻   +  2H₂O

The balance molecular equation is given as :

2NaOH (aq)   +   H₂C₂O₄ (aq)   ----->  Na₂C₂O₄ (aq)    +  2H₂O (l)

now, the complete ionic equation is given as :

H₂C₂O₄ +  2Na⁺   +  2OH⁻  ---->   2Na⁺   +  C₂O₄²⁻   +  2H₂O

cancel out the spectators ion the spectators ions are those which are on both side the reactant side and the product side : the net ionic equation is given as :

H₂C₂O₄  +  2OH⁻  ---->     C₂O₄²⁻   +  2H₂O

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Answer:

I DONT KNOW SORRY

Explanation:

Answer:

Iodine-131 is more likely to undergo beta decay than positron decay.

Answer:

Natural gas is an odorless, gaseous mixture of hydrocarbons—predominantly made up of methane (CH4). It accounts for about 30% of the energy used in the United States. About 40% of the fuel goes to electric power production and the remaining is split between residential and commercial uses, such as heating and cooking, and industrial uses. Although natural gas is a proven, reliable alternative fuel that has long been used to power natural gas vehicles, only about two-tenths of 1% is used for transportation fuel.

The vast majority of natural gas in the United States is considered a fossil fuel because it is made from sources formed over millions of years by the action of heat and pressure on organic materials. Alternatively, renewable natural gas (RNG), also known as biomethane, is a pipeline-quality vehicle fuel produced from organic materials—such as waste from landfills and livestock—through anaerobic digestion. RNG qualifies as an advanced biofuel under the Renewable Fuel Standard.

Because RNG is chemically identical to fossil-derived conventional natural gas, it can use the existing natural gas distribution system and must be compressed or liquefied for use in vehicles.

CNG and LNG as Alternative Transportation Fuels

Two forms of natural gas are currently used in vehicles: compressed natural gas (CNG) and liquefied natural gas (LNG). Both are domestically produced, relatively low priced, and commercially available. Considered alternative fuels under the Energy Policy Act of 1992, CNG and LNG are sold in units of gasoline or diesel gallon equivalents (GGEs or DGEs) based on the energy content of a gallon of gasoline or diesel fuel.

Compressed Natural Gas

CNG is produced by compressing natural gas to less than 1% of its volume at standard atmospheric pressure. To provide adequate driving range, CNG is stored onboard a vehicle in a compressed gaseous state at a pressure of up to 3,600 pounds per square inch.

CNG is used in light-, medium-, and heavy-duty applications. A CNG-powered vehicle gets about the same fuel economy as a conventional gasoline vehicle on a GGE basis. One GGE equals about 5.66 pounds of CNG.

Liquefied Natural Gas

LNG is natural gas in its liquid form. LNG is produced by purifying natural gas and super-cooling it to -260°F to turn it into a liquid. During the process known as liquefaction, natural gas is cooled below its boiling point, removing most of the extraneous compounds found in the fuel. The remaining natural gas is primarily methane with small amounts of other hydrocarbons.

Because of LNG's relatively high production cost, as well as the need to store it in expensive cryogenic tanks, the fuel's widespread use in commercial applications has been limited. LNG must be kept at cold temperatures and is stored in double-walled, vacuum-insulated pressure vessels. LNG is suitable for trucks that require longer ranges because liquid is denser than gas and, therefore, more energy can be stored by volume. LNG is typically used in medium- and heavy-duty vehicles. One GGE equals about 1.5 gallons of LNG.

Answer:

Genetic modification or GMOs can change foods. It's typically used to preserve foods, enlargen foods or create seedless grapes

Explanation:

The concentration of the solution in g per dm cube is 35.24 g/dm cube.

The amount of sand in grams is 0.2 g and the volume of the solution is two-thirds of a litre. We have to find the concentration of the solution in g per dm cube.To find the concentration of the solution in g per dm cube, we need to know the concentration of ethanol. As the concentration of ethanol is not given in the question, let us assume the concentration of ethanol is 100%. Therefore, the volume of ethanol in the solution is

(1 - 2/3) litres= 1/3 litres= 1000/3 mL.

As the density of ethanol is 0.789 g/mL,

the mass of ethanol in the solution is:

0.789 g/mL × 1000/3 mL= 789/3 g

The mass of the solution is:

789/3 g + 0.2 g= 2367/9 g

The volume of the solution in dm cube is:

2/3 L= 0.67 dm cube

The concentration of the solution in g per dm cube is: (2367/9 g)/(0.67 dm cube)≈ 35.24 g/dm cube.

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A 64.8 g 64.8 g sample of the compound x2o5 x 2 o 5 contains 48.0 g 48.0 g of oxygen atoms. The molar mass of element x is 56 g/mol.

To determine the molar mass of element X, we can use the information provided about the mass of the compound and the mass of the oxygen atoms.

First, convert the mass of the compound to moles by dividing it by the molar mass of the compound:

(64.8 g) / (molar mass of X2O5) = moles of X2O5

Next, use the moles of X2O5 to determine the moles of oxygen atoms by multiplying by the number of oxygen atoms per molecule of X2O5:

moles of X2O5 x (5 moles of O / 1 mole of X2O5) = moles of O

Then, convert the mass of the oxygen atoms to moles by dividing it by the molar mass of oxygen:

(48.0 g) / (16.00 g/mol) = 3.00 moles of O

We know that the mass of the compound is equal to the mass of the element X and the mass of the oxygen atoms.

mass of X = mass of the compound - mass of the oxygen atoms

mass of X = 64.8 - 48.0 = 16.8 g

convert the mass of element X to moles by dividing it by the molar mass of X:

(16.8 g) / (molar mass of X) = moles of X

Now we can calculate the molar mass of element X by using the moles of X and the mass of X

molar mass of X = mass of X / moles of X

molar mass of X = 16.8 g / (3.00 moles of O x (1 mole of X2O5 / 2 moles of X)) = 56 g/mol.

The molar mass of element X is 56 g/mol.

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A slice of cheese pizza contains approximately 400 Calories.

To calculate the number of Calories in a slice of cheese pizza with 16 grams of fat, 37 grams of carbohydrates, and 27 grams of protein, you can use the following steps:

1. Multiply the grams of fat by 9 Calories per gram: 16 grams x 9 Calories/gram = 144 Calories from fat.
2. Multiply the grams of carbohydrates by 4 Calories per gram: 37 grams x 4 Calories/gram = 148 Calories from carbohydrates.
3. Multiply the grams of protein by 4 Calories per gram: 27 grams x 4 Calories/gram = 108 Calories from protein.

Now, add the Calories from each macronutrient:
144 Calories (fat) + 148 Calories (carbohydrates) + 108 Calories (protein) = 400 Calories.

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The acid dissociation constant of hexanoic acid is 4.93 × 10^-10 mol/L.

When measuring the pH of a solution of hexanoic acid to be 4.96, the acid dissociation constant of hexanoic acid can be calculated. This can be done through the following equation:

Ka = [H3O+][A-] / [HA]whereKa

= acid dissociation constantH3O+

= hydronium ionA-

= conjugate baseHA

= acidThe pH of the solution of hexanoic acid is measured to be 4.96.

Thus, [H3O+] is equal to 10^-4.96 or 7.02 × 10^-5 M.

The initial concentration of the hexanoic acid is equal to the concentration of the undissociated acid or [HA].The acid dissociation constant of hexanoic acid can be calculated by plugging the known values into the equation:

Ka = [7.02 × 10^-5][A-] / [HA]The concentration of the conjugate base, A-, is equal to the concentration of the dissociated acid, which is equal to [H3O+].

Thus,Ka = [7.02 × 10^-5]^2 / [HA]Ka = 4.93 × 10^-10 mol/L

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The empirical formula of a compound found to contain 26.56% potassium, 35.41% chromium, and the remainder oxygen is K₂Cr₂O₇.

The term an Empirical formula is defined as the chemical formula of a compound that gives the ratios of the elements present in the compound but not the actual numbers or arrangement of atoms.

The number of mole of each element in the compound can be identified by dividing each element's percentage with their respective molar weights:

Potassium K = 26.56%

= 26.56 / 39.1        

= 0.68

Chromium, Cr = 35.41%                

= 35.41/52

= 0.68

Oxygen,

O = 100 - 26.56+35.41                      

= 38.03/16

= 2.38

Divide each number of moles by the smallest.

K = 0.68/0.68  

= 1                                                            

Cr = 0.68/0.68

= 1    

O = 2.38/0.68

= 3.5      

Thus, the empirical formula would be KCrO₃.₅

Multiply all by 2 to remove the fraction:

Then the empirical formula would be K₂Cr₂O₇.

Thus, the empirical formula of a compound found to contain 26.56% potassium, 35.41% chromium, and the remainder oxygen is K₂Cr₂O₇.

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When H₂S gas is removed from the system at equilibrium, the reaction shifts to the right (products) and the concentration of NH₃ increases (option C)

A French scientist (Chatelier) postulated a principle which helps us to understand a chemical system in equilibrium.

The principle states that If a an external constraint such as change in temperature, pressure or concentration is imposed on a system in equilibrium, the equilibrium will shift so as to neutralize the effect.

According to Chatelier's principle a decrease in concentration of the products will favor the forward (right) reaction.

From the above principle, we can conclude that when H₂S gas is removed from the system at equilibrium, the reaction shifts to the right (products) and the concentration of NH₃ increases.

Thus, the correct answer to the question is option C

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To calculate the final centimolarity of the caffeine solution, we need to first calculate the number of moles of caffeine in the solution:

Number of moles of caffeine = mass of caffeine / molecular weight of caffeine

Number of moles of caffeine = 0.05 kg / 194 g/mol

Number of moles of caffeine = 0.257732 moles

Next, we need to calculate the total volume of the solution:

Total volume of solution = 150 dL = 15000 mL

Now we can calculate the final centimolarity of the caffeine solution:

C = (number of moles of solute / total volume of solution) x 1000

C = (0.257732 moles / 15000 mL) x 1000

C = 0.0172 M or 1.72 cmol/L (rounded to the nearest 0.01 units)

Therefore, the final centimolarity of the caffeine solution would be 1.72 cmol/L if you dissolve 0.05 kilograms of caffeine in 150 deciliters of water.

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Answer:

B.) Chemical changes produce new substances, while physical changes do

not.

This is a chemical change as the products have very different property as compared to reactant not only physically but also chemically. Therefore, the correct option is option B.

Chemical change is a reaction in which breaking and forming of new bonds take place. One molecule completely converted to totally different molecule. The number of atoms remains same

One famous example of chemical change is the rusting of iron. The color, odor and arrangements of atoms in products are very much different from reactant. Chemical change are mostly irreversible in nature.  

Cooking is a chemical change not a physical change. During cooking the reaction that is associated is combustion reaction as the by product is carbon dioxide and water. Chemical changes produce new substances, while physical changes do not.

Therefore, the correct option is option B.

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Answer:

The answer is D

Liters of hydrogen gas, measured at stp, are produced 0.300 mol of  HCl hydrogen gas, measured at STP, is produced.

From the reaction, the ratio of Mg to HCl used is 1:2 .

This means that if the reaction goes to completion, the  0.100 mol of  Mg will react with 0.100mol×2=0.200ml of HCl.

This leaves 0.500mol−0.200mol=0.300 mol of  HCl.

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