Answer:
255N
Explanation:
Given parameters:
Mass of barrel = 75kg
Acceleration = 3.4m/s²
Unknown:
Force exerted = ?
Solution:
Force is the product of mass and acceleration according to Newton's second law of motion.
Force = mass x acceleration
Now insert given parameters and solve,
Force = 75 x 3.4 = 255N
The net force on the barrel is the sum of the pulling force (magnitude p, acting upward) and the barrel's weight (mag. w, opposing p ). So by Newton's second law,
∑ F = p - w = m a
p = w + m a
p = m g + m a
p = m (g + a)
p = (75 kg) (9.80 m/s² + 3.4 m/s²)
p = 990 N
An object of mass m = 2 kg placed * on a rough horizontal surface is given an initial speed of 10 m / s and comes to rest after covering a distance d = 12m . The kinetic friction f_k is equal to :
We are given that a 20 kg object moves a distance of 12 meters. The intial velocity is 10 m/s. To calculate the friction force we will use the fact that the chage in the kinetic energy is equal to the work done by the frictio force, therefore, we have:
\(\frac{1}{2}m(v_f^2-v_0^2)=W_f\)Where:
\(\begin{gathered} m=\text{ mass} \\ v_f,v_0=\text{ final and initial velocities} \\ W_f=\text{ work done by friction} \end{gathered}\)Now, we plug in the values:
\(\frac{1}{2}(2kg)((10\frac{m}{s})^2-0)=W_f\)Solving the operations:
\(100J=W_f\)Now, the work done by friction is equal to the friction force multiplied by the distance:
\(100J=F_fd\)Now, we divide both sides by the distance:
\(\frac{100J}{12m}=F_f\)Solving the operations:
\(8.33N=F_f\)Therefore, the force of friction is 8.33 Newtons.
Identify the energy levels from which the 410.2 nm emission line of the Balmer series of the
hydrogen atom originates, i.e., state the values of ninitial and nfinal. What is the frequency of the
radiation involved in the transition between these levels?
The energy level from which is emitted is n = 6
The frequency is\(7.3 * 10^14\) Hz
What is the energy level?The Rydberg equation is a mathematical formula that relates the wavelengths of light emitted by an atom to the energy levels of its electrons.
Using the Rydberg equation;
1/λ= RH (1/\(n_{2}^2\) - 1/\(n_{1} ^2\))
1/\(410.2 * 10^-9\) = \(1.097 * 10^7\)(1/\(2^2\) - 1/ /\(n_{1} ^2\))
1/\(4.102 * 10^-7\) = \(1.097 * 10^7\)(1/4 - 1/\(n_{1} ^2\))
1/\(4.102 * 10^-7\) * 1/ \(1.097 * 10^7\) = (1/4 - 1/\(n_{1} ^2\))
0.22 = 0.25 - 1/\(n_{1} ^2\)
0.22 - 0.25 = - 1/\(n_{1} ^2\)
-0.03 = - 1//\(n_{1} ^2\)
\(n_{1}\) = 6
Using;
f = c/λ
\(3 * 10^8/4.102 * 10^-7 \\f = 7.3 * 10^14 Hz\)
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During a football match, the ball kicked at 45° angle of elevation went just over the goal post, height 2.4m. Assuming the goal post height is the greatest, calculate: (a) The speed at which the ball was projected (b) The time taken to reach the greatest height (c) The horizontal distance between the point of kick and foot of the goal post (neglect the thickness of the bar).
Answer:
We can use the kinematic equations to solve this problem. Here are the steps:
(a) To find the initial velocity of the ball:
Let v be the initial velocity of the ball, and g be the acceleration due to gravity (-9.81 m/s^2).
The horizontal component of the velocity will remain constant throughout the motion, so we can write:
vx = v cos(45°)
where vx is the horizontal component of the velocity.
At the highest point, the vertical velocity of the ball will be zero, so we can use the equation:
vy^2 = u^2 + 2gh
where u is the initial vertical velocity, and h is the maximum height. We know that u = v sin(45°), so we can write:
(v sin(45°))^2 = v^2 + 2gh
Substituting the given values, we get:
(v^2)/2 = 2.4 m
v = √(4.8g) ≈ 9.25 m/s
Therefore, the initial speed of the ball was approximately 9.25 m/s.
(b) To find the time taken to reach the greatest height:
We can use the kinematic equation:
v = u + gt
At the highest point, the vertical velocity of the ball is zero, so we can write:
0 = (v sin(45°)) + gt
Solving for t, we get:
t = (v sin(45°)) / g
Substituting the value of v, we get:
t = (9.25 m/s) / (sqrt(2) * 9.81 m/s^2) ≈ 0.66 s
Therefore, the time taken to reach the greatest height was approximately 0.66 seconds.
(c) To find the horizontal distance between the point of kick and the foot of the goal post:
We can use the kinematic equation:
d = vxt
where d is the horizontal distance, and t is the time taken to reach the foot of the goal post. We already know the time t from part (b), so we just need to calculate the horizontal velocity:
vx = v cos(45°) ≈ 6.54 m/s
Substituting the values, we get:
d = (6.54 m/s) x (0.66 s) ≈ 4.32 m
Therefore, the horizontal distance between the point of kick and the foot of the goal post was approximately 4.32 meters.
A ball is kicked horizontally at 4.6 m/s off of a cliff 12.4 m high. How far from the cliff will it land?
A) 2.5 m
B) 1.6 m
C) 7.4 m
D) 4.1 m
Answer:
42
Explanation:
42
what is the Vector product of A=2.00i+3.00j+1.00k and B= 1.00i -3.00j -2,00k
The vector product of A=2.00i+3.00j+1.00k and B=1.00i-3.00j-2.00k is C=9.00i+4.00j-9.00k.
To find the vector product (also known as the cross product) of two vectors, A and B, we can use the following formula:
C = A × B
Where C is the resultant vector, A and B are the given vectors, and × denotes the cross product.
Given A = 2.00i + 3.00j + 1.00k and B = 1.00i - 3.00j - 2.00k, we can substitute these values into the formula to find the vector product:
C = (2.00i + 3.00j + 1.00k) × (1.00i - 3.00j - 2.00k)
Now, let's expand the cross product using the properties of vector products:
C = (2.00i × 1.00i) + (2.00i × -3.00j) + (2.00i × -2.00k) +
(3.00j × 1.00i) + (3.00j × -3.00j) + (3.00j × -2.00k) +
(1.00k × 1.00i) + (1.00k × -3.00j) + (1.00k × -2.00k)
Now, let's calculate each of these cross products:
C = (2.00 × 1.00) \(i^2\) + (2.00 × -3.00) i × j + (2.00 × -2.00) i × k +
(3.00 × 1.00) j × i + (3.00 × -3.00) \(j^2\) + (3.00 × -2.00) j × k +
(1.00 × 1.00) k × i + (1.00 × -3.00) k × j + (1.00 × -2.00) \(k^2\)
Since i × j = k, j × k = i, and k × i = j, we can simplify the expression further:
C = 2.00k - 6.00i + 4.00i - 9.00j + k - 3.00j - 2.00j - 2.00k
Combining like terms, we get:
C = (2.00i + 4.00i) + (-6.00i - 9.00j - 3.00j) + (2.00k + k - 2.00k)
Simplifying further:
C = 6.00i - 12.00j + k
Therefore, the vector product of A and B is C = 6.00i - 12.00j + k, which can be written as C = 9.00i + 4.00j - 9.00k in terms of i, j, and k.
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The vector product of A and B is -3i - 5j - 9k.
Explanation:The vector product, also known as the cross product, of two vectors A and B is denoted as A x B. It is a vector that is perpendicular to both A and B. To calculate the vector product, you can use the formula A x B = (Ay * Bz - Az * By)i + (Az * Bx - Ax * Bz)j + (Ax * By - Ay * Bx)k.
In this case, we have A = 2.00i + 3.00j + 1.00k and B = 1.00i - 3.00j - 2.00k. Substituting the values into the formula, we get A x B = (3 * -2 - 1 * -3)i + (1 * 1 - 2 * -2)j + (2 * -3 - 3 * 1)k = -3i - 5j - 9k.
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Dillan rolls a rubber band ball off a desk. If the desk is 0.9 m tall, and the ball lands 2.5 m away, what was the horizontal velocity of the rubber band ball as it went off the table?
Answer: 6.25 m/s
explanation: remember an easir way to solve problems like this is to have a horizontal side (x) and a vertical side (y) and on each side always set up for initial speed, average speed, final speed, distance, time, and acceleration.
lmk if you need anything else or any more good tips yk
What do feathers, fur, overcoats, and whale blubber all have in common?
A. They are all good conductors of heat.
B. They all generate heat.
C. They are all electrical conductors.
D. They are all heat insulators.
Answer:
D. They are all heat insulators.
Explanation:
Those things mentioned above are examples of heat insulators. As a heat insulator, it helps to prevent the heat from leaving the body thereby keeping the body warm and risk free.Feathers in birds and overcoat in humans helps to keep the bodies of the wearer safe and warm during the cold season.
A 2.80 kg mass is dropped from a height of 4.50 m. Find its potential energy when it reaches the ground.
Answer:
123.48J
Explanation:
Given parameters:
Mass of the ball = 2.8kg
Height = 4.5m
Unknown:
Potential energy = ?
Solution:
The potential energy is the energy due to the position of a body. It is mathematically given as;
P.E = mgh
m is the mass
g is the acceleration due to gravity
h is the height
Now insert the parameters and solve;
P.E = 2.8 x 4.5 x 9.8 = 123.48J
Answer:
0
Explanation:
There is 0 PE when its on the ground
1. A charge of 6.4 C passes through a cross-sectional area or conductor in 2s. How much charge will pass through a cross sectional area of the conductor in 1 min?
The amount of charge that will pass through the cross-sectional area of the conductor in 1 min is 192 C.
What is the amount of charge?
We can use the formula Q = I * t,
where;
Q is the amount of charge, I is the current, and t is the time.Given that a charge of 6.4 C passes through a cross-sectional area of the conductor in 2 s, we can find the current using the formula:
I = Q / t = 6.4 C / 2 s = 3.2 A
So, the current through the conductor is 3.2 A.
To find the amount of charge that will pass through the cross-sectional area of the conductor in 1 min (60 s), we can use the same formula:
Q = I * t = 3.2 A * 60 s = 192 C
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Why is it better to use the metric system, rather than the English system, in scientific measurement?
A. The English system uses one unit for each category of measurement.
B. The metric system uses one unit for each category of measurement.
C. The English system uses consistent fractions that are multiples of 10.
D. The metric system utilizes a variety of number conversions.
A. The English system uses one unit for each category of measurement.
Answer:
A
Explanation:
A liquid of density 1230 kg/m3 flows steadily through a pipe of varying diameter and height. At Location 1 along the pipe, the flow speed is 9.15 m/s and the pipe diameter 1 is 12.3 cm. At Location 2, the pipe diameter 2 is 16.1 cm. At Location 1, the pipe is Δ=9.29 m higher than it is at Location 2. Ignoring viscosity, calculate the difference Δ between the fluid pressure at Location 2 and the fluid pressure at Location 1.
The difference between fluid pressure at location 2 and fluid pressure at location 1 is mathematically given as
dP = 114 kPa
What is the difference between fluid pressure at location 2 and fluid pressure at location 1.?
Parameters are :
density of liquid,
speed of flow at location 1, = 9.15m/s
diameter of pipe at location 1, = 12.3cm
diameter of pipe at location 2, = 16.1 cm
height of pipe at location 1, = 9.29 m
We know that the Bernoulli's equation is mathematically given as
P + ρ*g*y + v² =pipe constant
Where
A1*v1 = A2*v2
π*(0.105/2)²*9.91 = π*(0.167/2)²*v2
v2 = 3.9 m/s
Hence, we have that
P1 + ρ*g*y1 + v1² = P2 + ρ*g*y2 + v2²
dP = 1290*9.8*9.01 + 9.91² - 3.9²
dP = 114 kPa
In conclusion, difference between fluid pressure is dP = 114 kPa
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If you want to make a strong battery, should you pair two metals with high electron affinities, low electron affinities, or a mix? Explain your answer.
4. You currently have TWO 9 volt batteries connected to a 82 resistor. How
much current is flowing through the circuit? *
1.125 A
5 A
72 A
2.25 A
Back
Next
Never submit passwords through Gon
Explanation:
Total voltage = 9 × 2 = 18v
Resistance = 82 Ω
Ohm's law::
V = IR
18v = 82 Ω × I
18v /82 /Ω = I
18/82 Ampere is the current
Which are disadvantages of renewable resources? Check all that apply.
Renewable energy supplies may not be completely reliable.
sources will never run out.
Renewable energy produces large quantities of waste products.
It is difficult to generate electricity in large quantities using renewable resources.
Many renewable energy facilities have higher operating costs.
Answer:
Renewable energy supplies may not be completely reliable.
It is difficult to generate electricity in large quantities using renewable resources.
Explanation:
i got it correct on edgeneuity
The disadvantages of renewable resources is energy supplies may not be completely reliable and many renewable energy facilities have higher operating costs.
What are renewable and non-renewable sources?The main difference between renewable and non-renewable energy sources is the limitation of use: renewable resources are infinite, while non-renewable energies use non-renewable resources, so they tend to run out if there is an exacerbated use.
Disadvantages of Renewable Energies:High investment costs and appropriate infrastructure;Negative visual impacts on the environment;Biomass Energy – the biomass combustion method is not clean;Hydroelectric Power – causes soil erosion that can impact the vegetation of the site;See more about renewable energy at brainly.com/question/17373437
Wound coils of wire that function as magnets when an electrical current is passed through it is
called?
a. Temporary Magnets
b. Permanent Magnets
c. Electromagnets
d. Diamagnet
e. Paramagnet.
The picture shows two solutions of salt water. Which solution is more concentrated (has a higher concentration)?
Question 15 options:
The first solution is more concentrated
The second solution is more concentrated
The solutions have the same concentration.
In order to determine which of the two solutions of salt water is more concentrated, we need to first understand what concentration means and how it is measured. Concentration refers to the amount of solute dissolved in a given amount of solvent. It is typically measured in units of mass per volume, such as grams per liter (g/L) or milligrams per milliliter (mg/mL). so The second solution is more concentrated
When comparing the concentration of two solutions, the one with a higher concentration has more solute dissolved in the same amount of solvent. Therefore, in the picture provided, we can determine which solution is more concentrated by looking at the relative amounts of solute in each solution.If the solutions have the same concentration, then they must have the same amount of solute dissolved in the same amount of solvent. From the picture, we can see that both solutions are in the same size container and have the same amount of solvent (water) in them. Therefore, we can conclude that they have the same concentration of salt.The amount of solute dissolved in a solution can be increased by either adding more solute or by reducing the amount of solvent. If we were to add more salt to one of the solutions, we would increase the concentration of that solution. Alternatively, if we were to evaporate some of the water from one of the solutions, we would reduce the amount of solvent and increase the concentration of that solution.
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If an ice skater pulls their hands towards their body, will their angular momentum and kinetic energy both increase?
Answer:
The angular momentum depends on both the angular velocity and the mass distribution of the object. You can change this angular momentum by exerting a torque (a twisting force)—but with no external torque, the angular momentum is conserved. Now getting back to the ice skater.
A Student 330 m 990m from another tall flip between the the Student stands Sound Interval beteeen cliff is cliff from of 1 st and 630 tall Hip which speed of 330 if the 330 m/s 2nd eh what is echo?
The interval between the first and second echo is 7 seconds. This means that after the initial sound wave reaches the first cliff, it takes a total of 7 seconds for the sound to travel to the second cliff and then return to the student as the second echo.
To determine the interval between the first and second echo, we need to consider the time it takes for sound to travel from the student to the first cliff, and then from the first cliff to the second cliff, and finally back to the student.
Let's break down the distances and calculate the time for each part of the journey:
Distance from the student to the first cliff: 330 meters
Time taken: t₁ = distance / speed = 330 m / 330 m/s = 1 second
Distance from the first cliff to the second cliff: 990 meters
Time taken: t₂ = distance / speed = 990 m / 330 m/s = 3 seconds
Distance from the second cliff back to the student: 990 meters
Time taken: t₃ = distance / speed = 990 m / 330 m/s = 3 seconds
Now, we can calculate the total interval between the first and second echo by adding up the individual times:
Interval between first and second echo = t₁ + t₂ + t₃ = 1 s + 3 s + 3 s = 7 seconds
Therefore, the interval between the first and second echo is 7 seconds. This means that after the initial sound wave reaches the first cliff, it takes a total of 7 seconds for the sound to travel to the second cliff and then return to the student as the second echo.
It's important to note that this calculation assumes a straight path for the sound waves and neglects factors such as air temperature and wind that can affect the speed of sound. Additionally, it assumes perfect reflection of sound waves off the cliffs, which may not be the case in real-world scenarios.
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Note the complete questions is:
A student stands 330m from a tall cliff which is 990m from another tall cliff. If the speed of sound between the cliffs is 330m/s.What is the interval between the first and second echo?
Question 1 of 5
Which type of energy warms most of Earth's surface?
A. Solar energy
B. Nuclear energy
C. Geothermal energy
OO
D. Gravitational energy
SUBMIT
Answer:
solar energy warms most of the earths surface
Answer:
c
Explanation:
Which theory states that the principle cause of forgetting is passage of time? A. motivated forgetting B. retrieval failure C. decay theory D. ineffective encoding
HI PLEASE HELP ON QUESTION ASAP USING AVERAGE (MEAN) TO ANSWER QUESTION! IF UR ANSWER AND EXPLAINATION IS CORRECT ILL RATE YOU FIVE STARS, A THANKS AND MAYBE EVEN BRAINLIEST. PLEASE MAKE SURE YOU ANSWER MY QUESTION USING AVERAGES.
1) a meal for 6 cost £12 per person. as it is one of the diners birthday , the other 5 decided to pay for his meal. how much do each of the five friends need to pay?
Each of the five friends needs to pay £12 to cover the cost of their own meals and contribute towards the birthday person's meal. Using mean allows us to distribute the cost equally among the friends, ensuring a fair division of expenses for the meal.
To determine how much each of the five friends needs to pay, we can use the concept of averages (mean) and divide the total cost by the number of people paying.
In this scenario, the total cost of the meal for 6 people is £12 per person. Since the other 5 friends have decided to pay for the birthday person's meal, they will collectively cover the cost of their own meals plus the birthday person's meal.
To calculate the total cost covered by the five friends, we can subtract the cost of one person's meal (since the birthday person's meal is being paid by the group) from the total cost. The cost of one person's meal is £12.
Total cost covered by the five friends = Total cost - Cost of one person's meal
= (£12 x 6) - £12
= £72 - £12
= £60
Now, to find out how much each of the five friends needs to pay, we divide the total cost covered by the five friends (£60) by the number of friends (5).
Amount each friend needs to pay = Total cost covered by the five friends / Number of friends
= £60 / 5
= £12
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*
Which of the following cannot be an example of projectile motion
A. A football flying through the air
B. An apple falling from a tree
C. A pencil rolling on the ground
D.A rocket dropping from its maximum height
9. If the mass of a 200 N object is cut in half, what would happen to its weight in Newtons?
Answer:
as we know that weight = mass ×gravity (earth's gravity 9.8m.s²)the weight will be also be cut in halfmass is directly proportional to the weightExplanation:
let's say our mass is 50 kgour gravity is 9.8m.s²therefore 50×9.8=490Nnow cut the mass in half therefore 25×9.8=245NWhat is the powder taking the shape of?
The magnetic field
The poles
A snowman
A star
The powder takes the shape of a magnetic field.
What is the particle shape of powder?Powder morphology is connected to the shape and size of powder particles and is strongly dependent on the manufacturing methods. For example, mechanical alloying/mechanical milling leads to unevenly shaped powder particles, while gas dissipation leads to spherically shaped particles.
Atomized metal powder particles come in two basic particle shapes: those that are almost superbly round called spherical, and those that have lopsided, rounded shapes, called spheroidal.
So we can conclude that Powders are a group of particles of different sizes.
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A figure skater glides along a circular path of radius 3.93 m. (a) If she coasts around one half of the circle, find the magnitude of the displacement vector. (b) If she coasts around one half of the circle, find what distance she skated. (c) What is the magnitude of the displacement if she skates all the way around the circle?
The magnitude of the displacement vector refers to the length or amount of the displacement vector. Displacement is the change in position of an object. Displacement is a vector quantity, which means it has both magnitude and direction. In this question, a figure skater is gliding along a circular path of radius 3.93 m.
If she coasts around one half of the circle, we have to find the magnitude of the displacement vector. The figure skater is gliding along a circular path of radius 3.93 m. If she coasts around one half of the circle, then her final and initial position is on the same point. Therefore, the magnitude of the displacement vector is zero. Distance Skated Distance refers to the length covered by an object or an individual. In this question, the figure skater is gliding along a circular path of radius 3.93 m. If she coasts around one half of the circle, we have to find what distance she skated. The distance covered by an object or individual is determined by the formula:Distance = Circumference/2Given that the radius of the circle is 3.93 m, then:Circumference of the circle = 2πr= 2 × 3.14 × 3.93= 24.7 m.Therefore, the distance covered by the figure skater around half of the circle = 24.7 m/2 = 12.35 m. Therefore, she skated 12.35 m.Magnitude of DisplacementIf the figure skater skates all the way around the circle, then she covers the entire circumference of the circle. Therefore, the magnitude of the displacement vector is the same as the circumference of the circle, which is given as:Circumference of the circle = 2πr= 2 × 3.14 × 3.93= 24.7 mTherefore, the magnitude of the displacement vector when the figure skater skates all the way around the circle is 24.7 m.For such more question on magnitude
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A plate of iron at 20 °C has shown in the figure below. If the temperature
raised to 100 °C and the coefficient of linear expansion of iron is 1.1 x 10-7 o
1, then what is the final area of the plate?
(5
2 m
2 m
The final area of the plate is 4.0000352 \(m^2\) if the temperature raised to 100 °C and the coefficient of linear expansion of iron is 1.1 x 10-7.
Expecting that the plate of iron is rectangular, we can involve the recipe for warm extension of solids to compute the last region of the plate. The equation for direct warm development is given by ΔL = αLΔT, where ΔL is the adjustment of length, α is the coefficient of straight extension, L is the first length, and ΔT is the adjustment of temperature.
Since the region of the plate is given by A = L*W, where L is the length and W is the width, we can involve the equation for straight warm extension to compute the adjustment of length of the plate and afterward use it to compute the last region.
ΔL = αLΔT = \((1.1 x 10^-7 m/oC)(2 m)(80 oC) = 1.76 x 10^-5 m\)
The last length of the plate is L + ΔL = 2 m + 1.76 x \(10^-5\) m = 2.0000176 m (approx.)
The last width of the plate is thought to be unaltered as it isn't impacted by the adjustment of temperature.
Thusly, the last region of the plate is A = L*W = (2.0000176 m)(2 m) = 4.0000352 \(m^2\) (approx.)
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2 kg and 3 kg objects slide together, and then they break apart. If the final velocity of 2 kg is 10 m/s,
a) Find the velocity of object 3 kg.
b) Find the total change in the kinetic energies of the objects.
Answer:
P = (2 + 3) * V where V is their initial speed (total momentum)
P = 2 * 10 + 3 * Vx where Vx here would be V3
If the initial momentum is not known how can one determine the final velocity of the 3 kg obj.
Also work depends on the sum of the velocities
W (initial) = 1/2 (2 + 3) V^2 the initial kinetic energy
W (final) = 1/2 * 2 * V2^2 + 1/2 * 3 * V3^2
It appears that more information is required for this problem
1. Nitrile gloves:
OA. Are more impermeable than latex gloves
OB. Are less impermeable than latex gloves
OC. Are as permeable as latex gloves
OD. Should not be used
Grade/Exit
Nitrile gloves are more impermeable than latex gloves is the correct answer.
What are nitrile gloves?Nitrile gloves are a type of personal protective equipment (PPE) used in various industries, including medical, dental, and food service. They are made of synthetic rubber known as nitrile, which is puncture-resistant and provides a barrier against liquids, chemicals, and other hazardous materials. Nitrile gloves are often preferred over latex gloves because they do not cause allergic reactions and are more durable. They also provide an excellent fit and are easy to put on and take off, making them a popular choice for people who need to wear gloves for extended periods of time.
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An arrow is launched upwards with an initial velocity of +48.0 m/s. Assuming that it was launched upwards from the ground, what will be the height of the arrow after 4.5 s?solve algebraically first then substitute in numbers and solve
Given:
The initial velocity of the arrow in an upward direction is
\(v_o=48\text{ m/s}\)The time duration is t = 4.5 s.
Required: The distance travelled by the arrow.
Explanation:
The distance travelled in an upward direction can be calculated by the formula,
\(\begin{gathered} \Delta y=v_ot+\frac{1}{2}at^2 \\ \Delta y= v_{o}t-\frac{1}{2}gt^{2} \end{gathered}\)Here, a= -g is the acceleration due to gravity whose value is
\(g=\text{ 9.8 m/s}^2\)On substituting the values, the distance covered by the arrow will be
\(\begin{gathered} \Delta y=\text{ 48}\times(4.5)-\frac{1}{2}\times9.8\times(4.5)^2 \\ =116.78\text{ m} \end{gathered}\)Final Answer: The distance covered by the arrow is 116.78 m
Question 6.Why does a ball dropped from a certain height not bounce back 1 point
to the same height it was dropped from? *
Answer:
Because the coefficient of restitution is less than 1.
This coefficient is 1 for a perfectly elastic collision.
Some of the energy of the fall is absorbed by the ball so the ball cannot return to its original height.
Also, you have the effects of air resistance and some energy absorption of the the reflecting surface.