Scope Creep: beneficial or disadventageous?

Answer:

The wind force on the screen is approximately 5,341.5936 \(lb_f\)

Explanation:

The speed of the wind, v = 36 mph

The width of the outdoor movie, w = 70 ft. wide

The height of the outdoor movie, h = 20 ft. tall

The drag coefficient, Cd = 1.15

We have;

\(C_d = \dfrac{F}{\dfrac{\rho \cdot v^2 \cdot A}{2} }\)

From which we have;

The wind force, F = 0.00256·\(C_d\)·v²·A

Where;

A = The cross sectional area of the rectangular outdoor movie screen, A = w × h

∴ A = 70 ft. × 20 ft. = 1,400 ft.²

The wind force, F = 0.00256 × 1.15 × (36 mph)² × 1,400 ft.² = 5,341.5936 \(lb_f\)

The wind force on the screen, F = 5,341.5936 \(lb_f\).

The wind force on the outdoor movie screen is;

F = 23437.26 N

We are given;

Wind speed; v = 36 mph = 16.0934 m/s

Width of screen; w = 70 ft = 21.336 m

Height of screen; h = 20 ft = 6.096 m

Drag coefficient; Cd = 1.15

Now formula for the drag force is;

F = ½•C_d•ρ•A•v²

Where;

F is drag force

C_d is drag coefficient

ρ is density of object

v is speed of object

A is area

Let us use density as 1.21 kg/m³

Area; A = wh = (21.336 × 6.096)

Thus;

F = ½ × 1.15 × 1.21 × (21.336 × 6.096) × 16.0934²

F = 23437.26 N

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Answer:

  radiative heat loss substantially increases as the wall temperature declines

Explanation:

The body's heat loss due to convection is ...

  (2 W/m^2·K)((32 -20)K) = 24 W/m^2

__

The body's heat loss due to radiation in the summer is ...

  \(\epsilon\sigma(T_b^4-T_w^4)\quad\text{where $T_b$ and $T_w$ are body and wall temperatures ($^\circ$K)}\\\\0.90\cdot 5.6703\cdot 10^{-8}(305.15^4-300.15^4)\,\text{W/m$^2$}\\\\\approx 28.3\,\text{W/m$^2$}\)

The corresponding heat loss in the winter is ...

  \(0.90\cdot 5.6703\cdot 10^{-8}(305.15^4-287.15^4)\,\text{W/m$^2$}\\\\\approx 95.5\,\text{W/m$^2$}\)

Then the total of body heat losses to surroundings from convection and radiation are ...

  summer: 24 +28.3 = 52.3 . . . W/m^2

  winter: 24 +95.5 = 119.5 . . . W/m^2

__

It is reasonable that a person would feel chilled in the winter due to the additional radiative loss to the walls in the winter time. Total heat loss is more than doubled as the wall temperature declines.

Under ideal conditions, a truck with air brakes going 55 MPH would require a stopping distance of 344 feet.

Stopping distance is the total distance covered by a vehicle from the time the driver perceives the need to stop to the point where the vehicle comes to a complete halt.

The stopping distance is determined by the vehicle's speed, brakes, tires, and roadway surface conditions.

Stopping distance can be determined by adding together the thinking distance and the braking distance. The thinking distance is the distance traveled by the vehicle before the driver can react.

The braking distance is the distance required by the vehicle to come to a halt once the driver applies the brakes.

Under ideal conditions, a truck with air brakes going 55 MPH would require a stopping distance of 344 feet.

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Technician a is correct. The car may veer off course due to loose ball joints. The propensity of a vehicle to veer from one side of the road to the other is known as wander.

The propensity of a vehicle to veer from one side of the road to the other is known as wander. Uneven tire pressure or mismatched tires are potential causes number one. Linkage binding or inadequate lubrication is a potential cause number two. The third potential factor is binding or inadequate lubrication of the steering gear.

The bottom line is that before you start to address poor steering performance, you must identify the underlying source of the issue. Oversteer and understeer have been discussed separately, but we've also included 10 other common steering issues with their likely causes below. You can stop cursing and start fixing your steering problems by locating potential problem areas.

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When it comes to combining multiple documents, an important word processing skill to know that ensures the final result is organized and easy to use is pagination.

Pagination is a page numbering technique that is done sequentially. These page numbers are usually located at the top or bottom of the web page. In most cases, it is used for main pages and partitions in corporate websites. This kind of design can generally make the user experience simpler on the site. They can also feel more comfortable when it comes to distributing and navigating products within the website.

For example, like this, imagine an e-commerce site that consists of hundreds of product catalogs from various categories. Of course, these products will not be found easily if only placed on one page. As a solution, UI developers and designers can take advantage of pagination to make product placement more structured.

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Answer:

Follows are the solution to this question:

Explanation:

Its difference in power supply will be smaller whenever the pressure transducer is being performed. Its transducer sensitivity(s) is often used to calculate its number of changes occurring at voltage output of (\(v_o\)) when the supply tension (\(v_s\)) changes with the measured pressure (\(p_m\)) and the rated tension of transducers (\(p_s\)).

\(v_o= (s) V_s (\frac{P_m}{P_s})\)

Answer:

Cross pattern, according to the internet

Answer: 75,000 Hz

Explanation:

To calculate the frequency of the supply voltage, we need to use the formula:

frequency = 1 / time period

where the time period is the time it takes for one complete cycle of the waveform. For a sine wave, the time period is given by:

time period = 2π / angular frequency

where the angular frequency is the rate of change of the angle with respect to time and is given by:

angular frequency = 2π × frequency

Comparing the given voltage expression v = 240 sin (471,239t) V to the general form of a sine wave:

v = Vm sin(ωt + θ)

where Vm is the amplitude, ω is the angular frequency, t is time, and θ is the phase angle, we can see that the amplitude is 240 V, the angular frequency is 471,239 rad/s, and there is no phase angle (θ = 0).

Using the formula for angular frequency, we can find the frequency:

angular frequency = 2π × frequency

471,239 = 2π × frequency

frequency = 471,239 / (2π) ≈ 75,000 Hz

Therefore, the frequency of the supply voltage is approximately 75,000 Hz.

Hope this helps, :^)

it is undesirable that all of the points should fall extremely near, or exactly on, the centerline of the control chart Because:

If a data point falls is said to outside the control limits, we can say that the process is said to be out of one's control and it is good that an investigation is done to ascertain and remove the cause or causes.

So, it is undesirable that all of the points should fall extremely near, or exactly on, the centerline of the control chart Because:

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Answer:

whatsthe question choices

The maximum percentage recovery of p-chlorophenol in this process is 100%.

To calculate the maximum percentage recovery of p-chlorophenol, we first need to determine the equilibrium concentrations in both stages of the crosscurrent contact using the given equilibrium relation y = x.

For the first stage, the initial concentration of p-chlorophenol is 1 g/kg, which means x1 = 1 g/1000 kg. Using the equilibrium relation, we get y1 = x1, so y1 = 1 g/kg. In this stage, 1 kg of adsorbent is used, so the total solute adsorbed is 1 kg * y1 = 1 g.

In the second stage, the remaining solution has 100 kg - 1 g = 99 g of p-chlorophenol. The new concentration is x2 = 99 g/100,000 kg. The second 1 kg of adsorbent is used, so y2 = x2, and the total solute adsorbed in this stage is 1 kg * y2 = 99 g.

The total solute adsorbed in both stages is 1 g + 99 g = 100 g. Since the initial amount of solute was 100 g, the maximum percentage recovery is:

(100 g / 100 g) * 100% = 100%

Thus, the maximum percentage recovery of p-chlorophenol in this process is 100%.

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The factor of Safety by Maximum Distortion Energy Theory is given as: N = 6.04

According to this idea, failure by yielding happens when the distortion energy per unit volume in a condition of combined stress equals that associated with yielding in a basic tension test at any location in the body.

Note that we are given the following:

A solid Steel bar subjected to a bending force of F = 55kN

Torsional load T = 30 kN-mm; and

Yield Strength (sy) = 280Mpa

Sut = 330 Mpa

The formula for Normal Stress is given as:

\(\alpha _{x}\) = [UP/πd²] + [ (32* f * L)/πd³]

= [(4 * 8 * 10³)/π * (0.02)²] + [(32 * 55 *10³ * 0.1)/ π * (0.02)³]

= 25.46 + 7.003

\(\alpha _{x}\)= 32.5 Mpa

Tyz = (16T)/πd³

= (16 * 30)/ π * (0.02)³

= 19.098

Tyz = 19.098

Following from the above, sate of stress, we have:

α₁ = αₓ = 32.46 Mpa; and

α₂ = Tyz = 19.098 Mpa;

α₃ = -Tyz = -p19.098 Mpa;

Utilizing the formula given by the Maximum Distortion Energy Theory:

α₁² + α₂² + α₃² - (α₁α₂ + α₂α₃ + α₃α₁)

= Sy²/N²

→ 32.46² + 19.098² + 19.098² - ( 32.46* 19.098 - 19.098² -32.46 *  19.098)

= 280/N²

N = 6.04

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Answer:

At the time of the summer or winter solstices, the Sun is 23.44° degrees above or below the horizon, respectively, irrespective of time of day.

Explanation:

Answer:

A video camera with onboard storage(whether is a tape or digital memory) will record sound

A strategy that may help a visual learner process data is a pie chart or histogram.

Answer:d

Explanation:

(d) chain drive belt drive gear drive

The chain drive belt drive gear drive. Thus option D is correct.

The power transmission includes the bulk of the electrical energy form the generating sites such as the power station or the power plant and send to the anelectric substation where the voltage gets transformed and distributed to the insurers on other substations.

They can be mechanical, electrical and hydrologic, etc. The power transmission can move the electricity over larger distances.

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Answer:

Engine oil level.

Brake fluid.

Power steering fluid.

For ε = 0.1, approximately 2.147 random inputs are needed for a collision. The number of inputs required for the hash functions producing outputs of lengths 128 and 160 bits using the same formula.

To determine the number of random inputs needed to achieve a specific probability of collision, we can use the birthday paradox principle. The birthday paradox states that in a group of people, the probability of two individuals having the same birthday is higher than expected due to the large number of possible pairs.

The formula to calculate the approximate number of inputs required for a given probability of collision (ε) is:

n ≈ √(2 * log(1/(1 - ε)))

Let's calculate the number of inputs needed for ε = 0.5 and ε = 0.1 for each hash function:

For a hash function producing a 64-bit output:

n ≈ √(2 * log(1/(1 - 0.5)))

n ≈ √(2 * log(2))

n ≈ √(2 * 0.693)

n ≈ √(1.386)

n ≈ 1.177

For ε = 0.5, approximately 1.177 random inputs are required to have a probability of collision.

For ε = 0.1:

n ≈ √(2 * log(1/(1 - 0.1)))

n ≈ √(2 * log(10))

n ≈ √(2 * 2.303)

n ≈ √(4.606)

n ≈ 2.147

For ε = 0.1, approximately 2.147 random inputs are needed for a collision.

Similarly, we can calculate the number of inputs required for the hash functions producing outputs of lengths 128 and 160 bits using the same formula.

Please note that these calculations provide approximate values based on the birthday paradox principle. The actual probability of collision may vary depending on the specific characteristics of the hash functions and the nature of the inputs.

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The wired networking standard that specifies the order in which data is sent through the network is Ethernet.

Ethernet is a widely used wired networking standard that defines the protocols and specifications for data transmission over a local area network (LAN). It specifies the order in which data is sent through the network by utilizing the Carrier Sense Multiple Access with Collision Detection (CSMA/CD) algorithm.

The CSMA/CD algorithm ensures that multiple devices connected to an Ethernet network can share the same communication medium without interfering with each other. Before transmitting data, a device using Ethernet listens to the network to detect if it is clear to send data. If the network is busy, it waits for an opportune moment. Once the network is clear, the device sends the data, constantly monitoring for collisions. If a collision occurs (when two or more devices transmit data simultaneously), they stop transmitting, wait for a random period of time, and then retry.

By following this protocol, Ethernet ensures orderly and efficient data transmission within the network, minimizing collisions and maximizing data throughput. It has become the de facto standard for wired local area networks due to its reliability, scalability, and widespread adoption.

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Answer:

Answer is. (d) all of the above

Answer:

my answer is D

Explanation:

all of the above

Answer:

The in-shell pine nuts enter a long rotating cylinder where the shells are crushed between two cylinders (2). The product is then sieved/sorted to spate the shells from the nuts, leaving the nuts ready for further processing. Once the shelling process is complete, the pine nuts are then dried.

Explanation:

hope it helps:)

The RPM of the single-acting compressor is 300 revolutions per minute if the stroke is 8 inches and the piston speed is 400 feet per minute.

RPM is an abbreviation for revolutions per minute which is used to indicate the speed of a thing by determining how many times it turns one complete circle during one minute.

To determine the RPM in this case, we use the formula for piston speed as follows;

Piston speed = ( 2 × Stroke × RPM ) ÷ 12

As the stroke is given to be 8 inches and the piston speed is given to be 400 feet per minute, substituting these values in the equation as follows;

400 = ( 2 × 8 × RPM ) ÷ 12

400 × 12 = 16 × RPM

4800 = 16 × RPM

RPM = 4800 ÷ 16

RPM = 300

Therefore this single-acting compressor is determined to have 300 revolutions per minute.

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Efficiency of the algorithm is O(1)Algorithm efficiency is the amount of time and space it takes to solve a given problem. The efficiency of an algorithm is determined by the total number of operations it executes in the worst-case scenario. A mathematical proof will be presented to support this result.

As a result, we may compute the efficiency of the given algorithm by counting the number of operations required to execute the algorithm. The given algorithm is written in Java, and it takes an integer input from the user. Two variables i and j are created and initialized to 0.

The loops are executed to iterate from 0 to 99. Each iteration involves a comparison to check whether the condition is met or not. The result of this program would be the value of j = 50.

In addition, the time complexity for this program is O(1).Below is the proof that shows why the efficiency of the algorithm is O(1):1. For the first loop, the variable i is initialized to 0 and incremented up to 99.

Therefore, the loop will execute for a total of 100 times.

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Any compressor's discharge temperature cannot exceed 225 degrees F. if the discharge temperature rises above 225 degrees.

However, many compressor packages will contain components that limit discharge temperature to no more than 148.9°C (300°F). In general, it is advised to never exceed operating discharge temperatures of 176.7°C (350°F).

The primary cause of high condensing pressure is high discharge pressure. High condensing pressure can be caused by insufficient condenser heat dissipation, condenser fouling, insufficient cooling air or water volume, and high cooling water or air temperature.

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An ATX power supply performs essential functions like power conversion, power distribution, voltage regulation, power protection, cooling, power management, and providing connectors and cabling.

1. Power Conversion: An ATX power supply converts the incoming AC voltage from the wall outlet into multiple DC voltages required by the computer components. It provides +3.3V, +5V, and +12V DC power outputs.

2. Power Distribution: The power supply distributes the converted DC power to various components of the computer system, such as the motherboard, CPU, memory, hard drives, and expansion cards.

3. Voltage Regulation: It ensures that the DC voltages supplied to the components remain stable and within the specified tolerance limits. Voltage regulation is vital for the proper functioning and longevity of computer components.

4. Power Protection: The power supply incorporates various protection mechanisms to safeguard the computer system from power fluctuations, surges, and short circuits. These protections include overvoltage protection (OVP), undervoltage protection (UVP), overcurrent protection (OCP), and overtemperature protection (OTP).

5. Cooling and Heat Dissipation: ATX power supplies include cooling fans and heat sinks to dissipate the heat generated during operation. They ensure proper airflow within the power supply unit and prevent overheating.

6. Power Management: ATX power supplies support power management features, such as standby power and sleep modes. These features enable the computer system to enter low-power states when not in use, reducing energy consumption.

7. Connectors and Cabling: The power supply provides various connectors and cables to connect to different components, including the motherboard, drives, and peripherals. Common connectors include the 24-pin ATX connector, SATA power connectors, and PCIe power connectors.

An ATX power supply performs essential functions like power conversion, power distribution, voltage regulation, power protection, cooling, power management, and providing connectors and cabling. These functions ensure the reliable and efficient delivery of power to the various components of a computer system.

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It is a weakly dominant strategy for each agent i to vote for her ideal location Pi.

(a) The strategic form of the game can be represented as follows:

Agent 1's strategy set: S1 = [0,1]

Agent 2's strategy set: S2 = [0,1]

Agent 1's payoff function: U1(11,12) = -P1 - d(x1,0)

Agent 2's payoff function: U2(11,12) = -P2 - d(x2,0)

Here, P1 and P2 represent the ideal locations of Agent 1 and Agent 2, respectively. x1 and x2 are the voted locations by Agent 1 and Agent 2, respectively. The function d(a,b) represents the distance between points a and b.

(b) To show that it is a weakly dominant strategy for each agent i to vote for her ideal location Pi, we need to compare the payoffs for different strategies of each agent.

For Agent 1:

Suppose Agent 1 votes for a location x' != P1. Let's consider two cases:

1. If x' < P1:

  In this case, the utility of Agent 1 would be U1(x',x2) = -P1 - d(x',0).

  Since x' < P1, the distance d(x',0) would be greater than or equal to the distance d(P1,0).

  Therefore, U1(x',x2) <= -P1 - d(P1,0) = U1(P1,x2).

2. If x' > P1:

  In this case, the utility of Agent 1 would be U1(x',x2) = -P1 - d(x',0).

  Since x' > P1, the distance d(x',0) would be greater than or equal to the distance d(P1,0).

  Therefore, U1(x',x2) <= -P1 - d(P1,0) = U1(P1,x2).

From the above two cases, we can conclude that for Agent 1, voting for any location other than P1 would result in a weakly lower or equal utility compared to voting for P1. Hence, voting for P1 is a weakly dominant strategy for Agent 1.

Similarly, we can show that voting for Pi is a weakly dominant strategy for Agent 2.

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Answer:

a) C1 = 3C2

b) C1 = 1 , C2 = -3  

c) \(w = \frac{-x^2}{2} + \frac{y^2}{2} + 3xy + C\)

d) (v.v)T = 0

Explanation:

u = 3x + C1y

v = x + C2y

A) determining all  stagnation points

At The stagnation points : u = 0, v = 0

for all  values of C1 and C2 , C1 = 3C2

B) The coefficients of C1 and C2 so that the flow is potential

C1 = 1 , C2 = -3  

C) Determine the expression of the stream function

\(w = \frac{-x^2}{2} +\frac{y^2}{2} +3xy+ C\)

D) The value of (v.v)T at the point (x,y) = (1,2)

(v.v)T = 0

Attached is the detailed solution

Answer:

1.96 kg/s.

Explanation:

So, we are given the following data or parameters or information which we are going to use in solving this question effectively and these data are;

=> Superheated water vapor at a pressure = 20 MPa,

=> temperature = 500°C,

=> " flow rate of 10 kg/s is to be brought to a saturated vapor state at 10 MPa in an open feedwater heater."

=> "mixing this stream with a stream of liquid water at 20°C and 10 MPa."

K1 = 3241.18, k2 = 93.28 and 2725.47.

Therefore, m1 + m2= m3.

10(3241.18) + m2 (93.28) = (10 + m3) 2725.47.

=> 1.96 kg/s.

Answer:

Virtually every product or service in modern life has probably been touched in some way by a mechanical engineer to help humankind. This includes solving today's problems and creating future solutions in health care, energy, transportation, world hunger, space exploration, climate change, and more.