Scientists have been collecting atmospheric co2 data for many years to monitor changes over time. Which of the following best describes why an island location, such as the mauna loa observatory in hawaii, is an ideal location to measure global co2 concentrations?.

Answers

Answer 1

Mauna Loa Observatory in Hawaii is an ideal location to measure global atmospheric CO2 concentration. This is because the observatory is situated far away from the main continental sources of atmospheric pollution. This allows for direct measurement of the undisturbed background concentration of CO2 in the atmosphere.

The monitoring of atmospheric CO2 data has been going on for several years to watch over the changes that happen over time. The Global Atmosphere Watch (GAW) is a program established by the World Meteorological Organization to measure and monitor various atmospheric trace gases and their isotopes and other related parameters.The observatory is situated at an elevation of 3,397 meters, which is high enough to make measurements above the "boundary layer," the lowest part of the atmosphere, which is influenced by nearby sources. Mauna Loa is in a remote location, far from urban and industrial pollution sources. Mauna Loa is situated in the middle of the Pacific Ocean, thousands of miles from any large continental sources of atmospheric pollution, which makes it a suitable place for accurate measurements of undisturbed background atmospheric CO2 concentrations.

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Related Questions

50 POINTS PLEASE ANSWER CORRECTLY
Two balls collide on a pool table. Before the collision, ball 1 is traveling with a speed of 4 m/s, and ball 2 is at rest. After the collision both balls are in motion.
What has happened in this collision?

A. There was no change in ball 2's velocity, therefore momentum was not conserved.

B. Ball 2's velocity decreased, and it gained some of ball 1's momentum.

C. Ball 1's velocity decreased, and it gained momentum.

D. Ball 2's velocity increased, and it gained some of ball 1's momentum.

Answers

Answer:

D

Explanation:

With the collision, obviously Ball 2's velocity increased, while Ball 1 slowed down a little bit due to the impact. This decrease in velocity caused a decrease in Ball 1's Momentum. Satisfying both conditions, option D is right.

Ammonia (NH3) reacts with oxygen to form nitrogen monoxide and water. All the materials involved in this reaction are gasses. 0.100 moles of each of the reactants are initially introduced to a 5.0-liter reaction vessel. a. What would be the quantity of each gas in the container upon completion of the reaction? b.What would be the partial pressure of each gas on the reaction vessel upon reaction completion if the temperature of the system is 105 degrees C? c. What is the total pressure of all the gases on the reaction vessel at 105 degrees C?

Answers

Answer:

a. 0.02 moles  of NH₃, 0 moles of O₂, 0.08 moles of NO, 0.12 moles of H₂O

b. \(P_{NH_3}\) = 12,576.5 Pa, \(P_{NO}\) = 50,306.05 Pa, \(P_{H_2O}\) =  74,459.1 Pa

c. The total pressure is 138,341.64 Pa

Explanation:

a. NH₃ + O₂  → NO + H₂O

The balanced chemical equation is first found to be

4NH₃ + 5O₂  → 4NO + 6H₂O

Therefore, we have;

4 moles of NH₃ reacts with 5 moles of O₂ to form 4 moles of NO and 6 moles H₂O

Dividing by the reactant with the highest number of moles which is 5 moles of oxygen gives;

4/5 moles  of NH₃ reacts with 5/5 moles of O₂ to form 4/5 moles of NO and 6/5 moles H₂O

Which is the same as 4/5 moles  of NH₃ reacts with 1 mole of O₂ to form 4/5 moles of NO and 6/5 moles H₂O

Multiplying by 0.100 gives;

0.1×4/5 moles  of NH₃ reacts with 0.1 mole of O₂ to form 0.1×4/5 moles of NO and 0.1×6/5 moles H₂O

The quantity of each gas in the container upon completion of the reaction is therefore;

(0.1 - 0.1×4/5) = 0.02 moles  of NH₃

0 moles of O₂

0.08 moles of NO

0.12 moles H₂O

b. Given that the temperature = 105°C, we have;

PV = nRT

P = nRT/V

Where:

n = Total number of moles = 0.02 + 0.08 + 0.12 = 0.22 moles

R = Universal gas constant = 8.3145 J/(mol·K)

T = Temperature = 105°C = 378.15 K

V = Volume = 5 litre = 0.005 m³

P = 0.22×8.3145×378.15/0.005 = 138,341.64 Pa

From Dalton's law of partial pressure, we have;

Partial pressure Pₓ = Xₓ × P

Where:

Xₓ = Mole fraction

Which gives for ammonia NH₃ with 0.02 moles;

Mole fraction = 0.02/0.22 = 1/11

\(P_{NH_3}\) = 1/11 × 138,341.64  = 12,576.5 Pa

For the 0.08 moles of NO, we have

Mole fraction = 0.08/0.22 = 4/11

\(P_{NO}\) = 4/11 × 138,341.64  = 50,306.05 Pa

For the 0.12 moles H₂O

P = 0.12×8.3145×378.15/0.005 = 74,459.1 Pa

Mole fraction = 0.12/0.22 = 6/11

\(P_{H_2O}\) = 6/11 × 138,341.64  = 74,459.1 Pa

c. The total pressure = 12,576.5 Pa + 50,306.05 Pa + 74,459.1 Pa = 138,341.64 Pa.

What is the pH of a solution whose H + concentration is 4.0 10 –9?

Answers

Answer:

he pH of a solution is defined as the negative log10 [H+] ... 1 x 10-11. 11. Acidic Solution. 1 x 10-4. 4. 1 x 10-10. 10. 1 x 10-5. 5. 1 x 10-9.

Explanation:

m

A 35.0mL sample of 0.150 M acetic is titrated with 0.150 M NaOH solution. Calculate the pH after the following volumes of base have been added?
a) 0 mL b) 17.5 mLc) d) 35.0 mL e) 35.5 mL

Answers

The pH of the acetic acid solution after the addition of different volumes of NaOH solution are as follows:

a) pH = 2.87. Before any NaOH is added, the solution consists of 0.150 M acetic acid, which is a weak acid with a pKa of 4.76. At equilibrium, the concentrations of acetic acid and acetate ions are equal, and the pH can be calculated using the Henderson-Hasselbalch equation: pH = pKa + log([acetate]/[acetic acid]). Since no NaOH has been added yet, the concentrations of acetate and acetic acid are both equal to 0.150 M, so pH = 4.76 + log(0.150/0.150) = 2.87.

b) pH = 3.53. After adding 17.5 mL of NaOH solution, the concentration of acetic acid has decreased to 0.075 M, while the concentration of acetate ions has increased to 0.075 M. Using the Henderson-Hasselbalch equation with these new concentrations gives: pH = 4.76 + log(0.075/0.075) = 3.53.

c) pH = 9.09. After adding 35.0 mL of NaOH solution, all of the acetic acid has been converted to acetate ions. At this point, the solution consists of a 0.150 M acetate ion solution, which is the conjugate base of acetic acid. The pH of this solution can be calculated using the equation: pH = pKa + log([base]/[acid]). Since the pKa of acetic acid is 4.76, the pH of the solution is: pH = 4.76 + log(0.150/0) = 9.09.

d) pH = 9.28. After adding 35.0 mL of NaOH solution, there is still an excess of base in the solution. The pH can be calculated using the same equation as in part (c), but with the new concentration of acetate ions: pH = 4.76 + log(0.300/0) = 9.28.

e) pH = 9.35. After adding 35.5 mL of NaOH solution, the concentration of base is now greater than the concentration of acetate ions, resulting in a basic solution. The pH can be calculated using the equation: pH = 14.00 - pOH = 14.00 - (-log[OH-]) = 9.35.

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Using the reaction of Calcium Chloride and Sodium Phosphate, what would be the limiting reactant if 15mL of 0.2SOM Calcium Chloride was combined with 15mL of 0.325M Sodium Phosphate? Show your calculations. Include the Balanced Chemical Equation, with phases. 2). The solubility of Barium Hydroxide is listed in the solubility table as 5.60g of Barium Hydroxide Octahydrate at 15°C in 100mL of Water. Show your work for the following calculations. Give all values to three significant figures. How many moles of Barium Hydroxide is this? How many grams of Barium Hydroxide can dissolve in 100mL of water at 15°C? What is the molarity of Barium lons? What is the molarity of Hydroxide ions?

Answers

The limiting reactant is Calcium Chloride, and Barium Hydroxide's molarity is 0.11M with a solubility of 5.60g in 100mL of water at 15°C.

1. The limiting reactant in the reaction between Calcium Chloride and Sodium Phosphate would be Sodium Phosphate, as it has a lower number of moles.

The balanced chemical equation for the reaction is: \(CaCl_2\)(aq) + \(Na_3PO_4\)(aq) → \(Ca_3(PO_4)_2\)(s) + 6NaCl(aq).

The calculation for the limiting reactant can be shown as follows:

Moles of \(CaCl_2\) = (0.2 mol/L) x (0.015 L) = 0.003 mol

Moles of \(Na_3PO_4\) = (0.325 mol/L) x (0.015 L) = 0.004875 mol

Therefore, \(Na_3PO_4\) is the limiting reactant.

2. The molar mass of Barium Hydroxide Octahydrate is 315.46 g/mol.

Moles of Barium Hydroxide Octahydrate that can dissolve in 100mL of water at 15°C = (5.60 g) / (315.46 g/mol) = 0.0178 mol

Grams of Barium Hydroxide that can dissolve in 100mL of water at 15°C = 5.60 g

Molarity of Barium ions = (0.0178 mol) / (0.1 L) = 0.178 M

Molarity of Hydroxide ions = 2 x (0.0178 mol) / (0.1 L) = 0.356 M.

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which point marks the highest temperature and pressure at which it's possible to determine whether a sample of pure x is a liquid or a gas?

Answers

The point that marks the highest temperature and pressure at which it's possible to determine whether a sample of pure x is a liquid or a gas is called the critical point.

At the critical point, the substance can no longer be compressed into a liquid and expanding it does not result in vaporization. At this point, the temperature and pressure are at their highest and are called the critical temperature and critical pressure, respectively.

The critical point marks the boundary between the liquid and gas phases, and any further increase in pressure or temperature will result in a single homogeneous phase. The critical temperature and pressure are unique properties of each substance and can be used to identify and differentiate between different materials.

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a 1.5 m solution of nacl has a volume of 0.534 l. if this is diluted to 0.80 m, what will be the final volume?

Answers

Dilution formula is: M conc . Vol conc = M diluted . Vol diluted

1.5 M . Vol conc = 0.80 M . 0.10L

Vol conc = 0.80 M . 0.10L / 1.5M = 0.053L

Does NaCl produce a solution?

When water molecules push the ions apart, the ionic bond holding sodium and chloride ions together is destroyed. The water molecules surround the sodium and chloride atoms in this image after the salt compounds have been separated. The salt then starts to dissolve and turns into a homogeneous solution.

0.9% sodium chloride Injection, USP is a sterile, nonpyrogenic, isotonic sodium chloride and water solution for injection. Each mL of solution contains 9 mg of sodium chloride. It is only offered in single-dose vials and doesn't contain any bacteriostats, antibacterial agents, or extra buffers. Drugs for injection are diluted or dissolved using it.

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Help plz (will mark brainleist)

Help plz (will mark brainleist)

Answers

Answer:

energy disturbance easy

PLEASE HELP!!!!! NEED HELP ASAP!!!!!

Write the chemical formula for the covalent compounds below
EXAMPLE- dinitrogen trioxide= N2O3

nitrogen monoxide =
dihydrogen oxide =
diphosphorus pentoxide =
sulfur trioxide =

Answers

Answer:

down below

Explanation:

NO

H20

P4O10

SO3

1. NO

2. H2O

3. P4O10

4. SO3

How many moles of potassium chloride (KCl) can be produced by the decomposition of 4.0 mol of potassium chlorate (KClO3).

Answers

It takes 4 moles of potassium chlorate to make 6 moles of oxygen gas.

How many moles of KCl are generated from the breakdown of one mole of KClO3?

Due to the fact that there will only be 1 chemical present, this indicates that approximately 2 moles of KCL03 will disintegrate. It will break down into two moles of KCL and three moles of oxygen.

How many grammes of oxygen gas are created when 5.00 moles of potassium chlorate are broken down?

We can observe that three moles of oxygen are created from two moles of potassium chlorate. As a result, we can say that 1.9684 g of oxygen will be created during the entire breakdown of 5 g of $KClO 3$.

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A fundamental equation of thermodynamics, the Gibbs-Helmholtz equation, is a linear equation that relates free energy change, AG, to absolute temperature, T. The equation is AG = AH -TAS, where AH is enthalpy change and AS is entropy change. Using the above equation, find AG at 400 K for a reaction in which AH = 61.0 kcal and AS = 0.020 kcal/K. 7. A cost equation is known to be y = 10x + 250, where x is the number of units produced and y is the cost in $. Find the total cost of producing 5 000 units. Round your answer to four significant digits (SD).

Answers

At 400 K, the free energy change (ΔG) for the reaction is 53.0 kcal. The total cost of producing 5,000 units is $50,250.

To find ΔG at 400 K using the Gibbs-Helmholtz equation, we need to substitute the given values of ΔH and ΔS into the equation.

ΔG = ΔH - TΔS

Given;

ΔH = 61.0 kcal

ΔS = 0.020 kcal/K

T = 400 K

Substituting these values into the equation;

ΔG = 61.0 kcal - (400 K)(0.020 kcal/K)

ΔG = 61.0 kcal - 8.0 kcal

ΔG = 53.0 kcal

Therefore, at 400 K, the free energy change (ΔG) for the reaction is 53.0 kcal.

To find the total cost of producing 5,000 units using the cost equation y = 10x + 250, we need to substitute x = 5,000 into the equation.

y = 10x + 250

Given;

x = 5,000

Substituting x = 5,000 into the equation:

y = 10(5,000) + 250

y = 50,000 + 250

y = 50,250

Therefore, the total cost of producing 5,000 units is $50,250.

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How much heat is released or absorbed in the reaction of 10.0 grams of SiO2 (quartz) with excess hydrofluoric acid?SiO2(s) + 4HF(aq) → SiF4(g) + 2H2O (kJ/mol) −910.9 −320.8 −1615 −285.8a. 1.25 kJ absorbedb. 1.25 kJ releasedc. 11.3 kJ absorbedd. 11.3 kJ releasede. 6.56 kJ released

Answers

The correct answer is d. 11.3 kJ released, which is the value obtained by rounding the actual heat of hydrofluoric acid released to two significant figures.

Based on the given thermochemical equation, the reaction releases 910.9 kJ/mol of SiO2 reacted. To determine the amount of heat released or absorbed in the reaction of 10.0 grams of SiO2 with excess hydrofluoric acid, we need to first convert the mass of SiO2 to moles.

Molar mass of SiO2 = 60.08 g/mol
10.0 g SiO2 ÷ 60.08 g/mol = 0.166 mol SiO2

Since the reaction ratio between SiO2 and heat is 1 mol SiO2 : 910.9 kJ, we can calculate the amount of heat released or absorbed by multiplying the number of moles of SiO2 by the heat released per mole:

0.166 mol SiO2 x 910.9 kJ/mol = 151.2 kJ

The heat released in the reaction of 10.0 grams of SiO2 with excess hydrofluoric acid is 151.2 kJ. However, the answer choices do not match this value exactly. The closest answer choice is e. 6.56 kJ released. This answer is incorrect, as it is much lower than the actual heat released in the reaction.

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Option 1: Individual Activity

Clear the coordinates you currently have on the interactive map from Part E by clicking on the red X symbol in the coordinates menu. Directly below it, click on the Add Coordinates button. Enter the coordinates N 35°00’ 00”, latitude and E 33°00’ 00” longitude. Then zoom out so that you can see the entire country where these coordinates are located. What is the name of the country and the body of water that surrounds it?

Option 2: Group Activity

Using the interactive online map from parts D and E, locate a country that you have never been to but would like to visit. Without the other members of your group watching, type in the name of this place in the address box. Then write down only its latitude and longitude coordinates on a piece of paper. Next, trade your paper with a partner who has also looked up and written down the coordinates of a place. Using your partner’s coordinates and the online map, locate the country your partner would like to visit. Do this by clicking the Add Coordinates button below the address and coordinates boxes and then entering your partner’s coordinates.

Check with your partner to make sure you got the location right. After you determine the location your partner would like to visit, write the coordinates and the name of the country in the answer space.

Answers

The country located at coordinates N 35°00' 00", latitude and E 33°00' 00" longitude is Cyprus and is surrounded by the Mediterranean Sea. The country I would like to go to would be the one located at coordinates N 41°89'01" E 12°49'22".

What is a geographic coordinate?

Geographic coordinates is a term that refers to a reference system that has the objective of identifying a point located on Earth using a system of numbers, letters or symbols.

The geographical coordinates take as reference points the Greenwich meridian (longitude 0°) and the line of the equator (latitude 0°). On the other hand, longitudes range from 0° to -180° or 180° and latitudes range from to 90° or -90°.

According to the above, it can be inferred that the location of the coordinates N 35°00' 00", latitude and E 33°00' 00" longitude is the country of Cyprus surrounded by the Mediterranean Sea.

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P4(s) + Cl₂(g) → PCI3(l) + energy 4. Calculate the gram-formula mass of the product. Show all work. g/mol ​

Answers

The gram formula mass of the product, PCl₃, is 137.5 g.

What is the gram formula mass of a compound?

The amount of a compound that has the same mass in grams as the formula mass in an atomic mass unit is said to have the compound's gram formula mass. It is also known as the molar mass.

Every element's atom has a characteristic mass, and each compound's molecule has a characteristic mass determined by the compound's formula.

The gram formula mass of the product PCl₃ is calculated below:

The atomic mass of P = 31 g

The atomic mass of Cl = 35.5 g

The gram formula mass of PCl₃ = 31 + 35.5 * 3

The gram formula mass of PCl₃ = 137.5 g

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two types of fine chemical​

Answers

Answer:

Flavors and fragrances

flavors and fragrances

how much heat is evolved when 27.0 g of glucose is burned according to this equation? c6h12o6 6o2 → 6co2 6h2o; δ h comb. = -2808 kj/mol. a. 421 kJ
b. 241 kJ
c. 280 kJ
d. 136 kJ

Answers

The amount of heat evolved when 27.0 g of glucose is burned according to the equation is (A) 421 kJ.

The balanced chemical equation for the combustion of glucose is

C₆H₁₂O₆ + 6O₂ → 6CO₂ + 6H₂O.

To determine the amount of heat evolved when 27.0 g of glucose is burned, we need to use the molar mass of glucose and the given heat of combustion (ΔHcomb) in kJ/mol. The molar mass of glucose (C₆H₁₂O₆) can be calculated as follows:

Molar mass of C = 12.011 g/mol

Molar mass of H = 1.008 g/mol

Molar mass of O = 15.999 g/mol

Molar mass of glucose = (6 x 12.011) + (12 x 1.008) + (6 x 15.999) = 180.156 g/mol

So, 27.0 g of glucose is equal to 27.0/180.156 = 0.1499 mol of glucose.

The amount of heat evolved when 1 mol of glucose is burned is ΔHcomb = -2808 kJ/mol.

So, the amount of heat evolved when 0.1499 mol of glucose is burned is:

ΔHcomb x 0.1499 mol = -2808 kJ/mol x 0.1499 mol = -420.8 kJ (rounded to one decimal place)

Therefore, the amount of heat evolved when 27.0 g of glucose is burned is 420.8 kJ. However, since the answer choices are given in kJ and not in kJ/mol, we need to round the answer to the nearest whole number. The correct answer is therefore (a) 421 kJ.

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Is Palladium an elementary substance or a compound?

Answers

Answer:

Elementary substance, since it is in the periodic table of elements.

Hope that helps!

-SCSB

Explanation:

A sample of carbon dioxide gas occuples a volume of 2.5L at standard temperature and pressure (STP). What will be the volume of a sample of argon gas that has the same number of moles and pressure but twice the absolute temperature?

Answers

Answer:

The correct answer is 5.0 L

Explanation:

STP are defined as T=273 K and P= 1 atm

By using the ideal gas equation, we can calculate the number of moles (n) of the gas at a volume V=2.5 L:

PV= nRT

⇒n= (PV)/(RT) =(1 atm x 2,5 L)/(0.082 L.atm/K.mol x 273 K)= 0.112 mol

For a sample of argon gas, with the same number of moles (0.112 mol) but twice the temperature (T = 273 K x 2= 546 K):

V= (nRT)/P = (0.112 mol x 0.082 L.atm/K.mol x 546 K)/1 atm = 5.0 L

That is consistent with the fact that when a gas is heated, it expanses. So, if the temperature increases twice, the volume also increases twice.

If rates of nitrogen fixation increased tenfold in aquatic ecosystems, would you expect a tenfold increase in primary productivity? Yes or No

Answers

The given statement " If rates of nitrogen fixation increased tenfold in aquatic ecosystems, would you expect a tenfold increase in primary productivity" is true because because nitrogen is a limiting nutrient in terrestrial ecosystems.

In the terrestrial ecosystem the nitrogen is the most important limiting nutrient. The Nitrogen gas is the one of the major abundant gas in the atmosphere that occupying 78 % by the volume. Nitrogen plays the important role in the controlling the aquatic and the terrestrial ecosystem. The nitrogen and the phosphorus are the most common limiting nutrient in the aquatic ecosystem.

Therefore, the presence of the high amount of the nitrogen in the atmosphere will leads to the release of the large amount of pollutants.

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When refering to a gas, the higher the temperature, the faster the particles move:
True
False

Answers

Answer:

True

Explanation:

In Gas,The movement of particles depends upon their temperature. When, the temperature is high the movement of the particles is faster.When, the temperature is low the movement of the particles is slower down and move close together.

Hence,

The above statement is true for, the gas particles moves faster in high temperature.

What is the molar mass of AI(CIO4)3?

Answers

Answer:

Molar mass is 325.33

Explanation:

Molar mass is 325.33

What is the molar mass of AI(CIO4)3?

If 6.73 g of Na2CO3 is dissolved in enough water to make 250.0 mL of solution, what is the molarity of the sodium carbonate solution

Answers

If 6.73 g of Na2CO3 is dissolved in enough water to make 250.0 mL of solution. The molar concentration of sodium carbonate will be  0.254 M.

Molarity is defined as the concentration of solute or a substance in given volume of a solution. The data guven in the question is as follows,

mass of sodium carbonate = 6.73 g

volume of solution =250 mL

Molar mass of sodium carbonate = 105.99 g/mol

So the molarity can be calculated as:

M =\(\frac{n}{V}\)

=\(\frac{6.73}{250}\) × \(\frac{1}{105.99}\) ×\(\frac{1000ml}{1L}\)

=0.254M Na₂CO₃

Thus, molarity of sodium carbonate is 0.254 M.

The dissociation of sodium carbonate in the ions, we get:

Na₂CO₃→ 2Na⁺ + CO₃⁻²

From the above equation, it can be interpreted as there is 1:2 mol ratio between sodium carbonate and sodium ion. The molarity of sodium will be:

Na⁺ =2×0.245=0.508 M

Also, it is seen that there is 1:1 mol ratio between sodium carbonate and carbonate ion, therefore, its molarity will be:

CO₃⁻² = 0.245M

Thus, the molarity of the sodium carbonate will be 0.254 M.

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a flask of an unknown gas with a pressure of 759 torr was attached to an open-end manometer. the mercury level was 2.4 cm higher at the open end than at the flask end. the atmospheric pressure when the gas pressure was measured was atm. report your answer to the hundredths place.

Answers

The atmospheric pressure when the gas pressure was measured is approximately 0.99 atm.

To determine the gas pressure inside the flask, we need to consider the pressure difference between the gas and the atmospheric pressure. The pressure difference can be determined by measuring the height difference of the mercury levels in the open-end manometer.

Pressure inside the flask (P_gas) = 759 torr

Height difference in the manometer (h) = 2.4 cm

The pressure difference between the gas and the atmospheric pressure can be calculated using the equation:

P_gas - P_atm = ρgh

Where:

P_atm is the atmospheric pressure

ρ is the density of mercury (13.6 g/cm³)

g is the acceleration due to gravity (9.8 m/s²)

h is the height difference in meters

First, we need to convert the height difference from centimeters to meters:

h = 2.4 cm = 0.024 m

Substituting the given values into the equation, we have:

759 torr - P_atm = (13.6 g/cm³ * 0.024 m * 9.8 m/s²)

Simplifying the equation, we can convert grams to kilograms and cancel out the units:

759 torr - P_atm = (0.3264 kg/m² * 9.8 m/s²)

To convert torr to atm, we divide by 760:

0.998 - P_atm = 0.3264 * 9.8 / 760

0.998 - P_atm = 0.0042

P_atm = 0.998 - 0.0042

P_atm = 0.9938 atm

Therefore, the atmospheric pressure when the gas pressure was measured is approximately 0.99 atm.

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PLEASE HEP QUICK!! I'M BEING TIMED!!
1. _____ - the phase change in which a substance changes from a liquid into a gas.
25 points
Vaporization
Condensation
Heat of vaporization
Evaporation
2. _____ - the process that changes a substance from a liquid to a gas at temperatures below the substances boiling point.
25 points
Heat of vaporization
Vaporization
Evaporation
Condensation
3. _____ - the energy a substance must absorb in order to change from a liquid to a gas.
25 points
Vaporization
Evaporation
Heat of vaporization
Condensation
4. The arrangement of molecules in water becomes less orderly as water melts and _____ orderly as water freezes.
25 points
more
less
Other:

Answers

Answer:

Evaporation, conensation, Heat of vaporization, more

Explanation:

im pretty sure this is correct

Answer: create a question.

Explanation:

what is the balance of S8+Br2=S3Br7

Answers

Answer:

     3S₈  +  28Br₂ => 8S₃Br₇

Explanation:

Start with either sulfur (S) or bromine (Br) and balance ...

    3S₈  +  Br₂ => 8S₃Br₇    or      S₈  +  7/2Br₂ => S₃Br₇

Balance the remaining reactant ...

    3S₈  +  56/2Br₂ => 8S₃Br₇    

Remove fractions by multiplying by the fraction's denominator

    2(3S₈  +  56/2Br₂ => 8S₃Br₇)     =>     6S₈  +  56Br₂ => 16S₃Br₇      

Reduce to smallest whole number ratio => standard equation at STP ...

        3S₈  +  28Br₂ => 8S₃Br₇

3. What are the values of the graduations (unmarked lines) in each of the
following graduated cylinders?
Q
(A)
50
3
graduations =
(B)
50
-40
-30
-20
10
graduations =
(C)
25
-20
-15
10
5
graduations =

Answers

The values of the Graduations for A , B and C will be  0.2 ml,  2ml and 1ml respectively.

Graduated Cylinder - A popular piece of scientific equipment used to measure the volume of a liquid is a graduated cylinder, sometimes referred to as a measuring cylinder or mixing cylinder. Its form is slender and cylindrical. Each marked line on the graduated cylinder indicates the volume of liquid that has been measured.

The clear graduated cylinder is widely used for volume measurements and is regarded to be more accurate than a beaker since it contains permanently marked incremental graduations.

To calculate the value of graduations-

1. Subtract the two values to get the value between the labeled graduations.

2. Determine how many spaces there are between the two graduations. Keep in mind that volume equals space.

3. Divide the number of gaps by the value between the graduations.

For cylinder  A.

2 ml- 1ml  = 1ml

Number of spaces = 5

∴1/ 5 = 0.2

Graduation = 0.2ml

For cylinder B -

20-10 = 10

number of spaces = 5

∴10/ 5 =2

Graduation = 2ml

For cylinder C-

10-5 = 5

Number of spaces= 5

∴5/5 = 1

Graduation = 1ml

Hence , Graduations for A , B and C will be  0.2 ml,  2ml and 1ml respectively.

To learn more about graduated cylinders refer-https://brainly.com/question/26216613

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3. What are the values of the graduations (unmarked lines) in each of thefollowing graduated cylinders?Q(A)503graduations

True or False? You can observe physical properties of matter without changing the identity of the substance

Answers

True it is true a

true
True And im typing this for charater limit

Germanium has ______ valence electrons and chlorine has ____ valence electrons

Answers

Answer:

Germanium has 4 valence electrons and chlorine has 7 valence electrons.

Explanation:

last shell of chlorine atom has 7 electrons in it. Therefore, there are 7 valence electrons present in an chlorine atom.

Solid state electronics arises from the unique properties of silicon and germanium, each of which has four valence electrons and which form crystal lattices in which substituted atoms (dopants) can dramatically change the electrical properties.

If the half-life of a radioactive substances is 590 million years and you have 40 atoms of it, how many half-lives will have passed when 5 atoms remain

Answers

Answer:

3

Explanation:

Applying,

\(2^{n'}\) = R/R'............... Equation 1

Where n' = number of halflives that have passed, R = Original atom of the substance, R' = atom of the substance left after decay.

From the question,

Given: R = 40 atoms, R' = 5 atoms

Substitute these values into equation 1

\(2^{n'}\) = 40/5

\(2^{n'}\) = 8

\(2^{n'}\) = 2³

Equation the base,

n' = 3

1. A student in lab measures 4.6 grams of copper for an experiment. Upon further analysis he determines that he should have measured out 4.7 grams of copper. What is his percent error?

Answers

Answer:

\(2.13\%\)

Explanation:

Quantity of copper measured by a student = 4.6 grams

Original quantity of copper = 4.7 grams

Error in measurement = Original quantity of copper - Quantity of copper measured by a student  \(=4.7-4.6=0.1\) grams

To find the percent error, apply the following formula:

Percent error = (Error in measurement / Original quantity of copper) × 100

\(=\frac{0.1}{4.7}(100)=2.13\%\)

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