The number of rock music is 192,000
Here, we want to know the number of rock music from the total
We have this as 64% of the total
That will be;
\(\frac{64}{100}\times\text{ 300,000 = 192,000}\)Simplify (10x^3 -3x-5) - (7x^2 +4x-9)
Answer:
10x³ - 7x² - 7x + 4
General Formulas and Concepts:
Pre-Algebra
Distributive PropertyAlgebra I
Combining Like TermsStep-by-step explanation:
Step 1: Define
(10x³ - 3x - 5) - (7x² + 4x - 9)
Step 2: Simplify
Distribute negative: 10x³ - 3x - 5 - 7x² - 4x + 9Combine like terms (x): 10x³ - 7x² - 7x - 5 + 9Combine like terms (Z): 10x³ - 7x² - 7x + 4plz do this ill mark brainly
Answer:
I'm pretty sure its C and D
If y varies directly as x, and y = 8 when x = 4, find y when x = 24.
The value of y is 48
How to calculate the value of y in the variation ?y= kx
let's solve for k which is the constant
y= 8 , x= 4
k= 8/4
k= 2
Next is to calculate the value of y when x is 24
y = 2 × 24
y= 48
Hence the value of y is 48
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Alastair drives 18.2 miles in 14 minutes.
He passes a sign which gives the speed limit as 50 mph.
By how much, in mph, did Alastair's average speed exceed the speed limit?
Answer:
28 mph
Step-by-step explanation:
Distance
18.2 milesTime
14 min = 14/60 hrAverage speed
d/t = 18.2 ÷ 14/60 = 182/10 × 60/14 = 78 mphThe difference with allowed speed
78 - 50 = 28 mphAnswer:
28mph
Step-by-step explanation:
Try These questions out and I’ll give you brainliest
The expressions are simplified to;
1. 72n² + 63n
2. 18t - 18t²
3. -18b² - 18b
4. -56r - 21r²
5. -6m + 9m²
What are algebraic expressions?Algebraic expressions are simply described as expressions that are known to consist of coefficients of variables, variables, constants, terms, and factors.
These algebraic expressions are also made up of mathematical or arithmetic operations.
These operations are;
BracketParenthesesAdditionMultiplicationDivisionSubtractionFrom the information given, we have;
1. -9n (-8n -7)
expand the bracket
72n² + 63n
2. -2t(-9 + 9t)
expand the bracket
18t - 18t²
3. -3b(6b + 6)
expand the bracket
-18b² - 18b
4. -7r(8 + 3r)
expand the bracket
-56r - 21r²
5. 3m(-2 + 3m)
expand the bracket
-6m + 9m²
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work out 4/5 - 1/5
work out 9/11 +5/11
work out 3/4 + 1/8
Answer:
4/5-1/5=6.0
9/11+5/11=1.27
3/4+1/8=0.875
Water flows through a pipe at a rate of 91 fluid ounces every 2.5 weeks. Express this rate of flow in cups per hour.
Answer:
\(Rate = 0.2167\ fl\ oz/hour\)
Step-by-step explanation:
Given
\(Rate = \frac{91\ fl\ oz}{2.5\ weeks}\)
Required
Express the rate as per hour
\(Rate = \frac{91\ fl\ oz}{2.5\ weeks}\)
There are 168 hours in a week;
So, the rate becomes
\(Rate = \frac{91\ fl\ oz}{2.5 * 168\ hours}\)
\(Rate = \frac{91\ fl\ oz}{420\ hours}\)
\(Rate = 0.2167\ fl\ oz/hour\)
Hence;
The equivalent of the given rate is \(0.2167\ fl\ oz/hour\)
the domain of f(x)= logb x is the set of all real numbers true or false pls need now
Answer: False
Step-by-step explanation:
The only number that makes this impossible to solve is x = 0
100 Points
Use geometry to evaluate the integral from negative 2 to 6 of f of x, dx where f of x equals the absolute value of x for x between negative 2 and 2 inclusive, equals 2 for x greater than 2 and less than or equal to 4, and equals negative x plus 4 for x greater than 4 and less than or equal to 6.
Answer:
\(\int\limits^{6}_{-2} {f(x)} \, dx=6\)
Step-by-step explanation:
Review the attached graph
By using geometry to evaluate the given integral, the value is equal to 6 units.
How to use geometry to evaluate an integral?In order to use a geometry to evaluate a definite integral, you should identify the portion of a graph which corresponds to the given integral.
Also, you'll mark out the geometric shapes that are formed on the graph, so as to enable you calculate their areas. Finally, you'll add the areas together.
From the graph of the integral shown in the image attached below, the geometric shapes that are formed are rectangle and triangles.
For the area of rectangle, we have:
Area of rectangle = L × B
Area of rectangle = 2 × 2
Area of rectangle = 4 units.
For the area of triangle, we have:
Area of triangle = 1/2 × b × h
Area of triangle = 1/2 × 2 × 2
Area of triangle = 2 units.
Total area = 4 + 2
Total area = 6 units.
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Describe the five-step procedure to graphing logarithmic functions in your own words.
A logarithm function is a function that uses the log keyword, and it is the opposite of an exponential function
The procedure to graph a logarithm functionAssume the logarithm function is:
\(y = a\log_b(x - h) + k\)
Where b represents the base of the function.
Step 1The first step is to determine the vertical asymptote of the function
The vertical asymptote of \(y = a\log_b(x - h) + k\) is:
\(x = h\)
Step 2The second step is to determine the x-intercepts
To do this, we set the function to 0
i.e. \(a\log_b(x - h) + k = 0\)
Step 3The next step is to determine the y-intercepts
To do this, we set the x to 0
i.e. \(y = a\log_b(0- h) + k\)
Step 4The next step is to plot the vertical asymptote, the intercepts and few points on the graph
Step 5Lastly the points that were plotted on the graph must be connected
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Hello please help willl give brainliest!
Answer:
It will take Wilson 50 minutes to paint this bookcase.
Step-by-step explanation:
40%=20 minutes
10%=5 minutes
100%=50 minutes
Hope this helped! :)
Which one of these are right??!?
Answer:
B. X
Step-by-step explanation:
the essential rule for a function is that each value of x must have exactly one associated y value.
in other words, if we "feed" the x- value to the function it must be clear what y-value we get as result.
in W 6 has 2 associated y values. no function.
in X all is OK. yes, a function.
in Y again, 6 has 2 associated y values. no function.
in Z 7 has 2 associated y values. no function.
Question 10
- 6x + 4y = -12
Answer 2/3y+2
Step-by-step explanation:
Answer:
divide y y by 1 1 . Divide 8 8 by 4 4 . Using the slope-intercept form, the slope is 0
Step-by-step explanation:
find a) average daily balance - new purchase b) finance charge c) new balance
Answer:
Step-by-step explanation:
Describe each of the following correlation coeffi cients using the terms strong, moderate, or weak and positive or negative. a. r = 0.17 b. r = –0.62 c. r = –0.88 d. r = 0.33 e. r = 0.49 f. r = –0.25 g. r = 0.91
Find the value of k so that the line going through the points A(2,7) and B(k, 5)
is parallel to the line y=12x-1
Answer:
Step-by-step explanation:
parallel line y=12x+c
put this point A(2,7)
7=12*2+c
c=-17
so the equation is y=12x-17
now put the point B
k=12*5-17
k=43
As the CAPS document outlines, the Content Specification and Content Clarification for Patterns, Functions, and Algebra shows sequenced mathematics content topics and a content area spread. In the Intermediate Phase, select one topic and report on the topic sequence and content area spread. Your report should demonstrate mathematics concepts and procedures’ hierarchical and logical progression.
Answer:
Step-by-step explanation:
In the Intermediate Phase of mathematics education, one topic that demonstrates a hierarchical and logical progression in patterns, functions, and algebra is the concept of "Linear Equations."
The topic of Linear Equations in the Intermediate Phase builds upon the foundation laid in earlier grades and serves as a stepping stone towards more advanced algebraic concepts. Here is an overview of the topic sequence and content area spread for Linear Equations:
Introduction to Variables and Expressions:
Students are introduced to the concept of variables and expressions, learning to represent unknown quantities using letters or symbols. They understand the difference between constants and variables and learn to evaluate expressions.
Solving One-Step Equations:
Students learn how to solve simple one-step equations involving addition, subtraction, multiplication, and division. They develop the skills to isolate the variable and find its value.
Solving Two-Step Equations:
Building upon the previous knowledge, students progress to solving two-step equations. They learn to perform multiple operations to isolate the variable and find its value.
Writing and Graphing Linear Equations:
Students explore the relationship between variables and learn to write linear equations in slope-intercept form (y = mx + b). They understand the meaning of slope and y-intercept and how they relate to the graph of a line.
Systems of Linear Equations:
Students are introduced to the concept of systems of linear equations, where multiple equations are solved simultaneously. They learn various methods such as substitution, elimination, and graphing to find the solution to the system.
Word Problems and Applications:
Students apply their understanding of linear equations to solve real-life word problems and situations. They learn to translate verbal descriptions into algebraic equations and solve them to find the unknown quantities.
The content area spread for Linear Equations includes concepts such as variables, expressions, equations, operations, graphing, slope, y-intercept, systems, and real-world applications. The progression from simple one-step equations to more complex systems of equations reflects a logical sequence that builds upon prior knowledge and skills.
By following this hierarchical progression, students develop a solid foundation in algebraic thinking and problem-solving skills. They learn to apply mathematical concepts and procedures in a systematic and logical manner, paving the way for further exploration of patterns, functions, and advanced algebraic topics in later phases of mathematics education.
What is the IQR for 10, 14, 15, 15, 16, 18, 19, 21
Answer:
15-18
Step-by-step explanation:
The IQR is the middle 50% of a set of numbers
There are 8 numbers, so its the middle 4
The middle 4 consists of 15,15,16,18
The range is 15-18
Three different design configurations are being considered for a particular component. There are two possible failure modes for the component. An engineer obtained the following data on the number of failures in each mode for each of the three configurations. Is there evidence to conclude that the configuration has an effect on the type of failure?
Failure Mode
1 2 3 4
Configuration 1 20 44 17 9
2 4 17 7 12
3 10 31 14 5
Answer:
No evidence .because the configurations factors and failure mode are independent
Step-by-step explanation:
Determine if there is sufficient evidence to conclude that configuration affects the type of failure
Number of configurations = 3
Number of failures = 4
assuming Pij represents proportion of items in pop i of the category j
H0 : Pij = Pi * Pj, I = 1,2,-- I, j = 1,2,---J
Hence the expected frequencies will be
16.10 , 43.58 , 18, 12.31
7.5, 19.37, 8 , 5.47
10.73, 29.05, 12, 8.21
x^2 = 13.25
test statistic = 14.44. Hence the significance level where Null hypothesis will be acceptable will be = 2.5%
I need help with #6!!
The probability of randomly drawing a 10 from the deck is:
P = 1/13
How to find the probability?We want to find the probability of randomly drawing a 10 from the deck.
Remember that there are 4 suits of 13 cards each, so thereare 52 cards in total and 4 of these cards are tens.
The probability of randomly drawing a 10 is equal to the quotient between the number of cards with a 10 on it (4 of these) and the total number of cards in the deck (52).
It is:
P = 4/52 = 1/13
That is the probability.
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Suppose we have a random sample of size n = 5 from a continuous uniform distribution on the interval [0, 1]. Find the probability that the third largest observation in the
sample is less than 0.7.
The probability that the third largest observation in the sample is less than 0.7 is 0.2401 = 24.01%.
How do we calculate?The sample size n = 5,
Therefore the order statistics will be represented as X₁, X₂, X₃, X₄, and X₅.
Probability that X₃ is less than 0.7:
Since X₃ is the third largest observation = (X₁ and X₂) < 0.7.
The probability that X₃ is less than 0.7 is (0.7)² = 0.49.
The Probability that X₁ and X₂ < or equal to 0.7 is found as:.
The probability that both X₁ and X₂ are less than or equal to 0.7 is (0.7)² = 0.49 because in a continuous uniform distribution, the probability of any single observation being less than 0.7 is 0.7 - 0 = 0.7.
We then get the product of both cases:
Probability = 0.49 * 0.49 = 0.2401
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Adam's age is 6 years less than one-third of Melissa's age. Adam's age is 18. How old is Melissa?
A. 12
B. 72
C. 36
D. 78
Answer:
B. 72
Step-by-step explanation:
Adam (A): 18
Melissa (M):?
\(A=\frac{m}{3} -6\)
\(18=\frac{m}{3} -6\)
\(24=\frac{m}{3}\)
\(m=4(3)=72\)
Therefore, Melissa is 72 years old.
Hope this helps!
Ms. Wong's class had 11 girls and 14 boys. What is the probability that a girl will get the infection first and then a boy ?
Answer: 25,67%
Step-by-step explanation:
We have 11 girls and 14 boys, this is a total of 11 + 14 = 25 students.
If all the students have the same probability of being infected, the probability that a girl will get infected first is equal to the number of girls dividedthe total number of students:
p1 = 11/25
Now we get a boy infected, the number of boys is 14, and the total number of students is now 24 (because we already have a girl infected)
this probability is p2 = 14/24
The probability for both events is equal to the product of the probabilities:
P = p1*p2 = (11/25)*(14/24) = 0.2567
or 25,67%
The equation C=24n+2 represents the cost
Jim did not buy any tickets (n_Jim = 0).
Larry bought 7 more tickets than Jim.
To determine the number of tickets Larry bought more than Jim, we need to find the values of n for Larry and Jim's ticket purchases.
For Larry:
Let's substitute C = $170 into the equation C = 24n + 2 and solve for n:
$170 = 24n + 2
Subtracting 2 from both sides:
$168 = 24n
Dividing both sides by 24:
n = 7
For Jim:
We can calculate the number of tickets Jim bought by subtracting 12 from Larry's number of tickets:
n_Jim = n_Larry - 12
n_Jim = 7 - 12
n_Jim = -5
Since we cannot have a negative number of tickets, we can conclude that Jim did not buy any tickets (n_Jim = 0).
To find the difference in the number of tickets bought, we subtract the number of tickets Jim bought from the number of tickets Larry bought:
n_difference = n_Larry - n_Jim
n_difference = 7 - 0
n_difference = 7
Therefore, Larry bought 7 more tickets than Jim.
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Question
The equation C=24n+2 represents the cost, C, in dollars, of buying n tickets to a play. J $170. How many more tickets did Larry buy than Jim? 12
A thermometer reading 10°C is brought into a room with a constant temperature of 36°C. if the thermometer reads 14°C after 2 minutes, what will it read after beint left in the room for 4 minutes? and for 9 minutes?
Answer:
4 minutes: 17.4 °C9 minutes: 23.7 °CStep-by-step explanation:
You want to know a thermometer's reading 4 minutes and 9 minutes after begin brought into a room with a temperature of 36 °C if its initial reading is 10 °C, and it rises to 14 °C after 2 minutes.
Newton's law of coolingNewton's law of cooling tells you the temperature difference of 36 -10 = 26 °C will decline exponentially. If it declines to 36 -14 = 22 °C after 2 minutes, then the temperature reading can be modeled by ...
T = 36 -26·(22/26)^(t/2)
At times of t=4 and t=9, the temperature readings will be ...
4 minutes: 36 -26(11/13)^(4/2) ≈ 17.4 °C9 minutes: 36 -26(11/13)^(9/2) ≈ 23.7 °C__
Additional comment
The time constant of this thermometer is about 12 minutes, so it will take about 67 minutes to read within 0.1 °C of the room temperature.
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Find the binomial coefficient:200/1
Answer:
1/200????????????????
Step-by-step explanation:
Please help with this 1-3
Answer:
1 is a
2 is c
3 is b
Step-by-step explanation:
Rotation - Question 5
When the former image is rotated, the dots will be located at section 2 and 7.
What is the effects of image rotation?When an image is rotated, the constituents within it also changes its position as the object is moves from a point to another about a pivot junction.
From the given image above, after the rotation of the initial image, the dot should be located at number 2 and 7 of the new image.
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WHAT IS THE EXPERIMENTAL PROBABILTY THAT THE HIGH TEMPATURE ON THE NEXT JUNE 23RD
IS OVER 75 DEGREES
It should be noted that experimental probability is based on past observations and might not accurately predict future events.
How should we calculate the experimental probability of temperature on the next June 23rd?It has been established that experimental probability is based on past observations or on historical data.
To determine the experimental probability of the high temperature being over 75 degrees on June 23rd, one would basically gather historical data of high temperatures on June 23rd from previous years. Then, one would calculate the proportion of times the temperature was over 75 degrees.
For example, if one had data for the past 10 years and on 7 of those years the temperature was over 75 degrees on June 23rd, the experimental probability would be 7/10 or 0.7 (or 70%).
Therefore, it's always a good idea to consult meteorological sources or weather forecasts for the most up-to-date and accurate information.
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Solve the initial value problem yy' + x = x2 + y2 with y(3) = -V40. a. To solve this, we should use the substitution help (formulas) U = u' = help (formulas) Enter derivatives using prime notation (e.g., you would enter y' for dy dx b. After the substitution from the previous part, we obtain the following linear differential equation in x, u, u'. help (equations) c. The solution to the original initial value problem is described by the following equation in x, y. help (equations)
The final solution for the initial value problem: y = −e∫x dx√40 − ∫x2e∫x dx − ∫y2e∫x dx.
The given initial value problem is yy′+x=x2+y2 with y(3) = −√40. To solve this we make the substitution U = u' and u = y. This transforms the given equation into the linear differential equation in x, u, and u': u'+xu=x2+u2. To solve this, we can use the integrating factor method. Multiplying both sides by the integrating factor e∫x dx gives us u'e∫x dx + xue∫x dx = x2e∫x dx + u2e∫x dx. Taking the integral of both sides, we obtain ue∫x dx = ∫x2e∫x dx + ∫u2e∫x dx + c, where c is the constant of integration. Solving for u, we have u = c/e∫x dx − ∫x2e∫x dx − ∫u2e∫x dx. Using the fact that u = y, we can substitute this expression into the equation to obtain the solution in terms of x and y: y = (c/e∫x dx) − ∫x2e∫x dx − ∫y2e∫x dx. Using the initial condition y(3) = −√40, we can solve for c to get c = −e∫3 dx√40. Substituting this into the solution, we get the final solution for the initial value problem: y = −e∫x dx√40 − ∫x2e∫x dx − ∫y2e∫x dx.
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During your journey, you develop an abscessed tooth and have to visit the dentist. You are prescribed an antibiotic with a dosage of 7.5 mg/kg every six hours. If you weigh 128 pounds and the antibiotic comes in 250 mg tablets, how many tablets should you take each day?
Answer:
I should take 10.44 tablets in a day, approximately 10.5 tablets.
Step-by-step explanation:
In order to solve this problem we need to convert the weight from pounds to kilograms, to do that we need to divide it by 2.205.
\(w = \frac{128}{2.205}\\w = 58.05 \text{ kg}\)
Since I need to take 7.5 mg per kg of body weight, then in order to find the dosage we need to multiply the weight in kg by 7.5.
\(\text{dosage} = 58*7.5 = 435 \text{ mg}\)
Since I need to take it every six hours and there are 24 hours in a day, we will have to take 4 dosages in a day, therefore we need:
\(\text{dosage(day)} = 435*6 = 2,610 \text{ mg}\)
The antibiotic comes in 250 mg in tablets, therefore the number of tablets is:
\(tablets = \frac{2610}{250} = 10.44\)
I should take 10.44 tablets in a day, approximately 10.5 tablets.