Robert is currently working for a landscaping company earning $1520 per month. he has a dream of starting his own landscaping company and figures he would need to save $5000 to buy his own equipment. select the budget that would help robert most quickly achieve his financial goal of starting his own business, while still meeting his basic needs. monthly budget budget a budget b budget c budget d income $1520 $1520 $1520 $1600 expenses rent utilities food cell phone savings entertainment clothing $400 $80 $250 $0 $400 $220 $130 $400 $80 $25 $75 $600 $320 $0 $400 $80 $150 $70 $500 $125 $120 $400 $80 $400 $110 $260 $200 $150 net income $40 $20 $75 $0 a. budget a b. budget b c. budget c d. budget d
Answers
The budget with the highest savings amount that still meets Robert's basic needs is Budget C. The answer is C. Budget C
To determine which budget would help Robert most quickly achieve his financial goal of starting his own landscaping business, we need to compare the savings amounts in each budget.
Budget A:
Income: $1520
Expenses: Rent ($400), Utilities ($80), Food ($250), Cell Phone ($0), Savings ($400), Entertainment ($220), Clothing ($130)
Net Income: $40
Budget B:
Income: $1520
Expenses: Rent ($400), Utilities ($80), Food ($250), Cell Phone ($75), Savings ($600), Entertainment ($320), Clothing ($0)
Net Income: $20
Budget C:
Income: $1520
Expenses: Rent ($400), Utilities ($80), Food ($150), Cell Phone ($70), Savings ($500), Entertainment ($125), Clothing ($120)
Net Income: $75
Budget D:
Income: $1600
Expenses: Rent ($400), Utilities ($80), Food ($400), Cell Phone ($110), Savings ($260), Entertainment ($200), Clothing ($150)
Net Income: $0
In Budget C, Robert can save $500 per month while still covering his expenses for rent, utilities, food, cell phone, entertainment, and clothing. Additionally, this budget has a positive net income of $75, indicating that it is sustainable.
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Related Questions
Use a Maclaurin series derived in this section to obtain the Maclaurin series for the given functions. Enter the first 3 non-zero terms only.
f(x) = cos(5x2) =______+...
f(x) = sin(-pix) =______+...
f(x) = xtan-1(5x) =_____+...
f(x) = x2e-x/2 =______+...
Answers
Suppose that the daily log return of a security follows the model rt = 0.02 +0.5rt-2 + et where {e} is a Gaussian white noise series with mean zero and variance0.02. What are the mean and variance of the return series rt? Compute the lag-1 and lag-2 autocorrelations of rt. Assume that r100 = -0.01, and r99 = 0.02. Compute the 1- and 2-step-ahead forecasts of the return series at the forecast origin t = 100. What are the associated standard deviation of the forecast errors?
Answers
Mean of rt = 0.02,
Variance of rt = 0.02,
Lag-1 Autocorrelation (ρ1) = -0.01,
Lag-2 Autocorrelation (ρ2) = Unknown,
1-step ahead forecast = -0.005,
2-step ahead forecast = 0.02,
The standard deviation of forecast errors = √0.02.
We have,
To find the mean and variance of the return series, we can substitute the given model into the equation and calculate:
Mean of rt:
E(rt) = E(0.02 + 0.5rt-2 + et)
= 0.02 + 0.5E(rt-2) + E(et)
= 0.02 + 0.5 * 0 + 0
= 0.02
The variance of rt:
Var(rt) = Var(0.02 + 0.5rt-2 + et)
= Var(et) (since the term 0.5rt-2 does not contribute to the variance)
= 0.02
The mean of the return series rt is 0.02, and the variance is 0.02.
To compute the lag-1 and lag-2 autocorrelations of rt, we need to determine the correlation between rt and rt-1, and between rt and rt-2:
Lag-1 Autocorrelation:
ρ(1) = Cov(rt, rt-1) / (σ(rt) * σ(rt-1))
Lag-2 Autocorrelation:
ρ(2) = Cov(rt, rt-2) / (σ(rt) * σ(rt-2))
Since we are given r100 = -0.01 and r99 = 0.02, we can substitute these values into the equations:
Lag-1 Autocorrelation:
ρ(1) = Cov(rt, rt-1) / (σ(rt) * σ(rt-1))
= Cov(r100, r99) / (σ(r100) * σ(r99))
= Cov(-0.01, 0.02) / (σ(r100) * σ(r99))
Lag-2 Autocorrelation:
ρ(2) = Cov(rt, rt-2) / (σ(rt) * σ(rt-2))
= Cov(r100, r98) / (σ(r100) * σ(r98))
To compute the 1- and 2-step-ahead forecasts of the return series at
t = 100, we use the given model:
1-step ahead forecast:
E(rt+1 | r100, r99) = E(0.02 + 0.5rt-1 + et+1 | r100, r99)
= 0.02 + 0.5r100
2-step ahead forecast:
E(rt+2 | r100, r99) = E(0.02 + 0.5rt | r100, r99)
= 0.02 + 0.5E(rt | r100, r99)
= 0.02 + 0.5(0.02 + 0.5r100)
The associated standard deviation of the forecast errors can be calculated as the square root of the variance of the return series, which is given as 0.02.
Thus,
Mean of rt = 0.02,
Variance of rt = 0.02,
Lag-1 Autocorrelation (ρ1) = -0.01,
Lag-2 Autocorrelation (ρ2) = Unknown,
1-step ahead forecast = -0.005,
2-step ahead forecast = 0.02,
The standard deviation of forecast errors = √0.02.
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Find the volume of the solid lying under the circular paraboloid z = x2 + y2 and above the rectangle R = (-4,4] x [-6,6). 1. 2496 2. 1664 3. 1248 4. 960 5. 640
Answers
According to the question we have the correct answer is option 2, with a volume of 1664 cubic units.
The volume of the solid lying under the circular paraboloid z = x^2 + y^2 and above the rectangle R = (-4, 4] x [-6, 6] can be found using a double integral. First, set up the integral with respect to x and y over the given rectangular region:
Volume = ∬(x^2 + y^2) dA
To evaluate this integral, we will use the limits of integration for x from -4 to 4, and for y from -6 to 6:
Volume = ∫(from -4 to 4) ∫(from -6 to 6) (x^2 + y^2) dy dx
Now, integrate with respect to y:
Volume = ∫(from -4 to 4) [(y^3)/3 + y*(x^2)](from -6 to 6) dx
Evaluate the integral at the limits of integration for y:
Volume = ∫(from -4 to 4) [72 + 12x^2] dx
Next, integrate with respect to x:
Volume = [(4x^3)/3 + 4x*(72)](from -4 to 4)
Evaluate the integral at the limits of integration for x:
Volume = 1664
Therefore, the correct answer is option 2, with a volume of 1664 cubic units.
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1.-40/2 D
(10 Points)
N
W
Z
R
Answers
Answer:
-40/2 is equal to -20
Step-by-step explanation:
still dont kno what n w z r means
A plane can fly 640 miles in the same time as it takes a car to go 240 miles. If the car travels 100 mph slower than the plane, find the speed (in mph) of the plane.
Answers
Answer:
Let s be the speed of the plane. Then s - 100 is the speed of the car.
640/s = 240/(s - 100)
640(s - 100) = 240s
8(s - 100) = 3s
8s - 800 = 3s
5s = 800, so s = 160 mph
The speed of the plane is 160 mph, and the speed of the car is 60 mph.
the product of a number and 3
as an expression
Answers
Answer:
3x
Step-by-step explanation:
Let the number be 'x'
The product of a number and 3 = 3*x = 3x
Answer:
3x
.................
An electron has a normalized wavefunction
ψ(x)=
a
5
30
[(a/2)
2
−x
2
]
ψ(x)=0
−a/2
x≤−a/2,x>a/2
which is not an eigenfunction of the kinetic energy operator. Part A Find the expectation value of the kinetic energy in terms of the constant a. Express your answer in terms of a, reduced Plank's constant ℏ, and electron rest mass m
e
.
Answers
The expectation value of the kinetic energy, <T>, in terms of the constant a, reduced Planck's constant ℏ, and electron rest mass \(m_e\), is <T> = (ℏ²/2\(m_e\)) * a².
To find the expectation value of the kinetic energy, we first need to determine the kinetic energy operator and then calculate the integral of the wavefunction multiplied by the kinetic energy operator.
The kinetic energy operator, T, is defined as:
T = -(ℏ²/2\(m_e\)) * (d²/dx²),
where ℏ is the reduced Planck's constant and \(m_e\) is the electron rest mass.
The expectation value of the kinetic energy, <T>, is given by:
<T> = ∫ ψ*(x) * T * ψ(x) dx,
where ψ*(x) represents the complex conjugate of ψ(x).
Let's calculate the expectation value:
<T> = ∫ ψ*(x) * [-(ℏ²/2\(m_e\)) * (d²/dx²)] * ψ(x) dx,
Considering the given wavefunction, ψ(x), has different definitions for different x ranges, we need to split the integral into three parts:
For x ≤ -a/2:
<T> = ∫ ψ*(x) * [-(ℏ²/2\(m_e\)) * (d²/dx²)] * ψ(x) dx
= ∫ [0] * [-(ℏ²/2\(m_e\)) * (d²/dx²)] * [0] dx
= 0,
as ψ(x) = 0 for x ≤ -a/2.
For -a/2 < x < a/2:
<T> = ∫ ψ*(x) * [-(ℏ²/2\(m_e\)) * (d²/dx²)] * ψ(x) dx
= ∫ [(a/5)² - x²] * [-(ℏ²/2\(m_e\)) * (d²/dx²)] * [(a/5)² - x²] dx
= ∫ [-(a²/25) + x²] * [-(ℏ²/2\(m_e\)) * (-2)] dx
= (ℏ²/2\(m_e\)) * ∫ [(a²/25) - x²] dx
= (ℏ²/2\(m_e\)) * [ (a²/25)x - (x³/3) ] ∣ from -a/2 to a/2
= (ℏ²/2\(m_e\)) * [ (a³/75) - (a³/3 - a³/75) ]
= (ℏ²/2\(m_e\)) * [ (a³/75) + (74a³/75) ]
= (ℏ²/2\(m_e\)) * (75a³/75)
= (ℏ²/2\(m_e\)) * (a³/a)
= (ℏ²/2\(m_e\)) * a²,
as the terms with x vanish after integrating.
For x ≥ a/2:
<T> = ∫ ψ*(x) * [-(ℏ²/2\(m_e\)) * (d²/dx²)] * ψ(x) dx
= ∫ [0] * [-(ℏ²/2\(m_e\)) * (d²/dx²)] * [0] dx
= 0,
as ψ(x) = 0 for x ≥ a/2.
Therefore, the expectation value of the kinetic energy, <T>, in terms of the constant a, reduced Planck's constant ℏ, and electron rest mass \(m_e\), is:
<T> = (ℏ²/2\(m_e\)) * a².
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Water flows through a pipe at a rate of 89 cups per second. Express this rate of flow in gallons per hour
Answers
Answer:
Step-by-step explanation:
that sucks
Answer:
Answer: 20025 gallons per hour
89 times 60= 5340 cups in one minute
5340 times 60= 320,400 cups in one hour
Convert 320,400 cups into gallons and you will get 20025.
Not positive if this is correct but it’s better than nothing lol
Collete mapped her vegetable garden on the graph below. Each unit represents 1 foot. Collete plants an 8-foot row of lettuce in the garden. Which points could tell where the row of lettuce starts and ends?
Answers
Answer:
(-4,-1) and (-4,7)
Step-by-step explanation:
If Collete planted a row of lettuce, that means their coordinates must have the same vertical coordinate, or the same horizontal coordinate. Another important characteristic is that between those points, there must have 8 units of separation, because it's an 8-foot row.
please help mee
i’ve been on this for so long
Answers
Angle PQ = Angle RQ
Line PQ = Line QR
(some added things because mathswatch likes them!!)
Activity 3.1.12. Let the polynomial maps S:P→P and T:P→P be defined by S(f(x))=(f(x)) 2
T(f(x))=3xf(x 2
) (a) Note that S(0)=0 and T(0)=0. So instead, show that S(x+1)
=S(x)+S(1) to verify that S is not linear. (b) Prove that T is linear by verifying that T(f(x)+g(x))=T(f(x))+T(g(x)) and T(cf(x))=cT(f(x))
Answers
(a) S is not linear because S(x+1) ≠ S(x) + S(1).
(b) T is linear because it satisfies additivity and homogeneity: T(f(x) + g(x)) = T(f(x)) + T(g(x)) and T(cf(x)) = cT(f(x)).
(a) To show that S is not linear, we need to demonstrate that it does not satisfy the property of additivity.
Let's consider S(x+1):
S(x+1) = (x+1)² = x² + 2x + 1
Now let's evaluate S(x) + S(1):
S(x) + S(1) = x² + 2x + 1 + 1 = x² + 2x + 2
We can see that S(x+1) ≠ S(x) + S(1) since x² + 2x + 1 is not equal to x² + 2x + 2.
Therefore, S is not linear.
(b) To prove that T is linear, we need to verify that it satisfies the properties of additivity and homogeneity.
1. Additivity:
For any polynomials f(x) and g(x), we need to show that T(f(x) + g(x)) = T(f(x)) + T(g(x)).
Let's evaluate T(f(x) + g(x)):
T(f(x) + g(x)) = 3x(f(x) + g(x))²
= 3x(f(x)² + 2f(x)g(x) + g(x)²)
= 3xf(x)² + 6xf(x)g(x) + 3xg(x)²
Now let's evaluate T(f(x)) + T(g(x)):
T(f(x)) + T(g(x)) = 3xf(x)² + 3xg(x)²
We can see that T(f(x) + g(x)) = T(f(x)) + T(g(x)), which satisfies additivity.
2. Homogeneity:
For any polynomial f(x) and constant c, we need to show that T(cf(x)) = cT(f(x)).
Let's evaluate T(cf(x)):
T(cf(x)) = 3x(cf(x))²
= 3xc²f(x)²
= c²(3xf(x)²)
Now let's evaluate cT(f(x)):
cT(f(x)) = c(3xf(x)²)
We can see that T(cf(x)) = cT(f(x)), which satisfies homogeneity.
Therefore, T is linear.
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Which of these expressions is equal to 1?
3/4 + 2/3 + 1/2
2/8 + 1/4 + 1/2
1/4 + 1/2
5/3 + 1/6 + 1/3
Answers
Answer: 2/8+1/4+1/2
Step-by-step explanation: I think the correct answer is 2/8+1/4+1/2, because 3/4+2/3+1/2=1 11/12. 1/4+1/2=3/4. 5/3+1/6+1/3=2 1/6.
A sample of 3500 cakes sold recently in a bakery gave the mean price of cakes equal to RM60.80. The population standard deviation of the prices of cakes in this bakery is RM4.50. Construct a 95% confidence interval for the mean price of all cakes in this bakery.
Answers
The 95% confidence interval for the mean price of all cakes in the bakery is RM60.16 to RM61.44.
To construct a confidence interval for the mean price of all cakes in the bakery, we can use the formula:
Confidence Interval = Sample Mean ± Margin of Error
First, we calculate the margin of error using the formula:
Margin of Error = (Z * Standard Deviation) / sqrt(n)
Where Z is the critical value for the desired confidence level (95% confidence corresponds to a Z-value of approximately 1.96), Standard Deviation is the population standard deviation, and n is the sample size.
Substituting the given values:
Z = 1.96
Standard Deviation = RM4.50
Sample Size (n) = 3500
We can calculate the margin of error:
Margin of Error = (1.96 * 4.50) / sqrt(3500) ≈ 0.486
Next, we construct the confidence interval:
Confidence Interval = Sample Mean ± Margin of Error
Sample Mean = RM60.80
Confidence Interval = 60.80 ± 0.486
Therefore, the 95% confidence interval for the mean price of all cakes in the bakery is approximately RM60.16 to RM61.44. This means that we are 95% confident that the true population mean falls within this range.
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Solve.
−0.65p − 4 = 0.35p
The solution is p =
Answers
Answer:
Step-by-step explanation:
Solution,
p=-4
If you found my answer useful then please mark me brainliest.
6c=2(3c-4)+2c
what is the step by step solution to this equation
Answers
i'll do it step-by-step here. if there's any step that doesn't make sense, feel free to let me know!
6c = 2(3c-4) + 2c
distribute the 2 among the terms in the parentheses first.
6c = 6c - 8 + 2c
because both sides have 6c, we can cancel them out. 6c - 6c = 0.
0 = -8 + 2c
move the 8 to the other side (+8 to both sides).
8 = 2c
divide both sides by 2.
8/2 = c
therefore, 4 = c.
hope i helped! good luck.
The common ratio of a geometric series is \dfrac14 4 1 start fraction, 1, divided by, 4, end fraction and the sum of the first 444 terms is 170170170.
Answers
Answer:
The common ratio of a geometric series is \dfrac14
4
1
start fraction, 1, divided by, 4, end fraction and the sum of the first 4 terms is 170
The first term is 128
Step-by-step explanation:
The common ratio of the geometric series is given as:
\(r = \frac{1}{4}\)
The sum of the first 4 term is 170.
The sum of first n terms of a geometric sequence is given b;
\(s_n=\frac{a_1(1-r^n)}{1-r}\)
common ratio, n=4 and equate to 170.
\(\frac{a_1(1-( \frac{1}{4} )^4)}{1- \frac{1}{4} } = 170\)
\(\frac{a_1(1- \frac{1}{256} )}{ \frac{3}{4} } = 170\\\\ \frac{255}{256} a_1 = \frac{3}{4} \times 170\\\\\frac{255}{256} a_1 = \frac{255}{2} \\\\\frac{1}{256} a_1 = \frac{1}{2} \\\\ a_1 = \frac{1}{2} \times 256\\\\a_1 = \frac{1}{2} \times 256 \\\\= 128\)
Answer:
The first term is 128
The longevity of people living in a certain region is normally distributed with a standard
deviation of 14 years. What is the mean longevity in years if 30% of the people live longer
than 75 years?
Answers
The mean longevity of people in the region is approximately 82.336 years, as calculated by finding the z-score corresponding to the 30th percentile and using the formula for a normal distribution.
Given that the longevity of people in the region is normally distributed with a standard deviation of 14 years, we can determine the mean longevity by finding the z-score corresponding to the 30th percentile.
To find the z-score, we look up the corresponding value in the standard normal distribution table. The 30th percentile corresponds to a z-score of approximately -0.524.
Using the formula for a normal distribution:
z = (x - μ) / σ
Where z is the z-score, x is the value, μ is the mean, and σ is the standard deviation.
Rearranging the formula to solve for the mean, we have:
μ = x - (z * σ)
Substituting the known values, we get:
μ = 75 - (-0.524 * 14)
μ ≈ 75 + 7.336
μ ≈ 82.336
Therefore, the mean longevity of people in the region is approximately 82.336 years.
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explain how the input impedance effects the drain current. Use the standard component and calculated bias point values to prove your answer
Answers
The drain current of a device affects its input impedance.
When using a high input impedance, the drain current also tends to be high. Conversely, a low input impedance leads to a low drain current. In the context of a FET amplifier circuit, the input impedance plays a crucial role in determining the circuit's overall gain and stability. It is defined as the ratio of the voltage across the input port to the current flowing through it. Typically, the input impedance of an amplifier circuit is designed to be very high. This design choice offers several benefits such as reduced susceptibility to external noise and the ability to provide a stable input signal, resulting in a high gain. To demonstrate the effect of input impedance on drain current, we can use standard component values and calculated bias points. Considering the given values for components (R1, R2, RD, RS) and voltage values (VDD, VP), the calculated IDQ is 2.65 mA. The resulting input impedance is 4.62 kohms, which is higher than the combined resistance of R1 and R2 in series.
Therefore, we can summarize that the input impedance is high.
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use the limit comparison test to determine whether the following series converge or diverge. a) [infinity]Σn=3 5n/7+n²
b) [infinity]Σn=1 ln(n)²/n²
c) [infinity]Σn=1 2^n/4^n-n²
d) [infinity]Σn=1 sin (1/n)/n
Answers
(a) As this limit is finite and positive, the series is said to converge.
(b) As this limit is finite and positive, the series is said to converge.
(c) The numerator tends to infinity faster than the denominator, so we can say that the series diverges.
(d) As this limit is finite and positive, the series is said to converge.
(a) Use the limit comparison test to determine whether the following series converge or diverge:
$$\sum_{n=3}^\infty \frac{5n}{7+n^2}$$We have that:$$\lim_{n \to \infty} \frac{\frac{5n}{7+n^2}}{\frac{1}{n}} = \lim_{n \to \infty} \frac{5n^2}{7+n^2} = 5$$
As this limit is finite and positive, the series is said to converge.
(b) Use the limit comparison test to determine whether the following series converge or diverge:
$$\sum_{n=1}^\infty \frac{\ln^2 n}{n^2}$$We have that:$$\lim_{n \to \infty} \frac{\frac{\ln^2 n}{n^2}}{\frac{1}{n}} = \lim_{n \to \infty} \frac{\ln^2 n}{n} = 0$$
As this limit is finite and positive, the series is said to converge.
(c) Use the limit comparison test to determine whether the following series converge or diverge:
$$\sum_{n=1}^\infty \frac{2^n}{4^{n-n^2}}$$We have that:$$\lim_{n \to \infty} \frac{\frac{2^n}{4^{n-n^2}}}{\frac{1}{n}} = \lim_{n \to \infty} \frac{n2^n}{4^{n-n^2}}$$
The numerator tends to infinity faster than the denominator, so we can say that the series diverges.
(d) Use the limit comparison test to determine whether the following series converge or diverge:
$$\sum_{n=1}^\infty \frac{\sin(1/n)}{n}$$We have that:$$\lim_{n \to \infty} \frac{\frac{\sin(1/n)}{n}}{\frac{1}{n}} = \lim_{n \to \infty} \sin\left(\frac{1}{n}\right) = 0$$
As this limit is finite and positive, the series is said to converge.
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Olivia drives 35 mph for 7.2 hours. How far does she get?
Answers
she goes 252 miles.
What is multiplication?In mathematics, multiplication is a method of finding the product of two or more numbers. It is one of the basic arithmetic operations, that we use in everyday life.
here, we have,
given that,
Olivia drives 35 mph for 7.2 hours
i.e. she go = 35*7.2
=252miles.
hence, she goes 252 miles.
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Find the elasticity of demand for the demand function D(p)=60-8p
and determine whether the demand is elastic, inelastic or
unit-elastic at the given price p=5?
Answers
The elasticity of demand for the demand function D(p) = 60 - 8p at p = 5 is -2. Elasticity of demand is a measure of how responsive quantity demanded is to a change in price.
Mathematically, it is the ratio of the percentage change in quantity demanded to the percentage change in price, holding all other factors constant. Given the demand function D(p) = 60 - 8p, where ΔQd is the change in quantity demanded, Qd is the original quantity demanded, ΔP is the change in price, and P is the original price. To determine whether the demand is elastic, inelastic, or unit-elastic at a given price p, we compare the absolute value of the elasticity of demand to 1. If it is greater than 1, the demand is elastic; if it is less than 1, the demand is inelastic; and if it is exactly 1, the demand is unit-elastic.
This means that a 1% increase in price will lead to a greater than 1% decrease in quantity demanded, and vice versa. Mathematically, it is the ratio of the percentage change in quantity demanded to the percentage change in price, holding all other factors constant. Given the demand function D(p) = 60 - 8p, where ΔQd is the change in quantity demanded, Qd is the original quantity demanded, ΔP is the change in price, and P is the original price. To determine whether the demand is elastic, inelastic, or unit-elastic at a given price p, we compare the absolute value of the elasticity of demand to 1.
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In Exercises 8-10, sketch the figure described.
8. plane A and line c intersecting at all points on line c
9. GM and GH
10. line CD and plane X not intersecting
Answers
The sketch answers to question 8, 9 and 10 is given in the image attached.
What is an intersecting lines?A link is known to be intersecting if two or more lines are said to have cross one another in a given plane.
Note that the intersecting lines are known to be one that often share a common point, and it is one that can be seen on all the intersecting lines, and it is known to be the point of intersection.
Looking at the image attached, you can see how plane A and line c intersecting at all points on line c and also GM and GH and line CD and plane X as they are not intersecting
Therefore, The sketch answers to question 8, 9 and 10 is given in the image attached.
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The number of students in a chess club decreased from 17 to 10. What is
the percent decrease?
There are 3 answers
Answers
Answer:
41.18%Step-by-step explanation:
Initial number = 17Final number = 10Decrease in number:
17 - 10 = 7Percent decrease:
7/17*100% = 41.18% (rounded)What is the correct answer need answer ASAP
Answers
Help please!! Directions: Transform the following equations into standard form.
1. x² + 2x=-1
2.4+x²= 7x
3.x²-x=1
4. x² + 9x = 10
5.4x + 3 = x²
6.x2+5x+5
7.2x5 + 7x= 3x
8. x² = 3x+8
9. x(x + 3) = 1
10.x²-3x = -2
Answers
BRAINLEST IF CORRECT!!!!!!!
Answers
Answer:\(\huge \boxed{x=180-26-90=64}\)
Step-by-step explanation:
Answer:
Step-by-step explanation:
You have the angels 180, 26, 90(right angle) and x. So when you add them all up you should get 360 because there aren’t two straight lines. Only line makes a 180 angle. So...
180 + 26 + 90 + x = 360
296 + x = 360
x = 360 - 296
x = 64
25 Points!
Which of the following relations describes a function?
{ (2, -2), (0, 0), (2, 2), (3, 3) }
B.
{ (-3, 9), (-2, 4), (2, 4), (3, 9) }
C.
{ (-2, 0), (0, 2), (2, 0), (0, -2) }
D.
{ (9, -3), (4, -2), (4, 2), (9, 3) }
Answers
Hello! My name is Chris and I’ll be helping you with this problem.
Date: 9/28/20 Time: 11:59 CST
Answer:
B: { (-3, 9), (-2, 4), (2, 4), (3, 9) }
Explanation:
This shows a function because, for each x value, there is not another x value of the same number
I hope this helped answer your question! Have a great rest of your day!
Furthermore,
Chris
Please help.
Algebra.
Answers
Answer:
The answer is sometimes.
If the two lines have the same slope, then there will be 0 solutions, and if the two lines are the same, then there will be infinite solutions.
Hope this helps!
a hospital administrator is interested to compare the average hospital stay at three hospitals in a certain city. the administrator collects random data for the length of hospital stay (in days) for the three hospitals. the administrator is interested to know if the average hospital stays are statistically the same for the three hospitals. use a significance level of 5%. the administrator has confirmed that the samples were randomly selected and independent, and the populations have normal distribution and the population variances are equal.
Answers
To determine if the average hospital stays are statistically the same for the three hospitals, a statistical test called ANOVA (Analysis of Variance) can be used. With a significance level of 5%, the null hypothesis is that the means of the three hospital stays are equal, while the alternative hypothesis is that at least one mean is different.
In this scenario, the administrator collects random data for the length of hospital stay from three hospitals in the city. Since the samples were randomly selected and independent, and the populations have normal distribution with equal variances, the conditions for performing an ANOVA test are satisfied.
ANOVA allows for comparing the means of multiple groups simultaneously. By conducting an ANOVA test, the administrator can determine if there are statistically significant differences among the average hospital stays in the three hospitals.
The test will calculate the F-statistic, which is the ratio of the between-group variability to the within-group variability. If the calculated F-statistic exceeds the critical value at the 5% significance level, it indicates that there are significant differences among the means.
If the ANOVA test results in rejecting the null hypothesis, indicating significant differences among the average hospital stays, the administrator can proceed with post-hoc tests to identify which specific hospital means differ from each other.
Overall, by utilizing the ANOVA test with the provided conditions and a significance level of 5%, the hospital administrator can determine if the average hospital stays are statistically the same or if there are significant differences among the three hospitals.
Learn more about variability here:
brainly.com/question/29583350
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-4/7p+ (-2/7p)+1/7? I need help on my assignment please :)
Answers
Answer:
-6p-1/7
Step-by-step explanation: