Rihanna swims everyday. she Burns approximately 10.6 calories per minute when swimming and about 15 calories warming up before she swims. right and equation to find out how many minutes Rihanna must swim to burn 205.8 calories.

Answer: 216.2 + 48.75 = 264.95

Step-by-step explanation:

Multiply the amount of sandwiches by the cost.

47 * 4.60 = 216.2

Multiply the amount of chips by the cost.

39 * 1.25 = 48.75

Add them the totals together.

216.2 + 48.75 = 264.95

Answer:

Step-by-step explanation:

The money is worth approximately $8,806 today, rounded to the nearest dollar.

To calculate the present value of the money, we need to discount the future cash flows using the interest rate. In this case, the interest rate is 5%.

First, let's calculate the present value of receiving $5,000 at the end of four years. We'll use the formula for present value:

PV = FV / (1 + r)^n

where PV is the present value, FV is the future value, r is the interest rate, and n is the number of years.

PV1 = 5000 / (1 + 0.05)^4

Simplifying the equation:

PV1 = 5000 / (1.05)^4

PV1 = 5000 / 1.2155

PV1 ≈ 4113.23

Next, let's calculate the present value of receiving $6,000 at the end of five years:

PV2 = 6000 / (1 + 0.05)^5

Simplifying the equation:

PV2 = 6000 / (1.05)^5

PV2 = 6000 / 1.2763

PV2 ≈ 4692.84

Finally, we can find the present value of the money by adding PV1 and PV2:

Present value = PV1 + PV2

Present value ≈ 4113.23 + 4692.84

Present value ≈ 8806.07

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Answer:

First system: no solution

Second system: one solution

Third system: one solution

Fourth system: infinite solutions

Fifth system: no solution

Step-by-step explanation:

First system: 3x-2y=3; 6x-4y=1

From the first equation: y = (3x - 3)/2

Using this value of y in the second equation:

6x - 6x + 6 = 1

6 = 1 -> System has no solution

Second system: 3x-5y=8; 5x-3y=2

From the first equation: x = (8 + 5y)/3

Using this value of x in the second equation:

5*(8 + 5y) - 9y = 6

40 + 25y - 9y = 6

16y = -34 -> y = -2.125

x = (8 - 5*2.125)/3 = -0.875

This system has one solution

Third system: 3x-2y=8; 4x-3y=1

 From the first equation: x = (8 + 2y)/3

Using this value of x in the second equation:

4*(8 + 2y) - 9y = 3

32 + 8y - 9y = 6

y = 26

x = (8 + 2*26)/3 = 20

This system has one solution

Fourth system: 3x-6y=3; 2x-4y=2

  From the first equation: x = 1 + 2y

Using this value of x in the second equation:

2*(1 + 2y) - 4y = 2

2 + 4y - 4y = 2

2 = 2

This system has infinite solutions

Fifth system: 3x-4y=2; 6x-8y=1

  From the first equation: x = (2 + 4y)/3

Using this value of x in the second equation:

2*(2 + 4y) - 8y = 1

4 + 8y - 8y = 2

4 = 2

This system has no solution

Answer:

-18 + 3k

3k - 6

24k - 48

Step-by-step explanation:

thats just to name a few of the infinite possibilites

Step-by-step explanation:

\( \implies \sf{(x - 1) {}^{2} + (x + 1)(x - 1)} \\ \implies \sf{x}^{2} + {(1)}^{2} - 2(x)(1) + {x}^{2} - {(1)}^{2 } \\ \implies \sf {x}^{2} + 1 - 2x + {x}^{2} - 1 \\ \implies \red{\sf 2 {x}^{2} - 2x}\)

Hence, solved!

This is a translation of 2 units to the left and 5 units up, so the correct option is the first one.,

Remember that a vertical translation of N units is:

g(x) = f(x) + N

if N < 0 the translation is down.

if N > 0 the translation is up.

And a horizontal translation of N units is:

g(x) = f(x + N)

If N > 0 the translation is to the right.

if N < 0 the translation is to the left.

Here we have the transformation:

f(x) = x²

g(x) = (x + 2)² + 5

So this is a translation of 2 units to the left and 5 units up.

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The first quartile would be drawn at 3 and the median would be drawn

at 4.

What is the median in math?

Scores of group of students                        Frequency

                1                                                           0

                2                                                          2

                3                                                          2

                4                                                          4

                5                                                          3

                6                                                          1

                7                                                          1

First three set of scores from 1 to 3 comes under first quartile.

Median is in the center.

Last three set of scores comes under third quartile.

Therefore, the first quartile would be drawn at 3.

And the median would be drawn at 4.

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The given argument is invalid. The statement "If x=y', then x=y" is not true in general. In order to determine the validity of the argument, we need to analyze the statement "p⇒ (qvr)" and see if it holds for all possible truth values of p, q, and r.

To determine the validity of the argument, let's consider the statement "p⇒ (qvr)" where p, q, and r are real numbers. This statement is in the form of an implication (p implies q or r).

For the statement to be true, either p must be false (which would make the implication true regardless of the truth values of q and r), or q or r (or both) must be true.

Now, let's analyze the given argument: "If x=y', then x=y." This statement suggests that if the derivative of y is equal to x, then x is equal to y. However, this is not a universally true statement. There can be cases where x=y' but x is not equal to y. For example, consider y = x^2. The derivative of y is y' = 2x. In this case, x = 0 implies y' = 0, but y ≠ 0. Therefore, the given argument is invalid.

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To roughly represent the definite integral i with the specified accuracy. is equal to 0.473 and i = 0.5 x2ex2 dx 0 (|error| 0.001)

We can utilise the Taylor series expansion of the integrand function f(x) = 0.5 x2e(-x2) to roughly estimate the definite integral i to the required level of accuracy.

f(x) = f(0) + f'(0)x + f''(0)x^2/2 + f'''(0)x^3/6 + ...

where

f(0) = 0.5(0)^2e^(-0^2) = 0

f'(x) = xe^(-x^2) - x^3e^(-x^2) = xe^(-x^2)(1 - x^2)

f'(0) = 0

f''(x) = (1 - 2x^2)e^(-x^2)

f''(0) = 1

f'''(x) = (-4x + 6x^3)e^(-x^2)

f'''(0) = 0

Therefore, f(x) = x^2/2 - x^4/4 + x^6/12 - ...

We may now integrate f(x) term by term to approximate i as follows:

i ≈ ∫[0,∞) f(x) dx = [x^3/6 - x^5/20 + x^7/84 - ...]0^∞

= lim{t->∞} [t^3/6 - t^5/20 + t^7/84 - ... - 0]

= lim_{t->∞} [t^3(1/6 - 1/20t^2 + 1/84t^4 - ...) ]

= lim_{t->∞} [t^3/6(1 - 3/t^2 + 1/14t^4 - ...) ]

We can use the alternating series estimation theorem to confine the error because the series inside the limit is an alternating series that converges quickly for large t:

|error| ≈ \(|t^3/6(1 - 3/t^2 + 1/14t^4 - ...) - t^3/6(1 - 3/(t+1)^2 + 1/14(t+1)^4 - ...)|\)

\(= |t^3/6(3/t^2 - 1/14t^4 + ...)|\)

< 0.001

Solving for t gives:

t^3/6(3/t^2 - 1/14t^4 + ...) < 0.001

t > 7.56

As a result, we can use the first few terms of the series up to t = 8 to approximate i:

i ≈ ∫[0,8] f(x) dx ≈ [x^3/6 - x^5/20 + x^7/84]_0^8

≈ (8^3/6 - 8^5/20 + 8^7/84)

≈ 0.473

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If the perimeter of a rectangular living room is 38 meters, the length of the living room is 105 meters.

The perimeter of a rectangle is the sum of the lengths of all its sides. Let's denote the length of the living room as "L". The formula for the perimeter of a rectangle is:

Perimeter = 2(length + width)

We know that the width of the living room is 9 meters, and the perimeter is 38 meters. Substituting these values in the formula, we get:

38 = 2(L + 9)

Dividing both sides by 2, we get:

19 = L + 9

Subtracting 9 from both sides, we get:

L = 105

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By answering the above question, we may state that Hence, there is a probability 0.908 percent chance that a random smartphone user is between the ages of 23 and 64.7.

Calculating the chance that an event will occur or a statement will be true is the subject of probability theory, a branch of mathematics. A risk is a number between 0 and 1, where 1 denotes certainty and a probability of about 0 denotes the likelihood that an event will occur. The likelihood that an event will take place is mathematically expressed as probability. Probabilities can also be expressed as percentages ranging from 0% to 100% or as integers between 0 and 1. the proportion of equally plausible possibilities that actually happen in relation to all possible outcomes when a certain event occurs.

(X - mu) / sigma = z

Where: x is the age we're interested in estimating the likelihood of, and mu is the average age of smartphone users

The number of smartphone users' standard deviation is sigma.

To calculate the likelihood that a random smartphone user is between the ages of 23 and 64.7:

z1 = (23 - 36.9) / 13.9 = -0.995\sz2 = (64.7 - 36.9) / 13.9 = 2.003

We can calculate the likelihood of a z-score between -0.995 and 2.003, which is around 0.908, using a conventional normal distribution table or calculator.

Hence, there is a 0.908 percent chance that a random smartphone user is between the ages of 23 and 64.7.

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The equation of the polynomial is P(x) = 0.16875x² - 0.3375x - 13.5

From the question, we have the following parameters that can be used in our computation:

The graph

On the graph, we have the following readings:

A polynomial is represented as

P(x) = a * (x - zero)^multiplicity

Using the above as a guide, we have the following:

P(x) = a * (x + 8)(x - 10)

The y-intercept is -13.5

So, we have

a * (0 + 8)(0 - 10) = -13.5

This gives

a = 0.16875

Recall that

P(x) = a * (x + 8)(x - 10)

So, we have

P(x) = 0.16875(x + 8)(x - 10)

Expand

P(x) = 0.16875(x² + 8x - 10x - 80)

P(x) = 0.16875(x² - 2x - 80)

Remove bracket

P(x) = 0.16875x² - 0.3375x - 13.5

Hence, the expression is P(x) = 0.16875x² - 0.3375x - 13.5

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Therefore, in a 2x2 table, the pattern of cell frequencies that would indicate independence is d. All cell frequencies are exactly the same.

In a 2x2 contingency table, the expected cell frequencies under the null hypothesis of independence are equal for all cells. If the observed cell frequencies in the table are approximately equal to the expected cell frequencies, then we can conclude that there is no significant association between the two variables being studied. In other words, the pattern of observed cell frequencies is consistent with the null hypothesis of independence. Therefore, if all cell frequencies are exactly the same, it suggests that the variables are independent, as each cell has an equal chance of being filled by any observation regardless of the value of the other variable.

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Answer: I think the answer is A (4,6)

Step-by-step explanation:

Because point B is translated up you have to move the whole shape and pint D would end up at (4,6)

Based on the differential equation a) Solving the DE subject to P(0) = P0 will yield P = ((kP0 - h)e^(kt) + h)/k. b) For the three cases given (P0 > h/k, P0 = h/k, P0 = 0), the behavior of the population P(t) is will be population will grow without bound, the population will remain constant, and the population will decrease and approach zero as t approaches infinity respectively. c) The fish population will go extinct in finite time if there exists a time T > 0 such that P(T) = 0. At T = (1/k)ln(-h/(kP0 - h)) the fish population will go extinct.

(a) To solve the differential equation (dP/dt) = kP - h subject to P(0) = P0, we need to separate the variables and integrate both sides:

(dP/dt) = kP - h

dP/(kP - h) = dt

∫dP/(kP - h) = ∫dt

ln|kP - h| = kt + C

kP - h = e^(kt + C)

P = (e^(kt + C) + h)/k

Using the initial condition P(0) = P0, we can solve for C:

P0 = (e^(k*0 + C) + h)/k

P0 = (e^C + h)/k

e^C = kP0 - h

C = ln(kP0 - h)

Substituting back into the equation for P, we get:

P = (e^(kt + ln(kP0 - h)) + h)/k

P = ((kP0 - h)e^(kt) + h)/k

This is the solution to the differential equation subject to the initial condition P(0) = P0.

(b) The behavior of the population P(t) for increasing time depends on the initial condition P0:

- If P0 > h/k, then the term (kP0 - h)e^(kt) will be positive and will increase exponentially as t increases, so the population will grow without bound.

- If P0 = h/k, then the term (kP0 - h)e^(kt) will be zero and the population will remain constant at P = h/k for all time.

- If P0 < h/k, then the term (kP0 - h)e^(kt) will be negative and will decrease exponentially as t increases, so the population will decrease and approach zero as t approaches infinity.

(c) The fish population will go extinct in finite time if there exists a time T > 0 such that P(T) = 0. From the equation for P, we can see that this will happen if and only if P0 < h/k:

P(T) = ((kP0 - h)e^(kT) + h)/k = 0

(kP0 - h)e^(kT) = -h

e^(kT) = -h/(kP0 - h)

Since the exponential function is always positive, this equation has no solution for P0 > h/k or P0 = h/k. However, if P0 < h/k, then the term (kP0 - h) is negative and the equation has a solution:

kT = ln(-h/(kP0 - h))

T = (1/k)ln(-h/(kP0 - h))

This is the time at which the fish population will go extinct.

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The graph that represents the derivative of function f in the table is given as follows:

Graph 3.

To obtain the graph of the derivative of the function, we need to look at the function's behavior, as the derivative represents the rate of change of the function over an interval.

From the table, we have that the function is increasing over it's entire domain, hence the derivative is always positive.

The increase is initially slow, then it gets faster around x = 4, and then it gets slower again, meaning that the format of the graph of the derivative is that of a concave down parabola.

The highest derivative achieved is between 3.6 and 4.2, which is of:

(4.45 - 3.1)/0.6 = 2.25.

Meaning that Graph 3 is correct.

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Answer:

B is the answer

Step-by-step explanation:

$5.25 + $1.75x = $14.00

$14.00 - $5.25 = $8.75

$8.75 = $1.75x

$8.75 ÷ $1.75 = 5

x = $5

Answer:

$51.513

Step-by-step explanation:

First you covert 18% to decimal→0.18

Then you multiply 0.18 by 45.35→ 8.163

Finally you add 45.35 to 8.163 to get, 51.513

Answer:

(7x-4)^2

Step-by-step explanation:

To test the hypothesis H0: μ = 45 versus H1: μ ≠ 45, the methods presented in this section require the sample mean to follow a normal distribution. However, this does not necessarily imply that the population has to be normally distributed.

The Central Limit Theorem states that as the sample size increases, the distribution of the sample mean becomes approximately normal, regardless of the population distribution, provided the sample is random and independent. Therefore, if the sample size n is sufficiently large (say, n ≥ 30), the normality assumption for the population can be relaxed, and the hypothesis test can be conducted using the t-distribution. However, if the sample size is small (say, n < 30) and the population distribution is non-normal, then the t-test may not be valid, and alternative non-parametric tests such as the Wilcoxon rank-sum test or the Kruskal-Wallis test may be considered.

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Answer:

sure, the answer is 50

Step-by-step explanation: Because this is a right triangle, you can use the pythagorean theorem, which is a^2 + b^2 =c^2 so you square 48 and add it to 14 squared and then take the square roo t to get the value of the hypotenuse, note that c will always represent the hypotenuse or longest side, and that pythagorean theorem can only be used on right triangles

Answer:

There are no solutions. Hope this helps! :)

The rate of return if the price of Telecom stock goes up by 10% during the next year is 12%.

The rate of return (RoR) is a rate of return that calculates the net profit or loss of an investment over a certain period of time, and is expressed as a percentage. RoR is an indicator that can be useful to see the level of efficiency in an investment. When the RoR is positive, it means that the investment is making a profit.

Conversely, when the RoR is negative, it reflects a loss in investment. The higher the percentage RoR value, the higher the level of investment you can invest. For example, if the investment is IDR 1,000,000 and has a rate of return of 22%, then the growth rate is 22%.

Based on the question above,

Buy 200 shares of Telekom stock at $50 for $10,000.

The value of these shares increases by 10% or $1,000.

Interest expense = 0.08 x 5,000 = $400

Return values are:

(price increase - interest expense) / borrowed assets

= $1000 - $400 / $5000

= 0.12 = 12%

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Answer:

Step-by-step explanation:

The volume of water in a pool can be calculated using the following formula:

Volume (in gallons) = Length (in feet) x Width (in feet) x Average Depth (in feet) x 7.5

For example, if your pool is 20 feet long, 15 feet wide, and has an average depth of 5 feet, the volume of water in your pool would be:

20 x 15 x 5 x 7.5 = 5625 gallons

Note: If you prefer metric units, the formula for volume in liters would be:

Volume (in liters) = Length (in meters) x Width (in meters) x Average Depth (in meters) x 1000

It's important to note that this formula assumes a standard rectangular or square pool shape. If your pool has a more complex shape, you may need to measure the volume in smaller sections and add the volumes together to get the total volume.

To find a differentiable function y(x) that satisfies the initial value problem (IVP) y' = |x| and y(-1) = 2, we can integrate the given differential equation and then apply the initial condition.

Integrating both sides of the differential equation y' = |x| with respect to x, we get:

∫ y' dx = ∫ |x| dx

Integrating ∫ y' dx gives us y(x) + C₁, where C₁ is an arbitrary constant of integration.

Integrating ∫ |x| dx involves considering the different cases for x. Since x > 0 (as given in the problem), we have:

∫ |x| dx = ∫ x dx (for x > 0)

= (x^2)/2 + C₂, where C₂ is another arbitrary constant of integration.

Now, we have:

y(x) + C₁ = (x^2)/2 + C₂

To determine the values of C₁ and C₂, we can use the initial condition y(-1) = 2:

y(-1) + C₁ = ((-1)^2)/2 + C₂

2 + C₁ = 1/2 + C₂

Simplifying further:

C₁ = 1/2 - 2 + C₂

C₁ = C₂ - 3/2

We can rewrite the equation for y(x) by substituting C₁ with C₂ - 3/2:

y(x) = (x^2)/2 + (C₂ - 3/2)

Therefore, a differentiable function that satisfies the given IVP y' = |x| and y(-1) = 2 is:

y(x) = (x^2)/2 + (C₂ - 3/2), where C₂ is an arbitrary constant.

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Answer:

y = 1/2x + 12

Step-by-step explanation:

The y intercept is 12, and the slope is 1/2

Both the scale factor and the ratio of the perimeters are 7:10. The scale factor between the two similar rectangles is 7:10. This means that the dimensions of the larger rectangle are 7/10 times the dimensions of the smaller rectangle.

The ratio of the perimeters of the two rectangles is also 7:10. This is because the perimeter of a rectangle is the sum of all its sides, and since the scale factor applies to all sides equally, the ratio of the perimeters remains the same as the ratio of the areas. Therefore, the scale factor between the two similar rectangles is 7:10. This implies that the dimensions of the larger rectangle are 7/10 times the dimensions of the smaller rectangle. The ratio of the perimeters is also 7:10. This is because the perimeter of a rectangle is calculated by adding up all its sides, and the scale factor applies to all sides equally. Hence, the ratio of the perimeters remains the same as the ratio of the areas, resulting in a ratio of 7:10 for both.

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