Richard is driving home to visit his parents. 150 mi of the trip are on the interstate highway where the speed limit is 65 mph . Normally Richard drives at the speed limit, but today he is running late and decides to take his chances by driving at 80 mph. How many minutes does he save?

Explanation:

Newton's second law of motion is F = ma, or force is equal to mass times acceleration

Answer:

\(V = 331.6946\ m/s\)

Explanation:

First let's find the time that takes the shell to hit the ground (height zero).

To find this time, we can use the equation:

\(S = So + Vo*t + at^2/2\)

Where S is the final position, So is the inicial position, Vo is the inicial speed, a is the acceleration and t is the time. Then, for the vertical movement of the shell, we have that:

\(0 = 80 + 0*t - 9.81*t^2/2\)

\(9.81*t^2/2 = 80\)

\(t^2 = 160/9.81 = 16.31\)

\(t =4.0386\ seconds\)

Now, to find the horizontal speed, we use the equation:

\(S = So + V*t\)

Then, for the horizontal movement, we have:

\(1330 = 0 + V_h * 4.0386\)

\(V_h = 1330/4.0386 =329.32\ m/s\)

Now we need to find the vertical speed, using:

\(V = Vo + a*t\)

\(V_v = 0 - 9.81*4.0386\)

\(V_v = -39.6187\ m/s\)

Finally, to find the magnitude of the velocity, we have:

\(V = \sqrt{V_h^2 + V_v^2}\)

\(V = \sqrt{329.32^2 + (-39.6187)^2}\)

\(V = 331.6946\ m/s\)

Answer:

In a material, the magnetic behavior depends on the alignment of magnetic moments of the atoms. Magnetic moments are generated by the motion of the electrons in the atoms. When the magnetic moments of atoms in a material are aligned in a specific pattern, it creates a magnetic field which results in the material being magnetic.

In many materials, the magnetic behavior arises due to the alignment of magnetic domains, which are regions of atoms with magnetic moments aligned in the same direction. When many domains with aligned magnetic moments are present in a material, the material becomes magnetic.

The magnetic behavior of a material depends on the number of electrons and the arrangement of those electrons in the atoms. In particular, for an atom to have a magnetic moment, it must have unpaired electrons, meaning electrons that are not paired with another electron with the opposite spin. When these unpaired electrons in the atoms are aligned, they generate a magnetic moment. If all electrons are paired, there will not be a net magnetic moment, so the material will not be magnetic.

So, in summary, the magnetic behavior of a material is determined by the alignment of magnetic moments of atoms. When the magnetic moments of many atoms in a material align in the same direction, it creates a magnetic field, leading to a material being magnetic. This alignment is usually present in magnetic domains consisting of atoms with unpaired electrons.

Answer: -5 m/s^2

Explanation: a = v - u/t

                         = 32 - 47/3

                         = -15/3

                         = -5 m/s^2

The resistive force from load of the kettle lifted by the arm is determined from principle of moment and the magnitude is 71 kg.

The moment of force about a point is the product of applied force and the perpendicular distance of the force action. The moment of force about a point is equal to the torque exerted by the force.

τ = Fr

where;

F₁r₁ = F₂r₂

925(22.86) = F₂(30.38)

696 N = F₂

in kg, m = 696/9.8 = 71 kg

Thus, the resistive force from the applied force and distance is 71 kg.

The complete question is below:

If she wants the elbow flexors to exert 925 N of force during an isometric contraction, what should the resistance force be at 90 deg of flexion (the upper arm is vertical and the forearm is parallel to the ground) in kg

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Answer:

Your answers are correct

Explanation:

In my opinion, your answers are grouped in the appropriate columns.

Answer:

7.407 recurring m/s^2

Explanation:

Initial velocity= 0 m/s [as it starts from rest]

Final velocity= 10 m/s

Time taken= 1.35 s

Hence,

Acceleration = Final velocity - Initial velocity

                                 Time taken

a=10

   1.35

a=7.407 recurring m/s^2

Answer:

\(\boxed {\boxed {\sf 2.2 \ m/s^2}}\)

Explanation:

We are asked to solve for the magnitude of the car's acceleration.

We are given the initial speed, final speed, and distance, so we will use the following kinematic equation.

\({v_f}^2={v_i}^2+2ad\)

The car is initially traveling at 15.0 meters per second and accelerates to 20.0 meters per second over a distance of 40.0 meters. Therefore,

Substitute the values into the formula.

\((20.0 \ m/s)^2= (15.0 \ m/s)^2 + 2 a (40.0 \ m)\)

Solve the exponents.

\(400.0 \ m^2/s^2 = 225.0 \ m^2/s^2 + 2 a(40.0 \ m)\)

Subtract 225.0 m²/s² from both sides of the equation.

\(400.0 \ m^2/s^2 - 225.0 m^2/s^2 = 225.0 \ m^2/s^2 -225 \ m^2/s^2 +2a(40.0 \ m)\)

\(400.0 \ m^2/s^2 - 225.0 m^2/s^2 = 2a(40.0 \ m)\)

\(175 \ m^2/s^2 = 2a(40.0 \ m)\)

Multiply on the right side of the equation.

\(175 \ m^2/s^2 =80.0 \ m *a\)

Divide both sides by 80.0 meters to isolate the variable a.

\(\frac {175 \ m^2/s^2}{80.0 \ m}= \frac{80.0 \ m *a}{80.0 \ m}\)

\(\frac {175 \ m^2/s^2}{80.0 \ m}=a\)

\(2.1875 \ m/s^2 =a\)

Round to the tenths place. The 8 in the hundredth place tells us to round the 1 up to a 2.

\(2.2 \ m/s^2=a\)

The magnitude of the car's acceleration is 2.2 meters per second squared.

Answer:

The speed of the car before it began to skid is 47.56 m/s.

Explanation:

We can use kinematics to solve this problem.

We are given three known variables:

We can use this kinematic equation to solve for the initial velocity, v₀.

Substitute the known variables into the equation.

The speed of the car before it began to skid is 47.46 m/s.

A block of 0.5 kg is placed on top of another wooden block which weighs 1.0 kg. The coefficient of static friction between the two blocks is 0.35, whereas the coefficient of kinetic friction between the lower block and the level table is 0.20.

To calculate the maximum horizontal force that can be applied to the lower block, we need to determine the limiting frictional force between the two blocks.

Since the upper block is not moving, the force of static friction is acting on it. We can calculate this force as follows:

`F_static = friction coefficient * normal force`

where, normal force = weight of upper block = 0.5 kg * 9.81 m/s^2 = 4.905 N

`F_static = 0.35 * 4.905 = 1.718 N`

Therefore, the static frictional force acting on the upper block is 1.718 N.

Now, we need to find the maximum force that can be applied to the lower block before it starts moving. This force is equal to the force of static friction acting on the lower block.

Since the upper block is not moving, the force of static friction acting on the lower block is equal to the force of static friction acting on the upper block.

`F_static(lower block) = F_static(upper block) = 1.718 N`

This means that the maximum horizontal force that can be applied to the lower block is 1.718 N.

However, if the applied force exceeds this value, the lower block will start moving and the force of kinetic friction will be acting on it, which is equal to:

`F_kinetic = friction coefficient * normal force`

`F_kinetic = 0.20 * 4.905 = 0.981 N`

Hence, if the applied force exceeds 1.718 N, the lower block will start moving and the force of kinetic friction will act on it, which is 0.981 N.

Therefore, the maximum horizontal force that can be applied to the lower block is 1.718 N.

Answer:

Explanation:

To determine the maximum horizontal force that can be applied to the lower block without causing the blocks to move, we need to calculate the maximum static friction force between the two blocks. This force is given by:

F_friction = coefficient of static friction * normal force

where the normal force is the force perpendicular to the surface of contact between the blocks. Since the blocks are resting on a level table, the normal force acting on the lower block is equal to the weight of both blocks, which is:

N = (m1 + m2) * g

where m1 is the mass of the lower block, m2 is the mass of the upper block, and g is the acceleration due to gravity (9.81 m/s^2).

Plugging in the given values, we have:

N = (1.0 kg + 0.5 kg) * 9.81 m/s^2 = 14.715 N

The maximum static friction force is then:

F_friction = 0.35 * 14.715 N = 5.15025 N

Therefore, the maximum horizontal force that can be applied to the lower block without causing the blocks to move is 5.15025 N. If a greater force is applied, the blocks will start to move and the kinetic friction force will take effect, which is given by:

F_kinetic = coefficient of kinetic friction * normal force

where the coefficient of kinetic friction is 0.20 in this case.

Answer:

Explanation:

From the given information:

The speed of a synchronous motor in relation to its frequency can be represented with the formula:

\(n_{sm}= \dfrac{120f_{se}}{P}\)

where,

the electrical frequency \(f_{se}\) is measured in Hz

the number of poles = P

For us to estimate the number of poles to have 50 Hz - 60 Hz Power, then we need to relate the frequencies of the above equation.

i.e

\(\dfrac{120(50 \ Hz)}{P_1}= \dfrac{120( 60 \Hz)}{P_2} \\ \\ \dfrac{6000 \ Hz}{P_1}= \dfrac{7200 \ Hz}{P_2} \\ \\ \dfrac{P_2}{P_1}=\dfrac{7200}{6000} \\ \\ \\ \dfrac{P_2}{P_1}= \dfrac{12}{10}\)

Thus, we can conclude that 10 poles synchronous motor is attached with 12 poles synchronous generator in order to convert 50 Hz to 60 Hz power.

Answer:

I've always wanted to be a nurse. growing up my auntie used to show me a lot of stuff about becoming a nurse since she us one.

The speed of the ball just after striking the floor a second time, is 30.0 m/s.

Initial height (h) = 45 m

Acceleration due to gravity (g) = 10 m/s²

Energy loss per collision (k) = 19% = 0.19

At each collision with the floor, the ball loses 19% of its kinetic energy, which means the remaining kinetic energy is 81% (100% - 19%).

When the ball reaches the floor for the first time, it has converted all its potential energy into kinetic energy. So, the initial kinetic energy (K₁) is equal to the potential energy (PE) at the initial height:

K₁ = PE = mgh

Now, let's consider the ball's motion from the initial height to the first collision point. The ball undergoes free fall, so we can use the equations of motion:

h = (1/2)gt²

t = sqrt(2h/g)

Using this time, we can calculate the initial kinetic energy (K₁):

K₁ = mgh = m * 10 m/s² * 45 m

Since the ball loses 19% of its kinetic energy at each collision, the remaining kinetic energy is 81%:

K₂ = K₁ * 0.81

The ball then rebounds elastically from the floor, conserving both kinetic energy and speed. Therefore, the speed just after striking the floor for the second time (v₂) is equal to the speed just before the first collision (v₁):

v₂ = v₁

To find the speed just before the first collision (v₁), we can use the equation of motion:

v = gt

Substituting the time (t) we found earlier, we have:

v₁ = g * sqrt(2h/g)

Now, we can substitute the known values and calculate the speed just after striking the floor for the second time:

v₁ = 10 m/s² * sqrt(2 * 45 m / 10 m/s²)

v₂ = v₁

By evaluating the expression, we find:

v₁ ≈ 30.0 m/s

v₂ ≈ 30.0 m/s

Therefore, the speed of the ball just after striking the floor for the second time is 30.0 m/s.

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Answer:

7. d. England during the Age of Enlightenment

8. a. State governments do not usually act together

Explanation:

The Age of Enlightenment occurred in the 18th century and at this time England was a Constitutional monarchy with a monarch and parliament ruling the country with different powers.

The third and fourth methods of amending the Constitution will be much harder to use because state governments simply do not usually act together as they most times have ideological differences. The sheer number of states it would take to unite for these methods to be used makes this impractical.

As vₙ<v, no photoelectron is emitted, thus no extraction work is required.

The minimum frequency of incident radiation below which photoelectric emission or electron emission is not feasible is referred to as the threshold frequency.

The frequency of light at which an electron will be forced to leave a metal surface is referred to as the threshold frequency.

The wavelength of incident radiation is λ = 180nm = 1800A = 1800 * 10⁻¹⁰ m.

Therefore, the frequency of incident radiation is

v = c / λ

v = 3 * 10⁸ / 1800 * 10⁻¹⁰

v = 0.166 * 10¹⁶ Hz

Therefore, threshold frequency is

v₀ = c/λₙ

vₙ = 3 * 10⁸ / 275 * 10⁻¹⁰

vₙ = = 1.09 * 10¹⁶ Hz

As vₙ<v, no photoelectron is emitted.

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The question is incomplete. The complete question is :

Two conducting spheres are mounted on insulating rods. They both carry some initial electric charge, and are far from any other charge. Their charges are measured. Then, the spheres are allowed to briefly touch, and the charge in one of them (sphere A) is measured again. These are the measured values:

 a). Before contact:

Sphere A = 4.8 nC

Sphere B = 0 nC

What is the charge on sphere B after contact, in nC?

b). Before contact:

Sphere A = 2.9 nC

Sphere B = -4.4 nC

What is the charge on sphere B after contact, in nC?

Solution :

It is given that there are two spheres that are conducting and are mounted on an insulating rods which carry a initial charge and they are briefly touched and then one of the charge is measured.

Here the charge becomes divided when  both the spheres are connected and then removed.

a). charge after they are charged

   \($Q = \frac{q_1+q_2}{2}$\)

    \($Q = \frac{4.8+0}{2}$\)

      = 2.4 nC

b). The charge is

    \($Q = \frac{q_1-q_2}{2}$\)

    \($Q = \frac{2.9-4.4}{2}$\)

      = -0.75 nC    

La longitud del faldón de la rampa es de 5.4 m.

La pendiente expresada en porcentaje sigue la siguiente ecuación:

\(m=\frac{y}{x}*100\) (1)

Donde:

Sabemos que la pendiente es de 27%. Por lo tanto, usando la ecuación 1, despejamos y.

\(27=\frac{y}{20}*100\)

\(y=\frac{27*20}{100}\)

\(y=5.4\: m\)        

La longitud del faldón es 5.4 m

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Answer:

Part One: Defining the Problem and Sub-Problems

1. Choose one of the real-world problems about natural resources to research. Explain which one you chose here.

o I chose pollution, due to the overwhelming pollution in todays day and age.

2. Research this problem to learn more about it. Use the research tools given in the lesson if you need help.

o There are 4 main types of pollution Air Pollution, Water Pollution, Soil Pollution, Noise Pollution.

o Air pollution refers to the release of harmful contaminants into the earth’s atmosphere.

o Water pollution is said to occur when toxic pollutants and particulate matter are introduced into water bodies such as lakes, rivers and seas.

o Soil pollution, also called soil contamination, refers to the degradation of land due to the presence of chemicals or other man-made substances in the soil.

o Noise pollution refers to the excessive amount of noise in the surrounding that disrupts the natural balance.

o Pollution is harmful things within an environment, that can cause decay within an environment.

3. After you have researched the problem, explain in your own words who the problem impacts and why it is important.

o It impacts the environment, people, animals, water, food, and the atmosphere. Its important to try and stop pollution to- a. make the world a cleaner place and b. stop such harmful substance from killing the environment around us.

4. List two sub-problems that are part of the bigger problem but are more manageable and solvable.

o Man made factories, cars, and garbage dumps.

o Being a litter bug (throwing trash on the ground).

5. Explain how these sub-problems are related to or a direct result of the overall problem.

o Cars create air pollution, along with factories. With being a litter bug and garbage dumps it causes soil pollution.

Part Two: Criteria, Constraints, and Prioritizations

1. Choose one sub-problem that you will investigate further and explain which one you chose here.

o Cars/fuel

2. List two realistic criteria for the sub-problem.

o Reducing fuel and oil can help fix the problem.

o Also using more electric ways to charge the car to run could be based off solar power to create a better environment.

3. Explain why it is important for these criteria to be met in order to solve the problem.

o It would create less air pollution, and could help with sickness, plants dying, and animals dying.

4. List two constraints for the sub-problem.

o Electric cars are a bit to expensive for the average person.

o People need to drive for work/travel, so they need gas for their car and due to the higher priced cars, it makes it almost impossible for this goal to be reached.

5. Explain why these constraints exist. (How do they limit solutions to the problem?)

o They exist due to the underpayment of workers and the average and below average social class. As for limiting the solutions, that is currently happening due to two oil factories shutting down raising the price on gas and limiting more gas for people. But causing more global panic/ angry people, due to not being able to receive what they need to continue their life by driving.

6. Prioritization of the criteria and constraints and an explanation supporting the decisions made based on research.

Ranking Criteria or Constraint Reason for Prioritization

1.  Fuel and oil  Its highly needed to run cars but causes sever pollution.

2.  Prices for electric cars We could possibly have less pollution though its too expensive to afford a car that runs off electric. Because it may reduce pollution but the average paid person couldn’t afford it.

3.  Under payment Within underpayment it causes more fuel and oil to be used in older cars that cant use electric charging.

4.  Solar powered electric charge stations Low pollution and easily earth friendly acceptable.

Part Three: Generate Solutions

1. List two solutions that you have generated for the chosen sub-problem.

o Lowering prices on electric cars.

o Creating solar powered charge stations to reduce more pollution.

2. Describe how the sub-problem can be solved, and include the research supporting each solution.

o Lowering prices on electric cars and creating less fuel and oil providing cars could reduce pollution dramatically due to the burning fuels not polluting the air. And along with lowering car prices creating a solar energy charge station creates a more natural charge station instead of causing soil pollution with factories and under ground pipes.

3. Explain how prioritization was involved in designing each solution.

o Lowering prices on electric cars and creating less fuel and oil providing cars could reduce pollution dramatically due to the burning fuels not polluting the air.

4. Explain how both solutions to the sub-problem play a role in solving the larger problem.

o Both of my solutions would stop both soil and air pollution when it comes to cars and factories.

Answer:

join my z o o m

Explanation:

Answer:

Explanation:

The volume of a substance when given the density and mass can be found by using the formula

\(volume = \frac{mass}{density} \\\)

From the question

mass = 35 g

volume = 5 g/cm³

We have

\(volume = \frac{35}{5} \\ \)

We have the final answer as

Hope this helps you

Answer:

I really don't want to go out for a week and I deserve to be wit me she said that she would have been able even better then again this year moma and she was the one that was earlier than you and my parents are going through a tough time and it was broken down into the last time I was coming from but I see an feel a lot of hate

Explanation:

no exceptions