Researcher are recording how much of an experimental medication is in a person’s bloodstream every hour. they discover that half-life of the medication is about 6 hours.

Average waiting time for FCFS: 8.75

Average waiting time for SJF: 4.75

To solve this scheduling problem using FCFS (First-Come, First-Served) and SJF (Shortest Job First) algorithms, let's go step by step:

Schedule order for FCFS:

The FCFS algorithm schedules processes based on their arrival time. So, the schedule order for FCFS is as follows:

Pl -> P2 -> P3 -> P4

Average waiting time for FCFS:

To compute the average waiting time for FCFS, we need to calculate the waiting time for each process and then take the average.

Process | Arrival Time | Running Time | Waiting Time

Pl | 0 | 3 | 0

P2 | 3 | 10 | 3

P3 | 4 | 6 | 13

P4 | 5 | 1 | 19

Average waiting time = (0 + 3 + 13 + 19) / 4 = 8.75

Therefore, the average waiting time for FCFS is 8.75.

Schedule order for SJF:

The SJF algorithm schedules processes based on their running time. The process with the shortest running time gets executed first. If multiple processes have the same running time, the process with the earliest arrival time is selected first. The schedule order for SJF is as follows:

Pl -> P4 -> P3 -> P2

Average waiting time for SJF:

To compute the average waiting time for SJF, we need to calculate the waiting time for each process and then take the average.

Process | Arrival Time | Running Time | Waiting Time

Pl | 0 | 3 | 0

P4 | 5 | 1 | 3

P3 | 4 | 6 | 6

P2 | 3 | 10 | 10

Average waiting time = (0 + 3 + 6 + 10) / 4 = 4.75

Therefore, the average waiting time for SJF is 4.75.

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The rate of change of a periodic function is itself a periodic function. In the case of a sinusoidal wave, the derivative is also a sinusoidal wave with the same period, but shifted by a phase angle of \(π/2.\)

The rate of change of a periodic function at a specific point is equal to the instantaneous slope of the tangent line to the graph of the function at that point.

To calculate the rate of change of a periodic function, you need to take the derivative of the function with respect to the independent variable (usually time). If the function is a sinusoidal wave, you can use trigonometric identities to find the derivative.

For example, let's say we have a function f(t) = sin(t), which represents a sinusoidal wave. To find the rate of change of the function at a particular point t = a, we need to take the derivative of the function with respect to t:

f'(t) = cos(t)

Then we can evaluate this derivative at t = a to find the rate of change at that point:

f'(a) = cos(a)

This tells us the instantaneous rate of change of the function at the point t = a.

Note that the rate of change of a periodic function is itself a periodic function. In the case of a sinusoidal wave, the derivative is also a sinusoidal wave with the same period, but shifted by a phase angle of \(π/2.\)

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Two point charges, q1 = 3.99 nC located at x = 0.205 m and q2 = 5.01 nC at x = -0.302 m, are placed on the x-axis. The electric field and direction at a given point can be calculated using the principle of superposition.

The electric field at a point due to a point charge is given by Coulomb's law, E = kq/r^2, where E is the electric field, k is Coulomb's constant (8.99 x 10^9 Nm^2/C^2), q is the charge, and r is the distance between the point charge and the point where the electric field is being measured. To calculate the net electric field at a point due to multiple charges, we use the principle of superposition, which states that the total electric field at a point is the vector sum of the electric fields due to each individual charge.

In this case, we have two charges, q1 = 3.99 nC and q2 = 5.01 nC. The electric field at a point P on the x-axis, due to q1, can be calculated as E1 = kq1/r1^2, where r1 is the distance between q1 and point P. Similarly, the electric field at point P due to q2 can be calculated as E2 = kq2/r2^2, where r2 is the distance between q2 and point P. To find the net electric field at point P, we add the electric fields vectorially, E_net = E1 + E2.

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The amount accumulated after investing a principal P for t years at an interest rate compounded annually is  $46,057.58.

Compound interest is the interest you earn on interest. Compound interest is the interest calculated on the principal and the interest accumulated over the previous period.

Therefore, let's find the amount accumulated after investing a principal P for t years at an interest rate compounded annually.

\(A = p(1 + \frac{r}{n} )^{nt}\)

where

p = 15,500

r = 9.5%

t = 12

n = 1

\(A = 15500(1 + \frac{0.095}{1} )^{1(12)}\)

A = 15,500.00(1 + 0.095)¹²

A = $46,057.58

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$46,057.58, answer for acellus

Answer:

hope it helps you.........

Answer:

correct me if I'm wrong but 40?

In order to calculate the z-scores for the given Confidence Interval (CI) levels, we need to use the Z-table. It is also known as the standard normal distribution table. Here are the z-scores for the given Confidence Interval levels:1. 68% CI: The confidence interval corresponds to 1 standard deviation on each side of the mean.

Thus, the z-score for the 68% \(CI is ±1.00.2. 85% CI\): The confidence interval corresponds to 1.44 standard deviations on each side of the mean.

We can calculate the z-score using the following formula:\(z = invNorm((1 + 0.85)/2)z = invNorm(0.925)z ≈ ±1.44\)Note that invNorm is the inverse normal cumulative distribution function (CDF) which tells us the z-score given a certain area under the curve.3. 99% CI: The confidence interval corresponds to 2.58 standard deviations on each side of the mean. We can calculate the z-score using the following formula:\(z = invNorm((1 + 0.99)/2)z = invNorm(0.995)z ≈ ±2.58\)

Note that in general, to calculate the z-score for a CI level of (100 - α)% where α is the level of significance, we can use the following formula:\(z = invNorm((1 + α/100)/2)\) Hope this helps!

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The range of the function f(x) = \(-2^{x}\) + 4 is -∞ < y < 4.

What is range of a function?

All potential values for y are included in a function's range. The equation to determine a function's range is Y = f. (x). If every x value has exactly one y value, then it is merely a function in a relation.

We are given a function which is defined as  f(x) = \(-2^{x}\) + 4.

We know that range is the output we get after substituting the value of x.

So, in this situation, we will get the value for y less than 4 or equal to 4 because when x = 0, we will get 4 and when x = 1, we will get 2 as there is a minus sign before 2 due to which this will be always a negative value.

Thus, the range of the function will be -∞ < y < 4.

Hence, the third option is the correct option.

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Answer:

x = 14 2/3

Step-by-step explanation:

it is a parallelogram.

that means AB is parallel to CD, and AD to BC.

it also means that the total angles at B and D must be equal. and the total angles at A and C.

and the sum of all angles in a parallelogram is 360 degrees.

so, we have

360 = 2×(4x + 4x + 8) + 2×(x + 10 + 2x + 8) =

= 8x + 7x + 16 + 2x + 20 + 4x + 16 =

= 21x + 52

308 = 21x

x = 14.666666666.... = 14 2/3

Given:

Thus, the answer of 4/5 divided by 1/10 is 8.

The range of possible lengths for the third side be

0 ft < x < 76 ft

0 ft < x < 33 ft

Given, two sides of a triangle

we have to find the range of possible length for the third side of the triangle.

a) 24 ft and 52 ft

given first side of the triangle be, 24 ft

and second side of the triangle be, 52 ft

as we know that the third side should be less than the sum of the remaining two sides of any triangle.

So, let the third side be x

x < 24 + 52

x < 76

Therefore, the third side should be less than 76 ft and obviously greater than 0 ft.

Range of the third side be, 0 ft < x < 76 ft

b) 16 ft and 17 ft

given first side of the triangle be, 16 ft

and second side of the triangle be, 17 ft

as we know that the third side should be less than the sum of the remaining two sides of any triangle.

So, let the third side be x

x < 16 + 17

x < 33

Therefore, the third side should be less than 33 ft and obviously greater than 0 ft.

Range of the third side be, 0 ft < x < 33 ft

Hence, the range of possible lengths for the third side be

0 ft < x < 76 ft

0 ft < x < 33 ft

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Answer:

17/30

Step-by-step explanation:

Answer:

x=17/30

Step-by-step explanation:

Answer:

x = -7 and x = 4

Step-by-step explanation:

Note, I am taking the polynomial equation as
\(x^2 - 28 = -3x\)

Otherwise it does not become a polynomial of one variable and cannot be solved

Zeros of a polynomial are the values of x where the polynomial value itself is 0

Standard equation for a polynomial of degree 2 is ax² + bx + c = 0 where a, b and c are constants

Degree is the highest exponent. Here the highest exponent is 2 so the polynomial has degree 2. Such a polynomial is called a quadratic polynomial

So we first have to convert
x² - 28 = - 3x into  this form ax² + bx + c

1. Add 3x to both sides
x² - 28 + 3x = -3x + 3x =0

==> x² + 3x - 28  = 0
With a = 1, b = 3 and c = -28

2. Factor x² + 3x - 28  = 0

Here a = 1, b = 3 and c = -28

Factoring means find two expressions x+a and x +b such that (x + a) (x + b) = x² + 3x - 28  = 0

Then we can state that
x + a = 0           ==> x = -a as one solution
x + b = 0           ==> x = -b as the other solution

To factor, find two numbers m and n(could be negative) such that mn = c and m + n = b

28 has factors 7 and 4 so that is a good start

-28 = -7 x 4 or could also be 7 x -4

How do we choose?
Add both and see what gives you +3

-7 +  4 = -3  Nope
7 + -4 = 7-4 = 3 YES

So the factors are 7 and -4

(x + m) = (x + 7)
(x + n)  = (x -4)

So the original quadratic polynomial becomes

(x + 7)(x -4) =

This means

x + 7 = 0 ==> x = -7

x -  4 = 0 ==> x = 4

So the solutions(also called roots) of x² + 3x - 28  = 0 are:

x = -7 and x = 4

Both the above values satisfy the quadratic equation

Answer:

Since February 1988 is a leap year, February has 29 days in it. Multiply 29 times $250.00 to get C. $7,250.00.

Answer:

1 mile.

Step-by-step explanation:

3/3 mile is equal to 1 mile.

Answer:

Joe walked his dog 1 mile.

Step-by-step explanation:

3/3 =1 mile.

Answer: graph b

Step-by-step explanation:

Vertex:  ( 3 ,0 )

Focus:  ( 3 , 1 4 )

Axis of Symmetry:  x = 3

Directrix:  y = − 1 4

Answer:

2.25 42.1

2.75 43.0

3.25 43.8

Step-by-step explanation:

soybean crop yields (in bushels per acre) for an agricultural region.

Rainfall Crop Yield

2.25 42.1

2.75 43.0

3.25 43.8

3.75 44.2

4.25 44.5

4.75 44.3

5.25 43.5

Use a quadratic regression calculator to write a quadratic function that provides a reasonable fit to this set of data

The one function that satisfies f '(x) = 3x² + 6x + 5 is f(x) = x³ + 3x²÷2 + 5x + C. where C is the constant of integration.

The given function's derivative is f'(x) = 3x² + 6x + 5.

To find the original function f(x), we need to integrate the derivative.

We can integrate the given function f'(x) term by term, using the power rule of integration:

∫f'(x) dx = ∫(3x² + 6x + 5) dx

f(x) = x^3 + 3x²÷2 + 5x + C

Any constant value of C can be added to the above function, resulting in an infinite number of functions that satisfy

f '(x) = 3x² + 6x + 5.

f(x) = x^3 + 3x²÷2 + 5x + 2 and f(x) = x³ + 3x²÷2 + 5x - 7 are both valid solutions to f '(x) = 3x² + 6x + 5, with different constant values of C.

This is because the constant of integration represents an arbitrary constant, and when we take the derivative, the constant term becomes zero. Hence, any function that differs from the original function by a constant value will also have the same derivative.

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Answer:

Step-by-step explanation:

we can replace 5 with \(\sqrt{5}^{2}\)

then.

\(\sqrt{5}^{n-1+2}=\sqrt{5}^{n+1}\)

Answer: 5y + 2x - 3

(In simplest form)

A country with little land and few natural resources could make up for such deficits without depending on other countries and having a healthy economy by developing its Human Capital.

Examples of small countries with low natural resources and high GDP are:

It is to be noted that of all the factors of production, (Land, labor, Capital, and Entrepreneurship) Human Capital (Labor and Entrepreneurship) are the most valuable and yield the greatest return on investment.

The Democratic Republic of the Congo is commonly regarded as the world's richest country in terms of natural resources; its undiscovered stockpiles of raw minerals are estimated to be worth more than US $24 trillion.

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Answer:

IU=161

Step-by-step explanation:

Angle Formed by Two Secants=  1/2 (difference of Intercepted Arcs)

42 = 1/2 (7m+5 - (3m-1))

Distribute the minus sign

42 = 1/2 (7m+5 - 3m+1))

Combine like terms

42 = 1/2 ( 4m+6)

Distribute the 1/2

42 = 2m+3

Subtract 3 from each side

42-3 = 2m+3-3

39 = 2m

Divide by 2

19.5 = m

The sum of the arcs = 360

IU+ 3m-1 + 7m+5 = 360

IU +10m+4 = 360

IU +10(19.5) +4 = 360

IU +195+4 = 360

IU = 360 - 199

IU=161

Answer:

The second choice; KJL and HGJ

Step-by-step explanation:

These 2 angles are corresponding angles

a(a+2b) - c(c + 2b) is the product form of the expression (a+b)^2-(b+c)^2

What is simplification of an algebraic expression?

Simplification of an algebraic expression is defined as a way of writing an expression in the most efficient and compact form without affecting the value of the original expression

Given (a+b)^2-(b+c)^2

(a+b)²-(b+c)² = (a+b)(a+b) - (b+c)(b+c)          (Clear the parenthesis)

                    = ( a(a+b) + b(a+b) ) - ( b(b+c) + c(b+c) )

                   = (a² + ab + ab + b²) - (b²+ bc + bc +c²)

                  = (a² + 2ab + b²) -  (b²+ 2bc +c²)

                 = a² + 2ab + b² -  b² - 2bc - c²           (Add/subtract like terms)

                =   a² + 2ab - 2bc - c²                         (Factorise)

                =  a(a+2b) - c(2b + c)                          (Rearrange)

               =   a(a+2b) - c(c + 2b)

Therefore, the expression (a+b)^2-(b+c)^2 can be simplified as a product to a(a+2b) - c(c + 2b)

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For various levels of output, businesses in a competitive market have the following production costs. Right now, the price on the market is $4. Total Cost Quantity 0 1 10 2 13 3 18 4 25 34. Therefore,

1. Each firm maximizes profit by supplying 2 units where MR = MC.

2. At $4 market price, market not in long-run equilibrium as ATC ($6.5) > price.

3. Market reaches long-run equilibrium at $6, the minimum point of ATC curve.

To determine the units each firm will supply to maximize profit and calculate the profit, we need to examine the cost and revenue associated with each quantity of output.

Quantity                    Total Cost

0                                       1

1                                       10

2                                      13

3                                      18

4                                     25

1. To find the quantity that maximizes profit for each firm, we need to compare the marginal cost (MC) and marginal revenue (MR) at each quantity level.

Quantity   Total Cost   MC       MR

0                  1                   -       -

1                  10                 9       4

2                  13                 3       4

3                  18                 5       4

4                  25                 7       4

To maximize profit, a firm will produce where MR equals MC. Looking at the table, we can see that at a quantity of 2, the MR and MC are equal. Therefore, each firm will supply 2 units to maximize profit.

2. To determine if the market is in long-run equilibrium at a market price of $4, we need to compare the market price with the average total cost (ATC) for each firm. If the market price is equal to or greater than the ATC, the market is in long-run equilibrium.

Let's calculate the ATC for each firm at a quantity of 2:

\(ATC = \frac{Total Cost}{Quantity}\)

\(ATC = \frac{13}{2}\)

ATC = 6.5

The ATC for each firm is $6.5, which is greater than the market price of $4. Therefore, the market is not in long-run equilibrium because firms are not covering their costs and would not continue to operate in the long run.

3. To determine the price at which the market will be in long-run equilibrium, we need to find the minimum point of the average total cost (ATC) curve. This point represents the price at which firms can cover their costs and earn a normal profit in the long run.

Looking at the table, we can observe that the minimum ATC occurs at a quantity of 3. Let's calculate the ATC at this quantity:

\(ATC = \frac{Total Cost}{Quantity}\)

\(ATC = \frac{18}{3} = 6\)

Therefore, the market will be in long-run equilibrium at a price of $6, which corresponds to the minimum point of the ATC curve.

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(a) The real discrete Fourier transform (DFT) is calculated for the given data set to analyze the helicopter's acoustic signature.

(b) To obtain the ck values and illustrate the relative size of each term in the Fourier series, we calculate the magnitude of each coefficient and plot their amplitudes on a bar graph against the corresponding frequency component, k.

To analyze the helicopter's acoustic signature, the real DFT is computed for the provided data set. The DFT transforms the time-domain measurements of acoustic pressure into the frequency domain, revealing the different frequencies present and their corresponding amplitudes. This analysis helps in understanding the spectral characteristics of the helicopter's acoustic signature and identifying prominent frequency components.

Using the Fourier series representation, the amplitudes (ck's) of the different frequency components in the Fourier series are determined. These amplitudes represent the relative sizes of each term in the series, indicating the contribution of each frequency component to the overall acoustic signature. By plotting the amplitudes on a bar graph, the relative strengths of different frequency components become visually apparent, enabling a clear comparison of their importance in characterizing the helicopter's acoustic signature.

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Answer:

7:10

Step-by-step explanation:

1. There are a total of 10 sections, each with a different number.

2. Out of all these sections, 3 sections are less than 10 and 7 are greater than 10.

Therefore, the odds are 7:10.

There are 3 balanced strings in set T.

To count the number of balanced strings in the set T={0, 1, 2}, we can establish a bijection between the set of balanced strings and T itself. A balanced string is defined as a string in which the sum of its digits is a multiple of 3.

We can define a function f: T" -> T that maps each string in T" to T by preserving the balanced property. If a string in T" is already balanced, f returns the string itself. If the string is not balanced, f replaces the last digit with digit that makes the sum a multiple of 3.

By showing that this function is both injective (one-to-one) and surjective (onto), we establish a bijection. The bijection rule states that if two sets have a bijection between them, they have the same cardinality. Therefore, the number of balanced strings is equal to the number of elements in T, which is 3.

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To be a solution of the system, it has to be true in both equations.

As the coordinate is (x,y), then we have to replace 3 in every x in the equations and 7 in every y in the equations.

• Equation 1

As this is NOT TRUE, then it is not a solution for this equation, and as we are looking for a solution for the system of equations, then this is not a solution.

Answer: B. No

Answer:

130 degrees is your answer

Step-by-step explanation:

The measurement of angle C is given by the expression 180° – 25° – 25°. So, angle C measures 130°.- answer from edmentum