Research Hypatia's achievements in the world

of science.

What is she most known for?

Write down three interesting facts about her

life.

Answer:

Brass is an alloy, and either a "solid solution".

Alloys in general may be solid solutions or they simply be mixtures

Explanation:

Answer:

Well the answer of 1 and 3 is WRONG based on the 1 star review and the answer of 3 is wrong too I just took a test with this question.

Explanation:

Sorry...

Answer:

it's 6

Explanation:

I just took the test and got it right

Answer:

S is [Ne] 3s²3p⁴

Cl is [Ne] 3s² 3p⁵

Explanation:

Answer:

Please find the complete question in the attached file.

Explanation:

It would only be radioactive if the DNA molecule that employed the poly-T rand as templates. Its other molecule of the daughter would not have been radioactive as it did not need dATP for its replication. While each strand of the second molecule includes t, simultaneous reproduction dATP from both daughter molecules is needed so that each of those is radioactive.

The equation for the equilibrium constant (K) of the reaction studied in this exercise can be written as follows: K = ([\(CI_20\), 2-] * [\(H_20\)(1)]) / ([\(C0_4^ 2\)-] * [Ht])

In this equation, the concentrations of the species involved in the reaction are represented by the square brackets [ ]. The subscripts indicate the stoichiometric coefficients of each species in the balanced chemical equation.

The reaction being studied involves the following species:

\(C0_4^ 2\)- (ag) + 2Ht (ag) = \(CI_20\), 2- (ag) + \(H_20\)(1)

In the equilibrium constant expression, the concentration of \(CI_20\), 2- is multiplied by the concentration of \(H_20\)(1) and divided by the product of the concentrations of \(C0_4^ 2\)- and Ht. The stoichiometric coefficients in the balanced equation are used as exponents for the concentrations of the respective species.

It is important to note that the concentrations used in the equilibrium constant expression should be in molar units (mol/L) or expressed as partial pressures for gases.

Additionally, the equilibrium constant is specific to a given temperature, and its value provides information about the relative amounts of reactants and products at equilibrium.

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The enthalpy of combustion for 1kg of urea is -1223525.84 J/mol.

Urea is a compound that is used in fertilizers and in some plastics.The enthalpy of combustion for urea is the amount of energy that is released when urea is burned. In order to calculate the enthalpy of combustion for 1kg of urea, we need to use the information that is provided to us in the question. Let us start by writing down the balanced equation for the combustion of urea: CO(NH2)2 + 3/2 O2 → CO2 + 2H2O + N2
The balanced equation shows that 1 mole of urea reacts with 1.5 moles of oxygen gas to produce 1 mole of carbon dioxide, 2 moles of water, and 1 mole of nitrogen gas. The enthalpy change for this reaction is equal to the amount of energy that is released when 1 mole of urea is burned.
The heat of combustion (ΔHc) of urea is -632.6 kJ/mol. This means that 632.6 kJ of energy is released when 1 mole of urea is burned. We know that 12g of urea raised the temperature of water by 30°C. We can use this information to calculate the amount of energy that was released when 12g of urea was burned.
The specific heat capacity of water is 4.18 J/g°C. This means that it takes 4.18 J of energy to raise the temperature of 1 gram of water by 1°C. Therefore, it takes 4.18 x 1000 = 4180 J of energy to raise the temperature of 1 kg of water by 1°C.
We know that 12g of urea raised the temperature of water by 30°C. Therefore, the amount of energy that was released when 12g of urea was burned is:
Energy = mass x specific heat capacity x temperature change
Energy = 0.012 kg x 4180 J/kg°C x 30°C
Energy = 1497.6 J
We can now use this information to calculate the enthalpy of combustion for 1kg of urea:
Enthalpy of combustion = energy released / moles of urea burned
Enthalpy of combustion = 1497.6 J / (0.012 kg / 60.06 g/mol)
Enthalpy of combustion = - 1223525.84 J/mol
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Answer:

hope this helps

Explanation:

˙˚ʚ(´◡`)ɞ˚˙

There is no overall change in reactants and products whenever a chemical reaction reaches equilibrium. It is a fundamental point in a reaction.

A chemical reaction is a process where one or more reactants interact with an enzyme to generate one or more products.

The equilibrium refers to the state where reactants and products are found in the same concentrations.

During the equilibrium, there is no change in the properties of the reaction and the amounts of substances involved remain the same.

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Answer:

0.44 mole of oxygen gas can 0.88 mole of hydrogen peroxide (h2o2) produce, if decomposition is complete.

From each drop-down menu, a solid has (a definite volume and a definite shape), a Liquid has (a definite volume) and gas has ( non of the above)

Matter is defined as anything that has weight and occupies space.

There are three states of matter that is in existence which include:

Therefore, a liquid occupies the shape of its container.

Therefore, a gas neither has a definite shape nor volume.

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3.0 moles of \(Al\) can fully react with hydrogen chloride to produce 4.5 moles of \(H_{2}\). Thus, 0.93 moles will be produced by 0.62 moles of \(Al\).

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Answer:

NA

Explanation:

Answer:

- regular nitrogen balance, maintain healthy body weight and protein count does not change

- negative nitrogen balance, nitrogen intake is greater than nitrogen output, makes body weight and protein decrease caused by illness

-positive nitrogen balance, nitrogen intake is less than nitrogen output, increase muscle mass, protein increases, due to pregnancy or weight lifting

Explanation:

The amount of heat required to raise the temperature of 67 g of water from 25.7°C to 66°C is approximately equal to 40.3 kJ. Thus, the answer is option a) 40.3 kJ.

The amount of heat required to raise the temperature of a substance is given by the equation:

q = m * c * ΔT

Here, q is the amount of heat required to raise the temperature , m is the mass of the substance, c is the specific heat capacity, and ΔT is the change in temperature due to the heat supplied.

Substituting the given values in the equation, we get:

q = (67 g) * (4.184 J/g°C) * (66°C - 25.7°C)

q = 40,332 J

Converting this value to kilojoules we obtain:

q = 40.332 kJ = 40.3 kJ

Thus 40.3 kJ of heat energy is required to raise the temperature of  67g of water from 25.7 °C to 66° C.

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Answer:

The speed of the given electromagnetic wave is  3 x 10⁸ m/s.

Explanation:

Electromagnetic wave is a type of energy that is commonly known as light energy. The speed of light in air is about 3 x 10⁸ meters per second (m/s).

All electromagnetic waves travel at the same speed which is equal to speed of light, approximately  3 x 10⁸ meters per second (m/s) through a vacuum or air.

Therefore, the speed of the given electromagnetic wave is  3 x 10⁸ m/s.

Answer:

\(\boxed {\boxed {\sf A. \ 2082 \ mL}}\)

Explanation:

We are asked to find the initial volume of a gas given a change in pressure. Since the temperature remains constant, we are only concerned with volume and pressure. We will use Boyle's Law, which states the volume of a gas is inversely proportional to the pressure. The formula for this law is:

\(P_1V_1= P_2V_2\)

The pressure was initially 248.71 millimeters of mercury, but the volume is unknown.

\(248.71 \ mm \ Hg * V_1 = P_2V_2\)

The pressure is increased to 911.6 millimeters of mercury and the volume is 568 milliliters.

\(248.71 \ mm \ Hg * V_1 = 911.6 \ mm \ Hg * 568 \ mL\)

We are solving for the initial volume, so we must isolate the variable V₁. It is being multiplied by 248.71 millimeters of mercury. The inverse operation of multiplication is division, so we divide both sides by 248.71 mm Hg.

\(\frac {248.71 \ mm \ Hg * V_1 } {248.71 \ mm \ Hg}= \frac{911.6 \ mm \ Hg * 568 \ mL }{248.71 \ mm \ Hg}\)

\(V_1 = \frac{911.6 \ mm \ Hg * 568 \ mL }{248.71 \ mm \ Hg}\)

The units of millimeters of mercury (mm Hg) cancel.

\(V_1 = \frac{911.6 * 568 \ mL }{248.71 }\)

\(V_1 = \frac {517788.8} {248.71 } \ mL\)

\(V_1 = 2081.897793 \ mL\)

Let's round to the nearest whole number. The 8 in the tenths place tells us to round the 1 up to a 2.

\(V_1= 2082 \ mL\)

The gas initially occupied a volume of 2082 milliliters and choice A is correct.

Answer:

0.036  × 10²³ oxygen atoms

Explanation:

Given data:

Mass of compound = 0.24 g

Number of oxygen atoms = ?

Solution:

First of all we will calculate the number of moles of compound.

number of moles = mass/ molar mass

Number of moles = 0.24 g/ 100.1 g/mol

Number of moles = 0.002 mol

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.022 × 10²³ is called Avogadro number.

1 mole of CaCO₃ contain 3 moles of oxygen atom.

0.002 mol × 3 = 0.006 moles of oxygen atoms.

Number of oxygen atoms:

1 mole = 6.022 × 10²³ number of oxygen atoms

0.006 mol ×  6.022 × 10²³ f oxygen atoms / 1 mol

0.036  × 10²³ oxygen atoms

Answer:

B.O2\

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The first half-reaction is the oxidation of Cr2O7^2– to Cr^3+ and the second half-reaction is the reduction of I^– to IO3^–. When combined, the overall reaction is Cr2O7^2– + I^– → Cr^3+ + IO3^–.

The electrolytic cell consists of two electrodes, one anode and one cathode, both of which are immersed in an electrolyte solution. At the anode, the Cr2O7^2– ions are oxidized to Cr^3+ ions, releasing electrons into the external circuit.

At the cathode, the I^– ions are reduced to IO3^– ions, and the electrons from the external circuit are used to drive the reaction. The electrolyte solution must contain both Cr2O7^2– and I^– ions in order to facilitate the transfer of electrons between the electrodes.

The overall reaction is driven by the potential difference between the anode and the cathode, which is created by the flow of electrons through the external circuit.

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At 40°C, the maximum amount of KNO₃ that can dissolve in 200 g of water is 130 g, but since only 110 g of KCl was added, all the KCl will dissolve, and 71.5 g of KNO₃ will dissolve.

To determine how much KNO₃ will dissolve, we need to compare the amount of KCl that was added to the maximum amount of KNO₃ that can dissolve at the same temperature.

First, we can find the maximum amount of KNO₃ that can dissolve in 200 g of water at 40°C, which is given as 65 g/100 g of water

Maximum amount of KNO₃ that can dissolve

= 65 g/100 g x 200 g

= 130 g

This means that at most, 130 g of KNO₃ can dissolve in 200 g of water at 40°C.

Next, we need to compare the amount of KCl added to the maximum amount of KNO₃ that can dissolve.

The amount of KCl added is 110 g, which is less than the maximum amount of KNO₃ that can dissolve (130 g). Therefore, all of the KCl will dissolve and some of the KNO₃ will dissolve.

To find the amount of KNO₃ that will dissolve, we need to calculate how much KNO₃ would be in 110 g of the solvent (water) if it were saturated with KNO₃

Amount of KNO₃ in 110 g of water

= 65 g/100 g x 110 g

= 71.5 g

This means that 71.5 g of KNO₃ will dissolve in 110 g of water at 40°C.

Therefore, the amount of KNO₃ that will dissolve in the 200 g of water containing 110 g of KCl is 71.5 g.

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Answer:

The human population has increased by the billions, and we have been creating better and more complex technology over the years. So, overall there is a difference between now and 50 years ago.

Answer:

2.25 moles

Explanation:

thats correct answer

Thank you

Answer:

B: Invertebrates

Explanation:

Since no other food source for invertebrates is shown, the invertebrates will starve and die off first

Table salt does not melt on the stove, it dissolves in water and does not conduct electricity.

There are several substances listed in the table Epsom salt is another one of these substances. It does not melt on a stove, it dissolves in water and also conducts electricity.

Finally, potassium chloride does not melt on the stove, it dissolves in water and it does conduct electricity. These are the experiences one can have with these common substances.

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Answer:

C6H12O6

Explanation:

C6H12O6

If I put you on a goat

Put you in some water

Now you’re gonna float

Answer:

ZnCO3 solid reacts to form Zn0 solid plus CO2 gas