refrigerant 134a enters a water-jacketed compressor operating at steady state at -10 c, 1.4 bar, with a mass flow rate of 22.2 kg/s, and exits at 50 c, 12 bar. the compressor power required is 792.9 kw. neglecting kinetic and potential energy effects, determine the magnitude of the rate of heat transfer to the cooling water circulating through the water jacket, in kw.

Answer:

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Explanation:

Answer:

Answer to the following question is as follows;

Explanation:

The amount of alcohol consumption can be influenced by a variety of things, including food.

The proportion and pace at which alcohol reaches the circulation is affected by drinking rate, body mass, and the size of the beverage. Alcohol enters your system as soon as it reaches that first sip, as per the National Institute on Drug Abuse and Alcoholism. After 10 minutes, the results are noticeable.

Answer:

Option D

Explanation:

A composite material is made up of two material which have different properties (chemically or physically). The two materials are mixed in such a way that it improves the properties of both the materials (the one  in the matrix and the other in the filler) thereby enhancing the overall strength and stiffness of the matrix.

Hence, option D is correct

A correct option is an option (c)

The main advantage of the composite is there higher strength as compared to the matrix.

The strength is very low as compared to the resultant composite and the fiber.

The resultant strength can be calculated in two direction

The longitudinal way is,

\(E=V_mE_m+V_fE_f...(1)\)

The transversal way is,

\(\frac{1}{E}=\frac{V_m}{E_m}+\frac{V_f}{E_f} ...(2)\)

From equations (1) and (2) we get,

\(E_m < E < E_f\)

So, mode with strong fibers embedded in a weaker and softer matrix to obtain strength better than the strength of the matrix.

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Both technicians are correct

Explanation:

They are each correct for separate reasons. Tech A is correct due to pressure and temperature both being important factors and quantities to vaporize anything. Tech B is correct due to fuel particles being easier to burn due to their chemical structure.

Control transformers generally have two primary terminals and two secondary terminals connected to the primary and secondary leads.

The primary terminals are where the input power is connected, typically from the mains power supply. These terminals are responsible for receiving the primary voltage and current that will be transformed by the transformer.

The secondary terminals are where the transformed voltage is available for use in the control circuit. These terminals provide the stepped-down voltage required for control devices, such as relays, solenoids, or other control components connected to the secondary side of the transformer.

The primary and secondary terminals are designed to be isolated from each other, meaning there is no direct electrical connection between the primary and secondary sides of the transformer. This isolation ensures safety and prevents potential hazards by maintaining electrical separation between the input power and the control circuit.

The primary and secondary terminals of a control transformer are usually labeled to indicate the correct connection points. The primary terminals may be labeled with designations such as "H" (hot) and "N" (neutral), depending on the specific application and local electrical standards. Similarly, the secondary terminals may be labeled as "X1" and "X2" or "1" and "2" to indicate the polarity of the secondary winding.

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Control transformers generally have two primary terminals and two secondary terminals connected to the primary and secondary leads.

The primary terminals are where the input power is connected, typically from the mains power supply. These terminals are responsible for receiving the primary voltage and current that will be transformed by the transformer.

The secondary terminals are where the transformed voltage is available for use in the control circuit. These terminals provide the stepped-down voltage required for control devices, such as relays, solenoids, or other control components connected to the secondary side of the transformer.

The primary and secondary terminals are designed to be isolated from each other, meaning there is no direct electrical connection between the primary and secondary sides of the transformer. This isolation ensures safety and prevents potential hazards by maintaining electrical separation between the input power and the control circuit.

The primary and secondary terminals of a control transformer are usually labeled to indicate the correct connection points. The primary terminals may be labeled with designations such as "H" (hot) and "N" (neutral), depending on the specific application and local electrical standards. Similarly, the secondary terminals may be labeled as "X1" and "X2" or "1" and "2" to indicate the polarity of the secondary winding.

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In practice, government-issued bonds are similar to individuals using loans or credit cards to finance consumer purchases.

Bonds allow governments to borrow money from investors, similar to how individuals borrow money from banks or credit card companies. Governments issue bonds to raise funds for various purposes such as infrastructure projects or to cover budget deficits. Investors purchase these bonds and, in return, receive periodic interest payments and the return of their principal investment at maturity. Just like individuals, governments use bonds as a means of obtaining funds upfront while agreeing to pay back the borrowed amount plus interest over time. Both bonds and individual loans or credit cards involve debt financing to meet financial needs.

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To pass data to a new fragment instance upon creation, the recommended way is to pass it arguments using a Bundle object with an entry for each data element.

This can be achieved by calling the setArguments() method on the fragment instance and passing in a Bundle object containing the necessary data.
It is also possible to create or use a constructor for the class with a parameter for each data element, but this method is not as flexible as the Bundle approach. Another option is to use a setter after creating and attaching the fragment to the activity, but this approach can lead to synchronization issues and should be used with caution.
In summary, the most reliable way to pass data to a new fragment instance is to use the Bundle approach, which allows for easy retrieval of the data within the fragment's onCreate() method.

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In the radio communication system, multipath is the propagation phenomenon that causes diffusion or reflection in multiple different directions of a signal.

Multipath is a propagation mechanism that impacts the propagation of signals in radio communication. Multipath results in the transmission of data to the receiving antenna by two or more paths. Diffusion and reflection are the causes that create multiple paths for the signal to be delivered.

Diffraction occurs when a signal bends around sharp corners; while reflection occurs when a signal impinges on a smooth object. When a signal is received through more than one path because of the diffraction or reflection, it creates phase shifting and interference of the signal.

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Answer:

10.203 Volts

Explanation:

For this problem, we need to understand that a series resistive circuit is simply a circuit with some type of voltage source and some resistors, in this case, R1 and R2.

First, we need to find the voltage in the circuit.  To do this, we need to find the total resistance of the circuit.  When two resistors are in series, you sum the resistance.  So we can say the following:

R_Total = R1 + R2

R_Total = 570 Ω + 560 Ω

R_Total = 1130 Ω

Now that we have R_Total for the circuit, we can find the voltage of the circuit by using Ohm's law, V = IR.

V_Total = I_Total * R_Total

V_Total = 17.9 mA * 1130 Ω

V_Total = 20.227 V

Now that we have V_Total, we can find the voltage drop across each resistor by using Ohm's law once more.  Note, that since our circuit is series, both resistors will have the same current (I.e., I_Total = I_1 = I_2).

V_Total = V_1 + V_2

V_Total = V_1 + I_2*R2

V_Total - I_2*R2 = V_1

20.227 V - (17.9 mA * 560 Ω) = V_1

20.227 V - (10.024 V) = V_1

10.203 V = V_1

Hence, the voltage drop across R1 is 10.203 Volts.

Cheers.

When adding water to a concrete mix, it is important to follow the manufacturer's instructions and use the right amount of water. Too little water can result in a dry, crumbly mix that is difficult to work with, while too much water can weaken the concrete and reduce its strength.

To add water to a concrete mix, follow these steps:

It is important to note that the exact amount of water needed will vary depending on the type of concrete mix you are using, as well as the weather conditions and the intended use of the concrete. Therefore, it is important to follow the manufacturer's instructions and use the recommended amount of water.

Answer:

16.2 cents

Explanation:

Given that a homeowner consumes 260 kWh of energy in July when the family is on vacation most of the time.

Where Base monthly charge of $10.00. First 100 kWh per month at 16 cents/kWh. Next 200 kWh per month at 10 cents/kWh. Over 300 kWh per month at 6 cents/kWh.

For the first 100 kWh:

16 cent × 100 = 1600 cents = 16 dollars

Since 1 dollar = 100 cents

For the remaining energy:

260 - 100 = 160 kwh

10 cents × 160 = 1600 cents = 16 dollars

The total cost = 10 + 16 + 16 = 42 dollars

Note that the base monthly of 10 dollars is added.

The cost of 260 kWh of energy consumption in July is 42 dollars

To determine the average cost per kWh for the month of July, divide the total cost by the total energy consumed.

That is, 42 / 260 = 0.1615 dollars

Convert it to cents by multiplying the result by 100.

0.1615 × 100 = 16.15 cents

Approximately 16.2 cents

Answer:

Feed Forward

Explanation:

In FEED FORWARD compression design the signal is split at the input, and one signal is used to compress the other slightly delayed split signal.

I hope it helps! Have a great day!

Answer:

a) the maximum tensile stress due to the weight of the wire is 1361.23 psi

b) the maximum load P that could be supported at the lower end of the wire is 624.83 lb

Explanation:

Given the data in the question;

Length of wire L = 400 ft = ( 400 × 12 )in = 4800 in

Diameter d = 3/16 in

Unit weight w = 490 pcf

First we determine the area of the wire;

A = π/4 × d²

we substitute

A = π/4 × (3/16)²

A = 0.0276 in²

Next we get the Volume

V = Area × Length of wire

we substitute

V = 0.0276 × 4800

V = 132.48 in³

Weight of the steel wire will be;

W = Unit weight × Volume

we substitute

W = 490 × ( 132.48 / 12³ )

W = 490 × 0.076666

W = 37.57 lb

a) the maximum tensile stress due to the weight of the wire;

σ\(_w\) = W / A

we substitute

σ\(_w\) = 37.57 / 0.0276

= 1361.23 psi

Therefore, the maximum tensile stress due to the weight of the wire is 1361.23 psi

b) the maximum load P that could be supported at the lower end of the wire. Allowable tensile stress is 24,000 psi

Maximum load P that the wire can safely support its lower end will be;

P = ( σ\(_{all\) - σ\(_w\) )A

we substitute

P = ( 24000 - 1361.23  )0.0276

P = 22638.77 × 0.0276

P = 624.83 lb

Therefore, the maximum load P that could be supported at the lower end of the wire is 624.83 lb

The two ways through which a computer model is likely to be used by an engineer in order to help refine a design are as follows:

Thus, the correct options for this question are A and D.

A Computer model may be defined as a type of computer program that significantly runs on a computer that typically develops a model, or simulation, of a real-world feature, phenomenon, or any other event.

According to the context of this question, an engineer would try to perform the ways in order to support the refining of the design through the help of calculating the possible costs of building a design and the run simulations to test a problem with the design.

Therefore, the correct options for this question are A and D.

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Where you own two pottery stores in your city and you want to find the number of two particular vase colors (color) sold in both stores (location) each week (for each week). If are not interested in the sum total, note that the bar graph you should select to compare the data between both stores is: the "Stacked Bar Chart" (Option A)

When comparing data points, a stacked bar chart is generally simpler to notice the comparison than a combined chart.

When data points are stacked on top of each other, it is easier to discern the percentage of each data point relative to the total value.

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Answer: hello the diagram related to your question is missing please the third image is the missing part of the question

Fx = 977.76 Ib/ft

Explanation:

Estimate the force that water exerts on the pier

V = 12 ft/s

D( diameter ) = 6 ft

first express the force  on the first half of the cylinder  as

Fx1 =  - \(-2\int\limits^\pi _\frac{\pi }{2} {Ps*cos\beta *a} \, d\beta\)   ---------------- ( 1 )

where ; Fy = 0

Ps = Po + 1/2 Pv^2 ( 1 - 4 sin^2β )  ------------- ( 2 )

Input equation (2)  into equation ( 1 )         (note :  assuming Po = 0 )

attached below is the remaining part of the solution

Answer: The transition from product to process oriented development in software engineering is a shift from a project management mindset to a product-oriented approach. This approach defines success according to the areas that truly matter to users and design software that delights and engages their customers.

Explanation: In the traditional project management mindset, software development is treated as a one-time project with a defined scope, budget, and timeline. The focus is on delivering the project on time and within budget, rather than on creating a product that meets the needs of users. This approach can lead to software that is delivered on time and within budget, but does not meet the needs of users.

In contrast, the product-oriented approach focuses on creating software that delights and engages users. The goal is to create a product that meets the needs of users, rather than just delivering a project on time and within budget. This approach involves continuous improvement and iteration based on user feedback.

The transition from product to process oriented development involves several changes in how software is developed. First, there is a shift from a project-based approach to a product-based approach. Second, there is an increased focus on user needs and feedback. Third, there is an increased emphasis on continuous improvement and iteration.

Overall, the transition from product to process oriented development can lead to better software that meets the needs of users. However, it can also be more challenging than traditional project management approaches because it requires more flexibility and adaptability.

Hope this helps, and have a great day!

The right response is to Consider Figure 1, which shows the electric field lines of a solitary positive point charge. An electric field line that is produced by a positive charge.

Radiation from RF (radio frequency) waves is produced by all computers. There is no proof that they are harmful unless the intensity is high enough to warm tissue (like a microwave oven). You are not putting yourself in danger if you use your computer for more than four hours each day (from radiation). Computers emit electromagnetic radiation into the environment. In particular, electromagnetic radiation that is visible light is produced. It is also possible for computers to produce other forms of electromagnetic radiation, such as radio waves, ultraviolet light, and infrared light, depending on the components of the device. Avoid using them an hour before going to bed. Even though it may be in your bedroom, you are under no obligation to use it.

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One can write the report under the title Deploying a Robust Web Application in an On-Site Datacenter by Design.

This report's recommendations for deploying the most recent web application of the business in the local datacenter are intended to guarantee high levels of uptime and reduce potential failures.

We can create a strong system that can resist both routine maintenance and significant problems while sustaining uninterrupted service if we have a sizable budget and a skilled staff of sysadmins and devops engineers.

We can develop a reliable deployment for the company's web application in the on-site datacenter by putting the suggested hardware and software design considerations into practise.

Thus, hardware failures will be less damaging because to redundant servers, RAID storage, network redundancy, and power backup systems.

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Depending on whether Hi is greater than or equal to MD, the ALU either subtracts the MD register (the divisor) from its Hi input or allows the Hi input to pass through unaltered.

In conclusion, the division and multiplication operations used in this project are performed by the Arithmetic Logic Unit (ALU), which is an arithmetic and logical operation.

two binary values can be multiplied using this procedure. Take into account the fact that the ALU only offers the addition and shifting operations, not the multiplication operation. The microprogramming code can then be stored in memory and used to perform multiplication operations.

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Answer:

a) 47500 mg/L

b) 5250366.444  kg/year

Explanation:

Given data:

suspended solids removal efficiency = 20%

Flowrate in the primary clarifier ( Q ) = 20 MGD ( change to Liters/day

Q = 20* 10^6 * 3.785412  Liters /day

settled concentration  ( St ) = 950mg/L * 0.2 = 190 mg/L

amount of settled solid = Q * St

                                   = ( 20* 10^6 * 3.785412 ) * 190  = 14384.5656 kg/day

∴ Amount going into sludge with a flowrate of 0.08 MGD = 14384.5656 kg/day

a) concentration of solid in sludge  ( leaving the clarifier )

= amount of settled solid / flow rate out of the clarifier in liters/day

= 14384.5656 / ( 0.08 * 10^6 * 3.785412 )

= 0.0475 kg/L

= 47500 mg/L

b) Determine mass of solids that is removed annually

= 14384.5656 kg/day * 365 days

= 5250366.444  kg/year

Answer:

the order higher is 3p79g5t88=yv5379

The number of paths in the network is six.

The paths are:
C - A - T - N - EndC - A - T - R - N - EndC - B - P - U - N - EndC - B - P - U - T - R - N - EndC - B - P - A - T - N - EndC - B - P - A - T - R - N - End
2. The critical path is C - A - T - N - End with a duration of 24 weeks.

3. The float on activity U is 1 week.

4. If activity B takes three weeks longer than planned, it will affect the duration of path 3 and the entire project. It will elongate the project duration to 29 weeks.

2. b) The critical path is A-C-E-G with a duration of 18 weeks.

(c) The normal expected project completion time is 18 weeks.

(d) The total project cost using normal time is RM 7600.

(e) To complete the project two weeks faster, activities C and E can be crashed for the minimum cost.

The additional cost incurred will be RM 600.

The total cost is RM 8200.

3 The inventory cost that will minimize the total cost of inventory is obtained using the formula,

TAC = IC + OC + HCS

Where TAC

= Total Annual CostIC = Inventory CostOC = Ordering CostHCS = Holding and Carrying Cost.

The probability distribution is shown below. Demand 0 1 2 3 4 5Probability 0.20 0.15 0.25 0.20 0.10 0.10

To determine the optimal order quantity and reorder policy that would minimize total cost,

the EOQ (Economic Order Quantity) model will be used.

The EOQ can be determined using the formula,

Q = √((2DCO)/CH')

Where Q = Economic Order Quantity

D = Demand'

C0 = Cost per order

H = Holding cost

C = IC per unit

Let’s assume the cost per unit, C = RM 500,

the holding cost, H = 0.2,

and demand, D = 3 units per day.

Hence,CO = RM 800 (C0 = Cost per order, which is the same as ordering cost)

Then,Q = √((2 x 3 x RM 800)/RM 100)Q = 24 units per order

Then, the reorder level can be determined using the formula,

ROL = d * LWhere L = Lead time

ROL = 3 x 5 = 15 units

The total annual cost can be determined by substituting the values into the formula,

TAC = IC + OC + HCS

where IC = 0.5 x RM 500

= RM 250OC

= (365/EOQ) x C0OC

= (365/24) x RM 800OC

= RM 12133.33HCS

= (Q/2) x H x dHCS

= (24/2) x 0.2 x 3HCS

= RM 7.20

TAC = RM 250 + RM 12133.33 + RM 7.20TAC = RM 12390.53

Hence, the order quantity that will minimize the total cost of inventory is 24 units.

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Answer:

Explanation:

Simple control requires the direct intervention of an authority figure to accomplish all three aspects of the control process. A supervisor provides the initial direction to the worker, evaluates his or her performance, and

then administers some sort of disciplinary action (reward or punishment). This control strategy relies upon the

strength of the relationship between the supervisor and the subordinate to maintain order in the system. It is

also a fairly obtrusive management strategy; the worker is not required to internalize or actively participate in

the control process.

Answer:

please give me brainlist and follow

Explanation:

Mild steel can be converted into high carbons steel by which of the following heat treatment process? Explanation: Case hardening, also referred as carburizing increases carbon content of steel, thus, imparting hardness to steel.

To convert binary numbers to 2421 code, you can design a PLA (Programmable Logic Array) or a Decoder.

A PLA is a combinational logic device that consists of programmable AND and OR gates. By programming the PLA, you can create a truth table that maps binary inputs to the corresponding 2421 code outputs. The AND gates in the PLA implement the product terms of the truth table, and the OR gates combine these terms to generate the desired outputs.

On the other hand, a Decoder is a logic device that decodes a binary input into multiple outputs. By designing a Decoder specifically for the 2421 code, you can directly convert the binary inputs to the corresponding 2421 code outputs using the internal circuitry of the Decoder.

The choice between using a PLA or a Decoder depends on the specific requirements of your application, such as the complexity of the truth table, the number of inputs and outputs, and the available resources.

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